The ending balance would be $11,268.55 after 3 years.
If you deposit $10,000 at 1.85% simple interest, compounded daily, what would your ending balance be after 3 years?The ending balance after 3 years is $11,268.55 for $10,000 deposited at 1.85% simple interest, compounded daily.
To calculate the ending balance after 3 years,
we can use the formula for compound interest which is given by;A = P (1 + r/n)^(n*t)Where A is the ending amount, P is the principal amount, r is the annual interest rate, n is the number of times
the interest is compounded per year and t is the number of years.
Using the given values, we get;P = $10,000r = 1.85%n = 365t = 3 years
Substituting the values in the formula, we get;A = 10000(1 + 0.0185/365)^(365*3)A = $11,268.55
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In the figure below, m<2=35 and m
Answer:
36 Degrees
Step-by-step explanation:
First the entire angle of BAC is 71 degrees, so all you have to do is subtract the known angle (2) by the entire angle. 71-35= 36. So that means the measure of angle 1 is 36 degrees.
Worth 60 points for a rapid reply- find the area of each regular polygon. Answers are rounded to the nearest whole number.
The area of the regular polygons with 12 sides(dodecagon) and 5 sides (pentagon) are 389.06 in² and 19.87 in² respectively.
How to calculate for the area of the polygonArea of regular polygon = 1/2 × apothem × perimeter
perimeter = (s)side length of octagon × (n)number of side.
apothem = s/[2tan(180/n)].
11 = s/[2tan(180/12)]
s = 11 × 2tan15
s = 5.8949
perimeter = 5.8949 × 12 = 70.7388
Area of dodecagon = 1/2 × 11 × 70.7388
Area of dodecagon = 389.0634 in²
Area of pentagon = 1/2 × 5.23 × 7.6
Area of pentagon = 19.874 in²
Therefore, the area of the regular polygons with 12 sides(dodecagon) and 5 sides (pentagon) are 389.06 in² and 19.87 in² respectively.
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796154 rounded to the nearest ten thousand
Answer:
800,000
Step-by-step explanation:
the number that we are rounding is 90,000 which is gonna make the seven go up to 8
Answer:
800,000 is the answer.
Step-by-step explanation:
The nearest 10,000 would change the answer to 800,00.
Triangle A is the pre-image, and triangle B is the image. Find the scale factor for this dilation if the center of dilation is at (0,0)
Answer:
The scale factor is 3
Step-by-step explanation:
6/2=3 (one of the triangles sides)
HELPPPP IMA CRYYYYYYYYYY
help meeeee
Answer:
B
Step-by-step explanation:
Your answer is b because when u solve the equation u get that answer.
Hope this helps:)
pls mark brainlist
Answer:
b maybe..?
i am not too sure tho
Solve the equation A
B
=
B
C
AB=BC for A
A, assuming that A
,
B
A,B and C
C are square matrices and B
B is invertible.
We have solved the equation AB=BC for A, assuming that A, B, and C are square matrices and B is invertible, then the solution is A=C B⁻¹.
First, let's take a look at the equation AB=BC. This is an equation that involves matrices, which are essentially rectangular arrays of numbers. In this case, we have three matrices: A, B, and C. The equation tells us that the product of A and B is equal to the product of B and C.
Now, we want to solve this equation for A. This means that we want to isolate A on one side of the equation and have everything else on the other side. To do this, we can use matrix algebra.
One property of matrices is that we can multiply both sides of an equation by the inverse of a matrix without changing the solution. Since we know that B is invertible, we can multiply both sides of the equation by B⁻¹, the inverse of B:
AB B⁻¹ = BC B⁻¹
Now, we can simplify the left side of the equation, because B times its inverse gives us the identity matrix I:
A I = C B⁻¹
Again, we can simplify the left side of the equation, because anything multiplied by the identity matrix stays the same:
A = C B⁻¹
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the following are the results of a hypothesis test for the difference between two population means: assume that the populations are normally distributed with unknown but equal variances. what is the p-value for the test?
