The mode of the data at the call center will be 15 which are the non urgent s that was received.
What is the mode of a data set?The mode of a data set is defined as the value of the set of data that appeared or occurred the most. When two values have the same number of occurrences or frequency, it is said that the data set is bimodal or has two modes.
From the scenario given,
The number of calls received in a day = 20 calls.
The number of calls that are urgent = 5
The number of calls that are not urgent = 15
Therefore, the mode of this data set would be the number of non urgent calls which is 15.
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Let X and Y be discrete random variables with finite sample spaces {x1,...,xK} and {y1,...,yK], and let pij = [X = xi and Y = Yj]. Use the definition of E[], V ar(), and summation notation , to show E[aX + bY + c] = aE[X] + bE[Y] + c Var(aX + bY + c) = aVar(X) + 2abCov(X, Y) + b2 Var(Y) If X and Y are independent, then E[X]y = y] = E [X], for any y.
Answer:
E[X|Y = y] = E[X] (by the definition of independence)
Step-by-step explanation:
How to find linearity of the expected value?To show that E[aX + bY + c] = aE[X] + bE[Y] + c, we can use the linearity of the expected value:
E[aX + bY + c] = E[aX] + E[bY] + E[c] (by linearity of E[ ])
= aE[X] + bE[Y] + c (since E[c] = c for any constant c)
To show that Var(aX + bY + c) = aVar(X) + 2abCov(X, Y) + b2Var(Y), we can use the definition of variance:
Var(aX + bY + c) = E[(aX + bY + c - E[aX + bY + c])^2]
= E[((aX - aE[X]) + (bY - bE[Y]) + c)^2]
= E[(aX - aE[X])^2] + E[(bY - bE[Y])^2] + E[c^2]
+ 2aE[(aX - aE[X])(bY - bE[Y])] + 2cE[aX - aE[X]] + 2cE[bY - bE[Y]]
= a^2 E[(X - E[X])^2] + b^2 E[(Y - E[Y])^2] + c^2 + 2abE[(X - E[X])(Y - E[Y])]
+ 2ac(aE[X] - aE[X]) + 2bc(E[Y] - E[Y])
= aVar(X) + b^2Var(Y) + 2abCov(X, Y)
Finally, if X and Y are independent, then Cov(X, Y) = 0, so:
E[X|Y = y] = E[X] (by the definition of independence)
This means that the expected value of X given a particular value of Y is simply the expected value of X, regardless of the value of Y.
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William Beville's Computer Training School in Richmond stocks notebooks for sale and would like to reduce its inventory cost by determining the optimal number of notebooks to order in each order. The ordering cost for each order is $27. The annual demand is 19455 units. The annual cost of holding each unit is $6. Each notebook costs $12. The school has a year of 250 working days. When a new order of notebooks is made, the supplier takes 4 days to deliver it.1. What inventory management model should we use to solve this problem?
Model Economic Quantity to Order
Model for discount purchases
Model Economic Quantity to Produce
Model to handle dependent demand
2. What is the optimal number of notebooks to make in each order? 3. What is the annual ordering cost (AOC)? 4. What is the Annual Holding Cost (AHC)? 5. What is the annual product cost (APC)? 6. What is the annual total cost of managing inventory (ATC) 7. What would be the total number of orders in the year (N)? 8. What would be the estimated time between each order (T)? 9. What is the daily demand? 10. What is the reorder point (ROP)? ____
units.
The inventory management model that should be used to solve this problem is the Model Economic Quantity to Order (EOQ) model. The optimal number of notebooks to make in each order is 590 units. The annual ordering cost (AOC) is approximately $892.20. The Annual Holding Cost (AHC) is $3540. The annual product cost (APC) is $233,460. The annual total cost of managing inventory (ATC) is approximately $237,892.20. The total number of orders in the year (N) is 33. The estimated time between each order (T) is approximately 7.58 days. The daily demand is approximately 77.82 units. The reorder point (ROP) is approximately 311 units.
The inventory management model that should be used to solve this problem is the Model Economic Quantity to Order (EOQ) model.
To find the optimal number of notebooks to make in each order, we can use the EOQ formula:
EOQ = √[(2 * Demand * Ordering Cost) / Holding Cost]
EOQ = √[(2 * 19455 * 27) / 6]
EOQ ≈ 589.96
Since the number of notebooks must be a whole number, the optimal number to order would be 590 notebooks.
