Make the shear force and bending moment diagrams for
the beam situation. shown in the figure
solve by integration method
Answers
The given beam situation can be drawn as below:We need to determine the shear force and bending moment diagrams for the given beam situation. We will find the shear force and bending moment using the integration method.To find the shear force diagram, we take an elemental length (x) of the beam.
Let's assume that the elemental length (x) is at a distance 'x' from point A. Thus the total length of the beam is (10-x).The downward force acting on the beam at a distance x from A = 10 kNThe length of the elemental section of the beam = dxWe know, Shear force (V) = dM/dx, where M is bending momentThe total downward force acting on the beam at a distance x from A = 10 kN.As there is no force acting to the left of x, the shear force diagram for x = 0 will start from zero.From A to C, the shear force is constant and equal to -10 kN. The negative sign shows that the shear force is downward.From C to B, there is no external force acting on the beam.
Hence the shear force diagram will be horizontal.Between C and B, the shear force diagram will become a straight line joining -10 kN at C and +5 kN at B.So the shear force diagram is as shown below:To find the bending moment diagram, we integrate the shear force equation. We know that the bending moment (M) at any point is the algebraic sum of all the moments to the left or right of that point. We take an elemental length (x) of the beam and assume that the elemental length is at a distance 'x' from A. Thus the total length of the beam is (10-x).The downward force acting on the beam at a distance x from A = 10 kN
The length of the elemental section of the beam = dxShear force (V) = dM/dxBending moment at a distance x from A = M(x)The bending moment at point A is zero. We take point A as the reference point. Then we will get the bending moment equation as:M(x) = ∫ V dx = ∫[(-10) dx] = -10x + CImplying M(0) = 0, we get C = 0Thus, the bending moment equation becomes,M(x) = -10x + CBy applying the boundary condition M(10) = 0, we get,C = 100Hence the bending moment equation is given byM(x) = -10x + 100The bending moment diagram is as shown below:Therefore, the shear force and bending moment diagrams for the given beam situation are as shown above.
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Related Questions
The illustration in figure below shows a uniform metre rule weighing 30 N pivoted on a wedge placed under the 40 cm mark and carrying a weight of 70 N hanging 2 from the 10 cm mark. The ruler is balanced horizontally by a weight W hanging from the 100 cm mark. Calculate the value of the weight W.
Answers
Answer:
W = 30 N
Explanation:
Applying the summation of torques about the wedge for equilibrium, taking the clockwise direction as negative. Since the ruler is balanced horizontally about the wedge. Therefore, the summation of all torques acting about the wedge must be equal to zero.
\((70\ N)(40\ cm - 10\ cm)-(30\ N)(50\ cm-40\ cm)-(W)(100\ cm - 40\ cm) = 0\\W(60\ cm) = (70\ N)(30\ cm)-(30\ N)(10\ cm)\\\\W = \frac{1800\ N.cm}{60\ cm}\)
W = 30 N
What forces are acting on a book lying on the table? Are action-reaction forces involved in this situation?
Answers
Leslie is investigating which brand of cell phone has the longest lasting battery.
WHAT IS A TESTABLE SCIENTIFIC QUESTION for Leslie’s investigation
Answers
Answer:
Which battery has a longer battery life?
Explanation:
duh
Answer:
is leslin testing on a brand hope it's helpful to you
Right ABC has coordinates a -7 and 3 B -7 and 10 in C -1 and 3 the triangle is reflected over the X axis and then reflected again over the Y axis to create ABC which are the coordinates of vertex a?
Answers
Answer:
Explanation:
X-axis = A (-7,-3) B (-7,-10) C (-1,-3) first they changed to the x-axis which is this. Just so you know on the x-axis the x-axis stay and the y-axis changed which is this.
When they reflect again on the y-axis the verter of A' is
A' (7, 3) = answer
On the y-axis the y- axis doesnt change but the x-axis changed.
Hope this help!
What is the acceleration of an object with an applied force of 100 N and a mass 50 kg? Q"
Answers
The acceleration of the object with an applied force of 100N and a mass of 50kg is 2m/s².
Acceleration is defined as the change in velocity per unit time. Velocity is defined as the speed of the object in a particular direction. The acceleration is a vector quantity. The unit of acceleration is m/s².
According to Newton's second law, Force is directly proportional to the acceleration of the object. F = m×a, where F is the force of the object, m is the mass of the object and a is the acceleration of the object.
From the given,
Force, F = 100N
mass of the object, m=50kg
acceleration of the object, a=?
F = m×a
a =F/m
= 100/50
=2m/s².
Thus, the acceleration of the object is 2m/s².
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What does Pascal's principle state?
A. The pressure at two pistons within an enclosed fluid system is
always the same.
B. The buoyant force on an object is equal to the weight of the fluid
displaced by the object.
C. The pressure of a fluid decreases as the speed of the fluid
increases.
D. The pressure exerted by a fluid decreases as depth increases.
Answers
Which of the following is not a vector
A) Acceleration
B) Length
C) Velocity
D) Force
Answers
9) when the distance was one fourth as much, what happened to the force between the objects?
in this case (G=6.67E-11)
Answers
Hi there!
Recall Newton's Law of Universal Gravitation:
\(\large\boxed{F_g = \frac{Gm_1m_2}{r^2}}\)
G = Gravitational Constant
m1, m2 = mass of objects (kg)
r = distance between objects (m)
There is an INVERSE-SQUARE relationship between the gravitational force and the distance between the objects, so:
\(F_g = \frac{Gm_1m_2}{(\frac{1}{4}r)^2} = F_g = \frac{Gm_1m_2}{\frac{1}{16}r^2}\)
\(= 16G\frac{m_1m_2}{r^2} = 16F_g\)
Thus, the gravitational force between the objects would INCREASE by a factor of 16.
A man weighing 800 Newtons is standing in an elevator. If the elevator rises with an acceleration of 0.5 meters per second2, the force exerted by the elevator on the man will be400 N800 N1200 N1000 N
Answers
If the elevator rises with an acceleration of 0.5 meters per second^2, the force exerted by the elevator on the man will be equal to the man's weight, which is 800 Newtons.
This is because the force exerted by the elevator on the man is equal to the man's mass multiplied by the acceleration of the elevator. In this case, the mass of the man is equal to his weight divided by the acceleration due to gravity, which is approximately 9.81 meters per second^2.
Therefore, the force exerted by the elevator on the man will be equal to his weight, which is 800 Newtons.
The correct answer is: 800 N
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Consider the polynomial
() = −0. 14 − 0. 153 − 0. 52 − 0. 25 + 1. 2
The true value of its derivative at x=0. 5 is ′
(0. 5) = −0. 9125. Use backward, forward, and centered
first finite differences to estimate the derivative numerically if the step size ∆ = 0. 25, and determine
the percent error between the true value and each of the estimated values (percent error is given by
= −
converted to a percentage. ) What value of ∆ would you have to use for the backward and forward
finite differences to get the same percent error as the centered finite difference (hint: it should be less
than 0. 25. )
Answers
The backward finite difference method for estimating the derivative at x=0.5 is:
(f(0.5) - f(0.25)) / (0.5 - 0.25) = (-0.14 - (-0.4025)) / (0.5 - 0.25) = 0.2625 / 0.25 = 10.5
The percent error between this estimate and the true value is:
|(10.5 - (-0.9125)) / (-0.9125)| * 100% = |11.4125 / (-0.9125)| * 100% = 12.48%
The forward finite difference method for estimating the derivative at x=0.5 is:
(f(0.75) - f(0.5)) / (0.75 - 0.5) = (-0.6275 - (-0.14)) / (0.75 - 0.5) = -0.4875 / 0.25 = -1.95
The percent error between this estimate and the true value is:
|(-1.95 - (-0.9125)) / (-0.9125)| * 100% = |-1.0375 / (-0.9125)| * 100% = 1.14%
The centred finite difference method for estimating the derivative at x=0.5 is:
(f(0.75) - f(0.25)) / (0.75 - 0.25) = (-0.6275 - (-0.4025)) / (0.75 - 0.25) = -0.225 / 0.5 = -0.45
The percent error between this estimate and the true value is:
|(-0.45 - (-0.9125)) / (-0.9125)| * 100% = |0.4625 / (-0.9125)| * 100% = 0.51%
To get the same percent error as the centred finite difference, we would have to use a step size of ∆ = 0.125.
This is because a smaller step size means a smaller difference between the estimates and the true value, and therefore a smaller percent error.
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1. Mr. Gewanter, whose mass is 60 kg, is doing a physics demonstration in the front of the classroom.
A. How much gravitational force does he exert on 55 kg Martha in the front row, 1.5 m away?
B. How much force does he exert on 65 kg Lester in the back row, 4.0 m away?
2. A 400 kg weather satellite is about to launched into orbit.
A. When the satellite is still on Earth, what is the gravitational force on it? (The mass of the Earth is 5.98x1024 kg and the radius of the Earth is 6.37x106 m)
B. What radius of orbit does the satellite need to experience half this force?
Answers
By performing a physics demonstration in front of the students. F is 9.79 x 108 newtons.
Given,
Mr. Gewanter weighs 60 kilograms (kg).
The weight of Martha is 55 kg.
d = 1.5 meters separates them.
The equation F = GMm/d2 newton determines the gravitational force between them.
changing the given values in the equation above
F = (6.673 x 1011 x 60 x 55)/1.52 = 9.79 x 108 newtons.
As a result, F = 9.79 x 108 newton is the gravitational pull Mr. Gewanter has on Martha.
A geostationary satellite travels in a circular path around the planet with a 36,000 km radius. The orbital period of a spy satellite will then be roughly (Re = 6400 km), orbiting a few hundred kilometers above the surface of the planet.
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much like a battery these generate electricity from chemical events
Answers
The term you are looking for is "chemical battery". Chemical batteries work by converting chemical energy into electrical energy through a series of chemical reactions. These reactions take place within the battery's cells, which are composed of two electrodes and an electrolyte.
When the battery is connected to a circuit, the chemical reactions produce an electrical current that can be used to power devices. Chemical batteries are widely used in many applications, including consumer electronics, electric vehicles, and renewable energy systems. They are a crucial component of our modern technological society, and ongoing research is focused on developing more efficient and sustainable battery technologies to meet growing energy demands.
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A yo-yo with a mass of 1 kg is being swung around in circles on a 2-meter long string at a constant speed of 4 m/s. What is the centripetal acceleration of the yo-yo?
Answers
Answer:
8 m/s²
Explanation:
Centripetal acceleration formula:
a = v²/r where v = velocity and r = radiusAs you can see, the mass of the yo-yo is not relevant to this problem.
We are given that the velocity of the yo-yo is 4 m/s.
The radius of the circle formed by the yo-yo on a 2-meter long string is 2 meters.
Substitute these known values into the equation.
a = (4)²/2 a = 16/2 a = 8The centripetal acceleration of the yo-yo is 8 m/s².
What is Newton's third law motion answer part a and b
Answers
Answer:
hope it helps
Explanation:
Newtons third law is that objects exert equal and opposite forces on each other.
'every action has an equal and opposite reaction'.
Answer:
to every action there's equal and opposite reaction
A computer uses 3. 5A at 110V what is the resistance and ohms
Answers
To calculate the resistance of the computer, we can use Ohm's law:
V = IR
where V is the voltage, I is the current, and R is the resistance.
In this case, the voltage is 110V and the current is 3.5A. Substituting these values into the equation gives:
110V = 3.5A * R
Solving for R, we get:
R = 110V / 3.5A
R ≈ 31.43 Ω
Therefore, the resistance of the computer is approximately 31.43 ohms (Ω).
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Realizing that she often doesn't have her students' full attention during class, a professor devises an elaborate device on which to stand while she lectures. (Figure 1) The pulley is placed so that the string makes a 45.0-degree angle with the beam. The beam is uniform, 5.00 meters long, and has weight wb . The professor stands 2.00 meters from the pivot point and has weight wp .
Find the tension T in the rope in terms of the professor's weight wp and the weight of the beam wb .
Answers
The tension T in the rope in terms of the professor's weight wp and the weight of the beam wb is T = 2 * (wb + wp) * 9.81 / sqrt(2).
Using the principle of torque equilibrium the torque produced by the weight of the beam is:
τb = wb * g * (5/2) * sin(45°)
where g is the acceleration due to gravity.
Next, let's calculate the torque produced by the weight of the professor. The torque produced by the weight of the professor is:
τp = wp * g * 2 * sin(45°)
Now, let's consider the tension in the rope. The tension in the rope acts at an angle of 45 degrees with the horizontal, so we need to resolve it into its horizontal and vertical components.
The vertical component of the tension balances the weight of the beam and the professor, so we have:
T * cos(45°) = wb * g + wp * g
Simplifying and substituting values, we get:
T * cos(45°) = (wb + wp) * 9.81 m/s^2
T * sqrt(2)/2 = (wb + wp) * 9.81 m/s^2
T = 2 * (wb + wp) * 9.81 / sqrt(2)
Therefore, the tension in the rope in terms of the professor's weight wp and the weight of the beam wb is:
T = 2 * (wb + wp) * 9.81 / sqrt(2)
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Kepler's second law is ultimately due to.
the conservation of angular momentum
Einstein's theory of special relativity
Newton's third law
Answers
We can see that Kepler's second law is ultimately due to A. the conservation of angular momentum.
What is Kepler's second law?Kepler's second law, also known as the law of equal areas, describes the motion of a planet or any object orbiting around a central body, such as the Sun. It states that a line connecting the planet to the Sun sweeps out equal areas in equal time intervals.
Angular momentum is a physical quantity that describes the rotational motion of an object or a system. According to the conservation of angular momentum, the total angular momentum of a system remains constant unless acted upon by an external torque.
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The complete question is:
Kepler's second law is ultimately due to _________.
A. the conservation of angular momentum
B. Einstein's theory of special relativity
C. Newton's third law
A 0.75M Sun white dwarf has a radius of 7.00 x 108 cm. Another white dwarf has a mass of 1.2M Sun: What is its density (in kg/m3)? What is the escape velocity (in km/s) from its surface?
Answers
The density of the white dwarf is 1.08 x 10³ kg/m³.The escape velocity from the surface of the second white dwarf is 15.8 km/s.
To find the density of the white dwarf, we can use the formula:
density = mass / volume
The volume of a sphere (which approximates the shape of the white dwarf) is:
volume = (4/3) x pi x radius³
Plugging in the given values for the first white dwarf, we get:
volume = (4/3) x pi x (7.00 x 1\(0^{8}\) cm)³
volume = 1.38 x 1\(0^{27}\) cm³
The mass of this white dwarf is 0.75M Sun, or 0.75 x 1.99 x 1\(0^{30}\) kg = 1.49 x 1\(0^{30}\) kg. Therefore:
density = 1.49 x 1\(0^{30}\) kg / 1.38 x 1\(0^{27}\) cm³
density = 1.08 x 10³ kg/m³
For the second white dwarf, we can use the formula for the escape velocity of an object:
escape velocity = (2GM/r)
where G is the gravitational constant, M is the mass of the object, and r is its radius. Plugging in the given values, we get:
escape velocity = (2 x 6.67 x 1\(0^{-11}\) N m²/kg² x 1.2 x 1.99 x 1\(0^{30}\) kg / (7.00 x 1\(0^{8}\) cm))
escape velocity = 1.58 x 1\(0^{4}\) m/s
escape velocity = 15.8 km/s
Therefore, the escape velocity from the surface of the second white dwarf is 15.8 km/s.
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‼️‼️EMERGENCY ITS DUE SOON‼️‼️
A box weighing 2000N is sliding across a cement floor. The force pushing the box is 500N, and the coefficient of sliding friction between the box and the floor is 0.20. What is the acceleration of the box? 
Answers
Answer:
I couldn't send you this over comments so you could keep your points but this is from an article I found that breaks it down. I hope it helps. I'm sorry I've never taken physics but wanted to help you.
Explanation:
Example 1
A box weighing 2000. N is sliding across a cement floor. The force pushing the box is 500. N, and the coefficient of sliding friction between the box and the floor is 0.20. What is the acceleration of the box?
In this case, the box is sliding along the ground, so the normal force for the box is equal to its weight. Using the normal force and the coefficient of friction, we can find the frictional force. We can also find the mass of the box from its weight since we know the acceleration due to gravity. Then we can find the net force and the acceleration.
