The molecular weight of KMnO4 is 158 g/mol. If you wanted to make 500 mL of a 0.1M stock solution of KMnO4, how much solid KMnO4 would you need to add before filling mL flask of water?

In the balanced equation for the given reaction under basic conditions, there will be 2 hydroxide ions appearing on the left side. The correct answer is (c) 2 on the left.

When a reaction occurs under basic conditions, hydroxide ions (OH-) are involved in the chemical process. They act as a base, accepting protons (H+) to form water molecules (H2O). In this reaction, the hydroxide ions are responsible for oxidizing the zinc metal to zinc ions.

The balanced equation for the reaction is as follows:

2Ag(s) + 2OH-(aq) + Zn2+(aq) ? Ag2O(s) + Zn(s) + H2O(l)

In this equation, two hydroxide ions (OH-) appear on the left side, indicating their involvement as part of the base in the reaction. They react with the zinc ions (Zn2+) to form water (H2O) and facilitate the reduction of silver ions (Ag+) to silver oxide (Ag2O).

Therefore, there are 2 hydroxide ions on the left side of the balanced equation, and the correct answer is (c) 2 on the left.

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No approximations or assumptions need to be made in the calculation of the pH and the tartrate ion 1C4H4O6 2-2 concentration for a 0.250 M solution of tartaric acid.

The pH and the tartrate ion 1C4H4O6 2-2 concentration of a 0.250 M solution of tartaric acid can be calculated using the acid-dissociation constants and the Henderson-Hasselbalch equation. The acid-dissociation constants (Ka1 and Ka2) of tartaric acid are 1.14x10-2 and 5.01x10-5, respectively.

The pH of the solution can be calculated using the Henderson-Hasselbalch equation: pH = pKa + log([base]/[acid]) where [base] is the concentration of the conjugate base (the tartrate ion) and [acid] is the concentration of the acid (tartaric acid). Since the solution is 0.250 M in tartaric acid, [acid] = 0.250 M and [base] = 0.250 M - [tartrate ion], which can be calculated using the Ka1 and Ka2 values.

For Ka1, the tartrate ion 1C4H4O6 2-2 concentration can be calculated as 0.250 M - 0.250 * 1.14x10-2 = 0.249 M. For Ka2, the tartrate ion 1C4H4O6 2-2 concentration can be calculated as 0.250 M - 0.250 * 5.01x10-5 = 0.249 M.

Using the Henderson-Hasselbalch equation, the pH of the solution can be calculated as pH = pKa + log([base]/[acid]). The pKa values of tartaric acid are 3.92 and 5.63 respectively. Therefore, for Ka1, the pH of the solution can be calculated as pH = 3.92 + log(0.249/0.250) = 3.91, and for Ka2, the pH of the solution can be calculated as pH = 5.63 + log(0.249/0.250) = 5.63.

No approximations or assumptions need to be made in the calculation of the pH and the tartrate ion 1C4H4O6 2-2 concentration for a 0.250 M solution of tartaric acid, as the Henderson-Hasselbalch equation and the acid-dissociation constants of tartaric acid can be used.

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Answer:

A

Explanation:

l took the test

Answer:

The Moon’s appearance changes during its orbit around Earth. These changes are called phases.

Explanation:

We now have a net ionic equation that is balanced. Our balanced net ionic equation, with state symbols, is 4Fe(s) H+ 12H+(aq) H+ 3O2(aq) react to generate 4Fe3+(aq) plus 6H2O from the dissolution of hydrogen ions and oxygen molecules in metallic iron (L).

In reality, the three rules for formulating net ionic equations are rather simple. Only take into account fracturing the (aq) compounds. Break apart only powerful electrolytes. Any ions that show up on both sides of the equation should be removed.

A complete ionic equation also contains the spectator ions, whereas a net ionic equation just displays the chemical species that are involved in a reaction.

So, the net ionic equation is now balanced. Our balanced net ionic equation, which takes into account state symbols, reads as follows: 4Fe(s) H+ 12H+(aq) H+ 3O2(aq) react to generate 4Fe3+(aq) plus 6H2O from metallic iron dissolves hydrogen ions (L).

Questio is what is the net ionic equation for formation of iron (iii) hydroxide via mixing aqueous iron (iii) nitrate and potassium hydroxide?

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The atoms in the ring portion of the Haworth structure of glucose are oxygen, carbon, and hydrogen.

The Haworth structure is a way to represent the cyclic form of a monosaccharide, such as glucose. In this structure, the atoms are shown in a planar representation, with the oxygen and carbon atoms forming a hexagonal ring and the hydrogen atoms attached to the carbon atoms.

The ring is formed when the hydroxyl group on the fifth carbon atom of the linear structure reacts with the aldehyde group on the first carbon atom, forming a hemiacetal bond. The resulting ring structure is known as a pyranose ring. The ring structure of glucose is important because it affects the reactivity of the molecule and its interactions with other molecules in biological systems.

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is it amino acids???????

a) The total suspended solids (TSS) concentration of the water = 7.89 g/L

b) The volatile suspended solids (VSS) concentration of the water = 0.049 g/L

c) Calculation cannot be completed for TDS concentration because muffle furnace only provides information about the amount of suspended solids only.

To calculate the total suspended solids (TSS) concentration of the water, we need to use the weight of the filter paper plus residue after being heated in the muffle furnace (1.40025 g), subtract the tare weight of the filter (1.38448 g), and divide the result by the volume of the water sample (200 mL). Therefore, TSS = (1.40025 g - 1.38448 g) / 0.2 L = 7.89 g/L.

We can calculate the weight loss by subtracting the weight of the filter paper plus residue after being heated in the muffle furnace (1.40025 g) from the weight of the filter paper plus residue before being heated in the muffle furnace (1.41006 g). Therefore, VSS = (1.41006 g - 1.40025 g) / 0.2 L = 0.049 g/L.

The TDS concentration is the total amount of dissolved substances in the water, and the weight of the filter paper plus residue after being heated in the muffle furnace only provides information about the amount of suspended solids.

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The grams of the reactant that were consumed will be 2g

The Law of Conservation of Mass by Antoine Lavoisier states that mass is neither created nor destroyed in chemical reactions. In other words, the mass of any one element at the beginning of a reaction will equal the mass of that element at the end of the reaction.

According to the law we understand that mass is neither created nor destroyed. So, if 2 grams of product are produced, then the mass of reactants consumed will also be equal to 2 grams.

Hence if 2 grams of product is produced by the chemical reaction, 2 grams of reactants are consumed.

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Answer:

ask a question

Explanation:

You have to ask a question or solve a problem before you can develop a prediction/hypothesis, conduct an experiment or even make a conclusion. The question comes first.

Using this formula, we can calculate the confidence interval once we have the sample data, without the sample data, it is not possible to provide an accurate confidence interval estimate.

To construct a 90% confidence interval estimate of the percentage of cell phone users who develop cancer of the brain or nervous system, we would need the sample data, specifically the number of cell phone users and the number of users who developed cancer. Without the sample data, it is not possible to provide an accurate confidence interval estimate.

However, if we assume that we have the necessary sample data, we can proceed with the calculation. The formula for calculating a confidence interval for a proportion is:

Confidence interval

\(=�^±�×�^(1−�^)�Confidence interval= p^​ ±z× np^​ (1− p^​ )​ ​ where:�^p^​\)

 is the sample proportion (number of users with cancer divided by the total number of cell phone users).

\(�\)

z is the z-score corresponding to the desired confidence level (90% confidence level corresponds to a z-score of approximately 1.645).

\(�\)

n is the sample size (total number of cell phone users).

Using this formula, we can calculate the confidence interval once we have the sample data.

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In this experiment, we have various components labeled as a, b, c, d, e, f, g, j, and l.Let's analyze each component to determine if it is an element, compound, or mixture.

a: We are given that when 10 g of a is heated, 4.4 g of b is given off, leaving 5.6 g of e. This suggests that a is a compound, as it can be broken down into b and e.
b: 4.4 g of b is given off when a is heated, and the same quantity of b can be made by adding 1.2 g of c and 3.2 g of d. This indicates that b is a compound formed by the combination of c and d.
c and d: These components are combined to produce b, indicating that they are elements.
e: 5.6 g of e remains after the production of b. It combines with water to give a 1.3 g ppt of j per gram of e and also produces l, a homogeneous material. This suggests that e is a compound that can react with water to form a precipitate (j) and a homogeneous material (l).
f and g: These are the products of electrolyzing

e. They cannot be broken down further chemically, indicating that they are elements.
j: It is formed as a precipitate when e reacts with water, suggesting that j is a compound.
l: It is produced when e combines with water, indicating that l is a homogeneous material.

In summary:
1. a: Compound
2. b: Compound
3. c: Element
4. d: Element
5. e: Compound
6. f: Element
7. g: Element
8. j: Compound
9. l: Homogeneous material

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The value of ΔG at 298 K for a reaction mixture containing 1.9 atm N2, 1.6 atm H2, and 0.65 atm, the answer is (a) -3.86 × 10^3.

NH3 can be calculated using the equation:

ΔG = ΔG° + RT ln(Q)

where ΔG is the standard Gibbs free energy change, ΔG° is the standard Gibbs free energy change at standard conditions, R is the gas constant, T is the temperature in Kelvin, and Q is the reaction quotient.

In this case, we are given ΔG° as -33.3 kJ/mol. To calculate Q, we need to use the partial pressures of the gases in the reaction mixture. The reaction stoichiometry tells us that the ratio of the partial pressures of N2, H2, and NH3 is 1:3:2. Therefore, we can write:

Q = (P(NH3))^2 / (P(N2) * P(H2)^3)

Plugging in the given values of P(N2) = 1.9 atm, P(H2) = 1.6 atm, and P(NH3) = 0.65 atm, we can calculate Q. Then, using the value of R = 8.314 J/(mol·K) and the temperature T = 298 K, we can substitute these values into the equation and solve for ΔG.

The calculated value of ΔG at 298 K for the given reaction mixture is approximately -3.86 × 10^3 J/mol. This value is equivalent to -3.86 kJ/mol. Therefore, the answer is (a) -3.86 × 10^3.

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Answer:

Atacama

Explanation:

Answer:

Chlorine

Explanation:

Answer:

44 g

Explanation:

hope this helps

When a sodium-22 nucleus undergoes electron capture, it captures an electron from one of its inner shells. This results in the formation of a new nucleus with one less proton in its nucleus.

Since the atomic number of an element is defined by the number of protons in its nucleus, the atomic number of the product will be one less than the atomic number of sodium-22, which is 11. Therefore, the product of this reaction will have an atomic number of 10. This new nucleus will also have the same mass number as sodium-22, which is 22, as the number of neutrons in the nucleus remains the same.

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There is an inversion of stereochemistry, which implies a back-side attack of the nucleophile as in SN₂ reaction the nucleophile attacks opposite from the side of the leaving group.

SN2 (Substitution Nucleophilic Bimolecular) reactions occur when a nucleophile attacks an electrophilic carbon atom and substitutes a leaving group. In SN₂ reactions, the nucleophile attacks from the opposite side of the leaving group, which causes the stereochemistry at the reaction center to invert.
The size of the anion can affect the nucleophilicity due to solvation, with larger anions being less suppressed by solvation.

Additionally, smaller anions may be more solvated by ion-dipole forces.

However, these factors do not directly influence the stereochemical outcome of the SN₂ reaction.

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At equilibrium, the composition of the reaction vessel with 0.51 moles of CO₂ and 0.51 moles of H₂ is given by the equilibrium constant K, which is 819.

The reaction given is:

H₂(g) + CO₂(g) ⇌ CO(g) + H₂O(g)

So, we know the formula for Kp and Kc in terms of partial pressure and concentration are as follows:

Kc = (CO(g) × H₂O (g)) / (CO₂(g) × H₂(g))

Kp = (PCO × PH₂O) / (PCO₂ × PH₂)

At equilibrium, the equilibrium constant expression can be written as:

Kc = [CO][H₂O] / [H₂][CO₂] = x²/ [(0.51-x)(0.51-x)]

Substituting the given value of Kc into the above equation and solving for x gives:

819 = x²/[(0.51-x)(0.51-x)]

x = 0.302

From the results, we can say that "There will be very little CO₂ and H₂" at equilibrium.

The equilibrium constant for the given reaction is 819.

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7.22 × 10³ grams of magnesium nitrate is equivalent to 4.306 × 10²⁵ molecules.

The number of molecules of a substance can be calculated by multiplying the number of moles in the substance by Avogadro's number as follows;

no of molecules = no of moles × 6.02 × 10²³

According to this question, 7.22 × 10³ grams of magnesium nitrate is given. The number of moles can be calculated as follows;

molar mass of Mg3N2 = 100.9494 g/mol

moles = 7.22 × 10³g ÷ 100.95g/mol = 71.52moles

no of molecules = 71.52 mol × 6.02 × 10²³

no of molecules = 4.306 × 10²⁵ molecules.

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The subsequent The following chemical equations are balanced:

Chemical equations serve to represent the transformation of reactants into products. For instance, iron sulfide is created when iron (Fe) and sulfur (S) combine (FeS). S(s) + Fe(s) = FeS (s) The + symbol denotes an iron-sulfur reaction.

A chemical equation can be used to condense the details of a chemical process. A chemical equation's generic form is: Products Reactants. In a chemical equation, the reactants are the chemicals that are present before the action begins, and the product are the materials that are created during the reaction.

2 AlBr3 + 3 K2(SO4) → 6 KBr + Al2(SO4)3

2 O2 + CH4 → 2 CO2 + 2 H2O

2 Na3(PO4) + 3 CaCl2 → 6 NaCl + Ca3(PO4)2

2 Al + 6 HCl → 3 H2 + 2 AlCl3

3 F2 + N2 → 2 NF3

2 NH3 + H2SO4 → (NH4)2SO4

C3H8 + 5 O2 → 3 CO2 + 4 H2O

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Answer:

it is a mixture.

Explanation:

Soda water is a solution of water (H2O) and carbon dioxide (CO2). It has a variable composition and there are not chemical bonds involved.

There is some chemical reaction between CO2 and H2O, producing some carbonic acid H2CO3. This is what gives a slight acidity to soda water.

The correct option for the given question about Mixtures is Option A) Mixture

A mixture of water (H2O) and carbon dioxide is soda water (CO2). There are no chemical bonds present, and it has a variable composition.

It is also called carbonated water as CO2 is first compressed and then get dissolved in it.

The chemical interaction between CO2 and H2O results in the production of H2CO3, a carbonic acid. This is what gives soda water a little acidity.

If the water is somewhat cold in temperature, gas can dissolve in it. The less soluble gas is, the hotter the water is. Additionally, more gas may dissolve in water at greater pressures for the water and gas combination.

Thus we can conclude that Soda water is a homogenous mixture of water and carbon dioxide.

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Answer:

Reactions take place too slowly at body temperature and must be speeded up.

Explanation:

Reactions take place too slowly at body temperature and must be speeded up.

An enzyme is a substance that acts as a catalyst in living organisms, regulating the rate at which chemical reactions proceed without itself being altered in the process. Enzymes are required for living things to function because they speed up chemical reactions. Enzymes are protein catalysts.

Reactions take place too slowly at body temperature and must be speeded up.

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The electron configuration for each of the following elements is provided below along with the symbol of the previous noble gas in brackets to represent the core electrons.1.

The electron configuration of an atom represents the distribution of electrons within the atom's atomic orbitals. Each electron shell is filled with electrons, beginning with the innermost shell, which is closest to the nucleus, and progressing outward. The symbol of the previous noble gas in brackets represents the core electrons.

The electron configuration of Ga, which has atomic number 31, is as follows: 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p¹ (Ar)The electron configuration of As, which has atomic number 33, is as follows: 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p³ (Ar)The electron configuration of Rb, which has atomic number 37, is as follows: 1s²2s²2p⁶3s²3p⁶4s¹ (Kr)The electron configuration of Sn, which has atomic number 50, is as follows: 1s²2s²2p⁶3s²3p⁶4s²3d¹⁰4p⁶5s²4d¹⁰5p² (Kr)

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Moving hot food in a covered pan to a cooler space, such as a storage room, or submerging it in ice water, is another option. Ice can also be used to hasten the cooling process.

Soups can be chilled by submerging them in cold water. This technique aids in a swift and secure drop in food temperature. To make a slush, put some ice in a big container or sink and add some water. After that, put the plate of food to be chilled into the ice bath. bathing in ice water and stirring the food often.Food is stirred with ice paddles, which are plastic containers that have been frozen after being filled with water.using ice as a component (if water is an ingredient).chiller that jars or tumbles.

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halogens have 7

allali have 2

noble gases have 8

K = 1

P = -3

Ra= 7

Cl = -1

N = 5

O = 6

Answer:

\(\boxed {\boxed {\sf C. \ 9460 \ kJ}}\)

Explanation:

The formula we must use is given to us:

\(q=mL_{vapor}\)

q is the energy, m is the mass, and L(vapor) is the latent heat of vaporization.

The energy is what we calculate and the mass is 2 kilograms. We need to find the latent heat of vaporization, which is on the table.

Now we know:

\(m= 2 \ kg \\L_{vapor}=4730 \ kJ/kg\)

Substitute the values into the formula.

\(q=(2 \ kg ) * (4730 \ kJ/kg)\)

Multiply. Note that the kilograms (kg) will cancel each other out.

\(q= 2* 4730 \ kJ\)

\(q= 9460 \ kJ\)

9460 kilojoules are required to vaporize 2 kilograms of copper.