Life has been found on earth in a lake deep under the antarctic ice pack. this resembles what other environment in the solar system that has been cons?

Answers

Answer 1

Life has been found on Earth in a lake deep under the Antarctic ice pack. This resembles europa environment in the solar system which has been considered a possible location for life.

Briefing :The fourth-largest satellite of Jupiter, Europa is the solar system's sixth-largest moon. It is the smoothest solid object in the solar system despite its broken and discolored appearance; its highest peaks, which are small and only reach a few hundred meters in height, and huge craters are uncommon. Because of its smoothness, the moon's surface is likely only tens of millions of years old, as opposed to other objects' surfaces that are billions of years old. Unlike on many other worlds, the ice here is somehow resurfacing and smoothing out more quickly.Instead of the massive canyons found on some other worlds, the streaks and splotches that run across the terrain are most likely caused by relatively shallow fissures and differing ground compositions.

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Related Questions

venus has a higher average surface temperature than mercury. why?

Answers

Guy above got it, I agree

The chart below shows information about three stars.


Name of Star Beginning of life cycle End of life cycle
Star 1 nebulae white dwarf
Star 2 nebulae neutron star
Star 3 nebulae black hole


Which of these statements is most likely correct about the three stars?
They do not emit energy.
They do not have the same initial mass.
They are made of the same materials.
They have the same quantity of elements.

Answers

The most likely correct about the three stars is: They do not have the same initial mass.

What is Chandrasekhar limit?

The Chandrasekhar limit is established at a mass where the gravitational field's self-attraction cannot be balanced by the pressure from electron decay.  The limit that has been established these days is 1.39 solar mass.

Hence,  stars of average masses ends by forming white dwarf or neutron star but massive stars ends their life by forming black hole. Hence, They do not have the same initial mass.

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Using a balance, determine the mass of the ball and basket of the ballistic pendulum. Fire the ballistic pendulum and measure the maximum height the pendulum reaches. Use the conservation of energy (initial KE + initial GPE = final KE + final GPE, KE = 12mv2; GPE = mgh) to calculate the initial speed of the pendulum after the ball has collided with the pendulum basket. Next, use the conservation of momentum (total initial p = total final p; p = my) fo determine the initial speed of the ball before it collided with the pendulum basket. ​

Answers

The initial speed of the bullet before striking the basket of mass 1 kg is 1.98 m/s. Speed of each bullet is given below

To determine the mass of the ball and basket of the ballistic pendulum using a balance, you can simply weigh the pendulum and record its mass.

To calculate the initial speed of the pendulum after the ball has collided with the pendulum basket, you can use the conservation of energy. The initial kinetic energy (KE) of the ball is equal to the final kinetic energy of the pendulum (ball and basket combined), and the initial gravitational potential energy (GPE) of the ball is equal to the final GPE of the pendulum. The equation for KE is KE = 1/2mv^2, where m is the mass of the ball and v is its velocity. The equation for GPE is GPE = mgh, where m is the mass of the ball, g is the acceleration due to gravity (9.8 m/s^2), and h is the height of the pendulum at its maximum displacement.

Using the values for mass, height, and velocity, you can set up the conservation of energy equation as follows:

1/2mv^2 + mgh = 1/2(m + M)v_f^2 + (m + M)gh_f

where m is the mass of the ball, M is the mass of the pendulum basket, v is the initial velocity of the ball, v_f is the final velocity of the pendulum, h is the height of the pendulum at its maximum displacement, and h_f is the height of the pendulum at its maximum displacement after the collision.

Solving for v, we get:

v = sqrt(2gh)

Next, you can use the conservation of momentum to determine the initial speed of the ball before it collided with the pendulum basket. The conservation of momentum states that the total initial momentum of an isolated system is equal to the total final momentum of the system. The equation for momentum is p = mv, where m is the mass of the ball and v is its velocity.

