Answer:
Explanation:
From the information given:
\(CaF_2 \to Ca^{2+} + 2F^-\)
\(Ksp = 3.2 \times 10^{-11}\)
no of moles of \(Ca^{2+}\) = 0.01 L × 0.0010 mol/L
no of moles of \(Ca^{2+}\) = \(1 \times 10^{-5} \ mol\)
no of moles of \(F^-\) = 0.01 L × 0.00010 mol/L
no of moles of \(F^-\) = \(1 \times 10^{-6}\ mol\)
Total volume = 0.02 L
\([Ca^{2+}}] = \dfrac{1\times10^{-5} \ mol}{0.02 \ L} \\ \\ \\ \[[Ca^{2+}}] = 0.0005 \ mol/L\)
\([F^{-}] = \dfrac{(1\times 10^{-6} \ mol)}{0.02 \ L}\)
\([F^{-}] = 5 \times 10^{-5} \ mol/L\)
\(Q = [Ca^{2+}][F^-]^2 \\ \\ Q = 0.0005 \times (5\times 10^{-5})^2 \\ \\ Q = 1.25 \times 10^{-12}\)
Since Q<ksp, then there will no be any precipitation of CaF2
copper and silver voltmeters were connected together in series. If a current of 0.4A flows for 5 hours. Calculate the masses of copper and silver deposited.
The mass of copper deposited is approximately \(1.32 * 10^{(-3) }g\), and the mass of silver deposited is approximately \(2.23 * 10^{(-3)} g\).
To calculate the masses of copper and silver deposited, we need to use the concept of Faraday's law of electrolysis, which states that the amount of substance deposited during electrolysis is directly proportional to the quantity of electricity passed through the electrolyte.
First, we need to calculate the total charge (Q) passed through the circuit using the equation:
Q = I * t
where I is the current (0.4 A) and t is the time (5 hours). Therefore,
Q = 0.4 A * 5 hours = 2 C (Coulombs)
Next, we need to determine the amount of substance deposited using the equation:
n = Q / F
where n is the number of moles of the substance and F is the Faraday constant. The Faraday constant represents the charge of one mole of electrons and is approximately 96,485 C/mol.
For copper (Cu), the molar mass is approximately 63.55 g/mol, and for silver (Ag), the molar mass is approximately 107.87 g/mol.
Using the molar mass and the number of moles, we can calculate the mass of the substance deposited using the equation:
Mass = n * molar mass
Let's calculate the masses of copper and silver deposited:
For copper (Cu):
n(Cu) = Q / F = 2 C / 96485 C/mol ≈ \(2.07 * 10^{(-5)\) mol
Mass(Cu) = n(Cu) * molar mass(Cu) = \(2.07 * 10^{(-5)\) mol * 63.55 g/mol ≈ \(1.32 * 10^{(-3)} g\)
For silver (Ag):
n(Ag) = Q / F = 2 C / 96485 C/mol ≈ \(2.07 * 10^{(-5)\) mol
Mass(Ag) = n(Ag) * molar mass(Ag) = \(2.07 * 10^{(-5)\)mol * 107.87 g/mol ≈ \(2.23 * 10^{(-3)\\}g\)
Therefore, the mass of copper deposited is approximately \(1.32 * 10^{(-3)} g\), and the mass of silver deposited is approximately \(2.23 * 10^{(-3)\\}g\)
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Which of the following are true statements with regard to catalyst?
a. A catalyst is formed in the first elementary step of a reaction and consumed by a later step.
b. Catalysts can speed up chemical reactions by providing the reactants with more
energy.
c. Catalysts can speed up chemical reactions by providing an alternate pathway for the reaction that requires less energy.
d. Catalysts can speed up chemical reactions by providing an alternate pathway for the reaction that requires more energy.
e. Catalysts can speed up a chemical reaction by increasing the number of collisions.
f. Catalysts can speed up chemical reactions by forming intermediates and introducing new elementary steps that require less energy.
g. Catalysts are completely consumed in the reaction.
h. Catalysts are regenerated within a chemical reaction.