FF=μFN=(0.20)(2000. N)=400. N
mass of box=weightg=2000. N9.8 m/s2=204 kg
FNET=pushing force−frictional force=500. N−400. N=100. N
a=FNm=100. N204 kg=0.49 m/s2
This question involves the concepts of frictional force, Newton's Second Law of Motion, and acceleration.
The acceleration of the box is "0.49 m/s²".
According to Newton's Second Law of Motion:
\(Net\ Force = ma\\F - f = ma\)
where,
F = Pushing force = 500 N
f = frictional force = μN
μ = coefficient of friction = 0.2
N = Normal Force = Weight = 2000 N
m = mass of box = \(\frac{N}{g}=\frac{2000\ N}{9.81\ m/s^2}=203.9\ kg\)
a = acceleration = ?
Therefore,
\(500\ N -\mu N=(203.9\ kg)a\\\\\frac{500\ N - (0.2)(2000\ N)}{203.69\ kg}=a\\\\\)
a = 0.49 m/s²
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The attached picture shows Newton's Second Law of Motion.
A proton moving at 7.0 × 10^4 m/s horizontally enters a region where a magnetic field of 0.10 t is present, directed vertically downward. What magnitude force acts on the proton due to this field?
Answers
The force on the proton due to the magnetic field is 1.12×10⁻¹⁵ N.
What is force?Force can be defined as the product of mass and acceleration
To calculate the force that acts on the proton due to the field, we use the formula below.
Formula:
F = qVB.............. Equation 1Where:
F = Force on the protonq = Charge of the protonV = Velocity of the protonB = Magnetic field.From the question,
Given:
q = 1.60 x 10⁻¹⁹ CB = 0.1 TV = 7×10⁴ m/sSubstitute these values into equation 1
F = (1.60 x 10⁻¹⁹)(0.1))(7×10⁴)F = 1.12×10⁻¹⁵ NHence, the force on the proton due to the magnetic field is 1.12×10⁻¹⁵ N.
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Un cuerpo lleva una velocidad de 122k por hora y de golpe frena reduciendo su velocidad a 50km por hora en un instante de tiempo de 4,5 segundos y la fuerza de frenado es de 1200n, ¿cual será su masa?
Answers
Answer:
La masa del objeto es 270.027 kilogramos.
Explanation:
Asumamos que el cuerpo decelera a tasa constante, entonces podemos calcularlo por medio de la siguiente ecuación cinemática:
\(a = \frac{v-v_{o}}{t}\) (1)
Donde:
\(v_{o}\) - Velocidad inicial, en metros por segundo.
\(v\) - Velocidad final, en metros por segundo.
\(t\) - Tiempo, en segundos.
\(a\) - Deceleración, en metros per segundo al cuadrado.
Si sabemos que \(v_{o} = 33.889\,\frac{m}{s}\), \(v = 13.889\,\frac{m}{s}\) y \(t = 4.5\,s\), entonces la deceleración experimentada por el cuerpo es:
\(a = \frac{v-v_{o}}{t}\)
\(a = -4.444\,\frac{m}{s^{2}}\)
Por las Leyes de Newton, tenemos que la masa del cuerpo se calcula a partir de la siguiente expresión:
\(m = \frac{F}{a}\) (2)
Donde:
\(m\) - Masa, en kilogramos.
\(F\) - Fuerza de frenado, en newtons.
Si sabemos que \(F = -1200\,N\) y \(a = -4.444\,\frac{m}{s^{2}}\), entonces la masa del cuerpo es:
\(m = \frac{F}{a}\)
\(m = 270.027\,kg\)
La masa del objeto es 270.027 kilogramos.
an apple has a mass of 2kg. it is 3 m above ground. What is its potential energy?
Answers
Answer:
PE = 58.8J
Explanation:
potential energy = mgh
mass = 2kg
g = 9.8m/s^2
h = 3m
A rock once contained 1.0 mg of uranium-238, but now contains only 0.25 mg. Given that the half-life for uranium-238 is 4.5 x 10^9 (4.5 billion) years, how old is the rock?
Answers
Answer:
9 x 10 ^9 yrs ( 9 billion years <=====older than Earth !)
Explanation:
.25 = 1.0 (1/2) ^n
.25 / 1.0 = = (1/2 )^n
log .25 = n log 1/2
n = 2 half lives
2 * 4.5 x 10^9 = 9 x 10 ^ 9 yrs
The sides of a rectangle are 6.01 meters and 12 meters. Taking the significant figures into account, what is the area of the rectangle? A. 70 square meters B. 72 square meters C. 72.00 square meters D. 72.1 square meters
Answers
Answer:
D. 72.1 m^2
Explanation:
6.01m x 12m = 72.12 m^2
A source of strong electric and magnetic fields will produce light with higher
a. amplitude
b. frequency
c. wavelength
d. wave speed
e. period
Answers
How far has a dolphin traveled in kilometers if it swims for 1.8 h at 5.6 km/h ?
Answers
Answer:
distance = 6.26342 miles
Explanation:
A car starts with a speed of 80 km/hr and slows to a rate of 50 km/hr in 5 sec
Answers
If the question is asking for acceleration,
To find acceleration, we have to find the change in velocity over the change in time
In this case, the change of velocity is -30 km/hr and the change in time is 5 seconds
We must convert the units of sec to hours to solve this question
5 sec * 1 min/60 seconds * 1 hour/60 min = .00138889 hours
acceleration = change in velocity / change in time = -30 km/hr / .00138889 hours = -21599.999 km/hr^2 = ~-21600 km/hr^2
Varsha16
varsha16
Explanation:
The state of matter of a material depends on its how fast its particles move and how strong the attraction is between its atoms and molecules
Answers
Matter is anything that has mass and occupies space, and it comes in three main states: solids, liquids, and gases. The state of matter of a material depends on how fast its particles move and how strong the attraction is between its atoms and molecules. Let's take a look at each state of matter and how these factors influence them.
Solids: In a solid, the particles are tightly packed together and have very little room to move. The attraction between atoms and molecules is very strong, which means they vibrate in place but cannot move around freely. This is why solids have a fixed shape and volume.
Liquids: In a liquid, the particles are more spread out than in a solid, but they are still in close contact with each other. The attraction between atoms and molecules is weaker than in a solid, which means they are able to move around more freely. This is why liquids have a fixed volume but not a fixed shape.
Gases: In a gas, the particles are very spread out and have a lot of room to move around. The attraction between atoms and molecules is very weak, which means they can move around freely. This is why gases have neither a fixed shape nor a fixed volume.
The state of matter of a material can also change depending on external factors like temperature and pressure. For example, if you increase the temperature of a solid, it can become a liquid, and if you increase the temperature of a liquid, it can become a gas. Similarly, if you decrease the pressure on a gas, it can become a liquid, and if you decrease the pressure on a liquid, it can become a solid.
In conclusion, the state of matter of a material depends on how fast its particles move and how strong the attraction is between its atoms and molecules. Solids have the strongest attraction, followed by liquids, and then gases. The state of matter can also change depending on external factors like temperature and pressure.
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These data tables show the distance of various galaxies from Earth in millions of light-years (Mly) at different times. Which table supports the theory of expansion in the formation of the universe?
Answers
Answer: it’s b
Explanation:
I had two attempts to do the test first I picked c but I did it again it’s b .
5. A 15 kilogram crate is held 2 meters above a spring with a spring constant of 2500 N/m. When
the crate is dropped, it lands on the spring, compressing it. How far does the spring compress?
Show all work, including the formula and substitution with units
I
Answers
To determine how far the spring compresses when the crate is dropped onto it, we can use the principles of potential energy and Hooke's Law.
The potential energy of the crate at its initial height is given by the formula: potential energy = mass * gravity * height.
Potential energy = 15 kg * 9.8 m/s^2 * 2 m = 294 J
When the crate lands on the spring, this potential energy is converted into elastic potential energy stored in the compressed spring. According to Hooke's Law, the elastic potential energy in a spring is given by the formula: elastic potential energy = 0.5 * spring constant * (compression)^2.
Equating the initial potential energy to the elastic potential energy of the compressed spring, we have:
294 J = 0.5 * 2500 N/m * (compression)^2
Simplifying the equation, we find:
(compression)^2 = (294 J * 2) / (0.5 * 2500 N/m)
(compression)^2 = 1.176 m^2
compression ≈ √1.176 ≈ 1.08 m
Therefore, the spring compresses approximately 1.08 meters when the crate is dropped onto it.
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