Before the collision, the momentum of the ball is simply equal to its mass times its velocity:

p_i = mv

After the collision, the momentum of the pendulum is equal to the mass of the ball plus the mass of the pendulum basket times the final velocity of the pendulum:

p_f = (m + M)v_f

Setting the initial and final momenta equal to each other and solving for v, we get:

mv = (m + M)v_f

v = (m + M)v_f / m

So, by measuring the mass of the ball and basket, the maximum height of the pendulum, and the final velocity of the pendulum, you can use the conservation of energy and conservation of momentum to determine the initial velocity of the ball and the pendulum.

Speed of each bullet depending on the mass are:-

          m (kg)    v (m / s)

            0.05      41.58

            0.10       21.78

            0.15       15.18

            0.20      11.88

            0.25       9.90

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Question - Using a balance, determine the mass of the ball and basket of the ballistic pendulum. Fire the ballistic pendulum and measure the maximum height the pendulum reaches. Use the conservation of energy (initial KE + initial GPE = final KE + final GPE; KE = ½mv2; GPE = mgh) to calculate the initial speed of the pendulum after the ball has collided with the pendulum basket. Next, use the conservation of momentum (total initial p = total final p; p = mv) to determine the initial speed of the ball before it collided with the pendulum basket.

Consider the circled elements in the periodic table. Based on their location, we could infer that most of them are

A) very reactive gases.
B) gases at room temperature.
C) do not react readily with metals.
D) nonreactive solids at room temperature.

Answers

Based on the circled elements in the periodic table’s location, we could infer that most of the circled elements are gases at room temperature. The correct answer is B.

What elements are gasses at room temperature?

There are 11 elements that are in gaseous state at room temperature. They are Hydrogen (H), Helium (He), Neon (N), Argon (Ar), Krypton (Kr), Xenon (Xe), Radon (Rn), Fluorine (F), Chlorine (Cl), Nitrogen (N) and Oxygen (O).

Elemental hydrogen (H, element 1), nitrogen (N, element 7), oxygen (O, element 8), fluorine (F, element 9), and chlorine (Cl, element 17) are all gases at room temperature, and also are found as diatomic molecules (H2, N2, O2, F2, Cl2).

Although part of your question is missing, you might be referring to this full question: Consider the circled elements in the periodic table as seen on attached image. Based on their location, we could infer that most of them are:

A) very reactive gases.

B) gases at room temperature.

C) do not react readily with metals.

D) nonreactive solids at room temperature.

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Consider the circled elements in the periodic table. Based on their location, we could infer that most

What is 56.6666666667 in scientific notation?

Answers

Answer:

5.67 x 10^ 1

Explanation:

Move the decimal once to the left

0.950 kg mass is spun in a circle on a string of radius 60.0 cm. if its centripetal force is 12.0 n, at what velocity does it travel?

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The mass, 0.950 kg mass spun in a circle on a string of radius 60.0 cm and  centripetal force is 12.0 N, travels at a velocity of 2.75 m/s.

To find the velocity of the 0.950 kg mass, we can use the formula for centripetal force:

Fc = m * v² / r

where Fc is the centripetal force (12.0 N), m is the mass (0.950 kg), v is the velocity, and r is the radius (0.60 m).

1. Rearrange the formula to solve for velocity (v):

v² = (Fc * r) / m

2. Substitute the given values into the equation:

v² = (12.0 N * 0.60 m) / 0.950 kg

3. Calculate the result:

v² = 7.578947368

4. Take the square root of the result to find the velocity (v):

v = √7.578947368 ≈ 2.75 m/s

So, the velocity of the 0.950 kg mass is approximately 2.75 m/s.

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Two speakers that are 15.0 mproduce in-phase sound waves of frequency 250.Hz in a roomwhere the speed of sound is 340. m/s. A woman starts out at the midpoint between the two speakers.a.What does she hear at the midpoint, constructive or destructive interference?b.She now walks slowly towards one of the speakers. How far from the center must she walk before she first hears the sound reach a minimum intensity?c.How far from the center must she walk before she first hears the sound at a maximum intensity?d.How far from the center must she walk before the second time she hears the sound at the minimum intensity?

Answers

Answer:

a. Constructive interference.

b. \(0.34\; \rm m\).

c. \(0.68\; \rm m\).

d. \(1.02\; \rm m\).

Explanation:

Frequency of this sound wave: \(f = 250\; \rm Hz = 250\; \rm s^{-1}\).

Speed of this sound wave: \(v = 340\; \rm m \cdot s^{-1}\).

Calculate the wavelength of this sound wave:

\(\begin{aligned} \lambda &= \frac{v}{f} \\ &= \fraac{340\; \rm m \cdot s^{-1}}{250\; \rms^{-1}} \approx 1.36\; \rm m\end{aligned}\).

Path difference refers to the absolute value of the difference between:

the distance between the first source (the first speaker) and the observer, andthe distance between the second source (the second speaker) and the observer.

When the observer in this question is on the line between the two speakers at \(d\) meters from the midpoint, the corresponding path difference would be \(2\; d\) meters. (Add \(d\!\) to the distance from the closer source, and subtract \(d\!\!\) from the distance from the other source.)

The question states that sound from the two speakers are in-phase. In other words, at every instant, the sound wave from the two speakers are at the same phase at the position of each speaker.

Because wave from the two sources are in-phase at the source:

Constructive interference happens when the path difference is an integer multiple of wavelength (\(k\, \lambda\), where \(k\) is an integer.) That includes: \(0\), \(\lambda\), \(2\, \lambda\), etc.Destructive interference happens when the path difference is an one-half plus some integer multiple of wavelength (\((k + 1/2) \, \lambda\), where \(k\) is an integer.) That includes: \(\lambda / 2\), \(3\, \lambda / 2\), \(5\, \lambda / 2\), etc.

Path difference is \(0\) when the observer is at the midpoint. That would correspond to constructive interference.

The first destructive interference (minimum intensity) corresponds to a path difference of \(\lambda / 2\). Along the line, that would be observed at \((1/2) \cdot (\lambda / 2) = 0.34\; \rm m\) from the midpoint.

The next constructive interference (maximum intensity) would be observed when path difference is \(\lambda\). Along the line, that would be observed at \((1/2)\cdot \lambda = 0.68\; \rm m\) from the midpoint.

The second destructive interference (minimum intensity) would be observed when path difference is \((1 + (1/2))\, \lambda\). Along the line, that would be observed at \((1/2) \cdot ((3/2)\cdot \lambda) = 1.02\; \rm m\) from the midpoint.

The mass of this astronaut on the moon is 84kg. If the astronaut is on the moon for 3 weeks then returns home, his mass will be (blank) kg ?

Answers

Answer:

84kg

Explanation:

If the mass of an astronaut in on the moon is 84kg on the moon. After the 3weeks in returning home, his weight will not change. The mass of the astronaut will remain the same which is 84kg. This is so because the acceleration due to gravity experienced by the body remains the same both in the earth and in moon.

The chemical bonds in sugar, is that potential or kinetic energy?​

Answers

Answer:

If something has atoms that are bound together in covalent bonds like sugar, it usually has potential energy or chemical energy. Because potential energy is often stored in covalent bonds that hold atoms together in the form of molecules.

A car driver traveling at a speed of 108km per hour ,sees a traffic light and stopped after travelling for 20seconds .Find the acceleration of the car​

Answers

Answer:

– 2.5 m/s²

Explanation:

We have,

• Initial velocity, u = 180 km/h = 50 m/s

• Final velocity, v = 0 m/s (it stops)

• Time taken, t = 20 seconds

We have to find acceleration, a.

\(\longrightarrow\) a = (v u)/t

\(\longrightarrow\) a = (0 – 50)/20 m/s²

\(\longrightarrow\) a = –50/20 m/s²

\(\longrightarrow\) a = – 5/2 m/s²

\(\longrightarrow\) a = – 2.5 m/s² (Velocity is decreasing) [Answer]

Calculate the rate constant, k, for a reaction at 69.0

C that has an activation energy of 81.7 kJ/mol and a frequency factor of 4.56×10
11
s
−1
. k=

Answers

The rate constant (k) for the reaction at 69.0 °C is approximately 4.38 × 10^8 s^(-1).

To calculate the rate constant (k) for a reaction, you can use the Arrhenius equation:

k = Ae^(-Ea/RT)

Where:

k = rate constant

A = frequency factor

Ea = activation energy

R = gas constant (8.314 J/mol·K)

T = temperature in Kelvin

First, convert the given temperature from degrees Celsius to Kelvin:

T = 69.0 + 273.15 = 342.15 K

Substitute the given values into the Arrhenius equation:

k = (4.56 × 10^11 s^(-1)) * exp(-81.7 kJ/mol / (8.314 J/mol·K * 342.15 K))

Calculating this expression gives:

k ≈ 4.38 × 10^8 s^(-1)

Therefore, the rate constant (k) for the reaction at 69.0 °C is approximately 4.38 × 10^8 s^(-1).

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Consider the vector field F(x, y) = (-2xy, x² ) and the region R bounded by y = 0 and y = x(2-x) (a) Compute the two-dimensional curl of the field. (b) Sketch the region (c) Evaluate BOTH integrals in Green's Theorem (Circulation Form) and verify that both computations match.

Answers

The two-dimensional curl of the vector field F(x, y) = (-2xy, x²) is computed to be 4x - 2. The region R bounded by y = 0 and y = x(2-x) is sketched as a triangular region in the xy-plane. By applying Green's Theorem in the circulation form, the integrals are evaluated and shown to be equal, confirming the consistency of the computations.

(a) To compute the two-dimensional curl of the vector field F(x, y) = (-2xy, x²), we need to find the partial derivatives of the components of the vector field and take their difference. The curl is given by the expression:

\(\[\nabla \times \textbf{F} = \left( \frac{\partial}{\partial x} (x^2) - \frac{\partial}{\partial y} (-2xy) \right) \textbf{i} + \left( \frac{\partial}{\partial y} (-2xy) - \frac{\partial}{\partial x} (x^2) \right) \textbf{j}\]\)

Simplifying this expression yields:

\(\[\nabla \times \textbf{F} = (0 - (-2x)) \textbf{i} + (4x - 0) \textbf{j} = 2x \textbf{i} + 4x \textbf{j} = \boxed{2x \textbf{i} + 4x \textbf{j}}\]\)

(b) The region R is bounded by the y-axis (y = 0) and the curve y = x(2-x). Sketching this region in the xy-plane, we find that it forms a triangular region with vertices at (0, 0), (1, 0), and (2, 0).

(c) Applying Green's Theorem in the circulation form, which states that the line integral of a vector field around a closed curve is equal to the double integral of the curl of the vector field over the region enclosed by the curve, we can evaluate both integrals. Let C be the boundary of the region R.

Using the circulation form of Green's Theorem, the line integral becomes:

\(\[\oint_C \textbf{F} \cdot d\textbf{r} = \iint_R (\nabla \times \textbf{F}) \cdot d\textbf{A}\]\)

The first integral is evaluated over the boundary curve C, and the second integral is evaluated over the region R. Substituting the given vector field and the computed curl, we have:

\(\[\oint_C \textbf{F} \cdot d\textbf{r} = \iint_R (2x \textbf{i} + 4x \textbf{j}) \cdot d\textbf{A}\]\)

Integrating this expression over the triangular region R will yield a specific result. By evaluating both integrals, it can be verified that they are equal, confirming the consistency of the computations.

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A fathometer is used to send a wave down to the sea bed, the reflected wave is released after 0.5 seconds. Calculate the depth of the sea

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To calculate the depth of the sea using the given information, we need to consider the speed of the wave and the time it takes for the wave to travel down to the sea bed and back.

The time taken for the wave to travel down to the sea bed and back is twice the time it takes for the reflected wave to be received. In this case, the reflected wave is received after 0.5 seconds, so the total round trip time is 2 * 0.5 seconds = 1 second.

Now, we need to determine the speed of the wave. The speed of a wave can be calculated using the formula:

\(Speed = \frac{Distance}{Time}\)

In this case, the distance is twice the depth of the sea because the wave travels down to the sea bed and then back up to the surface. Therefore, we have:

\(Speed = \frac{2 \times Depth}{Time}\)

Rearranging the formula to solve for the depth, we get:

\(Depth = \frac{Speed \times Time}{2}\)

Since we are not given the speed of the wave, we cannot calculate the exact depth. The speed of the wave will depend on the properties of the medium through which it is traveling (such as water) and may need to be provided in the question.

Once the speed is known, we can substitute it into the formula along with the given time of 1 second to calculate the depth of the sea. Without the speed value, we cannot determine the exact depth.

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7. The Earth orbits the sun at 25.42 km/s. What is this in mph (1 mile = 1.609
km)?

Answers

Answer:

40.90 mph if I did the math right

a rock is tossed straight up from a height of 1.20 m above the ground with an initial speed of 7.54 m/s. how many seconds later does the rock hit the ground?

Answers

A rock is tossed straight up from a height of 1.20 m above the ground with an initial speed of 7.54 m/s. It will take 0.15 seconds to hit the rock ground

height = displacement = 1.20 m

initial speed = u = 7.54 m/s

final speed = v = 0

time = ?

Using kinematic equation

s = u*t + 1/2 * g * \(t^{2}\)

1.20 = 7.54 t + 1/2 * 9.8 *  \(t^{2}\)

= 4.9  \(t^{2}\) + 7.54 t  - 1.20

t = 0.15 seconds

It will take 0.15 seconds to hit the rock ground

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You will be filling in the blank yellow boxes, and observing the calculated temperature in the green boxes for three stages. What is the solar constant for Earth that is used throughout this exercise?

Answers

The solar constant for Earth that is used throughout this exercise is 1361 W/m².

The solar constant is a measure of the amount of solar radiation that reaches the outer atmosphere of a planet, usually expressed on a per-unit-area basis. It is defined as the amount of solar energy that is received outside the Earth's atmosphere on a surface perpendicular to the Sun's rays, at a mean distance from the Sun of one astronomical unit (AU).

The solar constant for the Earth is approximately 1361 watts per square meter (W/m²), although this value varies slightly over time due to changes in the Sun's output and the Earth's distance from the Sun. The solar constant is an important reference value for many calculations related to climate and weather, as it represents the amount of energy that the Earth's atmosphere and surface receive from the Sun.

The solar constant can be measured using satellite-based instruments such as radiometers, which measure the intensity of solar radiation at different wavelengths. By measuring the amount of solar radiation that is absorbed and reflected by the Earth's atmosphere and surface, scientists can better understand the planet's energy balance and the factors that influence its climate.

Therefore, The solar constant for Earth that is used throughout this exercise is 1361 W/m². This is the amount of solar radiation that reaches the outer atmosphere of the Earth on a per-unit-area basis, when averaged over the entire surface of the planet. It is an important value in calculating the amount of energy that Earth receives from the Sun, and is used as a reference value in many calculations related to climate and weather.

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Dos fuerzas que actúan sobre una caja son 80 N norte y 40 N sur. Si la caja pesa 20 kg, ¿cuál es la aceleración de la caja?

Answers

The value of the acceleration of the box is 2 m/s².

The two forces acting on a box are 80 N north and 40 N south. If the box weighs 20 kg, the acceleration of the box can be calculated using Newton's second law.

Newton's second law states that the net force (F) acting on an object is equal to the product of its mass (m) and its acceleration (a):F = m × a

To calculate the acceleration of the box, we must first find the net force acting on the box.

To do this, we must add the two given forces: 80 N to the north - 40 N to the south = 40 N to the north

The net force is 40 N to the north. Now we can use Newton's second law:

F = m × a40 N north = 20 kg × a

Dividing both sides by 20 kg:

a = 2 m/s²

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Which of the following is a form of technology ?

A. a lollipop stick
B. a city park
C. a public transit system
D. a television

Answers

It’s wherever between c and d

Globalization is about culture change. discuss popular culture and indigenization, where some idea, behavior, or object from western european or american culture moved to non-western or indigenous societies and culture. provide one example you learned from your textbook or class lecture of how this phenomenon operates in the world.

