The decline of salmon fisheries along the Columbia River in Oregon has caused great concern among commercial and recreational fishermen. The paper 'Feeding of Predaceous Fishes on Out-Migrating Juvenile Salmonids in John Day Reservoir; Columbia River' (Trans. Amer: Fisheries Soc. (1991: 405-420) gave the accompanying data on y = maximum size of salmonids consumed by a northern squaw fish (the most abundant salmonid predator) and x = squawfish length, both in mm. Here is the computer software printout of the summary: Coefficients: Estimate Std. Error ((Intercept) ~89.010 16.720 [Length 0.704 0.049 t value 55324 14.333 Pr(> Itl) 0.000 0.000 Using this information , give the equation of the least squares regression line and the 95% confidence interval for the slope. a) y =16.720x 89.010; [0.623 , 0.785] b) y =0.704x 89.010; [0.604, 0.804] =0.704x + 16.720; [-121.781,-56.239] y =16.720x + 0.049; [0.349,-54.780] e y =-89.010x + 0.704; [-122.985, -55.035] f) None of the above

Answer and Explanation: The conditions when the net force and the net torque are zero are called static equilibrium.

The correct logarithm form is: a. log5 125 = 3

Question is about finding the logarithm form of 5³ = 125 using the given options.

The correct logarithm form is:

a. log5 125 = 3

Here's the step-by-step explanation:

1. The exponential form is given as 5³= 125.
2. To convert it to logarithm form, you have to express it as log(base) (argument) = exponent.
3. In this case, the base is 5, the argument is 125, and the exponent is 3.
4. Therefore, the logarithm form is log5 125 = 3.

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210 orders are possibe to pass across a bridge.

The number of orders in which 7 cars can cross a bridge that can only accommodate 4 cars at a time can be calculated using the permutation formula.

The formula for permutation is n!/(n-r)! where n is the total number of items and r is the number of items being selected at a time. In this case, n = 7 cars and r = 4 cars at a time.

Thus, the number of orders in which 7 cars can cross the bridge is 7!/(7-4)! = 7!/(3)! = 765 = 210. This means that there are 210 possible orders in which 7 cars can cross the bridge.

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We can convert that 30% into a decimal, as: 0.3 (That's 30/100)

Now, we can multiply this 0.3 by any quantity that we want to calculate 30% from.

For example, let's take Justin's commission:

Adding this to his base salary,

We can conclude that Justin's paycheck for the week would be $1,117.5

Similarly, the expression for Justin's paycheck in a week were he made x dollars in sales is:

The only energy released as a result is equal to two ATP molecules. Organisms can turn glucose into carbon dioxide when oxygen is present. As much as 38 ATP molecules' worth of energy is released as a result.

Why do aerobic processes generate more ATP?

Anaerobic respiration is less effective than aerobic respiration and takes much longer to create ATP. This is so because the chemical processes that produce ATP make excellent use of oxygen as an electron acceptor.

How much ATP is utilized during aerobic exercise?

As a result, only energy equal to two Molecules of ATP is released. When oxygen is present, organisms can convert glucose to carbon dioxide. The outcome is the release of energy equivalent to up of 38 ATP molecules. Therefore, compared to anaerobic respiration, aerobic respiration produces a large amount more energy.

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On solving the provided question, we can say that the inequality is  y+2> -3x-3, Graph the points (0,-5) and (-2,1)

An inequality in mathematics is a relationship between two expressions or values that is not equal. Thus, imbalance leads to inequality. An inequality creates the link between two values that are not equal in mathematics. Egality is distinct from inequality. When two values are not equal, most commonly use the not equal sign (). Different inequalities are used to contrast values, no matter how little or large. Many simple inequalities may be resolved by modifying the two sides until the variables are all that remain. But a number of things contribute to inequality: Negative values on both sides are divided or added. Trade off the left and right.

the inequality is

y+2> -3x-3

y > -3x-5

y = -3x-5

x   y = -3x-5

0   -5

-1   -2

-2   1

Graph the points (0,-5) and (-2,1)

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The target heart rate is strictly increasing then strictly decreasing between 40 and 60 minutes (Option B)

There are three observed intervals shown on the graph and during those three there are times when his heart rate increases, then becomes stable and then decreases.

However, between the intervals of 40 to 60 minutes, there was no point where it was stable or level. It increased rapidly at the 40th minute and at the 50th minute it began to drop rapidly till the 60th minute.

**(Note that when he approached the 70th minute he was already stable and there was no increase or decrease)**

The probability of selecting all bottles of the same variety is P(A) = 6/46656 = 0.00013.

The probability of selecting two bottles of each variety when randomly selecting 6 bottles can be calculated using the formula P(A) = n(A) / n(S), where n(A) is the number of possible ways to select two bottles of each variety and n(S) is the total number of possible ways to select 6 bottles. In this case, n(A) is equal to 6! / (2!2!2!) = 90 and n(S) is equal to 6^6 = 46656. So, the probability of selecting two bottles of each variety is P(A) = 90/46656 = 0.0019.

The probability of selecting all bottles of the same variety when randomly selecting 6 bottles can be calculated using the same formula. In this case, n(A) is equal to 6, which is the number of ways to select 6 bottles of the same variety, and n(S) is equal to 46656. So, the probability of selecting all bottles of the same variety is P(A) = 6/46656 = 0.00013.

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Each model should be produced on a weekly basis to maximize net profit is $75,900.

What is Net profit?

In both business and accounting, net income or profit is an entity's revenue less cost of goods sold, costs, depreciation and amortisation, interest, and taxes for a certain accounting period.

As given,

Number of products sold:

T ≥ 1.5G

Maximize Profit Z = 150T + 130G

Labor Constraint:

Labor hours Available:

Production Department:

Number of labor hours available per day = 58 × 7 = 406

Number of days in a week = 5

Number of lobor ours available per week = 406 × 5 = 2030

Assembly Department:

Number of labor hours available per day = 25 × 7 = 175

Number of days in a week = 5

Number of labor hours available per week = 175 × 5 = 875.

Labor hours Required:

Labor hours required for G1 model:

Labor hours required at Production department = 3.5G

Labor hours required at assembly department = 2G

Labor hours required for T1 model:

Labor hours required at Production department = 4T

Labor hours required at Assembly department = 1.5T

Total labor hours required at Production department = 3.5G + 4T

Total labor hours required at Assembly department = 2G + 1.5T.

Constraint:

Labor hours required ≤ Labor hours Available.

Production department Labor constraint

3.5G + 4T ≤ 2030

Assembly department Labor constraint:

2G + 1.5T ≤ 875

The function:

Maximum Profit Z = 150T +130G

Constraint:

3.5G +4T ≤ 2030

2G + 1.5T ≤ 875

T ≥ 1.5G

Suppose that for example:

10.5G +12T = 6090

 16G + 12T = 7000

Solve both equations simultaneously,

5.5G = 7000 - 6090

5.5G = 910

    G = 910/5.5

    G = 363

Since, T > G

Hence,

T = 363,

G = 165

Calculate Profit:

150T + 130G = 150 × 363 + 130 × 165

                     = 54450 + 21450

                     = 75900

Hence, each model should be produced on a weekly basis to maximize net profit is $75,900.

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Answer:

54 square units

Step-by-step explanation:

Answer:

A) prism B) cone i dont really know the rest

The solution to the system of linear equations is: x = 3.5

y = -4.

If two lines intersect at a point on a coordinate plane, that point represents the solution to the system of linear equations corresponding to those lines. In this case, the lines intersect at the point (3.5, -4).

To determine the solution, we need to find the values of x and y that satisfy both equations. Let's label the equations as Equation 1 and Equation 2.

Equation 1: represents one of the lines on the graph.

Equation 2: represents the other line on the graph.

At the point of intersection (3.5, -4), the x-coordinate represents the value of x that satisfies both equations, and the y-coordinate represents the value of y that satisfies both equations.

Therefore, the solution to the system of linear equations is:

x = 3.5

y = -4

To find the specific equations of the lines, we would need more information or the equations themselves.

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Answer:

30 moviegoers

Step-by-step explanation:

1% of 150 is 1.5

20% of moviegoers recommend the movie

1.5 times 20 = 30

Answer:

The slope is -6 and the y intercept is 0

The statement which correctly describes the number of possible positive zeros and the number of possible negative zeros is

\(f(x)=x^4+2x^3-11x^2-5x-6\)

there is only one sign change

So, there is a maximum of 1 positive zero

\(f(-x) = (-x)^4 + 2(-x)^3 - 11(-x)^2 - 5(-x) - 6\\\\f(-x) = x^6 - 2x^3 - 11x^2 + 5x - 6\)

Sign changes 3 times

So, number of negative zeros is either 3 or 1

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Step-by-step explanation:

To find probability ratio wise

Sports Cars: Total Cars

3 + 3 + 2 = 8 total cars

2 sports cars

Ratio is 2:8

Reduces to 1:4

a) When Lily's age is 20, and Raphael's age is divided by 3 then the expression of Lily's age in terms of h is h < 10.

b) Ethan's age is half of Raphael's age therefore, Ethan's age is half Raphael's age.

a) If Raphael is twice as old as his sister Lily, we can represent their ages as 2h and h, respectively, where h is Lily's age. The sum of their ages is less than 30, so we can write the equation:

2h + h < 30

Combining like terms, we get:

3h < 30

Dividing both sides by 3, we get:

h < 10

This is an expression of Lily's age in terms of h.

b) If Ethan's age is 16, and Raphael's age is twice Ethan's age, we can represent Raphael's age as 2 × 16 = 32.

Ethan's age is 16, which is half of Raphael's age of 32. Therefore, Ethan's age is half of Raphael's age.

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The question is -

Raphael is twice as old as his sister. The sum of their ages is less than 30.

a) Lily's age is 20, and Raphael's age is divided by 3. Write an expression in terms of h for Lily's age.

b) An expression for Ethan's age 16. Write a sentence to describe how Ethan's age compares with Raphael's age.

For the first series, we can use the Limit Comparison Test by comparing it to the series 1/n^2. Specifically, we will take the limit as n approaches infinity of the quotient of the two series:

lim_n->∞ [(n + 7)/(n^3 - 3n + 3)] / (1/n^2)

= lim_n->∞ [(n + 7)/(n^3 - 3n + 3)] * (n^2/1)

= lim_n->∞ [(n^3 + 7n^2)/(n^3 - 3n + 3)]

Since the numerator and denominator both have degree 3, we can apply L'Hopital's rule:

= lim_n->∞ [(3n^2 + 14n)/(3n^2 - 3)]

= lim_n->∞ [3 + 14/n] / [3 - 3/n^2]

= 3/3 = 1

Since the limit is positive and finite, and the series 1/n^2 is known to converge, the original series also converges.

For the second series, we can use the Limit Comparison Test by comparing it to the series 1/n^2. Specifically, we will take the limit as n approaches infinity of the quotient of the two series:

lim_n->∞ [(n^(k-1))/(n^(k+7))] / (1/n^2)

= lim_n->∞ (n^(k-1) * n^2) / (n^(k+7))

= lim_n->∞ n^(k+1) / n^(k+7)

= lim_n->∞ 1/n^6

Since the limit is positive and finite, and the series 1/n^2 is known to converge, the original series also converges.

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Closeness of primary dwelling to farmland as a predictor (in miles) outcome variable: support for animal rights (scale from 0-50) The proper inferential statistic to use is the correlation coefficient.

What is a predictor and response variable?

A predictor variable example is what?

Is a predictor variable dependent or independent?

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The cost of the holiday after the discount has been applied is £1440.

Discount is a reduction in the regular price of a product or service. It is often given when a customer buys multiple items or spends a certain amount of money. Discounts are a common way for businesses to increase sales by incentivizing customers to buy more. Discounts can be a percentage of the regular price, a fixed amount, or a free gift with purchase. Discounts can be applied to items already on sale or can be applied to the full price of an item.

The customers will receive a 20% discount on the cost of the holiday, which is 20% of £1800, which is £360.
Therefore, the cost of the holiday after the discount has been applied is £1800 - £360 = £1440.

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The 5th value of the 60% percentile is 47 when for each test score in the data set is 12, 28, 35, 47, 49, 50.

Given that,

For each test score in the data set, the percentile rank is determined. 12, 28, 35, 42, 47, 49,  

We have to find what number represents the 60% of the population.

We know that,

So,

Percentile rank =[(Number of values below x)+0.5]/ total number of values × 100

For 12,

Percentile rank = [0 +0.5]/7×100

= 7th

For 28,

Percentile rank = [1 +0.5]/7×100

= 21st

For 35,

Percentile rank = [2 +0.5]/7×100

= 36th

For 42,

Percentile rank = [3 +0.5]/7×100

= 50th

For 47,

Percentile rank = [4 +0.5]/7×100

= 64th

For 49,

Percentile rank = [5 +0.5]/7×100

= 79th

For 50,

Percentile rank = [6 +0.5]/7×100

= 93rd

Now,

n = 7

60th percentile = 60% of n

So,

60% of n = 60/100×7

= 0.6×7

= 4.2

Therefore, The 5th value of the 60% percentile is 47 when for each test score in the data set is 12, 28, 35, 47, 49, 50.

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Given the graph of a function, you need to remember that, by definition, the zeros of a function are the x-intercepts (where the function intersects the x-axis).

In this case, you can identify that the function intersects the x-axis at these points (approximately):

Therefore, the roots are, approximately:

Hence, the answer is:

Answer:

y= 3h

Step-by-step explanation:

make y the subject of the formular

The difference between the number of expected outcomes and the number of actual outcomes = 5

We have to given that;

Olivia flips a two-sided counter and then spins a spinner with six equal-size sections labeled 1 through 6.

Now, She tosses a two sided counter and spins a spinner with six equal sized sections numbered 1 to 6.

Then, Probability of the counter landing on either of the two sides is exactly = (1/2)

Probability of the counter landing on the red side = (1/2)

Probability of the spinner landing in a region greater than 3 = Probability of the spinner landing in a region of 4, 5 or 6.

P = (3/6) = (1/2)

In one toss and spin, the probability of a toss landing on red and the spinner landing on a number greater than 3 is,

p = (1/2) × (1/2)

p = (1/4)

Expected number of times that a toss will land on a red and a spinner will land on a number greater than 3 in 80 trials

= np = 80 × (1/4) = 20

And, Number of actual times that the toss lands on a red and a spinner lands on a number greater than 3 in 80 trials = 25

Hence, The difference between the number of expected outcomes and the number of actual outcomes is,

= 25 - 20

= 5

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Answer:

\(x=-1,\:y=-1\)

Step-by-step explanation:

\(\begin{bmatrix}-6x+5y=1\\ 6x+4y=-10\end{bmatrix}\)

\(\mathrm{Add\:the\:equations}\)

\(6x+4y=-10\)

\(+\)

\(\underline{-6x+5y=1}\)

\(9y=-9\)

\(\begin{bmatrix}-6x+5y=1\\ 9y=-9\end{bmatrix}\)

Solve 9y=-9 for y: y=-1

\(\mathrm{For\:}-6x+5y=1\mathrm{\:plug\:in\:}y=-1\)

Solve -6x+5(-1)=1 for x: x=-1

\(\mathrm{The\:solutions\:to\:the\:system\:of\:equations\:are:}\)

\(x=-1,\:y=-1\)

Answer:

Hi... Your answer is

-22d+f

Answer:

what do u mean

Step-by-step explanation:

Answer:

It would be 1.1¯ (1.1 repeating).

Hugh poured 100 kilograms of water into 10 kg of salt. He made 110 kilograms of 9.09 % salt solution.

To find the mass of the solution add the mass of salt and the mass of the solution. To find the concentration of the solution divide the salt mass by the total mass of the solution and multiply by 100.

Here we have  

Hugh poured 100 kilograms of water into 10 kg of salt.

After adding 100 kilograms of water to 10 kg of salt.  

The total mass of the solution = 100 + 10 = 110 kg

The concentration of salt

= [ Mass of salt/ Mass of solution] × 100

= [ 10/110] × 100 = 9.09%      

Therefore,

Hugh poured 100 kilograms of water into 10 kg of salt. He made 110 kilograms of 9.09 % salt solution.  

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