A: False, because the catalyst appears in the reactant and product in the main reaction, it will not appear in the product in the main reaction in this case
B: False, Catalysts speed up reaction by providing an alternative pathway for the reaction which have lower activation energy
C: True
D: False, Higher activation energy results in a slower reaction
E: False, it only provide an alternative pathway and do nothing with collisions
F: True
G: False, as I said before, catalyst does appears on the product and reactant side on the main reaction
H: True
Calculate the average atomic mass of sulfur if 95.00% of all sulfur atoms have a mass of 31.972 amu, 0.76% has a mass of 32.971 amu and 4.22% have a mass of 33.967 amu.
Answer:
32.057 amu
Explanation:
\(\text{Average atomic mass = Mass}\times \text{abundances}\)
\(M=95\%\ \text{of}\ 31.972 +0.76\%\ \text{of}\ 32.971 +4.22\%\ \text{of}\ 33.967 \\\\M=\dfrac{95}{100}\times 31.972 +\dfrac{0.76}{100}\ \times \ 32.971 +\dfrac{4.22}{100} \times \ 33.967\\\\M=32.057\ \text{amu}\)
So, the average atomic mass of sulfur is 32.057 amu.
The average atomic mass of sulfur is 32.06 amu if 95.00% of all sulfur atoms have a mass of 31.972 amu, 0.76% has a mass of 32.971 amu and 4.22% have a mass of 33.967 amu.
Sulfur is formed by 3 isotopes: 95.00% of all sulfur atoms have a mass of 31.972 amu, 0.76% has a mass of 32.971 amu and 4.22% have a mass of 33.967 amu.
The average atomic mass (am) is a weighted average that takes into account the mass and the abundance of each isotope.
\(am = \frac{\Sigma m_i \times ab_i }{100} = \frac{31.972amu \times 95.00 + 32.971amu \times 0.76 + 33.967amu \times 4.22}{100} = 32.06 amu\)
The average atomic mass of sulfur is 32.06 amu if 95.00% of all sulfur atoms have a mass of 31.972 amu, 0.76% has a mass of 32.971 amu and 4.22% have a mass of 33.967 amu.
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What is the resolution of a monochromator, Δλeff, with a exit slit width of 500 micrometers and a \(D^{-1}\) of 1.8 nm/mm? Express the answer in nm.
The resolution of the monochromator is 3.6nm
What is a MonochromatorA monochromator is an optical device that is used to isolate a specific wavelength or range of wavelengths of light from a broader spectrum of light. It is typically used in spectroscopy, where the goal is to measure the intensity of light at a specific wavelength or over a range of wavelengths.
The resolution of a monochromator, Δλeff, is given by the equation: Δλeff = (D^-1) * (exit slit width)
Plugging in the given values:
Δλeff = (1.8 nm/mm) * (500 micrometers)
Converting micrometers to millimeters:
Δλeff = (1.8 nm/mm) * (0.5 mm)
Δλeff = 3.6 nm
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Two samples of a compound containing only nitrogen and oxygen are decomposed into their constituent elements. The first sample produces 2.602 g of nitrogen and 6.400 g of oxygen. The second sample produces 3.903 g of nitrogen. If these two samples are consistent with the law of constant composition, how much oxygen is produced by the second sample?
A.) 6.505 g oxygen
B.) 9.600 g oxygen
C.) 1.587 g oxygen
D.) 6.400 g oxygen
Answer:
6.400 g oxygen is the answer
1.32x1024 atoms of carbon equals how many moles of Carbon?
Answer: 110g
Explanation:
110 g" Your strategy here will be to use Avogadro's number to calculate how many moles of carbon dioxide would contain that many molecules
a gas has a volume of 350ml at 45 degree celsius if the volume change to 400ml what is the new temperature
PLEASE HELP!!!!! WILL GIVE BRAINLIEST!!!!
The answer should be A
VisibleVisible wave length visible wavelength of light that are emitted by Adams can be used to get Nate explosive devices remotely
According to the article, elements are named by the number of protons in the nuclei.
Which paragraph BEST supports the idea outlined above?
A
The periodic table is getting a little bit longer, thanks to the addition of four super-heavy elements.
B
The discoveries of elements 113, 115, 117 and 118 were confirmed recently by the International Union of Pure and Applied Chemistry. The group vets the man-made elements seeking a permanent spot on the periodic table, a chart listing all the elements that hangs in science classrooms around the world.
C
Atoms are the building blocks that make up elements. At the center of each atom is a nucleus composed of small particles called protons and neutrons. Nuclei is the plural of nucleus.
D
The new elements are known as super-heavy elements. Element 118, for example, is the heaviest element to date, with 118 protons alongside 176 neutrons.
The correct answer is: Atoms are the building blocks that make up elements. At the center of each atom is a nucleus composed of small particles called protons and neutrons. Nuclei is the plural of nucleus; option C.
What is atomic number of an element?The atomic number of an element is the number of protons present in the nucleus of the atom of the element.
The nucleus is the center of the atom and is the heaviest part of the atom.
Another sub-atomic particle fund in the nucleus is the neutron.
Elements are named according to the number of protons in the nuclei.. This is because the number of protons in the nucleus of any given atom whereas the neutron number may vary, Also, electrons are easily removed from atoms of elements.
In conclusion, the number of protos in atom is used to name the atom.
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What type of energy does a ball falling through the air have?
Answer:
kinectic energy
Explanation:
............
There are two types of energy that a massive body posses are kinetic energy and potential energy. When a ball falling through air it posse both of these energy but kinetic energy increases on movement.
What is mechanical energy?Mechanical energy of a body is the sum of potential energy and kinetic energy . Kinetic energy is generated by the movement of the body. Whereas, potential energy forms by virtue of its position.
Kinetic energy increases when a body starts to move where, the potential energy decreases.
Potential energy of a body raises as its height from the surface increases. The equation relating mass, height and gravity is p= Mgh.
According to law of conservation of energy the mechanical energy of a a freely falling body remains constant. When it is at the height from the surface it experience potential energy and when starts to fall it gains kinetic energy.
Therefore, the energy that a ball falling through the air is mechanical energy.
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a cylinder container is filled with air. its radius is 6cm and its height is 3.5cm. what is the volume of the air inside?
Answer:
45
Explanation:
I am math teacher
A slap shot In hockey can travel 105 miles/homir. How many seconds does it take for a slap shot to get from the blue line to the goalie - a distance of 32 meters?
Answer:0
Explanation:
(100 POINTS) Write the chemical formula of the ionic compound magnesium chlorate. The magnesium (Mg) ion has a +2 charge. Chlorate (ClO3) has a −1 charge.
A) Mg (ClO3)2
B) Mg2 (ClO3)
C) Mg2 (ClO3)
D) Mg (ClO3)
Answer:
A
Explanation:
since Mg has a charge of +2 and ClO3 has a charge of 1-, you need 2 ClO3 to cancel out the +2 since 2 ClO3 ions would have a 2- charge
Answer:
Mg(ClO3)2
Explanation:
i know my chemestry
A liquid substance at ordinary temperatures, such as water (H2O) or bromine (Br2) is heated sufficiently so that it evaporates. The substance would typically be said to be now in _______________ form.
Select one:
a.
rare
b.
vapor
c.
osmotic
d.
solid
Answer:
b. vapor
Explanation:
When a liquid substance is heated sufficiently, the energy from the heat causes the molecules to gain enough kinetic energy to break the intermolecular bonds and escape into the air as individual gas molecules. This process is called evaporation, and the substance in this gaseous form is known as a vapor. The term "vapor" refers to the gaseous form of a substance that was originally in a liquid state, and it typically refers to the mixture of gas molecules that are in constant motion and in contact with the air.
Why would scientists use a control sample that is known to be from a
specific species in an eDNA surveillance for that species?
A. So they can have a negative control against samples
B. So they can cut sample DNA into fragments
C. So they can amplify the DNA in small samples
D. So they can identify samples that contain the target DNA
Answer:
Here is the answer...
Explanation:
Option A is used to control sample that is known to be form.
A solution is prepared by dissolving 15 grams of sugar in 85 grams of water. How many percent of sugar is in the solution?
Answer:
15%
Explanation:
From the question given above, the following data were obtained:
Mass of sugar = 15 g
Mass of water = 85 g
Percentage of sugar in the solution =?
Next, we shall determine the mass of the solution. This can be obtained as follow:
Mass of solute (sugar) = 15 g
Mass of solvent (water) = 85 g
Mass of solution =?
Mass of solution = mass of solute + mass of solvent
Mass of solution = 15 + 85
Mass of solution = 100 g
Finally, we shall determine the percentage of the sugar in the solution. This can be obtained as follow:
Mass of solute (sugar) = 15 g
Mass of solution = 100 g
Percentage of sugar in the solution =?
Percentage = solute /solution × 100
Percentage = 15 / 100 × 100
Percentage of sugar in the solution = 15%
how would you confirm the presence of lead in an ore?
There are numerous ways to determine whether lead is present in an ore. Atomic absorption spectroscopy is a popular approach. With this method, an ore sample is dissolved in acid and then atomized in a flame or plasma.
The sample's atoms will absorb light at particular wavelengths that are peculiar to the element under investigation. The amount of light absorbed can be used to calculate how much lead is present in the sample. Inductively coupled plasma mass spectrometry and X-ray fluorescence spectroscopy are further techniques. It is crucial to remember that these procedures call for specialized tools and training, thus they ought to only be carried out in a lab by qualified experts.
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Given the reaction: Mg(s) + 2HCl(aq) → MgCl2(aq) + H2(g)
The reaction occurs more rapidly when a 10-gram sample of Mg is powdered rather than in one piece, because powdered
Mg has
1. less surface area
2. more surface area
3. a lower potential energy
4. a higher potential energy
Hi could you please I just want to be sure on how to do these diagrams
Explanation:
Formaldeyde
Lewis Structure:
Structural diagram:
3D diagram.
KCIO3 decomposes according to thereaction below:
2KCIO3 → 2KCI + 302
How many moles of O2 form when
2.0 mole of KCIO3 decomposes?
When 2.0 moles of KCIO3 decompose, 2.0 moles of O2 will form.
The balanced chemical equation shows that 2 moles of KCIO3 decompose to produce 3 moles of O2. Therefore, we can use the stoichiometric ratio from the balanced equation to determine the number of moles of O2 formed when 2.0 moles of KCIO3 decompose.
According to the stoichiometry, 2 moles of KCIO3 produce 3 moles of O2. Therefore, we can set up a proportion:
(2 moles KCIO3 / 2 moles O2) = (2.0 moles KCIO3 / x moles O2),
where x represents the unknown number of moles of O2 formed.
Simplifying the equation:
(2 moles KCIO3 / 2 moles O2) = (2.0 moles KCIO3 / x moles O2),
1 = (2.0 moles KCIO3 / x moles O2),
Cross-multiplying:
x moles O2 = (2.0 moles KCIO3 / 1),
x moles O2 = 2.0 moles KCIO3.
Therefore, when 2.0 moles of KCIO3 decompose, 2.0 moles of O2 will form.
It is important to note that this calculation assumes complete and ideal conditions, where the reaction proceeds with 100% efficiency. In reality, the actual yield of O2 may be lower due to various factors such as side reactions or incomplete decomposition. To determine the actual yield, additional information or experimental data would be required.
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water can dissolve many substance because
Answer:
polarity
Explanation:
because of its polarity it can dissolve mutiple substance
How many moles of aluminum ions al3+ are present in 0.42 mol of al2so43
There are 0.84 moles of aluminum ions (Al3+) present in 0.42 mol of Al2(SO4)3.
To determine the number of moles of aluminum ions (Al3+) present in 0.42 mol of Al2(SO4)3, we need to consider the stoichiometry of the compound.
The formula of aluminum sulfate (Al2(SO4)3) indicates that for every 1 mole of the compound, there are 2 moles of aluminum ions (Al3+). This means that the mole ratio of Al3+ to Al2(SO4)3 is 2:1.
Given that we have 0.42 mol of Al2(SO4)3, we can calculate the moles of Al3+ as follows:
Moles of Al3+ = 0.42 mol Al2(SO4)3 x (2 mol Al3+ / 1 mol Al2(SO4)3)
Moles of Al3+ = 0.42 mol Al2(SO4)3 x 2
Moles of Al3+ = 0.84 mol Al3+
Therefore, there are 0.84 moles of aluminum ions (Al3+) present in 0.42 mol of Al2(SO4)3.
It's important to note that the stoichiometry of the compound determines the mole ratio between the different species involved in the chemical formula. In this case, the 2:1 ratio of Al3+ to Al2(SO4)3 allows us to determine the number of moles of Al3+ based on the given amount of Al2(SO4)3.
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A sample of chloroform is found to contain 12.0 g of carbon, 106.4 g of chlorine, and 1.01 g of hydrogen. If a second sample of chloroform is found to contain 28.9 g of carbon, what is the total mass of chloroform in the second sample?
Mass = _________ g chloroform
Answer:
287.6g CHCl₃
Explanation:
We can determine the structure of Chloroform, dividing the mass of each element in its molar mass:
C = 12.0g * (1mol /12g) = 1 mol C
H = 1.01g * (1mol / 1.01g) = 1 mol H
Cl = 106.4g * (1mol / 35.45g) = 3 moles Cl
The structure is CHCl₃. And its molar mass is: 12.0g C +1.01g H + 106.4g Cl = 119.41g/mol
Now, the moles of carbon in the second sample = Moles of chloroform are:
28.9g C * (1mol / 12g) = 2.408 moles C = Moles CHCl₃
And its mass is:
2.408 moles CHCl₃ * (119.41g/mol) =
287.6g CHCl₃Bismuth oxide reacts with carbon to form bismuth metal: Bi2O3(s) + 3C(s) → 2Bi(s) + 3CO(g) When 775 g of Bi2O3 reacts with excess carbon, (a) how many moles of Bi form? mol Bi (b) how many grams of CO form? g CO
Answer:
(a) 3.33 mol Bi
(b) 140. g CO
Explanation:
Step 1: Convert 775g to moles
Bi Molar Mass - 208.98 g/mol × 2 = 417.98 g/mol
O Molar Mass - 16.00 g/mol × 3 = 48.00 g/mol
775g Bi₂O₃ ÷ 465.98 g/mol = 1.66316 mol Bi₂O₃
Step 2: Find the conversion from Bi₂O₃ to Bi
1 mole of Bi₂O₃ equals 2 moles of Bi
Step 3: Use Dimensional Analysis
1.66316 mol · \(\frac{2 \hspace{2} mol \hspace{2} Bi}{1 \hspace{2} mol \hspace{2} Bi_2O_3}\) = 3.32632 mol Bi
3.32632 mol Bi ≈ 3.33 mol Bi (3 significant figures)
Step 4: Find the conversion from Bi₂O₃ to CO
1 mole of Bi₂O₃ equals 3 moles of CO
Step 5: Use Dimensional Analysis
1.66316 mol · \(\frac{3 \hspace{2} mol \hspace{2} CO}{1 \hspace{2} mol \hspace{2} Bi_2O_3}\) = 4.98948 mol CO
Step 6: Find molar mass of CO and convert moles to grams
C - 12.01 g/mol
O - 16.00 g/mol
4.98948 mol CO · 28.01 g/mol = 139.775 g CO
139.775 g CO ≈ 140. g CO (3 significant figures)
How many molecules of glucose are in 90.0 g C6H12O6? The molar mass of glucose is about 180 g/mol. 90.0 g C6H12O6 [?]×10 molecules C6H₁2O6 Note: Avogadro's number is 6.02 x 1023 particles/mole. Coefficient (green) Exponent (yellow) Enter
9.0 g of C6H12O6 contain 3.01 x 10²³ molecules of glucose.
How many moles of glucose, C6H12O6, are contained in 90 grammes?The result is 180.156, with grammes per mole being the unit. Hence, the mass of glucose is 90 and its molar mass is 180.156, giving us the moles of glucose, which are roughly 1.5 moles.
We can convert grammes to moles using the molar mass of glucose, and then moles to molecules using Avogadro's number:
1 mole C6H12O6 = 180 g C6H12O6
90.0 g C6H12O6 = (90.0 g C6H12O6) / (180 g/mol) = 0.5 mol C6H12O6
1 mol C6H12O6 = 6.02 x 10²³ molecules C6H12O6
0.5 mol C6H12O6 = (0.5 mol C6H12O6) x (6.02 x 10²³ molecules/mol) = 3.01 x 10²³ molecules C6H12O6
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What would be the formula of the compound that forms between Al and S?
a) AIS
b) Al₂S
c) AIS2
d) Al3S2
e) None of the above
The correct formula for the compound that forms between aluminum (Al) and sulfur (S) is (d) Al₂S₃.
The correct option is E, none of the above.
What is the nature of the reaction between Al and S?The reaction between aluminum (Al) and sulfur (S) is an example of a chemical reaction known as a combination or synthesis reaction. In this reaction, aluminum and sulfur combine to form a
.
The chemical equation for the reaction is:
2Al + 3S → Al₂S₃
Aluminum has a 3+ charge (Al³⁺) and sulfur has a 2- charge (S²⁻). In order to balance the charges, two aluminum ions (Al³⁺) are needed to combine with three sulfur ions (S²⁻), resulting in the formula Al₂S.
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Pls help I’ll brainlest and add extra points
Answer:
a top predator, fighting
An enzyme
A) decreases the rate of a reaction.
B) binds substrates in a manner that facilitates the formation of product.
C) changes the position of the equilibrium of the reaction.
D) does not change the rate at which the equilibrium is achieved.
E) is always a prot
The correct answer to an enzyme is B) binds substrates in a manner that facilitates the formation of product.
Enzymes are biological catalysts that speed up chemical reactions in living organisms. They do this by binding to substrates (the reactants in a chemical reaction) and facilitating the formation of product.
This is done by lowering the activation energy required for the reaction to occur, making it easier for the reaction to take place. Enzymes do not change the position of the equilibrium of the reaction, nor do they decrease the rate of the reaction.
Enzymes also do not change the rate at which the equilibrium is achieved. Lastly, enzymes are not always proteins, as some RNA molecules can also function as enzymes. Therefore, the correct answer is B) binds substrates in a manner that facilitates the formation of product.
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Some changes in matter may results to 1. _ or 2._ effects in the environment. We have to do our share in maintaining 3. environment. We must 4. too much use of electricity and gasoline. We must also avoid 5. rubber tires and plastics. We must avoid practices that will produce acid rain, increase global temperature, or deplete the ozone layer. pls i need answers
Answer:
C
Explanation:
PLEASE MARK AS BRAINLIEST!!!!!(04.02 LC) Based on the cell theory, which of the following is true?
A: Large organisms have fewer cells than small organisms.
B: Small organisms have smaller cells than large organisms.
C: All living things are made of more than one cell.
D: Cells vary in size depending on their type.
Answer:
c
Explanation:
there are billions of cells in living things. We are made out of millions of cells
Answer:
D is the answer
Explanation: