Many pain relief pills have powder that is enclosed inside a capsule. Why might this
type of medicine work faster that a tablet if they both have the same amount and
type of medicine?
powder has more surface area and will dissolve in the bloodstream faster
tablets have less surface area and will enter the bloodstream without dissolving
powder has less surface area and will dissolve in the bloodstream faster
tablets have more surface area and will take longer to dissolve into the bloodstream
Answers
Answer:
A
Explanation:
A) powder has more surface area and will dissolve in the bloodstream faster.
Encapsulated powder has a larger surface area compared to a tablet due to its fine particle size and loose nature. When ingested, the capsule dissolves quickly in the stomach, releasing the powder which dissolves rapidly in the digestive tract. The large surface area of the powder allows it to dissolve more quickly in the bloodstream, leading to faster pain relief. In contrast, a tablet may take longer to break down in the digestive tract, which can slow the release of the medication and delay its effectiveness.
It is not D) tablets have more surface area and will take longer to dissolve into the bloodstream because tablets have a smaller surface area compared to powders.Tablets are typically made by compressing a powder mixture into a solid form using pressure, which leads to a more compact structure with less surface area compared to a loose powder. This can make it more difficult for the digestive juices to penetrate the tablet and dissolve the medication, leading to slower dissolution and absorption.In contrast, encapsulated powders have a larger surface area due to their fine particle size and loose nature, which allows for faster dissolution in the bloodstream. When the capsule dissolves in the stomach, the powder is quickly released and the large surface area of the powder particles allows for more efficient contact with the digestive juices, leading to faster dissolution and absorption.
Related Questions
What is an example of climate?
Answers
Answer:
Tropical.Dry.Temperate.Continental.Polar.Explanation:
The tropical climate in the Köppen system is defined as having an average temperature in every month of above 18°C. There is no winter season, and annual rainfall is large and exceeds the annual evaporation. The dry climate regions are characterized by evaporation surpassing the humidity of precipitation. It is represented with the letter "B" in the Köppen climate classification. Precipitation is infrequent and vegetation is scarce in these areas. Temperate climates are generally defined as environments with moderate rainfall spread across the year or portion of the year with sporadic drought, mild to warm summers and cool to cold winters.A relatively dry climate with very hot summers and very cold winters, characteristic of the central parts of Asia and North America. A polar climate consists of cool summers and very cold winters, which results in treeless tundra, glaciers, or a permanent or semi-permanent layer of ice. It is identified with the letter E in the Köppen climate classification.#Let's Study
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What are characteristics of all protests?
Answers
Answer:
Explanation:
Una manifestación, protesta o marcha es la exhibición pública de la opinión de un grupo activista (económica, política o social), mediante una congregación en las calles, a menudo en un lugar o una fecha simbólicos y asociados con esa opinión.
pleaseeeeeeeeeee someone help urgent we are writing a test tmr can some one please explain subatomic particles to me...
Answers
Answer:
n physical sciences, subatomic particles are smaller than atoms. They can be composite particles, such as the neutron and proton; or elementary particles, which according to the standard model are not made of other particles. Particle physics and nuclear physics study these particles and how they interact.
Explanation:
a particle smaller than an atom (e.g., a neutron) or a cluster of such particles (e.g., an alpha particle).
balance each of the following redox reactions occurring in acidic solution. part a i−(aq) no−2(aq)→i2(s) no(g)
Answers
The balanced redox reaction occurring in acidic solution between i−(aq) and no−2(aq) is 6 i−(aq) + 2 no−2(aq) → 3 i2(s) + 2 no(g). This reaction involves the transfer of six electrons and occurs in an acidic solution.
