Finding the initial and final values for the quantity that the capacitor or inductor opposes changing—i.e., the quantity that the reactive component is seeking to maintain constant—is the first stage.
This amount is voltage for capacitors and current for inductors. This amount is to be used as the "beginning" value because when the switch in a circuit is closed (or opened), the reactive component will try to keep that quantity at the same level as it was before the switch transition. This quantity's ultimate value is whatever it will be after an infinitely long period of time.
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object with the force of 50N and mass of 0.1 kg what is the acceleration?
Answer:
500ms^-2
Explanation:
F = 50N, m = 0.1kg, a = ?
F = ma
making a subject of the formula;
a = F/m
a = 50N/0.1kg
a = 500ms^-2
For a stirred tank that is cooled by a water coil, what is the consequences of neglecting coll dynamics? a • Thermal capacitance of the collis neglected with respect to the tank wall and the tank liquid • Energy balance is done only on the tank wall Ob • Thermal capacitance of the collis neglected with respect to the tank wall and the tank liquid • Energy balance is done only on the tank liquid oc • Thermal capacitance of the collis neglected with respect to the tank wall and the tank liquid
The thermal capacitance of the coil is neglected with respect to the tank wall and the tank liquid. Energy balance is done only on the tank liquid. Option C is the correct answer.
The consequence of neglecting the thermal dynamics of the cooling coil in a stirred tank can vary depending on the specific situation and the magnitude of the neglected effects. However, in general, neglecting the thermal capacitance of the cooling coil in relation to the tank wall and the tank liquid can have the following consequences:
Inaccurate temperature predictions: Neglecting the thermal capacitance of the cooling coil means that the cooling effect provided by the coil will not be properly accounted for in the energy balance of the system. This can lead to inaccurate temperature predictions within the tank. The coil may cool the tank contents faster or slower than anticipated, leading to deviations from the desired temperature profile.Inefficient cooling: Neglecting the thermal capacitance of the coil implies that the cooling coil is assumed to have an instantaneous cooling effect, without considering its own thermal inertia. This can result in inefficient cooling as the coil may not be able to transfer heat effectively to the cooling water due to the lack of thermal capacitance consideration. Consequently, the cooling process may be slower or less efficient than expected.Risk of equipment failure: If the cooling coil is subjected to rapid temperature changes due to neglecting its thermal capacitance, it can potentially lead to thermal stress and mechanical failure of the coil. The coil may not be designed to handle abrupt temperature variations, which can result in damage or reduced lifespan of the equipment.Energy consumption discrepancies: Neglecting the thermal capacitance of the coil can affect the overall energy balance calculations for the system. The energy required to operate the cooling coil may be underestimated, leading to discrepancies in energy consumption estimations. This can have implications for energy management and cost considerations.Learn more about capacitance at
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helppppppppppppppppppppppp
Explanation:
v²= u² + 2as
v= final velocity.
u= initial velocity.
a= acceleration.
s= distance.
Your car can brake with a deceleration of 6 m/s2. The car is initially going at 40 m/s.
a) How long will it take the car to come to a full stop?
b) If the car is 5 meters long, about how many car lengths should be kept between you and the car in front of you (assume the car in front of you comes to a stop immediately).
We have that for the Question "" it can be said that how long will it take the car to come to a full stop and the car lengths before a stop is
t=6.67L=27cars
From the question we are told
Your car can brake with a deceleration of 6 m/s2. The car is initially going at 40 m/s.
a) How long will it take the car to come to a full stop?
b) If the car is 5 meters long, about how many car lengths should be kept between you and the car in front of you (assume the car in front of you comes to a stop immediately).
Generally the equation for the Velocity is mathematically given as
\(v=u+at\\\\Therefore\\\\40=0+6t\\\\t=6.667s\\\\\)
b)
s=ut+1/2at^2
Therefore
\(S=0+1/2(6)(6.7)^2\\\\S=134.67m\)
Therefore
The car lengths before a stop is
L=134.67m/5
L=27cars
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A sprinter had the following speeds at different times during a race: 0 m/s at 0 s, 4 m/s at 2 s, 7 m/s at 4 s, 10 m/s at 6 s, 12 m/s at 8 s, and 10 m/s at 10 s. Plot these data on a speed-time graph. During what time intervals is the acceleration positive? Negative? Is the acceleration ever zero?
