Question 3 (12 points)
A pump of 1200rpm rotational speed is connected to a delivery pipe (rising main) of 500m
length and 0.025 Darcy friction factor. The following plot shows the pump performance and the
rising main curve.
40
Reming main
25
нер
20
15
100
Eficency
50
Pump
ES
10
20
50
60
Q (L.)
I
Answer the following short questions
1) The flow rate delivered by the pump when connected to the rising main is
2) The total head delivered by the pump when connected to the rising main is
3) The static lift (Hs) is:
4) What is the power produced (output) and consumed (input) by the pump?
5) What is the diameter of the rising main!
6) What is the sort of this pump​

Answer is illustrated through images attached.

Here compression ratio is 15.

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Answer:

i need points 425677

Explanation:

yurrrrrr  awnser C

An alpha-numeric designator which is systematically assigned at the time of manufacture, so as to identify the manufacturer, month, year, location, and batch is referred to as lot number.

A product can be defined as any physical object (tangible item) that is typically produced by a manufacturer so as to satisfy and meet the demands, needs or wants of every customer. Also, some examples of a product include the following:

A lot number can be defined as an alpha-numeric designator which is systematically designed and assigned at the time of manufacture, so as to identify the manufacturer, month, year, location, and batch.

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Answer:

105 kips

Explanation:

Determine the factored bearing deformation strength per bolt

we can determine this using the relationship below

Bearing deformation strength = C * Area * Fl  --------- ( 1 )

Fl = factored load = 100 kips

Area ( bearing area ) = diameter of bolt * thickness of end plate

                                  = 0.875 * 0.5 = 0.4375 in^2

C = 2.4 ( constant for bolt holes not drilled at edges )

back to equation 1

2.4 * 0.4375 * 100

= 105 kips

Answer:

Technician A

Explanation:

Technician A is correct. Technician B is incorrect, as the brake booster aids in the drivers ability to depress the brake pedal, but the force applied is the same if the booster was absent.

Answer:

my friend here justin

Explanation:

hes already taken

Answer:

  1 13/64

Explanation:

The depth of the hole is the height of the block less the remaining material below the hole:

  depth = 1 3/8 +1 15/16 - 3/8 = (1 3/8 -3/8) +1 15/16 = 2 15/16

We want to find the difference between this depth and the depth of the hole already drilled:

  2 15/16 -1 47/64 = 2 60/64 -1 47/64

  = (2 -1) +(60 -47)/64 = 1 13/64

The hole must be drilled 1 13/64 deeper to match the drawing.

Network address translation between Walla Walla and Seattle is the optimum network method for this.

Network address translation is a technique for translating one IP address space to another by altering network address information in packet IP headers while they are in transit through a traffic routing device.

The NAT (network address translation) is originally established to limit the number of public IP addresses used by major corporate businesses or companies, hence preserving both IP address conservation and protection.

There are several devices within the community that need to be protected from the outside world, thus the NAT permits private IP addresses to connect to the outside world.

As an example, designating a public handle to a set of HOST/gadgets inside an inside community/corporation.

Remember that a host or device in an inner network with a private IP address, say (192.168.1.11), wishes to interact with an internet server on the internet ( outside world ). Now, NAT will convert this non-public IP address into a public IP address (for example, 1.12.1.1) that is known to everyone.

So, the web server recognizes this precise public IP and returns its outcome to this deal with (1.12.1.1), after which it routes to the vacation spot, where the NAT converts it once more to the private IP deal with and sends the outcomes to the desired device in the non-public network.  

As for a corporation's local network, there are numerous non-public IP with one public IP denoting all of them), so the result now, obtained via one of the devices in that network

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H is the enthalpy of the gas, Hf is the enthalpy of the fuel, m is the mass flow rate of air, Vexit and Vinlet are the exit and inlet velocities.

Mass is the measure of the amount of matter an object contains. It is measured in kilograms (kg) in the International System of Units (SI). Mass is also known as a measure of inertia, which is the resistance of an object to change its velocity or its direction. In other words, mass is the measure of an object's resistance to acceleration.

The specific thrust is the amount of thrust generated per unit mass flow rate of air through the engine. It can be calculated by the following equation:

T = m * (Vexit – Vinlet)

where m is the mass flow rate of air and Vexit and Vinlet are the exit and inlet velocities respectively.

TSFC

The TSFC is the amount of fuel consumed per unit of thrust produced. It can be calculated by the following equation:

TSFC = (mf/T) * (Vexit – Vinlet)

where mf is the fuel flow rate and T is the thrust generated.

T04

T04 is the temperature of the gases exiting the combustor. It can be calculated from the energy equation, which is given by:

H = Hf + m * (Vexit2/2 – Vinlet2/2) + mf * (Qf – Hf)

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The model that the student made is a motor. So, the answer is option A.

The following are the key elements that the student has used to make a model of a motor:

The pole pieces are placed on the edges of the strong, permanent magnets.

The Armature is a loop of wire that the student is rotating.

Finally, the slip rings are used to transfer electrical power from the armature to the external source.

With the flow of current in the loop, a magnetic field is established that interacts with the poles of the magnet, causing the armature to spin. The model is similar to a motor as it uses the basic principle of a motor - electromagnetic induction to convert electrical energy into mechanical energy.

Therefore, the student has made a model of a motor..

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Answer: None of the above

Explanation:

Business process modeling refers to the graphical representation of the business processes of a company, which is vital in the identification of potential improvements.

Business pticess modelling can be done through graphing methods, like data-flow diagram, flowchart etc. It is vital as business managers can effectively and quickly communicate their ideas.

It also enhances the customization of business processes, enhances the competitive advantage and enhances the process communication as well.

Therefore, the answer to the question will be "None of the above".

Answer:

Hello your question is incomplete attached below is the complete question

answer :

I) P = t/R * 492.85

II) The final equation : PR / t  + 4M/πR3 =  б e

Explanation:

attached below is a detailed solution to the given problem

i) P = t/R * 492.85

ii) Final equation : PR / t  + 4M/πR3 = б e

Answer:

Attached below is the derived next state equations

Explanation:

Attached below is the derived next state equations

used for the solution of the given problem.

Answer:

24 cans

Explanation:

The number of glycol solution needed to prevent water from freezing is 42 galloons. The glycol solution comes in cans of 1.75 gallons.

Therefore 1 can of glycol = 1.75 gallon.

Number of cans of glycol needed = Total gallons of glycol needed / number of gallon present in each can

Number of cans of glycol needed = 42 gallons / (1.75 gallon per can)

Number of cans of glycol needed = 24 cans

Therefore a total of 24 cans are needed.

To prevent aspiration (air being into the sprue), the velocity of the molten metal at the bottom of the sprue should not exceed a certain value.

Vmax = 0.027 * (d^2 / L) where:Vmax is the maximum allowable velocity in m/s

d is the diameter of the sprue in meters

L is the length of the sprue in meters

We are given that the volume flow rate of the molten metal is 0.01 m3/min, which is equivalent to 0.0001667 m3/s. Using the equation for volume flow rate (Q = A * V), we can find the velocity of the molten metal at the top of the sprue:Vtop = Q / A

= (0.0001667 m3/s) / ((π/4) * (0.02 m)^2)

= 1.329 m/s

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Answer:A

Explanation:

Those who want to save money and will use the product for only a few years

Answer:

THE ANSWER is A - those who want to save money and will use the product for only a few years

Explanation: Got it right on edg 2021

For a single-phase alternating circuit, it takes approximately 0.0041 seconds for the current to reach 6 A for the first time. and it takes approximately 0.0011 seconds to reach -100 V for the second time.

f. To calculate the time taken for the current to reach 6 A for the first time, we need to solve the equation:

i = 9.4sin(377t - π/3) = 6

Let's solve this equation for t:

9.4sin(377t - π/3) = 6

Dividing both sides by 9.4:

sin(377t - π/3) = 6/9.4

sin(377t - π/3) ≈ 0.6383

we need to find the inverse sine (arcsine) of 0.6383. However, since arcsine has multiple solutions, we need to consider the principal value between 0 and 2π. The principal value of arcsine(0.6383) is approximately 0.6949 radians or 39.82 degrees.

Now, we can solve for t:

377t - π/3 = 0.6949

377t = π/3 + 0.6949

t = (π/3 + 0.6949) / 377

Calculating this expression, we get:

t ≈ 0.0041 seconds

g. To calculate the time taken to reach -100 V for the second time, we need to solve the equation:

v = 209sin(377t - π/12) = -100

Let's solve this equation for t:

209sin(377t - π/12) = -100

Dividing both sides by 209:

sin(377t - π/12) = -100/209

we need to find the inverse sine (arcsine) of -100/209. Again, since arcsine has multiple solutions, we need to consider the principal value between 0 and 2π. Let's denote arcsine(-100/209) as α:

α ≈ arcsin(-100/209)

Calculating this, we get:

α ≈ -0.5535 radians or -31.68 degrees

Now, we can solve for t:

377t - π/12 = α

377t = π/12 + α

t = (π/12 + α) / 377

Calculating this expression, we get:

t ≈ 0.0011 seconds

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It is challenging(difficult) to pass on winding and curving roads.

Winding and curving roads often obstruct the driver's view of what lies ahead. This reduced visibility can make it difficult to anticipate oncoming traffic, pedestrians, or obstacles, increasing the risk of accidents if attempting to pass.

In terms of Uncertain Road Conditions, the nature of winding and curving roads can lead to varying road conditions. These conditions might include sharp turns, uneven surfaces, narrow lanes, and potential hazards around corners. Passing in such conditions can lead to loss of control or collisions.

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After first loading the simulator, the initial velocity that will land and roll into the hole without changing any of the other factors is 0.

To determine the initial velocity that will land and roll into the hole without changing any of the other factors after first loading the simulator, we can use the following formula:

V² = (2gh) / (1 - sinθ)

where V is the initial velocity, g is the acceleration due to gravity, h is the height of the hole, and θ is the angle of the inclined plane. To identify the initial velocity that will land and roll into the hole, we need to make sure the ball reaches the hole's bottom with a velocity of zero.

In other words, the velocity of the ball when it lands must equal the velocity of the ball when it rolls without any change in speed. Therefore, the final velocity must be zero, and we can set Vf = 0. Hence, we have:

Vf² = Vi² + 2gh

where Vi is the initial velocity. Since the ball rolls without any change in speed, we can use the distance traveled by the ball when it lands in the hole, which is equal to h / sinθ. Hence, we have:

h / sinθ = Vi² / (2g)

Therefore, Vi² = 2gh sinθ

Vi = √(2gh sinθ)

Vi = √(2 × 9.8 × 0.1 × sin(0))

Vi = √(0) = 0

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To determine the reactions at points A, B, and C, we will first need to analyze the forces and moments acting on the beam. Given that F1 = 450 N and F2 = 720 N, we can use the following steps:

1. Calculate the sum of the vertical forces, which should be equal to zero for static equilibrium:

ΣFy = Ay + By + Cy - F1 - F2 = 0

2. Calculate the sum of the moments about point A, which should also be equal to zero for static equilibrium:

ΣMA = (F1 * d1) + (F2 * d2) - (Cy * d3) = 0

Here, d1, d2, and d3 are the distances from point A to the points where the forces F1, F2, and Cy are applied.

3. Solve for the unknown reactions Ay, By, and Cy using the above equations.

Note that without the distances (d1, d2, and d3) or a diagram (Figure 1), it is not possible to provide specific numerical values for the reactions at A, B, and C.

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Answer:

No it is not permitted

Explanation:

It is not permitted  because as per NEC 410.21 policy no other conductor is allowed to be passed through integral junction box luminaries unless such conductor supply recessed luminaries.

The marking will show that the Luminaries is of the right construction or right installation to ensure that the the conductors ( in the outer boxes ) will not be exposed to temperatures greater than the conductor rating, hence the lack of marking makes it not to be permitted.

Answer:

Explanation:

The controlling resistance to heat transfer can be found by analyzing the different mechanisms of heat transfer involved in a given system and identifying the limiting factor that controls the overall rate of heat transfer.

There are three main mechanisms of heat transfer: conduction, convection, and radiation. Conduction occurs when heat flows through a solid material or between two materials in contact. Convection occurs when heat is transferred by the movement of fluids such as air or water. Radiation occurs when heat is transferred through electromagnetic waves.

The controlling resistance to heat transfer can be calculated using the following equations:

For conduction:

Rc = L / (k * A)

where Rc is the thermal resistance due to conduction, L is the distance over which heat is transferred, k is the thermal conductivity of the material, and A is the cross-sectional area through which heat flows.

For convection:

Rc = 1 / (h * A)

where Rc is the thermal resistance due to convection, h is the heat transfer coefficient for the fluid, and A is the surface area of the object.

For radiation:

Rc = 1 / (ε * σ * A * (T1^2 + T2^2) * (T1 + T2))

where Rc is the thermal resistance due to radiation, ε is the emissivity of the object, σ is the Stefan-Boltzmann constant, A is the surface area of the object, T1 and T2 are the temperatures of the object and the surrounding environment, respectively.

Once the thermal resistances for each mechanism of heat transfer have been calculated, the controlling resistance can be determined by identifying the highest value among them. The mechanism with the highest thermal resistance is the limiting factor that controls the overall rate of heat transfer in the system.

The heat transfer resistance control can be found with the following equation: R = L / (kA).

To find the controling resistnace to heat transfer, you must first understand what these terms mean.

Controling resistnace, also known as thermal resistance, is a measure of how difficult it is for heat to flow through a material. The higher the thermal resistance, the more difficult it is for heat to transfer.

Heat transfer, on the other hand, is the process of heat moving from one object or substance to another due to a difference in temperature. There are three main types of heat transfer: conduction, convection, and radiation.

To find the controling resistnace to heat transfer, you must consider the material's thermal conductivity, thickness, and surface area. The thermal resistance can be calculated using the equation R = L / (kA), where R is the thermal resistance, L is the thickness of the material, k is the thermal conductivity, and A is the surface area.

By understanding the factors that contribute to controling resistnace and using the equation above, you can find the controling resistnace to heat transfer for a given material.

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Answer:

true

Explanation:

Magnitude of average acceleration  \(a_{avg}\)=2.75 units

Average acceleration \(a_{avg}=\) \(2.265 i- 1.58j\)

We're given that \(s=\frac{t^2}{4}\)

And partice is at A at t=2 s and at B at t= 2.2s

Instantaneous velocity \(\frac{ds}{dt} =\frac{t}{2}\)

Velocity at A  (\(V_{a}\)) at 2s = \(\frac{t}{2}\) or  \(\frac{t}{2}Cos \frac{\pi}{3} i+ \frac{t}{2}Sin \frac{\pi}{3}j=\frac{i+\sqrt{3} j}{2}\)

Velocity at B  (\(V_{b}\)) at 2.2s =\(\frac{t}{2}\) or \(\frac{t}{2}Cos \frac{\pi}{6} i+ \frac{t}{2}Sin \frac{\pi}{6}j=\frac{\sqrt{3}i+j }{2}\)

Average acceleration = \(\frac{V_{b}-V{a}}{t}\) =\(2.265 i- 1.58j\)

magnitude = \(\sqrt{(2.265)^2- (1.58)^2}\) = \(2.75\)

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Actions violated:

Actions to be taken:

Edit: Use these to write your paragraph.

Answer:

The thickness of the oil reservoir is 10cm, the production rate of oil is 100m3, the well radius is 10cm, the permeability of the reservoir is 1um2, the porosity is 0.2, the viscosity of the oil is 4mPa.s, the density of oil is 850kg/m3. If the flow regime can be considered as linear flow, can this flow in the reservoir satisfy Darcy's