pls help with this question I need it now​
A
B
C

The probability of getting one even and one odd number when rolling two six-sided, fair dice is 1/4.

To calculate the probability of getting one even and one odd number, we can use the following approach:

So the probability of getting one even and one odd number when rolling two six-sided, fair dice is 1/4 or 0.25.

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The product of the expression (-3s + 2t) and (4s - t) is -12s² + 11st -2t². Then the correct option is D.

It is also known as multiplication. If the object n is given to m times then we just simply multiply them.

The expression is given below.

(-3s + 2t) and (4s - t)

Then the product of the expression (-3s + 2t) and (4s - t) is given as

(-3s + 2t)(4s - t)

-12s² +3st + 8st - 2t²

-12s² + 11st -2t²

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Answer:

34

Step-by-step explanation:

Answer: I would think that the midpoint is (2,3)

Step-by-step explanation: Because I have eyes

The probability of less than 14 successes in a binomial distribution with n = 18 and p = 0.6 is approximately 0.9917, or about 99.17%.

To find the probability of less than 14 successes in a binomial distribution with parameters n = 18 and p = 0.6, we need to sum the probabilities of all the possible outcomes where the number of successes is less than 14.

We can use the cumulative distribution function (CDF) of the binomial distribution to calculate this probability. The CDF gives the probability of getting up to a certain number of successes, and can be calculated as follows:

P(X < k) = Σ(i=0 to k-1) C(n, i) * p^i * (1-p)^(n-i)

where X is the binomial random variable, n is the number of trials, p is the probability of success, k is the number of successes we want to calculate the probability for, and C(n, i) is the binomial coefficient, which is equal to n choose i.

Using this formula, we can calculate the probability of less than 14 successes as follows:

P(X < 14) = Σ(i=0 to 13) C(18, i) * 0.6^i * 0.4^(18-i)

We can use a calculator or a computer program to evaluate this sum. Alternatively, we can use a binomial probability table to look up the values of the probabilities for each value of i from 0 to 13, and then add them up.

Using a calculator or a computer program, we can find that:

P(X < 14) = 0.9917 (rounded to 4 decimal places)

Therefore, the probability of less than 14 successes in a binomial distribution with n = 18 and p = 0.6 is approximately 0.9917, or about 99.17%.

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The linear optimization problem is to maximize the objective function 250x + 150y, subject to the constraints x + y ≤ 60, 3x + y ≤ 90, and 2x + y > 30, where x and y are both greater than or equal to 20.

The feasible region can be determined by graphing the constraints and finding the overlapping region that satisfies all the conditions. In this case, the feasible region is the area where the lines x + y = 60, 3x + y = 90, and 2x + y = 30 intersect. This region can be visually represented on a graph.

To find the corner points of the feasible region, we need to find the points of intersection of the lines that form the constraints. By solving the systems of equations, we can find that the corner points are (20, 40), (20, 60), and (30, 30).

The optimal solution and the optimal objective function value can be determined by evaluating the objective function at each corner point and selecting the point that yields the maximum value. By substituting the coordinates of the corner points into the objective function, we find that the maximum value is achieved at (20, 60) with an objective function value of 10,500.

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Many psychologists consider the distinguishing feature of adolescent thought to be the ability to think in terms of abstract concepts or hypothetical situations.

These cognitive abilities play a crucial role in adolescent development, facilitating problem-solving, decision-making, and the exploration of identity and future possibilities.

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The annual simple interest for the given principal and rate of interest is $840.

Given that, principal (P) = $2400, rate of interest (R) =7.0% and time period (T) = 5 years.

We know that, the formula to find simple interest is Simple Interest = (P×R×T)/100

Here, simple interest = (2400×7.0×5)/100

= 24×7×5

= $840

Therefore, the annual simple interest for the given principal and rate of interest is $840.

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Answer:

r = su/tv

General Formulas and Concepts:

Pre-Algebra

Order of Operations: BPEMDAS

Equality Properties

Step-by-step explanation:

Step 1: Define

su = rtv

Step 2: Solve for r

Answer:

Step-by-step explanation:

1.5 kilogram = 1.5* 1000= 1500

percentage = 300/1500 = 1/5 = 20%

The expression without using absolute value is 2z - 11

Given the expression with absolute value expressed as:

lz-6l-lz-5l

Since absolute function can both be negative or positive, hence;

lz-6l-lz-5l = z - 6 - -(z - 5)

lz-6l-lz-5l = z-6-(-z+5)

lz-6l-lz-5l = z - 6 + z - 5

lz-6l-lz-5l = 2z - 11

Hence the expression without using absolute value is 2z - 11

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The required formula for the function \(g\) is \[g(x)=-|f(x)|\

Given the graphs of functions \(f\) and \(g\), we need to find a formula for the function \(g\).

Since the given graph of \(g\) is a reflection of the graph of \(f\) over the \(y\)-axis, we know that \(g\) has the same absolute value as that of \(f\) but with a change in sign.

This means that the formula for \(g\) can be expressed as follows:\[g(x)=-|f(x)|\]

Let's verify this formula by graphing the given functions \(f\) and \(g\) and then compare the two graphs.

Graph of \(f(x)\):

Graph of \(g(x)\):

As you can see, the graph of \(g\) is a reflection of the graph of \(f\) over the \(y\)-axis and also has the same absolute value as that of \(f\) but with a change in sign.

This verifies that the formula for \(g\) is indeed:\[g(x)=-|f(x)|\]

Therefore, the required formula for the function \(g\) is \[g(x)=-|f(x)|\

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Question-

The graphs of f and g are given. Find a formula for the function g.

g(x) =

The pdf of W is: fw(w) = dFw(w)/dw = (1/16) \(e^{(-w/16)}\) for w>=0 .This is the pdf of a Gamma distribution with shape parameter 2 and scale parameter 16.

Since x and y are independent exponential random variables with E[x] = E[y] = 16, we have the pdf of x and y as:

fX(x) = (1/16) \(e^{(-x/16)}\)for x>=0

fY(y) = (1/16) \(e^{(-y/16)}\)for y>=0

Let W = XY, and we need to find the pdf of W. We can find the cumulative distribution function (CDF) of W and then differentiate it to find the pdf.

The CDF of W is given by:

Fw(w) = P(W<=w) = P(XY<=w) = ∫∫[xy<=w] fX(x) fY(y) dx dy

where [xy<=w] is the indicator function, which takes the value 1 if xy<=w and 0 otherwise.

Since x and y are non-negative, we can write:

Fw(w) = ∫∫[xy<=w] (1/256) \(e^{(-x/16)}\) \(e^{(-y/16)}\) dx dy

= (1/256) ∫∫[xy<=w] \(e^{(-x/16-y/16)}\) dx dy

Let's make a change of variables and define u = x+y and v = x. Then we have:

x = v

y = u-v

The Jacobian of this transformation is 1, so we have:

Fw(w) = (1/256) ∫∫[uv<=w] \(e^{(-u/16)}\) du dv

We can split the integral as:

Fw(w) = (1/256) ∫[0,w] ∫[v,∞] \(e^{(-u/16)}\) du dv

= (1/256) ∫[0,w] 16\(e^{(-v/16)}\) dv

= 1 - \(e^{(-w/16)}\)

Therefore, the pdf of W is: fw(w) = dFw(w)/dw = (1/16) \(e^{(-w/16)}\) for w>=0

This is the pdf of a Gamma distribution with shape parameter 2 and scale parameter 16.

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Step-by-step explanation:

6 + 7

8 1

6

6 + 56 = 62 = 7 __

8 8 8

Answer:

n = 5

Step-by-step explanation:

- Move all terms not containing  n  to the right side of the equation.

7n = 31 + 4

7n = 35

- Divide each term by  7  and simplify.

n = 5

i hope this helps :)

Answer:

I don't understand the question. Write it again & briefly.

Answer: 12 outcomes

Step-by-step explanation:

When you flip a coin there are two possible outcomes (heads or tails) and when you roll a die there are six outcomes(1 to 6). Putting these together means you have a total of 2×6=12 outcomes.

Answer:

the tetrahedron, octahedron and icosahedron

Answer:

tetrahedron, octahedron, icosahedron

a) The histogram for the data is illustrated below.

b) The cumulative percentage polygon is define in the histogram

c) The amount does the monthly electricity cost seem to be concentrated is 128 - 152

A histogram is a graphical representation of a frequency distribution. It consists of a set of bars that represent the frequency of data within certain intervals, also known as bins. The height of each bar represents the frequency or count of data points that fall within that bin.

To create a histogram for the electricity cost data, we need to first decide on the number and size of the bins. One common rule is to choose the number of bins as the square root of the sample size. In this case, we have 50 data points, so we can choose about 7 bins. The size of the bins can be determined by dividing the range of the data by the number of bins.

Once we have determined the number and size of the bins, we can create the histogram by drawing a set of bars with heights proportional to the number of data points that fall within each bin. The histogram can be further enhanced by adding labels for the x and y-axes, a title, and a legend.

As per the histogram, the amount does the monthly electricity cost seem to be concentrated is 128-152

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The equation for the base is that of a circle, so the cross sections will have a leg of length equal to the vertical distance between its halves.

x² + y² = 16   ⇒   y = ±√(16 - x²)

⇒   length = √(16 - x²) - (-√(16 - x²)) = 2 √(16 - x²)

Cross sections with thickness ∆x have a volume of

1/2 length² ∆x = 1/2 (2 √(16 - x²))² ∆x = (32 - 2x²) ∆x

since they are isosceles triangles and so their bases and heights are equal.

Then the total volume would be (D)

\(\displaystyle \int_{-4}^4 \frac12 \left(2 \sqrt{16-x^2}\right)^2 \, dx\)

In the equation V(t) = 40(1 - 0.15), 40 represents the initial volume of the tank when it is completely filled with water. Thus, the answer is, "40 represents the initial volume of the tank when it is completely filled with water."

Question: A 40-gallon tank has a small leak at the bottom. The volume remaining in a full 40 gallon tank of water after t minutes can be modeled by the following equation V(t)=40(1-15). where V(t) represents the volume remaining, in gallons, in the tank after t minutes.

a) What does 40 represent in the equation?

b) What does 1-0.15 represent in the equation?

c) How much water is left in the tank after 60 minutes?

Solution:

a) In the equation V(t) = 40(1 - 0.15), 40 represents the initial volume of the tank when it is completely filled with water. Thus, the answer is, "40 represents the initial volume of the tank when it is completely filled with water."

b) In the equation V(t) = 40(1 - 0.15), 1 - 0.15 represents the fraction of the initial volume of water left in the tank after t minutes. Here, 0.15 is the rate of leakage of the tank, which means that for every minute, 15% of the water will leak out. So, 1 - 0.15 will give the remaining fraction of water in the tank. Thus, the answer is, "1 - 0.15 represents the fraction of the initial volume of water left in the tank after t minutes."

c) To find out the volume of water left in the tank after 60 minutes, we need to substitute t = 60 in the equation V(t) = 40(1 - 0.15).V(60) = 40(1 - 0.15×60) = 40(1 - 9) = 40×(-8) = -320. Since the volume of water left cannot be negative, the answer is, "No water will be left in the tank after 60 minutes."Note: As the volume of water left can not be negative, the tank is empty after 8.8 minutes.

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Answer:

\( - 7 \: is \: an \: integer: \\ i.e \: - 7 \: fall \: within \: z.\)

The correct answer is that the probability of a cash flow being between $16,000 and $19,000 is approximately 18.59%.

To calculate the probability of a cash flow being between $16,000 and $19,000, we can use the standard deviation and assume a normal distribution.

We are given that the average cash flow is $14,000 with a standard deviation of $5,000. These values are necessary to calculate the probability.

The probability of a cash flow falling within a certain range can be determined by converting the values to z-scores, which represent the number of standard deviations away from the mean.

First, we calculate the z-score for $16,000 using the formula: z = (x - μ) / σ, where x is the cash flow value, μ is the mean, and σ is the standard deviation. Plugging in the values, we get z1 = (16,000 - 14,000) / 5,000.

z1 = 2,000 / 5,000 = 0.4.

Next, we calculate the z-score for $19,000: z2 = (19,000 - 14,000) / 5,000.

z2 = 5,000 / 5,000 = 1.

Now that we have the z-scores, we can use a standard normal distribution table or calculator to find the corresponding probabilities.

Subtracting the probability corresponding to the lower z-score from the probability corresponding to the higher z-score will give us the probability of the cash flow falling between $16,000 and $19,000.

Looking up the z-scores in a standard normal distribution table or using a calculator, we find the probability for z1 is 0.6554 and the probability for z2 is 0.8413.

Therefore, the probability of the cash flow being between $16,000 and $19,000 is 0.8413 - 0.6554 = 0.1859, which is approximately 18.59%.

So, the correct answer is that the probability of a cash flow being between $16,000 and $19,000 is approximately 18.59%.

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The probability of a cash flow between $16,000 and $19,000 is approximately 18.59%.

To calculate the probability of a cash flow being between $16,000 and $19,000, we can use the standard deviation and assume a normal distribution.

We are given that the average cash flow is $14,000 with a standard deviation of $5,000. These values are necessary to calculate the probability.

The probability of a cash flow falling within a certain range can be determined by converting the values to z-scores, which represent the number of standard deviations away from the mean.

First, we calculate the z-score for $16,000 using the formula: z = (x - μ) / σ, where x is the cash flow value, μ is the mean, and σ is the standard deviation. Plugging in the values, we get z1 = (16,000 - 14,000) / 5,000.

z1 = 2,000 / 5,000 = 0.4.

Next, we calculate the z-score for $19,000: z2 = (19,000 - 14,000) / 5,000.

z2 = 5,000 / 5,000 = 1.

Now that we have the z-scores, we can use a standard normal distribution table or calculator to find the corresponding probabilities.

Subtracting the probability corresponding to the lower z-score from the probability corresponding to the higher z-score will give us the probability of the cash flow falling between $16,000 and $19,000.

Looking up the z-scores in a standard normal distribution table or using a calculator, we find the probability for z1 is 0.6554 and the probability for z2 is 0.8413.

Therefore, the probability of the cash flow being between $16,000 and $19,000 is 0.8413 - 0.6554 = 0.1859, which is approximately 18.59%.

So, the correct answer is that the probability of a cash flow being between $16,000 and $19,000 is approximately 18.59%.

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The largest subset S on which the vector-valued function F is continuous is the interval (-3, ∞).

To find the largest subset S on which the given vector-valued function is continuous, we need to examine the individual component functions and identify any restrictions or conditions that could cause discontinuities.

Component 1: f1(t) = t/(9 + t^4)

This function is a rational function. It will be continuous for all real values of t except where the denominator equals zero: 9 + t^4 = 0. However, there are no real values of t that satisfy this equation, so f1(t) is continuous for all real values of t.

Component 2: f2(t) = 7t^2 - 7t + 1

This function is a polynomial function, and polynomial functions are continuous for all real values of t. Therefore, f2(t) is continuous for all real values of t.

Component 3: f3(t) = ln(t + 3)

The natural logarithm function is defined for the positive values of its argument. Therefore, t + 3 > 0, which implies t > -3. Hence, the function f3(t) is continuous for t > -3.

Taking all these considerations into account.The function is continuous for all values of t greater than -3.

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The length of the short leg is 4.5, of the long leg is 9.5 and of the hypotenuse is 10.5, respectively.

In this question we find a representation of a right triangle whose hypotenuse has a length of x + 6 and legs have lengths of x and x + 5, respectively. These side lengths are used in the Pythagorean theorem:

(x + 6)² = x² + (x + 5)²

Now we expand the expression and clear the variable x within the expression:

x² + 12 · x + 36 = 2 · x² + 10 · x + 25

x² - 2 · x - 11 = 0

(x - 1 - 2√3) · (x - 1 + 2√3) = 0

Since x must a non-negative value, then the lengths of each side are, respectively:

Leg 1

x = 1 + 2√3

x ≈ 4.5

Leg 2

x + 5 = 6 + 2√3

x ≈ 9.5

Hypotenuse

x + 6 = 7 + 2√3

x ≈ 10.5

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The absolute deviation of the data set 7 10 14 and 20 is 4.25.

What is the mean deviation method?

When calculating the average departure from the mean value of a particular data set, statisticians employ a measure known as the mean deviation. Following the steps below will make it simple to determine the mean deviation of the data values.

In statistics, the term "deviation" refers to the discrepancy between the observed value of a data point and its expected value. As a result, mean deviation, also known as mean absolute deviation, is the typical departure of a data point from the mean, median, or mode of the data collection.

data set is 7, 10, 14, 20,

Mean = m = 51/4 = 12.75

So the MAD is 1/4 |7-12.75| |10-12.75| |14-12.75| 20-12.75|

MAD = 17/4 = 4.25

Hence the mean absolute deviation of the data set 7 10 14 and 20 is 4.25.

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Answer:

45

Step-by-step explanation:

8 numbers summed and divided by 8 = 41

8numberssummed  / 8 = 41

8numberssummed = 41 * 8 = 328

now taking out two numbers whose mean is 29 is the same as taking out two 29's from the sum ....so now there are SIX numbers

  6numberssummed = 8numberssummed - 29 -29

                                   =   328    -29 -29 = 270

  so to find the mean of the remaining six numbers:

     6numberssummed / 6    is        270/6 = 45

Answer:

mean = 45

Step-by-step explanation:

mean is calculated as

mean = \(\frac{sum}{count}\)

given the mean of 8 numbers is 41 , then

\(\frac{sum_{8} }{8}\) = 41 ( multiply both sides by 8 )

sum₈ = 328

given the mean of 2 of the numbers is 29 , then

\(\frac{sum_{2} }{2}\) = 29 ( multiply both sides by 2 )

sum₂ = 58

Then

sum₆ = sum₈ - sum₂ = 328 - 58 = 270

then the mean of the other six numbers is

mean = \(\frac{sum_{6} }{6}\) = \(\frac{270}{6}\) = 45

Answer:

B

Step-by-step explanation:

im pretty sure, im sorry if its wrong ://

The differential equation to be solved is Nxy - 0.5ye-0.1x for osx54 with y(0) = 6.5 dx. This can be solved using Euler's method in MATLAB.

Follow the steps below.

Step 1: Create a function file - The differential equation needs to be defined in a function file first. Let's create a function file named "odefun.m".function dydx = odefun(x,y)

dydx = N*x*y - 0.5*y*exp(-0.1*x);

where N is a constant value that needs to be defined.

Step 2: Define the given values - Define the given values such as N, initial value y(0), and step size dx.

N = ...; %

Define N herey 0 = 6.5; %

Define initial value of y here. dx = ...; %

Define step size here

Step 3: Use Euler's method to solve the differential equation - Now, use Euler's method to solve the differential equation using a for loop. The MATLAB code is as follows: x = 0:dx:54; %

Define range of x values here y = zeros(size(x)); %

Initialize y as a vector of zeros y(1) = y0; %

Assign initial value of y to y(1) for i = 1: length(x)-1 dydx = odefun(x(i),y(i)); y(i+1) = y(i) + dydx*dx; end

Step 4: Plot the solution - Finally, plot the solution using the MATLAB command plot(x,y).

The complete MATLAB code is given below:

N = ...; %

Define N here y0 = 6.5; %

Define initial value of y here dx = ...; %

Define step size here x = 0:dx:54; %

Define range of x values here y = zeros(size(x)); % Initialize y as a vector of zeros y(1) = y0; %

Assign initial value of y to y(1) for i = 1: length(x)-1 dydx = odefun(x(i),y(i)); y(i+1) = y(i) + dydx*dx; end plot(x,y)

The plot of the solution will be displayed.

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