Answer:
Explanation:
We build graphs of speed and acceleration.
Acceleration is positive in the interval (0 - 8) s.
Acceleration is negative in the interval (8-10) s.
A 62.5-kg crate rests on a level floor at a shipping dock. The coefficients of static and kinetic friction are 0.687 and 0.317, respectively. What horizontal pushing force is required to (a) just start the crate moving and (b) slide the crate across the dock at a constant speed
Answer:
Here is a link for you
Explanation:
h t t p s : / / q u i z l e t . c o m / e x p l a n a t i o n s / q u e s t i o n s / a - 6 0 0 - k g - c r a t e - r e s t s - o n - a - l e v e l - f l o o r - a t - a - s h i p p i n g - d o c k - t h e - c o e f f i c i e n t s - o f - s t a t i c - a n d - k in e t i c - f r i c- 1 b b e 1 1 1 f - 8 e a 9 - 4 4 4 c - 8 5 d 2 - f a 2 e 3 0 d d f 0 b 9
Try it with out the spaces it does not let me with out the spaces. I think its easy to erase the spaces
a -ion (negative ion, one with extra negative charge )
Two trains sound identical horns of frequency 410 Hz. One train is stationary. The other is moving away from an observer, who heats a beat frequency of 35 Hz. How fast is the moving train going?
The speed of the moving train is approximately 33.5 m/s.
The beat frequency is given by the difference in frequency between the two horns, which is equal to the Doppler shift in frequency due to the motion of the moving train. Using the formula for the Doppler effect, we can solve for the speed of the train:
\(f_b = f_s\dfrac{(v + v_o)}{(v + v_s)}\)
where \(f_b\) is the beat frequency, \(f_s\) is the horn frequency, v is the speed of sound, \(v_o\) is the observer's speed, and \(v_s\) is the speed of the source.
We know that \(f_s\) = 410 Hz and \(f_b\) = 35 Hz. The speed of sound in air at standard temperature and pressure is approximately 343 m/s. Since the observer is stationary, \(v_o\) = 0.
Solving for \(v_s\), we get:
\(v_s = \dfrac{(f_s + f_b)}{f_s - 1} \times v\)
\(v_s\) = ((410 Hz + 35 Hz) / 410 Hz - 1) * 343 m/s
\(v_s\) = 33.5 m/s
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to avoid landing at the wrong airport or on the wrong runway, a
pilot should?
Pilots can prevent landing at the wrong airport or on the wrong runway by adhering to established procedures and employing various navigational aids.
Pilots can employ several measures to prevent landing at the wrong airport or on the wrong runway. Firstly, they should carefully review and follow established procedures provided by air traffic control (ATC) and the airport authority. This includes verifying the assigned runway and using the correct approach and landing charts. Secondly, pilots should make use of navigational aids such as instrument landing systems (ILS), global positioning systems (GPS), and visual aids like runway markings and signage.
These aids help pilots to accurately identify their intended destination and runway. Maintaining situational awareness throughout the flight is crucial, and pilots should cross-reference visual cues with navigational aids to ensure they are on the correct path. In cases of uncertainty or confusion, pilots should communicate with ATC to clarify any discrepancies or seek guidance. By diligently following procedures and utilizing navigational aids, pilots can significantly reduce the risk of landing at the wrong airport or on the wrong runway.
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What nuclear reaction is shown in the equation below?
A. Nuclear fusion
B. Nuclear fission
C. Positron emission
D. Beta decay
The carbon isotope was cobined with the proton to produce the nitrogen isotope hence it is a fusion reaction.
What is a nuclear fusion?The term nuclear fusion refers to a kind of reaction in which two nuclei fuse together to give rise to a single nuclei with the evolution of energy.
We can see that the carbon isotope was cobined with the proton to produce the nitrogen isotope hence it is a fusion reaction.
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Answer:
A. Nuclear fusion
Explanation:
got it right, trust
Comic-strip hero Superman meets an asteroid in outer space and hurls it at 800 m/s, as fast as a bullet. The asteroid is a thousand times more massive than Superman. In the strip, Superman is seen at rest after the throw. Taking physics into account, what would be his recoil speed (in km/s)?
Answer:
800km/s
Explanation:
Initial momentum = final momentum
the total momentum is zero, Before the release of the asteroid , but Superman and the asteroid are not moving.
So, according to the Conservation of momentum the total momentum when the astronaut is been thrown will equals to zero . Then we can say
Initial momentum = final momentum
Because the momentum of the Superman immediately the asteroid is been thrown is equal to the momentum of the asteroid
Momentum =(mass ×velocity)
the mass of the asteroid i= 1000M
Given velocity = 800 m/s,
momentum =(1000M)(800 m/s)
= 800,000M m/s.
to get the answer, we need to divide by Superman's mass, M, which gives his recoil velocity of 800,000 m/s.
But we're told to convert to km/ s
We know that 1m/s=0.001km/s
=(800,000M m/s)× (0.001km/s)
=800km/s
Therefore, his recoil speed (in km/s) is 800km/s
As the first five elements in group 15 are considered in order of increasing atomic number.
As the atomic number of group 15 elements increases, the first ionization energy drops/decrease. (option 1).
The energy needed to remove one electron from an atom is known as the ionization energy.
The members of the group 15 are N, P, As, Sb, Bi, and Mc.
The initial ionization energy is the force required to expel an electron from a neutral atom in the gaseous state. The general electron configuration for the valence shell of the elements in group 15 is ns² np³, where n is the primary quantum number (the same number of the row in which the element is).
As you move lower in the group, n rises, the valence electrons are farther from the nucleus, which means that their attraction to the nucleus is diminished. As a result, as you move down in the group, the electrons will be more readily removed, requiring less energy to do so.
This enables you to forecast the following arrangement in the initial ionization energies:
N > P > As > Sb > Bi > Mc
The question is incomplete, it should be:
As the first five elements in group 15 are considered in order of increasing atomic number, first ionization energy
(1) decreases
(2) increases
(3) decreases, then increases
(4) increases, then decreases
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The electric force between two charged balloons is 0.12 newtons. If the distance between the two balloons is halved, what will be the new force?
A.
0.03 newtons
B.
0.06 newtons
C.
0.36 newtons
D.
0.48 newtons
Answer:
d. 0.48
Explanation:
3000 centímetros cúbicos de un gas ideal a 80°C se expande hasta un volumen de 1000 cm³ a presión constante. ¿Cuál es la temperatura final?
Responder:
117,6 K
Explicación:
Dado :
V1 = 3000 cm³
T1 = 80 ° C = 273 + 80 = 353 K
V2 = 1000 cm³
T2 =?
La ley de Fromm Charles;
3000/353 = 1000 / T2
3000T2 = 353 * 1000
T2 = 353000/3000
T2 = 117. 67 k
can anyone help me please
Answer:
Gravity.
Rocket ships.
Ball.
Basketball.
Explanation:
Gravity has to do a lot with air. It puts the planets in there area.
Rocket Ship has to do a lot with air. If i'm right, they calculate the area, weather, about the air.
A ball gets throwed in the air, which gravity comes into place.
Basketball is also a similar example to a ball.
A boy weighs 400 N. What is his mass?
Answer:
40kg(88pounds)
Explanation:
.
.
.
.
.
.
Answer: ≈ 40.8 kilograms (89.9 pounds)
Explanation: Well, assuming the boy is on Earth, then the gravitational acceleration is approximately 9.8 m/s^2.
So, we get: mass = weight / gravitational acceleration
Put two and two together and you get 400-N / 9.8 m/s^2 ≈ 40.8 kg (89.9 pounds).
HELP PLS
In the context of climate change, is “positive feedback” a good thing?
What must happens within earth for a volcano to form
Answer:
Volcanoes on Earth form from rising magma. ... Magma also rises when these tectonic plates move toward each other. When this happens, part of Earth's crust can be forced deep into its interior. The high heat and pressure cause the crust to melt and rise as magma.
3) A block with an unknown mass rests on a rough table. Attached to the mass is a
string which is attached to a 12 kg mass that hangs over the edge of the table via a
pulley. The coefficient of friction is 0.35. When released from rest, the system
reaches a speed of 8 m/s after traveling a distance of 6 m.
a. Calculate the acceleration of the system.
b. What equation can you use to represent the force of friction acting on the
unknown mass.
c. Write out Newton's Second Law and solve for the unknown mass.
a. The acceleration of the system is 0.21 m/s^{2}
b. The equation of the force of friction is -
tension force - force of friction = unknown mass x its acceleration and force of friction is equal to product of coefficient of friction and normal force acting on unknown mass .
c. Newton's second law of motion applies when there are unbalanced forces acting on an object. According to the second law, the mass and the net force acting on the object both affect how quickly an object is accelerating . An object's acceleration is directly proportional to the net force applied and inversely proportional to the object's mass. An object's acceleration increases as the amount of force exerted on it does. A decreasing acceleration is caused by an increase in an object's mass.
The unknown mass is nearly equal to 30 kg .
What is acceleration ?
the rate at which the speed and direction of a moving object vary over time is termed as acceleration . An object going straight ahead when it accelerates or decelerates, is said accelerated. Even if the speed is constant, motion on a circle accelerates because the direction is always shifting. Both effects contribute to the acceleration for all other motions.
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Bill is farsighted and has a near point located 125 cm from his eyes. Anne is also farsighted, but her near point is 75.0 cm from her eyes. Both have glasses that correct their vision to a normal near point (25.0 cm from the eyes), and both wear the glasses 2.0 cm from the eyes. Relative to the eyes, what is the closest object that can be seen clearly (a) by Anne when she wears Bill's glasses and (b) by Bill when he wears Anne's glasses
Answer:
a) The closest object Anne can see, while wearing Bill's glasses is at approximately 22.39 cm relative to her eyes
b) The closest object Bill can see while wearing Anne's glasses is at approximately 26.38 cm relative to his eyes
Explanation:
The point where Bill has a near point = 125 cm
The point where Anne has a near point = 75.0 cm
Their vision are both corrected to the normal near point = 25.0 cm
The distance of their glasses from the eye, d = 2.0 cm
The lens formula is presented as follows;
\(\dfrac{1}{f} =\dfrac{1}{d_0} +\dfrac{1}{d_i}\)
The required distance of the of the object from Bill's glass, \(d_{oB}\) = 25 cm - 2.0 cm = 23.0 cm
The distance of the of the image from Bill's glass, \(d_{iB}\) = -(125 cm - 2.0 cm) = -123 cm
Therefore, for Bill, we have;
\(\dfrac{1}{f_B} =\dfrac{1}{d_{0B}} +\dfrac{1}{d_{iB}}\)
Plugging in the values gives;
\(\dfrac{1}{f_B} =\dfrac{1}{23} -\dfrac{1}{123} = \dfrac{100}{2,829}\)
Therefore;
\(f_B\) = 2,829/100 cm = 28.29 cm
The required distance of the of the object from Anne's glass, \(d_{oA}\) = 25 cm - 2.0 cm = 23.0 cm
The distance of the of the image from Anne's glass, \(d_{iA}\) = -(75 cm - 2 cm) = -73 cm
The focal length for Anne is therefore;
\(\dfrac{1}{f_A} =\dfrac{1}{d_{0A}} +\dfrac{1}{d_{iA}}\)
Plugging in the values gives;
\(\dfrac{1}{f_A} =\dfrac{1}{23} -\dfrac{1}{73} = \dfrac{50}{1,679}\)
Therefore, we have;
\(f_A\) = 1,679/50 cm = 33.58 cm
a) When Anne wears Bill's lasses, we have;
\(\dfrac{1}{f_B} =\dfrac{1}{d_{0A}} +\dfrac{1}{d_{iA}}\)
Therefore, we get;
\(\dfrac{1}{28.29} =\dfrac{1}{d_{0A}} -\dfrac{1}{73}\)
\(\dfrac{1}{d_{0A}} = \dfrac{1}{28.29} + \dfrac{1}{73} = \dfrac{10,129}{206,517}\)
\(d_{0A}\) ≈ 20.39 cm
The distance of the closest object Anne can see, from her eye, \(d_{oe}\) = \(d_{0A}\) + d
∴ \(d_{oe}\) ≈ 20.39 cm + 2.0 cm = 22.39 cm
The distance of the closest object Anne can see, from her eye, \(d_{oe}\) ≈ 22.39 cm
b) The closest object that can be seen when Bill wears Anne's glasses, we have;
\(\dfrac{1}{f_A} =\dfrac{1}{d_{0B}} +\dfrac{1}{d_{iB}}\)
Therefore;
\(\dfrac{1}{33.58} =\dfrac{1}{d_{0B}} -\dfrac{1}{123}\)
\(\dfrac{1}{d_{0B}} = \dfrac{1}{33.58} +\dfrac{1}{123} = \dfrac{7,829}{206,517}\)
∴ \(d_{oB}\) ≈ 26.38 cm
The closest object Bill can see while wearing Anne's glasses, \(d_{oB}\) ≈ 26.38 cm.
if you throw all three rocks with the same initial speed, which will be moving the fastest when it hits the ground?
When throwing three rocks with the same initial speed, the rock that hits the ground fastest is the one that has the least amount of air resistance.
The amount of air resistance depends on the size, shape, and mass of the object being thrown, as well as the speed at which it is thrown. Therefore, the rock that is the smallest , most streamlined, and lightest will hit the ground fastest.Additionally, the angle at which the rock is thrown will also affect its speed. If the rock is thrown at a higher angle, it will take longer to reach the ground, whereas if it is thrown at a lower angle, it will hit the ground faster. The force of gravity also plays a role in determining the speed at which the rock hits the ground.In conclusion, if three rocks are thrown with the same initial speed, the one that will be moving the fastest when it hits the ground is the one that has the least amount of air resistance, is the smallest and most streamlined, and is thrown at a lower angle.for more such question on resistance
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A novelty clock has a 0.0185-kg mass object bouncing on a spring which has a force constant of 1.45 N/m.
a) What is the maximum velocity of the object, in meters per second, if the object bounces 3.35 cm above and below its equilibrium position?
b) How much kinetic energy, in joules, does the object have at its maximum velocity?
The object is approximately 0.862 m/s, and its corresponding kinetic energy is approximately 0.0077 J.
What is the kinetic energy of the object at its maximum velocity?The maximum velocity, we need to determine the amplitude of the oscillation first. Since the object bounces 3.35 cm above and below its equilibrium position, the total displacement is 2 * 0.0335 m = 0.067 m.
Using the equation for the maximum velocity of a mass-spring system, v_max = A * ω, where A is the amplitude and ω is the angular frequency, we can calculate ω. The angular frequency is given by ω = √(k / m), where k is the force constant and m is the mass.
Plugging in the values, ω = √(1.45 N/m / 0.0185 kg) ≈ 12.87 rad/s. Now we can calculate the maximum velocity: v_max = 0.067 m * 12.87 rad/s ≈ 0.862 m/s.
b) The kinetic energy at the maximum velocity, we use the formula KE = (1/2) * m * v^2, where m is the mass and v is the velocity. Plugging in the values, KE = (1/2) * 0.0185 kg * (0.862 m/s)^2 ≈ 0.0077 J.
The maximum velocity of the object is approximately 0.862 m/s, and its corresponding kinetic energy is approximately 0.0077 J.
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A rock is thrown downwards from the edge of the Grand Canyon. With what velocity will it hit the donkey-riding tourist who is 40 m below?
Methods to prevent Air pollution from Microwave oven
Methods to prevent Air pollution from Microwave oven are Ensure proper ventilation,Use microwave-safe containers,Clean the microwave regularly,Avoid burning food and Dispose of damaged microwave ovens responsibly.
To prevent air pollution from microwave ovens, there are several effective methods you can follow:
1. Ensure proper ventilation: Make sure your microwave oven is installed in a well-ventilated area. Good ventilation helps in preventing the accumulation of pollutants in the air.
2. Use microwave-safe containers: Always use microwave-safe containers to heat or cook food. Using inappropriate containers can release harmful chemicals or toxins into the air.
3. Clean the microwave regularly: Regularly clean the inside of your microwave oven to remove any food residue or spills that can generate smoke or unpleasant odors when heated.
4. Avoid burning food: Be cautious when heating or cooking food in the microwave to prevent burning. Burning food releases smoke and harmful particles that can contribute to air pollution.
5. Opt for alternative cooking methods: Instead of relying solely on the microwave, consider using other cooking methods like stovetops, ovens, or slow cookers. This diversification reduces the frequency of microwave oven use and thus decreases air pollution.
6. Dispose of damaged microwave ovens responsibly: If your microwave oven is damaged beyond repair, dispose of it responsibly at an authorized recycling center. Improper disposal can contribute to environmental pollution.
By implementing these preventive measures, you can minimize air pollution associated with microwave oven usage and contribute to a cleaner and healthier environment. Remember to prioritize safety and proper usage guidelines provided by the manufacturer.
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someone please answer this ill give you brainliest and your getting 100 points.
Answer: the answers would be both of the ones in the middle
Explanation:
the one where it says plant more trees
and the other one that says paint ore cover black asphalt streets
A car accelerates at -1 m/s2. What is its final speed (in m/s) at the end of 4 seconds if it started at 1 m/s? (round
to the nearest whole number)
This is an exercise in Rectilinear Uniformly Varied Motion (MRUV) is a type of motion in which an object moves in a straight line and experiences changes in its velocity at a constant rate. In this type of motion, the acceleration of the object remains constant over time.
The distinctive feature of the MRUV is that the velocity of the object changes uniformly, that is, its velocity increases or decreases by a constant amount in each unit of time. If the object experiences a positive acceleration, its velocity increases with time. On the other hand, if the object experiences a negative acceleration, its speed decreases.
In an MRUV, constant acceleration has a direct impact on displacement and the time it takes for the object to reach a certain speed. Also, the direction of the acceleration determines whether the object is accelerating or decelerating relative to its initial motion.
This type of movement is found in various situations of daily life, such as the launch of an object upwards and its subsequent fall, the movement of cars on a road with acceleration or braking, or even the study of bodies in free fall.
To solve this problem, we can use the kinematics formula for constant acceleration:
Vf = V₀ + a × t
Where:
Vf is the final speedV₀ is the initial velocitya is the accelerationt is the timeIn this case, the initial velocity (vi) is 1 m/s, the acceleration (a) is -1 m/s^2 (negative because it indicates deceleration), and the time (t) is 4 seconds.
Substituting these values into the formula, we get:
Vf = V₀ + a × t
Vf = 1 m/s + (-1 m/s²) × 4 s
Vf = 1 m/s - 4 m/s
Vf = -3 m/s
The final velocity of the car at the end of 4 seconds would be -3 m/s. Negative velocity indicates that the car is slowing down.
What is the speed of light? What is the speed of sound?
Answer:
speed of light simulating traveling at the speed of light. Speed of light, speed at which light waves propagate through different materials. In particular, the value for the speed of light in a vacuum is now defined as exactly 299,792,458 metres per second
The speed of sound is the distance travelled per unit of time by a sound wave as it propagates through an elastic medium
How long does it take the principal to run to our classroom, if the distance is 125 meters, and he accelerates,
from rest, at a rate of 4 m/s^2?
answer
The kinematics to find the time to go from the office to the living room is: 2.81 s
Given Parameters
The distance x = 125 n The acceleration a = 4 m / s²To find
The timeKinematics allows us to find the relationships between the position, velocity and acceleration of bodies, let's use the relationship
x = v₀ t + ½ a t²
Where x is the position, v₀ the initial velocity, at acceleration and t the time
In this case, as he leaves the office, the initial velocity is zero.
x = ½ a t²
t = \(\sqrt{\frac{2x}{a} }\)
Let's calculate
t = \(\sqrt{\frac{2 \ 125}{4} }\)
t = 2.81 s
In conclusion, using the kinematics, we find that the time to go from the office to the classroom is: 2.81 s
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How many excess electrons must be present on each sphere if the magnitude of the force of repulsion between them is
what affects the strength of an electric field? FOR SCIENCE
Answer:
The electric field strength is dependent upon the quantity of charge on the source charge (Q) and the distance of separation (d) from the source charge.