Convert 3.5mol of CO2 to grams.
How much energy is released when 22.4g of CH4 is burned?
The combustion of methane, CH4, releases 890.4 kJ/mol. That is, when one mole of methane is burned, 890.4 kJ are given off to the surroundings. This means that the products have 890.4 kJ less than the reactants.
Combustion of one mole or 16 g of methane gas releases 810 kJ of heat energy. Thus, heat released by the combustion of 22.4 g of methane is 1134 kJ.
What is combustion?Combustion of a substance is its reaction with atmospheric oxygen producing carbon dioxide and water. Combustion of hydrocarbons gases takes places easily and can be burned easily for fuels.
The chemical equation of combustion of methane is written below:
\(\rm CH_{4} + 2O_{2} \rightarrow CO_{2} + 2H_{2}O\)
This is an exothermic process and heat is released from the reaction system.
The heat released by the combustion of one mole of methane is 810 kJ.
molar mass of methane = 16 g/mol
no.of moles in 22.4 g = 22.4/16 = 1.4 g
Thus, heat released by 1.4 moles = 1.4 ×810 kJ =1134 kJ.
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i need help plsss i need it fast if possible
The 1000 kg ball would have 62500 J of kinetic energy; The 10 kg ball would have 125 J of kinetic energy; The 100 kg person would also have 1250 J of kinetic energy.
What is kinetic energy?Kinetic energy is the energy an object possesses due to its motion. It is defined as the energy that an object has as a result of its motion, and is dependent on the mass and velocity of the object.
To calculate the kinetic energy of an object, we use the formula:
KE = \(1/2 * m * v^{2}\)
where m is the mass of the object and v is its velocity.
Given that a 100 kg ball is traveling at 5 m/s, we can calculate its kinetic energy:
KE = \(1/2 * 100 kg * (5 m/s)^2\) = 1250 J
Using the same formula, we can calculate the kinetic energy for the following scenarios:
A 1000 kg ball traveling at 5 m/s:
KE =\(1/2 * 1000 kg * (5 m/s)^2\)= 62500 J
The 1000 kg ball would have 62500 J of kinetic energy, which is 50 times greater than the kinetic energy of the 100 kg ball.
A 10 kg ball traveling at 5 m/s:
KE = \(1/2 * 10 kg * (5 m/s)^2\)= 125 J
The 10 kg ball would have 125 J of kinetic energy, which is 10 times smaller than the kinetic energy of the 100 kg ball.
A 100 kg person traveling at 5 m/s:
KE = \(1/2 * 100 kg * (5 m/s)^2\) = 1250 J
The 100 kg person would also have 1250 J of kinetic energy, which is the same as the kinetic energy of the 100 kg ball.
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N2O4 ⇌ 2NO2
for the following reaction at 373 K, Kc = 0.36. If initial concentration of N2O4 is 0.1 mol dm^-3, what is the equilibrium concentration of NO2? (Is there a way to solve this without using quadratics?)
Okay, let's solve this step-by-step without using quadratics:
1) The equilibrium constant Kc = 0.36 means the equilibrium lies to the left. So there will be more N2O4 than NO2 at equilibrium.
2) The initial concentration of N2O4 is 0.1 mol dm^-3. Let's call this [N2O4]initial.
3) At equilibrium, the concentrations of N2O4 and NO2 will be [N2O4]equil and [NO2]equil respectively.
4) We know the equilibrium constant expression for this reaction is:
Kc = ([NO2]equil)^2 / [N2O4]equil
5) Setting this equal to 0.36 and plugging in 0.1 for [N2O4]initial, we get:
0.36 = ([NO2]equil)^2 / (0.1 - [NO2]equil)
6) Simplifying, we get:
0.036 = [NO2]equil^2
7) Taking the square root of both sides, we get:
[NO2]equil = 0.06 mol dm^-3
So the equilibrium concentration of NO2 is 0.06 mol dm^-3.
Let me know if you have any other questions! I can also provide a more step-by-step explanation if needed.
Which of the following indicates a strong base is present?
A) pH close to 7 B) good conductor of electricity C) low reaction rate D) indicator turns green-blue
Strong bases are bases which completely dissociate in water into the cation and OH- (hydroxide ion). The hydroxides of the Group I (alkali metals) and Group II (alkaline earth) metals usually are considered to be strong bases. These are classic Arrhenius bases. Here is a list of the most common strong bases.
LiOH - lithium hydroxide
NaOH - sodium hydroxide
KOH - potassium hydroxide
RbOH - rubidium hydroxide
CsOH - cesium hydroxide
*Ca(OH)2 - calcium hydroxide
*Sr(OH)2 - strontium hydroxide
*Ba(OH)2 - barium hydroxide
A strong base has been indicated with the ability to be a good conductor of electricity. Hence, option B is correct.
What is the base?Bases are defined as compounds that have the ability to form the release of the negative ions or the hydroxide ions in the solution. The acids release hydrogen or proton, thereby bases tend to have the ability to neutralize acids.
The pH has been the measure of the solution to be able to accept or donate the protons and electrons. The pH has been measured on a scale of 1-14 with the acids having a pH of less than 7, and the pH of bases tends to move towards 14. 7 is the neutral pH.
The strong bases form the dissociation of the ions in the solution more readily, and ions contribute as the medium, thereby forming the conduction of the electricity. Hence, option B is correct.
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The Case of the Putrid Pond Problem Statement: A very large (500,000 sq. ft. 10 football fields) sludge pond is part of a waste treatment plant. The liquid in the pond is very viscous and sticky. From time to time, unwanted floating objects (dead animals, branches, etc.) appear on the pond and must be removed. Unfortunately, covering the pond is not an option. (a) Devise ways to solve the above-mentioned problem through all the FOUR (4) brainstorming methods and describe it in detail. (15 marks) (b) Draw and describe a fishbone diagram after organizing the ideas generated from (a). (10 marks)
The Case of the Putrid Pond Problem Statement:
1. Brainstorming generated solutions: debris collection nets, manual cleaning, water jets, filtration upgrades, waste management improvements, and regular maintenance.
2. Fishbone diagram: categorizes causes (inflow system, waste management, pond maintenance, environmental factors) and solutions (screening mechanisms, enhanced cleaning schedules).
(a) Devise ways to solve the above-mentioned problem through all the FOUR (4) brainstorming methods and describe it in detail:
1. Brainwriting: In this method, each team member writes down their ideas on sticky notes or a shared document without discussing them with others. The ideas can then be compiled and analyzed collectively. Some possible solutions through brainwriting could include:
- Deploying a large floating debris collection net or barrier around the perimeter of the pond to capture and remove floating objects.
- Implementing regular manual cleaning by workers using long-handled nets or other specialized tools.
- Introducing a system of water jets or pumps to create a flow within the pond, pushing floating objects towards a collection area for easy removal.
2. Reverse Brainstorming: In reverse brainstorming, instead of generating solutions, the focus is on identifying potential causes or factors that contribute to the problem. These causes can then be addressed to find solutions. Possible causes identified through reverse brainstorming might include:
- Inadequate filtration or screening mechanisms in the inflow system, allowing unwanted objects to enter the pond.
- Lack of proper waste management practices upstream, leading to the accumulation of debris in the pond.
- Inefficient or infrequent monitoring and maintenance of the pond, allowing the problem to persist.
3. Starbursting: This technique involves asking specific questions about the problem to prompt idea generation. Questions related to the Putrid Pond problem could be:
- How can we prevent unwanted floating objects from entering the pond in the first place?
- What alternative methods can be used to remove floating objects without covering the pond?
- Are there any environmentally friendly solutions that can be implemented?
4. Mind Mapping: Mind mapping is a visual brainstorming technique that involves creating a diagram with the main problem in the center and branching out ideas around it. Some ideas for solving the problem of the Putrid Pond could include:
- Installing automatic skimmers or surface vacuum systems to continuously remove floating debris.
- Implementing regular maintenance schedules for inspecting and cleaning the pond to prevent accumulation.
- Introducing biological treatment methods that can break down organic matter and prevent foul odors.
(b) A fishbone diagram, also known as a cause-and-effect or Ishikawa diagram, can help organize the potential causes and solutions identified through brainstorming. Here is a description of the fishbone diagram for the Putrid Pond problem:
The main problem, "Unwanted Floating Objects in the Pond," is written in the center of the diagram. The diagram branches out into different categories representing possible causes, such as "Inflow System," "Waste Management Practices," "Pond Maintenance," and "Environmental Factors." Each category contains the specific causes identified through brainstorming. For example, under "Inflow System," causes could include "Inadequate Filtration" and "Lack of Screening Mechanisms." Similarly, under "Pond Maintenance," causes could include "Insufficient Cleaning Procedures" and "Lack of Monitoring."