To balance the redox reaction occurring in acidic solution between i−(aq) and no−2(aq), we need to follow a series of steps:
Step 1: Identify the oxidation and reduction half-reactions. In this case, i− is oxidized to i2, and no−2 is reduced to no.
i−(aq) → i2(s) (oxidation half-reaction)
no−2(aq) → no(g) (reduction half-reaction)
Step 2: Balance the number of atoms in each half-reaction. In the oxidation half-reaction, we have one iodine atom on the reactant side and two on the product side, so we need to add a coefficient of 2 in front of i−(aq):
2 i−(aq) → i2(s)
In the reduction half-reaction, we have one nitrogen atom on both the reactant and product sides, so we don't need to add any coefficients.
no−2(aq) → no(g)
Step 3: Balance the number of electrons transferred in each half-reaction. To do this, we need to determine the oxidation state of each element and use the change in oxidation state to calculate the number of electrons transferred.
For the oxidation half-reaction, the oxidation state of iodine goes from -1 to 0, so it gains one electron. Therefore, we need to add one electron to the product side:
2 i−(aq) → i2(s) + 2 e−
For the reduction half-reaction, the oxidation state of nitrogen goes from +3 to 0, so it gains three electrons. Therefore, we need to add three electrons to the reactant side:
no−2(aq) + 3 e− → no(g)
Step 4: Multiply the half-reactions by coefficients to balance the number of electrons transferred. To do this, we need to find the least common multiple of the number of electrons transferred in each half-reaction, which is 6. We can achieve this by multiplying the oxidation half-reaction by 3 and the reduction half-reaction by 2:
6 i−(aq) → 3 i2(s) + 6 e−
2 no−2(aq) + 6 e− → 2 no(g)
Step 5: Add the half-reactions together and cancel out any common terms. In this case, the electrons cancel out, leaving us with:
6 i−(aq) + 2 no−2(aq) → 3 i2(s) + 2 no(g)
Therefore, the balanced redox reaction occurring in acidic solution between i−(aq) and no−2(aq) is 6 i−(aq) + 2 no−2(aq) → 3 i2(s) + 2 no(g). This reaction involves the transfer of six electrons and occurs in an acidic solution.
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a current of 3.69 a 3.69 a is passed through a fe(no3)2 fe ( no 3 ) 2 solution. how long, in hours, would this current have to be applied to plate out 5.90 g 5.90 g of iron?
Answers
The time required to plate out 5.90 g of iron using a current of 3.69 A in a Fe(NO3)2 solution is 67.53 hours. This calculation is based on Faraday's Law of Electrolysis.
The method involved with saving a metal from an answer onto a cathode utilizing an electric flow is called electrolysis. How much metal that can be kept relies upon the ongoing going through the arrangement, the time the current is applied, and the molar mass of the metal.
For this situation, we are given an answer of Fe(NO3)2 and a current of 3.69 A, which is gone through the answer for plate out 5.90 g of iron. We can utilize Faraday's law of electrolysis to decide the time expected for this interaction. The condition is:
mass of substance = (current × time × molar mass)/(Faraday's consistent)
Reworking the condition to settle for time, we get:
time = (mass of substance × Faraday's consistent)/(current × molar mass)
Subbing the given qualities into the situation, we get:
time = (5.90 g × 96,485 C/mol)/(3.69 A × 55.85 g/mol) = 6.52 hours
In this manner, a current of 3.69 A would should be gone through the Fe(NO3)2 answer for 6.52 hours to plate out 5.90 g of iron.
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calculate the molarity of 65.3 grams of sugar(342.3 g/mol), c12h22011 in 750 ml of solution.
Answers
Answer:
0.254 M
Explanation:
If the formula mass of sugar is 342.3 g/mol, and there are 65.3 g, then there are 65.3/342.3=0.190768 mol.
Also, 750 mL = 0.750 L.
molarity = (moles of solute)/(liters of solution)
molarity = 0.190768/0.750 = 0.254 M
A solution with ph 4 has __________ the h concentration of a solution with ph 8.
Answers
A solution with ph 4 has 10000 times the h concentration of a solution with ph 8.
the solution, in chemistry, is a homogeneous mixture of two or more substances whose relative amounts can be varied continuously up to the so-called solubility limit. The term solution is usually applied to the liquid state of aggregation, but gaseous and solid solutions are also possible. Hypotonic, isotonic, and hypertonic solutions (tonic).
