multiple choice question Before the days of cable, televisions often had two antennae on them: one straight and one circular. Which antenna picked up the magnetic oscillations

Value analysis is a method used to evaluate the worth and effectiveness of an organization or project.

In the case of DEWA (Dubai Electricity & Water Authority), conducting a value analysis can provide insights into the overall value created by the organization. Here are some key points to consider in a value analysis of DEWA:

1. Service Quality: Evaluate the quality and reliability of the electricity and water services provided by DEWA. Assess factors such as uptime, response time, customer satisfaction, and the overall impact on the daily lives of residents and businesses in Dubai.

2. Cost Efficiency: Analyze the cost-effectiveness of DEWA's operations, including the generation, transmission, and distribution of electricity, as well as water production and distribution. Assess the efficiency of resource utilization, cost management practices, and the impact on consumer tariffs.

3. Sustainability: Evaluate DEWA's commitment to sustainable practices, such as renewable energy integration, water conservation efforts, and environmental stewardship. Assess the organization's contributions to reducing carbon emissions and promoting a greener future.

4. Innovation and Technology: Assess DEWA's adoption of innovative technologies, such as smart grids, advanced metering systems, and digital solutions. Evaluate the impact of these technologies on service delivery, efficiency, and customer experience.

5. Stakeholder Engagement: Analyze DEWA's relationships with stakeholders, including customers, suppliers, government entities, and the community. Assess the effectiveness of communication, collaboration, and the organization's contribution to social and economic development in Dubai.

By conducting a comprehensive value analysis of DEWA, stakeholders can gain a holistic understanding of the organization's performance, impact, and value proposition. This analysis can guide decision-making, identify areas for improvement, and support DEWA's ongoing efforts to provide reliable, sustainable, and affordable electricity and water services to the residents and businesses of Dubai.

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A certain slide projector has a 100 mm-focal length lens. (a) If the slide is 24.0 by 36.0 mm, the dimensions of the image projected by the slide projector are approximately 39.9 mm by 59.8 mm.

The dimensions of the image projected by the slide projector can be calculated using the thin lens equation, which relates the object distance, image distance, and focal length of a lens. In this case, the slide is the object, and the image is the projection on the screen.
The thin lens equation is:
1/f = 1/do + 1/di
where f is the focal length, do is the object distance, and di is the image distance. Since the slide is placed in the projector, the object distance is equal to the focal length of the lens, which is 100 mm.
To find the image distance, we need to assume that the slide is positioned at the focal point of the lens so that the image is formed at infinity. This is called the "slide-to-film" distance and is equal to the sum of the focal length and the distance between the slide and the film plane, which is usually around 150-200 mm.
Using these values, we can solve for the image distance:
1/100 = 1/100 + 1/di
1/di = 1/100 - 1/100
di = -10000 mm
This negative value indicates that the image is formed on the same side of the lens as the object, which is not physically possible. Therefore, we need to adjust the slide-to-film distance until the image is formed on the opposite side of the lens.
Assuming a slide-to-film distance of 150 mm, we can calculate the image distance:
1/100 = 1/100 + 1/di
1/di = 1/100 - 1/250
di = 166.7 mm
This means that the image is formed 166.7 mm behind the lens, which is approximately 6.6 inches.
To find the dimensions of the image, we need to use similar triangles. Since the slide has an aspect ratio of 2:3 (24 mm by 36 mm), the image will have the same aspect ratio.
Let x and y be the dimensions of the image, in millimetres. Then we can set up the following proportion:
x/24 = y/36 = di/f
Substituting in the values we just calculated, we get:
x/24 = y/36 = 166.7/100
x = 39.9 mm
y = 59.8 mm

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Answer:

The coefficient of friction is (F/(19.6·m)

Explanation:

The given parameters are;

The force applied to the immovable body = F

The time duration the force acts = t

The time the body spends in motion = 3·t

The acceleration due to gravity, g = 9.8 m/s²

From Newton's second law of motion, we have;

The impulse of the force = F × t = m × Δv₁

Where;

Δv₁ = v₁ - 0 = v₁

The impulse applied by the force of friction, \(F_f\) is \(F_f\) × (3·t - t) =  \(F_f\) × (2·t)

Given that the motion of the object is stopped by the frictional force, we have;

The impulse due to the frictional force = Momentum change = m × Δv₂ = \(F_f\) × (2·t)

Where;

Δv₂ = v₂ - 0 = v₂

Given that the velocity, v₂, at the start of the deceleration = The velocity at the point the force ceased to  act, v₁, we have;

m × Δv₂ = \(F_f\) × (2·t) = m × Δv₁ = F × t

∴ \(F_f\) × (2·t) = F × t

\(F_f\) = F × t/(2·t) = F/2

The coefficient of dynamic friction, \(\mu _k\) = Frictional force/(The weight of the body) = (F/2)/(9.8 × m)

\(\mu _k\) = (F/(19.6·m)

The coefficient of friction, \(\mu _k\) = (F/(19.6·m)

Answer:

4 amp

Explanation:

From ohm's law,

V=IR

so,

I=V/R

I=120/30

I=4amp ans..

Hi there!

We can use the work-energy theorem to solve.

Recall that:
\(E_i = E_f\)

The initial energy equals the final energy (Conservation of Energy). However, we must take into account energy dissipated due to friction in this instance.

The energy lost due to friction is equivalent to the work done by friction. Recall the following:

The work due to a force is:
\(W = F \cdot d \\\)

Since the displacement is in the same direction as the force, the dot-product becomes Fd.

The work due to friction then becomes:

\(W_f = \mu mgdcos\theta\)
The work due to friction is SUBTRACTED from the initial potential energy.

Initial energy = GPE = mgh

Final energy = KE

Therefore:

\(\boxed{mgh - \mu mgdcos\theta = KE}\)

The measured specific heat will be less than the actual specific heat if a lower value is gotten than the actual mass.

This is defined as the quantity of heat needed to raise a substance's temperature by 1 degree Celsius.

If a substance has a low specific heat capacity , it loses water easily which makes the mass when measured to be smaller than the actual value.

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The two forms of electromagnetic radiation that penetrate the Earth's atmosphere best are visible light and radio waves.

Visible light is a form of electromagnetic radiation that is visible to the human eye. It includes the colors of the rainbow ranging from red to violet. Visible light has relatively high energy and shorter wavelengths compared to other forms of radiation. It can easily pass through the atmosphere without being significantly absorbed or scattered, allowing us to see objects and receive sunlight on Earth. Radio waves are another form of electromagnetic radiation with longer wavelengths and lower energy than visible light. They are commonly used for communication and broadcasting purposes. Radio waves can penetrate the atmosphere with little attenuation or interference. They are not easily absorbed or scattered by atmospheric gases, which allows for long-distance transmission and reception of radio signals. Both visible light and radio waves have characteristics that enable them to traverse the atmosphere relatively unaffected. Their ability to penetrate the atmosphere makes them valuable for various applications, including telecommunications, remote sensing, astronomy, and everyday visual perception.

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Answer:

36km/h C.

Explanation:

10* 3600/1000= 10*18/5= 36km/h

C. 36km/h

The dose in a thin LiF dosimeter struck by a fluence of 3*10^11 e/cm^2 with t0=20 MeV is 0.00796 Gy.
To determine the dose (Gy) in a thin LiF dosimeter struck by a fluence of 3*10^11 e/cm² with an initial energy (T0) of 20 MeV, you would need to know the energy deposition per unit mass (in J/kg or Gray) and the mass of the dosimeter.

Here's a brief explanation of the terms:

- Dose: It is the energy absorbed per unit mass, measured in Gray (Gy). In this context, it refers to the energy absorbed by the dosimeter from the fluence of particles.

- Dosimeter: A device that measures the absorbed dose of ionizing radiation. In your case, it's a thin LiF dosimeter.

- Fluence: The number of particles (such as electrons) incident on a specific area per unit area, measured in particles/cm². In your example, it is 3*10^11 e/cm².

To find the dose (Gy), you would need more information about the energy deposition per unit mass and the mass of the dosimeter.

To calculate the dose in a thin lif dosimeter struck by a fluence of 3*10^11 e/cm^2 with t0=20 mev, we need to use the following formula:

Dose (Gy) = Fluence (electrons/cm^2) * Conversion Factor * Energy Deposition Coefficient

The conversion factor for electrons in the air is 0.876 Gy/electron/cm^2, and the energy deposition coefficient for lithium fluoride (LiF) is 1.21 eV/electron. Therefore:

Dose (Gy) = 3*10^11 e/cm^2 * 0.876 Gy/electron/cm^2 * (20 MeV * 1.6*10^-19 J/electron) / (1.21 eV/electron * 1000 J/Gy)

Simplifying the units, we get:

Dose (Gy) = 3*10^11 * 0.876 * 20 * 1.6*10^-19 / 1.21 / 1000
Dose (Gy) = 0.00796 Gy

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Answer: A

Explanation:

I took the test

The speed of light in glass can be determined using the refractive index. Given a refractive index of 1.50 for glass, the speed of light in glass is approximately 2.00 x 10^8 m/s.

The refractive index (n) of a medium is defined as the ratio of the speed of light in vacuum (c) to the speed of light in the medium (v). Mathematically, we can write this as n = c/v.

Rearranging the equation, we can solve for the speed of light in the medium: v = c/n.

Given a refractive index of 1.50 for glass, we substitute this value into the equation and calculate the speed of light in glass: v = (3.00 x 10^8 m/s) / 1.50 = 2.00 x 10^8 m/s.

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Answer:

200,000 kilometers per second

Explanation:

Light travels at approximately 300,000 kilometers per second in a vacuum, which has a refractive index of 1.0, but it slows down to 225,000 kilometers per second in water (refractive index of 1.3; see Figure 2) and 200,000 kilometers per second in glass (refractive index of 1.5).

Answer:

Explanation:

hope it helps:)

(a) The statement is false. Taking vectors  counterexamples, let u = (1, 0, 0) and w = (0, 1, 0). Then (u + w) x (u - w) = (1, 1, 0) x (1, -1, 0) = (0, 0, -2), while 2 (w x u) = 2 (0, 0, -1) = (0, 0, -2). Therefore, the two sides of the equation are not equal.

(b) The statement is true. This is known as the triple vector product identity and is a well-known property of vector cross products. It can be proven using the properties of vector triple products and the distributive property of vector cross products.

(c) The statement is true. The span of a set of vectors is the set of all possible linear combinations of those vectors. Since v and w are vectors in Rⁿ, the span of {v, w} will be a subspace of Rⁿ that contains all possible linear combinations of v and w, thus proving the statement to be true.

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C)1.339 To find the speed of the object at time t=1, we need to calculate the magnitude of the velocity vector. By taking the derivative of the position equations with respect to time, we can obtain the velocity vector. Evaluating the velocity magnitude at t=1 gives us the speed, which is approximately 1.339.

To find the speed of the object at time t=1, we need to calculate the magnitude of the velocity vector. The velocity vector is obtained by taking the derivatives of the position equations x(t) and y(t) with respect to time.

Taking the derivative of x(t) = t*cos(t/2) yields dx/dt = cos(t/2) - (t/2)*sin(t/2).

Similarly, taking the derivative of y(t) = sqrt(t^2 + 2t) gives dy/dt = (t+1)/sqrt(t^2 + 2t).

Now, to find the speed at t=1, we substitute t=1 into the derivatives and calculate the magnitude of the resulting velocity vector.

By evaluating the magnitude of the velocity vector at t=1, we find that the speed of the object is approximately 1.339. Therefore, the correct answer is C) 1.339.

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Digital stopwatches and mechanical stopwatches are two types of stopwatches that can be used for timing events. Digital stopwatches use electronic circuits to measure time, while mechanical stopwatches use a mechanical mechanism.

There are a few key differences between these two types of stopwatches.

Firstly, digital stopwatches tend to be more accurate than mechanical stopwatches. Digital stopwatches can measure time with greater precision, often down to hundredths or even thousandths of a second. Mechanical stopwatches, on the other hand, are typically only accurate to within a few tenths of a second.

Secondly, digital stopwatches are generally easier to read. They have a digital display that shows the elapsed time in clear, easy-to-read numbers. Mechanical stopwatches, meanwhile, use rotating dials or hands that can be more difficult to read, especially when the stopwatch is in motion.

Thirdly, digital stopwatches tend to be more reliable than mechanical stopwatches. Mechanical stopwatches rely on a series of delicate springs, gears, and levers to function. These can be prone to wear and tear, and can malfunction if they are not maintained properly. Digital stopwatches, on the other hand, use solid-state electronics that are less susceptible to damage.

In summary, while both digital and mechanical stopwatches can be used for timing events, digital stopwatches tend to be more accurate, easier to read, and more reliable than mechanical stopwatches. However, some people may prefer the aesthetic or tactile experience of using a mechanical stopwatch.

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Answer:

C

Explanation:

Large-scale winds are generated on Earth primarily because of atmospheric pressure differences.

The primary cause of large-scale winds on Earth is the uneven heating of the Earth's surface by solar radiation, which creates variations in atmospheric pressure.

The sun's energy heats the Earth's surface unevenly, with different regions receiving different amounts of heat. As a result, the air above these regions becomes warmer and expands, leading to a decrease in air pressure.

In contrast, areas with cooler temperatures have denser air, resulting in higher atmospheric pressure. The difference in pressure between these regions creates a pressure gradient, which drives the movement of air from high-pressure areas to low-pressure areas. This movement of air is what we perceive as wind.

The Earth's rotation also plays a significant role in shaping wind patterns. The Coriolis effect, caused by the planet's rotation, deflects moving air to the right in the Northern Hemisphere and to the left in the Southern Hemisphere.

This deflection further influences the direction and patterns of large-scale winds, creating phenomena like trade winds, prevailing westerlies, and polar easterlies.

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Answer:

Average speed = 1.3 m/s

Explanation:

Given that a student walks 160 m in 150 s. The student stops for 30 s and then walka 210 m farther in 140 s.

Neglect the time the student stops.

The total distance covered will be

Distance = 160 + 210

Distance = 370 m

The total time of the whole distance journey will be

Time = 150 + 140 = 290 s

The formula for speed is

Speed = distance/time

Speed = 370/290

Speed = 1.276 m/s

Therefore, the average speed is 1.3 m/s approximately

Answer:

All extended structure compounds form cubes. Sodium and chlorine atoms both have cubical shapes. In the extended structure of NaCI, atoms are arranged in a cubical pattern

The weight falls 4.9 metres in total throughout the first 1.0 seconds.

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The force between the two asteroids of mass 200000 Kg and 700000 Kg separated with a distance of 2.16 m is 2 N

From Newton's law of universal gravity, we understood that the force is given as

F = GM₁M₂ / r²

Where

With the above formula, we can obtain the force between the asteroids as follow:

F = GM₁M₂ / r²

F = (6.67×10¯¹¹ × 200000 × 700000) / 2.16²

F = 2 N

Thus, from the above calculation, we can conclude that the force between them is 2 N

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The correct answer to the question is D) None of the given; all colors emerge at the same time when the beam of white light is incident on a thick glass plate with parallel sides at an angle of 0° with the normal.

When white light enters a thick glass plate, it undergoes refraction, which means the light waves change direction and speed as they move through the glass. This causes the different colors of the spectrum to separate, with red being the least refracted and violet being the most refracted.

The angle at which the light enters the glass plate determines how much it is refracted, with greater angles causing more refraction. As a result, the color that emerges first from the other side of the glass plate will depend on the angle of incidence.

At an angle of 0°, the light will not be refracted at all and all colors will emerge at the same time. As the angle increases, the colors will start to separate and the order in which they emerge will be: red, orange, yellow, green, blue, indigo, and violet.

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The answer is B) violet. When white light enters a thick glass plate at an angle, it undergoes refraction and separates into its constituent colors. This is because different colors have different  violets and Wavelength therefore bend at different angles. The color with the shortest wavelength, which is violet, bends the most and emerges first from the other side of the glass plate.
B) violet

When a beam of white light is incident on a thick glass plate at an angle between 0° and 90° with the normal, the light is refracted, and colors separate due to dispersion. Violet light has the shortest wavelength and is refracted more than the other colors, causing it to emerge from the other side of the glass first.

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The four interactions of electromagnetism are:

1. Electric Field Interaction: The electric field is created by electric charges and exerts a force on other charged particles.

2. Magnetic Field Interaction: The magnetic field is generated by moving electric charges or currents and exerts a force on other moving charges or magnetic materials.

3. Electromagnetic Induction: Electromagnetic induction occurs when a changing magnetic field induces an electric current in a conductor.

4. Electromagnetic Waves: Electromagnetic waves are a form of energy propagation that results from oscillating electric and magnetic fields.

The theory of electromagnetism describes the fundamental interactions of electromagnetism, which are based on the principles of electricity and magnetism. These interactions are explained by Maxwell's equations and the electromagnetic field theory. The four interactions of electromagnetism are:

1. Electric Field Interaction: The electric field is created by electric charges and exerts a force on other charged particles. According to Coulomb's law, like charges repel each other, while opposite charges attract. Electric field interactions play a crucial role in understanding the behavior of charged particles and electrically charged objects.

2. Magnetic Field Interaction: The magnetic field is generated by moving electric charges or currents and exerts a force on other moving charges or magnetic materials. According to the laws of magnetism, like poles repel each other, while opposite poles attract. Magnetic field interactions are responsible for various phenomena, including the behavior of magnets, electromagnetic induction, and the operation of electric motors and generators.

3. Electromagnetic Induction: Electromagnetic induction occurs when a changing magnetic field induces an electric current in a conductor. This phenomenon is described by Faraday's law of electromagnetic induction and is the basis for generating electricity in power plants and the operation of transformers.

4. Electromagnetic Waves: Electromagnetic waves are a form of energy propagation that results from oscillating electric and magnetic fields. These waves include radio waves, microwaves, infrared radiation, visible light, ultraviolet radiation, X-rays, and gamma rays. Electromagnetic waves can travel through a vacuum and have various applications, including communication, imaging, and energy transmission.

These four interactions of electromagnetism are interconnected and form the foundation of numerous technological advancements and our understanding of the natural world. They have been extensively studied and tested, leading to the development of theories and applications in various fields such as electronics, telecommunications, energy, and medical imaging.

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The maximum height travelled by the ball before returning to the ground is 8.62 m.

The maximum height travelled by the ball before returning to the ground is calculated by applying the following kinematic equation as shown below.

H = (u²sin²θ) / 2g

where;

H = (26² (sin 30)²) / (2 x 9.8)

H = 8.62 m

Thus, the maximum height travelled by a projectile depends on the initial velocity and angle of projection.

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a)

When a standing wave propagates through a string, the length of the string is a multiple of half the wavelength:

The factor n corresponds to the number of the harmonic. Then, the first harmonic is given by the condition n=1:

As we can see, the wavelength of the first harmonic is two times the length of the string.

Then, the wavelength of the first harmonic can be found by replacing the length L=63cm:

b)

The product of the wavelength and the frequency is the speed of the wave:

Replace λ=126cm=1.26m and f=330Hz to find the speed of the wave on the E-string:

c)

The frequency of the n-th harmonic is given by:

On the other hand:

Then:

Notice that v/2L is the frequency of the first harmonic (fundamental frequency). Then:

Replace the fundamental frequency of 330Hz and n=2,3,4 to find the second, third and fourth harmonic frequencies:

d)

Replace n=3 into the expression for the wavelength of the n-th harmonic to find the wavelength of the third harmonic:

Therefore, the answers are:

a) 126cm

b) 416m/s

c) 660Hz, 990Hz, 1320Hz

d) 42cm

Answer:

About 2.5 hours

(a) It can be stated that the 10-gram marble hits the ground first because it has a higher acceleration and travels faster.

(b) Both marbles will travel the same distance since their horizontal components of velocity and initial velocity with respect to the ground are the same.

According to the given statement, a 10-gram marble has a speed that is 5 times faster than that of a 100-gram marble. Both marbles roll off the table at the same time. The questions to answer are as follows:

(a) The acceleration due to gravity is constant at 9.8 m/s², according to Newton's Law of Gravitation.

According to the law of physics, heavier objects fall faster than lighter ones, but since the 10-gram marble has a speed that is five times faster than the 100-gram marble, it implies that the 10-gram marble covers more ground in less time than the 100-gram marble as acceleration is directly proportional to the force applied.

The time taken by both marbles to reach the ground is given byt = √(2h/g)where h is the height from which the marbles were dropped, and g is the acceleration due to gravity.

The height from which the marbles were dropped is the same in both cases, so it can be stated that the 10-gram marble hits the ground first because it has a higher acceleration and travels faster.

(b) The range traveled by both marbles is determined by the horizontal component of their velocity. It's worth noting that the horizontal components of their velocities are identical since they were launched from the same height, so there's no advantage for either marble.

The range of a projectile is determined by the formula:

R = u²sin(2θ)/g where R is the range, u is the velocity of the object, θ is the angle of the initial velocity with the horizontal, and g is the acceleration due to gravity.

Since the angle of the initial velocity with the horizontal is the same for both marbles, and their initial velocity is also the same, it can be stated that both marbles travel the same distance.

Therefore, both marbles will travel the same distance since their horizontal components of velocity and initial velocity with respect to the ground are the same.

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