The Km for the reaction of chymotrypsin with N-acetylvaline ethyl ester is 8.8 x 10-2 M, and the Km for the reaction of chymotrypsin with N-acetyltyrosine ethyl ester is 6.6 x 10-4 M. a.Which substrate has the higher apparent affinity for the enzyme? b.Which of the following substrates is likely to give a higher value for Vmax? -N-Acetylvaline ethyl ester -N-Acetyltyrosine ethyl ester (The value of Km is not related to the value of Vmax)

Answer:

radio waves

Explanation:

The number of molecules in 10.0 gram of NaOH is 15 * 10²².

To solve this question, we need to understand some terms of mole concept,

Mole - It is the amount of substance containing same number of molecules or atoms as there are atoms in 12 gram of carbon-12 isotope.

Molecules - It is group of atoms bonded together, representing the smallest fundamental unit of a chemical compound taking part in chemical reaction.

Molecular weight - The sum of atomic masses of all atoms in molecules.

Avogadro number - It is the number of atoms, ions, electrons, molecules in one mole of substance. It is represented as NA.

NA = 6.0 * 10²³ (approx)

To calculate the number of molecules, we apply the formulae,

no. of molecules = moles * NA

moles = weight / molecular weight

moles = 10.0 / 40

          = 0.25

Substituting this value to calculate number of molecules,

no. of molecules = 0.25 * 6.0 * 10²³

                            = 15 * 10²²

Therefore the number of molecules of in 10.0 g of NaOH is 15 * 10²².

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Answer:

A. hibernation

Answer:

Hibernation.

Explanation:

Answer:

sa gutan ko na nga para mabrainliest na sya

Answer:

67.8%

Explanation:

La reacción de descomposición del CaCO₃ es:

CaCO₃ → CO₂ + CaO

Donde 1 mol de CaCO₃ al descomponerse produce 1 mol de CO₂ y 1 mol de CaO.

Usando la ley general de los gases, las moles de dioxido de carbono son:

PV = nRT.

Donde P es presión (1atm), V es volumen (20L), n son moles de gas, R es la constante de los gases (0.082atmL/molK) y T es temperatura absoluta (15 + 273.15 = 288.15K). Reemplazando los valores en la ecuación:

PV / RT = n

1atmₓ20L / 0.082atmL/molKₓ288.15K = 0.846 moles

Como 1 mol de CO₂ es producido desde 1 mol de CaCO₃, las moles iniciales de CaCO₃ son 0.846moles.

La masa molar de CaCO₃ es 100.087g/mol. Así, la masa de 0.846moles de CaCO₃ es:

0.846moles ₓ (100.087g / mol) = 84.7g de CaCO₃

Así, la pureza del marmol es:

(84.7g de CaCO₃ / 125g) ₓ 100 =

The question requires us to calculate the mass, in grams, contained in 5.26 x 10^-4 mol of HC2H3O2.

To solve this question, first we need to calculate the molar mass of the compound, considering the number of atoms of each element, and then relate the value obtained with the number of moles given (5.26 x 10^-4 mol).

First, to calculate the molar mass of the compound, let's consider the following atomic masses:

atomic mass of C = 12.01 u

atomic mass of H = 1.007 u

atomic mass of O = 15.99 u

Next, we calculate the molar mass. To do that, we need to consider the number of atoms of each element: according to the chemical formula, there are 2 atoms of C, 4 atoms of H and 2 atoms of O:

molar mass (C2H4O2) = (2 * 12.01) + (4 * 1.007) + (2 * 15.99) = 60.03 g/mol

Now, we know that there are 60.03 g for each mol of the compound. With that information, we can estabilish the following relation to calculate the mass contained in 5.26 x 10^-4 mol of the compound:

1 mol --------------------- 60.03 g

5.26 x 10^-4 mol ----- x

Solving for x, we have:

Therefore, there are 0.03158 g of HC2H3O2 in 5.26 x 10^-4 mol of this compound.

The reaction in which entropy increases is PCI_3(g) + Cl_2(g) → PCI_5(g). Entropy is a measure of disorder or randomness in a system.

In this reaction, two gases (PCI_3 and Cl_2) are reacting to form a gas (PCI_5), resulting in an increase in the total number of gas molecules. As gases are more disordered than solids or liquids, this increase in the number of gas molecules leads to an increase in entropy. involves the formation of a solid from two aqueous ions, which results in a decrease in entropy. involves the conversion of two gases into a single gas, resulting in no net change in entropy. involves the decomposition of a liquid into a gas and a liquid, resulting in a decrease in entropy. Both the statistical and thermodynamic entropies are indicators of how chaotic or random a system is. The thermodynamic entropy is a measurement of the thermal energy that cannot be used to perform productive work in a system, whereas the statistical entropy counts the possible arrangements of the atoms or molecules in a system.

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The correct classification for both calcium (Ca) and iron (Fe) is:

D) Ca is an alkaline earth element and a metal, and Fe is a transition element and a metal.

Calcium (Ca) belongs to the alkaline earth metals group, which is located in Group 2 of the periodic table. Alkaline earth metals are characterized by their reactivity, high melting points, and tendency to form 2+ cations. Therefore, Ca is classified as an alkaline earth element and a metal.

Iron (Fe) is a transition element, also known as a transition metal. Transition metals are located in the d-block of the periodic table and are characterized by their ability to form multiple oxidation states and exhibit variable valencies. Fe is classified as a transition element and a metal due to its properties and location in the periodic table.

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To be considered a true hydrate, a compound must follow a few rules, and one of these rules is the color being the same before and after heating. In this case we have a difference in the color, the residue after heating when dissolved in water is forming a yellow brown solution, and in the meanwhile, a colorless solution is formed when a sample of the original compound is dissolved in water, which is not a characteristic of a true hydrate.

12.electrons

13.13

14.aluminum has 14 neutron.

Answer:

it is iceeeeeeeeeee

Explanation:

ice ice baby

Answer: Solid water, or ice, is less dense than liquid water. Ice is less dense than water because the orientation of hydrogen bonds causes molecules to push farther apart, which lowers the density. ... Because ice is less dense than water, it is able to float at the surface of water.

Answer:

Beacause  it does  just in a different place

Explanation:

Because the Earth's orbit around the sun differs from the Moon's orbit around the Earth, lunar eclipse don't happen every month.

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Answer:

The system can operate on a set level of parts per million (ppm) chlorine, where the set level is automatically maintained.

The heat energy absorbed by a body is equal to the product of its specific heat, mass and change in temperature. Therefore, we can say that heat energy = mass × specific heat capacity × change in temperature Hence, we can use the above formula to find out the mass of the sample of lead.

The specific heat capacity of lead is 0.128 J/g°C. The temperature of the sample of lead increased by 24.4°C when 257 J of heat was applied. Therefore, using the formula above:257 J = mass × 0.128 J/g°C × 24.4°CCanceling out the units, we have:mass = 257 J / (0.128 J/g°C × 24.4°C)mass = 68.8 gTherefore, the mass of the sample of lead is 68.8 g.

We have used the formula, heat energy = mass × specific heat capacity × change in temperature to calculate the mass of the sample of lead that is given in the question.

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Type 1A antiarrhythmics are a class of medications used to treat certain types of cardiac arrhythmias, including atrial fibrillation and ventricular tachycardia. Examples of Type 1A antiarrhythmic drugs include quinidine, procainamide, and disopyramide.

These drugs work by blocking the flow of sodium ions through the cell membrane of cardiac muscle cells, which slows down the rate of depolarization and makes it more difficult for an abnormal electrical impulse to be generated. This slows down the heart rate and helps restore normal rhythm.

Type 1A antiarrhythmics are known as "moderate" sodium channel blockers, as they block sodium channels to a moderate degree and have intermediate effects on cardiac conduction. They have a relatively broad range of effects on cardiac action potential and can affect both atrial and ventricular muscle cells.

However, Type 1A antiarrhythmics can have significant side effects, including the risk of inducing arrhythmias, especially if the dose is too high. They can also cause gastrointestinal symptoms, headaches, and hypotension.

Due to these potential risks, Type 1A antiarrhythmics are typically only used in patients with specific arrhythmias and under careful medical supervision.

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Answer:

covalent bond

Explanation:

they allow donation of electrons

Red blood cells

[•] More in numbers.

[•] No antibodies present in these cells.

White blood cells

[•] Less in numbers

[•] Antibodies are present in these cells.

Explanation:

COMPONENTS OF ENVIRONMENT

Environment mainly consists of atmosphere, hydrosphere, lithosphere and biosphere. But it can be roughly divided into two types such as (a) Micro environment and (b) Macro environment. (a) Micro environment refers to the immediate local surrounding of the organism.

Answer:

The basic component of the Environment are water,forest,living beings,e.t.c

The elements arranged in increasing order of the most positive electron affinity for each group are:

(a) Li, Na, K

(b) I, Br, Cl, F

(c) Ba, Ca, Si, P, O

(a) Li, Na, K: In this group, the electron affinity increases as we move from left to right in the periodic table. Therefore, the elements arranged in increasing order of the most positive electron affinity are Li, Na, and K.

(b) F, Cl, Br, I: In this group, the electron affinity generally increases as we move from left to right and from bottom to top in the periodic table. Therefore, the elements arranged in increasing order of the most positive electron affinity are I, Br, Cl, and F.

(c) O, Si, P, Ca, Ba: In this group, the electron affinity generally increases as we move from left to right and from top to bottom in the periodic table. Therefore, the elements arranged in increasing order of the most positive electron affinity are Ba, Ca, Si, P, and O.

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To calculate the molecular weight of this molecule, However, we can tell you that the sum of the atomic weights of the elements in a molecule is called its molecular weight.

In this case, the molecular weight would be the sum of the atomic weights of carbon, nitrogen, and hydrogen in the molecule.The correct amu for carbon, nitrogen, and hydrogen are 12 amu, 14 amu, and 1 amu, respectively.

To find the molecular weight of a molecule that includes one atom of each element, simply add their respective amu values together: 12 amu (carbon) + 14 amu (nitrogen) + 1 amu (hydrogen) = 27 amu. The molecular weight of this molecule is 27 amu.

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To determine the molecular weight of the molecule, we need to know the formula of the molecule. However, based on the information given, we can make an educated guess that the molecule is likely to be a combination of carbon, nitrogen, and hydrogen atoms.

Assuming that the molecule has the formula CHN, we can calculate its molecular weight as follows:

Molecular weight of CHN = (mass of carbon x number of carbon atoms) + (mass of hydrogen x number of hydrogen atoms) + (mass of nitrogen x number of nitrogen atoms)
                         = (12 amu x 1) + (1 amu x 1) + (16 amu x 1)
                         = 12 amu + 1 amu + 16 amu
                         = 29 amu

Therefore, the molecular weight of the molecule with carbon, nitrogen, and hydrogen atoms having masses of 12 amu, 16 amu, and 1 amu, respectively, is 29 amu.

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Sister chromatids is the term for the chromosomes that are identical after DNA replication.

Sister chromatids are identical chromosomes that are created during the process of DNA replication. DNA replication is the process where a DNA strand is copied, creating a new strand. During this process, each chromosome is split in half, forming two identical halves.

These halves are known as sister chromatids and are held together by a centromere. Sister chromatids are attached to one another during the interphase stage of the cell cycle and are separated during the metaphase stage of the cell cycle.

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The automobile gasoline tank will hold 59.05 pounds of gasoline.

Given that the volume of the gasoline tank of the automobile is 19.0 gal. and the density of the gasoline is 0.737 g/mL. So, we need to calculate the number of pounds of gasoline the tank can hold.The relationship between volume and density is as follows;Density= Mass/ VolumeRearranging the equation gives; Mass= Density × VolumeSubstitute the given values in the above equation;Mass = 0.737 g/mL × 19.0 gal × 3.78541 L/galWe know that; 1 L = 1 dm³Thus,Mass = 0.737 g/mL × 19.0 gal × 3.78541 dm³/LMass = 53.70 kgThe given mass is in kg and we need to convert it into pounds;1 kg = 2.20462 poundsThus,Mass = 53.70 kg × 2.20462 pounds/kgMass = 118.4 pounds therefore, the automobile gasoline tank will hold 59.05 pounds of gasoline.

Given that the volume of the gasoline tank of the automobile is 19.0 gal. and the density of the gasoline is 0.737 g/mL. So, we need to calculate the number of pounds of gasoline the tank can hold.The relationship between volume and density is as follows;Density= Mass/ VolumeThe above equation can be rearranged as; Mass= Density × Volume Substitute the given values in the above equation;Mass = 0.737 g/mL × 19.0 gal × 3.78541 L/galMass = 53.70 kgThe given mass is in kg and we need to convert it into pounds;1 kg = 2.20462 poundsThus,Mass = 53.70 kg × 2.20462 pounds/kgMass = 118.4 pounds therefore, the automobile gasoline tank will hold 59.05 pounds of gasoline.

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Yeast is a type of fungus that can ferment certain substances, meaning it breaks down sugars and converts them into alcohol and carbon dioxide. The ease with which a substance is fermented by yeast depends on a few factors, including the type of yeast being used and the composition of the substance itself.

Generally speaking, substances that contain a high amount of simple sugars are more easily fermented by yeast. This is because yeast is able to quickly and efficiently break down these sugars into alcohol and carbon dioxide. Examples of substances that are easily fermented by yeast include fruit juices, honey, and molasses.

On the other hand, substances that are more complex or contain less sugar may be more difficult for yeast to ferment. For example, yeast may have a harder time breaking down starches, such as those found in grains, without additional processing steps.

It's worth noting that different strains of yeast may also have varying levels of ability to ferment certain substances. Some strains may be better suited for fermenting certain types of beer or wine, for example, while others may be more effective at fermenting bread dough.

Overall, the ease with which a substance is fermented by yeast depends on a variety of factors, and may require some trial and error to determine the best approach for a particular substance.

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Answer:

In liquids, particles are quite close together and move with random motion throughout the container. Particles move rapidly in all directions but collide with each other more frequently than in gases due to shorter distances between particles. With an increase in temperature, the particles move faster as they gain kinetic energy, resulting in increased collision rates and an increased rate of diffusion.

Explanation:

In liquids, particles are quite close together and move with random motion throughout the container. Particles move rapidly in all directions but collide with each other more frequently than in gases due to shorter distances between particles. With an increase in temperature, the particles move faster as they gain kinetic energy, resulting in increased collision rates and an increased rate of diffusion.

The generic equation is M(OH)2 (s) + 2HCl (aq) → 2H2O (l) + MCl2 (aq), the molar mass of the unknown metal hydroxide is 121.4 g/mol and the identity of the metal is strontium (Sr).

The generic equation for the reaction between an alkaline earth metal hydroxide and hydrochloric acid is:

M(OH)2 (s) + 2HCl (aq) → 2H2O (l) + MCl2 (aq)

From the balanced equation, we can see that the stoichiometry of the reaction is 1:2 between the metal hydroxide and the hydrochloric acid. This means that for every mole of metal hydroxide reacted, 2 moles of hydrochloric acid are required.

To find the molar mass of the unknown metal hydroxide, we first need to calculate the number of moles of hydrochloric acid used in the titration:

Number of moles of HCl = 1.008 M × 0.01700 L = 0.01714 mol

Since 2 moles of HCl react with 1 mole of the metal hydroxide, the number of moles of metal hydroxide in the sample is:

Number of moles of metal hydroxide = 0.01714 mol / 2 = 0.00857 mol

We can now calculate the molar mass of the unknown metal hydroxide by dividing the mass of the sample by the number of moles:

Molar mass of metal hydroxide = 1.042 g / 0.00857 mol = 121.4 g/mol

To identify the metal, we can compare the molar mass of the unknown metal hydroxide (121.4 g/mol) to the molar masses of known alkaline earth metal hydroxides. The possible metals are beryllium, magnesium, calcium, strontium, and barium.

Beryllium hydroxide (Be(OH)2) has a molar mass of 43.03 g/mol, which is much lower than the molar mass of the unknown metal hydroxide. Magnesium hydroxide (Mg(OH)2) has a molar mass of 58.32 g/mol, which is also lower than the unknown metal hydroxide. Calcium hydroxide (Ca(OH)2) has a molar mass of 74.09 g/mol, which is still lower than the unknown metal hydroxide. Strontium hydroxide (Sr(OH)2) has a molar mass of 121.63 g/mol, which is very close to the molar mass of the unknown metal hydroxide. Finally, barium hydroxide (Ba(OH)2) has a molar mass of 171.34 g/mol, which is higher than the molar mass of the unknown metal hydroxide.

Based on the molar mass, the identity of the unknown metal is most likely strontium (Sr).

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Answer:

23 L

Explanation:

We'll begin by converting celsius temperature to Kelvin temperature. This can be obtained as follow:

T(K) = T(°C) + 273

Initial temperature (T₁) = 100 °C

Initial temperature (T₁) = 100 °C + 273

Initial temperature (T₁) = 373 K

Final temperature (T₂) = 50.5 °C

Final temperature (T₂) = 50.5 °C + 273

Final temperature (T₂) = 323.5 K

Finally, we shall determine the initial volume of gas. This can be obtained as follow:

Initial temperature (T₁) = 373 K

Final temperature (T₂) = 323.5 K

Final volume (V₂) = 20 L

Initial volume (V₁) =?

V₁/T₁ = V₂/T₂

V₁ / 373 = 20 / 323.5

Cross multiply

V₁ × 323.5 = 373 × 20

V₁ × 323.5 = 7460

Divide both side by 323.5

V₁ = 7460 / 323.5

V₁ = 23 L

Thus, the original volume of the gas is 23 L