The process of finding the p-value in a hypothesis test for the difference between two population means can be explained, given that the populations are normally distributed with unknown but equal variances.
1. Conduct the hypothesis test using either the t-test or z-test depending on the sample size and available information.
2. Calculate the test statistic (either t or z) using the sample means, sample sizes, and pooled variance.
3. Determine the degrees of freedom (df) for a t-test, which is calculated as (n1 - 1) + (n2 - 1), where n1 and n2 are the sample sizes.
4. Decide whether the test is one-tailed or two-tailed, based on the alternative hypothesis.
5. Use the test statistic and degrees of freedom (for t-test) to find the p-value from the appropriate distribution table (t-distribution or standard normal distribution).
Once you have the p-value, you can compare it with your chosen significance level (α) to decide whether to reject or fail to reject the null hypothesis.
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What is the nth term of the sequence below?
2, 6, 12, 20, . . .
A. \(n {}^{2} \: + \: 1\)
B. \(3n\)
C. \(n(n \: + \: 1)\)
D. \( {n}^{2} \: - \: 1\)
Answer:
Option C
Kindly award branliest
Step-by-step explanation:
Tn = n(n + 1)
T1 = 1(1 +1) = 1(2) = 2
T2 = 2(2+1) = 2(3) =6
T3 = 3(3 + 1) = 3(4) = 12
T4 = 4(4 + 1) = 4(5) = 20
... It obeys
HELP ME WITH THIS NOOW PLEASEEE
d...................................
if an adult is chosen randomly from the town, what is the probability that they have a high school degree or some college, but have no college degree? round your answer to the nearest thousandth.
The probability that the chosen adult have high school or some college degree but no college degree is 0.683.
From the definition of probability we know that,
Probability of Event = (Outcomes favorable to that event)/(Total number of outcomes under that event)
Total number of adults in the town is given by = 4286 + 6313 + 3033 + 1886 = 15518.
The number of adults have high school degree only = 4286
The number of adults have some college degree only = 6313
The number of adults have high school or some college degree but no college degree = 4286 + 6313 = 10599.
The probability that the chosen adult have high school or some college degree but no college degree is given by
= 10599/15518 [According to definition of probability]
= 0.683 [Rounding off to nearest thousandth]
Hence, probability that the chosen adult have high school or some college degree but no college degree is 0.683.
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The question is incomplete. The complete question will be -
0.326 as a percentage
Answer: 32.6%
Step-by-step explanation:
percentage is whatever number you have x100 which would move the decimal point right 2 points and in this case would move the decimal from .326 to 32.6
If a 48 gal hot water tank holds 400 lb of water, what weight of water will a 65 gal tank hold?
A 65 gal tank hold will holdlb of water.
(Round to the nearest whole number as needed.)
Using the cross-multiplication method we know that the 65 gallons of water tank can hold 542 lb of water.
What is cross-multiplication?For the following, we employ the cross-multiplication technique:
Cross multiplication is a technique used to compare fractions and ratios. We can determine their equality, greatness, or lesserness using this.
Finding the value of variables in an expression is another usage for it.
So, we know that:
48 gallons water tank = 400 lb water
Then,
65 gallons water tank = ?
Use cross-multiply as follows;
48/400 = 65/x
48x = 65*400
48x = 26,000
x = 26,000/48
x = 541.66
Rounding off: 542 lb water
Therefore, using the cross-multiplication method we know that the 65 gallons of water tank can hold 542 lb of water.
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Please answer my question
Take the points A(2,2) B(3,4) C(5,2) and D (5,4). Apply a scale factor of 2 to only the x values. What are the coordinates of your new set of points?
