rewrite this expression
\( \sqrt[5]{x} \)
​

Answer:

y = 31,x= 148

Step-by-step explanation:

the explanation is in the image

that's all....have fun

Answer:

5

Step-by-step explanation:

The greatest number of large pizzas that can be made with the leftover dough is 93.

To determine the greatest number of large pizzas that can be made after lunch with the leftover dough, we first need to calculate the total amount of dough used during lunch.

For small pizzas:

The shop makes 33 small pizzas, and each requires 4 ounces of dough.

Total dough used for small pizzas = 33 pizzas × 4 ounces/pizza = 132 ounces.

For large pizzas:

The shop makes 14 large pizzas, and each requires 4 ounces of dough.

Total dough used for large pizzas = 14 pizzas × 4 ounces/pizza = 56 ounces.

Now, let's calculate the total dough used during lunch:

Total dough used = Total dough used for small pizzas + Total dough used for large pizzas

Total dough used = 132 ounces + 56 ounces = 188 ounces.

Since there are 16 ounces in a pound, we can convert the total dough used to pounds:

Total dough used in pounds = 188 ounces / 16 ounces/pound = 11.75 pounds.

Therefore, the total amount of dough used during lunch is 11.75 pounds.

To find the leftover dough after lunch, we subtract the amount used from the initial amount of dough:

Leftover dough = Initial dough - Total dough used during lunch

Leftover dough = 35 pounds - 11.75 pounds = 23.25 pounds.

Now, we can calculate the maximum number of large pizzas that can be made with the leftover dough:

Number of large pizzas = Leftover dough / Amount of dough per large pizza

Number of large pizzas = 23.25 pounds / 4 ounces/pizza

Number of large pizzas = (23.25 pounds) / (1/4) pounds/pizza

Number of large pizzas = 23.25 pounds × 4 pizzas/pound

Number of large pizzas = 93 pizzas.

Therefore, the greatest number of large pizzas that can be made with the leftover dough is 93.

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The volume of the solid generated by revolving the region between y=2sin(x) and the x-axis for 6 ≤ x ≤ 5π/6 about the y-axis is 2π (6sin(6) - 5√3) cubic units.

To find the volume of the solid generated by revolving the region between y=2sin(x) and the x-axis for 6 ≤ x ≤ 5π/6 about the y-axis, we use the method of cylindrical shells.

The formula for the volume of the solid generated by revolving the region between y=f(x) and the x-axis for a ≤ x ≤ b about the y-axis is given by:

V = 2π ∫[a,b] x f(x) dx

In this case, f(x) = 2sin(x) and the interval is 6 ≤ x ≤ 5π/6, so we have:

V = 2π ∫[6,5π/6] x (2sin(x)) dx

Using integration by parts, we obtain:

V = -2π [x cos(x)]6^5π/6 + 2π ∫[6,5π/6] cos(x) dx

V = 2π [x sin(x)]6^5π/6 - 2π sin(5π/6) + 2π sin(6)

Simplifying the expression, we get:

V = 2π (6sin(6) - 5√3)

Therefore, the volume of the solid generated by revolving the region between y=2sin(x) and the x-axis for 6 ≤ x ≤ 5π/6 about the y-axis is 2π (6sin(6) - 5√3) cubic units.

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There are 144 possible sequences of chip colors.

We can solve this problem by counting the number of possible sequences of chip colors that can be drawn from the bag until the total value of the chips is at least $7.

Let's consider all the possible sequences of chips that can be drawn from the bag. The first chip can be any of the 6 chips in the bag. For each chip color, there are different scenarios that can happen after drawing the first chip:

Therefore, the total number of possible sequences of chip colors that can be drawn from the bag until the total value of the chips is at least $7 is: 2 x 32 + 1 x 32 + 3 x 16 = 144

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Answer:

Since the Independent variable is something that is modified or controlled in a scientific experiment, it is his age.

Answer:

10 please mark brainliest if satisfied

Step-by-step explanation:

When Dividing fractions, use the reciprocal of 3/4

7 1/2 times 4/3 equals

10

Answer:

10

Step-by-step explanation:

You would do something called KCF Keep, Change, and Flip.

You would keep the 7 1/2 and change the divided sign to multiplying sign and flip the 3/4 so its a 4/3 and then multiply it.

15/6 times 4/3. 15 x 4 = 60

                           2x3=   6

so I can be 60/6 but you would simplify and 6 goes into 60  10 times. so 10 is you answer

The exact value  of \(sin 2x\) is \(4√5/9.\)

Given that \(sec x = 3/2 and csc y = 3\)where x and y are in the 2x = 2 sin x quadrant, we need to find the exact value of sin 2x.

In the first quadrant, we have the following values of the trigonometric ratios:\(cos x = 2/3 and sin y = 3/5\)

Also, we know that sin \(2x = 2 sin x cos x.\)

Now, we need to find sin x.

Having sec x = 3/2, we can use the Pythagorean identity

\(^2x + 1 = sec^2xtan^2x + 1 = (3/2)^2tan^2x + 1 = 9/4tan^2x = 9/4 - 1 = 5/4tan x = ± √(5/4) = ± √5/2\)

As x is in the first quadrant, it lies between 0° and 90°.

Therefore, x cannot be negative.

Hence ,\(tan x = √5/2sin x = tan x cos x = √5/2 * 2/3 = √5/3\)

Now, we can find sin 2x by using the value of sin x and cos x derived above sin \(2x = 2 sin x cos xsin 2x = 2 (√5/3) (2/3)sin 2x = 4√5/9\)

Therefore, the exact value  of sin 2x is 4√5/9.

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The decimal approximation for cot(235°36') is approximately -0.9503.

To find the decimal approximation for cot(235°36'), we first need to convert the angle to degrees.

The given angle is 235°36'. We can convert this to decimal degrees by adding the fraction of minutes to the degree value. There are 60 minutes in a degree, so we divide 36 by 60 to convert it to a fraction of a degree:

36 / 60 = 0.6 degrees

Now, we can add this fraction to the degree value:

235 + 0.6 = 235.6 degrees

The cotangent function is the reciprocal of the tangent function. To find the cotangent of an angle, we can use the following formula:

cot(x) = 1 / tan(x)

Since we want to find cot(235.6°), we can find tan(235.6°) first and then take the reciprocal.

Using a scientific calculator or software, we can find

tan(235.6°) ≈ -1.0529

Now, we can take the reciprocal to find cot(235.6°):

cot(235.6°) ≈ 1 / (-1.0529) ≈ -0.9503

Therefore, the decimal approximation for cot(235°36') is approximately -0.9503.

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As per the question, All four students A, B, C, and D are loss-averse over money and have the same value function as below:v(x dollars)={√x     x ≥ 0   {-2√-x  x < 0They are also loss averse over mugs and have the same value function.

v(y mugs)={3y y ≥ 0
        {4y y < 0
Now, we have to find the values of a, b, c and d as below:
- Student A owns a mug and is willing to sell it for a price of a dollars or more. i.e v(a) = v(0) + v(a-A), where A is the initial endowment of A. According to the given function, v(0) = 0, v(a-A) = 3, and v(A) = 4.
So, a ≥ A+3/2
- Student B does not own a mug and is willing to pay up to b dollars for buying it. i.e v(B-b) = v(B) - v(0), where B is the initial endowment of B. According to the given function, v(0) = 0, v(B-b) = -4, and v(B) = -3.
So, b ≤ B+1/2
- Student C does not own a mug and is indifferent between getting a mug and getting c dollars. i.e v(c) = v(0) + v(c), where C is the initial endowment of C. According to the given function, v(0) = 0, v(c) = 3.
So, c = C/2
- Student D is indifferent between losing a mug and losing d dollars. i.e v(D-d) = v(D) - v(0), where D is the initial endowment of D. According to the given function, v(0) = 0, v(D-d) = -3.
So, d = D/2
2) In this case, value function for money changes to:v(x dollars)={√x     x ≥ 0
            {-√-x   x < 0
However, the value function for mugs remains the same:v(y mugs)={3y y ≥ 0
         {4y y < 0
Therefore, values for a, b, c, and d will remain the same as calculated in part (1).
3) In this case, students are not loss-averse. Value function for money:v(x dollars)={√x     x ≥ 0
            {-√-x   x < 0
Value function for mugs:v(y mugs)={3y y ≥ 0
The reference point is the status quo, i.e initial endowment. So,
- Student A owns a mug and is willing to sell it for a price of a dollars or more. The value of mug for A is 3 initially and he would sell it for 3 or more.
So, a ≥ A+3/2
- Student B does not own a mug and is willing to pay up to b dollars for buying it. The value of mug for B is 3 initially and he would buy it for 3 or less.
So, b ≤ B+3/2
- Student C does not own a mug and is indifferent between getting a mug and getting c dollars. The value of the mug for C is 3 initially.
So, c = 3
- Student D is indifferent between losing a mug and losing d dollars. The value of the mug for D is 3 initially.
So, d = 3
4) In this case, value function for money:v(x dollars)={√x     x ≥ 0
            {-√-x   x < 0
Value function for mugs: Mug will have a value of 4 for someone who owns it and 3 for someone who does not own it.
The reference point is the status quo, i.e initial endowment. So,
- Student A owns a mug and is willing to sell it for a price of a dollars or more. The value of mug for A is 4 initially and he would sell it for 4 or more.
So, a ≥ A+2
- Student B does not own a mug and is willing to pay up to b dollars for buying it. The value of mug for B is 3 initially and he would buy it for 3 or less.
So, b ≤ B+3/2
- Student C does not own a mug and is indifferent between getting a mug and getting c dollars. The value of the mug for C is 3 initially and he would like to buy it for 3.
So, c = 3
- Student D is indifferent between losing a mug and losing d dollars. The value of the mug for D is 3 initially.
So, d = 3.

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According to the information, the 95% confidence interval for the proportion of Americans who drink tea daily is approximately (0.2485, 0.2766). The margin of error is approximately 0.0140.

To construct a confidence interval for the proportion of Americans who drink tea daily, we can use the formula:

Where,

p = the sample proportion

Z = the critical value corresponding to the desired confidence level

n = the sample size

Given:

Now, let's calculate the confidence interval and margin of error:

According to the information, the 95% confidence interval for the proportion of Americans who drink tea daily is approximately (0.2485, 0.2766), with a margin of error of approximately 0.0140.

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Answer:

length=9

width=4m

Step-by-step explanation:

Let the width of the rectangle be, x and the length be, x+5

perimeter=2(L+W)

26 m=2(x+5+x)

26=2x+10+2

26-10=4x

16=4x

x=

length=9m

width=4m

An example of a nonlinear equation that is not solvable and has y = x² as one of its solutions is:

\(y = x^2 + e^y\)

This equation combines a quadratic term (x²) with an exponential term (\(e^y\)). While y = x² satisfies the equation, it is not possible to find a general solution for y in terms of x that satisfies the entire equation.

Solving this equation analytically becomes challenging due to the presence of the exponential term, which makes it a non-solvable equation.

An example of a Riccati equation that has \(y_1 = e^x\) as one of its solutions is:

y' = x² - y²

In a Riccati equation, y' represents the derivative of y with respect to x. By substituting \(y_1 = e^x\) into the equation, we can verify that it satisfies the equation:

\((e^x)' = x^2 - (e^x)^2\)

\(e^x = x^2 - e^2x\)

Since \(y_1 = e^x\) satisfies the Riccati equation, it can be considered as one of its solutions.

However, Riccati equations often have multiple solutions and may require specific initial or boundary conditions to determine a unique solution.

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Answer:

The slope is the same since they are parallel. The only thing that should be different is the 8 at the end should be any other number.

Step-by-step explanation:

Answer:

y = 3x + 3

Step-by-step explanation:

As x increases, y increases by 3. Therefore, the slope of the function is 3.

Setting x = 0 will give an output of 3. Therefore, the y-intercept is (0, 3).

Overall, the function rule for the given data set is y = 3x + 3.

Answer:

I believe it would be C if not then im sorry

Step-by-step explanation:

The chi-square test is useful for determining if a nonmonotonic relationship exists between two nominal-scaled variables. the correct answer is if a nonmonotonic relationship exists between two nominal-scaled variables.

The chi-square test determines whether there is a connection or relationship between two things or labels (known as nominal-scaled variables), such as gender or color. When there is no clear trend or pattern in the relationship between the two variables, it is used.

The test compares the actual number of observations in each category to the given number of observations, thinking that the variables have no relationship. If the actual number of observations is not same as what would be expected by chance, the variables may have a significant relationship.

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Answer:

\(a_n=4n-11\)

Step-by-step explanation:

The common difference is \(d=4\) with the first term being \(a_1=-7\), so we can generate an explicit formula for this arithmetic sequence:

\(a_n=a_1+(n-1)d\\a_n=-7+(n-1)(4)\\a_n=-7+4n-4\\a_n=4n-11\)

Answer:

2

Step-by-step explanation:

2

Answer:

There are 200 animals, and the cost is $8,000 daily

Step-by-step explanation:

y=f(x) represents the cost in thousands

x is the number of animals measured in hundreds

so the point (2,8) means

x = 2

y = f(2) = 8

so it means  for 2*100=200 animals, the cost is 8*1000=8 000

The correct answer is then

There are 200 animals, and the cost is $8,000 daily

hope this helps

The function represented in the table is:

y = 6*cos(x) + 4

Evaluationg this in x = 45 we will get:

y = 3√2 + 4

Here we have the table of the function:

y = a*cos(x) + b

We can see that when x = 0, y = 10, then:

10 = a*cos(0) + b

10  = a + b

And when x = 90, y = 4, then:

4 = a*cos(90) + b

4 = b

Replacing that value in the equation above:

10 = a + 4

10 - 4 = a

6 = a

Then the function is:

y = 6*cos(x) + 4

Evaluating this in x = 45 we will get:

y = 6*cos(45) + 4

y = 6*√2/2 + 4

y = 3√2 + 4

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Answer:

16.43

Step-by-step explanation:

gib brainlest or else:0

Answer: 6b + 10

Step-by-step explanation:

So the equation is b + 5b + 10. Add like terms and it is 6b + 10. We don't know what b is so we can't simplify it any further.

The volume of the truncated cone is approximately 70,336 ft3.

option B.

The volume of the truncated cone is calculated by using the following formula as shown below;

V = ¹/₃πh (R² + r² + Rr)

where;

The volume of the truncated cone is calculated as follows;

V = ¹/₃π(24) (40² + 20² + 40 x 20)

V = 70,371.7 ft³

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Answer:

Rise it to 2

( x ^2 ) ^2 − 9 ^2 = 0

Step-by-step explanation:

Answer:

The place value of 5 in 4.053 is Hundredth

The place value of 5 in the given number 4.053 is, hundredths

In mathematics, we have assigned a name for each digit in a number, which are known as place values. Place values are Ones, Tens, Hundreds, Thousands.

Given number,

⇒  4.053

we can write it as,

⇒   4 ≡ at ones

⇒   0 ≡ at tenths

⇒   5 ≡ at hundredths

⇒   3 ≡ at  thousandths

So, the place value of 5 is hundredths

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The feasible set for this system of constraints is not convex, and the points (5, 5) and (3, 7) violate the convexity definition.

To determine whether the feasible set for each system of constraints is convex, we need to analyze the constraints individually and examine their intersection.

a) (x1)² + (x2)² > 9

This constraint represents points outside the circle with a radius of √9 = 3. The feasible set includes all points outside this circle.

b) x1 + x2 ≤ 10

This constraint represents points that lie on or below the line x1 + x2 = 10. The feasible set includes all points on or below this line.

c) x1, x2 > 0

This constraint represents points in the positive quadrant, where both x1 and x2 are greater than zero.

Now, let's analyze the intersection of these constraints:

Considering the first two constraints (a and b), we can see that the feasible set consists of all points outside the circle (constraint a) and below or on the line x1 + x2 = 10 (constraint b).

To determine whether the feasible set is convex, we need to check if any two points within the set create a line segment that lies entirely within the set.

If we consider the points (5, 5) and (3, 7), both points satisfy the individual constraints (a) and (b). However, the line segment connecting these two points, which is the line segment between (5, 5) and (3, 7), exits the feasible set since it passes through the circle (constraint a) and above the line x1 + x2 = 10 (constraint b).

Therefore, the feasible set for this system of constraints is not convex, and the points (5, 5) and (3, 7) violate the convexity definition.

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The unit rate of the beef if it cost $14.40 for 4.5 pounds of beef is $3.2 per pound

The unit rate is the cost of each unit of an item at a particular time.

Cost of 4.5 pounds of beef = $14.40

Unit rate of beef = Total cost / Total pounds

= $14.40 / 4.5

= $3.2 per pound

Check:

Cost of 4.5 pounds of beef = unit cost of beef × pounds of beef

= $3.2 × 4.5

= $14.4

In conclusion, the unit rate of beef is given as $3.2 per pound.

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