mention the type of motion taking place in, horse pulling a cart which type of motion​

When light encounters an obstacle such as a wall, it can be either absorbed, transmitted, reflected, or refracted. The way in which light is blocked depends on the characteristics of the obstacle and the properties of the light.

For example, a solid object such as a wall absorbs light, meaning that the energy of the light is transferred to the object, causing the object to heat up. This can result in the object becoming warmer, such as a wall or floor in direct sunlight, or it can result in the object changing its chemical properties, such as with photosensitive materials like photographic film.

Reflection occurs when light bounces off an object, changing the direction of the light. This can result in a mirror image or a diffuse reflection, depending on the characteristics of the object.

Refraction occurs when light passes through an object, changing the direction of the light. This can occur when light passes through transparent materials such as water or glass.

Finally, light can also be blocked by scattering, which occurs when light is dispersed in many different directions as it encounters small particles in the atmosphere, such as dust or water droplets. This is why the sky appears blue during the day, as the shorter blue wavelengths of light are scattered more than the longer wavelengths of red and orange light.

Lower frequencies (red) move faster in a glass prism than higher frequencies.

Light of all colors moves at the same speed in a vacuum. However, light travels at different speeds in many media, including water.

Red light moves through glass at the fastest speed, whereas violet light moves at the slowest speed.

Red light bends the least of all the colors because it moves at the fastest speed, whereas violet light moves at the slowest speed and bends the most.

Wavelength and speed are directly proportional. Speed also rises with increasing wavelength. Light that has a maximal wavelength therefore moves at its fastest.

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Answer:

Explanation:

Let's just have our reference frame travel along with the original un broken mass. This way the original velocity is not relevant.

Each half will have a mass of 770/2 = 385 kg

Each half will have the same magnitude of velocity (conservation of momentum) which will be 2.6 x 10³/2 = 1.30 x 10³ m/s

Now add back the reference frame velocity to get velocity relative to earth.

Section one will have velocity 6.90 x 10³ + 1.30 x 10³ = 8.2 x 10³ m/s

Section two will have velocity 6.90 x 10³ - 1.30 x 10³ = 5.6 x 10³ m/s

In the moving reference frame, each half will have kinetic energy which could only come from the explosion

KE = ½(385)(1.3 x 10³)² = 325,325,000 J

2(325,325,000) = 650,650,000 J released in the explosion.

Rounding to the three significant figures of the problem numerals

E = 6.50 x 10⁸ J or 650 MJ released

The concept of time in space can be different from time on Earth due to the effects of time dilation. Time dilation occurs due to differences in gravitational fields and relative motion.

If we consider an astronaut who is in a relatively low-gravity environment and not traveling at a significant fraction of the speed of light, the time experienced by the astronaut in space would be very similar to the time experienced on Earth. In this scenario, one hour in space would be approximately the same as one hour on Earth.

However, if we consider extreme cases, such as an astronaut near a black hole or traveling at near-light speeds, time dilation effects would become significant. In these situations, the time experienced by the astronaut would be different from the time on Earth.

It's important to note that the magnitude of time dilation effects depend on the specific conditions and relative velocities involved. For most common space travel scenarios, the difference in time between space and Earth is negligible, and one hour in space would correspond to one hour on Earth.

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Answer:

Explanation:

according to the graph at B the potential energy of the particle is 2J

therefore we can use the kinetic energy equation to calculate the particle's velocity or speed.

\(E_{k} =1/2mv^{2}\)

2J= 1/2*1/2kg*v^2

8=v^2

v= 2√2 ms-1

The displacement of the train after 2.23 seconds is 25.4 m.

The resultant velocity of the train is calculated as follows;

R² = vi² + vf² - 2vivf cos(θ)

where;

R² = 8.81² + 9.66² - 2(8.81 x 9.66) cos(76)

R² = 129.75

R = √129.75

R = 11.39 m/s

The displacement of the train is the change in position of the train after a given period of time.

The displacement is calculated as follows;

Δx = vt

Δx = 11.39 m/s x 2.23 s

Δx = 25.4 m

Thus, the displacement of the train after 2.23 seconds is 25.4 m.

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Answer:

b. they both have permanent magnets and elctromagnetes

Answer:

A)    Magnetic and electric are part of the same force - see Maxwell's equations.

Answer:

"a certain compact disc (CD) contains 783.216 megabytes of digital information 4"

Answer:    Vf = Vi + A(t)

Vf= -2+ (-9.8)(5)

Vf = -51 m/s

Explanation:

The final velocity is equal to the initial velocity plus the acceleration multiplied by the time

(-9.8) is used for the acceleration for this question because that is the speed at which things in free fall accelerate when they are on earth

-2 is used as the initial velocity because the ball was thrown in the negative direction which is down.

The time of 5 was given in the question so you can plug it in for time

Answer:

Explanation:

Given:

V₀ = 2 m/s

g = 9.8 m/s²

t = 5 s

____________

V - ?

Axis OX direct vertically down. Then:

V = Vₓ = V₀ₓ + g·t

V = 2 + 9.8*5 = 51 m

Answer:

gass fire and the same density

Explanation:

Answer:

1. The day-to-day conditions of the atmosphere at a place with respect to elements like humidity, temperature, wind speed, rainfall, etc. is called the weather of that place.

2. Weather can be cloudy, sunny, rainy, stormy or clear. It is a part of the natural phenomenon which maintains the equilibrium in the atmosphere.

3. But conditions can be worse sometimes. When the atmospheric conditions are extreme or intense enough to cause property loss or life loss, such weather is termed as severe weather.

4. These also vary according to the altitudes, latitudes, and region and pressure differences. Tornadoes, cyclones, heavy rainfall, fog, winter storms come under this category. They are disastrous and hazardous. Proper disaster management and strategies are required to handle these conditions.

Answer:

The last one

Explanation:

on the exam

Among the following the derived demands are options 1 and 3 only. Because in each case, the demand for one thing is originated  by the demand for another.

The phrase derived demand in economics refers to the demand for a factor of production or intermediate good that results from the demand for another intermediate or final good. In essence, consumer demand for the firm's product determines how much a firm will need.

Additionally, if activity in one area rises, any sector that contributed to the success of the first sector may also experience growth. Here, the school is hiring more teachers because enrollment is increased. Thus, enrolling more teachers satisfies the demand by greater enrollments.

Similarly by recruiting more construction workers the increased demand for new house by people can be solved. However, the second case for filling the attendance is a necessary and not a derived demand.

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The following would expect to be a strong electrolyte in solution (b) KCI is correct option.

When dissolved in water, a strong electrolyte produces a large concentration of ions in solution by totally dissociating into ions.  The following compounds are typically strong electrolytes in solution according to this definition:

These substances readily dissociate into ions in water and exhibit high electrical conductivity, making them strong electrolytes in solution.

Therefore, the correct option is (b).

The complete question is,

Which of the following would be a strong electrolyte in solution?

a) Al(OH)₃ b) KCI c) Pbl₂

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Answer:

The number of electrons removed is  \(N = 9.513 *10^{11}\)

Explanation:

From hr question we are told that

    The radius is  \(r = 0.193 \ m\)

   The required electrical potential is \(V = 7.10 \ kV = 7.10 *10^{3} V\)

The total charge on the sphere  is mathematically evaluated as

           \(Q = \frac{Vr}{k}\)

where k is the coulombs constant with value \(k =9)*10^{9} \ kg\cdot m^3\cdot s^{-4}\cdot A^2.\)

substituting value

          \(Q = \frac{7.10 *10^3 * 0.193}{9*10^9}\)

          \(Q = 1.522*10^{-7} C\)

The number of electron removed is mathematically evaluated as

        \(N = \frac{Q}{e}\)

Where e is  the charge on one electron with value \(e = 1.6 *10^{-19} \ C\)

  substituting values  

      \(N = \frac{1.522 *10^{-7}}{1.60*10^{-19}}\)

      \(N = 9.513 *10^{11}\)

Answer:

Resistance is inversly proportional to the current.

V=I.R.

P=V.I

Answer:  Energy can be transferred between objects or systems through various mechanisms such as conduction, convection, radiation, and mechanical work.

In conduction, heat energy is transferred between objects or systems that are in contact with each other through direct molecular collisions. For example, if you heat a metal rod at one end, the heat energy is transferred through the rod to the other end.

In convection, heat energy is transferred between objects or systems through the movement of fluids, such as air or water. For example, when you boil water on a stove, the heat is transferred from the stove to the water through conduction. As the water heats up, it rises to the top of the pot and cooler water flows in to take its place. This process of rising and falling creates a convection current that transfers the heat energy throughout the water.

In radiation, energy is transferred through electromagnetic waves, such as light or infrared radiation. For example, the heat energy from the sun is transferred to the Earth through radiation.

Mechanical work can also transfer energy between objects or systems. For example, when you lift an object off the ground, you are doing work against the force of gravity. The energy you use to do this work is transferred to the object in the form of potential energy.

An example of energy transfer is the use of solar panels to generate electricity. When sunlight hits the solar panels, the energy is transferred through radiation, which creates an electrical current that can be used to power appliances and devices. In this case, the energy is transferred from the sun to the solar panels to the electrical devices.

Explanation: would apreciate a thanks and a brainliest :D

The first student's observation tells us that the frequency of the wave is 20/30 Hz or 2/3 Hz. Using the formula v = λf, we can find the velocity of the wave, where v is the speed of the wave, λ is the wavelength and f is the frequency.

To find the velocity we need to find λ. The second student's observation tells us that the wave travels 225 cm in 10.0 s. Therefore, the velocity of the wave is 22.5 cm/s. If we substitute this and the frequency into the formula, we get

22.5 cm/s = λ x 2/3 Hz

Solving for λ, we get λ = 33.75 cm. Therefore, the wavelength of the wave is 33.75 cm. Thus, we get A.

37.2 cm is the wavelength of the waves when a physics lab, a harmonic wave travels down a string.

Given that,

In a physics lab, a harmonic wave travels down a string. In 30.0 seconds, one student counts 20 vibrations. A second student finds that a wave's greatest peak travels 225 cm along a rope in 10.0 seconds.

We have to find what is the wavelength of the waves.

We know that,

The formula to find the wavelength is

λ = \(\frac{v}{f}\)

Here,

λ  is wavelength,

v is speed and

f is frequency.

So,

v is the ratio of maximum distance of wave travels by the time.

v = \(\frac{225}{10.0}\) = 22.5 cm per second.

f = \(\frac{20}{30}\) = 0.6 hz.

Now,

λ = \(\frac{v}{f}\) = \(\frac{22.5}{0.6}\) = 37.2 cm

Therefore, 37.2 cm is the wavelength of the waves.

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I mean if it will be anything the asnwer would be 23^90'200

Potential energy is the energy acquired by an object by virtue of its position.

Potential energy of the ball at the 4th step = 40 J

Let the mass of the ball, m is 1 kg

So, potential energy at 4th step,

mgh = 40

h = 40/1 x 9.8

h = 4.1 m

So, the height of each steps, h' = 4.1/4

h' = 1.025 m

Therefore, potential energy at 1,

PE₁ = 1 x 9.8 x 1.025

PE₁ = 10.045 J

Therefore, potential energy at 2,

PE₂ = 1 x 9.8 x 2 x 1.025

PE₂ = 20.09 J

Therefore, potential energy at 3,

PE₃ = 1 x 9.8 x 3 x 1.025

PE₃ = 30.13 J

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Answer:

No,why you say that

Explanation:

Answer:

The tortoise is 3.95 m from the finish line when the hare resumes the race

Explanation:

Since, both the  tortoise and the rabbit continue with the same uniform speed. Therefore, we will use the equation for constant speed, that is:

s = vt

t = s/v

where,

s = distance covered

v = speed

t = time taken

Now, we consider the motion of tortoise:

t₁ = s₁/v₁

For hare:

t₂ = s₂/v₂

According to the given condition both hare and tortoise cross the finish line at same instant. Therefore, time for both must be equal.

t₁ = t₂

using values:

s₁/v₁ = s₂/v₂

where,

s₁ = distance of tortoise from finish line when hare starts = ?

v₁ = speed of tortoise = 0.1 m/s

s₂ = distance of hare from finish line when he starts = 1.55 km - 1.24 km = 0.31 km = 310 m

v₂ = speed of hare = 7.85 m/s

Therefore,

s₁/(0.1 m/s) = (310 m)/(7.85 m/s)

s₁ = (0.1 m/s)(39.5 s)

s₁ = 3.95 m

The object's final velocity, given the data is 10.5 rad/s

This is defined as the rate of change of velocity which time. It is expressed as

a = (v – u) / t

Where

The following data were obtained from the question

The final velocity can be obtained as follow:

a = (v – u) / t

0.75 = (v – 1.5) / 12

Cross multiply

v – 1.5 = 0.75 × 12

v – 1.5 = 9

Collect like terms

v = 9 + 1.5

v = 10.5 rad/s

Thus, the final velocity of the object is 10.5 rad/s

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The linear speed will be the insect be 0.5759 meter/second carried collision with the near stationary photograph.

Speed is distance travelled by the object per unit time. Due to having no direction and only having magnitude, speed is a scalar quantity With SI unit meter/second.

Given that an insect lands 0.1m from the center of the turn table.

Rotational speed of the turn table = 55 rev/min

= (55×2π/60) rad/second

= 5.759 rad/second.

Hence, the speed of the insect be = Rotational speed × length

= 5.759 rad/second × 0.1 M.

= 0.5759 meter/second.

Therefore, the speed of the insect be 0.5759 meter/second.

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Answer: λ (wavelength) = 3.3 m →  ΔS = 3.3 m

v (speed) = 5.6 m/s → ΔV = 5.6 m/s

T (period) → ΔT = ?

f (frequency) = ?

If:

Now: (if, ΔT = T), Using the formula of the period of a wave, find the frequency:

Explanation: Your Welcome u.u

The frequency of this wave is approximately 1.697 Hz.

To find the frequency of a wave, we can use the formula:

frequency (f) = speed (v) / wavelength (λ)

Given:

Wavelength (λ) = 3.3 m

Speed (v) = 5.6 m/s

Substituting these values into the formula, we can calculate the frequency:

f = v / λ

f = 5.6 m/s / 3.3 m

f ≈ 1.697 Hz

Therefore, the frequency of this wave is approximately 1.697 Hz.

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The electric field between the two charged plates is 5.0 x 10^25 N/C.

The force on the electron is given by the equation:

F = q * E

where F is the force, q is the charge of the electron, and E is the electric field.

Rearranging this equation to solve for E, we get:

E = F / q

Plugging in the values given in the problem, we get:

E = (8.0 x 10^6 N) / (1.6 x 10^-19 C)

Simplifying this expression, we get:

E = 5.0 x 10^25 N/C

Therefore, the electric field between the two charged plates is 5.0 x 10^25 N/C.

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The tension in the strings are 31.47 and 19.25 N respectively.

Mass of the block, m = 3 kg

From the figure, consider the vertical components,

T₁ sin45° + T₂ sin30° = mg

(T₁/√2) + (T₂/2) = 3 x 9.8 = 29.4

Also, consider the horizontal components,

T₁ cos45° = T₂ cos30°

T₁/√2 = T₂ x√3/2

T₁ = T₂ x √3/2 x √2

So,

T₁ = 0.612T₂

Applying in the first equation,

(T₁/√2) + (T₂/2) = 29.4

(0.612T₂/1.414) + 0.5T₂ = 29.4

0.434 T₂ + 0.5 T₂ = 29.4

0.934 T₂ = 29.4

Therefore, the tension,

T₂ = 29.4/0.934

T₂ = 31.47 N

So, the tension,

T₁ = 0.612 T₂

T₁ = 0.612 x 31.47

T₁ = 19.25 N

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Answer:

MASS=4.8KG

VELOCITY= 18.9

Put into the formula.

Explanation:

Impulse= Mass* change in velocity, it gives you everything you need to input it into the formula

The velocity, if the satellite moves to an orbital radius of 4r is V/√4

We know that,

V = √ ( G M / r )

where,

V = Orbital velocity

G = Gravitational constant

M = Mass of the satellite

r = Radius of the orbit

Given that,

r' = 4r

V' = √ ( G M / r' )

V' = √ ( G M / 4r )

V' = ( 1 / √ 4 ) ( √ ( G M / r ) )

v' = v / √ 4

Orbital Velocity is the velocity at which one object revolves around another object in a orbit in uniform circular motion

Therefore, the velocity of the satellite that moved to an orbital radius of 4r is V/√4

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