The annual ordering cost (AOC) can be calculated by dividing the annual demand by the EOQ and multiplying it by the ordering cost:
AOC = (Demand / EOQ) * Ordering Cost
AOC = (19455 / 590) * 27
AOC ≈ $892.20
The Annual Holding Cost (AHC) is calculated by multiplying the EOQ by the holding cost per unit:
AHC = EOQ * Holding Cost
AHC = 590 * 6
AHC = $3540
The annual product cost (APC) is calculated by multiplying the annual demand by the cost per unit:
APC = Demand * Cost per unit
APC = 19455 * 12
APC = $233,460
The annual total cost of managing inventory (ATC) is the sum of the annual ordering cost, annual holding cost, and annual product cost:
ATC = AOC + AHC + APC
ATC = 892.20 + 3540 + 233460
ATC ≈ $237,892.20
The total number of orders in the year (N) can be calculated by dividing the annual demand by the EOQ:
N = Demand / EOQ
N = 19455 / 590
N ≈ 33
The estimated time between each order (T) can be calculated by dividing the number of working days in a year by the total number of orders:
T = Number of working days / N
T = 250 / 33
T ≈ 7.58 days
The daily demand is calculated by dividing the annual demand by the number of working days in a year:
Daily Demand = Demand / Number of working days
Daily Demand = 19455 / 250
Daily Demand ≈ 77.82 units/day
The reorder point (ROP) is the number of units at which a new order should be placed. It can be calculated by multiplying the daily demand by the lead time (time taken for the supplier to deliver the order):
ROP = Daily Demand * Lead Time
ROP = 77.82 * 4
ROP ≈ 311.28 units
Therefore, the reorder point would be approximately 311 units.
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A trangle has a 30 angle and a 55angle .what is the other angle ?how do you know?
Answer:
95°
Step-by-step explanation:
Sum of 3 angles of a triangle equals to 180°Here we have angles of 30° and 55°, so the remaining angle is:
180° -(30° + 55°) = 95°an ice cream truck that plays loud music is circling bulan's neighborhood. c(t)c(t)c, left parenthesis, t, right parenthesis models the volume of the music (in \text{db}dbstart text, d, b, end text) that bulan hears, ttt minutes after the truck arrives in her neighborhood. here, ttt is entered in radians.
The function c(t) = c(t) = c(t), left parenthesis, t, right parenthesis models the volume of the music (in dB) that Bulan hears t minutes after the ice cream truck arrives in her neighborhood. In this function, t is entered in radians.
The function c(t) represents how the volume of the music changes over time as t increases. The exact shape of the function depends on various factors like the distance between Bulan and the ice cream truck, the truck's speaker system, and any other interfering sounds in the neighborhood.
By analyzing the function c(t), one can determine the maximum and minimum volume levels Bulan experiences as the truck moves around her neighborhood. Additionally, the periodic nature of the function suggests that the music will repeat itself after a certain time interval.
In conclusion, the function c(t) = c(t) = c(t), left parenthesis, t, right parenthesis provides a mathematical representation of the volume of the music that Bulan hears as a function of time. This function helps us understand the changing volume levels and the periodicity of the ice cream truck's music in her neighborhood.
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So confused on how to do these kinda problems
An equation of the line that passes through the given point and is
(a) parallel to is y = -3x - 7
(b) perpendicular to is y = (1/3)x + 1/3.
How to write an equation of a line?a) Parallel line
The slope of the given line is -3. The slope of a parallel line is also -3. So, the equation of the parallel line will be of the form:
y = -3x + b
Plug the point (-2, -1) into this equation to solve for b, the y-intercept.
-1 = -3(-2) + b
-1 = 6 + b
-7 = b
Therefore, the equation of the parallel line is:
y = -3x - 7
b) Perpendicular line
The slope of a perpendicular line is the negative reciprocal of the slope of the given line. The slope of the given line is -3, so the slope of the perpendicular line is 1/3. So, the equation of the perpendicular line will be of the form:
y = (1/3)x + b
Plug the point (-2, -1) into this equation to solve for b, the y-intercept.
-1 = (1/3)(-2) + b
-1 = -2/3 + b
1/3 = b
Therefore, the equation of the perpendicular line is:
y = (1/3)x + 1/3
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consider the points a(0,3,−5), b(3,−5,0) and c(3,0,−5). find the exact distance from a to the line passing through b and c.
The distance from a to the line passing through b and c is 7/5.
To find the distance from a point to a line, you can use the cross product and the dot product.
First, find the vector pointing from a to b and the vector pointing from b to c:
u = b - a = (3, -5, 0) - (0, 3, -5) = (3, -8, 5)
v = c - b = (3, 0, -5) - (3, -5, 0) = (0, 5, -5)
Next, find the cross product of these two vectors, which gives a vector orthogonal to the plane defined by the line:
n = u x v = (-40, 0, 40)
Finally, find the dot product of n and a - b, which gives the magnitude of the projection of a - b onto n:
d = |n . (a - b)| / |n| = |(-40, 0, 40) . (-3, -8, -5)| / |(-40, 0, 40)| = 57 / √(40^2 + 40^2) = 57 / √1600 = 57 / 40 = 7/5
Therefore, the distance from a to the line passing through b and c is 7/5.
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The absolute maximum -3 less than or equal to x less than or equal to 3
Answer:
Equal to
Step-by-step explanation:
BTW WTH does OBJ MEAN????????(3x2y) 3
Evaluate the expression
Answer:
27x ^6 y ^3
Step-by-step explanation:
Answer:
\(27x^{6} y^{3}\)
Step-by-step explanation:
\((3x^{2} y)^{3}\)
→ Write out as a multiplication
\(3x^{2} y*3x^{2} y*3x^{2} y\)
→ Simplify
\(27x^{6} y^{3}\)
The distance between Prague and Vienna is 254 km. The local time in Prague is the same as the local time in Vienna. Calculate the average speed of the train
Answer: 56.44 km/h
Step-by-step explanation:
Speed = Distance / Time
Time = 1950 - 1520 = 4 hours 30 minutes = 4.5 hours
Speed = 254/4.5
= 56.44 km/h
i will mark u brainlist if u answer find the mistake... 4x + x = 30 –6 4x = 24 4 24 4 4 x x = 6
Answer:
The mistake is that 4x+x = 5x not 4x
Step-by-step explanation:
4x + x = 30 –6
Combine like terms
5x = 24
Divide each side by 5
5x/5 = 24/5
x = 24/5
The mistake is that 4x+x = 5x not 4x
The city plans a new road that will be parallel to Village Way and pass through the intersection of Gray Dr and Canon Rd. What is the equation of the road in slope-intercept form?
The equation line of the of the road in slope-intercept form is; y = 2·x - 10
What is the standard form of the equation of a line?The standard form of the equation of a line is Ax + Bx + C, where A, B, and C are constants and A and B are nonzero numbers.
The parameters for the new road are;
The road will be parallel to village way with points (0, 5), and (-4, -3)
The road will pass through the intersection of Gray Dr and Canon Rd., which is the point with coordinates (3, -4)
Required; The equation of the road
Since the new road is parallel to Village Way, which has slope;
m = (5 - (-3))/(0 - (-4)) = 8/4 = 2
The slope of the new road will also be 2.
Let the equation of the new road be y = m·x + c, where m = 2 is the slope we just found. To find c, we use the fact that the road passes through the point (3, -4);
y - (-4) = 2 × (x - 3)
y = 2·x - 6 - 4 = 2·x - 10
y = 2·x - 10
Therefore, c = -10
Therefore, the equation of the new road in slope-intercept form, therefore is; y = 2·x - 10
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plot the normal probability plot and the residual plot vs x. what do you infer from them? harrisburg
To obtain the residuals from the fit in 8.4a and plot them against y and x, as well as prepare a normal plot, we need the specific details of the fit and the data used.
WE know that residuals represent the differences between the observed values and the predicted values from a statistical model or regression analysis.
Since the residuals against y and x can help identify patterns or trends in the data that may indicate issues with the model's fit.
A normal plot, known as a Q-Q plot, compares the distribution of the residuals to a theoretical normal distribution. If the residuals closely follow a straight line in the normal plot, the residuals are normally distributed, which is an assumption of many statistical models.
Interpreting these plots involves examining the patterns and deviations from expected behavior. If the residuals exhibit a consistent pattern, it might indicate that the model does not capture all the relevant information in the data.
Thus if the residuals appear randomly scattered around zero with no discernible pattern, it suggests that the model adequately explains the data. Deviations in the normal plot may indicate departures from the assumption of normality in the residuals, which could impact the reliability of statistical inferences.
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Write the ratios for sin A and cos A.
A
26
B
10
C
24
Not drawn to scale
please help im desperate!!!
Answer:
1st one = 4th option
2nd one = 3rd option
Step-by-step explanation:
can anyone answer this with expanation?
18. ∆PQR =~ ∆RPA ( by SAS )
19. ∆DQR =~ ∆PQR ( by AAS )
20. ∆ARO =~ ∆PQO ( by AAS )
Help me please Hurry
Answer: y=mx+b
Step-by-step explanation:
Fill out the Rate column in the table below.
a = b=
The rate column will be:
A= 30
B= 20
C= x miles
D= x miles
What is rate?It should be noted that rate simply means the measure, quantity, or frequency that one measure against another quantity or measure.
In this case, Jorden drives to the store at 30 miles per hour and on her way home she averages only 20 miles per hour.
Therefore, the rate column will be:
A= 30
B= 20
C= x miles
D= x miles
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Fill out the Rate column in the table below. Jorden drives to the store at 30 miles per hour. On her way home she averages only 20 miles per hour. If the total driving time takes half an hour, how far does she live from the store? Fill out the Rate column in the table below. a = b =
Complete the following equation <, >, or = 3.20_ 3.02
Answer:
Step-by-step explanation:
Complete the following equation using , or = 3.20 ___ 3.02 A.
The following equation 3.20 > 3.02
Somebody please help meee!!!!
Answer:
\(area = 4\pi {r}^{2} \\ = 4 \times 3.14 \times {7.5}^{2} \\ = 706.86 \: {cm}^{2} \)
When Stephane plays chess against his favorite computer program he wins with probability 0.60 loses with probability 0.10 and 30% of the games result in a draw. Assume independence.
O Find the probability that Stephane wins 7 games if he plays 10 games.
The probability that Stephane wins 7 games out of 10 is 0.215 or about 21.5%.
We can model the number of games Stephane wins out of 10 as a binomial distribution with parameters n = 10 (number of trials) and p = 0.6 (probability of winning). The probability mass function of a binomial distribution is:
P(X=k) = (n choose k) * p^k * (1-p)^(n-k)
where (n choose k) = n! / (k! * (n-k)!) is the binomial coefficient.
To find the probability that Stephane wins 7 games out of 10, we can plug in k=7, n=10, and p=0.6 into the formula:
P(X=7) = (10 choose 7) * 0.6^7 * 0.4^3
= 120 * 0.0279936 * 0.064
= 0.215
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Solve for h.
19 =
h
4
+ 16
h =
Answer:
h=3/4
Step-by-step explanation:
19=h4+16
19-16=h4+16-16
3=h4
3/4=h4/4
3/4=h
h=3/4
Answer:
h = 3/4 or as a decimal it would be 0.75
Step-by-step explanation:
19 = h × 4 + 16
Reorder the terms
Use the communative property to reorder the terms
19 = 4h + 16
19 = 4h + 16
Move the terms
Move the variable to the left - hand side and change its side
19 - 4h = 16
Move the constant to the right - hand side and change its sign
-4h = 16 - 19
-4h = 16 - 19
Calculate
calculate the difference of 16 minus 19
-4h = -3
-4h = -3
Divide both sides of the eqaution by -4
Therefore your answer is h = 3/4 or if you want a decimal simplify 3/4 by dividing 3 and 4, which gives you 0.75
need help asap. low geometry grade
Answer:
x=9.3
Step-by-step explanation:
use SohCahToa
in this case u use cos
cos(41°)=7/x
x=7/cos(41)
x=9.275090953
x=9.3
2.A truck driver maintains a constant speed of 65 miles per hour on a stretch of highway that lasts 130 miles. Graph the remaining distance as a function of the time driven in hours.(1 point)
a.The horizontal axis labeled Hours Driven goes from 0 to 15 in increments of 1 and the vertical axis labeled Miles Remaining goes from 0 to 150 in increments of 10. The line segment starts at left parenthesis 0 comma 130 right parenthesis, passes through left parenthesis 1 comma 65 right parenthesis, and ends at left parenthesis 2 comma 0 right parenthesis.
b.The horizontal axis labeled Hours Driven goes from 0 to 15 in increments of 1 and the vertical axis labeled Miles Remaining goes from 0 to 150 in increments of 10. The line starts at left parenthesis 2 comma 0 right parenthesis, and passes through left parenthesis 3 comma 65 right parenthesis and left parenthesis 4 comma 130 right parenthesis.
