Answer:
m=-52
Step-by-step explanation:
1) multiply both sides by 4
m=-13×4=-52
SOLVE FOR N
-np-5=4(c-2)
The solution of the algebraic equation is n = (3-4c)/p
How to solve for N?
An algebraic equation or expression is any equation that contains unknown values, usually represented with alphabets or letter
Given: -np-5=4(c-2)
-np-5 = 4(c-2)
Expand the bracket:
-np-5 = 4c-8
Collect like terms:
-np = 4c-8+5
-np = 4c-3
Divide both sides by -p:
n = -(4c-3)/p
n = (-4c+3)/p = (3-4c)/p
Thus, the solution is n = (3-4c)/p
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find two whole numbers that are closest to v42. explain your reasoning
Answer:
The numbers are 6 and 7.
Step-by-step explanation:
4² = 16
5² = 25
6² = 36
7² = 49
√36 = 6
√42 = ?
√49 = 7
The numbers are 6 and 7.
what is the estimated sum of 4 5/12 + 3 8/14
A.7
B.7 1/2
C.8
D.9
The estimated sum of 7 83/84 is 8 to the nearest whole number.
Addition of mixed fractions:Mixed fractions are fraction that has a whole number attached to an improper fraction. A mixed fraction can be added by first adding the real whole numbers together, then adding their improper fraction counterparts with it.
Also, we can add two mixed fractions together by first converting all the mixed fractions to improper fractions before adding them together.
Using the first process:
= 4 5/12 + 3 8/14
The whole number are 4 and 3, adding those two together, we have:
= 7 (5/12 + 8/14)
The L.C.M of 12 and 14 is 84.
= 7( (7×5)+ (6*8) ) /84
= 7 (35+ 48/84)
= 7 (83/84)
To decimal, we get 7.988. Therefore, the estimated sum of 7 83/84 is 8 to the nearest whole number.
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For which values of x is the expression undefined
Answer:
7, -9
Reasoning:
When x is 7 or -9, the denominator equates to zero, making the expression undefined because nothing can be divided by zero.
33 inches of string how many 5 and 1/2 inch pieces can she cut from the string
Answer:
6 pieces
Explanation:
Given a string that is 33 inches in length.
She wants to cut the string into pieces that are 5½ inches in length each.
To determine the number of possible pieces, divide 33 by 5½.
\(\begin{gathered} 33\div5\frac{1}{2} \\ \text{ Change the mixed fraction to an improper fraction.} \\ =33\div\frac{11}{2} \\ \text{ Multiply each of the numbers by }\frac{2}{11} \\ =(33\times\frac{2}{11})\div(\frac{11}{2}\times\frac{2}{11}) \\ =\frac{66}{11}\div1 \\ =6 \end{gathered}\)The number of pieces she can cut is 6.
Bookwork code: N84
Look at the poster below showing the price of pencils in a stationery shop.
Annabel wants to buy exactly 76 pencils. What is the lowest amount she can
pay?
Give your answer in pounds (£).
spar
..
Pencils for sale!
30p each
Pack of 10
pencils for £2
Based on mathematical operations, the lowest amount that Annabel can pay for pencils is $15.20
How is the lowest amount determined?The lowest amount that Annabel can pay for pencils can be determined using the mathematical operations of multiplication and division.
Multiplication and division are two of the four basic mathematical operations, including addition and subtraction.
If Annabel chooses to purchase the first pencil at 30p each, she would pay £22.80 (£0.30 x 76).
If Annabel chooses to purchase the second pencil class of a pack of 10 pencils for £2, she would pay £15.20 [£2 x (76 ÷ 10)].
Pencils for sale
30p each
Pack of 10 pencils for £2
Thus, if Annabel wants to buy the pencils, she can either pay £15.20 or £22.80, but using mathematical operations, the lowest amount she can pay is £15.20.
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Suppose that a phone that originally sold for $800 and loses 3/5 of its value each year after it is released.
3. Write an equation for the value of the phone, p, t years after it is released.
Answer:
p=(800)(3/5)^t
Step-by-step explanation:
Answer: 800 - (3/5xt)
Step-by-step explanation:
800 is the base value and you have to multiply 3/5 by t
Find the area of the shape
The area of the given figure with rectangle and triangle is 27.5 square centimeters.
The given figure has a rectangle and two triangles.
The area of the rectangle is length times width
Length = 5 cm
Width = 4 cm
Area of rectangle = 5×4
=20 square centimeters
Area of triangle =1/2 base ×height
=1/2×2.5×3
=3.75 square centimeters
As there are two triangles, 2(3.75)=7.5 square centimeters
Total area = 20+7.5
=27.5 square centimeters
Hence, the area of the given figure with rectangle and triangle is 27.5 square centimeters.
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Yo please help I’ll mark you brainliest
Answer:
1116units²
Step-by-step explanation:
area of trapezium= (a+b)h all over 2
a=38
b=55
h=24
area= (38+55)*24 allover 2
area= 1116units²
Jenny buys 22 sports drinks for her soccer team they are on sale for $.35 off per drink Jenny paid $18.70 for the 22 sports drinks. What question does the equation help answer
Given the information
Jenny buys 22 drinks
drinks are on sale 0.35off per drink
22 drinks after sale= 18.70
the expression
\(22x-22(0.35)=18.70\)represents that for 22 drinks at a price x we substract 22*0.35 (sale) and the final result is 18.70
in other worlds
\(22(x-0.35)=18.70\)represent what is the presale price of the sport drink
Correct answer
option A
Evaluate the double integral by first identifying it as the volume of a solid.
\int \intR (5 x) dA, R = {(x, y) | 0 x 5, 0 y 3.
Answer:
37.5
Step-by-step explanation:
Given that:
We are to evaluate the integral of \(\iint_R (5-x) \ dA\) bounded by the region
0 ≤ x ≤ 5, 0 ≤ y ≤ 3
∴
\(\int ^3_0 \int ^5_0 (5-x) \ dx. dy\)
= \(\int ^3_0 \begin {bmatrix} 5x-\dfrac{x^2}{2} \end {bmatrix} ^5_0 \ dy\)
= \(\int ^3_0 \begin {bmatrix} 5\times 5-\dfrac{(5)^2}{2} \end {bmatrix} \ dy\)
= \(\int ^3_0 \begin {bmatrix}25-\dfrac{25}{2} \end {bmatrix} \ dy\)
= \(\int ^3_0 \begin {bmatrix}\dfrac{50-25}{2} \end {bmatrix} \ dy\)
= \(\begin {bmatrix}\dfrac{25}{2} \end {bmatrix}^3_0\)
= \(\dfrac{25 \times 3}{2}\)
= \(\dfrac{75}{2}\)
= 37.5
Select the statement that correctly explains how to use the benchmark fraction 1/2 to compare the fractions 2/6 and 4/5.
4/5 is less than 2/6 because 4/5 is less than 1/2 and 2/6 is greater than 1/2
4/5 is greater than 2/6 because 4/5 is greater than 1/2 and 2/6 is less than 1/2
2/6 is equal to 4/5 because 2/6 is equal to 1/2 and 4/5 is equal to 1/2
2/6 is greater than 4/5 because 2/6 is greater than 1/2 and 4/5 is less than 1/2
Answer:
4/5 is greater than 2/6 because 4/5 is greater than 1/2 and 2/6 is less than 1/2
What is benchmark fraction?
Benchmark fractions are fractions that are used to compare fractions, usually when teaching a concept. They are often used to represent common fractions like halves, thirds, fourths, and eighths. They are also used to help students understand the relationships between fractions, like one half being the same as two fourths.
In the given question:
the value of 1/2 = 0.5, it is represent as halves
the value of 2/6 = 0.3, when we divide 2/6 it gives 1/3 which is represent as thirds.
The value of 4/5 = 0.8.
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20% of the students in a class are left handed. There are 50 students. How many
of the students are left handed? (Show working)
Answer:
10
Step-by-step explanation:
50 students.
20% = 20/100 = 1/5
50*1/5 = 10
There are 10 left-handers.
27 minus ³/² of a number(x) is not more than 36. What is the number
Answer:
-6
Step-by-step explanation:
27 - 1.5x ≤ 36
54 - 3x ≤ 72
54 - 72 ≤3x
-18 ≤ 3x
-6 ≤ x
x ≥ -6 Hope this helped and sorry if its wrong
What is the domaun of the relation
{(3, 4), (4, 3), (4, 4), (5, 2)}?
o {2, 3, 4, 5}
o {3, 4, 5}
o {4}
o {2, 3, 4}
Answer:
[3,4,5]
Step-by-step explanation:
the answer is [3,4,5,]
because domain means it is the value of x.
Rewrite the equation `6y=2x+12`into slope intercept form.
Answer:
y=1/3x+2
Step-by-step explanation:
................
Answer:
y=1/3x+2
Step-by-step explanation:
slope intercept form: y=xm+b
6y=2x+12
/6 /6
y=2/6x+2
y=1/3x+2
have a great day!
If you open a bank account with 23,000 and its annual interest is compounded quarterly. What would the interest have to be for the amount to grow to $50,000 in 7 years?
\(~~~~~~ \textit{Compound Interest Earned Amount} \\\\ A=P\left(1+\frac{r}{n}\right)^{nt} \quad \begin{cases} A=\textit{accumulated amount}\dotfill & \$ 50000\\ P=\textit{original amount deposited}\dotfill &\$23000\\ r=rate\to r\%\to \frac{r}{100}\\ n= \begin{array}{llll} \textit{times it compounds per year}\\ \textit{quarterly, thus four} \end{array}\dotfill &4\\ t=years\dotfill &7 \end{cases}\)
\(50000 = 23000\left(1+\frac{ ~~ \frac{r}{100} ~~ }{4}\right)^{4\cdot 7} \implies \cfrac{50000}{23000}=\left( 1+\cfrac{r}{400} \right)^{28} \\\\\\ \cfrac{50}{23}=\left( \cfrac{400+r}{400} \right)^{28}\implies \sqrt[28]{\cfrac{50}{23}}=\cfrac{400+r}{400} \\\\\\ 400\sqrt[28]{\cfrac{50}{23}}=400+r\implies 400\sqrt[28]{\cfrac{50}{23}}-400=r\implies \stackrel{ \% }{11.25}\approx r\)
What’s the answer? Can you plz help?
Answer:
they are equal
Step-by-step explanation:
On a piece of paper, graph f(x) = (4x≤3. Then determine which answer
12 if x > 3
choice matches the graph you drew.
The graph of the piecewise function is the one in option D-
Which one is the graph of f(x)?First, we know that:
f(x) = 4 when x ≤ 3
So, we want to have a horizontal line in the left side of the graph, such that it ends in a closed circle at x = 3 (we need to have a closed circle because the symbol ≤ is used).
From the given graphs, the only one with that form is D.
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In an animal rescue facility are 21 animals.14 cats and 7 dogs. During the day 5 animals were adopted.what is the probabity that 3 cats and 2 dogs were adopted? Review ch 7 on probability
Answer:
0.3756
Step-by-step explanation:
I believe this is a combinatorics probability problem.
We first figure out in how many ways we can choose 3 cats out of 14 cats
Then we figure out how many ways we can choose 2 dogs out of 7 dogs
The total number of ways to select 3 cats and 2 dogs will be the product of these two
We then figure out in how many ways we can select 5 animals out of a total of 21 animals
The product we computed divided by the above number will give the probability
The number of ways we can choose k items out of n items is given by nCk i.e n Choose k
The formula is rather complicated but almost all calculators should be able to compute this given n and k
Let's deal with the selection of 3 cats from the population of 14 cats
This is given by 14C₃ which works out to 364
Number of ways for selecting 2 dogs from 7 dogs = 7C₂ = 21
Number of ways of selecting 5 animals from 21 = 21C₅ = 20349
The probability of selecting 3 cats and 2 dogs is therefore:
\(\dfrac{364 \times 21}{20349} = 0.3756\)
That, I believe is the answer. Please let me know if it is correct and if you need more info.
What is (-2/3)+(7/8)?
Answer: 5/24
Step-by-step explanation:
(-2/3)+(7/8)=
(-2/3)+(7/8)*24/24= ==> 24 is the LCM of 3 and 8
\(\frac{(-2*24)/3+(7*24)/8}{24}\)=
\(\frac{-2*24/3+7*24/8}{24}\)=
\(\frac{-2*8+7*3}{24}\)=
\(\frac{-16+21}{24}\)=5/24
The ratio of boys to girls in the school musical is 5 to 8. Which of the following shows the possible numbers of boys to girls in the school musical?
Answer:
10 and 16
15 and 24
20 and 32
Step-by-step explanation:
Brainliest please?
you roll two number cubes event a you roll a two first event b you roll a 5 second
Answer:
its independent, because the outcome of the first roll does not affect the outcome of the second roll
Hence, P(A and B) can be calculated as
P(A and B) = P(A) x P(B)
For event A,
you row a two first
Probability = possible outcome / total outcome
Fractions Word Problem
Pete Wong placed an order of crushed rock from Lowes. He ordered 6/7 of a ton of the crushed rock to
build a patio in his yard. If Pete only used 3/4 of the rock, how much crushed rock remains unused?
Choose one 4 points
1/6
1/4
1/3
2/3
If Pete used 3/4 of a ton of crushed rock then 1/4 crushed rock will remain unused.
How to subtract to fractions?
Go through the below steps to subtract fractions.
Step 1: Determine the LCM of the denominator values.
Step 2: Convert the denominator to the LCM value by multiplying the numerator and denominator using the same number.
Step 3: Subtract the numerators, once the fractions have the same denominator values.
Step 4: Simplify the fraction, if required.
According to the given question:
Pete ordered 6/7 of a ton of the crushed rock to build a patio in his yard.
If Pete used 3/4 of the rock instead of 6/7 of a ton then unused crushed rock
= 1 - 3/4
= (4 - 3)/4
= 1/4
Therefore 1/4 crushed rock will remain unused.
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what is simplify 4- (-7)+(-2)
Answer:
4+7-2
=11-2
=9
Step-by-step explanation:
use the distance formula to find the distance between each pair of points. (-1,4), (-4,-1)
Answer:
a.
Step-by-step explanation:
\(d = \sqrt{( y _2 - y) {}^{2} + ( x_2 - x ) {}^{2} } \)
\(d = \sqrt{( - 1 - 4) {}^{2} + \sqrt{ - 4 + 1) {}^{2} } } \)
\(d = \sqrt{ - 5 {}^{2} +( - 3 {}^{2} )} \)
\(d = \sqrt{25 + 9} \)
\(d = \sqrt{34} \)
Help. I'll mark as brainist!
The missing values are:
t = 11 sec.
D = 40 ft/sec
D = 70 ft/sec.
Given:
t r D
4 10
7 10
10 110
Time = divide and Distance = multiply
Finding t:
Time = divide means to find time divide.
Time = D/r
= 110/10
= 11 sec.
Finding D:
Distance = multiply
so D = t*r
= 4*10
= 40 ft.
D = t*r
= 7*10
= 70 ft.
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Factor 21x^2 - 14x - 56
Answer:
7((x-2)(3x+4))
Step-by-step explanation:
Common factor of 7 in this quadratic formula. \(7(3x^2-2x-8)\); -8 * 3x^2 = -24x^2, now find factors of this product that equal to -2x when added. The factors that fit this is -6x and 4x. So, if you make a generic rectangle you can find the product. You get 7((x-2)(3x+4))
What is the solution to this system of equations?
8a−4b=20
5a−8b=62
a=
b=
Answer:
Hello there, I think this is the answer
a = - 2
b = - 9
you have 51 coins in your pocket, all dimes and quarters. You have $10.20. How many dimes and quarters do you have?
To find the number of dimes and quarters, you have 17 dimes and 34 quarters in your pocket , when there are 51 coins in your pocket.
To solve this problem, we can set up a system of equations using the given information. Let's use "d" to represent the number of dimes and "q" to represent the number of quarters.
We know that there are 51 coins in total, so we can write the equation: d + q = 51.
We also know that the total value of the coins is $10.20, which can be expressed as 10d + 25q (since dimes are worth 10 cents and quarters are worth 25 cents). So our second equation is: 10d + 25q = 1020.
To solve this system of equations, we can use substitution or elimination. Let's use substitution:
Rearrange the first equation to solve for d: d = 51 - q.
Substitute this expression for d in the second equation: 10(51 - q) + 25q = 1020.
Simplify and solve for q: 510 - 10q + 25q = 1020.
Combine like terms: 15q = 510.
Divide both sides by 15: q = 34.
Now substitute this value back into the first equation to solve for d: d + 34 = 51.
Subtract 34 from both sides: d = 17.
Therefore, you have 17 dimes and 34 quarters.
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