We cannot determine which sample has a larger range based on the given information.
To determine which sample has a larger range, we need to calculate the standard deviation for each sample. The standard deviation is the square root of the variance.
For Sample 1, the standard deviation is √7 ≈ 2.65
For Sample 2, the standard deviation is √15 ≈ 3.87
The range is defined as the difference between the maximum and minimum values in a dataset.
However, we do not have access to the individual data points in each sample, only their means and variances. Therefore, we cannot directly calculate the range for each sample.
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2x-5y=20
What is y and what is x
Answer:
x=10 and y=4
Im not sure if this is correct but I looked it up and it said it was right
Answer:
x = 5/2y + 10y = 2/5x - 4(if you're looking for intercepts then: x = 10, y = -4)
Step-by-step explanation:
\(\sf{2x - 5y = 20\)
\(\sf{Finding~x:\)
\(2x - 5y = 20\)
\(+ 5y = + 5y\)
↪ 2x = 5y + 20
\(\frac{2x}{2} = \frac{5y}{2} + \frac{20}{2}\)
x = 5/2y + 10\(\sf{Finding~y:}\)
\(2x - 5y = 20\)
\(-2x~ = ~~~~-2x\)
↪ -5y = -2x + 20
\(\frac{-5y}{-5} = \frac{-2x}{-5} + \frac{20}{-5}\)
y = 2/5x - 4--------------------
Hope this helps!
Define surface area and volume. List an example of a situation where you would find surface area and a situation where you would find volume.
Answer:
Step-by-step explanation:
Surface area is the sum of the areas of the faces of a solid. It is measured in square units. Volume is the amount of space taken up by a solid. It is measured in cubic units. Surface area would be used to find the amount of wrapping paper for a gift, and volume would be used to find how much would fit into a box.
Answer: Surface area is the sum of the areas of the faces of a solid. It is measured in square units. Volume is the amount of space taken up by a solid. It is measured in cubic units. Surface area would be used to find the amount of wrapping paper for a gift, and volume would be used to find how much would fit into a box.
Step-by-step explanation:
Which table has a constant of proportionality between y and x of 0.3?
Table C has a constant proportionality between y and x of 0.3.
A constant is an expression-unchanging value or number. It always has the same value.
In mathematics, proportionality denotes a linear relationship between two quantities or variables. Both quantities increase in size when one double, and both decrease in size when one drops to a tenth of its original value.
The answer is the same as the one in the y column when you multiply the x number in table C by 0.3. The value that remains constant in the ratio is the proportionality constant. It is evident that table C is accurate because when you multiply each value in the x column by 0.3, the result is always the value in the y column.
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Suppose that the function f is given by f(z, 3) = 4 – 8 – +1. Find the critical points of f. For each critical point of f. determine whether it is a local minimum, local maximum, or a saddle point.
The critical point of f at z = 1 is a local minimum.
To find the critical points of the function f(z, 3) = 4z^2 - 8z + 1, we need to find the values of z where the first partial derivatives with respect to z are equal to zero. Let's solve it step by step.
Take the partial derivative of f with respect to z:
∂f/∂z = 8z - 8
Set the derivative equal to zero and solve for z:
8z - 8 = 0
8z = 8
z = 1
The critical point of f occurs when z = 1.
To determine whether the critical point is a local minimum, local maximum, or a saddle point, we can use the second partial derivative test. We need to calculate the second partial derivative ∂²f/∂z² and evaluate it at the critical point (z = 1).
Taking the second partial derivative of f with respect to z:
∂²f/∂z² = 8
Evaluate the second derivative at the critical point:
∂²f/∂z² at z = 1 is 8.
Analyzing the second derivative:
Since the second derivative ∂²f/∂z² = 8 is positive, the critical point (z = 1) corresponds to a local minimum.
Therefore, the critical point of f at z = 1 is a local minimum.
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show that the equation has exactly one real root 2x+cosx=0
The equation 2x + cos(x) = 0 has exactly one real root. This can be shown by considering the behavior of the function f(x) = 2x + cos(x) and using the intermediate value theorem.
To prove that the equation 2x + cos(x) = 0 has exactly one real root, we need to demonstrate the existence and uniqueness of the root.
Existence of a real root: By considering the behavior of the function f(x) = 2x + cos(x), we can observe that f(x) is continuous for all real numbers. As x approaches negative infinity, the value of f(x) becomes more negative, and as x approaches positive infinity, the value of f(x) becomes more positive. Since f(x) is continuous and changes sign as x varies, the intermediate value theorem guarantees the existence of at least one real root.
Uniqueness of the real root: To prove uniqueness, we consider the derivative of f(x), which is f'(x) = 2 - sin(x). Since the derivative f'(x) is always positive, it indicates that the function f(x) is strictly increasing. As a result, f(x) = 0 can have at most one real root since there are no significant changes in f(x) after the initial root.
Therefore, the equation 2x + cos(x) = 0 has exactly one real root.
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Let Z(x),D(x),F(x) and C(x) be the following predicates: Z(x) : " x attended every COMP2711 tutorial classes". D(x) : " x gets F in COMP2711". F(x) : " x cheated in the exams". C(x) : " x has not done any tutorial question". K(x) : " x asked some questions in the telegram group". Express the following statements using quantifiers, logical connectives, and the predicates above, where the domain consists of all students in COMP2711. (a) A student gets F in COMP2711 if and only if he/she hasn't done any tutorial question and cheated in the exams. (b) Some students did some tutorial questions but he/she either absent from some of the tutorial classes or cheated in the exams. (c) If a student attended every tutorial classes but gets F, then he/she must have cheated in the exams. (d) Any student who asked some questions in the telegram group and didn't cheat in the exams won't get F.
(a) Predicate logic representation:
D(x) ⇔ (C(x) ∧ F(x))
(b) Predicate logic representation:
∃x[Z(x) ∧ (D(x) ∨ ¬Z(x) ∨ F(x))]
(c) Predicate logic representation:
∀x[(Z(x) ∧ D(x)) → F(x)]
(d) Predicate logic representation:
∀x[(K(x) ∧ ¬F(x)) → ¬D(x)]
(a) A student gets F in COMP2711 if and only if he/she hasn't done any tutorial question and cheated in the exams."If and only if" in a statement means that the statement goes both ways. We can rephrase this statement as:"If a student gets F in COMP2711, then he/she hasn't done any tutorial question and cheated in the exams." (Statement 1)
If we want to translate this statement into predicate logic, we can use the implication operator: D(x) → (C(x) ∧ F(x))
However, we want to add the converse of this statement: "If a student hasn't done any tutorial question and cheated in the exams, then he/she gets F in COMP2711." (Statement 2)Using the same predicate logic form, we can use the implication operator: (C(x) ∧ F(x)) → D(x)
Therefore, the combined predicate logic statements are:D(x) ⇔ (C(x) ∧ F(x))
(b) Some students did some tutorial questions but he/she either absent from some of the tutorial classes or cheated in the exams.To express this statement, we can use the existential quantifier (∃), disjunction (∨), and conjunction (∧) operators. In other words, some student x exists that satisfies the following conditions: ∃x[Z(x) ∧ (D(x) ∨ ¬Z(x) ∨ F(x))]
(c) If a student attended every tutorial class but gets F, then he/she must have cheated in the exams.To express this statement, we can use the implication (→) operator. That is, for every student x, if they attended every tutorial class and got F, then they must have cheated in the exams: ∀x[(Z(x) ∧ D(x)) → F(x)]
(d) Any student who asked some questions in the telegram group and didn't cheat in the exams won't get F.To express this statement, we can use the negation (¬) operator and the implication (→) operator. That is, for every student x, if they asked some questions in the telegram group and didn't cheat in the exams, then they won't get F: ∀x[(K(x) ∧ ¬F(x)) → ¬D(x)]
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Which expression represents the area of this shape?
Answer:
(2x2)+(2x6)
Step-by-step explanation:
area= length x breathe
= (2x2) + (2x6)
If P=5x^4+4x-3 and Q=5x^4+3x^3-4x+3, what is p - q
Answer:
-3x^3+8x-6
step
p-q=5x^4+4x-3-(5x^4+3x^3-4x+3)=5x^4+4x-3-5x^4-3x^3+4x-3
=5x^4-5x^4-3x^3+4x+4x-3-3
=-3x^3+8x-6
A contractor bought 34 loads of soil each weighing 12 tonnes at $13 per tonne. What was the total cost?
Answer:
$5304
Step-by-step explanation:
One load of soil is 12 tons.
Multiply 34 with 12: 34 x 12 = 408 tonnes in all.
Next, multiply the cost per tonne with the amount of tonnes:
408 x 13 = 5304
$5304 is the total cost.
~
Denise poured milk into a glass shaped like a right circular cylinder with a radius of 2 inches. When she added chocolate syrup to the milk, the height of the liquid in the glass increased by 2 inch. What was the volume of the chocolate syrup that Denise added to the glass of milk?
Answer:
go to quizlet https://quizlet.com/141193969/mirrors-and-lenses-flash-cards/
Step-by-step explanation:
Answer:
V = π r^2 h
Step-by-step explanation:
i dont understand this pls help asap
The area of the shape is
24.4 square units
Perimeter of the shape = 18.09 units
How to find the area of the composite figureThe area is calculated by dividing the figure into simpler shapes.
The simple shapes used here include
2 sectors andsquareArea of shape
= area of square + area of the 2 sectors
= length x width + 2 * x/360 * πr^2
= 4 x 4 + 2 * 30/360 * π * 4^2
= 24.3775 square units
Perimeter of the shape
= 2 * length + 2 * radius + length of arc
= 2 * 4 + 2 * 4 + 30/360 * 2π * 4
= 18.09 units
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I really need help on this
Answer:
OK so I don't know the answer but there is something called calculator soup and it has a million kinds of calculators lemme give u the link
Step-by-step explanation:
calculatorsoup.com
Five and one half minus 7
Answer:
- 1 1/2
Step-by-step explanation:
5 1/2 - 7 = - 1 1/2
Classify ΔABC by its sides. Then determine whether it is a right angle triangle. A(2, 3), B(6, 3), C(2, 7)
Answer:
∴Given Δ ABC is not a right-angle triangle
a= AB = √45 = 3√5
b = BC = 12
c = AC = √45 = 3√5
Step-by-step explanation:
Given vertices are A(3,3) and B(6,9)
AB =
Given vertices are B(6,9) and C( 6,-3)
=
BC = 12
Given vertices are A(3,3) and C( 6,-3)
AC² = AB²+BC²
45 = 45+144
45 ≠ 189
∴Given Δ ABC is not a right angle triangle
Step-by-step explanation:
PLS HELP ASAP!!!
This figure is made up of a rectangle and parallelogram.
What is the area of this figure?
Enter your answer in the box. Do not round any side lengths.
__ units²
The area of figure is,
⇒ 26 units²
What is mean by Rectangle?A rectangle is a two dimension figure with 4 sides, 4 corners and 4 right angles. The opposite sides of the rectangle are equal and parallel to each other.
Here, The given figure is made up of a parallelogram and a rectangle.
Hence, The area of the parallelogram is
⇒ Base × Height
Here, The base of the parallelogram is 6 units (Just count the boxes).
And, The height is also 1 unit.
This implies that the area of the parallelogram is
⇒ Base × Height
⇒ 6 × 1
⇒ 6 units²
And, To find the area of the rectangle, we need to find the width and the length using the distance formula or the Pythagoras Theorem.
Using the Pythagoras Theorem as;
⇒ l² = a² + b²
⇒ l² = 2² + 6²
⇒ l² = 4 + 36
⇒ l² = 40
⇒ l = 2√10
And, We get;
⇒ w² = 1² + 3²
⇒ w² = 1 + 9
⇒ w² = 10
⇒ w = √10
Hence, Area of rectangle is,
⇒ l × w
⇒ 2√10 × √10
⇒ 2 × 10
⇒ 20 unit²
Hence, The area of figure is,
⇒ 20 + 6
⇒ 26 units²
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so how much homework do you guys have on average daily? ive just been wondering if my school has started to give out more homework than usual lately.
Answer:
At my school I don't get too much homework. My county doesn't have classes on Wednesday so usually my teachers give work on Monday that is due on Wednesday and then work on Thursday due in Sunday. Also I only get homework for 3 classes Math, S.S and ELA, not science.
btw - im in 8th grade
Step-by-step explanation:
Use the conditional statement below to answer each question.
“If two angle measures add up to 90 degrees, then the angles are complementary.”
Write the converse, inverse, and contrapositive of the given conditional statement.
Can the conditional be written as a biconditional statement? Why or why not. Support your answer.
Answer:
Step-by-step explanation:
Converse: If two angles are complementary, then the angle measures add up to 90 degrees.
Inverse: If two angle measures don't add up to 90 degrees, then the angles are not complementary.
Contrapositive: If two angles are not complementary, the two angle measures do not add to 90 degrees.
This can be written as a biconditional statement because there is no other case for which two angles will be complementary - this is only possible if their angle measures add to 90 degrees.
I need an answer for "−12x+y=10"
Answer:
If you need slope intercept, y = 12x + 10
i hope this helps
If the forecast for two consecutive periods is 1,500 and 1,400 and the actual demand is 1,200 and 1,500 , then the mean absolute deviation is 1) 500 2) 700 3) 200 4) 100
200 is the mean absolute deviation. Therefore, choice three (200) is the right one.
How to calculate the mean absolute deviation
The absolute difference between the predicted and actual values must be determined, added together, and divided by the total number of periods.
Forecasted values are as follows: 1,500 and 1,400
Values in actuality: 1,200 and 1,500
Absolute differences:
|1,500 - 1,200| = 300
|1,400 - 1,500| = 100
Now, we calculate the MAD:
MAD = (300 + 100) / 2 = 400 / 2 = 200
Therefore, 200 is the mean absolute deviation. Therefore, choice three (200) is the right one.
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Determine the area of the largest rectangle that can be inscribed in a circle of radius 4 cm.
3. (5 points) If R feet is the range of a projectile, then R(θ) = v^2sin(2θ)/θ 0≤θ phi/2, where v ft/s is the initial velocity, g ft/sec² is the acceleration due to gravity and θ is the radian measure of the angle of projectile. Find the value of θ that makes the range a maximum.
The area of the largest rectangle that can be inscribed in a circle of radius 4 cm is 32 square centimeters.
To find the area of the largest rectangle that can be inscribed in a circle, we need to determine the dimensions of the rectangle. In this case, the rectangle's diagonal will be the diameter of the circle, which is 2 times the radius (8 cm).
Let's assume the length of the rectangle is L and the width is W. Since the rectangle is inscribed in the circle, its diagonal (8 cm) will be the hypotenuse of a right triangle formed by the length, width, and diagonal.
Using the Pythagorean theorem, we have:
L^2 + W^2 = 8^2
L^2 + W^2 = 64
To maximize the area of the rectangle, we need to maximize L and W. However, since L and W are related by the equation above, we can solve for one variable in terms of the other and substitute it into the area formula.
Let's solve for L in terms of W:
L^2 = 64 - W^2
L = √(64 - W^2)
The area of the rectangle (A) is given by A = L * W. Substituting the expression for L, we have:
A = √(64 - W^2) * W
To find the maximum area, we can differentiate the area formula with respect to W, set it equal to zero, and solve for W. However, for simplicity, we can recognize that the maximum area occurs when the rectangle is a square (L = W). Therefore, to maximize the area, we need to make the rectangle a square.
Since the diameter of the circle is 8 cm, the side length of the square (L = W) will be 8 cm divided by √2 (the diagonal of a square is √2 times the side length).
So, the side length of the square is 8 cm / √2 = 8√2 / 2 = 4√2 cm.
The area of the square (and the largest rectangle) is then (4√2 cm)^2 = 32 square centimeters.
To find the value of θ that makes the range (R) of a projectile a maximum, we can start by understanding the given equation: R(θ) = v^2sin(2θ)/(gθ), where R represents the range, v is the initial velocity in feet per second, g is the acceleration due to gravity in feet per second squared, and θ is the radian measure of the angle of the projectile.
To find the maximum range, we need to find the value of θ that maximizes R. We can do this by finding the critical points of the function R(θ) and determining whether they correspond to a maximum or minimum.
Differentiating R(θ) with respect to θ, we get:
dR(θ)/dθ = (2v^2cos(2θ)/(gθ)) - (v^2sin(2θ)/(gθ^2))
Setting this derivative equal to zero and solving for θ will give us the critical points. However, the algebraic manipulations required to solve this equation analytically can be quite involved.
Alternatively, we can use numerical methods or optimization techniques to find the value of θ that maximizes R(θ). These methods involve iteratively refining an initial estimate of the maximum until a satisfactory solution is obtained. Numerical optimization algorithms like gradient descent or Newton's method can be applied to solve this problem.
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Maggie and Amelia filled up 40 water balloons shaped like spheres. Each water balloon had a radius of 6.5 cm.
The total volume of the 40 sphere shaped water balloons is 46032.38 cubic cm.
Radius of 1 sphere = 6.5 cm
We know that the volume of the sphere is given by 4/3 π r³
We will take the radius as 6.5 cm and π as 22/7
Now we will find the volume : 4/3 ×22/7×6.5³ = 1150.81 cubic cm.
Volume of 40 such spheres = 40 × 1150.81 = 46032.38 cubic cm.
The radius of all the spheres are 46032.38 cubic cm.
A sphere is a geometrical entity with three dimensions that resembles a two-dimensional circle. A sphere is a group of points in three dimensions that are all situated at the same r-distance from one another.
The supplied point is the sphere's center, while the letter r stands for the sphere's radius which is half the diameter. The earliest known allusions to spheres are found in the works of two ancient Greek mathematicians.
Therefore total volume of the 40 sphere shaped water balloons is 46032.38 cubic cm .
Disclaimer: The complete question is : Maggie and Amelia filled up 40 water balloons shaped like spheres. Each water balloon had a radius of 6.5 cm.Find the total volume of water required.
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The discriminant of these the blue and red function in the graph are different. TRUE
OR FALSE
Answer:
FALSE
Step-by-step explanation:
They are both 0.
Find the surface area of the figure. Hint: the surface area from the missing prism inside the prism must be ADDED!
To find the surface area of the figure, we need to consider the individual surfaces and add them together.
First, let's identify the surfaces of the figure:
The lateral surface area of the larger prism (excluding the base)
The two bases of the larger prism
The lateral surface area of the smaller prism (excluding the base)
The two bases of the smaller prism
The lateral surface area of a prism is given by the formula: perimeter of the base multiplied by the height.
The bases of the prisms are rectangles, so their areas can be calculated by multiplying the length by the width.
To find the missing prism's surface area, we need to consider that it is a smaller prism nested inside the larger prism. The lateral surface area and bases of the missing prism should also be included.
Once we have calculated the individual surface areas, we add them together to find the total surface area of the figure.
Without specific measurements or dimensions of the figure, it is not possible to provide a numerical answer. Please provide the necessary measurements or dimensions to calculate the surface area.
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Can someone help on this?
Answer:
D
Step-by-step explanation:
p(x, y) reflection on y axis = p'(-x, y)
what is the distance between (-1,-2) and (3,-1)
hello
Michael cycled 15 km at an average speed of 18 km/h.
How many minutes did his journey take?
Answer:
50 minutes
Step-by-step explanation:
Amount of time his journey took = 15km ÷ 18km/h
= 0.833h (to 3sf)
= 50 minutes
Assuming that someone is asked to write a code (i.e., program) for nonlinear problem using least square adjustment technique, what would be your advice for this person to terminate the program?
This criterion can be defined based on the desired level of accuracy or when the change in the estimated parameters falls below a certain threshold.
When implementing a program for a nonlinear problem using the least square adjustment technique, it is essential to determine a termination condition. This condition dictates when the program should stop iterating and provide the final estimated parameters. A common approach is to set a convergence criterion, which measures the change in the estimated parameters between iterations.
One possible criterion is to check if the change in the estimated parameters falls below a predetermined threshold. This implies that the adjustment process has reached a point where further iterations yield minimal improvements. The threshold value can be defined based on the desired level of accuracy or the specific requirements of the problem at hand.
Alternatively, convergence can also be determined based on the objective function. If the objective function decreases below a certain tolerance or stabilizes within a defined range, it can indicate that the solution has converged.
Considering the chosen termination condition is crucial to ensure that the program terminates effectively and efficiently, providing reliable results for the nonlinear problem.
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Given the curves y = x² - x and y = -x²+6,
(a) Sketch both curves on the same coordinate plane between x=0 and x = 3. Submit a graph showing the two functions. (b) Express the area of the region enclosed by the curves between x=0 and x = 3 in terms of definite integrals. (c) Evaluate the integral(s) in part (b) to find the area of the region described there.
The top curve is y = -x² + 6, and the bottom curve is y = x² - x.
( b) The area of the region enclosed by the curves between x = 0 and x = 3. is ∫[0, 3] (-x² + 6) dx - ∫[0, 3] (x² - x) dx
To sketch the curves y = x² - x and y = -x² + 6 on the same coordinate plane between x = 0 and x = 3, we can follow these steps:
(a) Sketching the Curves:
1. Calculate the y-values for each curve by substituting the x-values within the given range.
For y = x² - x:
- For x = 0, y = (0)² - (0) = 0.
- For x = 1, y = (1)² - (1) = 0.
- For x = 2, y = (2)² - (2) = 2.
- For x = 3, y = (3)² - (3) = 6.
For y = -x² + 6:
- For x = 0, y = -(0)² + 6 = 6.
- For x = 1, y = -(1)² + 6 = 5.
- For x = 2, y = -(2)² + 6 = 2.
- For x = 3, y = -(3)² + 6 = -3.
2. Plot the corresponding points on a graph, taking into account the x and y values obtained above.
The points we have are (0, 0), (1, 0), (2, 2), (3, 6) for y = x² - x and (0, 6), (1, 5), (2, 2), (3, -3) for y = -x² + 6.
3. Connect the points for each curve smoothly to complete the sketch.
Here is the graph showing the two functions on the same coordinate plane:
| + .
6 + .
| .
| .
| .
5 + .
| .
| .
| .
4 + .
|
|
|
3 + . +
| .
| .
| .
2 + . +
|
|
|
1 + .
| .
|
|
0 +---+---+---+---+---+---+---+---+
0 1 2 3 4 5 6 7 8
(b) Expressing the Area as Definite Integrals:
To find the area of the region enclosed by the curves between x = 0 and x = 3, we need to calculate the definite integrals of the two curves within that interval. The area can be expressed as the difference between the integrals of the top curve and the bottom curve.
Let's define the area as A:
A = ∫[0, 3] (top curve) dx - ∫[0, 3] (bottom curve) dx
In this case, the top curve is y = -x² + 6, and the bottom curve is y = x² - x.
(c) Evaluating the Integrals:
To find the area, we need to calculate the definite integrals for the top and bottom curves within the given interval.
∫[0, 3] (-x² + 6) dx - ∫[0, 3] (x² - x) dx
Evaluating these integrals will give us the area of the region enclosed by the curves between x = 0 and x = 3.
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Find the particular solution of the given differential equations 5. y""+3y +2y=7e³x, y(0)=0, y'(0)=0."
The particular solution to the given differential equation is: y(x) = (⁷/₂₀)e³ˣ - (⁷/₁₀)e⁻ˣ
How did we get the solution?To find the particular solution of the given differential equation, use the method of undetermined coefficients. Let's proceed step by step.
The differential equation is:
y'' + 3y' + 2y = 7e³ˣ
Step 1: Find the complementary solution:
The complementary solution is the solution to the homogeneous equation obtained by setting the right-hand side of the equation to zero.
y'' + 3y' + 2y = 0
The characteristic equation is:
r² + 3r + 2 = 0
Factoring the characteristic equation:
(r + 2)(r + 1) = 0
So the roots of the characteristic equation are:
r1 = -2
r2 = -1
The complementary solution is given by:
y_c(x) = c1 × e⁻²ˣ + c2 × e⁻ˣ
Step 2: Find the particular solution:
Assume that the particular solution has the form:
y_p(x) = Ae³ˣ
Now we substitute this form into the original differential equation:
(Ae³ˣ)'' + 3(Ae³ˣ)' + 2(Ae³ˣ) = 7e³ˣ
Differentiating twice:
9Ae³ˣ + 9Ae³ˣ + 2Ae³ˣ = 7e³ˣ
Combining like terms:
20Ae^(3x) = 7e³ˣ
Dividing both sides by e³ˣ:
20A = 7
Solving for A:
A = ⁷/₂₀
So the particular solution is:
y_p(x) = (⁷/₂₀)e³ˣ
Step 3: Find the complete solution:
The complete solution is the sum of the complementary and particular solutions:
y(x) = y_c(x) + y_p(x)
= c1 × e⁻²ˣ + c2 × e⁻ˣ + (7/20)e³ˣ
Step 4: Apply initial conditions:
Using the initial conditions y(0) = 0 and y'(0) = 0, we can solve for the constants c1 and c2.
y(0) = c1 × e⁻² ˣ ⁰ + c2 × e⁻⁰ + (⁷/₂₀)e³ ˣ ⁰ = 0
This gives us: c1 + c2 + (⁷/₂₀) = 0
y'(0) = -2c1 × e⁻² ˣ ⁰ - c2 × e⁻⁰ + 3(7/20)e³ ˣ ⁰ = 0
This gives us: -2c1 - c2 + (21/20) = 0
Solving these two equations simultaneously will give us the values of c1 and c2.
From the first equation, we get:
c1 + c2 = -(7/20) ----(1)
From the second equation, we get:
-2c1 - c2 = -(21/20)
Simplifying, we have:
2c1 + c2 = 21/20 ----(2)
Multiplying equation (1) by 2, we get:
2c1 + 2c2 = -7/10 ----(3)
Subtracting equation (2) from equation (3), we have:
2c1 + 2c2 - (2c1 + c2) = -7/10 - 21/20
Simplifying, we get:
c2 = -¹⁴/₂₀
c2 = -⁷/₁₀
Substituting the value of c2 in equation (1), we get:
c1 + (-⁷/₁₀) = -(⁷/₂₀)
c1 = -(⁷/₁₀) + (⁷/₁₀)
c1 = 0
So the values of c1 and c2 are:
c1 = 0
c2 = -⁷/₁₀
Therefore, the particular solution to the given differential equation is: y(x) = (⁷/₂₀)e³ˣ - (⁷/₁₀)e⁻ˣ
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Stephanie can jump rope 12o turns in 3 minutes. How many turns does she make in 1 minute
Answer:
40
Step-by-step explanation:
120 divided by three equals fourty