A solution is a homogeneous mixture of two or more components with particle sizes less than 1 nm. Common examples of solutions are the sugar in water and salt in water, soda water, etc. In solution, all components appear as a single phase.
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A gas has a volume of 150 cm3. Convert this volume into mL
Answers
Answer:
The answer is
150 mLExplanation:
To convert the volume from cm³ to mL we use the conversion
1 cm³ = 1 mL
So from the question
if 1 cm³ = 1 mL
Then 150 cm³ = 150 mL
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Which option is an example of a chemical property?
A. boiling point
B. ability to react with oxygen
C. color
D. density
Answers
Answer:
boiling point
Explanation:
Option B
What type of reaction is this: 2CaO - 2Ca + O2
Answers
Answer:
White or gray, odorless lumps or granular powder.
Name the type of reaction shown:2C4H10+13O2=8CO2+10H2O
Answers
Answer: It is AN combustion
reaction.
Explanation:
If the temperature outside is 75oF and the dew point is 75oF what is the humidity?
Answers
Answer:
in this file you will find it https://xlbrands.com/wp-content/uploads/2014/06/DEW-POINT-CALCULATION-CHARTenglish.pdf
Explanation:
which is a physical property of a substance
Answers
Considering the definition of physical property, a physical property is a characteristic that describes an object or substance and can be measured without affecting the composition or identity of the substance.
What is physical propertyA physical property is a characteristic that describes an object or substance and is based primarily on the structure of the object, substance or matter, which is visible and measurable.
That is, physical properties are those that can be measured without affecting the composition or identity of the substance. In this way, the physical properties of matter are the visible and characteristic characteristics of a substance that can be measured and do not produce new chemical substances.
Some examples of physical properties are: color, shape, size, density, melting point and boiling point.
SummaryA physical property is a characteristic that describes an object or substance and can be measured without affecting the composition or identity of the substance.
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Solid aluminum reacts with aqueous hydrochloric acid to form aqueous aluminum chloride and hydrogen gas. (0.15 g of aluminum are combined with 0.35 g of hydrochloric acid.) 1. Write and balance the equation. 2. Calculate the grams of hydrogen gas that can be theoretically formed. 3. Identify the limiting reactant, and justify your choice. 4. If the percent yield for this reaction was 72.44%, what is the actual yield, in grams?
Previous question
Answers
The actual yield of hydrogen gas is 0.024 g.
The balanced chemical equation for the reaction is:
\(2 Al(s) + 6 HCl(aq) → 2 AlCl3(aq) + 3 H2(g)\)
To calculate the grams of hydrogen gas that can be theoretically formed, we need to use stoichiometry. From the balanced equation, we can see that 2 moles of aluminum react with 6 moles of hydrochloric acid to produce 3 moles of hydrogen gas. Therefore, we can use the mole ratio to calculate the theoretical yield of hydrogen gas:
0.15 g Al x (1 mol Al/26.98 g Al) x (3 mol H2/2 mol Al) x (2.02 g H2/1 mol H2) = 0.033 g H2
Therefore, the theoretical yield of hydrogen gas is 0.033 g.
To identify the limiting reactant, we need to compare the amount of each reactant to the stoichiometry of the balanced equation. From the given masses, we can convert them to moles:
0.15 g Al x (1 mol Al/26.98 g Al) = 0.00556 mol Al
0.35 g HCl x (1 mol HCl/36.46 g HCl) = 0.0096 mol HCl
Using the stoichiometry of the balanced equation, we can see that 0.00556 mol of aluminum would require 0.0167 mol of hydrochloric acid. Since we have more hydrochloric acid than required, it is not the limiting reactant. Therefore, aluminum is the limiting reactant.
To calculate the actual yield of the reaction, we can use the percent yield equation:
% yield = (actual yield/theoretical yield) x 100
Rearranging the equation, we can solve for the actual yield:
actual yield =\(% yield x theoretical yield/100\)
Plugging in the given values, we get:
actual yield = 72.44 x 0.033 g / 100 = 0.024 g
Therefore, the actual yield of hydrogen gas is 0.024 g.
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UCI Chemistry researchers, Prof. F. Sherwood Rowland and Dr. Mario Molina werefirst to discovered in 1973 that chlorofluorocarbons (CFCs) were depleting the Earth’sozone layer when released into the atmosphere. Once they reach the stratosphere, Clis released from the CFCs molecules by interaction with UV light. Free Cl atoms areable to react with ozone in a catalytic cycle that converts O3into the more stable O2.It is estimated that a single Cl atom is able to react with∼100000 O3molecules.Although CFCs production was banned in 1996, there are still a substantial numberof motor vehicle air conditioners (MVACs) that use CFC-12 (CF2Cl2) as refrigerant.The average CFC-12 emission rate from operating MVACs has been estimated tobe 59.5 mg per hour per vehicle (Zhang et al.Environ. Sci. Technol. Lett.2017).How much chlorine, in kg, is added to the atmosphere in a year due to 100 millionMVACs using CFC-12 as refrigerant?
Answers
Answer:
15.27895 x 10⁶kg of chlorine radical is added to the atmosphere in a year due to 100 million MVACs
Explanation:
Chlorofluorocarbons (CF₂Cl₂) from refrigerants produce chlorine radicals according to the following equation
CF₂Cl₂ → CF2Cl + Cl ⁻ .........(1)
From equation 1, one mole of CF₂Cl₂ produces one mole of Chlorine radical
From the question,
The emission rate of CF₂Cl₂ is 59.5mg/hour/MVAC
In one day the emission rate would be 59.5 x 24hours
= 1428mg/day
In one year, the emission rate would be 1428mg/day x 365days
= 521220mg/year
= 521.220g/year/MVAC
Therefore the emission rate for 100 million MVAC using CF₂CL₂ in a year is
= 52122 x 10⁶g/year/MVAC
= 52122 x 10³kg/year/MVAC
The molar mass of CF₂CL₂ = 120.913g/mol
No of moles of CF₂CL₂ = mass/ molar mass
= 52122 x 10⁶g / 120.913g/mol
= 431 x 10⁶ moles of CF₂Cl₂
From equation 1, since one mole of CF₂Cl₂ produces one mole of Chlorine radical, it implies that
431 x 10⁶ moles of CF₂Cl₂ would produce 431 x 10⁶ moles of chlorine radical,
Therefore, to find the mass of chlorine radical produced, we use the formula
No of moles of chlorine radical = mass/ molar mass
431 x10⁶ moles = mass of chlorine radical /molar mass of chlorine radical
431 x 10⁶ moles = mass/ 35.45g/mol
mass of chlorine = 431 x 10⁶ moles x 35.45 g/mol
= 15278.95 x 10⁶ g
In Kg, the mass = 15,278.95 x 10³kg of cholrine radical
= 15.27895 x 10⁶ Kg of chlorine radical
explain what keeps the electrons confined in the space surrounding the nuleus
Answers
Answer:
Electrons are trapped inside the atom because of the attraction forces with positively charged protons that are found in the nucleus.
what is the coefficient for oh−(aq) when mno4−(aq) h2s(g) → s(s) mno(s) is balanced in basic aqueous solution?
Answers
The coefficient for OH⁻(aq) in the balanced equation is 8. The equation of a redox reaction in which oxidation and reduction take place is known as a redox equation.
To balance the equation in basic aqueous solution, the following steps can be followed:
Balance the atoms other than oxygen and hydrogen. In this case, Mn and S are already balanced.
Balance oxygen atoms by adding H₂O to the side that needs more oxygen. In this case, the left side needs more oxygen, redox reaction so we add H₂O to the left side:
MnO₄⁻(aq) + H₂S(g) → S(s) + MnO₂(s) + H₂O
Balance hydrogen atoms by adding H⁺ ions to the side that needs more hydrogen. In this case, the right side needs more hydrogen, so we add H⁺ ions to the right side:
MnO₄⁻(aq) + H₂S(g) → S(s) + MnO₂(s) + H₂O + 4H⁺
Balance the charge by adding electrons. In this case, the left side has a charge of -1, while the right side has a charge of +2. To balance the charges, we add 6 electrons to the left side:
MnO₄⁻(aq) + H₂S(g) + 6OH⁻(aq) → S(s) + MnO₂(s) + H₂O + 4H₂O + 6e⁻
Finally, balance the electrons by multiplying the half-reactions by appropriate coefficients. In this case, we multiply the reduction half-reaction by 6 and the oxidation half-reaction by 1:
6MnO₄⁻(aq) + 6H₂S(g) + 6OH⁻(aq) → 6S(s) + 6MnO₂(s) + 7H₂O
Therefore, the coefficient for OH⁻(aq) in the balanced equation is 6 × 2 = 12.
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A 634.5 g sample of helium absorbs 125.7 calories of heat. The specific heat capacity of helium is 1.241 cal/(g·°C). By how much did the temperature of this sample change, in degrees Celsius?
Answers
Answer:
\(\Delta T=0.160\°C\)
Explanation:
Hello there!
In this case, according to the following equation for the calculation of heat in this calorimetry problem:
\(Q=mC\Delta T\)
It is possible for us to calculate to calculate the change in temperature for this process by solving for DT in the aforementioned equation:
\(\Delta T=\frac{Q}{mC}\\\\ \Delta T=\frac{125.7cal}{634.5g*1.241 cal/(g\°C)} \\\\ \Delta T=0.160\°C\)
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g enter your experimental data into columns d-g. 2. use your temperature data and equation 7.1 to determine the calories of heat released (column h) for each sample combustion. enter the calculation of q using equation 7.1 into the cells of column h with the appropriate mass of water for m. the specific heat of water for c and at= column g entry - column f entry. report your results to the proper number of significant figures. 3. use the initial sample mass to determine the cal/g (column 1) you measured for each sample. if you used different sizes of sample and got very different results for a particular food, which value is likely to be more reliable? explain why. 4. use the mass lost in the burning (column e entry - column d entry) to determine the salg lost (column j) for each sample.
Answers
It is important to be concise and not provide extraneous amounts of detail.
When answering questions on the Brainly platform, you should always aim to be factually accurate, professional, and friendly. Additionally,You should also use the following terms in your answer if they are relevant to the question being asked
g enter your experimental data into columns d-g.
2. use your temperature data and equation 7.1 to determine the calories of heat released (column h) for each sample combustion. enter the calculation of q using equation 7.1 into the cells of column h with the appropriate mass of water for m. the specific heat of water for c and at
= column g entry - column f entry. report your results to the proper number of significant figures.
3. use the initial sample mass to determine the cal/g (column 1) you measured for each sample. if you used different sizes of sample and got very different results for a particular food, which value is likely to be more reliable? explain why.
4. use the mass lost in the burning (column e entry - column d entry) to determine the salg lost (column j) for each sample.
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Which statement characterizes an aqueous solution of a weak acid at room temperature? The hydrogen ion concentration is less than the hydroxide ion concentration. The solution turns red litmus paper blue. The pH is larger than 7. O the hydroxide ion concentration is less than 1 x 10-7M.
Answers
An aqueous solution of a weak acid at room temperature is characterized by the statement: "The hydrogen ion concentration is less than the hydroxide ion concentration."
In an aqueous solution of a weak acid, such as acetic acid there is a dynamic equilibrium between the dissociated and undissociated forms of the acid. The weak acid partially ionizes in water to form hydrogen ions and the corresponding conjugate base (in this case, acetate ions, Since the acid is weak, only a small fraction of the acid molecules dissociate.
The statement "The hydrogen ion concentration is less than the hydroxide ion concentration" is true because in a weak acid solution, the equilibrium lies more towards the undissociated form of the acid. As a result, the concentration of hydrogen ions is lower compared to the concentration of hydroxide ions in the solution. This leads to a pH value less than 7, indicating an acidic solution.
Therefore, the statement accurately characterizes an aqueous solution of a weak acid at room temperature.
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5. What must occur for a change to be a chemical reaction?
Answers
Answer:
A chemical reaction happens when two substances combine into a new one through chemical synthesis or chemical decomposition for two or more.
Explanation:
convert 33.6 degree Celsius to degree Fahrenheit
Answers
Answer:
Your answer is 92.48 degrees Fahrenheit, or just 92 degrees.
Explanation:
The formula for finding degrees Celsius and turning them into Fahrenheit is: (C x 9/5) + 32. So,
33.6 x 9/5 = 60.48
60.48+ 32= 92.48.
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what will be the experimental set up to electroplate nickel on tin. be sure to mention which metal will be connected to positive and negative terminals of the power supply and what solution will be chosen.
Answers
The anode (positive terminal of power supply) will be connected to the nickel electrode and at the cathode (negative terminal of power supply), the tin metal object will be connected.
Electroplating is a process in which an electrolytic cell is used to form a metal coating on a substrate or workpiece.
The following is the experimental setup for electroplating nickel on tin :
At the cathode (negative terminal of power supply), the tin metal object will be connected. The metal object to be electroplated is referred to as the cathode in electroplating.
In the electrolytic solution, it is submerged and functions as the electrode that attracts cations (positively charged ions).
Nickel is the metal that will be plated on it. The anode (positive terminal of power supply) will be connected to the nickel electrode. Nickel is the metal that will be electroplated onto the substrate, and it is submerged in the electrolytic solution.
In the electrolytic solution, the nickel electrode will release cations (positively charged ions), which will deposit on the tin electrode as a metal coating. The electrolytic solution used for electroplating nickel on tin is a nickel sulfate solution.
The process of electroplating nickel on tin begins with immersing the tin workpiece into the nickel sulfate solution and connecting it to the cathode. The nickel electrode is then submerged in the electrolytic solution and connected to the anode. When the power supply is turned on, nickel cations are released from the nickel electrode and migrate to the cathode (tin workpiece) because opposites attract. The nickel ions are then reduced at the cathode surface, forming a layer of nickel metal on the tin workpiece.
Thus, the experimental set up to electroplate nickel on tin is explained above.
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How much heat must be transferred to 1600 g of iron to change the iron's
temperature from 202°C to 214°C? (The specific heat capacity of iron is
0.450 J/g.°c.)
O A. 8600 J
O B. 3.4 J
O C. 300
O D. 60 J
Answers
Answer:
A. 8600 J
General Formulas and Concepts:
Thermochemistry
Specific Heat Formula: q = mcΔT
q is heat (in J)m is mass (in g)c is specific heat (in J/g °C)ΔT is change in temperature (in °C)Explanation:
Step 1: Define
[Given] m = 1600 g
[Given] ΔT = 214 °C - 202 °C = 12 °C
[Given] c = 0.450 J/g °C
[Solve] q
Step 2: Find Heat
Substitute in variables [Specific Heat Formula]: q = (1600 g)(0.450 J/g °C)(12 °C)Multiply [Cancel out units]: q = (720 J/°C)(12 °C)Multiply [Cancel out units]: q = 8640 JStep 3: Check
Follow sig fig rules and round. We are given 2 sig figs as our lowest.
8640 J ≈ 8600 J
Topic: AP Chemistry
Unit: Thermodynamics
H2CO: → H2O + CO2
Answer the following question about the equation above.
1. How many atoms of Hydrogen are in the reactant?
2. How many atoms of Carbon are in the reactant?
3. How many atoms of Oxygen are in the reactant?
4. How many atoms of Hydrogen are in the product?
5. How many atoms of Oxygen are in the product?
6. How many atoms of Carbon are in the product?
7. Does the number of atoms of each element on the reactant side match that of the product side?
Answers
Answer:
1) 2
2) 1
3)1
4) 2
5)3
6)1
7)yes except Oxygen
Consider the word equation.
calcium hydroxide + hydrochloric acid → calcium chloride + water
Which is the corresponding formula equation?
A: CaCl2(1)→ Ca(s) + Cl2(g)
B: O CaO(s)+ H2O(1)>Ca(OH)2(aq)
C: NaOH(aq) + 2HCl(aq) → NaCl(aq) + 2H2O(1)
D: Ca(OH)2(S) + 2HCI(I) → CaCl2(aq) + 2H20(1)
Answers
The chemical equation for the given word equation is Ca(OH)\(_2\)(S) + 2HCI(I) → CaCl\(_2\)(aq) + 2H\(_2\)0(1). Therefore, the correct option is option D.
Chemical equations are symbols or chemical formulas that depict a chemical reaction symbolically. With a plus sign separating the entities in the reactants and products, the reactant objects are listed on the left as well as the result entities are listed on the right.
An arrow indicating the reaction's direction points in the path of the products. The chemical formulas could be mixed, symbolic, or structural. The critical values of a stoichiometric figures are shown as coefficients beside the symbols as well as formulas of the various entities. The chemical equation for the given word equation is Ca(OH)\(_2\)(S) + 2HCI(I) → CaCl\(_2\)(aq) + 2H\(_2\)0(1).
Therefore, the correct option is option D.
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How many moles are in 64 g of O2?
Answers
Answer:
4 moles
Explanation:
Thus, 64 grams of oxygen contains 4 moles.
Heat i removed from a 1. 6-microgram ample of liquid in a ealed container. The liquid tranform into a olid. After the tate change, what i the ma of the olid?
Answers
The mass of the solid after the state change would still be 1.6 micrograms. Mass is a measure of the amount of matter in an object, and it remains constant during a phase change (such as from a liquid to a solid) as long as no matter is added or removed from the system.
About MicrogramsIn the metric system, a microgram is a unit of mass equal to one million grams. The unit symbol is μg according to the International System of Units; the recommendation symbol in the United States and United Kingdom when conveying medical information is mcg.
Formula Micrograms :
1 kilogram
1 * 10^3 gram
1 microgram
1 * 10^-3 gram
1 kilogram / 1 microgram
10^3 / 10^-3
10^6
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how do gas particles exert pressure on their container?
Answers
Gas particles exert pressure on their container through their random and constant motion, colliding with the walls of the container.
Gas particles are in constant motion, moving in all directions with varying speeds. When these particles collide with the walls of their container, they exert a force on the walls. The cumulative effect of these collisions leads to the creation of pressure within the container. The more frequent and energetic the collisions, the higher the pressure exerted by the gas.
The pressure exerted by gas particles is a result of the collective impact of their collisions with the container walls. This pressure is directly related to the temperature, volume, and number of gas particles present. Understanding the behavior of gas particles and their interactions with the container is crucial in various scientific and practical applications, such as in the study of thermodynamics, gas laws, and the design and operation of systems involving gases, such as engines and gas cylinders.
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STATES THAT FOR AN ATOM IN THE GROUND STATE, THE NUMBER OF UNPAIRED ELECTRONS IS THE MAXIMUM POSSIBLE AND THESE UNPAIRED ELECTRONS HAE THE SAME SPIN
Answers
Answer:
Hund's rule
Explanation:
Hund's rule states that for an atom in the ground state, the number of unpaired electrons is the maximum possible and these unpaired electrons have the same spin.
I will clearly illustrate this using the ground state of the nitrogen atom. Nitrogen atom contains seven electrons. Its electronic configuration is; 1s2 2s2 2px1 2py1 2pz1.
Notice that the number of unpaired electrons in this configuration is maximum and they are all expected to possess the same spin in accordance with Hund's rule .