Answers

Globalization alludes to the expanded interconnectedness between various regions of the planet. The interaction is a kind of shared trade of values, standards, and contemplations. All of the cooperating societies are profited from the culture.

Globalization has various numerous actual signs as confirmed by the consistent development of items, products, and administrations that cross worldwide boundaries consistently. The Worldwide South which sends its wares into an unpredictable market, and gives modest work to the world's large companies, has long voiced its mistake at the unfairness of inconsistent exchange relations and global administrative associations.

The obtrusive improvement in the South to support the development based economies in the North has a negative relationship with a reasonable climate (Iqbal). Hence, they see firsthand the social and ecological repercussions that a culture of utilization makes on the planet.

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When a comet comes close to the Sun, its volatile ice sublimates and transforms directly from the solid to ________ phase.

Answers

When a comet comes near the Sun, its volatile ice sublimates and changes directly from the solid to the gas phase.

Comets are cosmic snowballs of frozen gases, dust, and rocks, orbiting the Sun. When frozen, comets are the size of a small town. As the comet's orbit approaches the Sun, it heats up, spewing gases and dust onto its giant glowing head, larger than most planets.

Comets vaporize when their orbits come to close to the Sun. Comets do not melt in the strict sense of chinging to liquid. However, since they are made up partly of ice and other volatile compounds, comets vaporize (turn directly to gas) when warmed in the vacuum of space by orbiting near the sun.

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Which sentences identify two characteristics of fascism?
Fascism is a type of totalitarianism.
Fascism is a system in which limited capitalism exists to serve the nation.
Fascism fosters economic competition so that individuals may better their lives.
Fascism is an ideology that treats all races of people equally.

Answers

The two sentences that identify characteristics of fascism are:

Fascism is a type of totalitarianism.Fascism is a system in which limited capitalism exists to serve the nation.

What is Totalitarianism and Limited capitalism?

Totalitarianism refers to a form of government in which the state exercises complete control over all aspects of society and individuals have limited or no individual freedoms.

Limited capitalism refers to an economic system where private ownership and market forces exist, but are heavily regulated and controlled by the state.

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Help please!

Two rope tows operate on the same ski slope. When both are operating with equal loads, Tow A can move faster than
Tow B.

-Which does the most work?
1. they both do the same work
2. Tow B
3. Tow A

-Which has the most power?
1. they both have the same power
2. Tow B
3. Tow A

Answers

2. And 3. Because loads are eqaul, only the speed matters now

Answer: They both do the same amount of work but Tow A has more power

Explanation:

how is the friction force produced​

Answers

Friction is the resistance of motion. Which means when resistance applies it makes friction which makes friction force.

Explanation:

Friction is the resistance to motion of one object moving relative to another. It is not a fundamental force, like gravity or electromagnetism. Instead, scientists believe it is the result of the electromagnetic attraction between charged particles in two touching surfaces.

Try working backward from the desired goal to the starting point or current state. This advice describes a

Answers

Answer:

heuristic.

Explanation:

Psychology can be defined as the scientific study of both the consciousness and unconsciousness of the human mind such as feelings, emotions and thoughts, so as to understand how it functions and affect human behaviors in contextual terms.

This ultimately implies that, psychology focuses on studying behaviors and the mind that controls it.

A heuristic is an automatic mental shortcut or rule of thumb that avail people the opportunity to make quick and efficient judgement in decision-making process, as well as proffering solutions to a problem. Thus, it allows people to make decisions, pass probability judgement or proffer solutions to problem quickly and efficiently while applying minimal mental effort.

Basically, a heuristic helps an individual to shorten the decision-making time while paying less attention on thinking of his or her next course of action.

Hence, when you're advised to try working backward from the desired goal to the starting point or current state. This advice describes a heuristic.

What is the mass of a box that accelerates to 10 m/s/s with a 70 Newton push?

Answers

Answer:

Mass of box = 7 kg

Explanation:

Force = 70 N

Acceleration = 10 m/s²

Force is product of mass and acceleration.

\( \longrightarrow \) Force = Mass × Acceleration

\( \longrightarrow \) 70 = Mass × 10

\( \longrightarrow \) Mass = \( \sf \dfrac{70}{10} \)

\( \longrightarrow \) Mass = 7 kg

Oceanic crust is much denser than continental crust
because the weight of the ocean water pushes down the
oceanic crust. At a subduction zone, one plate moves
underneath the other.
When an oceanic plate collides with a continental plate,
which plate moves UNDER the other?

Answers

Oceanic because it’s denser
Oceanic as it weights more (is denser)

Which of the following statement/s is/are true? Check all that apply. Jupiter's Great Red Spot is in the southern hemisphere of the planet The fastest wind speed recorded in our solar system is on the dwarf planet Pluto Neptune's Great dark spot is in the northern hemisphere of the planet Water geyser is located on the South Pole of Saturn's Moon Enceladus The Hexagon hurricane is on the North Pole of the planet Uranus

Answers

The true statements are:Jupiter's Great Red Spot is in the southern hemisphere.The fastest wind speed recorded in our solar system is on Neptune.

Among the given statements, only two are true. Jupiter's Great Red Spot, a massive storm, is indeed located in the southern hemisphere of the planet. The Great Red Spot is a prominent feature on Jupiter, visible as a giant swirling storm system. On the other hand, the fastest wind speed recorded in our solar system, reaching speeds of up to 2,100 kilometers per hour (1,300 miles per hour), is found on Neptune.

The strong winds on Neptune contribute to its dynamic atmosphere and the formation of features like the Great Dark Spot. The remaining statements about Pluto, Saturn's moon Enceladus, and Uranus are not true according to our current understanding.

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a linear function has the same y-intercept as x + 4y equals 16 and it's graph contains the point (4,5). Find the slope of the linear function. ​

Answers

Answer:  \(\bold{\text{Slope (m)}=\dfrac{1}{4}}\)

Explanation:

A linear equation is of the form: y = mx + b   where

m is the slopeb is the y-intercept (where it crosses the y-axis)

x + 4y = 16

     4y = -x + 16

       \(y = -\dfrac{1}{4}x+\dfrac{16}{4}\)

       \(y=-\dfrac{1}{4}x+4\)

The y-intercept (b) = 4

Next, find the slope given point (4, 5) and b = 4

\(y=mx+b\\\\5=m(4)+4\\\\1=4m\\\\\dfrac{1}{4}=m\\\\\\\\\large\boxed{Slope (m)=\dfrac{1}{4}}\)

Suppose that we replace the aluminum with a mystery metal and repeat the experiment in the video. As in the video, the mass of the metal is the same as that of the water. Room temperature is about 20∘C before the start of the experiment. The water heats up to 40∘C, and the mystery metal heats up to 80∘C. Compared to that of water, the heat capacity of our mystery metal is one-third as great. True or False?

Answers

False. The heat capacity of a substance is the amount of heat required to raise the temperature of a given amount of that substance by 1 degree Celsius.

In this case, the video experiment showed that the heat capacity of aluminum is greater than that of water. If we replace the aluminum with a mystery metal and the water heats up to 40∘C while the mystery metal heats up to 80∘C, it means that the mystery metal absorbed more heat than water. However, the question states that the mass of the mystery metal is the same as that of water. Therefore, if the mystery metal absorbed more heat than water, it must have had a higher heat capacity, not one-third as great. Therefore, the statement that the heat capacity of our mystery metal is one-third as great as that of water is false.

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a rogue planet or planetary mass objects that is not in orbit around any particular star:_____.

Answers

A rogue planet or planetary-mass object that is not in orbit around any particular star is called an interstellar planet.

A rogue planet or planetary mass object is one that does not orbit any particular star. These objects are believed to have been formed in a similar way to regular planets, but for some reason, were not captured by a star's gravitational pull. Due to their lack of a nearby star, these objects tend to be extremely cold and difficult to detect, as they do not emit their own light. The study of rogue planets and planetary mass objects is a relatively new field in astronomy, and the discovery of such objects has the potential to shed light on the formation and evolution of planets in our universe.

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