Answer:
I = 2.18 10⁻⁴ W / m²
Explanation:
The two-slit interference pattern is described by the expression for constructive interference.
d sin θ = m λ
If we also want to know the distribution of intensities we must perform the su of the electric field of the two waves, and find the intensity as the square of the velvet field, obtaining the expression
I = I_max cos² ((π d /λ L) y)
where d is the separation of the slits, λ the wavelength, L the distance to the screen e and the separation of the interference line with respect to the central maximum
let's reduce the magnitudes to the SI system
λ = 583 nm = 583 10⁻⁹ m
L = 75.0 cm = 75.0 10⁻² m
d = 0.640 mm = 0.640 10⁻³ m
y = 0.900 mm = 0.900 10⁻³ m
let's calculate the intensity of this line
I = 5 10⁻⁴ cos² ((π 0.640 10⁻³ /583 10⁻⁹ 0.75 10⁻²) 0.900 10⁻³)
I = 5 10⁻⁴ cos2 (413.84)
I = 5 10⁻⁴ 0.435
I = 2.18 10⁻⁴ W / m²
The moon weighs 7x1022kg and we are about 380,000,000m away from the moon. If you weigh 50kg, how much gravitational force does the moon have on you? (G=6.7x10-¹¹)
The gravitational force that the moon has on a person with a mass of 50 kg is approximately 1.15 N.
The gravitational force between two objects depends on their masses and the distance between them. This force is given by the formula:
F = (G × m₁ × m₂) / r² where F is the gravitational force, m₁ and m₂ are the masses of the two objects, r is the distance between them, and G is the gravitational constant, which has a value of 6.7 × 10⁻¹¹ N m²/kg².
Using this formula, we can find the gravitational force that the moon has on a person with a mass of 50 kg.
The mass of the moon is 7 × 10²² kg, and the distance between the moon and the person is 380,000,000 m.
Therefore, we have:
m₁ = 50 kg
m₂ = 7 × 10²² kg
r = 380,000,000 m
G = 6.7 × 10⁻¹¹ N m²/kg²
Substituting these values into the formula, we get:
F = (G × m₁ × m₂) / r²
F = (6.7 × 10⁻¹¹ × 50 kg × 7 × 10²² kg) / (380,000,000 m)²
F = 1.15 N
Therefore, the gravitational force that the moon has on a person with a mass of 50 kg is approximately 1.15 N.
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__________:Union of egg sperm; restores normal chromosome number
In the diagram, R₁ = 40.0 , R2= 25.4 , and R3 = 70.8 . What is the equivalent resistance of the group?
According to the diagram the equivalent resistance of the group is
40.05 ohms
How to find the equivalent resistanceThe equivalent resistance is calculated by investigating the diagram to note that R2 and R3 are in parallel and both are in series to R1
Resistors in parallel is solved by
Resistors in parallel = 1/25.4 + 1/70.8
Resistors in parallel = 0.0535 ohms
Equivalent resistance
Equivalent resistance = Resistors in parallel + Resistor in series
Equivalent resistance = 0.0535 + 40
Equivalent resistance = 40.0535
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A tennis ball is kicked horizontally off the edge of a 25 m high building and lands a distance of 27 m from the edge of the building. What was the final horizontal velocity of the tennis ball, in m/s? Ignore air resistance.
Given:
Height = 25 m
Distance from the edge to where it lands = 27 m.
Let's find the final horizontal velocity of the tennis ball.
To find the final horizontal velocity of a projectile motion, apply the formula:
\(v_{fx}=v_ix\)The initial horizontal velocity and the final horizontal velocity are the same since there is no force acting on the object.
Now, to find the horizontal velocity, let's first make a free sketch of this situation:
Let's find the time of flight:
\(t=\sqrt{\frac{2h}{g}}\)Where:
h = 25 m
g is acceleration due to gravity = 9.8 m/s²
Thus, we have:
\(\begin{gathered} t=\sqrt{\frac{2*25}{9.8}} \\ \\ t=2.26\text{ s} \end{gathered}\)The time of flight if the projectile is 2.26 seconds.
Now, to find the final horizontal velocity, we have:
\(\begin{gathered} V=\frac{x}{t} \\ \end{gathered}\)Where:
x is the horizontal distance = 27 m
Thus, we have:
\(\begin{gathered} V=\frac{27}{2.26} \\ \\ V=11.96\text{ m/s} \end{gathered}\)Therefore, the final horizontal velocity is 11.96 m/s.
ANSWER:
11.96 m/s
A string that passes over a pulley has a 0.341 kg mass attached to one end and a 0.625 kg mass attached to the other end. The pulley, which is a disk of radius 9.00 cm , has friction in its axle.What is the magnitude of the frictional torque that must be exerted by the axle if the system is to be in static equilibrium? (Answer should be in N m)
Answer:
The frictional torque is \(\tau = 0.2505 \ N \cdot m\)
Explanation:
From the question we are told that
The mass attached to one end the string is \(m_1 = 0.341 \ kg\)
The mass attached to the other end of the string is \(m_2 = 0.625 \ kg\)
The radius of the disk is \(r = 9.00 \ cm = 0.09 \ m\)
At equilibrium the tension on the string due to the first mass is mathematically represented as
\(T_1 = m_1 * g\)
substituting values
\(T_1 = 0.341 * 9.8\)
\(T_1 = 3.342 \ N\)
At equilibrium the tension on the string due to the mass is mathematically represented as
\(T_2 = m_2 * g\)
\(T_2 = 0.625 * 9.8\)
\(T_2 = 6.125 \ N\)
The frictional torque that must be exerted is mathematically represented as
\(\tau = (T_2 * r ) - (T_1 * r )\)
substituting values
\(\tau = ( 6.125 * 0.09 ) - (3.342 * 0.09 )\)
\(\tau = 0.2505 \ N \cdot m\)
Answer:here to earn points
Explanation:
What is the amperage of a current flowing through a wire that has a resistance of 30 ohms if the voltage is 90 volts?
12 ohms
2700 amps
3 amps
4 volts
to make slime stretchy is by putting more glue and aclohal then mix it
The gravitational potential energy of a 4 kg book is 98 J. what is its height
The height of the 4 kilograms book with a gravitational potential energy of 98 Joules is approximately 2.5 meters.
How to determine the height of an object with a gravitational potential energy?Gravitational potential energy is simply the potential energy an object possessse in relation to another object due to gravity.
It is expressed as;
U = m × g × h
Given that:
Gravitational potential energy of the book U = 98 Joules
Mass of the book m = 4 kilograms
Acceleration due to gravity g = 9.8 m/s²
Height h = ?
Plug these values into the above formula and solve for height.
U = m × g × h
h = U / ( m × g )
h = 98 / ( 4 × 9.8 )
h = 98/39.2
h = 2.5 meters
Therefore, its height is 2.5 meters.
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Can a moving object have gravitational energy?
Answer:
It is worth noting that the higher the gravitational energy of an object moving downwards, the lower the kinetic energy, and the lower the kinetic energy of an object moving upwards, the higher its gravitational energy.
Gravitational potential energy is acquired by an object when it has been moved against a gravitational field. For example, an object raised above the surface of the Earth will gain energy, which is released if the object is allowed to fall back to the ground.
Wind is caused by ___. the earth's tilt the Coriolis effect temperature differences humidity
I am guessing wind is caused by climate change in the atmosphere
Explanation:
wind is cause by climate change in the atmosphere that depends weather is is breezy really cold or rain and cold
Answer:
caused by the uneven heating of the Earth by the sun and the own rotation.
What is the power (P) of an electric circuit with a current (I) of 2.5 A and a voltage (V) of 120 V? The formula for power is P = IV
The electric power of an electric circuit with a current of 2.5 A and voltage of 120 V is 300 watts.
What is Electric power?Electric power is the rate at which work has to be done or the energy is transformed into an electrical circuit to work. Power is a measure of how much energy is used in a span of time. The SI unit of power is watt (W). Power can be defined as the product of voltage and electric current.
P = VI
where, P is the power,
V is the voltage or potential difference,
I is the electric current
P = VI
P = 120 × 2.5
P = 300 watts
Therefore, the electric power in the circuit will be 300 watts.
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Please solve the Problem.
(a) The potential at the surface of the sphere is determined as 63 MV.
(b) The distance from the center of the sphere at the given potential is 37.8 m.
Potential at the surface of the sphere
The potential at the surface of the sphere is calculated as follows;
V = kq/r
where;
k is coulomb's constantq is magnitude of the charger is radius of the sphereV = (9 x 10⁹ x 5.25 x 10⁻³)/(0.5 x 1.5)
V = 63 x 10⁶ Volts
V = 63 MV
Distance from the center of the spherer = kq/V
r = (9 x 10⁹ x 5.25 x 10⁻³)/(1.25 x 10⁶)
r = 37.8 m
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2
1 point
Cars are safety tested to see how quickly they come to a stop under many conditions. The distance and time of one of these tests is graphed. What is the average
velocity of this car over the first second?
Automobile Brake Test
120
W
0
60
-50 m/s
-100 m/s
-25 m/s
-75 m/s
14
28
30 4.0 10
Q Search
945
6:58 PM
6/5/2025
The average velocity of the car over the first second is -50 m/s.
The first option is correct.
What is the average velocity of the car over the first second?Average velocity is the ratio of the displacement to the time interval.
The formula to calculate the average velocity is as follows;
Average velocity = Displacement / Timewhere;
Displacement is the change in distance or position in a specified direction.
That is the difference between the final and initial distances.
Considering the graph of the automobile brake test given in the attachment;
displacement over the first second = 50 - 100 m
displacement over the first second = -50 ms
Average velocity = -50 m/ 1 s
Average velocity = -50 m/s
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Which describes the reaction of a substance to form one or more new substances?
a physical change
a chemical change
a change of state
The cores of the terrestrial worlds are made mostly of metal because ______.
A. metals sunk to the centers a long time ago when the interiors were molten throughout
B. the terrestrial worlds as a whole are made mostly of metal
C. the core contained lots of radioactive elements that decayed into metals
D. over billions of years, convection gradually brought dense metals downward to the core
What happens to plankton during the spring bloom?Which organisms are consumers? (Select all that apply.) coyote, snail ,green algae, or bacteria
Answer:
See explanation
Explanation:
Plankton refers to the small and microscopic organisms drifting or floating in the sea or fresh water, consisting chiefly of diatoms, protozoans, small crustaceans, and the eggs and larval stages of larger animals(Oxford dictionary).
The spring bloom is a sudden growth or increase in plankton abundance. It begins around the early spring and continues until late in the spring or sometimes even early in the summer.
One organism that is a consumer of plankton are the snails. One of the commonest snails that eat plankton are the Nerite Snails.
Twelve identical point charges q are equally spaced around the circumference of a circle of radius R. The circle is centered at the origin. One of the twelve charges, which happens to be on the positive x axis, is now moved to the center of the circle.
A) Determine the magnitude of the total electric force exerted on this charge.
Express your answer in terms of Coulomb's constant k and the variables q and R .
F total = ?
B)Determine the direction of the total electric force exerted on this charge.
Express your answer as an integer.
θ = ? degrees
Answer:
For B it is 0
Explanation:
I think
A 1 kg rock is sitting at the edge of a cliff 100 meters high. What is the rock's gravitational potential energy?
Answer:
000.83
Explanation:
i dont know how to explain it bt i did something on paper for it
The half-life of a radioactive isotope is 210 d. How many days would it take for the decay rate of a sample of this isotope to fall to 0.58 of its initial rate?
It would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.
1. The decay rate of a radioactive isotope is proportional to the number of radioactive atoms present in the sample at any given time.
2. The decay rate can be expressed as a function of time using the formula: R(t) = R₀ * \(e^{(-\lambda t\)), where R(t) is the decay rate at time t, R₀ is the initial decay rate, λ is the decay constant, and e is the base of the natural logarithm.
3. The half-life of a radioactive isotope is the time it takes for half of the radioactive atoms in a sample to decay. In this case, the half-life is given as 210 days.
4. Using the half-life, we can find the decay constant (λ) using the formula: λ = ln(2) / T₁/₂, where ln(2) is the natural logarithm of 2 and T₁/₂ is the half-life.
5. Substituting the given half-life into the formula, we have: λ = ln(2) / 210.
6. Now, we need to find the time it takes for the decay rate to fall to 0.58 of its initial rate. Let's call this time "t".
7. Using the formula for the decay rate, we can write: 0.58 * R₀ = R₀ * e^(-λt).
8. Simplifying the equation, we get: 0.58 = \(e^{(-\lambda t\)).
9. Taking the natural logarithm of both sides, we have: ln(0.58) = -λt.
10. Substituting the value of λ from step 5, we get: ln(0.58) = -(ln(2) / 210) * t.
11. Solving for t, we have: t = (ln(0.58) * 210) / ln(2).
12. Evaluating the expression, we find: t ≈ 546.
13. Therefore, it would take approximately 546 days for the decay rate of the sample of this radioactive isotope to fall to 0.58 of its initial rate.
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Which of the following is the best prediction of what would happen if the distance across section 1 in the diagram were to decrease?
1. Frequency would increase
2. Energy would decrease
3. Wavelength would increase
4. Amplitude would decrease
Answer:
Option (1)
Explanation:
Relation between wavelength and frequency of a wave is,
Wavelength (λ) ∝ \(\frac{1}{\text{Frequency}}\)
That means wavelength is inversely proportional to the frequency of a wave.
When the wavelength of the wave is decreased, frequency of the wave will increase.
Therefore, if the distance across section 1 is decreased in the given picture,
wavelength gets decreased.
As a result frequency of the wave will increase.
Option (1) will be the answer.
What does the big bang theory suggest
Answer:
The Big Bang Theory is the leading explanation about how the universe began. At its simplest, it says the universe as we know it started with a small singularity, then inflated over the next 13.8 billion years to the cosmos that we know today.
Explanation: Hope this help! :)
Compute the density in g/cm? of a piece of metal that has a mass of 0.450 kg and a volume of 52 cm3
Answer:
Ro = 8.65 [g/cm³]
Explanation:
We must remember that density is defined as the ratio of mass to volume.
\(Ro=m/V\)
where:
m = mass = 0.450 [kg] = 450 [g]
V = volumen = 52 [cm³]
Ro = density [g/cm³]
Now replacing:
\(Ro = 450/52\\Ro = 8.65 [g/cm^{3} ]\)
A wave with a frequency of 17 Hz has a wavelength of 5 meters. At what speed will this wave travel?
Answer:
85
Explanation:
soln
given that;
frequency=17Hz
wavelength=5m
speed?
formula for wavelength is;
wavelength= speed/frequency
then ; making v the subject formula
we have that v=wavelength*frequency
v=17*5=>85ms
A car accelerates uniformly from rest and
reaches a speed of 28.7 m/s in 6 s. The
diameter of a tire is 58 cm.
Find the number of revolutions the tire
makes during this motion, assuming no slipping.
Answer in units of rev
The number of revolutions the tire makes in 6 s is
N = (58π)/(12π) = 4.83 rev.
What is revolutions?
Revolutions min physics is the study of the physical aspects of revolutions, including the forces and motions that cause them, the structures and systems that are produced in their wake, and the physical processes that lead to their initiation and termination. It has roots in the study of revolutions in the social sciences, but has developed its own principles and techniques to study physical phenomena related to revolutions. These techniques include the use of mathematical models, experiments, numerical simulations, and computer visualizations.
The linear velocity of a point on the tire's circumference is given by
v = (dπ)/t
where d is the diameter of the tire and t is the time.
Substituting d = 58 cm and t = 6 s, the linear velocity of a point on the tire's circumference is
v = (58π)/6 m/s.
The number of revolutions the tire makes in 6 s is given by
N = (v/2π)
Substituting v = (58π)/6 m/s, the number of revolutions the tire makes in 6 s is
N = (58π)/(12π) = 4.83 rev.
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Gravity causes objects to be attracted to one another. This attraction keeps our feet firmly planted on the ground and causes the moon to orbit the earth. The force of gravitational attraction is represented by the equationF=Gm1m2r2where F is the magnitude of the gravitational attraction on either body, m1 and m2 are the masses of the bodies, r is the distance between them, and G is the gravitational constant. In SI units, the units of force are kgâ‹…m/s2, the units of mass are kg, and the units of distance are m. For this equation to have consistent units, the units of G must be which of the following?Gravity causes objects to be attracted to one another. This attraction keeps our feet firmly planted on the ground and causes the moon to orbit the earth. The force of gravitational attraction is represented by the equation,where is the magnitude of the gravitational attraction on either body, and are the masses of the bodies, is the distance between them, and is the gravitational constant. In SI units, the units of force are , the units of mass are , and the units of distance are . For this equation to have consistent units, the units of must be which of the following?A. kg3mâ‹…s2B. kgâ‹…s2m3C. m3kgâ‹…s2D. mkgâ‹…s2
Answer:
The S.I unit of G must be m³/kg.s² to keep the equation consistent.
Explanation:
We have the equation:
F = Gm₁m₂/r²
where,
F = Gravitational Force between Two Bodies
G = Gravitational Constant
m₁ = Mass of 1st Body
m₂ = Mass of 2nd body
r = Distance between the Bodies
The S.I Units of the quantities are:
F = Newton = kg.m/s²
m₁ = kg
m₂ = kg
r = meter = m
G = ?
Therefore, to find the units of Gravitational Constant (G), we substitute the known units in the formula:
kg.m/s² = G(kg)(kg)/m²
G = m³/kg.s²
an object that is 42kg is a free fall, experiencing an acceleration from gravity (g=9.8m/s^2). what is the force of gravity on the object, assuming no air resistance
Answer:
411.6 N
Explanation:
The force is given by ...
F = ma . . . . m represents mass
F = (42 kg)(9.8 m/s^2) = 411.6 N . . . . m represents meters
The force on the object due to gravity is 411.6 newtons.
Which factor indicates the amount of charge on the source charge?
A. the number of field lines on the test charge
B. the number of field lines on the source charge
C. the direction of lines on the source charge
D. the direction of lines on the test charge
Answer:
B. the number of field lines on the source charge
Explanation:
As we know that electric flux is defined as the number of electric field lines passing through a given area.
So here electric flux due to a point charge "q" is given by
so here we know that flux depends on the magnitude of charge and hence we can say that number of filed lines originating from a point charge will depends on the magnitude of the charge.
The factor indicates the amount of charge on the source charge is the number of field lines on the source charge.
What is electric flux?The electric flux is defined as the number of electric field lines passing through a given area.
The electric flux due to a point charge q is given by the number of filed lines through particular closed area.
We know that flux depends on the magnitude of charge and number of field lines starting from a point charge will depends on the magnitude of the charge.
Thus, the correct option is B.
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A/An _____ is described as an automatic switch that acts as a safeguard in an electric current.circuit breakerfuseground fault interruptervoltage divider
ANSWER
circuit breaker
EXPLANATION
A circuit breaker is an automatic switch that is activated to protect an electrical circuit when an sudden increase in the circuit's current appears. This could happen when there's an overload or a short circuit.
Particles q₁ +8.0 μC, q2 +3.5 μC, and
93-2.5 μC are in a line. Particles q₁ and q2 are
separated by 0.10 m and particles q2 and q3 are
separated by 0.15 m. What is the net force on
particle q₂?
Remember: Negative forces (-F) will point Left
Positive forces (+F) will point Right
+8.0μ.C
+91
0.10 m
+3.5 C
+92
0.15 m
-2.5μ C
93
The net force on particle q₂, located between particles q₁ and q₃, is approximately 189000 N. The force exerted by particle q₁ on q₂ is positive and equals 252000 N, while the force exerted by particle q₃ on q₂ is negative and equals -63000 N.
To find the net force on particle q₂, we need to calculate the individual forces exerted on q₂ by particles q₁ and q₃ and then determine their sum.
The force between two charged particles can be calculated using Coulomb's law:
F = k * |q₁ * q₂| / r²
Where F is the force between the particles, k is the electrostatic constant (k ≈ 9.0 x \(10^9\) Nm²/C²), q₁ and q₂ are the charges of the particles, and r is the distance between them.
First, let's calculate the force exerted on q₂ by q₁:
F₁₂ = k * |q₁ * q₂| / r₁₂²
F₁₂ = (9.0 x \(10^9\) Nm²/C²) * |(8.0 μC) * (3.5 μC)| / (0.10 m)²
F₁₂ ≈ 252000 N
The force is positive because q₁ and q₂ have opposite charges.
Next, let's calculate the force exerted on q₂ by q₃:
F₂₃ = k * |q₂ * q₃| / r₂₃²
F₂₃ = (9.0 x \(10^9\)Nm²/C²) * |(3.5 μC) * (-2.5 μC)| / (0.15 m)²
F₂₃ ≈ -63000 N
The force is negative because q₂ and q₃ have the same charge.
Finally, we can find the net force on q₂ by summing the individual forces:
Net force = F₁₂ + F₂₃
Net force = 252000 N + (-63000 N)
Net force ≈ 189000 N
The net force on particle q₂ is approximately 189000 N.
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how was newton's laws used to solve problems on apollo 13 ship
Explain in two full paragraphs
Answer:
actually ships are made in newtons third law of motion.it states to every action there is equal and opposite reaction. curved is made in downwards to maintain upthrust and to made balance.
actually it prevents ships from drowning and to move with a heavy mass.