Please help! Correct answer only!


At a carnival, there is a game where you can draw one of 20 balls from a bucket. The balls are numbered from 1 to 20. If the number on the ball is odd, you win $31. If the number on the ball is even, you win nothing. If you play the game, what is the expected payoff?

$____

Answer:

2x + 60 - 37.50

x = 6

In a transformation called a translation, the pre-image is slid either vertically or horizontally.

A translation is a type of transformation in geometry where the pre-image (original figure) is moved or slid to a new position in a specific direction. The movement can be either vertical or horizontal.

When a pre-image is translated vertically, it means that it is moved up or down without any change in its orientation. The entire figure maintains the same shape and size, but its position on the coordinate plane is shifted vertically.

On the other hand, when a pre-image is translated horizontally, it is moved left or right while preserving its original shape and size. The orientation of the figure remains the same, but its position on the coordinate plane is shifted horizontally.

In both cases, the translation occurs without any rotation, reflection, or resizing of the pre-image. The resulting image is a new figure that is congruent to the original but located at a different position on the plane.

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Step-by-step explanation:

22 mi / gal  *  1/3.7854 L/gal  *  1.6093 km /mi = 9.353 km / L

To graph the line, plot the y-intercept is -3/2, and use the slope is -1/2, to additional points.

To graph the solution to the system of linear inequalities:

2x - (1/4)y < 1

4x + 8y > -24

We can start by graphing the corresponding equations for each inequality:

2x - (1/4)y < 1

To graph this inequality, we can rewrite it as:

y > 8x - 4

To graph the line y = 8x - 4, we can identify the slope, which is 8, and the y-intercept, which is -4.

Plot the y-intercept on the coordinate plane and then use the slope to determine additional points to plot a straight line.

Since the inequality is y > 8x - 4, we will graph a dotted line instead of a solid line to indicate that the points on the line itself are not included in the solution.

4x + 8y > -24

We can simplify this inequality by dividing both sides by 4:

x + 2y > -3

To graph the line x + 2y = -3, we can rewrite it in slope-intercept form:

y = (-1/2)x - (3/2)

Again, since the inequality is x + 2y > -3, we will graph a dotted line to indicate that the points on the line itself are not included in the solution.

After graphing both lines, the shaded region where the two lines overlap represents the solution to the system of linear inequalities.

A scale or additional constraints, the specific coordinates of the shaded region cannot be determined.

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The average velocity would be,

\(V_{avg}= \frac{-10h^2 - 80h + 8t -32}{h}\)

We know that the average velocity is nothing but the total displacement/ total time taken.

As we know the average velocity over the time interval [t1, t2] is given by, 

\(v_{avg}= \frac{s(t_2) - s(t_1)}{ t_2 - t_1}\)

Here, we have been given the disaplcement function s(t) = -10t² + 8t + 4

And time interval is [4, 4 + h]

For t = 4,

s(4) =  -10(4)² + 8(4) + 4

s(4) = -10(16) + 32 + 4

s(4) = -160 + 32 + 4

s(4) = -124

For t = 4 + h

s(4 + h) =  -10(4 + h)² + 8t + 4

s(4 + h) = -10(16 + 8h + h²) + 8t + 4

s(4 + h) = -160 - 80h - 10h² + 8t + 4

s(4 + h) = -10h² - 80h + 8t - 156

Using abova formula the average velocity V_(ave) would be,

\(V_{avg}= \frac{s(4+h) - s(4)}{ 4+h - 4}\\\\V_{avg}=\frac{-10h^2 - 80h + 8t - 156 - (-124)}{h} \\\\V_{avg}=\frac{-10h^2 - 80h + 8t - 156 + 124}{h} \\\\V_{avg}= \frac{-10h^2 - 80h + 8t -32}{h}\)

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The probability of exactly two flaws in a 50-yard piece of material is approximately 0.2706 or 27.06%.

In order to determine the probability of exactly two flaws in a 50-yard piece of material, we will use the Poisson distribution formula.

The Poisson distribution is used to calculate the probability of a given number of events occurring in a fixed interval of time or space when these events happen independently of each other and at an average rate.

To find the probability of exactly two flaws in a 50-yard piece of material, we will use the following formula:

P(X = k) = (e^(-λ) * λ^k) / k!

Where: P(X = k) is the probability of k flaws occurring in a 50-yard piece of material

λ = the average rate of flaws per unit of material (in this case, 50 yards)

k = the number of flaws we want to calculate is the mathematical constant ≈ 2.71828...

k! is the factorial of k, which is the product of all positive integers up to k

Let's plug in the values we have for this problem:

P(X = 2) = (e^(-λ) * λ^2) / 2!

λ = 2 flaws per 50 yards of material produced = 2/50 = 0.04 flaws per yard.

Therefore, the average number of flaws in a 50-yard piece of material is:

λ = 0.04 * 50 = 2e is a mathematical constant that equals ≈ 2.71828...

Then, let's plug in these values into the formula:

P(X = 2) = (e^(-2) * 2^2) / 2!P(X = 2) = (0.1353 * 4) / 2P(X = 2) = 0.2706

The probability of exactly two flaws occurring in a 50-yard piece of material is 0.2706 or approximately 27.06%.

Therefore, the probability of exactly two flaws in a 50-yard piece of material is approximately 0.2706 or 27.06%.

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The sum of angle in a triangle is 180°

A triangle is a polygon with three edges and three vertices. It is one of the basic shapes in geometry. A triangle with vertices A, B, and C is denoted \triangle ABC.

The sum of angle A, B and C is 180 i.e A+B +C = 180°

Also a triangle is a 3 sided polygon. The sum of of angle in a polygon is( n-2)180

How do we prove that the sum of angle in a triangle is 180°?

Since triangle is 3 sided, n= 3, because n denote the number if sides

therefore the sum of angle = (n-2) 180 = (3-2)×180

= 180°

therefore the sum of angle In a triangle is 180°

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\( \: \: \: \: 15.5 \\ - 11.2 \)

ANSWER :-

4.3

On solving the provided question we can say that  from the provided data in the graph we have, A"B"C" is a reflection then translation of ABC.

Mathematicians use graphs to logically convey facts or values using the a visual representations or charts. A graph point will typically reflect a relationship between two or more things. Nodes, or vertices, and edges make form a graph, a non-linear data structure. Glue together the nodes, often referred to as vertices. This graph has vertices V=1, 2, 3, 5, and edges E=1, 2, 1, 3, 2, 4, and (2.5), (3.5). (4.5). Statistical charts (bar charts, pie charts, line charts, etc.) graphical representations of exponential growth. a logarithmic graph in the shape of a triangle

from the provided data in the graph we have,

A"B"C" is a reflection then translation of ABC.

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Therefore, the total distance Gabe will paddle is 2x + 400 meters. The exact value of x depends on the width of the river, which is not provided in the given information.

To find the total distance Gabe will paddle, we need to consider the distance he will travel from Q to P, then from P to R, and finally from R back to Q.

First, let's consider the distance from Q to P. Since Gabe will paddle in a diagonal line across the river, this distance can be calculated using the Pythagorean theorem.

The length of the bridge (PR) is given as 400 meters, which is the hypotenuse of a right triangle. The width of the river can be considered as the perpendicular side, and the distance Gabe will paddle from Q to P is the other side. Let's call this distance x.

Using the Pythagorean theorem, we have:

x^2 + (width of the river)^2 = PR^2

Since the width of the river is not given, we'll represent it as w. Therefore:

x^2 + w^2 = 400^2

Next, let's consider the distance from P to R. Gabe will paddle along a route beside the bridge, which means he will travel the length of the bridge (PR) again. So, the distance from P to R is also 400 meters.

Finally, Gabe will paddle back from R to Q along the shore. Since he will follow the shoreline, the distance he will paddle is equal to the distance from Q to P, which is x.

To find the total distance, we add up the distances:

Total distance = QP + PR + RQ

= x + 400 + x

= 2x + 400

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The results tell us that jersey numbers on a football team vary much more than expected, as evidenced by the large range and standard deviation. The sample variance is also relatively high, indicating that there is a fair amount of variability among the jersey numbers in the sample. These statistics are meaningful and can provide insight into the distribution of jersey numbers on the team.

To find the range, we need to subtract the smallest number from the largest number in the sample. So, the range is:

94 - 15 = 79

To find the sample variance and standard deviation, we first need to find the mean of the sample. We can do this by adding up all the numbers and dividing by the total number of players:

(33 + 74 + 70 + 65 + 56 + 47 + 39 + 72 + 57 + 94 + 15) / 11 = 54.18

Next, we need to find the difference between each number and the mean, square them, and add them up. This gives us the sum of squares:

[(33 - 54.18)^2 + (74 - 54.18)^2 + (70 - 54.18)^2 + (65 - 54.18)^2 + (56 - 54.18)^2 + (47 - 54.18)^2 + (39 - 54.18)^2 + (72 - 54.18)^2 + (57 - 54.18)^2 + (94 - 54.18)^2 + (15 - 54.18)^2] = 15864.4

The sample variance is then calculated by dividing the sum of squares by the total number of players minus one:

15864.4 / 10 = 1586.44

Finally, we can calculate the sample standard deviation by taking the square root of the variance:

√1586.44 ≈ 39.83

The results tell us that jersey numbers on a football team vary much more than expected, as evidenced by the large range and standard deviation. The sample variance is also relatively high, indicating that there is a fair amount of variability among the jersey numbers in the sample. These statistics are meaningful and can provide insight into the distribution of jersey numbers on the team.

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the trigonometric ratios of angle C in right triangle ABC are: sin(C) = 8/17,  cos(C) = 15/17, tan(C) = 8/15, csc(C) = 17/8, sec(C) = 17/15 and cot(C) = 15/8

To determine the trigonometric ratios of angle C in right triangle ABC, we can use the values of the sides AC and BC. Here's how we can find the trigonometric ratios:

Given: AC = 17 units and BC = 8 units

Using the Pythagorean theorem, we can find the length of side AB:

AB² = AC² - BC²

AB² = 17² - 8²

AB² = 289 - 64

AB² = 225

AB = 15 units

Now we have the lengths of all three sides of the triangle:

AC = 17 units

BC = 8 units

AB = 15 units

Using these values, we can find the trigonometric ratios:

1. Sine (sin) of angle C:

sin(C) = BC/AC

sin(C) = 8/17

2. Cosine (cos) of angle C:

cos(C) = AB/AC

cos(C) = 15/17

3. Tangent (tan) of angle C:

tan(C) = BC/AB

tan(C) = 8/15

4. Cosecant (csc) of angle C:

csc(C) = 1/sin(C)

csc(C) = 1/(8/17)

csc(C) = 17/8

5. Secant (sec) of angle C:

sec(C) = 1/cos(C)

sec(C) = 1/(15/17)

sec(C) = 17/15

6. Cotangent (cot) of angle C:

cot(C) = 1/tan(C)

cot(C) = 1/(8/15)

cot(C) = 15/8

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according to question the linearization of f(x) = x^(2/3) at a = 64 is:

l(x) = 16 + (1/6) * (x - 64)

To find the linearization of a function f(x) at a point a, we need to use the formula:

l(x) = f(a) + f'(a) * (x - a)

where f(a) is the value of the function at the point a, f'(a) is the derivative of the function evaluated at a, and (x - a) is the difference between x and a.

First, we need to find the value of f(a):

f(a) = a^(2/3) = 64^(2/3) = 16

Next, we need to find the derivative of f(x):

f'(x) = (2/3) * x^(-1/3)

Now, we evaluate f'(a):

f'(a) = (2/3) * 64^(-1/3) = (2/3) * (1/4) = 1/6

Finally, we can plug in these values into the formula for the linearization:

l(x) = 16 + (1/6) * (x - 64)

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The complete graph with 100 vertices will have \(\( \binom{100}{2} = 4950 \)\)edges. Therefore, the correct option is (a) 4950. A connected graph with 100 vertices must have at least 99 edges.

1. A complete graph with 100 vertices means that there is an edge between every pair of vertices. The number of edges in a complete graph with n vertices is given by the formula \(\( \binom{n}{2} = \frac{n(n-1)}{2} \)\). Substituting n = 100, we get\(\( \frac{100 \cdot 99}{2} = 4950 \)\) edges.

2. In a connected graph with n vertices, the minimum number of edges required to ensure connectivity is n - 1. Therefore, a connected graph with 100 vertices must have at least 99 edges.

3. The given algorithm has a loop that divides the value of k by 2 in each iteration. As long as k is greater than or equal to 1, the loop continues. Since the value of k is halved in each iteration, the loop will run approximately \log ntimes. Therefore, the complexity of the algorithm is \(\( O(\log n) \)\).

4. The Minimum Spanning Tree algorithm is a Greedy method because it makes locally optimal choices at each step to construct the minimum spanning tree.

5. A graph is called connected if there is a path between every pair of vertices. Therefore, if a graph has a path between each two vertices, it is a connected graph.

6. NP-Complete problems are a subset of problems in the NP-class and are also NP-Hard. Therefore, any problem in the NP-Complete class is in both NP-class and NP-Hard class.

7. The algorithm with linear complexity is the Max is in-place Algorithm, which finds the maximum element in an array by comparing each element with the current maximum and updating it if necessary.

8. The worst-case time complexity of Insertion Sort is\(\( O(n^2) \)\) because in the worst case, for each element, it may need to be compared and shifted with every element to its left.

9. Dijkstra's algorithm is an example of the Greedy method for finding the shortest path in a graph.

10. The correct option is not provided for question 10, as none of the given options

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Answer:

Mindy=191

Amy=299

Step-by-step explanation:

first you want to divide $490 in half to see what each person has. Thats 245 and since Amy has $54 more, you minus 54 from 245 to get 191. So while Mindy has 191, Amy has 299

No, You cannot use your 10 meter radio on CB (citizen’s band), so long as you follow the rules on frequency, and power.

A public, two-way personal radio service is the Citizen's Band (CB) Radio Service, usually abbreviated as CB. There are various categories for CB operating. The most popular CB method is voice communication, which rose to popularity in the 1970s. Mobile CB operating is still common, particularly in automobiles and trucks. The majority of CB operating occurs in a constrained range of frequencies around 27 MHz. This band contains 40 channels. There is excessive channel saturation.

A CB (citizen’s band) radio must be FCC type approved. Of course, I have no idea where you are, so maybe, where you are, it is ok. In the US however, CB radios are not to be “easily modified” neither to increase power out nor to allow operation outside the citizen’s band frequencies. Even as an extra class amateur radio licensee, I may not use a modified radio on the CB band. I am allowed, however to modify a CB radio to operate on amateur radio bands.

You cannot use your 10 meter radio on CB (citizen’s band), so long as you follow the rules on frequency, and power.

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Hi! I hope you're enjoying your day!

The common factor of 10x and 5 is

5.

What is a factor?

It's a number that a number is evenly divisible by.

Example: 2 is a factor of 10, because 10 is evenly divisible by 2.

Also, it may be tempting to say, "Well, 2 is the common factor!"

And that's not true in this case, because 5 isn't divisible by 2.

x is also not a common factor; 5 is a constant, it doesn't have any variables next to it.

Hence, the factor is

\(\boxed{\boxed{\bold{5}}}\)

Hope everything is clear.

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Answer:

I think C is the current answer

Step-by-step explanation:

it makes sense to me because the $0.5 is depending on the $250

Answer:

182 baseball cards

Step-by-step explanation:

1 - 1/3 = 2/3

273 * 2/3 = 182

Answer:

75.36

Step-by-step explanation:

The formula for circumference of a circle is C = 2r

Since you are substituting 3.14 for , the equation you get when you input the given value is 2 x 3.14 x 12 = 75.36

Please mark as brainliest ;)

Answer:

38

Step-by-step explanation:

Answer:

number 0

Step-by-step explanation:

The identity property of addition states that when zero is added to any real number, the number does not change. Thus, the number "0" is called the additive identity of a matrix.

Answer:

\(m = 4\)

Step-by-step explanation:

\(6(m-2)=12\)

first, distribute

6 * m = 6m

6 * - 2 = -12

\(6m - 12 = 12\)

add 12 to both sides

\(6m = 24\)

divide both sides by 6

\(m = 4\)

Answer:

HN congruent to NL

Step-by-step explanation:

They have a line crossing both of them, signifiying congruence.

1000 km/h / 720 km/h = 1.39 hrs

800 km / hr * 1.39 hrs = 1112 km

An aircraft is cruising at 720 km/h and covered 1000 km. it would travel a distance of 1111.11 km approximately in the same period of time is the speed increased to 800 km/h.

The relationship between speed, time and distance is such that: distance divided by speed will give you the time.

\(v= \frac{s}{t}\),

where,

v = speed

s = distance

t = time

Given,

speed = 720 km/hr

distance = 1000km

time = \(\frac{distance}{speed} = \frac{1000}{720} hr\)

Given the same time,

if speed = 800 km/hr

distance = speed * time = \(\frac{1000}{720} *800 = 1111.11 \ km\)

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Answer:

Step-by-step explanation:

Start by looking at the face that is closest to the bottom left. It is a hexagon and it makes 1 face.

It is connected to a similar hexagon on the upper right by 6 tiles. So that adds 7 more faces.

The total is 2 hexagons + 6 rectangles = 8 faces.

The extreme values of f(x, y) = xy occur at the points (2, 1) and (-2, -1) on the ellipse \(3x^{2} +2y^{2} =1\).

To find the extreme values of f(x, y) = xy on the ellipse \(3x^{2} +2y^{2} =1\), we can use the method of Lagrange multipliers.

Define the function g(x, y) = \(3x^{2} +2y^{2} -1\). We need to find points (x, y) where the gradient of f is proportional to the gradient of g:

∇f = λ∇g

The gradient of f is ∇f = (y, x), and the gradient of g is ∇g = (6x, 4y). Therefore, we have the following system of equations:

y = 6λx
x = 4λy

Substitute the second equation into the first:

y = 6λ(4λy)
y = \(24λ^{2y}\)

If y ≠ 0, then 1 = \(24λ^{2}\), and λ = ±1/2. Plugging this value into the second equation gives x = ±2. Thus, we have two potential extreme points: (2, 1) and (-2, -1).

Now consider the case when y = 0. The constraint equation becomes \(3x^{2} =1\), and x = ±1/√3. However, these points correspond to f(x, y) = 0, which is not an extreme value.

Therefore, the extreme values of f(x, y) = xy occur at the points (2, 1) and (-2, -1) on the ellipse \(3x^{2} +2y^{2} =1\).

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By unitary method, Marissa can hike 7/3 miles in an hour.

A single unit's value can be determined from the values of multiple units, and multiple units' values can be determined from the values of single units using the unitary method.

Given:

\(1\frac{3}{4}\) = 7/4miles are hiked in 3/4 hours.

To find: the number of miles hiked in one hour

Finding:

By unitary method,

Miles hiked in 3/4 hours = 7/4

Miles hiked in 1 hour = 7/4(4/3) = 7/3

Hence, by unitary method, Marissa can hike 7/3 miles in an hour.

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Answer:

C.,77°{interior alternate angle}

hope it helps.

Answer:

2

Step-by-step explanation:

6 sides by 6 adding 4x4=12