One method to compensate adverse yaw is a:A) balance panel.B) balance tab.C) differential aileron.D) antibalance tab.

Answer:

yrt a

Explanation:

Hope this helps...........

Answer: the absolute static pressure in the gas cylinder is 82.23596 kPa

Explanation:

Given that;

patm = 79 kPa, h = 13 in of H₂O,

A sketch of the problem is uploaded along this answer.

Now

pA = patm + 13 in of H₂O ( h × density × g )

pA= 79 + (13 × 0.0254 × 9.8 × 1000/1000)

pA = 82.23596 kPa

the absolute static pressure in the gas cylinder is 82.23596 kPa

The total wall area that needs to be insulated of the home with 8’ ceilings measuring 42" x 30" and window and door openings approximately 125 ft² can be found out as follows:First, we need to convert 8 feet into inches as follows: 8 feet x 12 inches/foot = 96 inches.

Therefore, the area of one wall can be calculated as follows:Area of one wall = Length x Height= 42 inches x 96 inches= 4,032 square inches= 28 square feetSince there are four walls in a room, the total area of the walls can be calculated by multiplying the area of one wall by.

 Therefore:Total wall area that needs to be insulated = Total area of the walls – Area of the window and door openings= 112 square feet – 125 square feet= -13 square feetSince the total wall area can't be negative, there might be a mistake in the given values. Please check the given values and question and provide them if any of them are wrong.

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Since  Charles performed an investigation in his classroom in which he measured the freezing point of 250 mL of water, the type of investigation that Charles perform is known as option C:  laboratory experiment.

The term Laboratory experiments is known to be a term that connote any for of research method  which is one where researchers are known to make controllable environments so that they can be able to test hypotheses.

Note that Laboratories are known to be used for academic research such as rooms or specifically set up spaces.

Therefore, based on the above, one can say that since  Charles performed an investigation in his classroom in which he measured the freezing point of 250 mL of water, the type of investigation that Charles perform is known as option C:  laboratory experiment.

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Charles knows that adding salt to water causes the freezing point of water to be lowered, but he wants to know if rock salt affects the freezing point more than table salt. Charles performed an investigation in his classroom in which he measured the freezing point of 250 mL of water. He used this measurement as his control. Then, he dissolved equal amounts of rock salt and table salt in two identical 250 mL beakers of water. Finally, he measured the freezing points of each beaker of water, analyzed his results, and formed a conclusion. What type of investigation did Charles perform? A. observational field study B. collection of specimens C. laboratory experiment D. model-building

Answer:

Following are the solution to the given question:

Explanation:

Line voltage:

\(V_L=\sqrt{3}V_{ph}=\sqrt{3}(120) \ v\)

Power supplied to the load:

\(P_{L}=\sqrt{3}V_{L}I_{L} \cos \phi\)

\(10\times 10^3=\sqrt{3}(120 \sqrt{3}) I_{L}\ (0.85)\\\\I_{L}= 32.68\ A\)

Check wye-connection, for the phase current:

\(I_{ph}=I_L= 32.68\ A\)

Therefore,

Phasor currents: \(32.68 \angle 0^{\circ} \ A \ ,\ 32.68 \angle 120^{\circ} \ A\ ,\ and\ 32.68 -\angle 120^{\circ} \ A\)  

Magnitude of the per-phase load impedance:

\(Z_{ph}=\frac{V_{ph}}{I_{ph}}=\frac{120}{32.68}=3.672 \ \Omega\)

Phase angle:

\(\phi = \cos^{-1} \ (0.85) =31.79^{\circ}\)

Please find the phasor diagram in the attached file.

Answer:

Reflection

Explanation:

The specific behavior of light that will be essential to ensure the success of your design is "Reflection". This is because light maze makes use of a mirror and it's the light that is reflected that we see with our eyes. Also, the manner in which light is reflected off objects will affect the colors that are reflected as well.

The minimum pressure at which the water-supplying pump must operate is approximately 2.45 x 10⁶ Pa or 2450 bar.

To calculate the minimum pressure at which the water-supplying pump must operate, we need to use the formula for the volumetric flow rate of a fluid:

Q = A * v

where,

Q =the flow rate

A = the cross-sectional area of the hole

v = the velocity of the fluid.

We can use this formula to determine the velocity of the water, and then use the Bernoulli equation to determine the minimum pressure.

From the question:

ṁ=0.05 kg/s

ρ= 996 kg/m

d= 0.02 cm

Calculating the area of the hole:

A = (π/4) * (d²)

where,

d is the diameter of the hole, and pi is approximately 3.14.

d = 0.02 cm = 0.0002 m

A = (3.14/4) * (0.0002 m)² = 1.57 x 10⁻⁷ m²

Using the mass flow rate to calculate the velocity of water:

Q = ṁ / ρ

where,

Q = the volumetric flow rate

ṁ = the mass flow rate

ρ = the density of water.

Q = (0.05 kg/s) / (996 kg/m³)

Q = 5 x 10⁻⁵ m³/s

Using the area of the hole to find the velocity of water

v = Q / A

v = (5 x 10⁻⁵ m³/s) / (1.57 x 10⁻⁷m²)

v = 318.8 m/s

Using the Bernoulli equation to find the pressure:

P = Patm + (1/2) * ρ * v²

where,

P = the pressure

Patm = the atmospheric pressure

ρ =the density of water

v = the velocity of the water.

P = Patm + (1/2) * (996 kg/m³) * (318.8 m/s)²

Hence, the minimum pressure at which the water-supplying pump must operate is approximately 2.45 x 10⁶ Pa or 2450 bar.

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When the membrane is depolarized, voltage-gated potassium channels do not open instantly; instead, they require roughly 1 msec to open.

The opening of a group of voltage-gated potassium channels lets potassium stream out of the cell via its electrochemical gradient. These occurrences swiftly reduce the membrane potential, returning it to its typical resting state.

Depolarization triggers the activation of voltage-gated potassium channels, and the outward flow of potassium ions through them repolarizes the membrane potential to end action potentials, hyperpolarizes the membrane potential immediately after action potentials, and is essential in establishing the resting membrane potential.

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According to the question of temperature rises to boiling level, the given statement is false.

What is temperature?

Temperature is a measure of how hot or cold something is. It is a physical property of matter and is expressed in degrees on a scale such as Celsius, Fahrenheit, or Kelvin. Temperature is related to the average kinetic energy of molecules in a system, with higher temperatures corresponding to higher average kinetic energy and lower temperatures corresponding to lower average kinetic energy. Temperature can affect the properties of matter and the rate at which chemical reactions occur.

Reheating the food may make the lid easier to remove, but it will not create a vacuum. The vacuum is created when the food cools, and it is not released until the pressure inside the pan drops to atmospheric value.

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The answer of the given question based on the finding the values of y from the circuit output the answer is the given circuit diagram, the output would be: y = 0.

A gate is a basic building block that performs a logical operation on one or more binary inputs and produces a single binary output. Gates are the fundamental components used to design digital circuits, such as microprocessors, memory chips, and other digital devices.

There are several types of gates, each with its own distinct logic function. The common types of gates are given below:

AND gate - produces a binary output of 1 if and only if all of its inputs are 1.

OR gate - produces a binary output of 1 if any of its inputs are 1.

NOT gate - produces a binary output that is the logical negation of its input.

NAND gate - produces the opposite output of an AND gate, i.e., it produces a binary output of 0 if all of its inputs are 1.

NOR gate - produces the opposite output of an OR gate, i.e., it produces a binary output of 0 if any of its inputs are 1.

XOR gate - produces a binary output of 1 if and only if one of its inputs is 1, but not both.

XNOR gate - produces the opposite output of an XOR gate, i.e., it produces a binary output of 1 if both of its inputs are 1, or both of its inputs are 0.

Based on the given circuit diagram, the output would be: y = 0.

Explanation:

Initially, the input A is set to 0, which causes the NOT gate to output 1.

This 1 is then passed through the AND gate, which also receives input B (set to 1), resulting in an output of 1.

The output of the AND gate is then passed through the OR gate, which also receives input C (set to 0), resulting in an output of 1.

Finally, this output of 1 is passed through another NOT gate, which inverts it to give an output of 0 for y.

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Anemometer

Explanation:

An anemometer is a device used for measuring wind speed and direction. It is also a common weather station instrument. The term is derived from the Greek word anemos, which means wind, and is used to describe any wind speed instrument used in meteorology.

Answer:

the elevation of the water surface over the obstruction is highest at 1.341 m

the maximum height of the obstruction h = 0.159 m

Explanation:

From the given information:

The diagrammatic expression for the water profile showing a rectangular channel  with 3 cm width carrying a 4 m3/s of water at a depth of 1.5 m with an obstruction 15 cm high is placed across the channel can be seen in the diagram attached below.

To calculate the elevation of the water surface over the obstruction, we need to  determine the following:

a. the velocity of the channel

b. the froude number at the upstream of the obstruction

c. the specific energy level

To start with the velocity V of the channel.

\(V_1 = \dfrac{Q}{A} \\ \\ V_1 = \dfrac{4 \ m^3/s}{(3 \times 1.5 ) m^2 } \\ \\ V_1 = \dfrac{4 \ m^3/s}{4.5 \ m^2}\)

\(V_1 = 0.88 \ m/sec\)

The froude number  at the upstream of the obstruction

\(F _{\zeta} = \dfrac{V_1}{\sqrt{gy__1}}\)

\(F _{\zeta} = \dfrac{0.88}{\sqrt{9.81 \times 1.5}}\)

\(F _{\zeta} = \dfrac{0.88}{\sqrt{14.715}}\)

\(F _{\zeta} = \dfrac{0.88}{3.836}\)

\(F _{\zeta} =0.229\)

\(F _{\zeta} \simeq0.3\)  which is less than the subcritical flow.

Similarly, the specific energy level for this process can be expressed as:

\(E_1 = \dfrac{V_1^2}{2g}+y_1\)

\(E_1 = \dfrac{0.88^2}{2 \times 9.81 }+1.5\)

\(E_1 = \dfrac{0.7744}{19.62 }+1.5\)

\(E_1 =0.039469+1.5\)

\(E_1 =1.539469\)

\(E_1 \simeq1.54 \ m\)

\(E_2 + \Delta z = E_1\)

\(E_2= E_1 - \Delta z\)

\(E_2= (1.54 - 0.15) \ m\)

\(E_2=1.39 \ m\)

Suppose ;

\(V_1 y_1 = V_2y_2\\ \\ Then; \ making \ V_2 \ the \ subject \ of \ the \formula\ we \ have: \\ \\ \\V_2 = \dfrac{V_1 y_1}{y_2} ---- (1)\)

From the energy equation:

\(E_2 + \Delta z = E_1\)

we can now substitute the above derived parameter and have :

\(E_2 + \Delta z=y_1 + \dfrac{V_1^2}{2g}\)

\(E_2 =y_1 + \dfrac{V_1^2}{2g} - \Delta z\)

\(E_2 =y_2 + \dfrac{V_2^2}{2g}\)

replace the value of \(V_2\) =\(\dfrac{V_1 y_1}{y_2}\)  in equation (1), we have:

\(E_2 =y_2 + \dfrac{( \dfrac{V_1y_1}{y_2})^2}{2g}\)

\(E_2 =y_2 + \dfrac{ {V_1^2y_1^2}}{2gy_2^2}\)

\(E_2 \times y_2^2 =y^3_2 + \dfrac{ {V_1^2y_1^2}}{2g}\)

\(y^3_2 - E_2y^2_2 + \dfrac{V_1^2y_1^2}{2g}=0\)

Replacing our values now; we have:

\(y^3_2 - 1.39 \times y^2_2 + \dfrac{0.88^2 \times 1.5^2}{2 \times 9.81}=0\)

\(y^3_2 - 1.39 \times y^2_2 + \dfrac{1.7424}{19.62}=0\)

\(y^3_2 - 1.39 \times y^2_2 + 0.0888=0\)

\(y^3_2 - 1.39 y^2_2 + 0.0888=0\)

\(y_2 = 1.341 \ m \\ \\ y_2 = - 0.232 \ m \\ \\ y_2 = 0.281 \ m\)

Therefore,the elevation of the water surface over the obstruction is highest at 1.341 m

What is the maximum height of the obstruction that will not cause a rise in the water surface upstream

In order to determine the maximum height , we need to first estimate the rise in water level surface of \(\Delta z\)

\(\Delta z\) = 1.5 - (1.341+ 0.15) m

\(\Delta z\) =  (1.5 - 1.491) m

\(\Delta z\) = 0.009 m

Finally, the maximum height of the obstruction h = (0.009 + 0.15 )m

the maximum height of the obstruction h = 0.159 m

Answer:

Aerobic biological treatment process

Explanation:

Aerobic biological treatment process in which micro-organisms, in the presence of oxygen, metabolize organic waste matter in the water, thereby producing more micro-organisms and inorganic waste matter like CO₂, NH₃ and H₂O.

Answer: Non-programmable

Explanation:

A non-programmable solid-state relay is an electronic device that performs the same function as an electromechanical relay.

An SSR is an electrical switching device that turns on or off when an external voltage (AC or DC) is applied across its control terminals. They perform the same job as an electromechanical relay, but because they include no moving parts, they have a longer operational lifetime.

Solid-state relays are the semiconductor analogs of electromechanical relays and can thus control electrical loads. When energized, the solid-state relay is a fairly complex device with a simple purpose: to activate a single output load.

Therefore, a non-programmable solid-state relay is a type of electrical device that functions similarly to an electromechanical relay.

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This implies that the ratio of the inner and outer radii (r/rj) = 1. Hence, the use of the arithmetic mean area of the cylindrical wall with r = rj will not introduce more than 1% error in heat transfer calculation. However, the use of the arithmetic mean area always overestimates the heat transfer rate.

Given that the arithmetic mean area of the wall can be used to calculate the rate of heat transfer through a cylindrical wall of small thickness. We are required to determine the ratio of the inner and outer radii (r/rj) of the cylindrical wall for which the use of the arithmetic mean area does not introduce more than 1% error in heat transfer calculation.

The expression for the rate of heat transfer through a cylindrical wall of thickness 'dx' is given by dQ/dt = (2πL/kA) (T₁ − T₂), where 'L' is the length of the cylinder, 'k' is the thermal conductivity of the wall material, and 'A' is the area for heat transfer and is given by the arithmetic mean area of the wall as A = π(r² - rj²).

Let us assume that 'a' is the maximum allowable error, so we can express the acceptable limits of the area as (1 − a) A ≤ Am ≤ (1 + a) A, or A − aA ≤ Am ≤ A + aA, and π(r² − rj²) − aπ(r² − rj²) ≤ Am ≤ π(r² − rj²) + aπ(r² − rj²).

Since (r/rj) > 1, assume (r/rj) = α. The permissible range for the arithmetic mean area can be expressed as (1 − a) π(r² − rj²) ≤ Am ≤ (1 + a) π(r² − rj²), or (1 − a) π(r² − α²r²) ≤ Am ≤ (1 + a) π(r² − α²r²), or (1 − a)(1 − α²) ≤ Am/(π(r² − α²r²)) ≤ (1 + a)(1 − α²).

Since the arithmetic mean area does not introduce more than 1% error in heat transfer calculation, a = 0.01. Thus, (1 − 0.01)(1 − α²) ≤ Am/(π(r² − α²r²)) ≤ (1 + 0.01)(1 − α²). Therefore, (1 − α²) = 0.99(1 − α²), or 0.01(1 − α²) = 0.01, or (1 − α²) = 1. Therefore, α = 0.

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To find yss(t), we take the inverse Laplace transform of Y(s):

yss(t) = Inverse Laplace Transform [Y(s)]

To find the steady-state response, we can substitute the given input function into the transfer function and evaluate it at the steady-state condition.

For T(s) = 8/(s^2 + 10s + 100) and f(t) = 6 sin(9t):

To find the steady-state response yss(t), we substitute f(t) into the transfer function T(s):

T(s) = Y(s)/F(s) = 8/(s^2 + 10s + 100)

F(s) = 6/(s^2 + 81)

We can calculate Y(s) by multiplying T(s) and F(s):

Y(s) = T(s) * F(s) = (8/(s^2 + 10s + 100)) * (6/(s^2 + 81))

To find the steady-state response yss(t), we take the inverse Laplace transform of Y(s):

yss(t) = Inverse Laplace Transform [Y(s)]

For T(s) = 10/s^2(s + 1) and f(t) = 9 sin(2t):

Following the same process as above, we substitute f(t) into T(s) and calculate Y(s) as:

Y(s) = T(s) * F(s) = (10/s^2(s + 1)) * (9/(s^2 + 4))

To find yss(t), we take the inverse Laplace transform of Y(s):

yss(t) = Inverse Laplace Transform [Y(s)]

For T(s) = s/(2s + 1)(5s + 1) and f(t) = 9 sin(0.7t):

Substituting f(t) into T(s) and calculating Y(s) yields:

Y(s) = T(s) * F(s) = (s/(2s + 1)(5s + 1)) * (9/(s^2 + 0.7^2))

To find yss(t), we take the inverse Laplace transform of Y(s):

yss(t) = Inverse Laplace Transform [Y(s)]

For T(s) = s^2/(2s + 1)(5s + 1) and f(t) = 9 sin(0.7t):

Following the same steps as above, we have:

Y(s) = T(s) * F(s) = (s^2/(2s + 1)(5s + 1)) * (9/(s^2 + 0.7^2))

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Yes, the given statement is true, i.e., Windows Autopilot requires that a customized Windows image be deployed to devices.

Windows Autopilot is a cloud-based deployment solution that helps to streamline the provisioning and deployment of Windows 10 devices. It allows IT professionals to customize the Windows 10 installation and configuration process to their organization's requirements, regardless of where the device is located or who owns it.

Windows Autopilot can be used to deploy new devices, as well as to re-image existing devices with a customized image.Windows Autopilot works in conjunction with Microsoft Intune and other device management tools to automate the configuration and deployment of devices.

It eliminates the need for IT professionals to manually configure each device, saving time and reducing the risk of errors during the configuration process.

A customized Windows image is an image of the Windows operating system that has been modified to meet the specific needs of an organization. IT professionals can customize the Windows image to include pre-installed applications, device drivers, and settings that are specific to their organization.

This helps to streamline the deployment process and ensures that all devices are configured consistently with the organization's policies and procedures.

Windows Autopilot requires a customized Windows image to be deployed to devices because it is designed to automate the provisioning and configuration process. The customized image contains the settings, applications, and configurations required by the organization, which are applied automatically during the deployment process.

Windows Autopilot requires that a customized Windows image be deployed to devices. This is because the customized image contains the settings, applications, and configurations required by the organization, which are applied automatically during the deployment process.

Windows Autopilot automates the provisioning and configuration process, saving time and reducing the risk of errors during the configuration process.

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The long slot that is present in a 15-ampere, 125-volt, receptacle is known as the grounded conductor.

The long slot is the grounded conductor that is placed in the receptacle to meet with relevant National Electrical Codes (NEC).

The grounded conductor is meant to connect to the ground either directly or indirectly for safety purposes.

In conclusion, option A is correct.

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Answer:

The fundamental difference between effective and less effective matrix organizations is whether the tension between different perspectives is creative or destructive. While various processes, systems and tools can help, what matters most is what top leadership says and does and how that flows through the organization in shared targets, clear accountabilities, live team interactions and team-building transparency and behaviors.

Getting matrix management right is linked inextricably to an organization’s culture - the only sustainable competitive advantage. Key components of a culture can be grouped into behaviors, relationships, attitudes, values and the environment.

Environment and values: Each organization has its own environment, context and bedrock values. Everyone needs to know what matters and why. Don’t try to do anything else until you’ve got that set.

Attitude is about choices: An organization’s overall strategy drives choices about which of its parts will be best in class (superior), world class (parity), strong (above average), or simplified/outsourced to be good enough. These choices help determine the need for a matrix and how best to design it.

Relationships and behaviors: This is why organizations have matrices. The most effective of them best balance focus and collaboration. They allow leaders and teams to build differential strengths and then work together to make the best possible decisions and scale enterprises with a creative tension that they could not do on their own.

My colleague Joe Durrett has worked all sides of matrix organizations in marketing at Procter & Gamble, sales and general management at Kraft General Foods and CEO of Information Resources, Broderbund Software and Advo. He has seen matrices at their best and at their worst and offered his perspective for this article along with his partners John Lawler and Linda Hlavac. The 12 ways to make matrix organizations more effective were built on their ideas.

Explanation:

Answer:

80 Ib ( C )

Explanation:

The maximum force that can be lifted by this screw from the detailed calculation is 145.61 Ibf

Therefore from the options the closest heaviest weight that the screw can carry is 80 Ib

ATTACHED IS THE DETAILED SOLUTION

Answer:

using standardized parts

Explanation:

The code that assigns the value True to a variable called found if the target exists in L and False otherwise is:

found = target in L

From the question, we have the following parameters that can be used in our computation:

Initial variables = L and target

Where

L = List and target = integer

The condition is such that:

There are several ways to do this.

One of them is the following code segment

found = target in L

Another way is

if target in L:

   found  = True

else

   found  = False

Another solution is

found  = False

if target in L:

   found  = True

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Answer: Source: Fossil fuels

Explanation:

The capitalized cost of the permanent roadside historical marker is $116,386.30.

Capitalized cost

The capitalized cost is an assessment of the cost of the investment. Capitalized cost is a useful metric in cost accounting, particularly in the case of business assets. In the case of permanent roadside historical markers, we need to calculate the capitalized cost given the first cost and maintenance cost of $90,000 and $3,100 respectively that is done every 5 years.

Assuming the interest rate of 10% per year. We can use the following formula to calculate the capitalized cost.

C = P * (i / (1 - (1 + i)^(-n)))

Where,

C = Capitalized cost

P = First cost

i = Interest rate per year

n = Total number of years

To calculate the capitalized cost of the permanent roadside historical marker, we need to calculate the present value of the investment. We are given that the first cost of the historical marker is $90,000 and the maintenance cost of $3,100 is incurred once every 5 years at an interest rate of 10% per year.

The total number of years n = 20 years (4 maintenance cycles of 5 years each).

Therefore, using the formula, we have,

C = $90,000 + $3,100 * (PVIFA10%,20)

$3,100 * (PVIFA10%,20) = 8.513 (calculated using Excel or tables)

C = $90,000 + $3,100 * 8.513

C = $90,000 + $26,386.30 = $116,386.30.

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The amount of radiation that the system is radiating into space is 1.164 x 10¹⁷. See the explanation below.

Rockets or space crafts emit heat as they navigate into space. This heat or emissions is what is referred to as radiation.

Recall that we are given the following:

Thus,

Converting the temperature of the Radiator, we have:

30°C = 273 + 30

= 303K

Area of the Panel of the radiator = 0.3 x 0.1

= 0.03

The formula for the heat emitted by the system is given as:

Q = ∈δA (T₁⁴  - T₁⁴)

Where:

δ = Stefan - Bolta Mann constant

→ δ = 5.67 X 10⁻ⁿ

→ The amount of heat is thus given as:

Q = 0.89 x 5.17 x 10⁸ [ (303)⁴ - (3)⁴] x 0.03

Therefore,

Q = 1.1635158780036 × 10¹⁷

Q ≈ 1.164 x 10¹⁷

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Consider a low-speed subsonic wind tunnel with a nozzle contraction ratio of 1:21. One side of a mercury manometer is connected to the settling chamber and the other side is to the test section.

The pressure and temperature in the test section are 1.1 atm and 315 K, respectively. What is the height difference between the two columns of mercury when the test section velocity is 85 m/s?The Bernoulli equation is given byP1 + 1/2ρv12 + ρgh1 = P2 + 1/2ρv22 + ρgh2Where,P = pressureρ = densityv = velocityh = heightThe initial pressure and temperature of the wind tunnel are P1 = 1.1 atm and T1 = 315 K, respectively.

The nozzle contraction ratio is given by the ratio of the area of the throat to the area of the inletA2/A1 = 1/21We know that the velocity of the fluid through the throat is the sonic velocity v2 = 340 m/s

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The three main principles in engineering design are: strategic balance, top management approach and team work.

The principles are fundamental concepts that engineers use to develop effective solutions to complex problems. These principles are based on scientific and mathematical principles as well as practical considerations related to the materials, technologies and resources available to the engineer.

The engineering design process involves several stages, including problem identification, research, concept development, prototyping and testing. Throughout each stage, engineers apply various principles to ensure that their designs meet the needs and requirements of the intended users.

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Answer:

I can help you with your calculation.

To add and subtract angles in degrees, minutes, seconds (DMS) form, you need to follow these steps12:

Align the angles so that the degrees, minutes, and seconds are in the same column.

Add or subtract the seconds first. If the result is more than 60 or less than 0, adjust the minutes accordingly.

Add or subtract the minutes next. If the result is more than 60 or less than 0, adjust the degrees accordingly.

Add or subtract the degrees last.

Using this method, your calculation can be done as follows:

64º26’18’’ + 195º57’12,75’’ – 100º55’35’’ = 64º26’18’’ + 195º57’12.75’’ – 100º55’35’’ = 159º83’30.75’’ – 100º55’35’’ = 159º83’(30.75 - 35)’’ – 100º55’0’’ = 159º82’55.75’’ – 100º55’0’’ = 159º(82 - 55)’55.75’’ – 100º0’0’’ = 159º27’55.75’’ – 100º0’0’’ = (159 - 100)º27’55.75’’ = 59º27’55.75’’

Therefore, the answer is 59º27’55.75’’. I hope this helps!

Explanation: