state four law of photoelectric effect​

Answers

Answer 1

Answer:

LAW 1 :  For a given metal and frequency, the number of photoelectrons emitted is directly proportional to the intensity of the incident radiation.  

---------------------------------------------

LAW 2: For a given metal, there exists a certain frequency below which the photoelectric emission does not take place. This frequency is called threshold frequency.

-----------------------------------------------

LAW 3: For a frequency greater than the threshold frequency, the kinetic energy of photoelectrons is dependent upon frequency or wavelength but not on the intensity of light.

-----------------------------------------------

LAW 4: Photoelectric emission is an instantaneous process. The time lag between incidence of radiations and emission of electron is 10^-9 seconds.

Explanation:

Answer 2

Answer:

LAW 1 : For a given metal and frequency, the number of photoelectrons emitted is directly proportional to the intensity of the incident radiation. ... LAW 4: Photoelectric emission is an instantaneous process.


Related Questions

When the balloon sticks to the wall (assuming it sticks to the wall). It is
because the balloon is negatively charged and the wall carries an extra
positive charge.
1.false
2.true

Answers

The answer is false

A boat has a speed of 20m/s in still waters. what is the speed in a river flowing due east with a velocity of 5m/s if the boat is heading north. How far from a point directly north on the other side of the river will the boat arrive if the width of the river is 10m.​

Answers

The boat will arrive 2.5 meter in east far from a point directly north on the other side of the river.

What is velocity?

The rate at which a body's displacement changes in relation to time is known as its velocity. Velocity is a vector quantity with both magnitude and direction.

A boat has a speed of 20m/s in still waters.

The velocity of river is 5m/s in east.

The width of the river is = 10 meter.

Hence, time taken by the board to cross the river = 10/20 second

= 0.5 second.

In this time, the board will move in east direction   = 5×0.5 meter = 2.5 meter.

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The work function of a metal is 3.45 eV. Calculate the maximum wavelength of a photon that can eject photoelectrons from the metal

Answers

We are asked to determine the maximum wavelength of a photon that can eject photoelectrons from a metal given its work function. To do that we will use the following formula:

\(\lambda=\frac{hc}{E}\)

Where:

\(\begin{gathered} \lambda=\text{ wavelength} \\ h=\text{ plank's constant} \\ c=\text{ speed of light} \\ E=\text{ work function} \end{gathered}\)

First, we will convert the work function from eV to Joules. To do that we will use the following conversion factor:

\(1eV=1.6\times10^{-19}J\)

Multiplying by the conversion factor we get:

\(3.45eV\times\frac{1.6\times10^{-19}J}{1eV}=5.53\times10^{-19}J\)

Plank's constant is equivalent to:

\(h=6.63\times10^{-34}Js\)

The speed of light is equivalent to:

\(c=3\times10^8\frac{m}{s}\)

Now, we plug in the values in the formula:

\(\lambda=\frac{(6.63\times10^{-34}Js)(3\times10^8\frac{m}{s})}{5.53\times10^{-19}J}\)

Solving the operations:

\(\lambda=3.6\times10^{-7}m\)

And thus we have determined the wavelength.

Three cars are driving at 29.0 m/s along the road shown in the figure (Figure 1). Car B is at the bottom of the hill and car C is at the top. Suppose each car suddenly brakes hard and starts to skid. Assume μk=1.00. What is the x-component of the tangential acceleration (i.e., the acceleration parallel to the road) of car A?

Answers

Since the car masses are unknown, we are unable to calculate the numerical value of the x-component of Car A's tangential acceleration.

How do kinetic and potential energy compare?

The energy that is held in any object or system as a function of its position or component arrangement is known as potential energy. The object or system is unaffected by external factors like air pressure or altitude. Kinetic energy, on the other hand, describes the power of moving particles within a system or an object.

They are being affected by the kinetic frictional force, which is caused by:

f = μk * N

Therefore,

fB = μk * N = μk * mB * g

Car C is at its highest point at the top of the hill, where the normal force acting on it is equal to the force of gravity. Therefore,

fC = μk * N = μk * mC * g

where mC is the mass of Car C.

For Car A, the x-component of the tangential acceleration is given by:

aA = (fB - fC) / mA

where mA is the mass of Car A.

We can substitute the following values and simplify by assuming that the mass of each of the three automobiles is the same:

aA = (μk * mB * g - μk * mC * g) / mA

aA = μk * g * (mB - mC) / mA

Since μk = 1.00 and g = 9.81 m/s², we can plug in the values and get:

aA = (mB - mC) * 9.81 / mA

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Three cars are driving at 29.0 m/s along the road shown in the figure (Figure 1). Car B is at the bottom

High-power experimental engines are being developed by the Stevens Motor Company for use in its new sports coupe. The engineers have calculated the maximum horsepower for the engine to be 630HP
. Twenty five engines are randomly selected for horsepower testing. The sample has an average maximum HP of 650
with a standard deviation of 60HP
. Assume the population is normally distributed.
Step 1 of 2 : Calculate a confidence interval for the average maximum HP for the experimental engine. Use a significance level of α=0.01
. Round your answers to two decimal places.

Answers

The 99% confidence interval for the average maximum HP for the experimental engine is (610.12, 689.88).

To calculate the confidence interval for the experimental engines' average maximum HP, we can use the following formula:

To find the z-score for α=0.01, we can refer to a standard normal distribution table or use a calculator. The z-score is approximately 2.58.

Substituting the given values into the formula, we get:

CI = 650 ± 2.58*(60/√25) CI = 650 ± 30.96

Rounding to two decimal places, the confidence interval for the experimental engines' average maximum HP is:

CI = [619.04 HP, 680.96 HP]

Therefore, we can say with 99% confidence that the true average maximum HP for the experimental engines falls between 619.04 HP and 680.96 HP. Thus, we can conclude that the experimental engines' average maximum HP is likely to be within this range. However, note that this range does not include the manufacturer's claimed maximum HP of 630 HP, which may indicate that the engines are performing below expectations.

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A 50.0 Watt stereo emits sound waves isotropically at a wavelength of 0.700 meters. This stereo is stationary, but a person in a car is moving away from this stereo at a speed of 40.0 m/s. The frequency of sound waves that the car receives is ________. In addition, when the car is 70.0 meters away from the speaker, the car will hear sound waves with a sound intensity level of _________ .

Answers

Answer:

a) f' = 432 Hz

b) I = 8.12*10^-4 W/m^2

Explanation:

a) To calculate the frequency of sound waves that car receives, you take into account the Doppler effect. In this case (observer moves away of the source) you have the following formula:

\(f'=f(\frac{v-v_o}{v+v_s})\)    (1)

where

f: frequency of the source = ?

v: speed of sound = 343 m/s

vo: speed of the observer = 40.0 m/s

vs: speed of the source = 0 m/s (stationary)

You replace the values of all parameters in the equation (1):

To calculate f' you first calculate the frequency of the sound wave, by using the following formula:

\(v=\lambda f\\\\\)

v: speed of sound

λ: wavelength = 0.700 m

\(f=\frac{v}{\lambda}=\frac{343m/s}{0.700m}=480Hz\)

Next, you replace the values of all parameters in the equation (1):

\(f'=(490Hz)(\frac{343m/s-40.0m/s}{343m/s})=432Hz\)

hence, the frequency perceived by the car is 432 Hz

b) To calculate the power of the sound wave, when the car is 70.0 maway from the speaker, you use the following formula:

\(I=\frac{P}{4\pi r^2}\)

P: power of the source = 50.0 W

r: distance to the source = 70.0 m

\(I=\frac{50.0 W}{4\pi(70.0m)^2}=8.12*10^{-4}\frac{W}{m^2}\)

hence, the intensity is 8.12*10^⁻4 W/m^2


Which phrase describes a scientific law?
A. A statement that matter cannot be created or destroyed
B. A claim that experiments cannot verify whether matter has been
destroyed
O C. An explanation for why matter cannot be created or destroyed
D. A prediction of how much matter exists in the universe
SUBMIT
In

Answers

Answer:

C- An explanation for why matter cannot be created or destroyed

Explanation:

Answer: A. A statement that matter cannot be created or destroyed.

Explanation:

Apex

An object is dropped from a vertical height of 1.89 m above the balcony level. What is the object’s speed when it is 2.20 m below the balcony level if 10.0% energy is lost due to the air resistance? Does it matter when to apply 10% loss before V calculations or after? [8.49m/s] [yes it does, 0.9Energy result in √0.9Velocity]

Answers

Answer:

The 10% must come off the energy, not the velocity

Explanation:

Change in height h = 1.89 + 2.20 = 4.09 m

Potential energy = mgh = m(9.81)(4.09) = 40.1m J

Friction losses 40.1m(0.10) = 4.01m J

Kinetic energy at end 40.1m - 4.01m = 36.1m J

KE = ½mv²

v = √(2KE/m)

v = √(2(36.1m)/m = √72.2

v = 8.4983...

v = 8.50 m/s

what is a shargaff rule

Answers

According to Chargaff's rule, the amounts of adenine (A), thymine (T), and guanine (G) in the DNA molecule are equal to each other. The amounts of cytosine (C) and guanine (G) are also equal.

Who is Chargaff ?

Erwin Chargaff was a biochemist, author, Bucovinian Jew who immigrated to America during the Nazi era, and professor of biochemistry at Columbia University's medical school.

Chargaff found patterns among the four bases, or chemical building blocks, of DNA, which are directly related to DNA's function as the genetic material of living things.

He was born in Austria-Hungary. Heraclitean Fire: Sketches from a Life Before Nature, an autobiography he penned, received positive reviews.

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do you believe that doubting is thinking?yes or no then why?​

Answers

Answer:

yes

Explanation:

Because doubting is thinking something is

wrong

plzzzzzzzzzzzzzzzzzzzzzzzzzz help 20 points

plzzzzzzzzzzzzzzzzzzzzzzzzzz help 20 points

Answers

Answer:

1.23

Explanation:

\({\underline{\pink{\textsf{\textbf{ Answer : }}}}}\)

➩ 1.23 feet

\({\underline{\purple{\textsf{\textbf{Explanation : }}}}}\)

Given :

Simon cuts a pipe that was 4.92 feet long Then he cuts it into four equal pieces.

To find :

What is the length of the each piece.

Solution :

As it is told that it's divided into four equal pieces

Therefore,

We must divide it by 4 to get the length of each piece.

So,

\( \sf \to \: \frac{4.92}{4} \\ \sf \to \: 1.23 \: feet \: ans.\)

What is sound waves

Answers

Sound waves are a type of mechanical wave that propagate through a medium, typically air but also other materials such as water or solids.

Characteristics of sound waves

Frequency: the frequency of a sound wave refers to the number of cycles or vibrations it completes per second and is measured in Hertz (Hz).

Amplitude: the amplitude of a sound wave refers to the maximum displacement or intensity of the wave from its equilibrium position. It represents the loudness or volume of the sound, with larger amplitudes corresponding to louder sounds and smaller amplitudes corresponding to softer sounds.

Wavelength: the wavelength of a sound wave is the distance between two consecutive points in the wave that are in phase, such as from one peak to the next or one trough to the next. It is inversely related to the frequency of the wave.

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A basketball player passes the ball to a teammate. The ball reaches a velocity of 5.5 m/s, 2 seconds after the ball leaves the player’s hands. What is the acceleration of the ball during those two seconds?

Answers

Answer:

acceleration = 2.25 m/s²

Explanation:

\(a = \frac{v - u}{t}\)

where:

a = acceleration (?)

v = final velocity (5.5 m/s)

u = initial velocity (0 m/s, because the ball starts from rest)

t = time taken (2s).

Using the formula:

acceleration = \(\frac{5.5 - 0 }{2}\)

                     = 2.75 m/s²

Given a uniform plane wave in air as. Ei = 30 cos(wt - Bz)ax +40 sin(wt - Bz)ay V/m. i. Find H₁ (4 mks)
ii. If the wave encounters a perfectly conducting plate normal to the z-axis at z = 0,find the reflected wave E, and H, (8 mks) iii.The transmitted wave. (3 mks)​

Answers

Reflected wave E: -30 cos(wt - Bz)ax - 40 sin(wt - Bz)ay V/m

Reflected wave H: (1/377) x (-30 cos(wt - Bz)ax - 40 sin(wt - Bz)ay)

Transmitted wave E: 0 V/m

Transmitted wave H: 0

To find H₁, we can use the relation between electric field (E) and magnetic field (H) in a uniform plane wave in free space. The relation is given by:

H = (1/η) x E

where η is the intrinsic impedance of air, which is approximately 377 ohms. Given the electric field Ei = 30 cos(wt - Bz)ax + 40 sin(wt - Bz)ay V/m, we can calculate H₁ as follows:

H₁ = (1/377) x Ei

Substituting the values, we have:

H₁ = (1/377) x (30 cos(wt - Bz)ax + 40 sin(wt - Bz)ay)

When the uniform plane wave encounters a perfectly conducting plate normal to the z-axis at z = 0, it gets reflected. The electric field and magnetic field of the reflected wave can be found using the boundary conditions for a perfect conductor. The reflected wave has the same magnitude as the incident wave, but the direction of the electric field is reversed.Therefore, the reflected electric field Er = -30 cos(wt - Bz)ax - 40 sin(wt - Bz)ay V/m.

Using the same relation as before, we can find the reflected magnetic field Hr:

Hr = (1/377) x Er

Substituting the values, we have:

Hr = (1/377) x (-30 cos(wt - Bz)ax - 40 sin(wt - Bz)ay)

The transmitted wave occurs when the incident wave passes through the conducting plate. Since the plate is a perfect conductor, the transmitted wave is completely absorbed, and there is no transmission through the plate. Therefore, the transmitted wave has zero electric field and magnetic field.

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Question 1 of 10
What is the electric force acting between two charges of -0.0085 C and
-0.0025 C that are 0.0020 m apart?
Use F.- and k - 900-10° N m.cº.
kq,92
A. -4.8 - 1010N
B. -9.6x 107N
C. 9.6 x 10°N
D. 4.8 - 1010 N

Question 1 of 10What is the electric force acting between two charges of -0.0085 C and-0.0025 C that

Answers

Answer:

D

Explanation:

Calculate the absolute pressure at an ocean depth of 1.0 x 10³ m. Assume that the density of the water is 1.025 x 10³ kg/m³ and that Po = 1.01 x 10^5 Pa.

Answers

The absolute pressure at an ocean depth of 1.0 x 10^3 m is 1.002 x 10^8 Pa.

What is hydrostatic pressure?

Hydrostatic pressure is the pressure that a fluid exerts on a surface due to the weight of the fluid above it. It is the result of the force of gravity acting on a column of fluid, and it is directly proportional to the height of the column of fluid and the density of the fluid.

The absolute pressure at an ocean depth of 1.0 x 10^3 m can be calculated using the hydrostatic pressure equation:

P = ρgh + Po

where:

P is the absolute pressure at the given depth

ρ is the density of the water

g is the acceleration due to gravity (assumed to be 9.81 m/s²)

h is the depth of the ocean

Po is the atmospheric pressure at the surface (assumed to be 1.01 x 10^5 Pa)

Substituting the given values, we get:

P = (1.025 x 10^3 kg/m³) x (9.81 m/s²) x (1.0 x 10^3 m) + 1.01 x 10^5 Pa

P = 1.025 x 9.81 x 10^6 Pa + 1.01 x 10^5 Pa

P = 1.002 x 10^8 Pa.

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Alcohol wiped across a tabletop rapidly disappears. What happened to the temperature of the tabletop

Answers

Answer:

it gets colder

Explanation:

because if you put anything on a table top it will become colder

It gets colder. There wasn’t much of the liquid so it dried up, instead of staying on the surface


Can somebody please help

Can somebody please help

Answers

Answer:

Explanation:

part A: C

part B: B

An artillery shell is fired at a target 200 m above the ground. When the shell is 100 m in the air, it has a speed of 100 m/s. What is its speed when it hits its target?

Answers

The speed of the artillery shell when it hits its target is 100 m/s.

Given:

Initial vertical displacement (y) = 200 m

Vertical displacement at 100 m in the air (y') = 100 m

Final velocity in the vertical direction (vy') = 0 m/s (at the highest point of the trajectory)

Using the equation for vertical displacement in projectile motion:

y' = vy^2 / (2g),

where g is the acceleration due to gravity (approximately 9.8 m/s^2), we can solve for the initial vertical velocity (vy).

100 m = vy^2 / (2 * 9.8 m/s^2),

vy^2 = 100 m * 2 * 9.8 m/s^2,

vy^2 = 1960 m^2/s^2,

vy = sqrt(1960) m/s,

vy ≈ 44.27 m/s.

Now, since the horizontal motion is independent of the vertical motion, the horizontal speed of the shell remains constant throughout its trajectory. Therefore, the speed of the shell when it hits its target is 100 m/s.

Hence, the speed of the artillery shell when it hits its target is 100 m/s.

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A blow-dryer and a vacuum cleaner each operate with a voltage of 120 V. The current rating of the blow-dryer is 11 A, and that of the vacuum cleaner is 4.0 A. Determine the power consumed by (a) the blow-dryer and (b) the vacuum cleaner. (c) Determine the ratio of the energy used by the blow-dryer in 15 minutes to the energy used by the vacuum cleaner in one- half hour.

Answers

Answer:

(a) P₁ = 1320 W

(b) P₂ = 480 W

(c) \(\frac{E_1}{E_2} = 0.46\)

Explanation:

(a)

The power consumed by the blow dryer can be calculated as follows:

\(P_1 = VI\)

where,

P₁ = Power Consumed by the blow dryer = ?

V = Voltage = 120 V

I = Current Rating of the blow dryer = 11 A

Therefore,

\(P_1 = (120\ V)(11\ A)\\\)

P₁ = 1320 W

(b)

The power consumed by the blow dryer can be calculated as follows:

\(P_2 = VI\)

where,

P₂ = Power Consumed by the vacuum cleaner = ?

V = Voltage = 120 V

I = Current Rating of the vacuum cleaner = 4 A

Therefore,

\(P_2 = (120\ V)(4\ A)\\\)

P₂ = 480 W

(c)

\(\frac{E_1}{E_2} = \frac{P_1t_1}{P_2t_2}\)

where,

E₁ = Energy used by the blow-dryer

E₂ = Energy used by the vacuum cleaner

t₁ = time of use of the blow-dryer = (15 min)(60 s/1 min) = 900 s

t₂ = time of use of the vacuum cleaner = (1.5 h)(3600 s/1 h) = 5400 s

Therefore,

\(\frac{E_1}{E_2} = \frac{(1320\ W)(900\ s)}{(480\ W)(5400\ s)}\\\\\frac{E_1}{E_2} = 0.46\)

A 10 kg object has a 40 N force applied to it. What is the acceleration of the object ? *

Answers

Answer:

a = 4 [m/s^2]

Explanation:

To solve this problem we must use Newton's second law, which tells us that force is equal to the product of mass by acceleration.

F = m*a

where:

F = force = 40 [N]

m = mass = 10 [kg]

a = 40/10

a = 4 [m/s^2]

Which image best illustrates diffraction

Answers

Answer:

There is no image

Explanation:

Answer: Send me image than I will be able to help

Explanation:

Assuming 100% efficient energy conversion, how much water stored behind a 50 centimeter high hydroelectric dam would be required to charge the battery?

Answers

Complete question is;

Assuming 100% efficient energy conversion how much water stored behind a 50 centimeter high hydroelectric dam would be required to charge the battery with power rating, 12 V, 50 Ampere-minutes.

Answer:

Amount of water required to charge the battery = 7.35 m³

Explanation:

The formula for Potential energy of the water at that height = mgh

Where;

m = mass of the water

g = acceleration due to gravity = 9.8 m/s²

h = height of water = 50 cm = 0.5 m

We know that in density, m = ρV

Where;

ρ = density of water = 1000 kg/m³

V = volume of water

So, potential energy is now given as;

Potential energy = ρVgH = 1000 × V × 9.8 × 0.5 = (4900V) J

Now, formula for energy of the battery is given as;

E = qV

We are given;

q = 50 A.min = 50 × 60 = 3,000 C

V = 12 V

Thus;

qV = 3,000 × 12 = 36,000 J

E = 36,000 J

At a 100% conversion rate, the energy of the water totally powers the battery.

Thus;

(4900V) = (36,000)

4900V = 36,000

V = 36,000/4900

V = 7.35 m³

When is the direction of the total acceleration in a circular motion tan-(ac/at) and when is it tan-(at/ac)?Ive seen there are cases where the tangential acc is vertical and ac is horizontal and vice versa

Answers

In circular motion, the total acceleration has two components: the centripetal acceleration (a_c) and the tangential acceleration (a_t). The centripetal acceleration is directed towards the center of the circle, while the tangential acceleration is directed along the tangent to the circle at the point of interest.

The angle (θ) between the total acceleration vector (a) and one of its components (either a_c or a_t) can be found using the arctangent function (tan^(-1)) and the ratio of the other component. For example:

θ = tan^(-1)(a_c/a_t) or θ = tan^(-1)(a_t/a_c)

Which formula to use depends on the reference frame you are using and how you define the angle. Let's consider two cases:

1. If you define the angle (θ) between the total acceleration vector (a) and the tangential acceleration (a_t), you should use:

θ = tan^(-1)(a_c/a_t)

2. If you define the angle (θ) between the total acceleration vector (a) and the centripetal acceleration (a_c), you should use:

θ = tan^(-1)(a_t/a_c)Regarding the orientation of the acceleration vectors, the tangential and centripetal accelerations are always perpendicular to each other. The orientation (horizontal or vertical) depends on the specific problem and the point in the circular path being considered. For example, at the top and bottom points of a vertical circle, the tangential acceleration will be horizontal, and the centripetal acceleration will be vertical. On the other hand, at the left and right points of the circle, the tangential acceleration will be vertical, and the centripetal acceleration will be horizontal.

A child on roller skates undergoes as acceleration of 0.6m/s^2 due to a horizontal net force of 24N . What is the mass of the child?

Answers

Answer:

40Kg

Explanation:

F=m×a

24N÷0.6m/s^2=40

Suppose that a series RL circuit is connected to a voltage source whose input voltage (Vin) is shown in the figure above. As shown in the figure above, the input voltage Vin = Vmax only within time interval 0 ≤ t ≤ T. The input voltage Vin = 0 outside this time interval. Assume that initially (at t = 0), no current is flowing in this circuit (I = 0)! A Determine the output voltage Vout as a function of time t! B Assume that the time interval T is very short so that T → 0, and also assume the the maximum voltage Vmax is quite high, so that VmaxT ≈ Φimp. Show that the output voltage Vout can be approximated by the following equation : Vout(t) ≈ Φimp τ e −t/τ where τ = L R

Answers

A. The output voltage, Vout, as a function of time, t, in a series RL circuit can be determined using the equation: Vout(t) = Vmax * (1 - e^(-t/τ)), where τ = L/R.

B. When the time interval T is very short (T → 0) and the maximum voltage Vmax is quite high (VmaxT ≈ Φimp), we can approximate the output voltage Vout using the equation: Vout(t) ≈ Φimp * e^(-t/τ), where τ = L/R.

A. To determine the output voltage Vout as a function of time t in a series RL circuit, we use the following equation:

Vout(t) = Vmax * (1 - e^(-t/τ))

Here, Vmax is the maximum input voltage, τ = L/R is the time constant of the circuit (where L is the inductance and R is the resistance).

B. When the time interval T is very short (T → 0) and the maximum voltage Vmax is quite high (VmaxT ≈ Φimp), we can make the following approximation:

Vout(t) ≈ Vmax * e^(-t/τ)

In this case, we substitute VmaxT with Φimp, which is the total magnetic flux in the circuit.

Rearranging the equation, we get:

Vout(t) ≈ Φimp * e^(-t/τ)

This approximation is valid when the time interval T is very small compared to the time constant τ of the circuit and when the maximum voltage is sufficiently high.

The time constant τ is determined by the values of inductance (L) and resistance (R) in the circuit. It represents the characteristic time scale over which the current and voltage in the circuit change in response to a voltage or current input.

Therefore, in the given scenario, when T is very small and Vmax is high, we can approximate the output voltage Vout(t) in the series RL circuit by the equation: Vout(t) ≈ Φimp * e^(-t/τ), where τ = L/R.

Note: The symbol Φimp in the equation represents the total magnetic flux in the circuit.

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A ball is thrown at 200 ms-2 and its mass is 0.05kg what force is necessary to change
its direction?

Answers

Answer:

F = 10 [N]

Explanation:

To solve this problem we must use Newton's second law, which tells us that the sum of forces on a body is equal to the product of mass by acceleration.

∑F = m*a

where:

F = forces [N]

m = mass = 0.05 [kg]

a = acceleration = 200 [m/s²]

\(F =m*a\\F = 0.05*200\\F = 10 [N]\)

which of the following graphs shows the motion of an object that starts to travel forward, stops for several seconds, and then returns to its original position

which of the following graphs shows the motion of an object that starts to travel forward, stops for

Answers

Answer:

B

Explanation:

in graph B, you can see that the position increases and remains constant for a while before returning to 0

A 56 kg meteor enters the atmosphere with a whopping46,000,000 Joules of Potential Energy. What height does it enterour atmosphere?

Answers

Given:

Mass (m) = 56 kg

Potential Energy (PE) = 46000000 Joules

Let's find the height the meteor enters our atmosphere.

To find the height, apply the Potential Energy formula below:

\(PE=m\ast g\ast h\)

Since we are to find the height(h), rewrite the equation for h:

\(h=\frac{PE}{m\ast g}\)

Where:

g is the acceleration due to gravity = 9.8 m/s^2

Input values into the equation:

\(\begin{gathered} h=\frac{46000000}{56\ast9.8} \\ \\ h=\frac{46000000}{548.8} \\ \\ h=83819.24\text{ m} \end{gathered}\)

Therefore, the height it enters our atmosphere is 83819.24 meters

ANSWER:

83819.2 m

Keyana and Sam are testing the law of conservation of energy. They use the same ball and release it from the same vertical height. Keyana is using a frictionless track, while Sam's track has friction. They discover Keyana's ball had more kinetic energy than Sam's when it reached the bottom. Which statement best explains why this happened if energy is conserved? Sam's ball lost mass as it traveled along the track. Sam's ball interacting with the track converted energy into heat. Keyana's ball was able to gain momentum. Keyana's ball had more potential energy.

Answers

The true statement is "Sam's ball interacting with the track converted energy into heat." The correct option is B.

The law of conservation of energy states that energy cannot be created or destroyed, only transferred or converted from one form to another. This means that the total amount of energy in a closed system remains constant.

The friction between Sam's ball and the track caused some of the energy to be lost as heat, while Keyana's ball experienced no such loss due to the absence of friction in her experiment. Therefore, Keyana's ball retained more of its initial potential energy as kinetic energy, resulting in a greater velocity and hence more kinetic energy at the bottom.

Option A (Sam's ball lost mass as it traveled along the track) is not true because it is not possible for the ball to lose mass during the experiment. The mass of the ball is a constant value and is not affected by the experiment.

Option C (Keyana's ball was able to gain momentum) is not the best explanation because momentum is not conserved in this scenario since external forces like friction are acting on the ball. The ball is only gaining kinetic energy.

Option D (Keyana's ball had more potential energy) is not true because both Keyana and Sam released the ball from the same vertical height. Therefore, both balls had the same initial potential energy. The difference in their kinetic energies at the bottom can be explained by the difference in their conservation of energy due to friction.

Therefore, The correct statement that best explains why Keyana's ball had more kinetic energy than Sam's when it reached the bottom, even though energy is conserved, is: Sam's ball interacting with the track converted energy into heat.

To learn more about the conservation of energy click:

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