c.The horizontal axis labeled Hours Driven goes from 0 to 15 in increments of 1 and the vertical axis labeled Miles Remaining goes from 0 to 150 in increments of 10. The line starts at left parenthesis 0 comma 0 right parenthesis, and passes through left parenthesis 1 comma 65 right parenthesis and left parenthesis 2 comma 130 right parenthesis.
d.The horizontal axis labeled Hours Driven goes from 0 to 15 in increments of 1 and the vertical axis labeled Miles Remaining goes from 0 to 150 in increments of 10. The line segment starts at left parenthesis 0 comma 130 right parenthesis, passes through left parenthesis 2 comma 65 right parenthesis, and ends at left parenthesis 4 comma 0 right parenthesis.
3.Tayson walked for 8 minutes before running n laps around a track. Tayson takes 1 minute and 45 seconds to run each lap. What is the graph of the function that relates the amount of time, T, in minutes Tayson walked or ran after running n laps?(1 point)
A.A function is graphed on a first quadrant coordinate plane. The horizontal axis labeled Laps goes from 0 to 10 in increments of 1. The vertical axis labeled Time in minutes goes from 0 to 35 in increments of 1. A line starts at (0, 5) and passes through (2, 17) and (5, 35).
B.A function is graphed on a first quadrant coordinate plane. The horizontal axis labeled Laps goes from 0 to 10 in increments of 1. The vertical axis labeled Time in minutes goes from 0 to 35 in increments of 1. A line starts at (0, 8), and passes through (4, 11) and (8, 14).
C.A function is graphed on a first quadrant coordinate plane. The horizontal axis labeled Laps goes from 0 to 10 in increments of 1. The vertical axis labeled Time in minutes goes from 0 to 35 in increments of 1. A line starts at (0, 8), and passes through (4, 15).
D.A function is graphed on a first quadrant coordinate plane. The horizontal axis labeled Laps goes from 0 to 10 in increments of 1. The vertical axis labeled Time in minutes goes from 0 to 35 in increments of 1. A line starts at (0, 1.75), and passes through (1, 9.75). All coordinates are approximate.
4.Function f(x) has a slope of 32 and a y-intercept of 6. Explain how the graph of f(x) could be used to find the x-intercept.(1 point)
A.Find the x-coordinate of the point that crosses the x-axis. The x-intercept is −4.
B.Find the y-coordinate of the point where x=1. The x-intercept is 152.
C.Use the value of riserun for the function, which is 32.
D.Find the y-coordinate of the point that crosses the y-axis. The x-intercept is 6.
Answer:
The correct option is;
c. The horizontal axis labeled Hours Driven goes from 0 to 15 in increments of 1 and the vertical axis labeled Miles Remaining goes from 0 to 150 in increments of 10. The line starts at left parenthesis (0, 0), and passes through (1, 65) and (2, 130)
Step-by-step explanation:
The given parameters are;
The speed of the truck = 65 miles per hour
The length of the highway = 130 miles
Therefore, from the given information, we have;
The time, t, it will take the truck to arrive at the end of the highway is given as follows;
Time = Distance/speed = 130/65 = 2 hours
Therefore, if the truck timing starts from the point (0, 0), we have;
The points on the straight line (constant) speed graph are;
(0, 0), (1, 65), and (2, 130)
Answer:
C
Step-by-step explanation:
The equation of the ellipse that has a center at ( 3 , 1 ) (3,1), a focus at ( 7 , 1 ) (7,1), and a vertex at ( − 2 , 1 ) (-2,1), is ( x − C ) 2 A 2 + ( y − D ) 2 B 2 = 1 (x-C)2A2+(y-D)2B2=1
Where:
A=
B=
C=
D=
The equation of the ellipse with a center at (3, 1), a focus at (7, 1), and a vertex at (-2, 1) is given by \(\(\frac{{(x - 3)^2}}{{36}} + \frac{{(y - 1)^2}}{{25}} = 1\).\). In this equation, A = 6, B = 5, C = 3, and D = 1.
To find the equation of the ellipse, we need to determine the values of A, B, C, and D in the general form equation \(\[\frac{{(x - C)^2}}{{A^2}} + \frac{{(y - D)^2}}{{B^2}} = 1\]\)for an ellipse. The center of the ellipse is (C, D), so C = 3 and D = 1.
The distance between the center and each focus is given by the value of A, so we can calculate A as the distance between (3, 1) and (7, 1), which is 4. Therefore, A = 4.
The distance between the center and each vertex is given by the value of B, so we can calculate B as the distance between (3, 1) and (-2, 1), which is 5. Hence, B = 5. Plugging these values into the general form equation, we get \(\(\frac{{(x - 3)^2}}{{36}} + \frac{{(y - 1)^2}}{{25}} = 1\)\) as the equation of the ellipse.
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Three people are sitting on a bus. Austin is seated 12 feet directly behind Bernard and 9 feet directly left of Keenan. How far is Bernard from Keenan?
Answer: I would say 21 feet.
Step-by-step explanation:
Bernard is 12 feet ahead of Austin
So add 12 feet to get to Austin first
Then add the 9 feet that is apart from Austin and Bernard
12+9 = 21
21 feet would be the answer
Hope this helps ! ^^
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Which data value is farthest from the mean? How far you is this value from the mean? Round to the nearest hundredths. 34,37,48,32,25,34,35,23,33,30.
Answer:
48; 14.90 or 14.9
Step-by-step explanation:
First you have to take the mean of the data set.
In order to do this, we take the sum of all of the data points and then divide them by the number of values like so...
\(\frac{34+37+48+32+25+34+35+23+33+30}{10}\)
The answer to this is 33.1.
Now we have to find the value furthest from this value. In order to do this, we are going to take the highest (48) and the lowest value(23). Then we compare their distance from 33.1. After this, we can tell that 48 is further from 33.1 than 23 is.
Then for the second part, 48-33.1 = 14.90 and that is how far the value is from the mean.
Find the area of the region inside the circle r=4cos(theta) and outside the circle r=2.
Area of the region inside the circle r=4cos(theta) and outside the circle r=2 is 4π/3 + 2√3
What is the polar curve?A form created using the polar coordinate system is called a polar curve. Points on polar curves have varying distances from the origin (the pole), depending on the angle taken off the positive x-axis to calculate distance. Both well-known Cartesian shapes like ellipses and some less well-known shapes like cardioids and lemniscates can be described by polar curves.
r = 1 − cosθsin3θ
Polar curves are more useful for describing paths that are an absolute distance from a certain point than Cartesian curves, which are good for describing paths in terms of horizontal and vertical lengths. Polar curves can be used to explain directional microphone pickup patterns, which is a useful application. Depending on where the sound is coming from outside the microphone, a directional microphone will take up sounds with varied tonal characteristics. A cardioid microphone, for instance, has a pickup pattern like a cardioid.
The area between two polar curves can be found by subtracting the area inside the inner curve away from the area inside the outer curve.
The figure attached shows the bounded region of the two graphs. The red curve is r=4cos(θ) and the blue curve is r=2.
The points of intersection of the two curves are
θ = π/3 and 5π/3
The area is calculated as follows:
Since the bounded region is symmetric about the horizontal axis, we will find the area of the top region, and then multiply by 2, so as to get the total area.
A = 2 \(\(\int_{0}^{\pi /3}\) ½ (4 cos (θ)² − ½ (2)² dθ
= \(\(\int_{0}^{\pi /3}\) 16 cos2 (θ) − 4dθ
= \(\(\int_{0}^{\pi /3}\) 8 (1+cos(2θ)) − 4dθ
=\(\(\int_{0}^{\pi /3}\) 4 + 8 cos (2θ) dθ
= [4θ + 4sin (2θ)] \(\(\int_{0}^{\pi /3}\)
= 4π/3 + 2√3
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The dot plot shows how many cats are owned by each person in a neighborhood: Dot plot titled Neighborhood Cats and labeled Number of Cats shows number line from 1 to 10. There are 6 dots over 1, 3 dots over 2, 2 dots over 3, 1 dot over 4, 0 dots over 5, 6, 7, 8, and 9, and 1 dot over 10. Is the median or the mean a better measure of center for these data and why
Answer:
Median, because the data are skewed and there is an outlier
Step-by-step explanation:
yo hoped it helped
Create the graph of g(x) on a new set of axes using the graphs of a(x) and d(x). Label your scale and axes.
Answer:
I honestly don't know
Step-by-step explanation:
8182i2o2o
828262781
Evaluate N= -3.3 - n x n
Answer:kk
Step-by-step explanation: