Select the number in each drop down list that will create a list in descending order. (greatest to least)

12.33
12.034
12.003
12.301

prime between number of 1234 to 1352​ are 1237, 1249,  1259, 1277, 1279, 1283, 1289, 1291, 1297, 1301, 1303, 1307, 1319, 1321, 1327

Answer:

Answer:17 (I think)

Because if you look at the problem below Y u can see the patter 5+3=8 8+3=11 contiously adding 3 you get 17

The correct responses for the analytical geometry questions are;

Reasons:

1. The length of the sides of the rectangle are;

Width = √(4² + 2²) = 2·√5

Length = √(10² + 5²) = 5·√5

Area = Length × Width

∴ Area = 5·√5 × 2·√5 = 50

Area = 50 units²

2. Width = √((-2 - (-2))² + (-5 - 1)²) = 6

Length = √((4 - (-2))² + (3 - 1)²) = 2·√10

∴ Area = 2·√10 × 6 = 12·√10

The area of the rectangle = 12·√10 unit²

3. The lengths of the sides of the polygon are;

Side 1 = √(1² + 2²) = √5

Side 2 = √(2² + 2²) = 2·√2

Side 3 = √(3² + 1²) = √10

Side 4 = 3

Side 5 = 4

The perimeter = √5 + 2·√2 + √10 + 3 + 4 ≈ 15.2 units

5. The slope of ║ lines are equal,  the slope of the line ║ to the line whose slope is \(-\dfrac{3}{4}\), is also

The ║ line is \(line \ q \ with \ slope \ -\dfrac{3}{4}\).

The slope of a line ⊥ to another line that has a slope of m is \(-\dfrac{1}{m}\)

Slope of the ⊥ line is \(-\dfrac{1}{-\dfrac{3}{4}} =\dfrac{4}{3}\), which is  \(line \ n \ with \ slope \ \dfrac{4}{3}\)

Neither are;

\(Line \ m \ with \ slope \ \dfrac{3}{4}\) and \(line \ p \ with \ slope \ -\dfrac{4}{3}\)

6. The equation of line m is 4·x + 5·y = -2

Slope of the line m, is \(-\dfrac{4}{5}\)

Slope of the ⊥ line is \(\dfrac{5}{4}\)

7. Equation of line is -x + 3·y = 6

Point through which the line passes is (3, 5)

Slope of the line is \(\dfrac{1}{3}\)

Slope of the ║ line is \(\dfrac{1}{3}\)

The equation of the ║ line is \(y - 5 = \dfrac{1}{3} \cdot (x - 3)\)

Which gives;

3·y - 15 = x - 3

3·y - x = -3 + 15 = 12

The equation of the ║ line is; 3·y - x = 12

8. Equation of line is -x + 2·y = 4

Point ⊥ line passes = (-2, 1)

Slope is \(\dfrac{1}{2}\)

Slope of the ⊥ line is -2

Which gives; (y - 1) = -2·(x - (-2))

(y - 1) = -2·x - 4 + 1

The equation of the ⊥ line is; y + 2·x = -3

9.  \(Slope, \ of \ \overline{AB} \, =\dfrac{1-4}{-1-(-2)} = -3\)

Slope of BC is \(\dfrac{1}{3}\)

At C(2, 2), we have;

\(Slope, \ of \ \overline{BC} \, =\dfrac{1-2}{-1-2} = \dfrac{1}{3}\)

At C(0, 4), we have;

\(Slope, \ of \ \overline{BC} \, =\dfrac{4-1}{0-(-1)} =3\)

Therefore;

At C(-2, 1), we have;

\(Slope, \ of \ \overline{BC} \, =\dfrac{1-1}{-2-(-1)} =0\)

However, we have;

\(Slope, \ of \ \overline{AC} \, =\dfrac{1-(-2)}{-2-(-2)} = \infty\)

Therefore \(\overline{BC}\) ⊥ \(\overline{AC}\).

10. Given quadrilateral ABCD;

\(Slope, \ of \ \overline{AB} \, =\dfrac{3 -(-1)}{-3-(-1)} = -2\)

\(Slope, \ of \ \overline{BC} \, =\dfrac{3 -5}{-3-1} = \dfrac{1}{2}\)

\(Slope, \ of \ \overline{CD} \, =\dfrac{2 -5}{5-1} = -\dfrac{3}{4}\)

\(Slope, \ of \ \overline{AD} \, =\dfrac{2 -(-1)}{5-(-1)} = \dfrac{1}{2}\)

Sides  \(\overline{BC}\) ║ \(\overline{AD}\), sides  \(\overline{AB}\) ∦ \(\overline{CD}\), sides  

∴ ABCD is a right trapezoid.

Which gives;

The slope of \(\overline{AB}\) is -2, the slope of \(\overline{BC}\) is \(\underline{\frac{1}{2}}\), the slope of \(\overline{CD}\) is \(\underline{-\frac{3}{4}}\), the

slope of \(\overline{AD}\) is \(\underline{\frac{1}{2}}\). Quadrilateral ABCD is a trapezoid because only one pair

of opposite sides is ║.

11. Shorter side = a

∴ Longer side = 3·a (║to the x-axis)

Top right corner is \(\underline {(3\cdot a, \, a)}\).

12. The coordinates of the point C is (a, b)

According to Pythagoras's theorem, we have;

\(\overline{AC}\) = √(a² + b²)

\(\overline{BD}\) = √(b² + a²)

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The work done by the gradient of ƒ(x, y) = \((x y)^{2}\) counterclockwise around the circle  \(x^{2} y^{2}\)  = 4 from (2, 0) to itself is zero.

To find the work done by the gradient of ƒ(x, y),

evaluate the line integral ∮C ∇ƒ(x, y) · dr, where C is the circle  \(x^{2} y^{2}\) = 4 traversed counterclockwise from (2, 0) to itself.

Since ƒ(x, y) = (x y) 2, we have ∇ƒ(x, y) = (2x y, 2xy), and

∇ƒ(x, y) · dr = 2x y dx + 2xy dy.

Parameterizing the circle as x = 2 cos(t) and y = 2 sin(t) for 0 ≤ t ≤ 2π, we get dr = (-2 sin(t) dt, 2 cos(t) dt), and so ∇ƒ(x, y) · dr = -8 sin(t) cos(t) dt. Integrating this expression over 0 ≤ t ≤ 2π,

∮C ∇ƒ(x, y) · dr = 0, since sin(t) cos(t) is an odd function.

Therefore, the work done by the gradient of ƒ(x, y) counterclockwise around the circle x2 y2 = 4 from (2, 0) to itself is zero.

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The general solution of the system is: x = x (free parameter), y = (7/2)x, and z = -(3/2)x. This represents the set of all solutions to the system of equations.

To find the general solution of the system represented by the augmented matrix, we can perform row operations to bring the matrix to its reduced row-echelon form (RREF). The RREF will reveal the solution of the system.

Let's work through the row operations step by step:

Row 2 = Row 2 - 2 × Row 1

Row 3 = Row 3 - 4 × Row 1

The new augmented matrix after the first row operation:

[ 2 -7 3 0 ]

[ 0 0 0 0 ]

[ 0 0 0 0 ]

Next, divide Row 1 by 2:

Row 1 = Row 1 / 2

The updated augmented matrix:

[ 1 -7/2 3/2 0 ]

[ 0 0 0 0 ]

[ 0 0 0 0 ]

Now, we can see that the second and third rows consist of all zeros. This indicates that the system has infinitely many solutions.

To express the general solution, we can assign a parameter to one of the variables (let's choose x):

x = Free parameter

Then, we can express the other variables in terms of x:

y = (7/2)x

z = - (3/2)x

Therefore, the general solution of the system is:

x = x (free parameter)

y = (7/2)x

z = -(3/2)x

This represents the set of all solutions to the system of equations. By assigning different values to the parameter x, we can obtain infinitely many solutions.

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By using the definition of continuity and exploiting the fact that f(0) = 1, we were able to prove the existence of an open interval (a, b) containing 0 such that for any real number r within this interval, the function value f(r) is greater than 0.

First, let's recall the definition of continuity at a point. A function f is continuous at a point c if, for any positive number ε, there exists a positive number δ such that whenever x is within δ of c, the value of f(x) will be within ε of f(c).

Now, since f is continuous at 0, we can say that for any positive ε, there exists a positive δ such that if |x - 0| < δ, then |f(x) - f(0)| < ε.

Since f(0) = 1, the above inequality simplifies to |f(x) - 1| < ε.

We want to find an open interval (a, b) containing 0 such that for any r within this interval, f(r) > 0. Let's consider ε = 1 as an arbitrary positive number.

From the definition of continuity at 0, we can find a positive δ such that if |x - 0| < δ, then |f(x) - 1| < 1. This implies -1 < f(x) - 1 < 1, which further simplifies to 0 < f(x) < 2.

Now, consider the interval (a, b) = (-δ, δ). Since δ is positive, it ensures that 0 is within this interval. Also, since f(x) is continuous on this interval, we can conclude that f(r) > 0 for all r within (-δ, δ).

To prove this, let's take any r within (-δ, δ). Since r is within this interval, we have -δ < r < δ, which implies |r - 0| < δ. By the definition of continuity at 0, we know that |f(r) - 1| < 1. Therefore, 0 < f(r) < 2, and we can conclude that f(r) > 0.

Hence, we have shown that there exists an open interval (a, b) containing 0 such that for all r within this interval, f(r) > 0.

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The synthesised Fourier analysis provides a mathematical decomposition of the signal into sinusoidal components, allowing for a precise representation of the signal's frequency content,    

(a) The periodic signal p(t) exhibits symmetry about the vertical line passing through the point (3, 5). This symmetry impacts its Fourier analysis by resulting in a Fourier series representation consisting only of cosine terms, as even functions can be represented solely by cosine terms.

(b) Using Fourier synthesis, the coefficients can be determined. The constant term, ao, is obtained by finding the average value of p(t) over one period. The coefficients an and bn are determined by integrating the product of p(t) and the corresponding cosine and sine functions over one period, respectively. This may involve tabular integration or integration by parts.

(c) The p(t) expression provides a concise representation capturing the essential characteristics of the periodic signal. The synthesized Fourier analysis, on the other hand, offers a detailed breakdown of the signal into sinusoidal components, beneficial for signal processing applications like filtering and frequency analysis.

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A life table provides data on the number of living individuals in a particular age class. Age classes are often represented by a time period of 12 month(s).

A life table delivers data on the number of living individuals in a particular age class. Age classes are often represented by a time period of 1 year.

This means that the data in the life table will reflect the number of individuals who are alive in a specific age group, such as 0-1 year, 1-2 years, 2-3 years, and so on. The data in a life table is used to study mortality patterns, life expectancy, and other demographic measures.

By grouping the data into age classes of 1 year, the life table provides a snapshot of the population at different stages of life, making it easier to analyze trends and patterns in the data.

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--The given question is incomplete; the complete question is

"A life table provides data on the number of living individuals in a particular age class. Age classes are often represented by a time period of ______ month(s)."--

a) The campaign manager has a random sample of potential voters in a large city and records the number of individuals within each of the categories.

b) A Chi-Square goodness of fit test.

a) A campaign manager would like to show that the distribution of individuals within several social economic categories is different than what a newspaper reported and that's why we know that the campaign manager has a random sample of potential voters in a large city and records the number of individuals within each of the categories.

Chi-Square goodness of fit is used to find out how the observed value of a given phenomenon is significantly different from the expected value. In Chi-Square goodness of fit test, the sample data is divided into intervals.

In this case, we have one categorical variable which is the distribution of individuals within several social groups. We want to see if the actual distribution of the variable is significantly different from the distribution within several social groups as claimed(expected) by the newspaper.

Hence, we will use chi-square goodness of fit test for this case.

b) A Chi-Square goodness of fit test.

Here the variable is the distribution of individuals purchasing season pass at an amusement park. The variable has 4 categories based on the age group of the individuals.

A tourist company wants to test the actual distribution of individuals within each age group and wants to check if it is significantly different from the expected distribution i.e the one claimed by the amusement park.

The tourist company randomly sampled 200 individuals entering the park.

The proportion of individuals within each group as claimed by the amusement park is given.

Hence, we will use chi-square goodness of fit test to test if the actual distribution within each group is significantly different or not from the claimed distribution.

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Answer:

Step-by-step explanation:

We know that:

Solution:

Since the slope of the line is un-defined, the line is vertical. Please look at my graph to understand better.

Answer:

9

Step-by-step explanation:

;)

Answer:

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Step-by-step explanation:

Answer:

Hypotenuse is the longest slanting side

Step-by-step explanation:

Without an angle to consider, the other two could fit in any position

Refer to the attachment

The measures of the other three angles of the isosceles trapezoid are: 53°, 127°, 127°.

This is a trapezoid in which the base angles are equal and therefore the left and right side lengths are also equal. The opposite angles are supplementary which implies they sum up to 180°.

Since of the angles is 53°, then it's opposite angle is derived to be:

180° - 53° = 127°

so we can have the base angles as 53° and 53° while the other angles are 127° and 127°.

Therefore, the measures of the other three angles of the isosceles trapezoid are: 53°, 127°, 127°.

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Conceptually, the arithmetic and geometric average returns are different measures used to describe the performance of an investment or an asset over a specific period.

The arithmetic average return, also known as the mean return, is calculated by adding up all the individual returns and dividing by the number of periods. It represents the average return for each period independently.

On the other hand, the geometric average return, also called the compound annual growth rate (CAGR), considers the compounding effect of returns over time. It is calculated by taking the nth root of the total cumulative return, where n is the number of periods.

When to use each measure depends on the context and purpose of the analysis:

1. Arithmetic Average Return: This measure is typically used when you want to evaluate the average return for each individual period in isolation. It is useful for analyzing short-term returns, such as monthly or quarterly returns. The arithmetic average return provides a simple and straightforward way to assess the periodic performance of an investment.

2. Geometric Average Return: This measure is more suitable when you want to understand the compounded growth of an investment over an extended period. It is commonly used for long-term investment horizons, such as annual returns over multiple years.

The geometric average return provides a more accurate representation of the overall growth rate, accounting for the compounding effect and reinvestment of returns.

In summary, the arithmetic average return is suitable for analyzing short-term performance, while the geometric average return is preferred  evaluating long-term growth and the compounding effect of returns.

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The cost of laptop and cost of desktop are; $1,800 and $2,100 respectively.

A mathematical operation is a function that converts a set of zero or more input values (also called "b" or "arguments") into a defined output value.

From the question , we are given that the laptop costs $350 more than the desktop, therefore,

let x represent the cost of the laptop thus, x-350 will be the cost of the desktop .

The total finance charge of $388 is equal to 8% of the cost of the laptop and 7.5% of the cost of the desktop, we solve as;

388 = 0.08(x) + 0.075(x - 350)

252 = 0.08x + 0.075x - 26.25

278.75 = 0.155x

x = 278.75/0.155

x = 1798

Recall that the cost of desktop = x -350

therefore:

1,798- 350 = 1448

The cost of laptop = $1798

The cost of desktop = $1448

Thus, the cost of laptop and cost of desktop are; $1,800 and $2,100 respectively.

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Answer:

x=128

Step-by-step explanation:

Answer:128

Step-by-step explanation:

The angles in a trapezoid add up to 360, so if you add all the ones already given then subtract them from 360 you get 128.

Answer:

B

Step-by-step explanation:

AB=6 therefore Pto Q should be 6

6^2=36

8^2=64

add them together

=100

square root 100=10

divide by 2=5

The complete question is :

What statistical tests and analysis can be conducted to determine whether there is a significant association between being banded and penguin survival rates, given a dataset with information on the number of banded and non-banded penguins that survived and did not survive?

                                   Banded           Not Banded

Survived                  75                          100

Did Not Survive         25                          50

To determine if there is a significant association, statistical tests such as chi-squared test or Fisher's exact test can be used, to compare the observed proportions of survival and non-survival in banded and non-banded penguins to the expected proportions under the assumption of no association.

To answer the question of whether there is an association between being banded and survival rate, we can calculate the proportions of penguins that survived or did not survive in each group:

                                     Banded                           Not Banded

Survived                         0.75                                0.67

Did Not Survive         0.25                                0.33

From this table, it seems that a higher proportion of banded penguins survived compared to non-banded penguins. However, we cannot conclude that there is a definite association between being banded and survival rate based on this limited data. To make more definitive conclusions, we would need to conduct statistical tests and analysis.

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Answer:

He did not simplify correctly and forgot to place the decimal point correctly.

Step-by-step explanation:

To simplify the equation, one needs to divide both sides of the equal sign by 5.

i.e 5.25/5=5/5

Here we find 1.05=1

Note the placement of the decimal point.

A p-chart is used to monitor the fraction defective.

A p-chart is a type of control chart used to monitor the proportion of nonconforming units in a sample. It is used when the sample size is constant and the process is in statistical control.

It plots the proportion of nonconforming units in each sample on the y-axis and the sample number on the x-axis.

The chart can be used to detect changes in the process and to determine if the process is in control. It can also be used to estimate the process capability and to identify the causes of nonconformities.

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Answer:

first option

Step-by-step explanation:

I'm not really sure myself but I think the first option is the best option to choose because the others aren't really that true and if you look the angle c is much bigger than the other angles so I think the first option is more likely

Answer:

12.5 =x

Step-by-step explanation:

15 = 2x – 10

Add 10 to each side

15+10 = 2x – 10+10

25 = 2x

Divide by 2

25/2 = 2x/2

12.5 =x

Answer:

25/2

Step-by-step explanation:

2x-10=15

  +10 +10

2x=25

divide both sides by 2 to get 25/2

Answer:

Answer

4.0/5

58



amna04352

Genius

6.9K answers

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Answer:

x-less than-or-equal-to 3

Step-by-step explanation:

4x + 6 < 18 (less than or equal to)

4x < 12 (less than or equal to) x < 3 (less than or equal to)

Step-by-step explanation:

Step one:

given data

amount deposited=$48

after the purchase of groceries

account balance= $19

cell phone bill, which= $31

Step two:

The account balance after paying for groceries will be

=19-31= $-12

she will have a deficit of $12, hence a negative account balance

To start, Deena had a positive balance. -------True

In this situation, 0 represents an empty bank account. -----True

After paying for groceries, Deena had a negative balance. ---True

After paying her cell phone bill, Deena had –$12 in the account. ...True

The smallest balance in the account was $19. ....True

Answer:

-6/3 or -2

Step-by-step explanation:

The simplified form of the expression -6w + (–8.3) + 1.5+ (–7w) is -13w - 6.8.

Given the expression in the question;

-6w + (–8.3) + 1.5+ (–7w)

To simplify, first remove the parenthesis

Note that;

-6w + × - 8.3 + 1.5 + × - 7w

-6w - 8.3 + 1.5 - 7w

Next collect and add like terms

-6w - 7w - 8.3 + 1.5

Add -6w and -7w

-13w - 8.3 + 1.5

Add -8.3 and 1.5

-13w - 6.8

Therefore, -13w - 6.8 is the simplified form.

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Two possible expressions for the length and the width of the rectangle are:

Remember that for a rectangle of length L and width W, the area is:

A = L*W

Here the area is given by the quadratic equation:

A = x² + 2x - 7x - 14

We can factorize this equation to get:

A = (x + 2)(x - 7)

Then we can define:

length = x + 2

width = x- 7

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