The maximum value of the electric field for sunlight at Earth's surface with a typical intensity of 735 W/m² is approximately 597.9 V/m.
To calculate the maximum value of the electric field for sunlight at Earth's surface with a typical intensity of 735 W/m², we need to use the formula for the intensity of an electromagnetic wave:
Intensity (I) = (1/2) * ε₀ * c * E²
Where:
- Intensity (I) = 735 W/m²
- ε₀ is the vacuum permittivity (approximately 8.85 × 10^-12 C²/N·m²)
- c is the speed of light in a vacuum (approximately 3 × 10^8 m/s)
- E is the maximum value of the electric field
Rearranging the formula to solve for E:
E = √(2 * I / (ε₀ * c))
Plugging in the given values:
E = √(2 * 735 / (8.85 × 10^-12 * 3 × 10^8))
E ≈ 597.9 V/m
So, the maximum value of the electric field for sunlight at Earth's surface with a typical intensity of 735 W/m² is approximately 597.9 V/m.
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There are planets in the universe without a parent star. most all stars have planets. most stars are binary. true false
True : yes there are planets in the universe without a parent star called
rogue planets.
False : most stars are not binary
What is rogue planets ?
planets which do not orbits the planetary system is known as roque planets. For example, pluto. Rogue planets can be smaller and bigger than jupiter too.
Free-floating planets or rogue planets without orbits around stars may also harbor life, some scientists believe. Due to the gravitational effects of giant planets within their system, these planets get kicked out of their system like any other planets formed around stars.
no most stars are not binary, binary which means two stars orbit around the common center and approximately only 40 binary stars have been found till not in our solar system.
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A 50,0 g silver spoon at 20.0°C is placed in a cup of coffee at
90.0°C. How much heat does the spoon absorb from the coffee to
reach a temperature of 89.0°C?
The heat capacity of the silver spoon at the given temperature difference is 817.65 J.
Heat capacity of the silver spoon
The heat capacity of theb silver spoon is the quantity of heat absorbed by the silver spoon. The heat capacity of the silver spoon at the given temperature difference is calculated as follows;
Q = mcΔθ
where;
m is mass of the spoonc is specific heat capacity of silver = 0.237 J/g⁰CΔθ is change in temperatureQ = 50 x 0.237 x (89 - 20)
Q = 817.65 J
Thus, the heat capacity of the silver spoon at the given temperature difference is 817.65 J.
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At what substrate concentration would an enzyme with a km of 0.0050 M operate at one-eighth of its maximum rate? a. 5.8X10M b. 6.4X10 'M c. 7.1 X10M d. 1.2x10-?M
e. 6.1X 10M
At one-eighth of the maximum rate, the reaction velocity (V) is equal to (1/8) * Vmax. Therefore, the substrate concentration at which the enzyme operates at one-eighth of its maximum rate is option (b)6.4 x 10^-6 M
The Michaelis-Menten equation describes the relationship between enzyme activity and substrate concentration. It is given by the equation:
V = (Vmax * [S]) / (Km + [S])
Where V is the reaction velocity, Vmax is the maximum reaction velocity, [S] is the substrate concentration, and Km is the Michaelis constant.
At one-eighth of the maximum rate, the reaction velocity (V) is equal to (1/8) * Vmax. Substituting these values into the Michaelis-Menten equation, we get:
(1/8) * Vmax = (Vmax * [S]) / (Km + [S])
To simplify the equation, we can cancel out Vmax on both sides:
1/8 = [S] / (Km + [S])
Cross-multiplying and rearranging the equation, we have:
8[S] = Km + [S]
7[S] = Km
[S] = Km / 7
Given that Km = 0.0050 M, we can calculate the substrate concentration as:
[S] = 0.0050 M / 7 ≈ 7.14 x 10^-4 M
Therefore, the substrate concentration at which the enzyme operates at one-eighth of its maximum rate is approximately 6.4 x 10^-6 M.
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How much is the velocity of a body when it travels 600m in 5 minutes?( with the full process)
Holly is conducting an experiment in which she changes the voltage across a circuit and records the relative brightness of a light bulb in the circuit. She takes notes in the notebook below.
How might these notes be useful?
A.
They could help her teacher to understand what she did in the experiment.
B.
They could help someone interested in conducting the same experiment.
C.
They could help her remember the experiment in the future.
D.
all of these
Reset Submit
Answer:
all of these
Explanation:
Answer:
D.all of there
Explanation:
rhea, one of saturn's moons, has a radius of 764 km and an acceleration due to gravity of 0.265 m/s2 at its surface.calulate it's mas
The mass of Rhea, one of Saturn's moons, can be calculated using its radius and acceleration due to gravity at its surface.
How to calculate the mass of Rhea, a moon of Saturn with known radius and surface gravity?The mass of Rhea, one of Saturn's 62 moons, has a radius of 764 km and an acceleration due to gravity of 0.265 m/s2 at its surface. Using the formula for acceleration due to gravity, GM/R² = g, where G is the gravitational constant, M is the mass of the object (in this case, Rhea), R is the radius of the object (in this case, the radius of Rhea), and g is the acceleration due to gravity at the surface of the object, we can calculate the mass of Rhea to be approximately 2.31 x 10²¹ kg.
This calculation assumes that Rhea has a uniform density throughout its interior, which is a common assumption for small celestial bodies like moons.
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what are the two ways in which technical debt related to velocity
The two ways in which technical debt relates to velocity are slowing down velocity and accelerating velocity.
Technical debt has a significant impact on a team's velocity. On the one hand, having too much technical debt can slow down a team's progress as they take time to address the issue.
On the other hand, having an effective strategy for managing technical debt can help accelerate a team's velocity, allowing them to focus on more complex problems and get more done in less time. Therefore, managing technical debt is an important part of keeping a team's velocity in balance, both in the short and long term.
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Chapter 2section 2.21. In a cathode ray tubeA) electrons pass from the anode to the cathode.B) electrons pass from the cathode to the anode.C) protons pass from the anode to the cathode.D) protons pass from the cathode to the anode.
In Chapter 2 section 2.21, it is stated that in a cathode ray tube, electrons pass from the cathode to the anode. This is because the cathode is negatively charged, while the anode is positively charged.
The flow of electrons is controlled by an electric field between the cathode and anode, which causes the electrons to move towards the anode. Therefore, the correct answer to the question is option B) electrons pass from the cathode to the anode.
In Chapter 2, Section 2.21, regarding a cathode ray tube, the correct answer is B) electrons pass from the cathode to the anode. The cathode emits electrons, which are attracted to the positively charged anode, resulting in the flow of electrons in the tube.
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when resistors 1 and 2 are connected in series, the equivalent resistance is 13.6. when they are connected in parallel, the equivalent resistance is 2.40. what are (a) the smaller resistance and (b) the larger resistance of these two resistors?
The larger resistance is R₂ =12Ω.
Resistance values are expressed in ohms (Ω). when an electron differential exists among terminals, energy will float from excessive to low. Resistance counteracts that waft. The greater the resistance, the lower the current. Conversely, the decrease in the resistance, the extra the modern.
series connection:- R equivalent = R₁ + R₂
R₁ + R₂ = 13.6 Ω
R₁ = 13.6 Ω - R₂
parallel connection:- R equival;ent = R₁R₂ / R₁ + R₂
2.40 = R₁R₂ / R₁ + R₂
2.40 = R₁R₂ / 13.6 Ω
R₁R₂ = 2.40 × 13.6 Ω
R₁R₂ = 32.64 Ω
2.40 = R₁R₂ / R₁ + R₂
R₁ + R₂ = 32.64 Ω / 2.40 Ω
R₁ + R₂ = 13.6.
must be 4.0Ω and 13.6Ω, respectively.
(a) The smaller resistance is R₁ =4.0Ω
(b) The larger resistance is R₂ =12Ω
An electric-powered cutting-edge flows when electrons flow through a conductor, consisting of a metallic cord. The moving electrons can collide with the ions in the steel. This makes it greater tough for the present day to flow, and reasons for resistance.
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"Please include all relevant working out as detailed as possible
and all relevant diagram to find the answer. Much appreciated! I
will upvote! Thank you so much"
Find total response of the system (transient+steady state). Do not solve for coefficients. Determine the frequency of applied force at which resonance will occur? M = 20 kg F, = 90 N Given: -6 rad/s M
Given the following information:Mass of the system, m = 20 kg.Damping coefficient, b = 6 Ns/m.Force, F = 90 N.Frequency of applied force, f = ?Applied force angular frequency, w = 6 rad/s.Forced vibration equation:F(t) = F0 sin(wt)where F0 = 90 N and w = 6 rad/s.Under the action of the force F, the mass m will oscillate.The equation of motion for the mass-spring-damper system is given by:$$\mathrm{m\frac{d^{2}x}{dt^{2}}} + \mathrm{b\frac{dx}{dt}} + \mathrm{kx = F_{0}sin(\omega t)}$$where k is the spring constant.x(0) = 0 and x'(0) = 0.As we have the damping coefficient (b), we can calculate the damping ratio (ζ) and natural frequency (ωn) of the system.Damping ratio:$$\mathrm{\zeta = \frac{b}{2\sqrt{km}}}$$where k is the spring constant and m is the mass of the system.Natural frequency:$$\mathrm{\omega_{n} = \sqrt{\frac{k}{m}}}$$where k is the spring constant and m is the mass of the system.Resonant frequency:$$\mathrm{\omega_{d} = \sqrt{\omega_{n}^{2}-\zeta^{2}\omega_{n}^{2}}}$$At resonance, the amplitude of the system will be maximum when forced by a sinusoidal force of frequency equal to the resonant frequency.Resonant frequency:$$\mathrm{\omega_{d} = \sqrt{\omega_{n}^{2}-\zeta^{2}\omega_{n}^{2}}}$$$$\mathrm{\omega_{d} = \sqrt{(6.57)^{2}-(-2.88)^{2}} = 6.98 rad/s}$$Hence, the frequency of applied force at which resonance will occur is 6.98 rad/s.
The frequency of the applied force at which resonance will occur is ω = 2√5 rad/s.
To determine the frequency of the applied force at which resonance will occur, resonance happens when the frequency of the applied force matches the natural frequency of the system. The natural frequency can be determined using the formula:
ωn = √(K / M),
where ωn is the natural frequency, K is the spring constant, and M is the mass of the system.
Substituting the given values of K = 400 N/m and M = 20 kg into the equation, we can calculate the natural frequency ωn.
ωn = √(400 N/m / 20 kg) = √(20 rad/s²) = 2√5 rad/s.
Therefore, the frequency of the applied force at which resonance will occur is ω = 2√5 rad/s.
The correct question is given as,
M= 20kg
Fo = 90 N
ω = 6 rad/s
K = 400 N/m
C = 125 Ns/m
Determine the frequency of applied force at which resonance will occur?
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If you start with 200 grams of an isotope, how many grams would be left after 40 years if the half-life of the isotope is 10 years?
Answer:
12.5 grams
Explanation:
From the question,
E' = E/2⁽ⁿ/a⁾....................... Equation 1
Where E' = mass left, E = Original mass, n = time, a = half-life.
Given: E = 200 grams, n = 40 years, a = 10 years.
Substitute these values into equation 1
E' = 200/2⁽40/10⁾
E' = 200/2⁴
E' = 200/16
E' = 12.5 grams.
Hence 12.5 grams of the isotope will be left.
The electric potential everywhere on the x y plane isV = 36 / √(x+1)² + y² - 45 / √x² + (y - 2)² where V is in volts and x and y are in meters. Determine the position and charge on each of the particles that create this potential.
For the given electric potential the Positive point charge located at (-1, 0) and Negative point charge located at (0, 2).
To determine the position and charge of the particles that create the given electric potential, we need to analyze the form of the potential function and identify the type and location of the particles that could produce such a potential.
Given the electric potential function:
V = 36 / √(x+1)² + y² - 45 / √x² + (y - 2)²
We observe that the potential is composed of two terms with different square root expressions. Let's analyze each term separately:
Term 1: 36 / √(x+1)² + y²
This term suggests the presence of a point charge with a positive charge since the potential is inversely proportional to the distance (square root of the distance). However, the charge is not located at the origin (0,0) but rather at (-1,0) because of the presence of (x+1) in the denominator. Therefore, there is a positive point charge located at (-1, 0).
Term 2: -45 / √x² + (y - 2)²
This term also suggests the presence of a point charge, but with a negative charge since the potential is negative. The charge is not located at the origin but rather at (0,2) due to the presence of (y-2) in the square root expression. Therefore, there is a negative point charge located at (0, 2).
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How does the euglena differ from the paramecium? Question 20 options: Euglena are photosynthetic. Paramecia use flagella to move. Paramecia have an "eye spot" to detect light. Euglena have both a macronucleus and a micronucleus
Answer: Euglena are photosynthetic
Explanation: USA test prep
If a stream drops 45 meters in 15 kilometers, what is its gradient? a) 333.3
meters per kilometer b) 0.33 meters per kilometer c) 3 meters per kilometer d) 0.003 meters per kilometer
To calculate the gradient of the stream, we need to determine the change in elevation per unit of horizontal distance.
In this case, the stream drops 45 meters over a horizontal distance of 15 kilometers. To find the gradient, we divide the vertical drop (45 meters) by the horizontal distance (15 kilometers). However, to ensure consistent units, we convert the 15 kilometers to meters by multiplying it by 1,000 (since there are 1,000 meters in a kilometer).
So, the calculation becomes:
Gradient = Vertical drop / Horizontal distance
= 45 meters / (15,000 meters)
= 0.003 meters per meter
This means that for every meter of horizontal distance, the stream drops by 0.003 meters vertically. Simplifying the expression, we can also express it as 3 millimeters (mm) per meter.
Therefore, the correct answer is d) 0.003 meters per kilometer.
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A bullet of mass 10g moving horizontally at a speed of 140m/s strikes a block of mass 100g attached to a string like a simple pendulum. The bullet penetrates the block and emerges then on the other side. If the block rises by 80cm, then find the final velocity of bullet.A 80m/sB 100m/sC 120m/sD 140m/s
The final velocity of the bullet is 120 m/s. The answer is option C.
To solve this problem, we can use the conservation of energy and momentum principles.
Since the block rises to a height of 80 cm, we know that the initial kinetic energy of the bullet is equal to the potential energy gained by the block, given by mgh, where m is the mass of the block, g is the acceleration due to gravity, and h is the height of the rise.
Therefore, we can write:
(1/2)m_bullet * v_bullet² = m_block * g * h
where m_bullet is the mass of the bullet, and v_bullet is its final velocity.
To find the final velocity of the bullet, we need to use the conservation of momentum principle. Since the bullet is initially moving horizontally, and the block is initially at rest, the momentum of the system is equal to the momentum of the bullet.
After the collision, the bullet and block move together as a single system. Therefore, we can write:
m_bullet * v_bullet = (m_bullet + m_block) * v_final
where v_bullet is the initial velocity of the bullet, m_bullet and m_block are the masses of the bullet and block, respectively, and v_final is the final velocity of the combined bullet and block system.
Solving the two equations simultaneously, we can find that the final velocity of the bullet is v = 120 m/s, which corresponds to option C.
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a 0.210-kg ball is orbiting on the end of a thin string in a circle of radius 1.10 m with an angular speed of 10.4 rads/s. determine the angular momentum.
The angular momentum is 2.705 kg m²/s.
The angular momentum can be calculated using the formula;
angular momentum = moment of inertia × angular speed given;
the mass of the ball, m = 0.210 kg
The radius of the circle, r = 1.10 m
Angular speed, ω = 10.4 rad/s
The moment of inertia for a point mass moving in a circle is given by the formula;
a moment of inertia, I = mr²The moment of inertia of the ball is therefore;
I = mr² = 0.210 × (1.10)² = 0.2601 kg m²
angular momentum, L = moment of inertia × angular speed
L = I × ωL = 0.2601 × 10.4 = 2.705 kg m²/s.
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Question 4 of 10
Which statement describes the path of electrons from a battery to a circuit?
O A. Electrons move through the battery from the positive terminal to
the negative terminal and then into the circuit.
OB. Electrons move away from the positive end of a battery and then
through the circuit toward the negative end of the battery.
O C. Electrons move away from the negative end of a battery and then
through the circuit toward the positive end of the battery.
OD. Electrons move through the battery from the negative terminal to
the positive terminal and then into the circuit.
SUBMIT
Which statement describes the path of electrons from a battery to a circuit?
The correct answer would be:
C. Electrons move away from the negative end of a battery and then
through the circuit toward the positive end of the battery.
a sailor drops a wrench from the top of a sailboat's vertical mast while the boat is moving rapidly and steadily straight forward. where will the wrench hit the deck?
If the boat is truly moving at a constant pace, the answer is B. This is due to the fact that it still has the boat's velocity. The path taken by the wrench will appear to a stationary observer who is not on the boat to be a parabola.
What is the straightforward definition of velocity?The displacement an object and particle experiences with regard to time is expressed vectorially as velocity. The meter per second (m/s) is the accepted unit of velocity magnitude, sometimes referred to as speed.
What is a good illustration of velocity?Simply said, velocity is the rate of movement in a specific direction. like the speed of the a car driving north on the a highway or the pace at which a rocket takes off.g.
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A particle moves along the x-axis so that at any time t>2, its position is given by x(t)=(t−2)ln(t−2) What is the acceleration of the particle when the velocity is zero?
• 0
• 1
• 1+e−1
• There is no such value of t.
• e
The acceleration of the particle is zero for all values of t(option 5th), so there is no such value of t when the velocity is zero and the acceleration is nonzero.
Here are the steps to solve the problem:
The velocity of the particle is given by:
v(t) = (t - 2) * ln(t - 2) + 1
The acceleration of the particle is given by:
a(t) = (1 - 2ln(t - 2)) / (t - 2)
For the acceleration to be zero, the velocity must be equal to zero.
Setting v(t) = 0, we get:
(t - 2) * ln(t - 2) + 1 = 0
This equation has no real solutions, so there is no value of t such that the velocity is zero and the acceleration is nonzero.
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what is the mass of this portion? express your answer in terms of the variables m , l , and r .
Using the formula m = ρV, we can express the mass in terms of the variables m, l, r, and ρ as m = ρπr²l.
To calculate the mass of this portion, we need to know the density of the material it is made of. Let's assume the density is represented by the variable ρ.
The formula to calculate the mass of a portion of a solid object is:
m = ρV
where V represents the volume of the portion.
For a cylindrical portion with length l, radius r, and height h, the volume can be calculated as follows:
V = πr²h
If we assume that the portion in question is a cylindrical slice with height h, then we can calculate the volume as follows:
V = πr²h = πr²l
Therefore, the mass of the portion can be calculated as follows:
m = ρV = ρπr²l
So, the mass of the portion can be expressed in terms of the variables m, l, r, and ρ as follows:
m = ρπr²l
In summary, to calculate the mass of the portion, we need to know its density and dimensions (length, radius, and height).
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The gravitational acceleration on Earth is 9.8 m/s2. What is the weight of a car on Earth (to the nearest whole number) if it has a mass of 1360 kg? 14 N 139 N 1333 N 13,328 N
Weight = (mass) x (gravitational acceleration where the mass is)
Weight = (1360 kg) x (9.8 m/s²)
Weight = 13,328 kg-m/s²
That's 13,328 Newtons
Given:-
Mass (m) of the car = 1360 kgAcceleration due to gravity (g) = 9.8 m/s²To Find: Weight (W).
We know,
W = mg
where,
W = Weight,m = Mass &g = Acceleration due to gravity.Thus,
W = (1360 kg)(9.8 m/s²)
→ W = 13,328 N (D)
Suppose a 50.0 g block of silver (specific heat = 0.2350 J/g·°C) at 100.°C is placed in contact with a 50.0 g block of iron (specific heat = 0.4494 J/g·°C) at 0.00°C, and the two blocks are insulated from the rest of the universe. The final temperature of the two blocks will be:
Answer:
34.34 °C
Explanation:
From the question,
Heat lost by the silver block = heat gained by the iron block.
cm(x-y) = c'm'(y-z)................... Equation 1
Where c = specific heat capacity of the silver block, m = mass of the silver block, c' = specific heat capacity of the iron, m' = mass of the iron. x = initial temperature of the silver block, z = initial temperature of the iron, y = final temperature of the mixture.
make y the subject of the equation
y = (cmx+c'm'z)/(cm+c'm')............... Equation 2
Given: c = 50 g, c = 0.2350 J/g·°C, x = 100°C, m' = 50 g, c' = 0.4494 J/g.°C, z = 0°C
Substitute these values into equation 2
y = [(50×0.2350×100)+(50×0.4494×0)]/[(50×0.2350)+(50+0.4494)]
y = 1175/(11.75+22.47)
y = 1175/34.22
y = 34.34 °C
An alternating-current (AC) source supplies a sinusoidally varying voltage that can be described with the function v of t is equal to V times cosine of begin quantity omega times t end quantity, where V is the maximum voltage, omega is the angular frequency, and t is the time. If the frequency of this source is 60 Hz, what is omega equal to
Answer:
ω, the angular frequency of the source equals 377 rad/s
Explanation:
From the question, V(t) = V cosωt.
Now, ω = the angular frequency of the sinusoidal wave is given by
ω = 2πf where f = the frequency of the source = 60 Hz
So, the angular frequency of the source ,ω = 2π × the frequency of the source.
So, ω = 2πf
ω = 2π × 60 Hz
ω = 120π rad/s
ω = 376.99 rad/s
ω ≅ 377 rad/s
So, ω, the angular frequency of the source equals 377 rad/s
A measure of the number of links between one object and another object in a relationship is called the _______.
A measure of the number of links between one object and another object in a relationship is called the cardinality.
The number of cardinal (fundamental) members of a set is referred to as cardinality. A non-negative integer can have a limited or infinite degree of cardinality. For instance, the number of people living in the United States has a cardinality of about 270,000,000, whereas the number of integers has an unbounded cardinality.
Think about set A. If A only contains a limited number of elements, then A's cardinality is equal to A's element count. For instance, |A|=5 if A=2,4,6,8,10.
The empty set has a cardinality of 0, which is zero. When we write #=0, it means either "the cardinality of the empty set is zero" or "the empty set has no elements."
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What are positive relationships of the great white shark called?
Answer:
parasitic relationship, mutualistic relationship, and the commensalistic relationship
Explanation:
those are what they are called
a wagon has a mass of 12 kg it has an acceleration of 3 m/s/s 2 what is the net force that was required for the wagon to have this acceleration
Pls pls pls help me solve this problem
Answer:
\(\boxed {\boxed {\sf 36 \ Newtons}}\)
Explanation:
According to Newton's Second Law of Motion, force is the product of mass and acceleration.
\(F=m \times a\)
The mass of the wagon is 12 kilograms and the acceleration is 3 meters per square second.
m= 12 kg a= 3 m/s²Substitute the values into the formula.
\(F= 12 \ kg \times 3 \ m/s^2\)
Multiply.
\(F= 36 \ kg*m/s^2\)
1 kilogram meter per square second ( 1 kg*m/s²) is equal to 1 Newton (N)Our answer of 36 kg*m/s² is equal to 36 N\(F= 36 \ N\)
The force required for the 12 kilogram wagon to accelerate at 3 meters per square second is 36 Newtons.
The phases of the moon are caused by which of the following
A. Earths rotation around its axis
B. Earths orbit around the sun
C. The moons orbit around the earth
D. Earths shadow falling on the moon
Answer: C: The moons orbit around the earth.
Explanation:
An 80.8kg man is standing on a frictionless ice surface when he throws a 2.3kg book at 11.8m/s. with what velocity does the man move across the ice?
The man moves across the ice with a velocity of -1 m/s.
Formula:
To calculate the velocity we would be using the formula,
M₁U₁ + M₂U₂ = M₁V₁+ M₂V₂
Given:
After applying the law of linear momentum, we get the following value before the throw;
M₁ = Man's initial mass= 80kg,
U₁ = Initial velocity of Man = 0,
M₂= Initial mass of Book = 4kg,
U₂= Initial velocity of Book = 0.
After the throw, the book's velocity will be
M₁ = Man final mass = 80kg,
V₁ = Man's final velocity = V.
M₂ = Final mass of Book = 4kg,
V₂ = Final velocity of Book = 20 m/s
After substituting the values in the formula, we get,
M₁U₁ + M₂U₂ = M₁V₁+ M₂V₂
Or, (80 x 0) + (4 x 0) = (80V) + (4 x 20)
Or, 0 = 80V + 80
Or, 80V = -80
Or, V = -80/80
V= -1m/s
[Note: The -ve sign shows the opposite direction]
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Take some time to research a utility plant. If there is one in your area, you may even visit it. Otherwise, look up a type of plant that produces energy - such as a nuclear power plant, a hydroelectric plant, or a coal-burning plant. Find out what energy resources are brought into the plant. Then find out what energy and what “waste” is produced by the plant. Describe how the two Laws of Thermodynamics apply to what you find out in your research. Be thorough. You will be using the information you gather to engage in a debate with your class about thermodynamics.
Answer:
bro we cant do this
Explanation:
Answer:
The energy resource brought into a coal power plant is coal.
Found the answer at: https://www.tva.com/energy/our-power-system/coal/how-a-coal-plant-works#:~:text=Coal%2Dfired%20plants%20produce%20electricity,to%20start%20the%20process%20over.
The waste produced by coal power plants is coal ash and the energy produced by coal power plants is electricity.
Answers found at: http://www.groundtruthtrekking.org/Issues/AlaskaCoal/Coal-Ash-Combustion-Wastes.html and https://www.tva.com/energy/our-power-system/coal/how-a-coal-plant-works#:~:text=Coal%2Dfired%20plants%20produce%20electricity,to%20start%20the%20process%20over.
The two laws of thermodynamics apply to what I found out in my research because I know that the entropy increase due to the combustion of conventional fuels is much larger than that resulting from that of nuclear fuels, and is therefore much more dangerous. Also, I know that heat is used to burn coal and create energy.
Found answer at: https://www.encyclopedie-energie.org/en/energy-consumption-and-entropy-release-in-the-biosphere/
Explanation:
Hope this helps, i got an okay score on it but better than nothing i guess lol
What are the primary colors? What are the secondary colors?
Color Basics
Three Primary Colors (Ps): Red, Yellow, Blue.
Three Secondary Colors (S'): Orange, Green, Violet
Answer:
Color Basics
Three Primary Colors (Ps): Red, Yellow, Blue.
Three Secondary Colors (S'): Orange, Green, Violet.
Six Tertiary Colors (Ts): Red-Orange, Yellow-Orange, Yellow-Green, Blue-Green, Blue-Violet, Red-Violet, which are formed by mixing a primary with a secondary.
Explanation:
i added the tertiary colors just in case you need it hoped this helped