the radioactive isotope europium decays with a first order rate constant of 0.062 year-1. What fraction of the europium in a sample is still present 55.0 years later

the spin quantum number has values+1212 of -1212 describes the trends in ionic size.

spin quantum is denoted by (s) as it represents the electronic configuration of the atom and the ionic size also depends on the electronic configuration of the sub-shells of the atom like l, m, n, s.

ionic size increases as the electronic configuration increases because the electron adds as we move up to a higher atomic number

all the other quantum numbers may vary from atom to atom but the spin quantum number remains either +1212 or -1212. it also describes the orientation of the electrons in an atom and the axis of electrons in an atom.

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Answer:

maybe all the basic oxide i guess

Explanation:

cuo + hcl -> cucl2 + h20

...

The reaction of zinc oxide with hydrochloric acid is as follows:

The reaction of zinc chloride with hydrochloric acid represents an example of a neutralization reaction. This reaction significantly forms zinc chloride which is a salt and water.

According to the context of this question, the desired product of the given reaction forms the salt. In this reaction, zinc oxide acts as a base while hydrochloric acid is the strongest acid.

When acid reacts with bases, the product formed is called a salt, so zinc chloride is a salt. This is because it is one of the characteristic properties of acid.

Therefore, the desired product of the reaction of zinc oxide with hydrochloric acid is well described above.

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When there is an increase in an activity, like sales or manufacturing, the overall amount of an expense, known as a fixed expense, does not change.

Thus, Normal definitions typically include the phrase within a relevant or appropriate range of activity since a change is likely to take place at fixed expense either an exceptionally high or low volume or expense.

Of course, the rent will probably need to adjust if sales quadruple or fall to 20% of the average level. However, as the extreme circumstances are outside of the relevant range for short-term analysis, the current rent of $2,000 is regarded as a fixed expense.)

The following are some instances of costs that are probably set within a fair range of retail sales, The yearly pay for the shop manager.

Thus, When there is an increase in an activity, like sales or manufacturing, the overall amount of an expense, known as a fixed expense, does not change.

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The total number of atoms for each element in a chemical equation that is balanced is the same on both sides of the equation.

An equation for a chemical reaction is said to be balanced if both the reactants and the products have the same number of atoms and total charge for each component of the reaction.

For the chemical equation to adhere to the rule of conservation of mass, it must be balanced. A chemical equation is said to be balanced when the number of various elemental atoms on the reactants and products sides are equal.

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472.7ml of a .5500 M solution of NaI are needed to produce 34.81mg of I\(_2\) in the reaction COCl\(_2\)+2NaI  → 2NaCl+CO+I\(_2\).

A measurement of three-dimensional space is volume. Several imperial or US customary units, as well as SI-derived units (such the cubic meter and liter), are frequently used to quantify it quantitatively. Volume and length (cubed) have a symbiotic relationship.

COCl\(_2\)+2NaI  → 2NaCl+CO+I\(_2\)

number of moles of I\(_2\) =34.81/254=0.13moles

2 moles of NaI gives 1 moles of I\(_2\)

0.13moles are obtained by 2×0.13=0.26moles of NaI

0.550moles of I\(_2\) is present in 1000ml

0.26moles of I\(_2\) is present in (1000/0.55)×0.26=472.7ml

Therefore, 472.7ml of a .5500 M solution of NaI are needed to produce 34.81mg of I\(_2\).

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Answer:

B.  26.0 μL.

Explanation:

Hello,

In this case, taking into account that given the mass and density, the volume is computed to be:

\(V=\frac{m}{\rho} =\frac{25.000mg}{0.788g/mL}*\frac{1g}{1000mg}*\frac{1000\mu L}{1mL} \\ \\V=26.0\mu L\)

Thus, answer is B.  26.0 μL.

Best regards.

Step 1 - Understanding how to convert Celsius to Kelvin

Kelvin is called the absolute temperature because its zero is based on the complete absence of molecular motion (which is possible in theory, but quite impossible to reach experimentally).

The temperature in Kelvin is related to the temperature in Celsius by the following expression:

That is, to obtain the temperature in Kelvin, we just need to add 273.15 to the temperature in Celsius.

Step 2 - Using the expression to solve the exercise

The boiling point of propane is -42.0°C. Note that this is our T(°C). To obtain T(K) let's plug the value in the equation:

The equivalent temperature in Kelvin would be thus 231.15 K.

Answer:

CuSO₄.H₂O = 1

CuSO₄.3H₂O = 3

CuSO₄.5H₂O = 5

CuSO₄7.H₂O = 7

CuSO₄.9H₂O = 9

Explanation:

Some salts as CuSO₄ are presented in the hydratated form to give some stability in their uses.

Ratio of moles represents moles of H₂O / moles of CuSO₄.

In CuSO₄.H₂O you have 1 mole of water per mole of CuSO₄, Ratio is 1/1 = 1.

For CuSO₄.3H₂O are 3 moles of water per mole of CuSO₄. Ratio is 3/1 = 3

For CuSO₄.5H₂O are 5 moles of water per mole of CuSO₄. Ratio is 5/1 = 5

For CuSO₄.7H₂O are 7 moles of water per mole of CuSO₄. Ratio is 7/1 = 7

For CuSO₄.9H₂O are 9 moles of water per mole of CuSO₄. Ratio is 9/1 = 9

Answer:

W is tungsten on the periodic table

Answer:

\(T_2=400.73K\)

Explanation:

From the question we are told that:

Activation energy \(E_a= 51.02 kJ/mol.=>51.02*10^3J/mol\)

Reaction Ratio \(\triangle K=4.50\)

Initial Temperature \(T_1=365K\)

Generally the equation for Final Temperature \(T_2\) is mathematically given by

 \(log \triangle K=\frac{E_a}{2.303R}*(\frac{T_2-T_1}{T_1T_2})\)

Where

 \(R=Gas constant\)

 \(R =8.3143\)

Therefore

 \(log 4.50=\frac{51.2*10^3}{2.303*8.31432}*(\frac{T_2-365}{365*T_2})\)

 \(log 4.50=7.328*\frac{T_2-365}{T_2}\)

 \(0.0892=\frac{T_2-365}{T_2}\)

 \(0.0892T_2=T_2-365\)

 \(365=T_2-0.0892T_2\)

 \(365=0.91T_2\)

 \(T_2=\frac{365}{0.91}\)

 \(T_2=400.73K\)

Taking into account the reaction stoichiometry, a mass of 6.24 grams of Ba(OH)₂ are required to react with 12.2 grams of caesium phosphate.

In first place, the balanced reaction is:

3 Ba(OH)₂ + 2 Cs₃PO₄ → Ba₃(PO₄)₂ + 6 CsOH

By reaction stoichiometry (that is, the relationship between the amount of reagents and products in a chemical reaction), the following amounts of moles of each compound participate in the reaction:

The molar mass of the compounds is:

Then, by reaction stoichiometry, the following mass quantities of each compound participate in the reaction:

The following rule of three can be applied: If by reaction stoichiometry 987.4 grams of Cs₃PO₄ react with 504.9 grams of Ba(OH)₂, 12.2 grams of Cs₃PO₄ react with how much mass of Ba(OH)₂?

mass of Ba(OH)₂= (12.2 grams of Cs₃PO₄× 504.9 grams of Ba(OH)₂)÷ 987.4 grams of Cs₃PO₄

mass of Ba(OH)₂= 6.24 grams

Finally, a mass of 6.24 grams of Ba(OH)₂ are required.

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This is a perfect answer

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The partial pressure of nitrogen is approximately 733 mm Hg. Please note that the answer is rounded to the nearest whole number, which is 733 mm Hg. Option D)

To determine the partial pressure of nitrogen, we need to consider the Dalton's Law of Partial Pressures, which states that the total pressure of a gas mixture is the sum of the partial pressures of each gas present.

Given that the total pressure in the laboratory is 775 mm Hg and the partial pressure of water at 35.0°C is 42.2 mm Hg, we can calculate the partial pressure of nitrogen.

To find the partial pressure of nitrogen, we subtract the partial pressure of water from the total pressure:

Partial pressure of nitrogen = Total pressure - Partial pressure of water

Partial pressure of nitrogen = 775 mm Hg - 42.2 mm Hg

Partial pressure of nitrogen = 732.8 mm Hg

Therefore, the partial pressure of nitrogen is approximately 733 mm Hg.

Please note that the answer is rounded to the nearest whole number, which is 733 mm Hg. Option D) is correct.

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Answer:

6

Explanation:

I somehow know just cause im smart and stuff.

Electron configuration refers to the distribution of electrons in atoms and molecules.

In conclusion, electron configuration refers to the distribution of electrons in atoms and molecules.

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Answer:

In atomic physics and quantum chemistry, the electron configuration is the distribution of electrons of an atom or molecule in atomic or molecular orbitals.

To predict the products of such a reaction, see what happens if the chemical breaks into smaller, familiar products such as water, carbon dioxide, or any of the gaseous elements

AgNO3+Na2SO4→AgSO4+2NaNO3 is an exchange reaction.

Na + O2→ Na2O .

is an exchange reaction.

Thus, we refer to these processes as redox. Na is oxidized by losing electrons in reaction (a), while O is reduced by gaining electrons, forming O2-ions.

A single-displacement reaction would be Mg + HBr > MgBr2 + H2 HBr + Mg. In this process, magnesium creates magnesium bromide by swapping out hydrogen from HBr (MgBr2).

The decomposition process CuSO4(aq) + Zn(s) ZnSO4(aq) + Cu(s) is an illustration.

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Answer:

The Relationship between Pressure and Volume: Boyle's Law

As the pressure on a gas increases, the volume of the gas decreases because the gas particles are forced closer together. Conversely, as the pressure on a gas decreases, the gas volume increases because the gas particles can now move farther apart

Answer:

c

Explanation:

Photosynthesis is a chemical reaction in which energy from sunlight is used to convert carbon dioxide and water into glucose and oxygen. This process occurs in the chloroplasts of plant cells and is essential for the survival of plants, as well as for many other organisms that depend on plants for food.

Considering the definition of percent yield, the percent yield is 76%.

The percent yield is the ratio of the actual return to the theoretical return expressed as a percentage.

The percent yield is calculated as the experimental yield divided by the theoretical yield multiplied by 100%:

\(percent yield=\frac{actual yield}{theorical yield}x100\)

where the theoretical yield is the amount of product acquired through the complete conversion of all reagents in the final product, that is, it is the maximum amount of product that could be formed from the given amounts of reagents.

In this case, you know:

Replacing in the definition of percent yield:

\(percent yield=\frac{0.532 moles}{0.700 moles}x100\)

Solving:

percent yield= 76%

Finally, the percent yield is 76%.

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The equilibrium constant (Kc) for the given reaction is approximately 16.448. The value of Kc indicates the relative concentrations of reactants and products at equilibrium. In this case, a Kc greater than 1 suggests that the products (H2 and P4) are favored at equilibrium, indicating that the forward reaction is more favorable.

To determine the equilibrium constant (Kc) for the given reaction:

4PH3(g) ↔ 6H2(g) + P4(g)

We can write the equilibrium constant expression based on the stoichiometric coefficients:

Kc = ([H2]^6 * [P4]) / ([PH3]^4)

Substituting the given equilibrium concentrations:

[PH3] = 0.250 M

[H2] = 0.580 M

[P4] = 0.750 M

We can plug in these values into the equilibrium constant expression:

Kc = ([0.580]^6 * [0.750]) / ([0.250]^4)

Kc = (0.0860128 * 0.750) / (0.00390625)

Kc = 16.448

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Answer:

a) the final temperature of the air is 500° R

b) the amount of specific entropy produced is 0.0758 Btu/lb-°R  

Explanation:

Given the data in the question;

Air at 500° R = \(T_i\)

Using first law of thermodynamic;

δQ = dU + W

now, since the vessel is insulated, the transfer is zero, work done also is zero since there is also no external work done.

δQ = dU + W

0 = dU + 0

dU = 0

\(u_f\) - \(u_i\) = 0

\(u_f\) = \(u_i\)

hence, change in internal energy is 0

Now, since the ideal internal energy is a function of temperature, the temperature will also remain the same;

\(T_f = T_i\)

F = 500° R

Therefore, the final temperature of the air is 500° R

b)

given that; initial volume is one-third of the total volume

V₁ = \(\frac{1}{3}\)V₂

3V₁ = V₂

3 = V₂/V₁

Now, we take the value of gas constant R from air property table;  gas constant R = 0.069 Btu/lb-R  

so we calculate the entropy change;

Δs = \(c_v\)In( \(\frac{T_2}{T_1}\) ) + R.In( \(\frac{V_2}{V_1}\) )

we substitute

Δs = \(c_v\)In( \(\frac{500}{500}\) ) + 0.069 × In( 3 )

Δs = 0 + [0.069 × In( 3 )]

Δs = 0 + [0.069 × 1.0986]

Δs = 0.0758 Btu/lb-°R  

Therefore, the amount of specific entropy produced is 0.0758 Btu/lb-°R  

Insulated vessels separate the environment of the outer and the inner system. The final temperature is 500 degrees R and 0.0758 Btu/lb- degree R is the entropy.

The temperature is the measure of the hot or the coldness of the system.  The first law of the thermodynamics is used to measure the final temperature of the system:

\(\rm \Delta Q = \rm \Delta U + W\)

The work done will be zero as the system is insulated and no external work is being done.

\(\begin{aligned} \rm 0 &= \rm \Delta U + 0\\\\\rm U_{f} - U_{i} &= 0\\\\\rm U_{f} &= \rm U_{i} \end{aligned}\)

Hence, the change in the internal energy is zero. Thus, the final temperature will remain the same,

\(\rm T_{f} = \rm T_{i} = 500 ^{\circ} \rm R\)

Now, as we know, the initial volume is one-third of the total volume then,

\(\begin{aligned} \rm V_{1} &= \rm \dfrac{1}{3} V_{2}\\\\\rm 3V_{1}&= \rm V_{2}\\\\3 &= \rm \dfrac{V_{1}}{V_{2}}\end{aligned}\)

The change in entropy is calculated as:

\(\begin{aligned} \rm \Delta S &= \rm C_{v} ln ( \dfrac{T_{2}}{T_{1}}) + R \times ln ( \dfrac{V_{2}}{V_{1}}) \\\\&= 0 + [0.069 \times \rm ln( 3 )]\\\\& = 0.0758 \;\rm Btu/lb-^{\circ}R \end{aligned}\)

Therefore, the entropy produced is 0.0758 Btu/lb- degree R.

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Answer:

To start, you need know that all a mole means is you have 6.022 x 1023 atoms of that type. So if I tell you I have a mole of nitrogen, then I have 6.022 x1023 nitrogen atoms. That ugly number is called Avogadro's Constant, NA

Explanation:

hy its isnt the correct answer but checkout the equation hope it help help

Protons are positively charge particles that reside in the nucleus of an atom.

Neutrons are neutrally charged particles that also reside in the nucleus of an atom.

Electrons are negatively charged particles that orbit the nucleus in different levels called orbitals

Answer:

14g of Y to form the compound XY₂

Explanation:

In the compound XY, you have 1 mole of X and 1 mole of Y. Thus, you can imagine the molar mass of X is 2g/mol and molar mass of Y is 7g/mol.

Now, in the compound XY₂, you have 1 mole of X but 2 moles of Y.

If you have 2g of X, in this case you will need:

2 moles Y * (7g / mol) =

14g of Y to form the compound XY₂

The amount of element Y needed to form compound XY2 is; 14g of element Y.

From the law of conservation of mass which states that;

Matter can never be created nor destroyed.

By stoichiometry;

Since:

7 g of element Y to form compound XY(y =1)

a g of element Y to form compound XY2(y =2)

In essence,

a g = (2 × 7g)/1

a = 14g

Therefore, 14g of element Y is needed to form compound XY2.

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Answer:

Physical

Chemical

Explanation:

Intermolecular forces are the forces that hold the molecules of a substance together in a particular state of matter. They decide the physical properties of a substance.

The intra molecular forces are the bond forces that hold atoms together in molecules. The nature of this bonding determines the chemical properties of substances.

The total concentration of ions remaining in the solution is 0.0007 M.

To solve this problem, we need to determine the concentration of both magnesium nitrate and sodium hydroxide before the solutions are mixed, and then use the reaction between magnesium nitrate and sodium hydroxide to determine the concentration of ions remaining in solution after the reaction is complete.

To calculate the total concentration of ions remaining in solution after the reaction is complete, we need to first determine the number of moles of each reactant present before the reaction occurs. To do this, we can use the molar mass of each compound to convert the mass of each compound to moles.

First, we can calculate the number of moles of magnesium nitrate present in the 22.02 mL solution:

Number of moles of magnesium nitrate = (1.615 g magnesium nitrate) / (148.32 g/mol magnesium nitrate) = 0.0109 moles magnesium nitrate

Next, we can calculate the number of moles of sodium hydroxide present in the 28.64 mL solution:

Number of moles of sodium hydroxide = (1.073 g sodium hydroxide) / (40.00 g/mol sodium hydroxide) = 0.0268 moles sodium hydroxide

Now that we know the number of moles of each reactant, we can use the balanced chemical equation for the reaction between magnesium nitrate and sodium hydroxide to determine the number of moles of each product that will be formed:

Magnesium nitrate + Sodium hydroxide -> Magnesium hydroxide + Sodium nitrate

1 mole magnesium nitrate + 1 mole sodium hydroxide -> 1 mole magnesium hydroxide + 1 mole sodium nitrate

Since we have 0.0109 moles of magnesium nitrate and 0.0268 moles of sodium hydroxide, the number of moles of each product that will be formed is also 0.0109 moles for magnesium hydroxide and 0.0268 moles for sodium nitrate.

Finally, we can use the number of moles of each product and the total volume of the solution to calculate the concentration of each product in the solution. The total volume of the solution is 22.02 mL + 28.64 mL = 50.66 mL.

The concentration of magnesium hydroxide in the solution is:

(0.0109 moles magnesium hydroxide) / (50.66 mL solution) = 0.0002 M magnesium hydroxide

The concentration of sodium nitrate in the solution is:

(0.0268 moles sodium nitrate) / (50.66 mL solution) = 0.0005 M sodium nitrate

The total concentration of ions remaining in the solution after the reaction is complete is the sum of the concentration of the magnesium ions and the concentration of the sodium ions. The concentration of the magnesium ions is 0.0002 M, and the concentration of the sodium ions is 0.0005 M, so the total concentration of ions remaining in the solution is 0.0002 M + 0.0005 M = 0.0007 M.

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The result of the computation when you follow the steps is 1.699.

A logarithm is a mathematical function that represents the exponent or power to which a specific base must be raised to obtain a given number. In simpler terms, it answers the question: "To what power must we raise a base number to obtain a certain value?"

What you should do is that on your calculator, you could press the logarithm key and then put in the value that has been shown and then the result would be displayed on your calculator.

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NO is the most stable among the given compound. Thus, the most appropriate answer comes out to be option D.

The bond order is the number of bonds between two atoms. The higher the bond order the higher the stability of the compound.

It is calculated by  (number of bonding electrons - Number of the anti-bonding electron) * 0.5  

So, for C\(O_2\) the bond order is 2

For \(C_2\) ,

The number of electrons in the bonding orbital = 8.

Number of electrons in anti-bonding orbital = 4.

Bond order = (8- 4) * 0.5 = 2.

For \(O_2\) ,

The number of electrons in the bonding orbital = 10.

Number of electrons in anti-bonding orbital = 6.

Bond order = (10 - 6) * 0.5  = 2.

For NO,

The number of electrons in the bonding orbital = 10.

Number of electrons in anti-bonding orbital = 5.

Bond order = (10 - 5) * 0.5  = 2.5

Thus, the most stable compound is NO as it has a 2.5 bond order.

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