Object A is moving around another object B by the gravitational attraction. What is the attraction of object A, if the distance between the two objects is 5.24 x 10^3 m, and the mass of objects B is 4.21 x 10^21 kg? Estimate G as 6.67 x 10^-11 N (m/kg) ^2

Sphere B  reaches the bottom of the ramp first, as it has more kinetic energy.

sphere A= 7kg

sphere B=9 kg

friction force=0

height= h

kinetic energy=mv²/2

the more mass, more kinetic energy, more velocity to reach the ground.

A specific type of power that can be found in moving particles or things is called kinetic energy. When work, which entails the transfer of energy, is done on an object by applying a net force, that object accumulates kinetic energy. The mass and speed of an item or particle determine the kinetic energy, a property of motion. Any combination of vibration, axis rotation, translation, and movement is referred to as motion (along a path from one location to another). The translational kinetic energy of a body is equal to 1/2mv2, which is calculated by multiplying its mass, m, by the square of its speed, v.

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It is not possible for a particle with rest mass to travel at the speed of light in the laboratory frame. According to the theory of relativity, the speed of light is the maximum speed that any particle with mass can reach, and particles without mass (such as photons) always travel at the speed of light. Therefore, the question is not well-defined and cannot be answered.

According to the laws of physics, a particle with a non-zero rest mass cannot reach the speed of light. As a particle approaches the speed of light, its relativistic mass increases, and it would require infinite energy to accelerate it to the speed of light. Therefore, if a particle is observed to be traveling at the speed of light in the laboratory frame, it must be a massless particle like a photon. In this case, the rest mass (m) of the particle would be 0 MeV/c².

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A. The average drift speed of the electrons in the wire is  1.19 x \(10^{-3}\)cm/s.

B. The time it would take an electron to travel 8.84 m is 7.43 x \(10^{5}\)sec

(A) To find the average drift speed of electrons in a wire, we can use the equation:

I = nAvq

Where:
I is the current in Amperes
n is the electron density in electrons per \(cm^{3}\)
A is the cross-sectional area of the wire in \(cm^{2}\)
v is the average drift velocity of electrons in cm/s
q is the charge of an electron, which is 1.6 x \(10^{-19}\) Coulombs

First, we need to find the cross-sectional area of the wire. The formula for the area of a circle is:

A = π\(r^{2}\)

Where:
A is the area of the circle
r is the radius of the circle

Given that the wire diameter is 1.63 mm, we can find the radius by dividing it by 2:

r = 1.63 mm / 2 = 0.815 mm = 0.0815 cm

Now, we can calculate the area:

A = \(π(0.0815 cm)^{2}\) = 0.0209 \(cm^{2}\)

Next, we can rearrange the equation to solve for v:

v = I / (nAq)

Given that the current is 20 A and the electron density is 8.47 x \(10^{24}\)electrons per \(cm^{3}\), we can substitute these values into the equation:

v = 20 A / (8.47 x \(10^{24}\) electrons per cm^3 * 0.0209 cm^2 * 1.6 x \(10^{-19}\) C)

Simplifying the expression:

v = 1.19 x \(10^{-3}\) cm/s

Therefore, the average drift speed of electrons in the 14 gauge wire carrying a maximum current of 20 A is approximately 1.19 x \(10^{-3}\) cm/s.

(B) To calculate the time it would take for an electron to travel a distance of 8.84 m, we can use the formula:

t = d / v

Where:
t is the time in seconds
d is the distance in meters
v is the average drift velocity of electrons in meters per second

Given that the distance is 8.84 m and the average drift velocity is 1.19 x 10^-3 cm/s, we need to convert the velocity to meters per second:

v = 1.19 x \(10^{-3}\) cm/s * 0.01 m/cm = 1.19 x \(10^{-5}\) m/s

Now, we can substitute the values into the formula:

t = 8.84 m / 1.19 x \(10^{-5}\)m/s

Simplifying the expression:

t = 7.43 x \(10^{5}\)s

Therefore, it would take approximately 7.43 x \(10^{5}\) seconds for an electron to travel a distance of 8.84 m.

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Given:

distance of observer from the sound source, \(s=70~m\)

distance between the source of image information sender and the receiver, \(d=45~miles=72420.48~m\)

Assumptions:

speed of sound, \(v=343~m/s\)

speed of the image information being sent, \(c=3\times 10^8~m/s\) (we assume it to be nearly the speed of light in vacuum)

Solution:

Time taken by the sound to reach the observer:

\(time=\frac{distance}{speed}\)

\(time=70\div 343\)

\(time \approx 0.2~s\)

Time taken by the image to reach the destination:

\(time=\frac{72420.48}{3\times 10^8}\)

\(time=2.4\times 10^{-4}~s\)

The current in each resistor is 4 A, 2 A, and 4 A, respectively. The voltage drop across each resistor is 12 V.

When three resistors are connected in series with a six resistor and a 12-volt battery, the total resistance of the series circuit is R = R1 + R2 + R3 + ...

The current flowing through the circuit is the same at every point. So, if we want to know the current flowing through each resistor, we need to use Ohm's law, I = V/R, where V is the voltage of the battery and R is the resistance of each resistor.

I1 = V/R1 = 12/3 = 4 AI2 = V/R2 = 12/6 = 2 AI3 = V/R3 = 12/3 = 4 A. The voltage drop across each resistor can be calculated using Ohm's law, V = IR.

V1 = I1R1 = 4 x 3 = 12 VV2 = I2R2 = 2 x 6 = 12 VV3 = I3R3 = 4 x 3 = 12 V.

Therefore, the current in each resistor is 4 A, 2 A, and 4 A, respectively. The voltage drop across each resistor is 12 V.

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11.3 g/cm³ equals to 1130  kg/m³.

The mass of a substance per unit of volume is its density. Density is most frequently represented by the symbol ρ, however Latin letter D may also be used. Density is calculated mathematically by dividing mass by volume.

Given that 11.3 g/cm³.

Know that

1000 grams = 1 kg

1 grams = 1/1000 kg.

100 cm = 1 m

1 cm = 1/100 m.

Therefore, 1 cm³ = (1/100)³ m³

= 1/1000000 m³

Hence, 1  g/cm³ = (1/1000) ÷ (1/1000000)  kg/m³

= 1000000/1000 kg/m³

= 1000 kg/m³.

Hence, 11.3 g/cm³ = (11.3 × 1000) kg/m³

= 1130  kg/m³

Hence, 11.3 g/cm³ equals to 1130  kg/m³.

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The given statement, If a current is flowing perpendicular to a lead in between the positive and the negative electrodes, the waveform may be flat; also considered isoelectric is false.

Correct option is B. false.

A current flowing perpendicular to a lead between the positive and negative electrodes would not result in a flat waveform or an isoelectric state. The term "isoelectric" typically refers to a state where there is no electrical activity or voltage difference.

In this scenario, if a current is flowing perpendicular to the lead, it would still create a voltage difference across the electrodes, resulting in a measurable waveform. The waveform may vary depending on factors such as the magnitude and direction of the current, but it would not be flat or isoelectric.

When no current flows between the electrodes, the line produced is considered to be isoelectric. In this situation, no current is passing in either direction; hence, no energy is produced in the line.

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Answer:

Distance, d = 0.1 m

It is given that,

Initial velocity of meson,

Finally, the meson is coming to rest v = 0

Acceleration of the meson,  (opposite to initial velocity)

Using third equation of motion as :

s is the distance the meson travelled before coming to rest.

So,

s = 0.1 m

The meson will cover the distance of 0.1 m before coming to rest. Hence, this is the required solution.  

Answer:

Options?

Explanation:

Answer:

Unbalanced forces cause in object to move. (apex)

Explanation:

Answer:

E=2.58155844×10^-29

Explanation:

we use this formula

E= hc/ lambda

E= [(6.626×10^-34)( 3×10^8)]/(7.7×10^-3)

E=2.58155844×10^-29

Answer: B

Explanation: positive and negative charges attract each other and get stronger as they get closer

Answer:

The answer is 400

Explanation:

Answer:

Circuit

Explanation:

because a roughly circular line, route, or movement that starts and finishes at the same place.

This question can be solved by using the concepts of electrical energy, electricity, circuit, and electric current.

The flow of electricity from one place to another is called "Electrical Energy".

The electric current or electricity is defined as the rate of flow of electric charges from one point to another point, along a path known as a circuit. Electrical energy is caused by the movement of electric charges or the electric current from one point to another point of the circuit.

Therefore, this flow of electricity or electric current from one place to another place is termed Electrical Energy.

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The attached picture shows examples of electrical energy.

Answer:

\(d_{2}\) = 169 cm

Explanation:

Mass 1 = 45 kg   => Force = 450 N

Mass 2 = 29 kg   => Force = 290 N

According to principle of moments:

=> \(F_{1}d_{1} = F_{2}d_{2}\)

Where \(F_{1}\) = 450 N, \(d_{1}\) = 109 cm and \(F_{2}\) = 290 N

=> (450)(109) = 290\(d_{2}\)

=> 49050 =  290\(d_{2}\)

Dividing both sides by 290

=> \(d_{2}\) = 169 cm

The net torque about the axle on the pulley is 20 Ncm.

The net torque about the axle on the pulley can be calculated by first determining the direction of rotation. Since there are two forces acting in opposite directions, the pulley will not rotate in either direction unless there is a net torque acting on it. Therefore, we need to find the difference between the clockwise torque and the counterclockwise torque.

To calculate the torque, we need to use the formula: torque = force x distance. The distance is the radius of the pulley, which is half of the diameter, or 2 cm.

On the left side, the force of 20 N is pulling down and to the left, creating a clockwise torque. The distance from the axle to the force is 2 cm, so the torque is 20 N x 2 cm = 40 Ncm.

On the right side, the force of 30 N is pulling down and to the right, creating a counterclockwise torque. The distance from the axle to the force is also 2 cm, so the torque is 30 N x 2 cm = 60 Ncm.

Therefore, the net torque is the difference between these two torques: 60 Ncm - 40 Ncm = 20 Ncm.

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Answer:

add the Resistance

2(100)= 200

2) 200 ohms

If two 100 ohms resistors are placed in series, their total resistance will be 200 ohms

When two or more resistors are connected end to end consecutively , they are said to be connected in series combination .Total resistance in  series combination is calculated as the algebraic sum of individual resistances

General formula = R (equivalent ) = R1 + R2 + R3 + .......

let R1 = 100 ohms

R2 = 100 ohms

R(equivalent resistance in series combination )= R1 + R2

R = 100 + 100

R = 200 ohms

If two 100 ohms resistors are placed in series, their total resistance will be b) 200 ohms

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Answer:

cows a consumer

Explanation:

because it can make food by its own

         The technology that sends information as light pulses via a glass or plastic fiber is known as fiber optics, or optical fiber. These glass fibers can range in quantity from a few to several hundred in a fiber optic cable. The glass fiber core is encircled by yet another glass layer known as cladding.

         In fiber optics, data is sent as pulses of light, or photons, that travel over a fiber optic cable. Incoming light is bent at a specific angle due to the differing refractive indices of the glass fiber core and cladding.

       Total internal reflection is the method by which light signals traveling through fiber optic cable bounce off the core and cladding in a series of zigzag motions. Due to the thick glass layers, the light signals move around 30% slower than the speed of light instead of at the speed of light.

     Fiber optic transmission sometimes needs repeaters at a distance to renew, or amplify, the signal throughout its path. By converting the optical signal to an electrical signal, processing that electrical signal, and then retransmitting the optical signal, these repeaters regenerate the optical signal.

      Up to 10 Gbps transmissions can currently be supported by fiber optic connections. A fiber optic cable often gets more expensive as its bandwidth capacity increases.

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When a material is reflective, it would cause the light that meets it to bounce off while a transparent material would make the light to pass through it.

Light is a form of energy that produces a sensation that is visible to the optical eye. We know that a material is said to be transparent if the material can allow light to pass through it. A material is said to be reflective when it bounces off the rays of light that fall on it.

We can see that when light interacts with the transparent material, the light can pass through the material. If the light interacts with the reflective material then the light rays are seen to bounce off the light rays.

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A dirty headlight lens headlight lens can cut the amount of light it emits by 90%.

A dirty headlight lens has the ability to reduce the amount of light emitted by the lens by 90%. A plastic lens is commonly used to cover the headlight bulbs. The primary function of a plastic lens is to keep these bulbs from becoming blurry or clouded.

It was demonstrated that dirt is accumulated even when the road appears to be in good condition, and that even a little amount of dirt produces increased glare from low beam and decreased vision from high beam. Visibility is always lost when light levels are reduced by more than 20%.

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Answer:

Doldrums

Explanation:

Trust me and need more to write to post answer

Answer:

A

Explanation:

Put A, It will help you.

True. The proximal tubule and loop of Henle are both involved in the reabsorption of sodium and water, and this process is regulated by hormones such as aldosterone and antidiuretic hormone (ADH).

The proximal tubule and loop of Henle are subject to hormonal regulation of sodium and water. Hormones such as aldosterone, antidiuretic hormone (ADH), and atrial natriuretic peptide (ANP) play a significant role in regulating sodium and water reabsorption in these nephron segments to maintain proper fluid balance in the body.

It can be a little easier to understand this reaction when you think of sodium compared to a noble gas; it is similar to neon, which has ten protons and ten electrons. Noble gases are known for their stability due to their full atomic orbitals, and not needing to gain or lose electrons.

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By using the information in the table (see attachment), the metal with a volume of 1.375 cm³ is zinc.

Density simply refers to a ratio of mass to the volume of a physical object such as a metal, gray cube, or tennis ball. Mathematically, the density of a physical object can be calculated by using this formula:

Density = M/V

Where:

Making volume the subject of formula, we have:

Volume = Mass/Density

For the metal aluminum, we have:

Volume = 4.60/2.70

Volume = 1.70 cm³.

For metal zinc, we have:

Volume = 9.81/7.13

Volume = 1.375 cm³.

For metal chromium, we have:

Volume = 6.24/6.18

Volume = 0.87 cm³.

For metal nickel, we have:

Volume = 3.17/8.90

Volume = 0.36 cm³.

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Answer:

6 units

Explanation:

Gravitational force between two objects is given by the equation

\(F = G \dfrac{m_1m_2}{r^2}\)

where

\(G =\)universal gravitational constant
\(m_1\), \(;m_2\) are the masses of the objects

\(r\) = distance between the objects

We are given that F = 18 units.

If m₁ is tripled and r is also tripled then

new F = F':

\(F' = G \dfrac{3m_1 \cdot m_2}{(3r)^2}\\\\\\F' = G \dfrac{3m_1 \cdot m_2}{9r^{2}}\\\\\\So \dfrac{F'}{F} = G \dfrac{3m_1 \cdot m_2}{9r^{2}} \div G \dfrac{m_1 \cdot m_2}{r^{2}}\)

\(= \dfrac{3}{9} = \dfrac{1}{3}\\\)

Therefore the new F is 1/3 of the old f

In this case that would be 18/3 = 6 units

The acceleration of the cabinet and the normal reactions on the pair of rollers are both 0.  

Rollers at a and b that have negligible mass, we can use the equations of motion for the cabinet and the rollers. The equations of motion are:

For the rollers:

m*a = \(F_n - F\)

The net force on the cabinet is equal to the force applied to it by the person pushing it, minus the force of friction between the cabinet and the inclined plane. The force of friction is equal to the coefficient of friction between the cabinet and the inclined plane multiplied by the normal force exerted on the cabinet by the inclined plane

The normal force exerted on the cabinet by the inclined plane is equal to the weight of the cabinet multiplied by the coefficient of friction between the cabinet and the inclined plane.

The coefficient of friction between the cabinet and the inclined plane is usually small, so we can neglect it in the equations of motion.

We can also neglect the mass of each roller, so we can assume that the normal reactions on the rollers are negligible.

Equations of motion, we get:

m*a = F

m*a = 0

Solving these equations simultaneously, we can determine the acceleration of the cabinet and the normal reactions on the pair of rollers.

The acceleration of the cabinet is given by:

a = F / m

The normal reaction on each roller is given by:

a = F / m

here m is the mass of each roller.

Therefore, the acceleration of the cabinet and the normal reactions on the pair of rollers are both 0.  

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The mass of air is 58.110kg for a tank containing 2 m³ of air at -93°C and a gauge pressure of 1.4 MPa.

The ideal gas law equation is given below:

PV = nRT

where P is the absolute pressure, V is the volume, n is the number of moles, R is the ideal gas constant, and T is the absolute temperature.

Given: the volume of the tank, V = 2 m³

temperature of the air in the tank, T = -93°C

T = 273 - 93 K

T = 180K

Gauge pressure, P1 =  1.4 MPa.

Atmospheric pressure, P2 =  1 atm

1 atm =  101.325 kPa

P2 = 0.101 MPa

total pressure P = P1 + P2

P =  1.4 +  0.101

P = 1.501 MPa

Using the ideal gas equation,

PV = nRT

n = PV/RT

n =  1.501 MPa × 2 / 8.314 × 180

n = 2005.9 mol

mass of air = n × molar mass of air

mass of air = 2005.9 ×  28.97 g/mol

mass of air = 58.110 kg

Therefore, the mass of air is 58.110kg.

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Answer:

Velocity= 12t + 12t^2

Acceleration= 12 + 24t^2

When the velocity is 10m/s, the acceleration is 20.

The magnitude of the motional emf in the rod is 0.1872 when an isolated conducting rod of length 8.00 cm is oriented parallel to the x-axis. The speed of rod in y-direction is 3.90m/s.

Given an isolated conducting rod of length (l) = 8.00 cm = 8x10-2m

it moves in the y-direction at (v) = 3.90 m/s

uniform magnetic field of magnitude (B)= 0.600T

Let the magnitude of the motional emf in the rod be E

We know that E = BxlxV

E = 0.600T x 3.90m/s x 8x10-2m = 18.72x10-2

Hence the magnitude of the motional emf in the rod is 0.1872

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