The point (-2, -3) is rotated 90 degrees CCW about the origin. What are the coordinates of the image? *
1 point
(-3, -2)
(-3, 2)
(3, -2)
(3, 2)

Brainliest to fisrt answer I neeeed this please

To find the radius of the cylinder, we can use the formula for the volume of a cylinder:

V = πr²h

Given that the volume is 824 cubic inches, we can rearrange the formula to solve for the radius:

824 = πr²h

Since the height is not given, we cannot find the exact radius. However, we can still determine the relationship between the height and radius if the volume remains the same.

b. If the height of the cylinder is changed, but the volume stays the same, the radius will change inversely proportional to the height. This means that as the height increases, the radius will decrease, and vice versa. This relationship ensures that the volume remains constant.

Therefore, we cannot determine the exact radius without knowing the height, but we can conclude that the radius and height have an inverse relationship.

Answer:

\(2x(x+1)(x-6)(x+4)\)

Step-by-step explanation:

If \(a\) is a zero, then \((x-a)\) is a factor.

you add both the mixed numbers, which out be 5 2/3 so c.

If your total income before exemptions were $10,000, you would pay $0 taxes.

If your total income before exemptions were $20,000, you would pay $960 taxes.

If your total income before exemptions were $50,000, you would pay $5928 taxes.

A function that models total tax paid is T(x) = (0.10 x $15,000) + 0.18(x - 10,400 - 15,000).

No tax would be paid if income is $10,000. This is because $10,000 is less than the total deduction of $10,400($6350 + $4050).

Tax paid if total income is $20,000 = 0.10($20,000 - $10,400) = $960. The 18% tax would not be paid because income after the deductions is less than $15,000.

Tax paid if total income is $50,000 = 0.10 x $15,000 + 0.18($50,000  - $10,400 - $15,000) = $1500 + $4,428 = $5928

T(x) = (0.10 x $15,000) + 0.18(x - 10,400 - 15,000).

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The probability that Jessica picks a yellow pencil is 80%.

What exactly is probability?

Probability is a measure of an event's possibility or chance of occurring. It is stated as a number ranging from 0 to 1, or as a percentage ranging from 0% to 100%, where 0 indicates an impossible occurrence and 1 (or 100%) represents a certain event.

Now,

The probability of picking a yellow pencil =  the number of yellow pencils / total number of pencils:

Probability of picking a yellow pencil = Number of yellow pencils / Total number of pencils

In this case, there are 8 yellow pencils out of a total of 10 pencils:

Probability of picking a yellow pencil = 8 / 10

Simplifying the fraction by dividing both the numerator and denominator by 2, we get:

Probability of picking a yellow pencil = 4 / 5

Probability of picking a yellow pencil = 4 / 5 x 100%

Probability of picking a yellow pencil = 80%

Therefore, the probability that Jessica picks a yellow pencil is 80%.

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Answer:

The answer is most likely A.

The reason why, is because since the earning in 6 hours is $94.50, so the hourly wage would be, $15.75 because:

94.50/6 = 15.75

Graph B, for the first hour, the amount of dollars is correct, but in 11 hours, it says 25.75, which is not correct so Graph B cannot be it.

Graph C, shows that at hour 1, that it is 15.75 dollars, but at hour 2 16.75, as well with hour 3, 17.75. The graph is showing an increase of 1 dollar per hour, which is not correct so graph C is not it.

Graph D shows that at hour 6, there is $94.50, which is correct, but at hour 12, its 100.50. This is not true because , the hour has increased by 6, and when it increased by 6, the amount of pay increased by 6 as well, which is not the right way in which you would do so.

Option A is correct!

Step-by-step explanation:

Hope it helps! =D

Answer and Step-by-step explanation:

Divide both sides by 2 to get y.

2y > 4

y > 2

y > 2 is the answer.

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Answer:

origin.......................

Answer:on the x axis

Step-by-step explanation:

Answer & Step-by-step explanation:

It is less because 2 times 3/4 is the same as 2/1 times 3/4 which is 6/4 then simplify it and you get 3/2 which then is 1 1/2.

That is why 2 times 3/4 is less than 2.

Hope that helps ;)

Answer:

12

Step-by-step explanation:

3 (2*-1)^2

3*-2^2

3*4

12

The volume of A and B are 28m³ and 16m³ respectively.

For volume of A

The formula for volume of a cuboid is given as:

Volume = length × width × height

Substitute the values

Volume = 7 × 2 × 2

Volume = 28m³

For cuboid B

Volume = length× width × height

Substitute the values

Volume = 4 × 2 × 2

Volume = 16m³

Thus, the volume of A and B are 28m³ and 16m³ respectively.

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Answer:

[Fourth Option] 55.2

Step-by-step explanation:

60% -> 0.6

0.6 * 92 = 55.2

Have a nice day!

  I hope this is what you are looking for, but if not - comment! I will edit and update my answer accordingly. (ノ^∇^)

- Heather

Answer:

(D) 55.2

Step-by-step explanation:

To rewrite the expression -2(n-7) using the distributive property, we need to distribute the -2 to both terms inside the parentheses. The distributive property states that for any numbers a, b, and c:

a(b + c) = ab + ac

Applying this property to the given expression:

-2(n-7) = -2 * n + (-2) * (-7)

Simplifying further:

-2(n-7) = -2n + 14

Therefore, the rewritten expression is -2n + 14.

-1248 -1248 -. 936

- 3432

Answer:

5.29%

Step-by-step explanation:

5.29% = 100 x (1.99 - 1.89) / 1.89

Answer:

Step-by-step explanation:

The problem specifies that you may use a calculator. The formula, as reference, is:

You can use a regular calculator or an online spreadsheet to solve. In sheets, arrange your data and use the =PERCENTILE( ) function. In the parentheses, write the range of your data and the requested percentile as a decimal. So if I type the data (the ages of the signers for this example) in cells A:4 through A:23, I'd write =percentile(A7:A23,0.25).

So the answers:

25th percentile is 34.

80th percentile is 48.4.

Answer:

456

Step-by-step explanation:

The values of the coordinates x and y is P ( 6 , 3 )

The equation of a line is expressed as y = mx + b where m is the slope and b is the y-intercept

And y - y₁ = m ( x - x₁ )

y = y-coordinate of second point

y₁ = y-coordinate of point one

m = slope

x = x-coordinate of second point

x₁ = x-coordinate of point one

The slope m = ( y₂ - y₁ ) / ( x₂ - x₁ )

Given data ,

Let the equation of line be represented as A

Now , the value of A is

Let the first point be P ( x , y )

Let the second point be Q ( 0 , 0 )

Now , the slope of the line is m₁ = ( y₂ - y₁ ) / ( x₂ - x₁ )

Substituting the values in the equation , we get

Slope m₁ = y / x

m₁ = 1/2

So , y/x = 1/2

And , x = 2y

Now , the third point is R ( 7 , 5 )

m₂ = ( 5 - y ) / ( 7 - x )

m₂ = 2

On simplifying , we get

( 5 - y ) / ( 7 - x ) = 2

Multiply by ( 7 - x ) , we get

5 - y = 14 - 2x

Adding 2x and subtracting 5 on both sides , we get

2x - y = 9

Substitute the value of x from m₁ , we get

2 ( 2y ) - y = 0

3y = 9

Divide by 3 on both sides , we get

y = 3

And , the value of x = 6

Hence , the coordinate of the point P is P ( 6 , 3 )

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Answer:

2x² + 5x + c = 0

For this quadratic equation to have one double root, the discriminant must equal 0.

5² - 4(2)(c) = 0

25 - 8c = 0

c = 25/8

2x² + 5x is not a perfect square because the coefficient of x², 2, is not a perfect square.

2x² + 5x is not a perfect square.

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The total distance covered is 15000 m. The total time taken is 5220 seconds and the speed is 2.87 m/s.

We know that speed has to do with the ratio of the distance that has been covered to the time taken. The speed is a scalar quantity and as such we do not consider the direction hence we would not consider that going back in the opposite direction. The total distance can be obtained algebraically.

The total distance that the student travelled can be obtained from;

5000 m + 5000 m + 5000 m

= 15000 m

The total time taken in seconds = 1800 seconds + 1800 seconds + 1620 seconds

= 5220 second

Speed = Distance/ Time

= 15000 m/5220 second

= 2.87 m/s

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Answer:

\(5.80013+3.29613i\)

Step-by-step explanation:

Calculate the given double integral.

\(\int\limits^4_0 {\int\limits^{\sqrt{4y-y^2} }_0 {\sqrt{8-x^2-y^2} } \, dx } \, dy\)

\(\hrulefill\)

After attempting to solve this integral by hand, I found out quickly that this integral is way too complex to solve. I had to resort to a computing software to get an approximated solution. Here is what I got,

\(\int\limits^4_0 {\int\limits^{\sqrt{4y-y^2} }_0 {\sqrt{8-x^2-y^2} } \, dx } \, dy=\boxed{\boxed{5.80013+3.29613i}}\)

Below is all the work I had done before I stopped. I left my work here in case you wanted to take a peek. Other than that you can ignore it, as it ended up not being very useful.\(\hrulefill\)

(1) - Rearranging the integrand

\(\int\limits^4_0 {\int\limits^{\sqrt{4y-y^2} }_0 {\sqrt{8-x^2-y^2} } \, dx } \, dy\\\\\\\Longrightarrow \int\limits^4_0 {\int\limits^{\sqrt{4y-y^2} }_0 {\sqrt{8-y^2-x^2} } \, dx } \, dy\)

(2) - Applying trigonometric substitution to evaluate the first integral

\(\boxed{\left\begin{array}{ccc}\text{For} \ \sqrt{a-bx^2} \\\\ \rightarrow x=\sqrt{\dfrac{a}{b} }\sin(u) \end{array}\right}\)

Note that every term not containing an "x" is held constant. Thus, we can say:

\(a=8-y^2\\\\b=1\\\\\sqrt{\dfrac{a}{b} }=\sqrt{\dfrac{8-y^2}{1} } =\sqrt{8-y^2} \\\\\\\therefore \boxed{x=\sqrt{8-y^2} \sin(u) \ \text{and} \ dx=\sqrt{8-y^2} \cos(u)du}\)

Substituting in the values:

\(\int\limits^4_0 {\int\limits^{\sqrt{4y-y^2} }_0 {\sqrt{8-y^2-x^2} } \, dx } \, dy\\\\\\\Longrightarrow \int\limits^4_0 {\int\limits^{\sqrt{4y-y^2} }_0 {\sqrt{8-y^2-(\sqrt{8-y^2} \sin(u))^2} \cdot \sqrt{8-y^2} \cos(u) } \, du } \, dy\)

Simplifying the integrand:

\(\int\limits^4_0 {\int\limits^{\sqrt{4y-y^2} }_0 {\sqrt{8-y^2-(\sqrt{8-y^2} \sin(u))^2} \cdot \sqrt{8-y^2} \cos(u) } \, du } \, dy\\\\\\\\\Longrightarrow \int\limits^4_0 {\int\limits^{\sqrt{4y-y^2} }_0 {\sqrt{8-y^2-\sin^2(u)(8-y^2)} \cdot \sqrt{8-y^2} \cos(u) } \, du } \, dy\\\\\\\\\Longrightarrow \int\limits^4_0 {\int\limits^{\sqrt{4y-y^2} }_0 {\sqrt{8-y^2-8\sin^2(u)+y^2\sin^2(u)} \cdot \sqrt{8-y^2} \cos(u) } \, du } \, dy\)

\(\Longrightarrow \int\limits^4_0 {\int\limits^{\sqrt{4y-y^2} }_0 {\sqrt{(1-\sin^2(u))(8-y^2)}} \cdot \sqrt{8-y^2} \cos(u) } \, du } \, dy\)

Applying the Pythagorean identify:

\(\boxed{\left\begin{array}{ccc}\text{\underline{Pythagorean Identity:}}\\\\1-\sin^2{A}=\cos^2(A)\end{array}\right}\)

\(\Longrightarrow \int\limits^4_0 {\int\limits^{\sqrt{4y-y^2} }_0 {\sqrt{\cos^2(u)(8-y^2)}} \cdot \sqrt{8-y^2} \cos(u) } \, du } \, dy\)

Applying the following radical rule:

\(\sqrt{ab}=\sqrt{a}\sqrt{b}\)

\(\Longrightarrow \int\limits^4_0 {\int\limits^{\sqrt{4y-y^2} }_0 {\sqrt{\cos^2(u)}\sqrt{8-y^2}} \cdot \sqrt{8-y^2} \cos(u) } \, du } \, dy\\\\\\\\\Longrightarrow \int\limits^4_0 {\int\limits^{\sqrt{4y-y^2} }_0 {\cos(u)\sqrt{8-y^2}} \cdot \sqrt{8-y^2} \cos(u) } \, du } \, dy\\\\\\\\\Longrightarrow \boxed{ \int\limits^4_0 {\int\limits^{\sqrt{4y-y^2} }_0 {\cos^2(u)(8-y^2) } \, du } \, dy}\)

(3) - Adjusting the integral boundaries

\(\text{Recall,} \ x=\sqrt{8-y^2} \sin(u)\)

Solve for "u"

\(x=\sqrt{8-y^2}\sin(u) \\\\\\\Longrightarrow \sin(u)=\dfrac{x}{\sqrt{8-y^2}} \\\\\therefore \boxed{u=\sin^{-1}\Big(\dfrac{x}{\sqrt{8-y^2}}\Big)}\)

Adjusting the upper bound:

\(x_{upper}=\sqrt{4y-y^2}\\ \\\\\Longrightarrow u_{upper}=\sin^{-1}\Big(\dfrac{\sqrt{4y-y^2}}{\sqrt{8-y^2}}\Big)\)

Adjusting the lower bound:

\(x_{lower}=0\\ \\\\\Longrightarrow u_{lower}=\sin^{-1}\Big(\dfrac{0}{\sqrt{8-y^2}}\Big)\\\\\\\Longrightarrow u_{lower}=\sin^{-1}(0)\\\\\\\Longrightarrow u_{lower}=0\)

Now we have the following integral,

\(\int\limits^4_0 {\int\limits^{\sin^{-1}(\frac{\sqrt{4y-y^2} }{\sqrt{8-y^2} })}_0 {\cos^2(u)(8-y^2) } \, du } \, dy\)

(4) - Evaluating the first integral

\(\int\limits^4_0 {\int\limits^{\sin^{-1}(\frac{\sqrt{4y-y^2} }{\sqrt{8-y^2} })}_0 {\cos^2(u)(8-y^2) } \, du } \, dy\)

Pulling out the constant:

\(\Longrightarrow \int\limits^4_0 \Big[(8-y^2)\int\limits^{\sin^{-1}(\frac{\sqrt{4y-y^2} }{\sqrt{8-y^2}})}_0 {\cos^2(u)} \, du\Big]dy\)

Applying the square-to-linear identity:

\(\boxed{\left\begin{array}{ccc}\text{\underline{Square-to-Linear Identity:}}\\\\\cos^2(A)=\frac{1}{2}+\frac{1}{2}\cos(2A) \end{array}\right}\)

\(\Longrightarrow \int\limits^4_0 \Big[(8-y^2)\int\limits^{\sin^{-1}(\frac{\sqrt{4y-y^2} }{\sqrt{8-y^2}})}_0 {\dfrac{1}{2}+\dfrac{1}{2}\cos(2u) } \, du\Big]dy\\\\\\\\\Longrightarrow \int\limits^4_0 {(8-y^2)\Big[\dfrac{1}{2}u+\dfrac{1}{4}\sin(2u) \Big]\limits^{\sin^{-1}(\frac{\sqrt{4y-y^2} }{\sqrt{8-y^2}})}_0} \, dy \\\\\\\\\)

\(\Longrightarrow \int\limits^4_0 {(8-y^2)\Big[\dfrac{1}{2}(\sin^{-1}(\frac{\sqrt{4y-y^2} }{\sqrt{8-y^2}}))+\dfrac{1}{4}\sin(2\sin^{-1}(\frac{\sqrt{4y-y^2}}{\sqrt{8-y^2} } )\Big]\, dy \\\)

This is where I stopped^^

Answer:

y = -13/10x + 2/5

Hope this helps!

The measure of the angle in the triangle is of 85º.

In the context of this problem, the measure of the angle is found using the ruler in the given image.

Due to the position that the triangle opens, from left to right, we have to read the angles from the bottom line.

The measures are listed in intervals of 10º, however each trace represents one degree.

The angle of the illustrated triangle is positioned at the 5th trace between 80º and 90º, hence the measure of the angle in the triangle is calculated as follows:

80º + 5º = 85º.

This is because each trace represents one degree, and the angle is at the 5th trace between 80º and 90º.

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Answer:

20

Step-by-step explanation:

Find the number in the whole number place 9 and look one place to the right for the rounding digit on the right side of the decimal point 7. Round up if this number is greater than or equal to 5 and round down if it is less than 5.

All the options given are not true. The coordinates of Point H should be

(0,-3, -2). it becomes very obvious when you know how to read the figure of 3d geometry.

if we closely observe the figure we will see that point h is placed in 8th the quadrant. And as we know in the 8th quadrant x axis is positive and y & z axis are negative. Lets observe the y-z plane for point H. It is clear from the figure itself that value of z for point H is -2. Also value of y for point H is -3. we can locate our point H when we look at the y-z values together as in (x,-3,-2). It  means that value of x for point H is 0. Therefore coordinates of point H in 3d geometry will be (0.-3,-2).

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Answer: C

Step-by-step explanation:

1. divide 3 by 2 to find out how many pounds of blueberries she picked each day. 3/2 is 1.5

2. multiply 1.5 by 16 to convert to ounces. 1.5x16 is 24.

3. she picked 24 ounces of blueberries each day.

If two parallel lines are crossed by a transversal, the value of x is option (b) x = 70 degrees

When two parallel lines are intersected by a transversal, eight angles are formed. Two of these angles are vertical angles, which are opposite angles that share the same vertex and are formed by the intersection of two lines.

Vertical angles are always congruent, meaning they have the same measure. This is a geometric property that is true regardless of the angle's degree measurement.

In this problem, one of the vertical angles is given to be 70 degrees. Therefore, the other vertical angle must also have a measure of 70 degrees. This means that the value of x, which is the measure of one of the vertical angles, is also 70 degrees.

So, correct option is (b) x = 70 degrees.

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The given question is incomplete, the complete question is:

Two parallel lines are crossed by a transversal. What is the value of x? a) x = 40 b) x = 70 c) x = 110 d) x = 130.

Answer:

x = 9

Step-by-step explanation:

\(a^{2} = c^{2} - b^{2}\)

\(a^{2} = 15^{2} - 12^{2}\)

\(a^{2} = 225 - 144\)

\(a^{2} = 81\)

\(\sqrt{a^2} = \sqrt{81}\)

\(a = 9\)

Answer:

LCM of 12 and 3 is 12

Step-by-step explanation:

hope it helps you vhprince