Answer:
The set of coordinates are;
A’( 4,2)
B’(6,4)
C’(10,2)
D’(10,4)
Step-by-step explanation:
Here, we want to get a set of new points by dilating the x coordinates of the former points by 2
Using the scale factor, we simply are going to multiply the x-coordinate values by 2
Thus we have
A’( 4,2)
B’(6,4)
C’(10,2)
D’(10,4)
help please i don’t understand and this is do today :/!!
Answer:
A.15
Step-by-step explanation:
These two triangles are congruent triangles. This means that the side measurements can be found through a single multiplicative number.
All you have to do is divide 49 by 23 and get 2.130434783. You need that number to be specific
Next you want to multiply that number by the side length that corresponds to the length you are trying to find. In this case that is 7.
7 x 2.130434783=14.9
14.9 rounds to 15
Suppose that A and B are events on the same sample space with PlA) = 0.5, P(B) = 0.2 and P(AB) = 0.1. Let X =?+1B be the random variable that counts how many of the events A and B occur. Find Var(X)
The variance of X is 0.09.
Formula used: Variance is the square of the standard deviation. T
he formula to calculate variance of a discrete random variable X is given by:
Var(X) = E[X²] - [E(X)]²Calculation:
P(B) = 0.2P(A)
= 0.5P(AB) =
0.1
By definition,
P(A U B) = P(A) + P(B) - P(AB)
⇒ P(A U B) = 0.5 + 0.2 - 0.1
⇒ P(A U B) = 0.6
Now,E[X] = E[1B + ?]
⇒ E[X] = E[1B] + E[?]
Since 1B can have two values 0 and 1.
So,E[1B] = 1*P(B) + 0*(1 - P(B))
= P(B)
= 0.2P(A/B)
= P(AB)/P(B)
⇒ P(A/B)
= 0.1/0.2
= 0.5
So, the conditional probability distribution of ? given B is:
P(?/B) = {0.5, 0.5}
⇒ E[?] = 0.5(0) + 0.5(1)
= 0.5⇒ E[X]
= 0.2 + 0.5
=0.7
Now,E[X²] = E[(1B + ?)²]
⇒ E[X²] = E[(1B)²] + 2E[1B?] + E[?]²
Now,(1B)² can take only 2 values 0 and 1.
So,E[(1B)²] = 0²P(B) + 1²(1 - P(B))= 0.8
Also,E[1B?] = E[1B]*E[?/B]⇒ E[1B?] = P(B)*E[?/B]= 0.2 * 0.5 = 0.1
Putting the values in the equation:E[X²] = 0.8 + 2(0.1) + (0.5)²= 1.21Finally,Var(X) = E[X²] - [E(X)]²= 1.21 - (0.7)²= 0.09
Therefore, the variance of X is 0.09.
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solve the 3 × 3 system shown below. enter the values of x, y, and z. x 2y – z = –3 (1) 2x – y z = 5 (2) x – y z = 4
The solution to the given system of equations is x = 2, y = -1, and z = 1.
What are the values of x, y, and z that solve the given system of equations?To solve the system of equations, we can use methods such as substitution or elimination. Here, we will use the method of elimination to find the values of x, y, and z.
First, let's eliminate the variable x by multiplying equation (1) by 2 and equation (3) by -1. This gives us:
2x + 4y - 2z = -6 (4)
-x + y - z = -4 (5)
Next, we can subtract equation (5) from equation (4) to eliminate the variable x:
5y - z = 2 (6)
Now, we have a system of two equations with two variables. Let's eliminate the variable z by multiplying equation (2) by 2 and equation (6) by 1. This gives us:
4x - 2y + 2z = 10 (7)
5y - z = 2 (8)
Adding equation (7) and equation (8), we can eliminate the variable z:
4x + 5y = 12 (9)
From equation (6), we can express z in terms of y:
z = 5y - 2 (10)
Now, we have a system of two equations with two variables again. Let's substitute equation (10) into equation (1):
x + 2y - (5y - 2) = -3
x - 3y + 2 = -3
x - 3y = -5 (11)
From equations (9) and (11), we can solve for x and y:
4x + 5y = 12 (9)
x - 3y = -5 (11)
By solving this system of equations, we find x = 2 and y = -1. Substituting these values into equation (10), we can solve for z:
z = 5(-1) - 2
z = -5 - 2
z = -7
Therefore, the solution to the given system of equations is x = 2, y = -1, and z = -7.
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Julian describes an angle in the triangle using these statements.
GH is the adjacent side.
HK is the opposite side.
GK is the hypotenuse.
Triangle G H K is shown. Angle G H K is a right angle.
Which angle(s) is Julian describing?
∠G
∠H
∠K
∠H and ∠K
Step-by-step explanation:
The hypotenuse is the longest side of the right-angled triangle. The angle about which Julian is describing is ∠G.
Answer:
A. <G
Step-by-step explanation:
Took the test on edge, hope this helps
PLEASE HELP. I WILL MARK BRAINLIEST!!!!!
Answer:
coefficient is 1/6
Step-by-step explanation:
=-2a/3+5a/6-1/6
= a/6 -1/6
= 1/6(a -1)
coefficient is 1/6
Determine the number of distinguishable arrangements for each of the following words.
a. SASKATOON
b. MISSISSIPPI
there are 45,360 distinguishable arrangements of the letters in the word "SASKATOON" and there are 34,650 distinguishable arrangements of the letters in the word "MISSISSIPPI".
a. SASKATOON:
To determine the number of distinguishable arrangements of the word "SASKATOON", we can use the formula for permutations of indistinguishable objects, which is n!/a!b!c!…, where n is the total number of objects and a, b, c,… are the frequencies of each indistinguishable object. In this case, there are 9 letters in the word "SASKATOON", but some of them are repeated. Specifically, there are 2 S's, 2 A's, and 2 O's. Using the formula, we get:
9!/(2!2!2!) = 9876543/(222) = 45,360
Therefore, there are 45,360 distinguishable arrangements of the letters in the word "SASKATOON".
b. MISSISSIPPI:
To determine the number of distinguishable arrangements of the word "MISSISSIPPI", we can use the same formula for permutations of indistinguishable objects. In this case, there are 11 letters in the word "MISSISSIPPI", but some of them are repeated. Specifically, there are 4 I's, 4 S's, and 2 P's. Using the formula, we get:
11!/(4!4!2!) = 34,650
Therefore, there are 34,650 distinguishable arrangements of the letters in the word "MISSISSIPPI".
In summary, the number of distinguishable arrangements of a word can be found using the formula for permutations of indistinguishable objects, which takes into account the frequency of each repeated letter. By applying this formula to the words "SASKATOON" and "MISSISSIPPI", we find that there are 45,360 and 34,650 distinguishable arrangements, respectively.
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what is the gcf of 35, 20,15
Answer:
Prime factorisation of the numbers -
\( \\ \sf \: 35 = 7 \times \underline5 \\ \\ \sf \: 20 = \underline5 \times 4 \\ \\ \sf \: 15 = 3 \times \underline5 \\ \)
As, we can see that the 5 is common in the both three numbers. So,
GCF, greatest common factor (35, 20, 15) = 5
Suppose that X has a lognormal distribution with parameters θ = 10 and ω2 = 16. Determine the following: (a) P(X 1500) (c) Value exceeded with probability 0.7.
the value exceeded with probability 0.7.
Given that X has a lognormal distribution with parameters θ = 10 and ω² = 16.Now, we have to determine the following:(a) P(X > 1500)(c) Value exceeded with probability 0.7.Solution:For the lognormal distribution, we have,X ~ logN(θ, ω²)Now, taking the logarithm of both sides, we have,log(X) ~ N(θ, ω²)So, we have log(X) ~ N(10, 4)Now, for normal distribution, we have, P(X > a) = 1 - P(X < a)Now, let Z = (X - θ)/ωThen, Z ~ N(0, 1)So, P(X > 1500) = P(Z > (log(1500) - 10)/2)P(Z > (log(1500) - 10)/2) = P(Z > (log(15) + 1)/2)Now, the value of P(Z > 1.407) is 0.0808 (rounded off up to four decimal places) from the standard normal distribution table.Hence, P(X > 1500) = P(Z > 1.407) = 0.0808. Therefore, P(X > 1500) = 0.0808.The value exceeded with probability 0.7 is given by the 0.7-quantile of the lognormal distribution which can be calculated as follows:z = qnorm(0.7) = 0.5244The 0.7-quantile of the normal distribution is (θ + ωz) = (10 + 4(0.5244)) = 12.0976.Now, since X is log-normally distributed, e^(12.0976) = 17567.75 is the value exceeded with probability 0.7.
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According to given information, P(X < 1500) ≈ 0.9996 and the value exceeded with probability 0.7 is about 179152.9.
X has a lognormal distribution with parameters θ = 10 and ω2 = 16.
(a) P(X < 1500)
To find the probability that X is less than 1500 we need to find the cumulative distribution function (CDF) first.
Cumulative distribution function is given as:
CDF of X = F(X)
= P(X ≤ x)
= Φ [(ln(x) - θ) / ω]
Here, θ = 10 and ω = √16 = 4.
Then, \(F(X) = P(X ≤ x) = Φ [(ln(x) - 10) / 4]\)
To find P(X < 1500), substitute x = 1500 in the above equation:
\(F(X) = Φ [(ln(1500) - 10) / 4] ≈ 0.9996\)
\(P(X < 1500) = F(X) ≈ 0.9996\)
So, \(P(X < 1500) ≈ 0.9996\).
(c) Value exceeded with probability 0.7.
To find the value exceeded with probability 0.7, we need to use the inverse of the CDF of X.
In other words, we need to find the value of x such that F(X) = P(X ≤ x) = 0.7.
To find the required value, we need to use the inverse function of the standard normal distribution, denoted as Zα, where α is the area under the standard normal curve to the left of Zα.
That is: Zα = Φ-1 (α)
From the given information, we can see that:
CDF of X = F(X) = Φ [(ln(x) - θ) / ω]
Here, θ = 10 and ω = √16 = 4.
So, \(F(X) = Φ [(ln(x) - 10) / 4]\)
\(F(X) = P(X ≤ x) = 0.7\)
Now, we want to find the value x such that \(F(X) = P(X ≤ x) = 0.7\).
That is, \(Φ [(ln(x) - 10) / 4] = 0.7\)
This means,\([(ln(x) - 10) / 4] = Φ-1 (0.7) = 0.5244\)
On solving this equation, we get:
\(ln(x) = 0.5244 x 4 + 10 ≈ 12.0976\)
\(x ≈ e12.0976 ≈ 179152.9\) (rounded to the nearest tenth)
So, the value exceeded with probability 0.7 is about 179152.9.
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Melissa earns 4% commission on everything she sells. Last month she sold $5,819 and this month she sold $3,792. How much money has Melissa earned for the two months?
Answer:
Step-by-step explanation:
Melissa earned $5,819 x 4% = $232.76 in commission for the first month.
Melissa earned $3,792 x 4% = $151.68 in commission for the second month.
So, Melissa earned a total of $232.76 + $151.68 = $384.44 for the two months.
Who needs some words of motivation?
Answer:
I do
Step-by-step explanation:
Answer:
i believe in u, good luck and you got this :))
Step-by-step explanation:
what is the quotient of the expression
\( \frac{21a {}^{3} b - 14ab {}^{2} + 7ab}{7ab} \)
ayeee i need the values nowww pleaseee!!
factor completely 28x^2-15x^2yz^2
If the absolute value of your correlation is very close to 0, your error in prediction will be?
a) The predicted college GPA be for a student whose current high school GPA 3.2 is 2.97
b) The prediction error would be very high.
c) The point is intercept.
d) The predicted score of Y based on a known value of X should be represented as Y'
Given,
Slope = 0.704
Intercept = 0.719
(a) For aa =0.719, bb =0.704, and XX =3.2,
the predicted college GPA is,
Y′ = 0.719+(0.704⋅3.2)
= 2.9718
(b) For there is no correlation, the assumed two variables are considered to be independent, so predicting through linear equation them would not be justifiable if they are not linearly related. So the prediction error would be very high.
(c) The point is "intercept" where the estimated regression line is observed meeting the y-axis.
(d) As the alternate hypothesis is set up, rejecting any possible linear relationship, hence it is symbolized through "≠≠", hence it is non-directional.
(e) From part (a), we represented the predicted score though Y′Y′.
The question is incomplete. Completed question will be given below the answer.
Completed question:
Using the regression formula with a slope = .704 and intercept = .719,
a) what would the predicted college GPA be for a student whose current high school GPA = 3.2?
- 2.69
- 2.97
- 3.00
- 3.20
b) If the absolute value of your correlation is very close to 0, your error in prediction will be:
- High
- Low
- Very low
- 0
c) Which of the following is the point at which the regression line crosses the y-axis?
- Intercept
- Predicted point
- Criterion point
- Slope
d) In the t-test for independent samples, the actual statistical test is _____.
- Nondirectional
- Unidirectional
- Multidirectional
- Quasidirectional
e) How would you represent the predicted score of Y based on a known value of X?
- y
- y-intercept
- Y'
- Y = Xa
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If coin initially flipped is equally likely to be coin 1 or coin 2, then the probability that head will come up on tossing the coin = 12×0.7+12×0.6=0.65.
We are given the probability that head will come up on tossing the coin, when a coin initially flipped is equally likely to be coin 1 or coin 2 as;P(head will come up) = 12 × 0.7 + 12 × 0.6 = 0.65Now, let’s understand this solution by breaking it down into different steps:
Step 1: Calculation of probability for coin 1Let p(H) and p(T) be the probabilities of the coin 1 being tossed head and tail respectively.Then, we have:p(H) = 0.7, since coin 1 has 70% chance of coming up as heads.p(T) = 0.3, since coin 1 has 30% chance of coming up as tails.Step 2: Calculation of probability for coin 2Similarly, let p(H) and p(T) be the probabilities of the coin 2 being tossed head and tail respectively.Then, we have:p(H) = 0.6, since coin 2 has 60% chance of coming up as heads.p(T) = 0.4, since coin 2 has 40% chance of coming up as tails.
Step 3: Calculation of probability of the head coming upTo find the probability that a head will come up on tossing the coin, we have to consider both the coins.So, the probability of the head coming up = P(head will come up) = 12 × 0.7 + 12 × 0.6 = 0.65Thus, the probability that head will come up on tossing the coin, when a coin initially flipped is equally likely to be coin 1 or coin 2 is 0.65.
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Alacrosse player throws a ball in the air from an initial height of 7 feet.
The ball has an initial vertical velocity of 90 feet per second. Another player catches the ball when it is 3 feet
above the ground. How long is the ball in the air? Round your answer to the nearest hundredth.
Answer:
Modeling the situation with a quadratic equation, it is found that:
The maximum height of the ball is of 60.2 feet.
The ball hits the ground after 3.39 seconds.
Considering the gravity, the height of the ball, after t seconds, is given by the following quadratic equation.
In which:
is the initial velocity.
is the initial height.
In this problem:
Height of 8 feet, thus .
Initial velocity of 32 feet per second,
The equation is:
Which is a quadratic equation with .
The maximum height is the output of the vertex, which is:
Then, with the coefficients of this question:
The maximum height of the ball is of 60.2 feet.
It hits the ground at t for which , thus:
We want the positive value, so:
The ball hits the ground after 3.39 seconds.
A similar problem is given at brainly.com/question/24626341
Step-by-step explanation: