The tension in the 5.0 m supporting cable is determined as 1,633.3 N.
What is the angle between the cable and the beam?The angle between the cable and the beam is calculated by applying trigonometry ratio as follows;
sinθ = opposite side / hypotenuse side
sinθ = 3 m / 5 m
sinθ = 0.6
To calculate the tension in the cable, take a moment about the pivot of the beam as shown below;
let the distance from the pivot to the 5.0 m cable = d
let the tension in the 5.0 m cable = T
sinθ = d/4
d = 4 x sinθ
∑M = 0
T(4 x sinθ) = W x 4
where;
T is the tension is the ropeW is weight of the sign supportedRecall, sinθ = 0.6
T(4 x 0.6) = 980 x 4
2.4T = 3920
T = 3920/2.4
T = 1,633.33 N
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1. A car is traveling at 36 m/s hits a tree and comes to rest in 0.05 seconds.
a. What is the acceleration of the car?
b. Airbags deploy in a car if the acceleration of a car exceeds -600 m/s^2 Will the airbags deploy?
Answer: a. -720m/s^2
b. Yes, airbags will deploy
Explanation:
The formula for acceleration is:
= (Final velocity - Initial velocity)/Time
Final velocity = 0m/s
Initial velocity = 36m/s
Time taken = 0.05s
= (Final velocity - Initial velocity)/Time
= (0 - 36)/0.05
= -36/0.05
= -720m/s^2.
Since it's negative, it shows that there was a deceleration.
2. Yes the airbag will deploy since the acceleration gotten is more than -600 m/s^2.
how do atoms make different things
Answer:
Atoms makes different things because of the difference in the number of protons and neutrons.
Explanation:
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What is the effective resistance of a parallel circuit composed of three 15 Ohm resistors? Select one:a.3/15 Ohmsb.15 Ohms c.3 Ohmsd.5 Ohms
First, let us draw the situation. We have the following:
When resistors are connected in parallel, their resulting resistance can be calculated as:
\(\frac{1}{R_t}=\frac{1}{R_1}+...+\frac{1}{R_n}\)Then, in our case:
\(\frac{1}{R_t}=\frac{1}{15}+\frac{1}{15}+\frac{1}{15}=\frac{3}{15}\)Then, our total resistance is:
\(R_t=\frac{15}{3}=5\Omega\)Our final answer is R=5 Ohms
With what initial speed must a ball be thrown upward to reach a height of 39.0m and how long will the ball stay in the air?
A. The initial speed in which the ball should be thrown is 27.65 m/s
B. The total time spent by the ball in the air is 5.64 s.
A. Determination of the initial velocity
Maximum height (h) = 39 mFinal velocity (v) = 0 m/sAcceleration due to gravity (g) = 9.8 m/s²Initial velocity (u) =?v² = u² – 2gh (since the ball is going against gravity)
0² = u² – (2 × 9.8 × 39)
0 = u² – 764.4
Collect like terms
u² = 0 + 764.4
u² = 764.4
Take the square root of both side
u = √764.4
u = 27.65 m/s
B. Determination of the total time spent by the ball in the air.
We'll begin by calculating the time taken to reach the maximum height.
Maximum height (h) = 39 mInitial velocity (u) = 27.65 m/sFinal velocity (v) = 0 m/sTime to reach maximum height (t) =?s = ½(u + v)t
39 = ½(27.65 + 0)t
39 = ½ × 27.6 × t
39 = 13.825 × t
Divide both side by 13.825
t = 39 / 13.825
t = 2.82 s
Finally, we shall determine the total time.
Time to reach maximum height (t) = 2.82 s. Total time in the air (T) =?T = 2t
T = 2 × 2.82
T = 5.64 s
Therefore, the total time spent by the ball in the air is 5.64 s
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i will give u brainliest!
Answer:
True
Explanation:
idk
One of the pieces of evidence supporting energy quantization was the line spectra of elements. Why does this demonstrate energy quantization?.
The line spectra supports the quantization of energy, because there are sharp emission lines demonstrating discrete energy levels.
What is emission of radiation by elements?When an element emits energy in the form of radiation, it produces a spectrum of colors on a photographic plate.
This spectrum can either be continuous or discrete.
In continuous spectrum the spectrum continues without any discrimination between two regions.
Also, the line spectrum consists of discrete and sharp lines, which shows the emission of radiation in a certain amount in a certain time, with a break between emission.
Thus, the line spectra supports the quantization of energy, because there are sharp emission lines demonstrating discrete energy levels.
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Weighing a Bacterium Scientists are using tiny, nanoscale cantilevers 4 micrometers long and 500 nanometers wide-essentially miniature diving boards-as a sensitive way to measure mass. The cantilevers oscillate up and down with a frequency that depends on the mass placed near the tip, and a laser beam is used to measure the frequency. A single E. coli bacterium was measured to have a mass of 710 femtograms = 7.10×10−16 kg with this device, as the cantilever oscillated with a frequency of 17.1 MHz .Required:Treating the cantilever as an ideal, massless spring, find its effective force constant.
The effective force constant while Treating the cantilever as an ideal, massless spring is 8.19 N
What is the effective force constant?The term "spring constant" refers to the proportional constant k. It gauges the stiffness of the spring. A spring exerts a force F = -kx in the direction of its equilibrium position when it is stretched or compressed to a length that differs by an amount x from its equilibrium length.
This question requires us to find the effective force constant.
The frequency f is given as
\(f=\frac{1}{2\pi } (\sqrt{\frac{k}{m}) }\)
from the equation that we have above, we have
\(k = 4\pi ^2*f^2*m\)
we have the values as
f = 17.1 MHz
m = 7.10×10−16 kg
put these values in the equation
\(k = 4 * 3.14^2 * (17.1*10^6)^2*(7.10*10^-^1^6)\)
k = 8.19N/m
The effective force constant has been calculated as 8.19N/m
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Weighing a Bacterium Scientists are using tiny, nanoscale cantilevers 4 micrometers long and 500 nanometers wide-essentially miniature diving boards-as a sensitive way to measure mass. The cantilevers oscillate up and down with a frequency that depends on the mass placed near the tip, and a laser beam is used to measure the frequency. A single E. coli bacterium was measured to have a mass of 710 femtograms = 7.10×10−16 kg with this device, as the cantilever oscillated with a frequency of 17.1 MHz .
Treating the cantilever as an ideal, massless spring, find its effective force constant.
Which of the following objects is transforming electrical energy into energy of motion? (2 points)
A.
B.
C.
D.
Answer:
B
Explanation:
B because loudspeakers convert electrical energy into motion of the diaphram and thus into sound energy.
A 5.0-kg block is pulled horizontally across a floor by a string attached to it with an acceleration of 2 m/s2. What is the tension in the string if the coefficient of sliding kinetic friction between the block and floor is 0.2
The tension on the string when the coefficient of sliding kinetic friction between the block and floor is 0.2 is calculated as 19.8N
What is the tension on the string?The force acting on the block in the horizontal direction is given by:
F_net = ma
where F_net is the net force acting on the block, m is the mass of the block, and a is its acceleration.
The force of friction opposing the motion of the block is given by:
F(friction) = μKN
where μK is the coefficient of kinetic friction between the block and the floor, and N is the normal force acting on the block due to the floor.
Since the block is pulled horizontally, the normal force acting on the block is equal and opposite to the weight of the block, which is given by:
N = mg
where g is the acceleration due to gravity.
Therefore, the net force acting on the block is:
Fnet = T - F (friction) = ma
where T is the tension in the string.
Substituting the expressions for F (friction), N, and Fnet, we get:
T - μKmg = ma
Solving for T, we get:
T = ma + μKmg
Substituting the given values, we get:
T = (5.0 kg)(2 m/s^2) + (0.2)(5.0 kg)(9.8 m/s^2)
Simplifying, we get:
T ≈ 19.8 N
Therefore, the tension in the string is approximately 19.8 N.
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Unlike hard disks, which use magnetic charges to represent 1s and 0s, _____ use reflected light.
Answer:
Unlike hard disks, which use magnetic charges to represent 1s and 0s, Compact Disks, DVD's or Blue Rays use reflected light.
Explanation:
The way CD's work is that they are hit by a laser beam which is reflected on the surface of the disc. These disks have some valleys and mountains that reflect light differently so the CD player will interpret these differences in reflection as data which will then be turned into music, videos or computer files.
If it is the first day of Winter in the Northern Hemisphere, what day is it in the Southern Hemisphere?
Answer:summer
Explanation:
Answer:
first day of summer
Explanation:
a car is moving 18m/s to the east. if it takes the car 5 seconds to reach a velocity of 19 m/s to the east, what is its acceleration?
Kinematics
First Velocity (Vf) = 18 m/s
Last Velocity (Vl) = 19 m/s
time (t) = 5 seconds
acceleration = ______?
Answer :
Vl = Vf + a × t
19 = 18 + a × 5
19 - 18 = 5a
1 = 5a
1 / 5 = a
0,2 m/s² = a ✅
Answer: 0.2 m/s^2 east
Explanation:
A PE X
Light of wavelength λ = 630 nm and intensity i0 = 250 w/m2 passes through a slit of width w = 3.6 μm before hitting a screen l = 1.7 meters away. Use the small angle approximation to write an equation for the phase difference, β, between rays that pass through the very top and very bottom of the slit when the rays hit a point y - 79 mm above the central maximunm.
This expression will give us the phase difference, β, in radians. λ = 630 nm = 630 x 10^-9 m, w = 3.6 μm = 3.6 x 10^-6 m, y = -79 mm = -79 x 10^-3 m, l = 1.7 m, β = (2π / (630 x 10^-9 m)) * (3.6 x 10^-6 m) * (-79 x 10^-3 m) / (1.7 m)
To calculate the phase difference, β, between rays passing through the top and bottom of the slit, we can use the small angle approximation and consider the geometry of the setup.
Let's assume that the central maximum of the diffraction pattern falls at y = 0 on the screen. We are interested in calculating the phase difference at a point y = -79 mm above the central maximum.
Using the small angle approximation, we can assume that the angle θ formed by the rays passing through the top and bottom of the slit is small. This allows us to use the approximation sin(θ) ≈ θ.
The phase difference between the two rays is given by:
β = (2π / λ) * w * sin(θ)
In our case, sin(θ) ≈ θ, and we can express θ in terms of y, l, and the distance from the central maximum to the point of interest:
θ = y / l
Substituting this into the equation for β, we have:
β = (2π / λ) * w * (y / l)
Now we can plug in the given values:
λ = 630 nm = 630 x 10^-9 m
w = 3.6 μm = 3.6 x 10^-6 m
y = -79 mm = -79 x 10^-3 m
l = 1.7 m
β = (2π / (630 x 10^-9 m)) * (3.6 x 10^-6 m) * (-79 x 10^-3 m) / (1.7 m)
Evaluating this expression will give us the phase difference, β, in radians.
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Store size, cost savings, and repair costs are all important _______ which may impact Walmart’s decision to switch to LED lighting.
Store size, cost savings, and repair costs are all important financial impact. which may impact Walmart decision to switch to LED lighting.
Understanding how different components of a system or situation interact in complex and changing ways is known as financial impact. A change in the organization has an impact on other elements of the system. We can see that upgrading to LED lighting has an effect on other parts of the overall system in the Walmart scenario. Yet, the addition of LED illumination has no impact on the expenditures related to buying shop inventory or printing ads for weekly circulars. One factor that is dependent on other factors is a contingency. Managers can decide how to react to a situation by identifying critical contingencies. Walmart executives may decide that installing LED lighting in stores with less than 80,000 square feet is not cost-effective.
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A truck going has a head-on collision with a small car going which statement best describes the situation? (a) the truck has the greater change of momentum because it has the greater mass. (b) the car has the greater change of momentum because it has the greater speed. (c) neither the car nor the truck changes its momentum in the collision because momentum is conserved. (d) they both have the same change in magnitude of momentum because momentum is conserved. (e) none of the above is necessarily true.
The statement that best describes the situation is (a) the truck has the greater change of momentum because it has the greater mass.
This is because momentum is equal to mass times velocity, so even if the car is traveling at a higher speed, the truck's larger mass gives it a greater momentum. However, it is important to note that momentum is conserved in the collision, so the total momentum of the system remains the same before and after the collision.
The truck has a bigger change of momentum due of its greater mass, which is the statement that best captures the circumstance. This is because, even though the automobile is moving at a faster speed, the momentum of the truck is greater due to its bigger mass because momentum is equal to mass times velocity. It is crucial to keep in mind that momentum is conserved during the collision, meaning that the system's overall momentum is unchanged both before and after the event.
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What is the basis for the sounds referred to as korotkoff sounds?.
Answer:Korotkoff Sounds. -tapping sounds created by turbulent blood flow in arm. -pressure is slowly being released from cuff, so systolic pressure is above that of the cuff, but diastolic is still below, so the artery opens in systole and collapses in diastole.
Explanation:
Help me please with the steps
Answer:
Explanation:
I think it's wrong but I tried my best..
2. If a spring has a spring constant of 400 N/m, how much elastic potential
energy is stored when the spring is stretched by 0.25 m?
Answer:
The kinetic energy of a spring is equal to its elastic potential energy.
The elastic potential energy is 12.5N-m or 12.5 Joules.
Explanation:
\( = \frac{1}{2} k {x}^{2} \\ = \frac{1}{2} (400)( {.25)}^{2} \\ = 12.5\)
An issue the students encountered is that the marble doesn't land on the launch pad all of the time. To remedy this, they consider constructing a funnel to help direct the marble. How do you suggest the students move forward with their design process in order to find a solution?
A Test funnels of the same size and material with varying sized openings.
B Test funnels of the same shape and size with varying materials.
C Test funnels with identical openings and material with varying size.
D Test all of the above funnels and then construct a funnel with the best design elements from each.
I suggest that the students move forward with option A.
Test funnels of the same size and material with varying sized openings. This will allow them to determine the optimal size for the opening that will help direct the marble to the launch pad. Once they have determined the optimal size, they can move forward with constructing the funnel with that size opening.
If a rock falls from a cliff, at what point are its kinetic energy and its potential energy the same? Ignore air resistance.
Answer:
The gravitational potential energy it had from being above the ground is converted to kinetic energy as the rock falls. As kinetic energy increases, the velocity of the rock will also increase.
Explanation:
how many orbitals are in the 5th principal energy level
Answer:
25
Explanation:
(1 + 3 + 5 + 7 + 9) orbitals = 25 orbitals
A cannonball is shot up in the air with a vertical speed of 24 miles what is the cannon balls vertical speed just before it hits the ground?
Answer:
I think it will back towards the earth because earth gravitional field will attract to Wards
Which of these is a covalent compound?
Responses
CO
upper case C O,
LiCl
upper case L lower case i upper case C lower case l,
AlCl3
upper case A lower case l upper case C lower case l subscript 3 end subscript,
MgO
Answer: CO
I hope this helps
Answer:
co
Explanation:
How would the number 13,900 be written using scientific notation?
a. 13.9 x 104
C.
b. 1.39 x 104
1.39 x 10³
d. 1.39 x 105
Which one is it??
Answer:
um d. but I am guessing this ans
Fully explain step-by-step Questions number one a,b,c,d solve for all required
(1) The equation is
\(v_2=v_1+a\Delta t\)For v_1,
\(\begin{gathered} v_2=v_1+a\Delta t \\ Subtract\text{ a}\Delta t\text{ on both sides.} \\ v_2-a\Delta t=v_1+a\Delta t-a\Delta t \\ v_2-a\Delta t=v_1 \end{gathered}\)For a,
\(\begin{gathered} v_2=v_1+a\Delta t \\ \text{Subtract v}_1\text{ on both sides} \\ v_2-v_1=v_1-v_1+a\Delta t \\ v_2-v_1=a\Delta t \\ \text{Divide }\Delta t\text{ on both sides.} \\ \frac{v_2-v_1}{\Delta t}=a\frac{\Delta t}{\Delta t} \\ \frac{v_2-v_1}{\Delta t}=a \end{gathered}\)For time,
\(\begin{gathered} v_2=v_1+a\Delta t \\ \text{Subtract v}_1\text{ on both sides} \\ v_2-v_1=v_1-v_1+a\Delta t \\ v_2-v_1=a\Delta t \\ \text{Divide }a\text{ on both sides.} \\ \frac{v_2-v_1}{a}=\frac{a}{a}\Delta t \\ \frac{v_2-v_1}{a}=\Delta t \end{gathered}\)If Argon's melting point is -309 degrees then what is its freezing point?
The melting point of a substance is the temperature at which the substance changes its phase from solid to liquid.
The freezing point is the temperature at which the substance changes its phase from liquid to solid.
The melting point of a substance is the same as the freezing point. That is when the temperature of the substance in the liquid form is increased continuously, the temperature at which the substance turns into a solid is equal to the temperature at which the substance will turn into liquid from solid if the temperature is decreased continuously, from a higher temperature.
The minute hand on a watch is 1. 00 cm in length. Assume the origin of the xy-plane is at the center of the clock face, the x-axis points in the same direction as the minute hand at 8:15 a. M. , and the y-axis points in the same direction as the minute hand at 8:00 a. M. Part A What is the displacement vector of the tip of the minute hand from 8:00 to 8:20 a. M
The displacement vector of the tip of the minute hand from 8:00 a.m. to 8:20 a.m is 0.866cm and -1.5cm.
So,displacement in between 8:00 am to 8:20 am,
\(\vec{d}\) =(\(\vec{x_2}-\vec{x_1}\))= [(6-866)2 + (-0.5) \(\hat{j}\) ] - (1) \(\hat{j}\)
or, J = [(0·866) \(\hat{i}\) + (+1-5 ) \(\hat{j}\) ] cm
So,(X-component, y component) of displacement,
(0.866)cm , (-1.5)cm
B) From 8:00 am to 9:00am, time spend = 1 hour
After (1) hour, the minute hand returns back to its original position.
So, at that ease, the displacement vector = (final position - initial position)
So, X and Y-components of displacement = (0,0)cm.
Displacement is a term used in physics to describe the change in position of an object relative to a reference point. It is a vector quantity, meaning it has both magnitude (the distance traveled) and direction. Displacement can be represented graphically using a vector arrow, with the length of the arrow indicating the distance traveled and the direction of the arrow indicating the direction of movement.
Displacement is often confused with distance, but the two terms are not the same. Distance refers to the total amount of ground covered by an object, while displacement refers to the object's overall change in position. For example, if a person walks 10 meters forward and then 10 meters back, their distance traveled would be 20 meters, but their displacement would be zero since they ended up in the same position as they started.
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How long will it take a 6000W motor to lift a 5000kg load through a height of 2.5m?
Answer:
20.4375 seconds.
Explanation:
Wattage = Work / time
Work = f * d
F = mass * acceleration
mass = 5000 kg
acceleration = force of gravity
acceleration = 9.81
Force = 5000 * 9.81
Force = 49050 N
Work = F * d
d = 2.5
Work = 49050 * 2.5
Work = 122625 Joules
Wattage = Work / time
time = work / wattage
wattage = 6000 watts
time = 122625 / 6000
time = 20.4375 seconds.
radio telescopes cannot simply scan the skies looking for signals, because
Radio telescopes cannot simply scan the skies looking for signals, because they receive radio waves of low intensity from outer space, and these waves are mixed up with terrestrial interference such as radio or television signals. These radio waves, mostly of frequencies ranging between 10 MHz and 100 GHz, are extremely weak by the time they reach Earth because they have been traveling for millions of years through space.
Radio telescopes must be highly sensitive in order to detect these low-intensity radio waves. Radio telescopes are designed to minimize terrestrial interference by being placed in isolated areas far from civilization. To capture faint signals, radio telescopes must be very large in size. Many radio telescopes are composed of several large antennae connected together to form an interferometer. This type of design offers a much larger detection area compared to a single large antenna.Astronomers use computer algorithms and powerful computer processors to analyze radio signals. The signals received by radio telescopes can be processed to produce an image of the source of the signal, such as a star or galaxy. These radio images can provide valuable information about the properties of the celestial bodies they detect.
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Two long parallel wires are separated by a distance of 2.50cm. The force per unit length that each wire exerts on the other is 4.00×10−5Nm, and the wires repel each other. The current in one wire is 0.600A.
a. What is the current in the second wire ?
b. Are the two currents in the same direction or in opposite direction?
a)The current in the second wire is approximately 6.54 A.
b) Since the wires are repelling each other, it implies that the currents flow in the same direction.
a. To find the current in the second wire, we can use Ampere's Law. The force per unit length between the wires can be expressed as:
F = μ₀\(\times\) I₁\(\times\) I₂ / (2πd)
Where:
F is the force per unit length (4.00×\(10^(^-^5^)\) N/m),
μ₀ is the permeability of free space (4π×\(10^(^-^7^)\) T·m/A),
I₁ is the current in the first wire (0.600 A),
I₂ is the current in the second wire (to be determined),
d is the distance between the wires (0.025 m).
Rearranging the formula, we can solve for I₂:
I₂ = (2πd\(\times\)F) / (μ₀ \(\times\) I₁)
Substituting the given values, we get:
I₂ =\((2 \times\pi \times 0.025 \times 4.00\times10^(^-^5^)) / (4\pi\times10^(^-^7^) \times 0.600)\)
= (0.00157) / (2.40×\(10^(^-^7^)\))
= 6.54 A
b. The two currents are in the same direction. This can be determined by the fact that the wires repel each other. According to the right-hand rule for magnetic fields generated by current-carrying wires, when the currents flow in the same direction, the magnetic fields produced around the wires will have the same orientation, resulting in a repulsive force. If the currents were in opposite directions, the magnetic fields would have opposite orientations and attract each other. Since the wires are repelling each other, it implies that the currents flow in the same direction.
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