From the identified causes, further branches are created to suggest possible solutions. These solutions can be linked to the specific causes they address. For instance, under "Inflow System," a solution could be "Upgrading Filtration Systems" or "Implementing Effective Screening Mechanisms." Under "Pond Maintenance," solutions might include "Establishing Regular Cleaning Schedules" or "Enhancing Monitoring Practices."
The fishbone diagram visually represents the cause-and-effect relationships between the problem, its causes, and potential solutions, providing a structured overview of the brainstormed ideas.
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How many moles of carbon dioxide are produced from the combustion of 110 g of ch4
Answer:
6.875 moles of Carbon Dioxide
Explanation:
110 grams CH4 / 16 molar mass = 6.875 moles
Howmany moles of chlorine are there in 67.2 liter sample of chlorine at STP?
Identify the Lewis acid and Lewis base in each of the reactions. - C1- + AICI3 --> AICI4- ____ _____- BF3 +F- --> BF4-____ _____- NH3 + H+ --> NH4+____ _____
Each reaction's Lewis acid and Lewis base are as follows:
AlCl3 is the Lewis acid in the reaction, whereas Cl- is the Lewis base. F- is the Lewis base and BF3 is the Lewis acid in the reaction Cl- + AlCl3 --> AlCl4- BF3 + F- --> BF4-
The Lewis base in this reaction is NH3, and the Lewis acid is H+. NH3 + H+ --> NH4+
Explanation: A Lewis acid acts as an electron pair acceptor in a Lewis acid-base reaction, whereas a Lewis base acts as an electron pair donor. In the initial reaction, Cl- provides AlCl3 with a pair of electrons, which AlCl3 accepts to produce AlCl4-. As a result, AlCl3 is the Lewis acid and Cl- is the Lewis base. In the subsequent response, F- provides two pairs. BF3 takes the electrons and transforms them into BF4-. Hence, the Lewis bases are F- and BF3, respectively. In the third reaction, H+ absorbs a pair of electrons from NH3 and forms NH4+ as a result. As a result, the Lewis bases are NH3 and H+.
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g determine the empirical formula for a compound that is found to contain 10.15 g p and 34.85 g cl.
The empirical formula for the compound is \(PCl_{3}\)
The empirical formula of a compound is the formula in which the atoms of all the elements are present in their simplest whole-number ratio. It's possible that a compound's empirical formula and molecular formula are different.
Given Information:
P = 10.15 mg
Cl = 34.85 mg
Convert mg to moles
31 mg of P ----------------- 1 mmol
10.15 mg ------------------ x
x = 0.327 mmol of P
35.5 mg of Cl ------------ 1 mmol
34.85 mg ----------------- x
x = 0.982 mmol of Cl
Divide by the lowest number of mmoles:
For P = \(\frac{0.327}{0.327}\) = 1
For Cl = \(\frac{0.982}{0.327}\) = 3
So the empirical formula for the compound will be \(PCl_{3}\)
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What are 10 examples of homogeneous mixtures?
A homogeneous mixture is a mixture where the components are uniformly distributed throughout the mixture, resulting in a uniform composition and appearance. Here are 10 examples of homogeneous mixtures:
Saltwater: When salt is dissolved in water, the resulting mixture is homogeneous, with the salt molecules evenly distributed throughout the water.
Air: The air we breathe is a mixture of gases, including nitrogen, oxygen, and carbon dioxide. These gases are evenly distributed throughout the atmosphere, resulting in a homogeneous mixture.
Sugar solution: When sugar is dissolved in water, the resulting mixture is homogeneous, with the sugar molecules evenly distributed throughout the water.
Vinegar: Vinegar is a homogeneous mixture of acetic acid and water, with the two components evenly distributed throughout the solution.
Milk: Milk is a homogeneous mixture of water, fat, protein, and sugar, with these components evenly distributed throughout the liquid.
Brass: Brass is a homogeneous mixture of copper and zinc, with the two metals evenly distributed throughout the alloy.
Gasoline: Gasoline is a homogeneous mixture of hydrocarbons and other additives, with the components evenly distributed throughout the liquid.
Blood: Blood is a homogeneous mixture of plasma, red and white blood cells, and platelets, with these components evenly distributed throughout the liquid.
Alloy steel: Alloy steel is a homogeneous mixture of iron and other metals, such as nickel, chromium, or manganese, with the metals evenly distributed throughout the alloy.
Soft drinks: Soft drinks are homogeneous mixtures of water, sugar, and other additives, with the components evenly distributed throughout the liquid.
Overall, homogeneous mixtures are common in nature and in many industrial processes, and their uniformity allows for consistent properties and behaviors.
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noble gas with fewer protons than Br
what is the reason for analyzing a blank in the spectrophotometer before analyzing the standard solution?
the rearrangement of pinacol occurs in the cation intermediate after losing water as a leaving group. the cation is originally located on the carbon
Pinacol rearrangement is a widely known organic reaction that involves the conversion of a 1,2-diol into a ketone or an aldehyde.
This reaction proceeds via a cationic intermediate that forms after the loss of a water molecule as a leaving group. The cation intermediate, which is positively charged, is originally located on the carbon atom that is bonded to both alcohol groups. In this state, the cation can undergo a series of structural changes that result in the migration of a hydrogen atom and the formation of a carbonyl group. The final product of the pinacol rearrangement is a ketone or an aldehyde with one fewer carbon atom than the starting diol. This reaction has been extensively studied and applied in various fields of organic chemistry.
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a scientist mixes 0.02 g of a strong base in 83 ml of water and obtains a ph of 12. he then realizes that he forgot to label the container and forgot what base he added. what is the most likely the identity of this base?LiOH
NaOH
RbOH
KOH
Option (A) is correct. LiOH is the most likely strong base added to the container containing a mixture of 0.02g g and 30ml of water.
A base is said to be a strong base if that can remove a proton (H+) from a molecule of even a very weak acid such as water in an acid–base reaction. Some examples of strong bases are hydroxides of alkali metals and alkaline earth metals like sodium hydroxide and Ca(OH). A strong base is defined as a base that is completely dissociated in an aqueous solution. The strong bases ionizes in water to yield one or more hydroxide ion (OH-) per molecule of base. Basically strong base is a compound that has an ability to remove a proton from a very weak acid. It can completely dissociate into its ions when in water.
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Complete question is,
A scientist mixes 0.02 g of a strong base in 83 ml of water and obtains a pH of 12. he then realizes that he forgot to label the container and forgot what base he added. what is the most likely the identity of this base?
A. LiOH
B. NaOH
C. RbOH
D. KOH
without constants you would not know which variable affected the
Please Help ASAP, any suggestions help
The correct answer is C. -0.76 V. the potential for this reduction half-reaction is -0.76 V relative to the standard hydrogen electrode.
The correct answer is C. -0.76 V.
The standard reduction potential, denoted as E°, is a measure of the tendency of a species to gain electrons and undergo reduction in a redox reaction. It is expressed in volts (V) and represents the potential difference between the reduction half-reaction and the standard hydrogen electrode (SHE), which is assigned a potential of 0 V.
In the given half-reaction:
Mg2+(aq) + 2e- → Mg(s)
The species undergoing reduction is Mg2+(aq), and it is being reduced to Mg(s) by gaining 2 electrons.
To find the standard reduction potential for this half-reaction, we can refer to standard reduction potential tables. These tables provide a reference for various half-reactions with respect to the standard hydrogen electrode.
In the table, the standard reduction potential for the Mg2+(aq) + 2e- → Mg(s) half-reaction is listed as -0.76 V. This means that Mg2+ has a tendency to be reduced, and the potential for this reduction half-reaction is -0.76 V relative to the standard hydrogen electrode.
Therefore, the correct answer is C. -0.76 V.
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Which is the most polar molecule?
1. CF4
2. BF3
3. Ar
4. H2O
5. CO2
6. CH
glyceraldehyde 3-phosphate dihydroxyacetone phosphate --> 1,6-bisphosphate in the presence of aldolase enzyme
In the presence of the aldolase enzyme, the reaction between glyceraldehyde 3-phosphate and dihydroxyacetone phosphate results in the formation of 1,6-bisphosphate.
