The science that studies the impact of atmospheric smog on genetic expression, causing cancer and other diseases such as asthma, is called _____.


bioinformatics

biotechnology

epigenomics

molecular biology

Answer:

b. Hydrofluoric acid/sodium fluoride (pKa=3.14).

Explanation:

Hello!

In this case, since the buffer capacity is related to how good a buffer behaves under the addition of acidic or basic substances in the light of holding the pH as constant as possible, we need to keep in mind that the best buffer must have a pKa as close as possible to the desired pH, that is, if the desired pH here is 3.20, we must pick the acid/base pair which the pKa cosest to 3.20.

In such a way, since b. Hydrofluoric acid/sodium fluoride (pKa=3.14 ) and c. Nitrous acid/sodium nitrite (pKa=3.34) have a pKa close to 3.20, the closest one is b. Hydrofluoric acid/sodium fluoride pKa=3.14 which is 0.06 pH units away from the desired pH, therefore the answer is b. Hydrofluoric acid/sodium fluoride pKa=3.14.

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a. The Mass of water driven off = 0.15 g

b. Moles of anhydrate = 0.00257 moles

c. Moles of water driven off is 0.00833 moles

d. There are 3 moles of water within the crystalline structure of one molecule of the hydrated salt.

e. The molecular formula of the hydrated salt will be X.3H₂O

a. The mass of water driven off from the hydrated salt is:

Mass of water driven off = 0.5 g - 0.35 g

Mass of water driven off = 0.15 g

b. Molecular mass of salt = 136 g/mol

moles of anhydrate = 0.35/136

Moles of anhydrate = 0.00257 moles

c. Moles of water driven off = mass/molar mass

molar mass of water = 18 g/mol

Moles of water driven off = 0.15/18

Moles of water driven off = 0.00833 moles

d. Moles of water within the crystalline structure of one molecule of the hydrated salt is determined by converting to whole number mole ratio by dividing with the smallest ratio,

Salt to water ratio = 0.00257 /0.00257  :  0.00833/0.00257

Salt to water ratio = 1 : 3

Therefore, there are 3 moles of water within the crystalline structure of one molecule of the hydrated salt.

e. Assuming the anhydrous salt is X, the molecular formula of the hydrated salt will be X.3H₂O

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Answer:

1] Given the equation: 2 NH3 (g) + 3 Cl2(g) ---> N2(g) + 6 HCl(g)

a. How many milliliters of nitrogen can be made from 13 L of chlorine and 10.0 L of ammonia gas at STP?

10.0 L NH3 X

1 L N2

2 L NH3 = 5.00 L N2

13 L Cl2 X

1 L N2

3 L Cl2

= 4.3 L N2

Answer ________4.3 x 103 mL N2_________

b. How many grams of chlorine must react to produce 16 L of nitrogen gas at 1.2 atm and 23oC?

nN2 = (1.2atm) x (16L)

(0.0821

L-atm

mol-K) x (273+23)K

= 0.790 mol N2

0.790 mol N2 X

3mol Cl2

1mol N2

X 70.1g Cl2

1mol = 1.66 x 102 L Cl2

Explanation:

The amount of dry solute it would take to prepare 118 mL of 0.105 M NaNO3 is 1.05g.

The mass of a substance can be calculated by multiplying the number of moles in the substance by its molar mass as follows:

mass = no of moles × molar mass

However, the number of moles it took to prepare 118 mL of 0.105 M NaNO3 must be calculated as follows;

no of moles = 0.105 × 0.118 = 0.0124 moles

molar mass of sodium nitrate = 85g/mol

mass = 85g/mol × 0.0124 moles = 1.05g

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At constant temperature and pressure, If the amount of gas increases to the given value, its volume also increases to 20.85L.

Avogadro's law states that "equal volumes of all gases, at the same temperature and pressure, have the same number of molecules."

It is expressed as;

V₁/n₁ = V₂/n₂

Given the data in the question;

V₁/n₁ = V₂/n₂

V₁n₂ = V₂n₁

V₂ = V₁n₂ / n₁

V₂ = (13.9L × 3moles) / 2moles

V₂ = 41.7molL / 2mol

V₂ = 20.85L

Therefore, at constant temperature and pressure, If the amount of gas increases to the given value, its volume also increases to 20.85L.

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Answer:

Ductile

Explanation:

The metal is ductile, and that is why it can be stretched into wires.

Answer:

Analyze data and draw conclusions

Explanation:

because i got it right

The volume of the gas at 100K If 1 liter of gas at 300 K is cooled to 100K is 0.33L.

The volume of a gas can be calculated using the following formula:

V1/T1 = V2/T2

Where;

According to this question, a gas is in a flexible container. If 1 liter of gas at 300K is cooled to 100K. The volume of the gas is calculated as follows:

1/300 = V2/100

100 × 1 = 300V2

100 = 300V2

V2 = 100/300

V2 = 0.33L

Therefore, the volume of the gas at 100K If 1 liter of gas at 300 K is cooled to 100K is 0.33L.

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Answer:

24.088 * 10^23 atoms

Explanation:

The number of atoms in 4 moles of any atom is a constant since 1 mole has 6.022 * 10^23 atoms which is not affected by any property of any atom

So, 4 moles of Na will have 4 * 6.022 * 10*23 atoms

24.088 *10^23 atoms are present in 4 moles of any element

There are approximately 1.62 x 10^25 water molecules in the 499.8 mL bottle of water.

To determine the number of water molecules in the given volume of water, we need to use the relationship between mass, volume, and molar mass of water.

First, we need to find the mass of water in the bottle:

Mass = Density * Volume

Mass = 0.967 g/mL * 499.8 mL = 483.9 g

Next, we need to convert the mass of water to moles using the molar mass of water. The molar mass of water (H2O) is approximately 18.015 g/mol.

Moles = Mass / Molar mass

Moles = 483.9 g / 18.015 g/mol = 26.88 mol

Finally, we can calculate the number of water molecules using Avogadro's number, which is approximately 6.022 x 10^23 molecules/mol.

Number of molecules = Moles * Avogadro's number

Number of molecules = 26.88 mol * (6.022 x 10^23 molecules/mol) = 1.62 x 10^25 molecules

Therefore, there are approximately 1.62 x 10^25 water molecules in the 499.8 mL bottle of water.

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A mole ratio is a conversion factor that is used in stoichiometry calculations. It is a ratio between the number of moles of one substance and the number of moles of another substance in a balanced chemical equation.

To write a mole ratio, you first need to make sure that the chemical equation is balanced. Once the equation is balanced, you can use the coefficients in front of each substance to determine the mole ratio.

For example, consider the following balanced equation:

2 H₂ + O₂ → 2 H₂O

The mole ratio of hydrogen to oxygen in this equation is 2:1. This means that for every 2 moles of hydrogen, there is 1 mole of oxygen.

Similarly, the mole ratio of water to oxygen is 2:1, and the mole ratio of water to hydrogen is 2:2, or 1:1.

To write a mole ratio, simply write the coefficients of the substances in the equation in the form of a ratio. For example:

Mole ratio of hydrogen to oxygen = 2:1

Mole ratio of water to oxygen = 2:1

Mole ratio of water to hydrogen = 1:1

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Answer:

V=mass/Density

Explanation:

Since density is measured as grams/mL or grams/cm^3 and we are interested in converting mass to volume, we need to rewrite the equation.
Therefore, in order to convert the gram to mL, you just need to multiply the mass of the substance in grams with its density to get the volume in liters.

Answer:

Volume equals mass divided by density.

and

Mass equals density times volume.

Hope this helps :)

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Answer:

Option C Removing Na₂CO₃

Option E Heating the container.

Explanation:

The equation for the reaction is given below:

2NaHCO₃ (s) <=> Na₂CO₃ (s) + CO₂ (g) + H₂O (g)

Enthalpy change (ΔH) = 136 KJ

To obtain more CO₂ do the following:

1. Add more NaHCO₃

From chemical equilibrium, adding more NaHCO₃ means the reactant has increase. Thus, it (the reactant) will react to form more product (CO₂)

2. Removing any of the products. Removing any of the products implies that more reactants are in the reaction vessel than the product. Thus, the reactants will react to produce more products (CO₂)

3. Heating the container. Heating the container will lead to an increase in the temperature of the reaction. Since the enthalpy change (ΔH) is positive it means the reaction is endothermic. Thus, heating the container i.e increasing the temperature will favours the forward reaction i.e more products will be obtained.

NOTE: Pressure has no effect in the reaction system since there is no gaseous reactants.

Considering the options given above, C and E gives the correct answer to the question.

Answer:

28

Explanation:

The grams of salt dissolved in the solution was 28, because 40 minus 12 would be 28. I know I'm suppose to subtract 40 by 12 considering the fact, it is 12 grams of salt that came out. The rest of the numbers are irrelevant. (apologies this is a week late.)

The amount of salt that was dissolved in the water is 28 grams of the salt.

The term solubility refers to the amount of a substance that dissolves in solution. In this case we are told that about  40-grams of salt was added to water but about 12 grams of the salt came out of the solution.

In this case, the amount of salt that was dissolved in the water is 40 g - 12 g = 28 grams of the salt.

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The appropriate product are: 2Na(s) + F₂(g) → 2NaF(s), Na(s) + 1/2F₂(g) → NaF(s) and H₂(g) + 1/2O₂(g) → H₂O(g).

The prοcess by which οne οr mοre substances, referred tο as reactants, are changed intο οne οr mοre distinct substances, referred tο as prοducts, by the rearranging οf atοms and the breaking and fοrming οf chemical bοnds, is referred tο as a reactiοn. Chemical equatiοns that display the reactants οn the left and the prοducts οn the right, with an arrοw pοinting in the reactiοn's directiοn, can be used tο describe chemical reactiοns.

The amοunt οf energy released οr absοrbed when οne mοle οf a cοmpοund is prοduced frοm its cοmpοnent elements in their standard states at 1 atm and 25°C is knοwn as the standard enthalpy οf fοrmatiοn, οr Hf. The reactants must be in their standard states and the prοducts must be οne mοle οf the cοmpοund created frοm the cοnstituent elements in their standard states fοr a reactiοn tο have Hrxn equal tο Hf οf the prοduct(s).

These standards allοw us tο cοnclude that the subsequent reactiοns cοmply with the requirements:

2Na(s) + F₂(g) → 2NaF(s)

Na(s) + 1/2F₂(g) → NaF(s)

H₂(g) + 1/2O₂(g) → H₂O(g)

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A surfer rides an ocean wave is fluid friction

A bowling ball travels down a bowling lane rolling friction

A baseball flies through the air is air resistance

A hose rests on the edge of a truck is static friction.

Friction is described as the force resisting the relative motion of solid surfaces, fluid layers, and material elements sliding against each other.

Static friction is that force that keeps an object at rest.

It is that  friction experienced when individuals try to move a stationary object on a surface, without actually triggering any relative motion between the body and the surface on which it is on.

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Complete question:

dentify the type of friction acting in each scenario.

A surfer rides an ocean wave.

A bowling ball travels down a bowling lane.

A baseball flies through the air.

A hose rests on the edge of a truck.

OPTIONS:

air resistance

fluid

rolling

sliding

static

In Atlanta, GA, certain seasons are associated with poorer air quality due to various factors such as weather conditions, human activities, and geographical location.

Typically, the seasons with the worst AQI in Atlanta, GA, are summer and early fall. This is primarily due to the combination of high temperatures, stagnant air masses, and increased pollution from various sources.

During the summer months, Atlanta experiences hot and humid weather, which can contribute to the formation of ground-level ozone. Ozone is a harmful pollutant that is created when pollutants from vehicles, power plants, and industrial activities react with sunlight and heat. High levels of ozone can cause respiratory issues and other health problems.

In addition to ozone, Atlanta also experiences increased levels of particulate matter (PM) during the summer and early fall. PM refers to tiny particles suspended in the air, which can come from sources such as vehicle exhaust, industrial emissions, and wildfires.

These particles can be inhaled into the lungs and can have detrimental effects on respiratory health.

It's important to note that air quality can vary from year to year and is influenced by various factors. Local regulations, weather patterns, and changes in pollutant emissions can all impact the AQI during different seasons.

Monitoring air quality reports and taking necessary precautions such as reducing outdoor activities during times of poor air quality can help individuals stay informed and protect their health.

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Answer:

Iron(III) Carbonate

Explanation:

thts it

Answer:

\(\boxed{\boxed {\sf 5930.0 \ mol \ CH_4}}\)

Explanation:

We are asked to find how many moles of methane (CH₄)  a cow produces in a year. We must convert molecules of methane to moles of methane. We will do this using Avogadro's Number or 6.022 × 10²³. This is the number of particles (atoms, molecules, formula units, etc.) in 1 mole of a substance.

In this case, the particles are molecules of methane. There are 6.022 × 10²³ molecules of methane in 1 mole.

We will convert molecules to moles using dimensional analysis. Set up a ratio using Avogadro's Number.

\(\frac {6.022 \times 10^{23} \ molecules \ CH_4}{ 1 \ mol \ CH_4}\)

We are converting 3.571 × 10²⁷ molecules of methane to moles, so we multiply the ratio by this value.

\(3.571 \times 10^ {27} \ molecules \ CH_4 *\frac {6.022 \times 10^{23} \ molecules \ CH_4}{ 1 \ mol \ CH_4}\)

Flip the ratio. It is still the same value, but the units of molecules of methane cancel.

\(3.571 \times 10^ {27} \ molecules \ CH_4 *\frac { 1 \ mol \ CH_4}{6.022 \times 10^{23} \ molecules \ CH_4}\)

\(3.571 \times 10^ {27} *\frac { 1 \ mol \ CH_4}{6.022 \times 10^{23} }\)

\(\frac {3.571 \times 10^ {27}}{6.022 \times 10^{23} } \ mol \ CH_4\)

\(5929.923613 \ mol \ CH_4\)

The original measurement of molecules of methane( 3.571 × 10²⁷ molecules) has 4 significant figures, so our answer must have the same. For the number we calculated, that is the ones place. The 9 in the tenth place tells us to round the 9 in the ones place up to a 0, then the 2 in the tens place up to a 3.

\(5930 \ mol \ CH_4\)

We must add a placeholder zero in the tenth place to reach 4 sig figs.

\(5930.0 \ mol \ CH_4\)

The adult cow produces approximately 5930.0 moles of methane in a year.

Option A Nucleic Acids are a type of DNA is correct for  Biomolecules play a crucial role in the synthesis of DNA and RNA.

The genetic code of an organism—the order of nucleotides that determines the amino acid sequence of proteins—is uniquely stored by nucleic acids, specifically DNA and RNA, which are essential to life on Earth. Carbohydrates, lipids, proteins, and nucleic acids are the four main classes of biological macromolecules. Each is a vital part of the cell and carries out a variety of tasks. These molecules make up most of a cell's mass when they are all combined.

Any of the numerous substances produced by cells and living things is referred to as a biomolecule, also known as a biological molecule. Biomolecules come in a wide variety of shapes and sizes and serve a wide range of purposes. Proteins, lipids, nucleic acids, and carbohydrates are the four main categories of biomolecules.

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N - 7 - 1s2 2s2 2p3

O - 16 - 1s2 2s2 2p6 3s2 3p4

Mn - 25 - 1s2 2s2 2p6 3s2 3p6 4s2 3d5

Ga - 31 - 1s2 2s2 2p6 3s2 3p6 4s2 3d10 4p1

When glucose molecules are added to chains of glycogen for storage, the process is known as glycogenesis.

The liver and the Cori cycle's resting phases both trigger this process, and insulin's response to high blood glucose levels also triggers it. Blood glucose levels increase after eating because glucose enters the liver. The liver uses glycogenesis to deal with this extra glucose by converting it to glycogen for storage. Glycolysis is the process by which the glucose that is not stored is converted into energy. Each cell in the body experiences this. The first step in the multi-step process of glycogenesis, also known as glycogen synthesis, is the conversion of glucose to glucose-6-phosphate by hexokinase or the liver isoform of hexokinase, known as glucokinase.

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Answer:

An addition reaction occurs when two or more reactants combine to form a single product.

Addition reactions occur with unsaturated compounds.

The general equation for an addition reaction: A+BA+B →→ C

Hydrohalogenation involves the addition of a hydrogen atom and a halogen atom to an unsaturated compound (containing a carbon-carbon double bond).

A polymer is made up of lots of smaller units called monomers. When these monomers are added together, they form a polymer. One way for polymerization to occur is through an addition reaction. Example: The polymerization of vinyl chloride monomers to form a polyvinyl chloride polymer.

Halogenation is very similar to hydrohalogenation but a diatomic halogen molecule is added across the double bond.

Hydrogenation involves adding hydrogen to an alkene. During hydrogenation the double bond is broken (as with hydrohalogenation and halogenation) and more hydrogen atoms are added to the molecule

The two emissions required for oxygen-17 to become nitrogen-13 are a positron emission and a neutrino emission.

A neutrino is a subatomic particle that is similar to an electron in many ways but differs in that it lacks an electrical charge and has a very small mass that might potentially be zero.

Positron is a particle with the same mass as an electron but has a positive charge.

The transformation of oxygen-17 to nitrogen-13 requires the emission of two particles: a positron (also called a positive beta particle) and a neutrino.

The first emission is the positron, which is a particle with the same mass as an electron but with a positive charge. During the emission, a proton in the oxygen-17 nucleus converts into a neutron, and the positron and a neutrino are produced. The positron quickly annihilates with an electron, releasing two gamma rays.

The second emission is the neutrino, which is a subatomic particle with a very small mass and no electrical charge. The neutrino is emitted during the decay of the nitrogen-13 nucleus as it transitions to its ground state.

Therefore, the two emissions required for oxygen-17 to become nitrogen-13 are a positron emission and a neutrino emission.

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Acetic acid upon dissociation in water gives acetate ion and hydrogen ion as written in the chemical equation:

\(\rm CH_{3}COOH \rightarrow CH_{3}COO^{-} + H^{+}\).

Acetic acid is weak carboxylic acid. It is the simplest organic acid other than formic acid HCOOH. Acetic acid contains one methyl unit and the carboxyl group COOH.

Diluted acetic acid is used as vinegar to preserve food items such as pickle, salads etc. It gives a sore taste to the food also. Acetic acid is soluble in water and will dissociates into carboxylate ion and hydrogen ion.

Even though acetic acid easily loses a proton the carboxylate ion CH3COO- is not stable and it is a weak base the reverse of the reaction dominates in equilibrium.However in the presence of strong acids it can acts as a weak base also.

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When the reaction of  Grignard reagent reacted with methanol will yield a tertiary alcohol. Therefore, Option C tertiary alcohol is correct.

Contains a carbon-metal link, Grignard reagents are chemicals used in catalysis. They generally result from the anhydrous reaction of magnesium metal with an alkyl or aryl halide. Because of their high reactivity, Grignard reagents frequently act as nucleophiles in organic reactions.

An alkyl group from a Grignard reagent binds to the oxygen atom of methanol (CH3OH) when it interacts with the methanol, breaking the carbon-metal connection. A precursor alkoxide is created as a result. The equivalent alcohol is then produced by protonating the intermediate alkoxide.

The reaction of a Grignard reagent with methanol leads to the formation of a tertiary alcohol.

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The periodic table is an ordered way of representing chemical elements. They were ordered according to their atomic number, remember that the atomic number corresponds to the number of protons of the elements.

So the answer will be option C) Atomic Number