If a person paddles a canoe up a creek, a distance of 13.09 km, how fast does she need to move in order to get to the end of the creek within 2.371 hours?

a}The work is done by the piston in the process is 199 cal.

b) The increase in internal energy of the gas is  703 cal

c) The heat was supplied to the gas is  3771 J

(a) To calculate the work done by the piston, we can use the formula:

Work = P * ΔV

Where P is the constant pressure and ΔV is the change in volume. Since the pressure is constant, the work done is given by:

Work = P * (\(V_2 - V_1\))

Since the amount of gas is constant (1 mole), we can use the ideal gas law to calculate the initial and final volumes:

PV = nRT

\(V_1 = (nRT_1) / P_1\)

\(V_2 = (nRT_2) / P_2\)

Here, n is the number of moles (1 mole), R is the gas constant (1.99 cal/mol·°C), T1 is the initial temperature (27 °C + 273 = 300 K), T2 is the final temperature (127 °C + 273 = 400 K), and P1 and P2 are the initial and final pressures, respectively (both 1 atm).

Substituting the values into the equation, we have:

V1 = (1 mol * 1.99 cal/mol·°C * 300 K) / (1 atm) ≈ 597 cal

V2 = (1 mol * 1.99 cal/mol·°C * 400 K) / (1 atm) ≈ 796 cal

Therefore, the work done by the piston is:

Work = 1 atm * (796 cal - 597 cal) = 199 cal

(b) The increase in internal energy of the gas can be calculated using the equation:

ΔU = n * C * ΔT

Where ΔU is the change in internal energy, n is the number of moles (1 mole), C is the molar heat capacity (7.03 cal/mol·°C), and ΔT is the change in temperature (127 °C - 27 °C = 100 °C).

Substituting the values into the equation, we have:

ΔU = 1 mol * 7.03 cal/mol·°C * 100 °C = 703 cal

(c) The heat supplied to the gas can be calculated using the equation:

Q = ΔU + Work

Substituting the values calculated in parts (a) and (b), we have:

Q = 703 cal + 199 cal = 902 cal

Since 1 cal = 4.184 J, the heat supplied to the gas is:

Q = 902 cal * 4.184 J/cal ≈ 3771 J

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The number of pool noodles that  would be needed to support the weight is 20.

The volume of a single pool noodle is calculated as follows;

V = πr²h

V = π (0.025)² x 1.65

V = 0.00324 m³

The weight of the water displaced is calculated as follows;

W = ρVg

where;

W = 1000 x 0.00324 x 9.8

W = 31.75 N

The number of pool noodles needed to support a person is calculated as follows;

= (65 x 9.8 ) / (31.75)

= 20

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The owner's velocity is in the opposite direction of the combined velocity of the dog and the cat, and its magnitude is approximately 0.916 m/s.

To solve the given problem, we can use the principle of conservation of momentum to find the direction and magnitude of the owner's velocity.

Let's denote the velocity of the dog as v1 (northward), the velocity of the cat as v2 (eastward), and the velocity of the owner as v (unknown).

According to the conservation of momentum, the total momentum before the interaction is equal to the total momentum after the interaction.

The total momentum before the interaction is given by:

Total momentum before = (mass of the dog * velocity of the dog) + (mass of the cat * velocity of the cat) + (mass of the owner * velocity of the owner)

Mass of the dog (m1) = 24.4 kg

Velocity of the dog (v1) = 2.14 m/s

Mass of the cat (m2) = 5.53 kg

Velocity of the cat (v2) = 3.56 m/s

Mass of the owner (m3) = 78.5 kg

Velocity of the owner (v) = unknown

Total momentum before = (24.4 kg * 2.14 m/s) + (5.53 kg * 3.56 m/s) + (78.5 kg * v)

The total momentum after the interaction is zero since the owner has the same momentum as the pets taken together.

Total momentum after = 0

Equating the two expressions:

(24.4 kg * 2.14 m/s) + (5.53 kg * 3.56 m/s) + (78.5 kg * v) = 0

Simplifying the equation:

(52.216 kg·m/s) + (19.6488 kg·m/s) + (78.5 kg * v) = 0

71.8648 kg·m/s + (78.5 kg * v) = 0

Solving for v:

78.5 kg * v = -71.8648 kg·m/s

v = -71.8648 kg·m/s / 78.5 kg

v ≈ -0.916 m/s

Therefore, the direction of the owner's velocity is opposite to the combined velocity of the dog and the cat, and the magnitude of the owner's velocity is approximately 0.916 m/s.

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Answer:

hey so this website called quiz-let helps you it will give u the answer for every question i use it sometimes when im confused on a test.

It takes 0 seconds for the catcher to stop the ball and the ball travels 0 meters before stopping.

To find the time it takes for the catcher to stop the ball, you can use the equation:

time = distance / velocity

In this case, the distance is zero (since the ball is stopped) and the velocity is 21.80 m/s. Plugging these values into the equation gives us:

time = 0 / 21.80

time = 0 s

So, it takes 0 seconds for the catcher to stop the ball.

To find the distance the ball travels before stopping, you can use the equation:

distance = 1/2 * acceleration * time^2

In this case, the acceleration is the force applied to the ball divided by the mass of the ball, or (-360 N) / (0.18 kg) = -2000 m/s^2. The time is the time it takes the ball to stop, which we just found to be 0 s. Plugging these values into the equation gives us:

distance = 1/2 * (-2000 m/s^2) * (0 s)^2

distance = 0 m

So, the ball travels 0 meters before stopping.

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The percentage error in a steel tape used for measurement on a cold day when the temperature is -5 ℃ is - 0.028

Coefficient of linear thermal expansion for steel, α = 1.1 * \(10^{-5}\) / C

Let the length of the tape at 20 ℃ be L.

New length of the steel tape after cooling, L' = L ( 1 + α ΔT )

ΔL = L' - L

ΔL = L ( 1 + α ΔT ) - L

ΔL = L ( 1 + α ΔT - 1 )

ΔL = L α ΔT

ΔT = T - \(T_{0}\)

T = Final temperature

\(T_{0}\) = Initial temperature

ΔT = - 5 - 20

ΔT = - 25 ℃

ΔL = L * 1.1 * \(10^{-5}\) * ( - 25 )

ΔL = - 27.5 * \(10^{-5}\)  * L

Percentage error = ΔL / L * 100

Percentage error =  - 27.5 * \(10^{-5}\)  * L / L * 100

Percentage error =  - 0.028

Therefore, the percentage error in the steel tape is - 0.028

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The answer is  energy 3 times as much. option A.

To calculate the amount of energy released when a 5 kg object is converted to pure energy, we can use Einstein's famous equation: E = mc². In this equation, E represents energy, m represents mass, and c represents the speed of light.

Given that the mass of the object is 5 kg, we can calculate the energy using the equation:

E = (5 kg) * (c²)

Now, to compare this energy with the amount of energy the Earth receives from the Sun every second, we need to determine the Earth's solar energy input.

The solar constant is the amount of solar radiation received per unit area at the Earth's distance from the Sun. Its average value is approximately 1361 Watts per square meter (W/m²). Multiplying this value by the surface area of the Earth (approximately 510 million square kilometers), we can estimate the total energy received by the Earth from the Sun every second.

Energy from the Sun = (1361 W/m²) * (510,000,000,000 m²)

To compare the energy released from converting a 5 kg object to energy with the energy received from the Sun, we divide the former by the latter:

Energy conversion / Energy from the Sun = [(5 kg) * (c²)] / [(1361 W/m²) * (510,000,000,000 m²)]

Simplifying the equation, we find:

Energy conversion / Energy from the Sun = (5 kg * c²) / (1361 W/m² * 510,000,000,000 m²)

The value of c² is approximately (3x10^8 m/s)² = 9x10^16 m²/s².

Plugging in the values, we get:

Energy conversion / Energy from the Sun = (5 kg * 9x10^16 m²/s²) / (1361 W/m² * 510,000,000,000 m²)

Simplifying further:

Energy conversion / Energy from the Sun ≈ 3.52

Therefore, the amount of energy released when a 5 kg object is converted to pure energy is approximately 3.52 times larger than the amount of energy the Earth receives from the Sun every second.

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Answer:

That is true.

Explanation:

When the input force is applied to the wheel, as it is with a doorknob, the axle turns over a shorter distance but with greater force, so the mechanical advantage is greater than 1.

The electric potential energy of the pair of charges when the second charge is at point b is 7.3 x 10⁻⁸ J.

When work is done on a positive test charge to move it from one location to another, potential energy increases and electric potential increases.

The electric potential energy between the charges when the second charge is at point b is calculated as follows;

ΔU = -w

Ui - Uf = w

Uf = Ui - w

where;

Uf is the final potential energy

Ui is the initial potential energy

w is the work done by the force

Uf = 5.4 x 10⁻⁸ J - (-1.9 x 10⁻⁸J)

Uf = 5.4 x 10⁻⁸ J + 1.9 x 10⁻⁸ J

Uf = 7.3 x 10⁻⁸ J

Thus, the electric potential energy of the pair of charges when the second charge is at point b is 7.3 x 10⁻⁸ J.

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The final velocity with which the car strike the train is 15 m/s.

Velocity of an object is the time rate of change of displacement covered by the object.

Here,

Initial velocity of the car, u = 25 m/s

Time taken, t = 3 s

Displacement of the car after applying the brake, s = 60 m

The average velocity ,

v' = displacement/time

v' = s/t

Also, the average velocity can be given as,

v' = (u + v)/2

So,

s/t = (u + v)/2

Therefore, the final velocity with which the car strike the train,

v = (2s/t) - u

v = (2 x 60/3) - 25

v = 15 m/s

Hence,

The final velocity with which the car strike the train is 15 m/s.

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The pollution from the first plant would be half that of the second plant for the same amount of energy produced.

The energy efficiency of a coal plant refers to the amount of energy produced per unit of fuel consumed. If the first plant is twice as energy efficient as the second plant, it means that it can produce the same amount of energy using half the amount of fuel.

Since pollution from coal plants is directly proportional to the amount of fuel consumed, the first plant would produce half the pollution of the second plant for the same amount of energy produced. This assumes that the two plants have the same level of emissions per unit of fuel consumed, which may not necessarily be the case.

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Answer:

Introduction:

In this report, we will examine whether the 100 square meter parachutes with a drag coefficient of 1.5 are suitable for dropping 700-kilogram parcels from a plane at a refugee camp. The main concern is that the parcels cannot hit the ground at a velocity of more than 5 meters per second without damaging the contents.

Calculation:

To determine whether the 100 square meter parachutes with a drag coefficient of 1.5 are suitable, we need to calculate the terminal velocity of the parcels. The terminal velocity is the maximum velocity that the parcels can reach when they are falling through the air. We can calculate the terminal velocity using the following equation:

Vt = sqrt((2mg)/(ρACd))

Where:

Vt is the terminal velocity

m is the mass of the parcel (700 kg)

g is the acceleration due to gravity (9.8 m/s^2)

ρ is the air density (1.22 kg/m^3)

A is the area of the parachute (100 m^2)

Cd is the drag coefficient (1.5)

Substituting these values into the equation, we get:

Vt = sqrt((2 x 700 x 9.8)/(1.22 x 100 x 1.5)) = 52.0 m/s

This means that without any parachute, the parcel would hit the ground with a velocity of 52 m/s. However, the parachutes are designed to provide air resistance, which will slow down the parcels.

To determine whether the parachutes are suitable, we need to calculate the velocity at which the parcels will hit the ground when they are attached to the parachutes. We can use the following equation to calculate the force of air resistance:

F = (1/2)ρAv^2Cd

Where:

F is the force of air resistance

ρ is the air density (1.22 kg/m^3)

A is the area of the parachute (100 m^2)

v is the velocity of the parcel

Cd is the drag coefficient (1.5)

When the force of air resistance is equal to the weight of the parcel, the parcel will stop accelerating and will reach its terminal velocity. Therefore, we can set the force of air resistance equal to the weight of the parcel:

F = mg

Substituting the values into the equation, we get:

(1/2)ρAv^2Cd = mg

Solving for v, we get:

v = sqrt((2mg)/(ρACd))

Substituting the values into the equation, we get:

v = sqrt((2 x 700 x 9.8)/(1.22 x 100 x 1.5)) = 25.9 m/s

This means that the velocity at which the parcels will hit the ground when they are attached to the parachutes is 25.9 m/s.

Conclusion:

Based on our calculation, the 100 square meter parachutes with a drag coefficient of 1.5 are suitable for dropping 700-kilogram parcels from a plane at a refugee camp. The velocity at which the parcels will hit the ground when they are attached to the parachutes is 25.9 m/s, which is below the maximum velocity of 5 m/s specified by the U.S. Army. However, if the mass of the parcels or the area of the parachutes changes, the velocity at which the parcels hit the ground will also change. Therefore, it is important to recalculate the velocity for different scenarios to ensure the safety of the parcels.

Explanation:

About the possibility of a collision between this asteroid and the Earth the true statement is there is not enough information to determine whether there is danger of a collision.

What is asteroid?

A tiny, stony object called an asteroid orbits the Sun. They are made up of materials left over from the formation of the solar system and are typically found in the asteroid belt. Most asteroids are less than one kilometer in diameter, but some can be much larger. Asteroids are commonly composed of minerals and metals, such as iron, magnesium, and silicon. Asteroids are classified into three main types: C-type, S-type, and M-type. C-type asteroids are the most common and make up around 75% of known asteroids. They are made up of dark, carbon-rich material and are often referred to as "carbonaceous chondrites". S-type asteroids are made up of silicate material, such as clay and silica, and are typically brighter than C-type asteroids. M-type asteroids are made of metallic material, such as iron and nickel, and are the least common type.

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Taking half of the given length and pulling it to a length of 2L as before, the frequency obtained by vibrating in the basic method is 6fo. option(ii)

When a bow vibrates in its fundamental mode with a length of 2L, the frequency is denoted as f. Now, let's consider the scenario where half of the given length (L) is pulled to a length of 2L.

In the fundamental mode of vibration, the frequency is inversely proportional to the length of the vibrating object. Therefore, if the length of the bow is halved to L, the frequency would double to 2f.

When this new length of L is pulled to a length of 2L, we need to determine the frequency obtained in the fundamental mode.

Since the frequency is inversely proportional to the length, we can use the inverse relationship to find the new frequency.

If the original frequency was 2f at length 2L, when the length is reduced to L, the new frequency would be (2f)/(2L) = f/L.

Now, if this length of L is stretched to 2L again, the new frequency in the fundamental mode would be (f/L) * (2L) = 2f. option(ii)

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Placing lights at either side of the mirror to directly brighten the complexion is the simplest way to help reduce shadows on the face. The temperature of this bulb should be comfortable as well (2,700 to 3,500 Kelvin).

Lighting in salons should be positioned to eliminate shadows. Placing lights at either side of the mirror to directly brighten the complexion is the simplest way to help reduce shadows on the face. The temperature of this bulb should be comfortable as well (2,700 to 3,500 Kelvin).

Compared to other spaces or buildings, a beauty salon has a lot more practical uses for lighting. It facilitates work, helps staff members see consumers clearly, and ensures that everything is carried out correctly.

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The mistakes in the results include options (v) and (vii) which do not follow the five golden rules for reporting results.

The five golden rules for reporting results are:

Using these rules, identify the mistakes in the given results as:

(v) 97.1 × 10³ ± 276Ω - The uncertainty is reported to an inappropriate number of significant figures and the units are not consistent.

(vii) 98.6 × 10³ ± 3 × 10^(-Q) - The uncertainty is not reported to the same number of decimal places as the measured value, and the units are not consistent.

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Answer:

3.1 m/s

Explanation:

The total distance she has to run is the addition of the three lengths:

47 + 63 + 76 = 186 meters.

She needs to cover it one minute (60 seconds). Therefore her speed must be:

186 m / 60 s = 3.1 m/s

Answer: i think the answer is 20.0s

Explanation:

Answer:

The rabbit displaces 2.5m to the right.

Explanation:

Khan Academy hints

Answer:

Because gravity makes you able to stand and move around

Gravity can't fail

it can fail only in astronuts camp and in space

Explanation:

✌❤

Yh....

:)

Answer:

1.551 m

Explanation:

a)  Period, T      T = 5 s  / 2 oscill   = 2.5 seconds

b)    T = 2 pi sqrt (L/g)

     2.5  = 2 pi sqrt ( L/9.8)     <=====   solve for   L = 1.551 m

A metal sphere with a 2 cm radius in air has a maximum potential of 3.48 * 106 V, while one with a 0.6 mm radius has a maximum potential of 6.28 * 104 V.

non-count noun. When you refer to someone or something as having potential, you are referring to their potential to succeed or be beneficial in the future.

Something that has the potential to happen. The potential advantages of the new medicine are exhilarating for doctors. The factory, according to critics, could endanger the environment. potential expansion of the institution. He might run for the office of president.

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Answer:

Because it was too hot for volatile compounds (like water) to condense in the inner solar system, rocky planetesimals formed from compounds with high melting points, such as iron and rocky silicates

The scenario presented is an example of negative punishment.

Negative punishment involves the removal of a desirable stimulus or the addition of an aversive stimulus in response to a behavior, with the goal of decreasing the likelihood of that behavior occurring again in the future.

In this case, the desirable stimulus that was removed is the son's ability to engage in leisure activities like playing hockey, and the aversive stimulus that was added is the scolding from the parent. By experiencing this consequence, the son may be less likely to forget his chores in the future in order to avoid the negative outcome.

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The sculpture measures 16.70 kg, which is in accordance with the requirement.

Wires, often in the form of a wire rope, are used to transport mechanical loads. In the realm of electricity with telecoms transmissions, a "wire" might be an electrical cable. The "solid core" of this kind of cable might be formed of a wired connection or numerous strands that have been braided or stranded together.

Use the string's tautness' fundamental frequency as a formula.

f = (1/2L)*√(T/μ) .... (Eqn1)

Where,

f= frequency in Hertz =95Hz

T = String tension equals Mg

M represents the sculpture's mass, thus what is it?

g= 9.8m/s^2

L= Length of the string=90cm=0.9m

Mass density is equal to mass of string divided by string length.

mass of string =5g=0.005kg

L=0.9m

μ=0.005/0.9 = 0.0056kg/m

Using (Eqn1)

95 = 1/(2*0.9) √(T/0.0056)

171 = √(T/0.0056

Square both sides

29241 = T/0.0056

T= 163.74N

Recall that T =Mg

116.12= M * 9.8

M=163.74/9.8

M= 16.70kg

Consequently, the sculpture weighs 16.70kg.

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Answer:

the maximum intensity of an electromagnetic wave at the given frequency is 45 kW/m²

Explanation:

Given the data in the question;

To determine the maximum intensity of an electromagnetic wave, we use the formula;

\(I\) = \(\frac{1}{2}\)ε₀cE\(_{max\)²

where ε₀ is permittivity of free space ( 8.85 × 10⁻¹² C²/N.m² )

c is the speed of light ( 3 × 10⁸ m/s )

E\(_{max\) is the maximum magnitude of the electric field

first we calculate the maximum magnitude of the electric field ( E\(_{max\)  )

E\(_{max\) = 350/f kV/m

given that frequency of 60 Hz, we substitute

E\(_{max\) = 350/60 kV/m

E\(_{max\) = 5.83333 kV/m

E\(_{max\) = 5.83333 kV/m × ( \(\frac{1000 V/m}{1 kV/m}\) )

E\(_{max\) = 5833.33 N/C

so we substitute all our values into the formula for  intensity of an electromagnetic wave;

\(I\) = \(\frac{1}{2}\)ε₀cE\(_{max\)²

\(I\) = \(\frac{1}{2}\) × ( 8.85 × 10⁻¹² C²/N.m² ) × ( 3 × 10⁸ m/s ) × ( 5833.33 N/C )²

\(I\) = 45 × 10³ W/m²

\(I\) = 45 × 10³ W/m² × ( \(\frac{1 kW/m^2}{10^3W/m^2}\) )

\(I\) = 45 kW/m²

Therefore, the maximum intensity of an electromagnetic wave at the given frequency is 45 kW/m²

Taking into account the definition of wavelength, frecuency and propagation speed, the frequency of the waves in the tsunami is 2.59×10⁻⁴ Hz.

First of all, wavelength is the minimum distance between two successive points on the wave that are in the same state of vibration. It is expressed in units of length (m).

On the other side, frequency is the number of vibrations that occur in a unit of time. Its unit is s⁻¹ or hertz (Hz).

Finally, the propagation speed is the speed with which the wave propagates in the medium, that is, it is the magnitude that measures the speed at which the wave disturbance propagates along its displacement.

The propagation speed relate the wavelength (λ) and the frequency (f) inversely proportional using the following equation:

v = f×λ

In this case, you know:

Replacing:

0.194 m/s=f× 750 km

Solving:

f= 0.194 m/s ÷ 750 km

λ= 2.59×10⁻⁴ Hz

In summary, the frequency of the waves in the tsunami is 2.59×10⁻⁴ Hz.

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The normal force on the block is approximately 20.05 N.

Force describes the interaction between objects or between an object and its environment. It causes a change in the motion of the body it acts upon.

The normal force, which counteracts the force of gravity dragging the block downward, is the force generated by the slope acting perpendicular to its surface. As the incline has no friction, there is no force acting parallel to its surface.

To ascertain the parts of the force of gravity pulling on the block, we can apply trigonometry. There are two parts to the force of gravity: one that is parallel to the incline's surface and the other that is perpendicular to it. The weight of the block, mg, where m is its mass and g is its gravitational acceleration, is equal to the component of gravity perpendicular to the inclination. mg sin θ, where is the angle of the incline, is the component of gravity that is parallel to the incline.

To calculate the acceleration of the block moving down the incline, we can apply Newton's second law, F = ma. The component of gravity parallel to the inclination, or mg sin θ, represents the net force exerted on the block. As a result, we have:

\(mg sin(theta) = ma\)

To solve for a, we obtain:

\(a = g sin(theta)\)

Substituting the given values, we get:

\(a = 9.8 m/s^2 * sin(27°)\) ≈ \(4.69 m/s^2\)

Now that we know the normal force acting on the block, we can use Newton's second law once more. The component of gravity's force perpendicular to the incline is equal in magnitude to the normal force and moves in the opposite direction. As a result, we have:

\(mg cos(theta) = N\)

Inputting the values provided yields:

\(N = 2.3 kg * 9.8 m/s^2 * cos(27°)\) ≈ \(20.05 N\)

Therefore, the normal force on the block is approximately 20.05 N.

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Answer: 3,4,1,2,5

Explanation:

Potential energy is the energy that the skier have at the top of the slope as there will be a equillibrium which means zero velocity and maximum height.

The skier has potential energy at the top of the slope, which he will primarily transform into kinetic energy as he descends the hill. His body and the air, as well as his skis and the snow, will cause some of his PE to be transformed into thermal energy.

The ski lift, which elevated him against gravity, gave him his PE. In an electric motor, the lift transformed electrical energy into kinetic energy. A little portion of this energy was also converted to heat energy by friction in all of the moving elements.

The first law of thermodynamics is exemplified by the energy transformations. Examples of the second law include the losses caused by thermal energy diffusion.

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