Answers
Given:
The intensity of Solar radiation is,
\(I=700\text{ W/m}^2\)The area of the roof is,
\(A=7.48\text{ m}\times15.16\text{ m}\)The time is,
\(\begin{gathered} t=1.09\text{ hours} \\ =1.09\times3600\text{ s} \end{gathered}\)To find:
The incident solar energy
Explanation:
The incident energy is,
\(\begin{gathered} E=IAt \\ =700\times7.48\times15.16\times1.09\times3600 \\ =311.5\times10^6\text{ J} \end{gathered}\)Hence, the incident energy is
\(311.5\times10^6\text{ J}\)Related Questions
Help me please I don’t understand
Answers
Answer:
a. hydroelectric power plant
What is the index of refraction for a material if the speed of light in that material is 1.862x108 m/s?
Answers
The index of refraction for the material is 1.612.
The index of refraction (n) of a material can be calculated using the formula:
n = c / v
where c is the speed of light in vacuum and v is the speed of light in the material.
Given that the speed of light in the material is 1.862x\(10^8\) m/s, we can substitute the values into the formula:
n = (3.00x\(10^8 m/s) / (1.862x10^8 m/s\))
Simplifying the expression:
n = 1.612
Therefore, the index of refraction for the material is approximately 1.612.
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A rod with a length of L = 1 m is held vertically so that one end rests on the floor. After that
let go of the stick and fall. Let us assume that the supported end does not slip and that the thickness of the bar is very small compared to its length (that is, its moment of inertia with respect to the center of gravity is IT = 1/12mL^2
(a) With what speed does the other end of y hit the floor?
(b) How much does the end impact speed increase if it were a 100 m tall object that was originally
blasted off (and not broken when falling)?
Hint: Use the law of conservation of mechanical energy. Kinetic energy can be written in two ways:
1. Pure rotary movement around the end of the rod. 2. Rotary movement around the center of gravity + movement of the center of gravity. Both procedures,
of course, give the same result (you can try both and see for yourself).
Answers
Explanation:
(a) Let's use the law of conservation of mechanical energy to determine the speed with which the other end of the rod hits the floor. When the rod is released, it begins to rotate around its center of gravity and falls to the floor. At the moment of release, the rod has no kinetic energy or potential energy, but it has potential energy when it reaches the floor. The energy is conserved, so we can equate the initial potential energy to the final kinetic energy.
The initial potential energy of the rod is given by:
U_i = mgh
where m is the mass of the rod, g is the acceleration due to gravity, and h is the height of the center of gravity above the floor. Since the rod is vertical, h = L/2. The mass of the rod can be calculated using its density ρ and cross-sectional area A:
m = ρAL
The final kinetic energy of the rod is given by:
K_f = (1/2)Iω^2 + (1/2)mv^2
where I is the moment of inertia of the rod with respect to its center of gravity, ω is the angular velocity of the rod, and v is the linear velocity of the center of gravity. At the moment when the rod hits the floor, the angular velocity is zero, so the first term in the above equation is zero. We can simplify the equation to:
K_f = (1/2)mv^2
We can equate the initial potential energy and final kinetic energy to get:
mgh = (1/2)mv^2
Solving for v, we get:
v = sqrt(2gh)
Substituting the given values, we get:
v = sqrt(2gL/2) = sqrt(gL/2)
Now, we can substitute the values of g and L to get:
v = sqrt(9.81 m/s^2 x 1 m/2) = sqrt(4.905) m/s
Therefore, the other end of the rod hits the floor with a speed of approximately 2.216 m/s.
(b) If the length of the rod were 100 m instead of 1 m, the speed with which the end hits the floor would increase significantly. The potential energy of the rod when it is released is proportional to its height above the floor, so when the length of the rod is increased by a factor of 100, the potential energy increases by a factor of 100 as well. Therefore, the final speed of the end hitting the floor would be:
v' = sqrt(2gh') = sqrt(2g(100L)/2) = sqrt(100gL/2) = 10sqrt(gL/2)
Substituting the given values, we get:
v' = 10sqrt(9.81 m/s^2 x 100 m/2) = 10sqrt(490.5) m/s
Therefore, the end of the 100 m tall object would hit the floor with a speed of approximately 70.0 m/s, which is a significant increase compared to the initial speed of the 1 m rod.
An object accelerates 12.0 m/s2 when a force of 6.0 newtons is applied to it. What is the mass of the object?
Answers
Answer:
0.5 kgExplanation:
The mass of the object can be found by using the formula
\(m = \frac{f}{a} \\ \)
f is the force
a is the acceleration
From the question we have
\(m = \frac{6}{12} = \frac{1}{2} \\ \)
We have the final answer as
0.5 kgHope this helps you
The __ clause of the ___ amendment states that a person born in the United States is a us citizen.
Answers
A person born in the United States is considered a citizen of the country, according to the 14th Amendment's "Citizenship" provision.
Citizens of both the United States and the State in which they live include everyone who was born or naturalised in the country and is subject to its laws. No State may enact or carry out any legislation that restricts the rights or privileges of US citizens; no State may rob anyone of their life, liberty, or property without first providing them with a fair trial; and no State shall deny anyone living under its jurisdiction the equal protection of the law.
Based on the first clause of Section 1,1, the Court has determined that a child born in the United States to Chinese parents who were not qualified for naturalisation themselves is nonetheless a citizen of the United States with all the rights.
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What event is often considered the point where psychology split from philosophy?
A) Ivan Pavlov's findings on classical conditioning led psychology away from its philosophical roots.
B) When Sigmund Freud published his landmark "Interpretation of Dream" psychology officially split from philosophy.
C) The founding of Wilhelm Wundt's experimental psychology lab in Leipzig, Germany is often considered when philosophy and psychology split.
D) G. Stanley Hall's creation of the American Psychological Association is commonly seen as the official split of psychology from philosophy.
E) The publishing of William James's book "Principles of Psychology" was a major step in psychology's break from its philosophical influence.
Answers
Answer:
C) The founding of Wilhelm Wundt's experimental psychology lab in Leipzig, Germany is often considered when philosophy and psychology split.
Explanation:
Psychology became a separate discipline after the first psychology lab was established. Before the establishment of the lab, psychology was had its roots in the discipline of philosophy and physiology. After the creation of the experimental lab in 1879, a distinct path was constructed for the field of psychology. The training was provided to the students so that they can perform extensive research on the field of psychology.
bicycle generator rotates at 1800 rad/s, producing an 18.0 V peak emf. It has a 1.00 cm by 3.00 cm rectangular coil in a 0.794 T field. (a) How many turns are in the coil?
Answers
Answer:
N = 42
Explanation:
Given that,
Angular velocity, \(\omega=1800\ rad/s\)
Peak emf, \(\epsilon=18\ V\)
The dimensions of the rectangular coil = 1.00 cm by 3.00 cm
Magnetic field, B = 0.794 T
We know that, the emf of the coil is given by :
\(\epsilon=NAB\omega\)
Where
N is number of turns in the coil
So,
\(N=\dfrac{\epsilon}{AB\omega}\\\\N=\dfrac{18}{0.01\times 0.03\times 0.794\times 1800}\\\\N=41.98\)
or
N = 42
So, there are 42 turns in the coil.
What is located directly above the focus where the most damage can occur to structures?
Answers
Answer:
option(c) Epicenter
Explanation:
Hypocenter or the focus is the point where an earthquake or an underground explosion originates. center is the point that's directly above the focus on the face of the earth.
During earthquakes, utmost of the time it's the center that encounters topmost damage. The word center was deduced from the Latin word ‘ epicentrum ’ meaning positioned on a center.
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An object is attached to a trolley with a 0.80 kg mass, which is then pushed into an identical trolley at a speed of 1.1 m / s. The two trolleys couple together and move at a speed of 0.70 m / s after the collision. Calculate the mass of the object.
Answers
The mass of the object is approximately 0.457 kg.
The mass of the object attached to the trolley can be calculated using the principle of conservation of momentum. Since the two trolleys couple together and move as a single system after the collision, the total momentum before and after the collision should be the same. Given the mass of one trolley is 0.80 kg and the initial speed is 1.1 m/s, the momentum before the collision is 0.80 kg * 1.1 m/s = 0.88 kg·m/s. After the collision, the total mass is the sum of the two trolleys, and the final speed is 0.70 m/s.
Using the momentum equation, the mass of the object can be calculated as follows:
Total momentum before collision = Total momentum after collision
0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s
Solving for the mass of the object, we get:
0.88 kg·m/s = (0.80 kg + mass of the object) * 0.70 m/s
0.88 kg·m/s = 0.56 kg + 0.70 kg * mass of the object
0.88 kg·m/s - 0.56 kg = 0.70 kg * mass of the object
0.32 kg = 0.70 kg * mass of the object
Dividing both sides by 0.70 kg, we find:
mass of the object = 0.32 kg / 0.70 kg = 0.457 kg
The two trolleys collide and couple together, the total momentum before the collision is equal to the total momentum after the collision according to the principle of conservation of momentum.
The momentum of an object is defined as the product of its mass and velocity. In this case, the mass of one trolley is known (0.80 kg) and the initial speed is given (1.1 m/s), allowing us to calculate the momentum before the collision.
After the collision, the two trolleys move together at a new speed (0.70 m/s). By setting the initial momentum equal to the final momentum and solving for the unknown mass of the object, we can find its value.
In the calculation, we subtract the masses of the two trolleys from the total mass in order to isolate the mass of the object.
Dividing the difference in momentum by the product of the known mass and the new speed, we obtain the mass of the object. In this case, the mass of the object is approximately 0.457 kg.
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Particle is thrown in upward direction with initial velocity of 60m/s. Find average speed & average velocity after 10 seconds. Take g= 10 ms-2
Answers
The particle's average speed after 10 seconds is 110 m/s, and its average velocity is zero.
When a particle is thrown upwards, its initial velocity is in the upward direction and its acceleration is in the downward direction due to gravity. The acceleration due to gravity is approximately 10 m/s² near the surface of the Earth. Therefore, the particle's velocity decreases at a rate of 10 m/s² until it reaches its highest point, where its velocity is zero. After that, the particle's velocity becomes negative and it starts to fall back to the ground.
To find the particle's average speed after 10 seconds, we need to calculate the total distance traveled by the particle in 10 seconds. The formula to calculate the distance traveled by a particle under constant acceleration is:
distance = initial velocity * time + (1/2) * acceleration * time²
Substituting the given values, we get:
distance = 60 m/s * 10 s + (1/2) * 10 m/s² * (10 s)²
distance = 600 m + 500 m
distance = 1100 m
Therefore, the average speed of the particle after 10 seconds is:
average speed = total distance / total time
average speed = 1100 m / 10 s
average speed = 110 m/s
To find the particle's average velocity after 10 seconds, we need to calculate the displacement of the particle in 10 seconds. Displacement is the change in position of the particle, which is equal to the difference between its final and initial positions. Since the particle is thrown upwards and then falls back to the ground, its displacement after 10 seconds is zero. Therefore, the average velocity of the particle after 10 seconds is also zero.
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For the following distance vs time graph
Answers
Answer:
3
5
4
Explanation:
x = (8=(9+9)
(9+9) = 4, 5, 3
I’ve been struggling with this question, help!
Answers
The masses of the two objects MA and MB in the binary system are 4 Mo respectively.
How can the masses of the binary systems be calculated?The masses of binary systems can be calculated using Kepler's laws of planetary motion and observations of the system.
Let's denote the masses of the two objects as MA and MB, where MA is the mass of object A and MB is the mass of object B. We know that the total mass of the binary system is 8 Mo, so:
MA + MB = 8 Mo
We also know that the ratio of the distances between the two objects is 1/3. Let's denote the distance between the two objects as d, so we have:
d(A to B) / d(Binary System) = 1/3
We can simplify this equation by using the fact that the distances between the objects and the binary system add up to the total distance between the objects:
d(A to B) + d(B to binary system) = d(Binary system)
Since we know the ratio of the distances, we can substitute 1/3d for d(B to binary system):
d(A to B) + 1/3d = d(Binary system)
3d(A to B) + d = 3d(Binary system)
Substituting d(A to B) for d(Binary system) - d(B to binary system), we get:
3d(A to B) + d = 3(d(A to B) + d(B to binary system))
2d(A to B) = 2d(B to binary system)
d(A to B) / d(B to binary system) = 1
So the two objects are at the same distance from the binary system center of mass. This means that the masses of the two objects are equal:
MA = MB
Substituting this into the first equation, we get:
2MA = 8 Mo
MA = MB = 4 Mo
Therefore, the mass of each object is 4 Mo.
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An 4.0-kg fish pulled upward by a fisherman rises 1.9 m in 2.4 s, starting
from rest. Assuming the acceleration is constant, find the magnitude
and direction of the net force acting on the fish during this interval.
Answers
Answer:
2.64N
Explanation:
Force = mass * acceleration
Given
mass = 4kg
distance = 1.9m
Time t = 2.4s
Get the acceleration using the equation of motion
S = ut + 1/2at²
1.9 = 0 + 1/2a(2.4)²
1.9 = 5.76a/2
1.9 = 2.88a
a = 1.9/2.88
a = 0.66m/s²
Get the magnitude of the force
Force = 4 * 0.66
Force = 2.64N
Hence the net force acting on the fish is 2.64N
A rocket takes off from Earth's surface, accelerating straight up at 47.2 m/s2. Calculate the normal force (in N) acting on an astronaut of mass 89.4 kg, including his space suit. (Assume the rocket's initial motion parallel to the +y-direction. Indicate the direction with the sign of your answer.)
Answers
Answer:
The normal force acting on the astronaut is equal to the astronaut's weight minus the force of gravity acting on him. The force of gravity acting on the astronaut is equal to his mass times the acceleration due to gravity on Earth (9.8 m/s^2).
F_norm = F_gravity - ma = (89.4 kg)(9.8 m/s^2) - (89.4 kg)(47.2 m/s^2) = -4095.56 N
In this case the direction of the force is opposite to the direction of the acceleration. So the force is acting in -y direction. So the answer is -4095.56 N.
Two objects are dropped from a bridge, an interval of 1.0 s apart, and experience no appreciable air resistance. As time progresses, the DIFFERENCE in their speeds
a.
increases.
b.
remains constant.
c.
decreases.
d.
increases at first, but then stays constant.
e.
decreases at first, but then stays constant.
Answers
Answer: a
Explanation:
what energy is gotten from wind
Answers
Kinetic energy is gotten from wind which is converted into rotational energy.
How energy is produced from the wind?The wind is used to produce electricity using the kinetic energy created by air in motion wind turbines convert the kinetic energy in the wind into mechanical power. This mechanical ability can be used for particular tasks (such as grinding grain or forcing water) or can be converted into electricity by a generator. into electricity. In present wind turbines, wind rotates the rotor blades, which change kinetic energy into rotational energy. Wind turbines labor on an easy principle: in lieu of using electricity to make wind like a fan wind turbines use the wind to make electricity. The wind turns the rotter-like blades of a turbine around a rotor, which spins a generator, which produced electricity.
So we can conclude that Wind rotates the rotor blades that convert kinetic energy into rotational energy.
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A wagon with a mass of 30kg is accelerated across a level surface at 2.4 m/s^2. What net forces acts on the wagon?
Answers
Answer:
72 NExplanation:
The force acting on an object given it's mass and acceleration can be found by using the formula
force = mass × acceleration
From the question we have
force = 30 × 2.4
We have the final answer as
72 NHope this helps you
Assuming 100% efficient energy conversion, how much water stored behind a 50
centimeter high hydroelectric dam would be required to charge the battery?
Answers
Answer:
Explanation:
The power rating of the battery isn't provided. But let us assume that it is one of the common batteries with ratings of 12 V and 50 A.h
Potential energy possessed by water at that height = mgh
m = mass of the water = ρV
ρ = density of water = 1000 kg/m³
V = volume of water = ?
g = acceleration due to gravity = 9.8 m/s²
h = height of water = 50 cm = 0.5 m
Potential energy = ρVgh = 1000 × V × 9.8 × 0.5 = (4900V) J
Energy of the battery = qV
q = 50 A.h = 50 × 3600 = 180,000 C
V = 12 V
qV = 180,000 × 12 = 2,160,000 J
Energy = 2,160,000 J
At a 100% conversion rate, the energy of the water totally powers the battery
(4900V) = (2,160,000)
4900V = 2,160,000
V = (2,160,000/4900)
V = 440.82 m³
Hence, with our assumed power ratings for the battery (12 V and 50 A.h), 440.82 m³ of water at the given height of 50 cm would power the battery.
Incase the power ratings of the battery in the complete question is different, this solution provides you with how to obtain the correct answer, given any battery power rating.
Hope this Helps!!!
What is the symbol for carbonate ?
Answers
how does bluetooth work
Answers
Bluetooth works through radio waves in the ISM band, that is, they work by radio frequency. For that use the wireless networks of personal area (WPAN).
What is bluetooth?Bluetooth is a form of communication that works through radio waves by which there can be a transfer of data such as music, documents, images, etc. It works at a short distance so the devices must be close for the data transfer to occur correctly
Therefore, we can confirm that Bluetooth works through radio waves in the ISM band, that is, they work by radio frequency. For that use the wireless networks of personal area (WPAN).
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How much energy, in joules, is released by an earthquake of magnitude 8?
______________ joules
(Use scientific notation. Use the multiplication symbol in the math palette as needed.)
Answers
Answer:
6.309573e+16 joule is released by an earthquake of magnitude 8
Answer:
An earthquake with a magnitude of 8 on the Richter scale releases 6.309573e+16 J of energy.
Explanation:
An earthquake with a magnitude of 8 on the Richter scale releases 6.309573e+16 J of energy.
A 68 kg
man's arm, including the hand, can be modeled as a 79-cm
-long uniform cylinder with a mass of 3.3 kg. In raising both his arms, from hanging down to straight up, by how much does he raise his center of gravity?
Answers
Answer:
Explanation:
We can calculate the change in the man's center of gravity by considering the initial and final positions of the center of gravity of his arms.
Assuming the man's arms are initially hanging down by his sides, the center of gravity of his arms is located at the midpoint of the cylinder, which is at a distance of L/2 = 79/2 = 39.5 cm from the shoulder joint.
When the man raises his arms straight up, the center of gravity of his arms is located at the top of the cylinder, which is at a distance of L = 79 cm from the shoulder joint.
The change in the man's center of gravity is therefore:
Δh = h_final - h_initial
= L - L/2
= 79 cm - 39.5 cm
= 39.5 cm
Therefore, the man raises his center of gravity by 39.5 cm when he raises both his arms from hanging down to straight up.
Which of the following phenomenon odd called photoelectric effect?
A. High energy electrons impinge on a metallic Annie which emits electrons
B. A high energy photon emits photons as it slows down
C. A metal absorbs a quanta of light and then emits electrons
D. Two electrons are created from a quanta of light.
Answers
two electrons are created from a quanta of kight
what is the change of entropy if 536 g of gold are melted?
Answers
Answer: Therefore, the change in entropy when 536 g of gold are melted is 0.132 J/K.
Explanation: To calculate the change in entropy when 536 g of gold are melted, we need to know the entropy of fusion of gold and the temperature at which it melts.
The entropy of fusion of gold is 2.35 J/g·K, and the melting point of gold is 1064 °C or 1337 K.
The change in entropy when gold is melted can be calculated using the formula:
ΔS = Q/T
where ΔS is the change in entropy, Q is the heat absorbed during the process, and T is the temperature at which the process occurs.
The heat absorbed when gold is melted can be calculated using the formula:
Q = m × ΔH_fus
where m is the mass of the gold and ΔH_fus is the enthalpy of fusion of gold, which is 64.9 kJ/mol.
Converting the mass of gold to moles:
536 g / 196.97 g/mol = 2.72 mol
The heat absorbed by the gold when it is melted is:
Q = 2.72 mol × 64.9 kJ/mol = 176.2 kJ
Finally, we can calculate the change in entropy:
ΔS = Q/T = 176.2 kJ / 1337 K = 0.132 J/K
Which of the following is true about mutations in somatic cells?
A.) They get mutated easily and often, once every minute.
B.) They affect the reproductive cells.
C.) They don't affect offspring.
Answers
Answer:
B.) They affect the reproductive cells.
Part
A block of mass 2 kg is acted upon by two forces: 3 N (directed to the left) and 4 N (directed to the right). What can you say about the blocks motion?
Answers
Answer:
Explanation:
the block will move to the right side with small velocity because the force from the left side greater than force from right side. Velocity will be less because of friction and gravitational attraction.
If a block of mass 2 kg is acted upon by two forces: 3 N (directed to the left) and 4 N (directed to the right), then the block would move towards the right side.
What is Newton's second law?Newton's Second Law states that The resultant force acting on an object is proportional to the rate of change of momentum.
As given in the problem statement If a block of mass 2 kg is acted upon by two forces: 3 N (directed to the left) and 4 N (directed to the right),
The net force acting on the block = 4 Newtons - 3 newtons
= 1 Newton
Thus, we can say that the block would move to the right side.
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Suppose there are 100,000 atoms of a radioactive substance that has a ½ life of 10 minutes. How many atoms will remain after 40 minutes:
a. 2,500
b. 10,000
c. 12,500
d. 50,000
Show calculation
Answers
Answer:
c. 12,500
Explanation:
Original number of atoms = 100,000 atoms
Half- life = 10min
Unknown:
The number of atoms that will remain after 10min = ?
Solution:
The half - life is the time taken for half of a radioactive substance to decay by half.
Time taken Number of atom half life
10min 100000 _
20min 50000 1
30min 25000 2
40min 12500 3
An object moving 20 m/s
experiences an acceleration of 4 m/s' for 8
seconds. How far did it move in that time?
Variables:
Equation and Solve:
Answers
Answer:
We are given:
initial velocity (u) = 20m/s
acceleration (a) = 4 m/s²
time (t) = 8 seconds
displacement (s) = s m
Solving for Displacement:
From the seconds equation of motion:
s = ut + 1/2 * at²
replacing the variables
s = 20(8) + 1/2 * (4)*(8)*(8)
s = 160 + 128
s = 288 m
An electron with a velocity of 10^7 m/s enter into a region of magnetic flux density of 0.10T,the angle between the direction of the field and the initial path of electron being 25°.Find the axial distance between two turn of the helical path
Answers
Answer:
F = q v B sin Θ describes force on the electron
F = m v^2 / R describes force required to keep electron in circular path
q v B sin Θ = m v^2 / R
R = m v / (q B sin Θ)
R = 9.1E-31 * 1E7 / (.1 * 1.6E-19 * .423)
R = 9.1 / 6.77 * E-3 = .00134 m = .134 cm
a small weather rocket weighs 20 newtons. what is the Rockets Mass? the rocket fires is engine, if the rocket has a thrust of 109.2 Newtons, and if fixing from the air is 37.5 Newtons what is the acceleration on the rocket?
Answers
Answer: the mass is 1.60 kg and the acceleration on the rocket is...
58.4 m/s with a Power of Two
Explanation:
A model rocket lifting off from the launch pad is a good example of this principle. Just prior to engine ignition, the velocity of the rocket is zero and the rocket is at rest. If the rocket is sitting on its fins, the weight of the rocket is balanced by the re-action of the earth to the weight as described by Newton's third law of motion. There is no net force on the object, and the rocket would remain at rest indefinitely. When the engine is ignited, the thrust of the engine creates an additional force opposed to the weight. As long as the thrust is less than the weight, the combination of the thrust and the re-action force through the fins balance the weight and there is no net external force and the rocket stays on the pad. When the thrust is equal to the weight, there is no longer any re-action force through the fins, but the net force on the rocket is still zero. When the thrust is greater than the weight, there is a net external force equal to the thrust minus the weight, and the rocket begins to rise. The velocity of the rocket increases from zero to some positive value under the acceleration produced by the net external force. But as the rocket velocity increases, it encounters air resistance, or drag, which opposes the motion and increases as the square of the velocity. The thrust of the rocket must be greater than the weight plus the drag for the rocket to continue accelerating. If the thrust becomes equal to the weight plus the drag, the rocket will continue to climb at a fixed velocity, but it will not accelerate.