Identify the like terms in this expression: 4x^2 + 2x - 6x + 3y

Answer:

47

Step-by-step explanation:

10*4 -3

40-3

47

Answer:

2w-42

Step-by-step explanation:

-24+2(w-9)

We need to distribute the 2 to the w-9 in the parentheses as per PEMDAS (Parentheses, Exponents, Multiplication, Division, Addition, Subtraction)

-24+2w - 18

Subtract -24 -18

2w - 42

Answer:

No

Step-by-step explanation:

x=5 produces y=3 and y=5 so the relation is not a function.

Yes that is function by looking that this

y

The value of log(0.47) after rounding to 4 decimal place is -0.3279

Option D

Given :

Find the value of log(0.47) using calculator

To find the log value we use the calculator

here we are asked to find out log (0.47) that is the log (decimal)

we cannot find the log value without calculator because we have decimal argument inside log.

Use scientific calculator

Press log first then enter the number 0.47 inside a parenthesis

Press enter , it will show you the log(0.47)

log(0.47) =-0.327902142

Now round the answer to 4 decimal places

We have 0 in the 5th decimal place . so we keep 9 as it is

log(0.47) =-0.3279

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Answer: He did not convert the fractions into the like fraction to add.

Step-by-step explanation:Given: The distance Jonah runs on Sunday=  milesThe distance Jonah runs on Monday=  milesThe total distance he ran = Since both the fractions are not like , thus multiply 2 to the numerator and the denominator of the first fraction [to add fractions first convert them into like fractions], we get The total distance he ran = The right answer is "The total distance he ran ="

Answer:

Step-by-step explanation:

−36w+60

=12(−3w+5)

12(−3w+5)

The equations of the vertical asymptotes can be given as x = -4, -2, and 1. The function f(x) does not have any horizontal asymptotes.

The function, f(x) is given as f(x)=5 - f ′(x)>0 on (−2,1)∪(1,[infinity]) f ′(x)<0 on (−[infinity],−2)f ′′(x)>0 on (−[infinity],−4)∪(1,4)f ′′(x)<0 on (−4,−2)∪(−2,1)∪(4,[infinity])

To sketch the graph of the original function, we have to determine the critical points, intervals of increase and decrease, the local maximum and minimum, and asymptotes of the given function.

Using the given information, we can form the following table of f ′(x) and f ′′(x) for the intervals of the domain.

The derivative is zero at x = -2, 1.

To get the intervals of increase and decrease of the function f(x), we need to test the sign of f ′(x) at the intervals

(−[infinity],−2), (-2,1), and (1,[infinity]).

Here are the results:

f′(x) > 0 on (−2,1)∪(1,[infinity])f ′(x) < 0 on (−[infinity],−2)

As f ′(x) is positive on the intervals (−2,1)∪(1,[infinity]) which means that the function is increasing in these intervals.

While f ′(x) is negative on the interval (−[infinity],−2), which means that the function is decreasing in this interval.

To find the local maximum and minimum, we need to determine the sign of f ′′(x).

f ′′(x)>0 on (−[infinity],−4)∪(1,4)

f ′′(x)<0 on (−4,−2)∪(−2,1)∪(4,[infinity])

We find the inflection points of the function f(x) by equating the second derivative to zero.

f ′′(x) = 0 for x = -4, -2, and 1.

The critical points of the function f(x) are -2 and 1.

The inflection points of the function f(x) are -4, -2, and 1.

Hence, the equations of the vertical asymptotes can be given as x = -4, -2, and 1.The function f(x) does not have any horizontal asymptotes.

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This equation is not satisfied for any value of x. Therefore, there is no optimal value of good x in this case.

To find the optimal value of good x in Ann's utility function U(x,z) = xz/(x+z) with pz = 1, we need to maximize the utility function.
To do this, we can take the derivative of the utility function with respect to x and set it equal to zero.
First, let's differentiate the utility function:
dU/dx = (z(x+z) - xz)/(x+z)^2
Setting this equal to zero, we have:
(z(x+z) - xz)/(x+z)^2 = 0
Simplifying, we get:
z(x+z) - xz = 0
Expanding and rearranging, we have:
xz + z^2 - xz = 0
Simplifying further, we get:
z^2 = 0
Since pz = 1, we can substitute z = 1 into the equation:
1^2 = 0
This equation is not satisfied for any value of x. Therefore, there is no optimal value of good x in this case.

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Answers:

#1: infinite solutions;  #2: no solutions

Step-by-step explanations:

Steps for #1

3(2x+7)=13+4(x+2)+2x

6x+21=13+4x+8+2x

6x+21=21+6x

6x=6x

x=x

After completing the steps to find the value of x using Order of Operations, we see that in the end, the answer we have is x=x. We can easily conclude that x is equal to any number because the final answer in this exercise is always whatever the value of x is. For example, if x=4, our final answer would be 4.

Steps for #2

5(6x+8)=9x-10+21x

30x+40=30x-10

40=-10

Here, we see that once we've completed the steps using the Order of Operations, we come out with the answer 40=-10, which is not true on any terms. Therefore we can simply conclude that the answer for #2 is "no solutions."

If you have any trouble figuring out how I got my answers, please refer back to the steps I used to get the answers.

Thank you!

Table: x         2  5  9

   f ( x )   5  8  11

Domain: {2, 5, 9}, Range: {5, 8, 11}.

The domain of a function is the set of all the input values, while the range is the set of all output values. In this example, the function f(x) is represented in a table with three values. For the domain, the input values are 2, 5 and 9. This means that the domain of f(x) is {2, 5, 9}. The range of f(x) is the set of all output values. The output values for this problem are 5, 8, and 11. This means that the range of f(x) is {5, 8, 11}. Therefore, the domain and range of f(x) can be written as {2, 5, 9} and {5, 8, 11} respectively.

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The density is 6.48 (g/cm³).

Density (vοlumetric mass density οr specific mass) is the substance's mass per unit οf vοlume. The symbοl mοst οften used fοr density is ρ (the lοwer case Greek letter rhο), althοugh the Latin letter D can alsο be used. Mathematically, density is defined as mass divided by vοlume:

\({\displaystyle \rho ={\frac {m}{V}}}\)

Here the given Vοlume = 1250 cm³, Mass = 8.1 kg.

We knοw that 1kg = 1000 g. Then,

Mass = 8.1*1000 = 8100 gram.

Nοw density = Mass/ Vοlume

=> Density = \(\frac{8100}{1250}\) = 6.48 (g/\(cm^3\))

Hence the density is 6.48 (g/\(cm^3\)).

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To find the amount of sand that a box will hold, we would use the measure of volume.

Volume is the amount of space that an object or substance takes up in three dimensions, typically measured in cubic units. In the case of the box being filled with sand, we would use the volume of the box to determine how much sand it can hold. This can be calculated by multiplying the length, width, and height of the box together, which gives the total cubic units of volume. The resulting value would be in cubic units such as cubic inches, cubic feet, or cubic meters, depending on the units of measurement used.

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It is true that the null space of a is the solution set of the equation ax = 0.

The null space of a matrix A is Nul(A)= {x : Ax=0}. In other words, if A is m × n, then its null space consists of those vectors x ∈ Rn which solve the homogeneous equation Ax= 0.

Solving Ax=0 yields an explicit description of Nul(A).

Therefore, the Option A is correct.

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Answer: -1

Step-by-step explanation:

17-18 looks easy but, the answer would be minus.

So, the answer would be: -1

Answer:

i think its 18

Step-by-step explanation:

Answer:

y = 8

x = 17

Step-by-step explanation:

We can find the missing values using similarity ratio

15/30 = y/16 cross multiply expressions

30y = 240 divide both sides by 30

y = 8

Now do the same for x

15/30 = x/34 cross multiply expressions

30x = 510 divide both sides by 30

x = 17

Answer:

three hundred fifteen meters per second

Step-by-step explanation:

Answer:

I believe that it is 812 tiles.

Step-by-step explanation:

Answer:

812 tiles

Step-by-step explanation:

28 feet by 29 feet is 812, each tile is 1 square foot. This means that there are 812 tiles.

The requirement f(x1) * f(x2) < 0 for choosing initial guesses x1 and x2 with opposite signs ensures the validity and convergence of certain numerical root-finding methods such as the bisection method or the regula falsi method.

The statement you provided is true for certain numerical methods used to find roots of equations, such as the bisection method or the regula falsi method. These methods are iterative and require an initial interval or range where the root is expected to be found. To ensure convergence and a valid solution, it is necessary to choose initial guesses x1 and x2 such that the function f(x) evaluated at those points have opposite signs, i.e., f(x1) * f(x2) < 0.

The rationale behind this requirement is based on the Intermediate Value Theorem, which states that if a continuous function f(x) changes sign over an interval [x1, x2], then there exists at least one root within that interval. By ensuring that f(x1) and f(x2) have opposite signs, we guarantee the existence of a root within the interval [x1, x2].

The bisection method works by repeatedly bisecting the interval and selecting a new subinterval that contains the root. At each iteration, the method narrows down the interval by halving it, based on the sign change observed in the function evaluations.

Similarly, the regula falsi (or false position) method also operates by iteratively refining the interval based on the linear interpolation between the function values at the endpoints. The method adjusts the interval based on the sign change of the function, converging to the root.

Both methods rely on the property of opposite signs to guarantee convergence and avoid getting stuck in a non-converging or incorrect solution. If the initial guesses do not satisfy the condition f(x1) * f(x2) < 0, it is possible that the method fails to converge or converges to a different root or solution.

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Answer:

-4

Step-by-step explanation:

-5x-10=10

add 10 to -10 to get rid of it, and to 10 because whatever you do to one side, you have to do to the other

-5x=20

divide -5 into 20

x = -4

Step-by-step explanation:

3x - 2x² = 7

2x² - 3x + 7 = 0

or

f(x) = 2x² - 3x + 7

a = 2

b = -3

c = 7

5 - 2x² = 6x

2x² + 6x - 5 = 0

or

f(x) = 2x² + 6x - 5

a = 2

b = 6

c = -5

(x+3)(x+4) = x² + 4x + 3x + 12 = x² + 7x + 12 = 0

f(x) = x² + 7x + 12

a = 1

b = 7

c = 12

(2x + 7)(x - 1) = 2x² - 2x + 7x - 7 = 2x² + 5x - 7 = 0

f(x) = 2x² + 5x - 7

a = 2

b = 5

c = -7

2x(x - 3) = 15

2x² - 6x = 15

2x² - 6x - 15 = 0

or

f(x) = 2x² - 6x - 15

a = 2

b = -6

c = -15

Twelve horses will take 18 hours to consume 36 bales of hay.

Given,Six horses eat 12 bales of hay in 12 hours We need to find,

Let's assume that 1 horse will eat 1 bale of hay in x hours.

As we know,6 horses will eat 12 bales of hay in 12 hours.

Now we can find x as follows:

For 1 horse, 1 bale of hay is consumed in x hours

So, for 6 horses, 6 bales of hay will be consumed in x hours.

Then,6 horses consume 12 bales of hay in 12 hours6 horses consume 6 bales of hay in 6 hours1 horse consumes 1 bale of hay in 6 hours

Now we have to find how many hours will 12 horses take to eat 36 bales of hay.

If 1 horse eats 1 bale of hay in 6 hours, then 12 horses will consume 12 bales of hay in 6 hours.

Therefore, 12 horses will consume 36 bales of hay in 18 hours.

So, the answer is: Twelve horses will take 18 hours to consume 36 bales of hay.

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Answer:

65--but the method is the important part that the directions indicated.

Step-by-step explanation:

26 + 39

(2 × 13) + (3 × 13)

The GCF is 13.

Factor the 13 out; it's like Distributive Property in reverse.

13 (2 + 3)

13 (5)

65

26+39= 65, so we obtain the same answer as just adding, by using GCF and Distributive Property.

Answer:

  13(2 +3)

Step-by-step explanation:

26 = 2·13

39 = 3·13

The greatest common factor is 13, so the sum can be written ...

  26 +39 = 13(2 +3)

_____

Additional comment

Of course, the value of the sum is ...

  13(2+3) = 13(5) = 65

Alternatively, the sum can be evaluated as ...

  26 +39 = 26 -1 +1 +39 = (26 -1) +(1 +39) = 25 +40 = 65

The function \(\(f(x) = x^2 - 8\)\) does not have any horizontal asymptotes at positive or negative infinity and does not have any vertical asymptotes.

To find the horizontal and vertical asymptotes of the function\(\(f(x) = x^2 - 8\),\) , we need to evaluate the limits as x approaches positive or negative infinity.

First, let's determine the horizontal asymptote. As x approaches infinity, the term \(\(x^2\)\)  dominates the expression. Hence, we can say that the function grows without bound as \(x\) approaches infinity, indicating that there is no horizontal asymptote at positive infinity.

Similarly, as x approaches negative infinity,\(\(x^2\)\) remains positive, and the term \(-8\) becomes negligible. Thus, the function again grows without bound and does not have a horizontal asymptote at negative infinity either.

Moving on to the vertical asymptote, it occurs when the function approaches infinity or negative infinity at a specific x-value. In the case of \(\(f(x) = x^2 - 8\)\) , there are no vertical asymptotes because the function is a polynomial, and polynomials are defined for all real values of \(x\).

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The quotient of the expression 5x^2/7÷10x^3/21 is 3/(2x)

From the question, we have the following parameters that can be used in our computation:

5x^2/7÷10x^3/21

Assume that no denominator has a value of 0, we have

5x^2/7÷10x^3/21 = 5x^2/7 ÷ 10x^3/(7 * 3)

Express as products

So, we have the following representation

5x^2/7÷10x^3/21 = 5x^2/7 * (7 * 3)/10x^3

When the factors are evaluated, we have

5x^2/7÷10x^3/21 = 5 * 3/10x

So, we have

5x^2/7÷10x^3/21 = 15/10x

This gives

5x^2/7÷10x^3/21 = 3/(2x)

Hence, the solution is 3/(2x)

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The critical value of z₀.₀₀₀₅ = 4.7507 (approx)

The given confidence level is 1 - α = 1 - 0.00005 = 0.99995

We find the closest value to 0.99995 in the table, which is 0.99995003. This corresponds to the z-value of z0.99995003, which is the critical value for a two-tailed test at the given confidence level.

Thus, the critical value z₀.₀₀₀₅ (to four decimal places) is z0.99995003, which is approximately 4.7507.

z₀.₀₀₀₅ = 4.7507 (approx)

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The various output values are displayed on the y-axis and make up the range. The whole of all conceivable outcomes for the dependent variable constitutes a function's range.

The statistical range is the range of values between the highest and lowest for a particular data collection. Another way to represent the range is the difference between the highest and lowest observation. The sample interval is determined by subtracting the largest number from the lowest. For continuous variables, the sample range is a critical measure of variability.

here

A function y = f is an example (x).

The function's range is the range between all of the y values, from least to maximum.

All the values of x should be substituted into the specified expression of y to determine whether it is positive, negative, or equal to other values.

So , The various output values are displayed on the y-axis and make up the range.

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Using a two-sided coin and tossing it in the air to determine which participants go into which groups is an example of random assignment.

Random assignment is a process that involves assigning research participants to experimental groups or conditions in such a way that each participant has an equal chance of being assigned to any group. In the case of a two-sided coin, each participant has an equal chance of being assigned to either group.

The primary purpose of random assignment is to create comparable groups in experimental research. It helps to ensure that there are no systematic differences between the groups that could affect the results of the study.

There are several other ways to accomplish random assignment, including drawing numbers from a hat, using a random number generator, or flipping a coin. Whatever method is used, the important thing is that it is random and provides each participant with an equal chance of being assigned to any group.

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Answer:

if u are asking how many more pages Matthew read then it's 48 pages. If u are asking how many they read all together then it's 144 pages.