The conversion of glyceraldehyde 3-phosphate and dihydroxyacetone phosphate to 1,6-bisphosphate is facilitated by the aldolase enzyme. This enzyme catalyzes the aldol condensation reaction, which involves the formation of a carbon-carbon bond.
During the reaction, the aldolase enzyme binds to both glyceraldehyde 3-phosphate and dihydroxyacetone phosphate, positioning them for the condensation reaction. The enzyme facilitates the transfer of a hydroxyl group from one molecule to the other, resulting in the formation of a new carbon-carbon bond between the two molecules.
The end product of the reaction is 1,6-bisphosphate, which is an important intermediate in various metabolic pathways, including glycolysis and gluconeogenesis.
The aldolase enzyme plays a crucial role in these pathways by facilitating the conversion of glyceraldehyde 3-phosphate and dihydroxyacetone phosphate to 1,6-bisphosphate.
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PLEASE HELP ME!!!!!!!!
nswerllo
Explanation:
please help me with this : what is the Classification of a prairie dog
Prairie dogs are a type of squirrels and they are classified in the group of rodents. The family of prairie dog is Sciuridae.
What is taxonomical classification ?The taxonomical classification of an animal is to indicates its kingdom, phylum, class, order, family, genus and species. All the known animals, plants and other livings are classified to these 7 categories.
The prairie dogs are ground squirrels usually seen in the prairie grass lands. They are in the mammalian class and in the order of Rodentia.
They are classified to the family of Sciuridae.
Genus of prairie dogs is cynomys and their species can be of various types such as ludovicianus, gunnisoni, mexicanus etc based on the regions they reside.
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I need to know how to do this but if you could just answer it it's fine
Answer:
im not entirely sure what needs to be done but the 2NH3 is the product and the other half is the reactants .
if any elements are added to others it is the reactants
this is a breakdown of a compound because the arrow always indicates the direction of the reaction .
Can someone help me with this??
゚+*:ꔫ:*﹤ ﹥*:ꔫ:*+゚Answer:゚+*:ꔫ:*﹤ ﹥*:ꔫ:*+゚
The following: Jupiter, Saturn, Uranus, or Neptune.
゚+*:ꔫ:*﹤ ﹥*:ꔫ:*+゚Explanation:゚+*:ꔫ:*﹤ ﹥*:ꔫ:*+゚
any of the planets Jupiter, Saturn, Uranus, and Neptune whose orbits lie beyond the asteroid belt.
Answer:
it is Saturn
Explanation:
and outer planter is just a planet outside the asteroid belt
Help Me Find The Answer. Will Give Brainliest.
Answer:
Explanation:
Gloves
the most specific method for the assay of glucose in all body fluids utilizes:
The most specific method for measuring glucose in body fluids is the enzymatic glucose oxidase/peroxidase assay. It involves the enzymatic conversion of glucose to gluconic acid and hydrogen peroxide, followed by a colorimetric measurement of the reaction product. The glucose concentration in the sample is determined by comparing its color intensity to a calibration curve generated from known glucose standards.
The most specific method for the assay of glucose in all body fluids is enzymatic glucose oxidase/peroxidase assay. Here are the steps involved in this method:
1. Sample collection: Obtain the body fluid sample (e.g., blood, urine, cerebrospinal fluid) that contains glucose.
2. Sample preparation: If necessary, prepare the sample by removing any interfering substances or diluting it to an appropriate concentration.
3. Enzymatic reaction: Mix the prepared sample with a reagent containing glucose oxidase and peroxidase enzymes. Glucose oxidase converts glucose to gluconic acid and hydrogen peroxide, while peroxidase reacts with hydrogen peroxide to produce a colored compound.
4. Colorimetric measurement: Measure the color intensity of the reaction product using a spectrophotometer at a specific wavelength. The intensity of the color is directly proportional to the concentration of glucose in the sample.
5. Calibration: Create a calibration curve by measuring known concentrations of glucose standards under the same conditions as the sample. This curve helps determine the glucose concentration in the sample based on its color intensity.
6. Calculation: Use the calibration curve to calculate the glucose concentration in the sample based on the measured color intensity.
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Save
Drag the tiles to the correct boxes to complete the pairs.
Which types of matter are these substances?
Tiles
element
compound
homogeneous mixture
heterogeneous mixture
Pairs
a cloud, which consist of small water droplets
distributed throughout the air
helium, a gas composed of identical atoms
rubbing alcohol, a liquid composed of chemically bonded
carbon, oxygen, and hydrogen atoms
sugar thoroughly dissolved in water
Submit
Answer:
1.heterogeneous mixture
2.element
3.compound
4.homogeneous mixture
Explanation:
The correct pairs are:
A cloud, which consist of small water droplets - Heterogeneous mixture
Distributed throughout the air
helium, a gas composed of identical atoms - Element
Rubbing alcohol, a liquid composed of chemically bonded - Compound
Carbon, Oxygen, and Hydrogen atoms
sugar thoroughly dissolved in water - Homogenous mixture.
In Heterogenous mixture, the composition of the mixture is not uniform. In Homogenous mixture, the composition is uniform throughout. Element is the combination of same atoms. Compound contains two or more elements.
Therefore, the correct pairs are,
A cloud, which consist of small water droplets - Heterogeneous mixture
Distributed throughout the air
helium, a gas composed of identical atoms - Element
Rubbing alcohol, a liquid composed of chemically bonded - Compound
Carbon, Oxygen, and Hydrogen atoms
sugar thoroughly dissolved in water - Homogenous mixture.
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Which describes what a velocity/time graph would look like with no acceleration?
curved line on a upward slope
straight line on a downward slope
straight line with zero slope
curved line on a downward slope
A velocity/time graph would look like with no acceleration is the straight line with zero slope
Here the given data is related with the concept and fundamental of velocity/time graph and the graphical representation where the velocity of an object is concluded with respect to the time is known as velocity-time graph
Velocity-time graph refer the information about acceleration where the velocity should be at y-axis and on the other hand the time should be at x-axisAnd if there is zero acceleration the slope should be shown in horizontal line and when the acceleration is negative there is downward slopingTherefore the given case in the graph is straight line with zero slope means no acceleration
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Answer:
C
Explanation:
got it right
Determine the major organic product(s) of the following reaction. Include appropriate stereochemistry in answer. Be sure to consider which mechanism would dominate (SN1, SN2, E1, or E2) when predicting the product.
The major organic product of the given reaction would depend on the mechanism that dominates, either SN1, SN2, E1, or E2.To determine the major organic product, we need to consider the mechanism that would dominate in the given reaction.
SN1 mechanism: If the reaction proceeds through the SN1 mechanism, the major product would be the carbocation intermediate, followed by the nucleophilic attack. The stereochemistry would depend on the attack of the nucleophile, and it may result in the formation of both retention and inversion products.
SN2 mechanism: If the reaction proceeds through the SN2 mechanism, the major product would be the direct substitution of the leaving group by the nucleophile. The stereochemistry of the product would be inverted, as the nucleophile attacks from the opposite side of the leaving group.
E1 mechanism: If the reaction proceeds through the E1 mechanism, the major product would be the elimination of the leaving group to form a double bond. The stereochemistry would depend on the orientation of the leaving group and the hydrogen atoms involved in the elimination.
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What are the function of the cytokinesis hormone in plant's. Choose the correct answer
A ) ! ck jd pyk v zc !
B ) ! ck jd pyk v zc !
These are some of the important functions of the cytokinesis hormone in plants :-
Cytokinesis is a group of growth regulators that is found in plants. It helps in performing cell divison of plant roots, and shoot system. It also helps in promoting the cell's growth, development, flowering, and seed formation.
It helps in the protein production which is important for mitosis. It provides resistance against certain diseases causing bacteria in crops. It mainly contains Nitrogen, Hydrogen, and a few atoms of oxygen in its structure.
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The options for the function of cytokinesis should be:
(A) performing cell division in plant roots
(B) shoot system
(C) promoting the cell’s growth, development
(D) All of these
Answer - (D) All of these
what hypothesis is best for chemical reaction?
will give Brainliest
Answer:
If the reactants in the chemical reactions are known, then the products can be predicted because the pattern of the chemical reactions is being followed. The pattern for a single replacement is A + BC --> AC + B. This is like the Hear It Pop Chemical Reaction which is also an example of the single replacement.
Explanation: