The galactic center lies in the direction of which constellation?.

Answer:

The volume of the object is 3.5cm³

Answer:

The length of the incline is 3.504 meters.

Explanation:

Let suppose that Julietta's ball decelerates uniformly, then we determine the length of the incline is determined by the following equation of motion:

\(\Delta s = v_{o}\cdot t +\frac{1}{2}\cdot a \cdot t^{2}\) (Eq. 1)

Where:

\(\Delta s\) - Length of the incline, measured in meters.

\(v_{o}\) - Initial speed of the ball, measured in meters per second.

\(a\) - Aceleration of the ball, measured in meters per square second.

\(t\) - Time, measured in second.

If we know that \(v_{o} = 2.95\,\frac{m}{s}\), \(t = 1.54\,s\) and \(a = -0.876\,\frac{m}{s^{2}}\), then the length of the incline is:

\(\Delta s = \left(2.95\,\frac{m}{s} \right)\cdot (1.54\,s)+\frac{1}{2}\cdot \left(-0.876\,\frac{m}{s^{2}} \right) \cdot (1.54\,s)^{2}\)

\(\Delta s = 3.504\,m\)

The length of the incline is 3.504 meters.

Answer:

v = 4.79 10³ m / s

Explanation:

For this exercise we will use the universal law of gravitation and Newton's second law

          F = G M m / r²

where G is the gravitational constant, m the mass of the satellite, M the mass of the Earth, r the distance from the center of the planet to the satellite

           F = m a

since the satellite has a circular path, the acceleration is centripetal

          a = v² / r

we substitute

          G M m / r² = m v² / r

           G M / r = v²

We calculate

          v² = 6.67 10⁻¹¹ 5.98 10²⁴ / 6.96 10⁶

          v = √ (22.94 10⁶)

          v = 4.79 10³ m / s

Answer:

7570 m/s

Explanation:

take the square root of: 6.67E-11× 5.98E24/6.96E6

Speed:-

\(\\ \rm\rightarrowtail Speed=\dfrac{45}{9}=5m/s\)

Momentum:-

\(\\ \rm\rightarrowtail 45(5)\)

\(\\ \rm\rightarrowtail 225kgm/s\)

Answer:

B.

I think.

Explanation:

Mars doesn't have that much of an atmosphere!

Have a great day!

Answer:

Hi Emily, I know you from school.

Explanation:

You're in my class. 2024 am i right

No, due to the fact lactose is damaged down into glucose, that's already ample. A normal E. coli cell is grown for several hours in the presence of glucose.

If each glucose and lactose are both present, lactose binds to the repressor and stops it from binding to the operator region. The block of lac gene transcription is consequently lifted, and a small amount of mRNA is produced.

Escherichia coli can use the disaccharide lactose as a source of metabolic electricity. Lactose is first transported throughout the plasma membrane by means of the membrane carrier lactose permease, then it is cleaved to free glucose and galactose by the enzymeβ-galactosidase.

Glucose requires fewer steps and less energy to interrupt than lactose. but, if lactose is the best sugar available, the E. coli will cross right ahead and use it as an electricity source. to use lactose, the microorganism should express the lac operon genes, which encode key enzymes for lactose uptake and metabolism.

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Answer:

It is called Motion Energy

Explanation:

Answer:

distance and length are the same quantity

the frequency is  6x10⁻¹⁴ s⁻¹, the work function is 1.890 x 10⁻¹⁹ J, the energy of photons is  1.875 x 10⁻¹⁸ J and the wavelength is 780 nm.

a. The frequency of the 500 nm radiation is  6x10⁻¹⁴ s⁻¹.

b. The work function for the material can be determined using the equation W = hf - eV, where W is the work function, h is Planck's constant, f is the frequency of the radiation, and eV is the energy necessary to stop the photoelectrons from reaching the anode. In this case, eV = 3 V, so W = 6.63x10⁻³⁴ x 6x10¹⁴ - 3 = 1.890 x 10⁻¹⁹ J.

c. The energy of the photons associated with the unknown wavelength can be determined by using the equation E = hf, where E is the energy of the photon, h is Planck's constant, and f is the frequency of the radiation. Since we do not know the frequency of the unknown wavelength, we can use the equation E = hc/lambda, where c is the speed of light and lambda is the wavelength of the radiation. Since we are given that the potential required to stop the photoelectrons is 3V, we can calculate the energy of the photon as E = 3/1.6x10¹⁹ = 1.875 x 10⁻¹⁸ J.

d. The unknown wavelength can be determined using the equation lambda = hc/E, where h is Planck's constant, c is the speed of light, and E is the energy of the photon. Substituting the values, we get lambda = 6.63x10⁻³⁴ x 3x10⁸/1.875 x 10 = 7.8 x 10⁻⁷ m, or 780 nm.

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By knowing how intensity relates to distance, we will see that at 4 meters of the engine the intensity is 80.

The sound spreads in a solid angle like all waves, so the intensity of the sound will decrease with the distance squared, this means that:

\(I = \frac{P}{4*pi*r^2}\)

Where P is the sound power, we know that when the student is at 8m from the engine, the intensity measured is 20 (it does not tell the units) so we have:

\(20 = \frac{P}{4*3.14*(8m)^2} \\\\P = 20*4*3.14*(8m)^2 = 16,078.8 m^2\)

Now, if you move 4 meters closer to the engine, your new position will be:

r = 4m

Then we have:

\(I = \frac{16,078.8 m^2}{4*3.14*(4m)^2} = 80\)

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Answer:

80 is the answer! 100% CORRECT!

Explanation:

~Hope this helps! :)

Answer:

Radio pulsars and Recycled pulsars

When such two balls are moving at the same speed, F1: F2 = 1: 4 will be the ratio of drag forces on balls A and B.

Within science, the term "force" has to have a specific definition. At this point, describing a force as both a push or even a pull is completely acceptable. There is no substance that only an object "seems to have in it" or which it "contains" that is the force. This force is applied to one thing by another. The definition of a force comprises both living as well as non-living things.

Drag force calculation formula is = F(d) = 1/2 * C * rho*A * v²

Drag coefficient, or C

A = object area

rho = density of the moving object

v = the object's velocity

A = the object's area

F1 (force of drag on ball A) = 1/2 * C * rho * area of ball A *  v²

Ball A's drag force, F2, is equal to = 1/2 * C * rho * area of ball B *  v²

The only difference between the two balls is their differences in area because both are falling in the same environment and have the same speed.

F1/F2 = ball area A / ball area B=  4 * pi * r1² / 4 * pi * r2²

r1²/r2²

(d/2)²/(2d/2)²

F1 : F2 = 1 : 4

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Answer:

hello and thank you

Explanation:

The existence of coal beds in Antarctica is evidence that the region once experienced significant warming and was home to vast amounts of plant life.

One of the earliest hypotheses put up by geologists for how continents might migrate through time is called continental drift. The science of plate tectonics has now supplanted the theory of continental drift.

The scientist Alfred Wegener is most closely connected with the concept of continental drift. Wegener wrote a paper outlining his notion that the continents were "drifting" across the Earth, occasionally crashing through oceans and into one another, in the early 20th century. He referred to it as continental drift.

What is known about Antarctica's changing climate is that it didn't begin to cool until roughly 34 million years ago, when the continent was severed from the others which supports Continental Drift theory.

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As the mass moves back towards its equilibrium point, its speed is zero.

The motion of the mass attached to the spring can be described using the equation of motion:

\(m(d^2x/dt^2) = -kx\)

where x is the displacement of the mass from its equilibrium position, t is time, m is the mass of the object, and k is the spring constant.

We can solve this differential equation to obtain the displacement x as a function of time:

x(t) = A cos(wt) + B sin(wt)

where A and B are constants that depend on the initial conditions of the system, and w is the angular frequency of the oscillation:

w = sqrt(k/m)

To find the speed of the mass when it returns to the equilibrium position, we need to find the velocity v at that point. The velocity is the derivative of the displacement with respect to time:

v(t) = -Aw sin(wt) + Bw cos(wt)

At the equilibrium position, the displacement x is zero, so we have:

x(0) = A = d

v(0) = Bw = 0

Therefore, the displacement of the mass from its equilibrium position is:

x(t) = d cos(wt)

And the velocity of the mass at the equilibrium position is:

v(0) = -dw sin(0) + 0 = 0

v = 0.

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Answer:

I think 50%

Explanation:

Because the efficiency of a machine is always less than 100%. And efficiency of a machine is 75%.

So, if 15% input work is lost due to friction then efficiency is maybe 50%.

Answer:

its electric or magnetic fields, i think its electric fields

Hope its right

The flow velocity and the gauge pressure in such a pipe on the top floor is \(P2 = 4.8547 × 10^5 Pa + (1\)

To solve this problem, we can use the principle of conservation of mass and conservation of energy for an incompressible fluid. We assume that the fluid is incompressible, so its density remains constant throughout the pipe.

First, we can calculate the flow velocity at street level using the equation of continuity:

A1V1 = A2V2

where A1 and A2 are the cross-sectional areas of the pipe at street level and the top floor, respectively, and V1 and V2 are the corresponding flow velocities.

We can calculate the cross-sectional areas using the formula for the area of a circle:

\(A = πr^2\)

where r is the radius of the pipe. Thus,

\(A1 = π(0.025 m)^2 = 0.00196 m^2A2 = π(0.013 m)^2 = 0.0005309 m^2\)

Now, we can solve for V1:

\(V1 = (A2/A1) * V2 = (0.0005309 m^2 / 0.00196 m^2) * 0.06 m/s = 0.0162 m/s\)

Next, we can use the principle of conservation of energy to relate the pressure and velocity at street level to the pressure and velocity at the top floor. We assume that there is no frictional losses or energy transfer to the surroundings, so the total mechanical energy of the fluid is conserved. This gives us the Bernoulli equation:

\(P1 + (1/2)ρV1^2 + ρgh1 = P2 + (1/2)ρV2^2 + ρgh2\)

where P1 and P2 are the pressures at street level and the top floor, respectively, ρ is the density of the fluid, g is the acceleration due to gravity, h1 is the height of the pipe at street level, and h2 is the height of the pipe at the top floor.

We can assume that the height difference between the two floors is the only difference in potential energy. Also, we can assume that the density of water is constant at 1000 kg/m^3. Thus, we can simplify the equation to:

\(P1 + (1/2)(1000 kg/m^3)(0.0162 m/s)^2 + (1000 kg/m^3)(9.81 m/s^2)(0 m) = P2 + (1/2)(1000 kg/m^3)V2^2 + (1000 kg/m^3)(9.81 m/s^2)(20 m)\)

Simplifying and solving for P2, we get:

\(P2 = P1 + (1/2)(1000 kg/m^3)(V1^2 - V2^2) + (1000 kg/m^3)(9.81 m/s^2)(h2 - h1)P2 = 3.8 atm + (1/2)(1000 kg/m^3)(0.0162 m/s)^2 - (1/2)(1000 kg/m^3)(V2^2) + (1000 kg/m^3)(9.81 m/s^2)(20 m)\)

We can convert the gauge pressure at street level to absolute pressure by adding atmospheric pressure (1 atm) and converting to Pascals (Pa):

\(P1 = (3.8 atm + 1 atm) * 1.01325 × 10^5 Pa/atm = 4.8547 × 10^5 Pa\)

Now we can solve for P2:

\(P2 = 4.8547 × 10^5 Pa + (1\)

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Answer:

electrons can be removed or added creating ions of the element

Explanation:

A flying bird possesses both potential and kinetic energy. This is because potential energy is associated with its height or position in the gravitational field, while kinetic energy is linked to its motion.

Potential energy is the energy an object possesses due to its position or condition. In the case of a flying bird, it has potential energy associated with its height above the ground. As it gains altitude, the bird's potential energy increases because it is moving against the force of gravity. Additionally, the flying bird also possesses kinetic energy, which is the energy of motion. As the bird moves through the air, its wings flap and it accelerates, acquiring kinetic energy. The faster the bird flies, the greater its kinetic energy becomes.

The interplay between potential and kinetic energy is evident during the flight of a bird. When the bird climbs higher, it gains potential energy at the expense of kinetic energy as its speed decreases. Conversely, when the bird descends or accelerates, its potential energy decreases while its kinetic energy increases. In conclusion, a flying bird possesses both potential and kinetic energy. The potential energy arises from its position in the gravitational field, while the kinetic energy stems from its motion through the air.

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Answer: Helium=4 is the answer

Explanation:

took the test and got it right that'

s the answer.

Answer:

It's b

Explanation:

I took the quiz on EDGE and got it right.

The bond angle of the molecule to the nearest degree is 120 degrees.

According to the valence shell electron pair repulsion theory (VSEPR). We know that the bond angle that an atom has with its neighbors which also call the dihedral angle of the compound is affected by the number of atoms that surround the central atom in the molecule.

Let us recall that when we have two atoms that surround the central atom then we are going to have a three atom compound which has a trigonal planar geometry and has a bond angle of 120 degrees.

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Answer:

False you dont repaint your hamster.

Explanation:

LOL

A force diagram is shown below:

where,

N: normal force on block1

fg1: weight of block1 = (6kg)(9.8m/s^2) = 58.8N

T: tension in the string

Fr: friction force between the block and the table = μk*N

fg2: weight of block2 = (5kg)(9.8m/s^2) = 49N

Consider that the normal force is equal and opposite to the weight of block1 (becasue the equilibrium of the vertical forces n the block1), then:

N = fg1 = 58.8N

μk: coefficient of kinetic friction = 0.3

Fr = μk*N = (0.3)(58.8N) = 17.64N

Based on the given information and the force diagram, you can conclude:

Four forces are acting on the sliding block.

Two forces are acting on the hanging block.

The forces of the system are unbalanced due to the weight of the hanging block.

The magnitud of the friction force is 17.64N

The mass of the system is the sum of the masses of the blocks:

mass of the system = 6kg + 5kg = 11kg

The net force is, based on the clarification of point 4:

Fnet = fg2 - Fr = 49N - 17.64N = 31.36N

The acceleration of the system is:

a = 31.36N/(11kg) = 2.85 m/s^2

After release the sliding block moves to the right.

The tension in hte string is calculated by using the sum of forces on the sliding block:

T = Fr + m1*a

T = 17.64N + (6kg)(2.85m/s^2) = 17.64N + 17.1N = 34.74N

Moving away from the source causes the observer to measure a lower frequency and higher wavelength.

The frequency of the detected sound from a stationary source will change as a result of the observer's movement. Moving away from the source causes the observer to measure a lower frequency and higher wavelength.

The Doppler effect is a shift in sound wave frequency that happens when the source of the sound waves is moving in relation to a listener who is stationary.

The wave propagates the sound energy throughout the medium, typically in all directions and with decreasing intensity as it gets further away from the source.

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Answer:

30.66667

Explanation:

should be the answer if the calculator is correct

$ \large\boxed{ \sf \red{More ~Info :}}$

The units of supplementary quantities are dimensionless units.

\( \\ \)

Answer:

a)   U = 1.96 10⁵ J, b)  K = 9.675 10³ J

Explanation:

a) the potential energy is

          U = m g h

where zero energy in general takes the floor

let's calculate

          U = 86 9.8 233

          U = 1.96 10⁵ J

b) They ask for kinetic energy and give us the speed of man

          K = ½ m v²

let's calculate

          K = ½ 86 15²

          K = 9.675 10³ J

The  momentum of object B after the collision is + 18  kg m/s.

The principle of momentum conservation asserts that momentum is never created nor destroyed but only modified by the action of forces as they are represented by Newton's equations of motion. This applies to a particular issue area.

According to principle of momentum conservation:

The  momentum of object B after the collision = total initial momentum - momentum of object A after the collision

=  +20 kg m/s  -6 kg m/s - ( -4 kg m/s)

= + 18  kg m/s

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a) Its focal length is half the radius of curvature, or 10 cm.

b) The image of the candle will be located 17.5 cm from the mirror.

c) The image will be upright.

(a) The focal length of the mirror can be calculated using the formula:

1/f = 1/do + 1/di

where f is the focal length, do is the distance of the object from the mirror, and di is the distance of the image from the mirror.

In this case, do = 35 cm and the mirror has a radius of curvature of 20 cm, so its focal length is half the radius of curvature, or 10 cm.

(b) To find the location of the image, we can use the mirror formula:

1/do + 1/di = 1/f

Plugging in the values we have, we get:

1/35 + 1/di = 1/10

Solving for di, we get:

di = 17.5 cm

So the image of the candle will be located 17.5 cm from the mirror.

(c) To determine whether the image is upright or inverted, we can use the sign convention:

- If the object distance (do) is positive, the object is on the same side of the mirror as the incoming light, and the image is upright.
- If the object distance is negative, the object is on the opposite side of the mirror from the incoming light, and the image is inverted.

In this case, the object is 35 cm from the mirror, which is on the same side of the mirror as the incoming light. Therefore, the image will be upright.

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