Answer: 0.00098
Explanation:
1. Zeroes that appear before a nonzero significant figure are not significant.
Ex: 0.002 (1 significant figures), 0.13 (2 significant figures)
2. Zeroes that appear between nonzero digits are significant
Ex: 0.705 (3 significant figures), 2006 (4 significant figures)
3. Zeroes that appear after a nonzero digit are significant only if it is
A. Followed by a decimal point
Ex: 40 (1 significant figure), 20. (2 significant figures)
or B. They appear to the right of a decimal point
Ex: 37.0 (3 significant figures), 4.100 (4 significant figures)
Boyle's Law states that when a sample of gas is compressed at a constant temperature, the pressure P and volume V satisfy the equation PV = C, where C is a constant. Suppose that at a certain instant the volume is 100 cm3, the pressure is 150 kPa, and the pressure is increasing at a rate of 30 kPa/min. At what rate is the volume decreasing at this instant?
Answer:
The volume is decreasing at a rate of 30 cm³/min.
Explanation:
From the question given above, pressure (P) and volume (V) are related by the following equation
PV = C
C => constant
If we make P the subject of the above, we shall have:
P = C/V
From the equation above (i.e P = C/V),
We can say that P is inversely proportional to V. This implies that as P is increasing, V will be decreasing and also, as P is decreasing, V will be increasing.
Considering the question given above, the pressure (P) is increasing at a rate of 30 kPa/min. Therefore, the volume will be decreasing at a rate of 30 cm³/min.
In the balanced equation-aPb(NO3)2(s)heatb PbO(s)+ c NO2(g)+ dO2(g); the values of a,b,c, d are respectively
Answer:
The balance reaction is
2Pb(NO3)2 ----》4NO2+2PbO+O2
hence the value of a,b,c,d are 2,4,2,1 respectively!
When solid Fe metal is put into an aqueous solution of SnSO4, solid Sn metal and a solution of FeSO4 result. Write the net ionic equation for the reaction.
Answer:Fe(s) + Sn^2+(aq) ----> Fe^2+(aq) + Sn(s)
Explanation:
The net ionic equation involved is;
Fe(s) + Sn^2+(aq) ----> Fe^2+(aq) + Sn(s)
We must recall that iron is above tin in the electrochemical series. The implication of this is that, iron has a more negative reduction potential compared to tin.
A metal can displace metals below it in the electrochemical series from their aqeous solution. Hence, iron displaces tin from it's solution.
0.487 grams of quinine (molar mass = 324 g/mol) is combusted and found to produce
1.321 g CO2, 0.325 g H2O and 0.0421 g nitrogen. Determine the empirical and molecular
formulas.
The empirical and molecular formulas of the quinine would be C40H48N and C23H27N respectively.
Empirical and molecular formulasTo determine the empirical formula, we need to find the mole ratios of each element in the compound.
First, let's calculate the number of moles of each product:
moles of CO2 = 1.321 g / 44.01 g/mol = 0.0300 molmoles of H2O = 0.325 g / 18.015 g/mol = 0.0180 molmoles of N2 = 0.0421 g / 28.01 g/mol = 0.00150 molNext, let's find the number of moles of each element:
moles of C = moles of CO2 = 0.0300 molmoles of H = 2 x moles of H2O = 0.0360 molmoles of N = 0.5 x moles of N2 = 0.00075 molNow, we can find the empirical formula by dividing each mole value by the smallest mole value:
C: 0.0300 mol / 0.00075 mol = 40H: 0.0360 mol / 0.00075 mol = 48N: 0.00075 mol / 0.00075 mol = 1The empirical formula is C40H48N.
To find the molecular formula, we need to determine the molecular mass of the compound. The empirical formula mass is:
Empirical formula mass = (40 x 12.01 g/mol) + (48 x 1.01 g/mol) + (1 x 14.01 g/mol) = 549.88 g/mol
Molecular formula factor = 324 g/mol / 549.88 g/mol = 0.5899
Molecular formula = 0.5899 x (C40H48N) = C23H27N
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Describe the relationship between the state of matter of water (gas, liquid, solid) and the motion of the water molecules
Water has three states of matter namely gas, solid or ice form and liquid. Molecules in solid state are not able to move since they are tightly packed.
Molecules can move in liquid state and they moves easily in gaseous state.
What is states of matter?Every substance have three states, that are gas, liquid and solid. In solid state, molecules are tightly packed and are unable to move apart. In liquid state, molecules have some space to move and motion of liquid is easy.
The movement of molecules in a substance depends on the space allotted for them or called the volume. More volume between molecules, easy to move apart.
Gaseous state is composed of molecules located far apart from each other and they diffuse easily. Therefore, motion in three states of water is different and moves faster in gaseous state.
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A rigid, 26-L steam cooker is arranged with a pressure relief valve set to release vapor and maintain the pressure once the pressure inside the cooker reaches 150 kPa. Initially, this cooker is filled with water at 175 kPa with a quality of 10 percent. Heat is now added until the quality inside the cooker is 40 percent. Determine the exergy.
The minimum entropy change of the heat-supplying source is -0.87 kJ/K.
Initial entropy of the systemIn this case, given the initial conditions, we first use the 10-% quality to compute the initial entropy.
at initial pressure of 175 kPaS₁ = 1.485 + (0.1)(5.6865) = 2.0537 kJ/kg K
Final entropyThe entropy at the final state given the new 40-% quality:
pressure inside the cooker = 150 kPaS₂ = 1.4337 + (0.4)(5.7894) = 3.7495 kJ/kg K
Mass of the steam at specific volumem₁ = 0.026/(0.001057 + 0.1 x 1.002643) = 0.257 kg
m₂ = 0.026/(0.001053 + 0.4 x 1.158347) = 0.056 kg
minimum entropy change of the heat-supplying sourceΔS + S₁ - S₂ + S₂m₂ - S₁m₁ - sfg(m₂ - m₁) > 0
ΔS + 2.0537 - 3.7495 + (3.7495 x 0.056) - (2.0537 x 0.257) - 5.6865( 0.056 - 0.257) > 0
ΔS > -0.87 kJ/K
Thus, the minimum entropy change of the heat-supplying source is -0.87 kJ/K.
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Which statement is true about the effect of human activity on atmospheric carbon dioxide?
Responses
Human activity has converted carbon dioxide in the atmosphere to other compounds.
Human activity has added carbon dioxide to the atmosphere.
Human activity consumes carbon dioxide in the atmosphere.
Human activity has disrupted the carbon cycle by preventing it from reaching the atmosphere.
The statement that is true about the effect of human activity on atmospheric carbon dioxide is Human activity has added carbon dioxide to the atmosphere.
Human activities, such as burning fossil fuels (coal, oil, and natural gas) for energy, deforestation, and industrial processes, have significantly increased the concentration of carbon dioxide in the Earth's atmosphere.
These activities release carbon dioxide that was previously stored in long-term reservoirs, such as fossil fuels and forests, into the atmosphere. This additional carbon dioxide contributes to the greenhouse effect and is a major driver of anthropogenic climate change.
The other statements mentioned are not accurate:
Human activity does not convert carbon dioxide in the atmosphere to other compounds on a large scale. There may be certain localized processes or technologies that aim to capture and convert carbon dioxide, but they are not widespread enough to significantly impact the overall levels of atmospheric carbon dioxide.
Human activity does not consume carbon dioxide in the atmosphere. In fact, human activities release carbon dioxide into the atmosphere through various processes, as mentioned above.
Human activity does not disrupt the carbon cycle by preventing it from reaching the atmosphere. The carbon cycle involves the movement of carbon between the atmosphere, oceans, land, and living organisms.
While human activities can impact the carbon cycle through land-use changes and deforestation, the overall effect is an increase in atmospheric carbon dioxide levels rather than preventing carbon dioxide from reaching the atmosphere.
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Look at Periodic Table. Which
element has 7 valence
electrons and is in period 3?
A. Fluorine
B. Sulfur
C. Chlorine
D. Bromine
why is a copper roof turning green a chemical change?
Answer:
Copper will start to react with the oxygen in the air to form copper oxide. The copper oxide will continue reacting to oxygen over time. As the copper oxide continues to react with carbon dioxide and water in the air it coats the surface with that iconic blue-green patina colour
Stephan’s mother cuts a twig from a rose bush and plants it in the soil. After a few days, Stephan observes a new plant growing. Which characteristic does the growth of the new plant depict?
The growth of the new plant depicts the asexual reproduction characteristic. The characteristic that describes the growth of the new plant in Stephan's mother cutting a twig from a rose bush and planting it in the soil is asexual reproduction.
Asexual reproduction is the mode of reproduction by which organisms generate offspring that are identical to the parent's without the fusion of gametes. Asexual reproduction is a type of reproduction in which the offspring is produced from a single parent.
The offspring created are clones of the parent plant, meaning they are identical to the parent.The new plant in Stephan’s mother cutting a twig from a rose bush and planting it in the soil depicts the process of asexual reproduction, which is the ability of a plant to reproduce without seeds. In asexual reproduction, plants can reproduce vegetatively by cloning themselves using their roots, bulbs, or stems.
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A solution of aluminum chloride has a pH of (4.5x10^0). What is the [H3O*(aq)], in mol/L?
Note: Your answer is assumed to be reduced to the highest power possible.
The concentration of H3O+ ions in the solution of aluminum chloride is \(3.16×10^-5\) mol/L.
Aluminum chloride is an acidic salt that contains a cation, Al3+, and an anion, Cl-. When aluminum chloride is dissolved in water, it dissociates into its constituent ions, and the Al3+ cations hydrolyze to produce H+ ions.
This reaction leads to the formation of an acidic solution. The pH of a solution of aluminum chloride is \(4.5×10^0\). We need to determine the concentration of H3O+ ions in this solution.
The concentration of H3O+ ions in a solution is given by the equation: pH = -log[H3O+] where pH is the negative logarithm of the concentration of H3O+ ions in the solution. The negative sign indicates that the pH is inversely proportional to the concentration of H3O+ ions. To determine the concentration of H3O+ ions, we need to rearrange the equation:
[H3O+] = \(10^-pH\) Substituting the value of pH =\(4.5×10^0\), we get: [H3O+] = \(10^-4.5\)
The value of \(10^-4.5\) can be calculated using scientific notation: \(10^-4.5\)= \(3.16×10^-5\) mol/L
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Calculate the volume occupied by the oxygen gas at a pressure of 210 kPa and temperature of 50°C. Use your answer from question 27 to help you solve this problem. Report your answer in liters with 3 significant figures._______L
Answer:
holaholaholaholaholaholaholahola
The volume occupied by the oxygen gas at a pressure of 210 kPa and a temperature of 50°C is 0.126 liters, rounded to three significant figures.
To calculate the volume occupied by the oxygen gas at a pressure of 210 kPa and a temperature of 50°C, we can use the ideal gas law equation:
PV = nRT
where:
P = pressure
V = volume
n = number of moles
R = ideal gas constant
T = temperature
First, we need to convert the given temperature from Celsius to Kelvin by adding 273.15:
T = 50°C + 273.15 = 323.15 K
Next, we rearrange the ideal gas law equation to solve for volume:
V = (nRT) / P
To find the number of moles (n), we can use the answer from question 27, which is the mass of oxygen gas:
m = 32 g
Using the molar mass of oxygen (O₂) which is approximately 32 g/mol, we can calculate the number of moles:
n = m / M = 32 g / 32 g/mol = 1 mol
Now we have all the values needed to calculate the volume:
V = (1 mol * 8.314 J/(mol*K) * 323.15 K) / 210,000 Pa
Using the ideal gas constant (R) of 8.314 J/(mol*K) and the pressure of 210 kPa (which is equivalent to 210,000 Pa), we can substitute these values into the equation and solve for volume.
V = 0.126 liters.
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Explain how a rainbow is produced
A rainbow is produced through a proces that includes refraction, reflection, and dispersion of sunlight.
What more should you know about the production of rainbows?A rainbow is formed when sulinght is refracted and reflected by rain drops in the atmospher.
The sunlight is split into its component colors, which is why rainbows appear as having an array of colors. This is due to each color being bent by a different amount during refraction.
The colors of a rainbow are always in the same order, with red on the outside and violet on the inside.
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2. Show the calculation supporting the claim that atmospheric pressure near sea level corresponds to the pressure exerted by a column of mercury that is about 760 mm high. Considering the density of mercury = 13.6 g/cm³.
The pressure exerted by a column of mercury that is about 760 mm high corresponds to approximately 0.987 atm.
To calculate the pressure exerted by a column of mercury, we can use the formula:
Pressure = density * gravity * height
Given:
Density of mercury = 13.6 g/cm³
Height of the mercury column = 760 mm = 76 cm
Acceleration due to gravity = 9.8 m/s²
First, we need to convert the height of the mercury column from centimeters to meters:
Height = 76 cm * (1 m / 100 cm) = 0.76 m
Now, we can calculate the pressure:
Pressure = 13.6 g/cm³ * 9.8 m/s² * 0.76 m
To ensure consistent units, we need to convert the density from grams per cubic centimeter (g/cm³) to kilograms per cubic meter (kg/m³):
Density = 13.6 g/cm³ * (1 kg / 1000 g) * (1 cm³ / (1e-6 m³))
Density = 13600 kg/m³
Plugging in the values into the pressure formula:
Pressure = 13600 kg/m³ * 9.8 m/s² * 0.76 m
Pressure = 99992.8 Pa
We can express the pressure in terms of atmospheric pressure:
1 atm = 101325 Pa (approximately)
To compare the pressure with atmospheric pressure, we can convert 99992.8 Pa to atm:
Pressure in atm = 99992.8 Pa / 101325 Pa/atm
Pressure in atm ≈ 0.987 atm
The pressure exerted by a column of mercury that is about 760 mm high corresponds to approximately 0.987 atm. Since atmospheric pressure near sea level is approximately 1 atm, this calculation supports the claim that atmospheric pressure near sea level is equivalent to the pressure exerted by a column of mercury about 760 mm high.
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Which statement describes a shortcoming of Rutherford’s model of the atom?A.
It incorrectly placed most of the atom’s mass in the nucleus.
B.
It did not explain how electrons behaved and why they don’t collide with the nucleus.
C.
It did not account for the fact that atoms have equal numbers of protons and electrons.
A shortcoming of Rutherford’s model of the atom is it did not account for the fact that atoms have equal numbers of protons and electrons. Therefore, option C is correct.
What is rutherford's model ?Ernest Rutherford, a scientist who was born in New Zealand, developed the Rutherford model to explain an atom. Rutherford oversaw the Geiger-Marsden experiment, which, after Rutherford's analysis in 1911, indicated that J. J. Thomson's plum pudding model of the atom was flawed, in 1909.
The first person to recognize an atom's nucleus was Rutherford. He attacked gold with -particles and discovered that there was positively charged material inside the atom as a result.
It did not explain the distribution of the atom's negatively charged electrons around its positively charged nucleus.
Thus, option C is correct.
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how does the position of an electron relates to its energy
The position and energy of an electron are intricately linked in the quantum realm.
The position of an electron is related to its energy through the principles of quantum mechanics. According to the Bohr model, electrons occupy specific energy levels or orbitals around the nucleus of an atom. These energy levels are quantized, meaning they can only have specific values. Electrons with lower energy are found closer to the nucleus in lower energy levels, while those with higher energy occupy outer energy levels. The energy of an electron is directly proportional to its distance from the nucleus. As the electron transitions between energy levels, it either absorbs or emits energy in discrete quantities known as photons. The energy of an electron can also be influenced by external factors such as electric and magnetic fields.
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What is the maximum number of electrons that can be identified with each of following sets of quantum numbers? If there are none, enter 0.
Answer:
So, only one electron is there with n = 0, l = 0 and its quantum set is n = 0, l = 0, ml = 0, ms = -1/2. Hope, this is helping. The maximum number of electrons that can fit inside a 'n' shell is 2n^2. So it would be 1.
Explanation:
Quantum numbers are defined as the set of four numbers with the help of which we can get complete information about the electrons in an atom. Here the term 'n' represents the principal quantum number.
What is principal quantum number?The quantum number which represents the main energy level or shell in which electrons are present. It also determines the average distance of orbital or electron from the nucleus. It can have the whole number values like 1,2,3,4, ....
1. When n = 2, the maximum number of electrons present is 8. That is one 's' sub level and three 'p' sub levels. The spin of four electrons will be +1/2 and other four will be -1/2.
2. When l = 3, the possible orientations = 2l + 1 = 2(3) + 1 = 7. So the maximum number of electrons is 14.
3. The value of ml = -1 indicates only one orbital. So the maximum electrons is 2.
4. Here ml = -1, 0, 1 which shows three orbitals. So in ml = -1, there are only two electrons.
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how do one get this solution
-log10 (2* 10^-2)
The result of the computation when you follow the steps is 1.699.
A logarithm is a mathematical function that represents the exponent or power to which a specific base must be raised to obtain a given number. In simpler terms, it answers the question: "To what power must we raise a base number to obtain a certain value?"
What you should do is that on your calculator, you could press the logarithm key and then put in the value that has been shown and then the result would be displayed on your calculator.
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Thermal energy has an impact on chemical reactions because
Group of answer choices
It makes molecules melt so they can mix together like a liquid
It increases the number of collisions between reactants
It makes atoms and molecules in the reactants more sticky
It brings reactants closer together so they are sitting side by side
Answer:
The correct answer is "It increases the number of collisions between reactants".
Explanation:
In chemistry, activation energy is defined as the amount of energy needed for compounds to perform a chemical reaction. Thermal energy decreases activation energy, which results on higher reaction rates. This is explained by the increase of entropy that results by increasing the thermal energy, which increases the number of collisions between reactants. Compounds and particles only react when they collide, if the particles are heated they move faster and collide more frequently.
fill in the blank! (for 15 pts)
In order:
alkali
reactive
shiny
electricity
soft
low
good luck!
Assume that the temperature is held constant and determine the pressure, in mmHg , if the volume is changed to 334 mL . Express your answer to three significant figures.
The new pressure of the gas when the volume is changed is 4.365 atm.
What is the new pressure of the gas whose volume is changed at constant temperature?The pressure and volume of a given mass of gas at constant temperature are inversely related.
This relationship is given by the equation of Boyle's law given below:
P₁V₁ = P₂V₂
where;
P₁ is the initial pressureV₁ is the initial volumeP₂ is the final pressureV₂ is the final volumeSolving for the final pressure, P₂
P₂ = P₁V₁ /V₂
P₂ = 1.445 * 1000 / 334
P₂ = 4.365 atm
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Complete question:
A gas has an initial pressure of 1.445 atm and an initial volume of 1009 mL. Assume that the temperature is held constant and determine the pressure, in mmHg, if the volume is changed to 334 mL. Express your answer to three significant figures.
Draw a skeletal structure and name the groups A) CH3CH2CH2CO2H B)CH3NH2. C)CH3CH2CH2CHO(aldehyde) pls
Hope this helps you a lot...
__ N2 + __ H2 → __ NH3
A. How many moles of ammonia (NH3) can be produced if 0.75 moles of N2 are reacted with enough hydrogen gas?
B. Extension Problem: How many moles of H2 gas are needed to react with 56.0 g of N2? Hint: Remember you can only apply the mole ratio on moles, not grams, but what can you do with grams first?
A total of 1.5 moles of ammonia (NH₃) could be produced.
To react with 56.0 g of N₂, 6.000 moles of H₂ gas are required.
A. We need to balance the chemical equation first:
N₂ + 3H₂ → 2NH₃
From the balanced equation, we can see that 1 mole of N₂ reacts with 3 moles of H₂ to produce 2 moles of NH₃.
Therefore, if 0.75 moles of N₂ are reacted with enough hydrogen gas, we can calculate the moles of NH₃ produced using the mole ratio:
0.75 moles N₂ × (2 moles NH₃ / 1 mole N₂) = 1.5 moles NH₃
Therefore, 1.5 moles of NH₃ can be produced.
B. We can use the molar mass of N₂ to convert 56.0 g of N₂ to moles:
56.0 g N₂ × (1 mole N₂ / 28.02 g) = 2.000 mole N₂
From the balanced equation, we know that 1 mole of N₂ reacts with 3 moles of H₂ to produce 2 moles of NH₃.
Therefore, the moles of H₂ required can be calculated using the mole ratio:
2.000 mole N₂ × (3 mole H₂ / 1 mole N₂) = 6.000 mole H₂
Therefore, 6.000 moles of H₂ are needed to react with 56.0 g of N₂.
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Figure1 of 1
A diagram shows that over a distance of 1.6 times 10 to negative 7 meters, wave A completes 4 and a half cycles and wave B completes two cycles.
Part A
What is the wavelength of wave A?
Express your answer using two significant figures.
λ =_________m
Part B
What is the wavelength of wave B?
λ =_________m
Wavelength is a physical quantity that measures the distance between two consecutive points in a wave that are in phase, or have the same displacement and direction of motion.
What is Wavelength?
The distance separating two wave peaks or troughs is known as the wavelength. It is typically denoted by the Greek letter lambda (λ) and is measured in units of length, such as meters (m) or nanometers (nm).
Part A:
To find the wavelength of wave A, we can use the equation:
wavelength = distance / number of cycles
Plugging in the given values, we get:
wavelength = (1.6 x 10⁻⁷m) / 4.5 cycles
wavelength = 3.56 x 10⁻⁸ m
Rounding to two significant figures, we get:
wavelength = 3.6 x 10⁻⁸ m
Part B:
To find the wavelength of wave B, we can use the same equation:
wavelength = distance / number of cycles
Plugging in the given values, we get:
wavelength = (1.6 x 10⁻⁷ m) / 2 cycles
wavelength =\(8.0 \times 10^{-8 }m\)
Rounding to two significant figures, we get:
wavelength = 8.0 x 10⁻⁸ m
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What is the limiting reagent when 9.517 g of Fe is allowed to react with 19.34 g of water according to
the reaction given below? Base your calculations on the yield of Fe2O3. How much of the excess reagent was used and left over. The actual yield of iron(III) oxide was 1.474 g. What is the percent yield?
2 Fe + 3 H20 -› Fe203 + 3 H2
Answer:
The percent yield = 11.04
Explanation:
the relative formula masses (Mr) are: CaCo3 = 100; CaO =56 ; Co2=44
describe how this experiment could be used to provide evidence for the law of conservation of mass.
[6 marks]
include your answer:
-method
-which measurements should eb taken
-how the student could show evidence for the conservation for mass
The law of conservation of mass states that in a chemical reaction, the total mass of the reactants is equal to the total mass of the products. To provide evidence for this law, we can perform an experiment in which calcium carbonate (\(CaCO_3\)) is decomposed to produce calcium oxide (CaO) and carbon dioxide (\(CO_2\) ), and then measure the masses of the reactants and products.
Method:
Weigh a sample of \(CaCO_3\) using a balance.
Heat the \(CaCO_3\) in a crucible until it decomposes to CaO and \(CO_2\). The \(CO_2\) gas will escape, leaving only CaO in the crucible.
Allow the crucible to cool and then weigh it again to determine the mass of the CaO produced.
Collect the \(CO_2\) gas that is released during the reaction in a gas syringe or other collection device. Measure the volume of \(CO_2\) gas produced, and calculate its mass using its molecular weight.
Which measurements should be taken:
The following measurements should be taken:
The mass of the \(CaCO_3\) used as a reactant.
The mass of the CaO produced as a product.
The volume of \(CO_2\) gas produced during the reaction.
The temperature and pressure of the \(CO_2\) gas to allow for the calculation of its mass.
How the student could show evidence for the conservation of mass:
To show evidence for the law of conservation of mass, the student can compare the mass of the \(CaCO_3\) used as a reactant to the total mass of the products, which includes the mass of CaO produced and the mass of \(CO_2\) gas released.
The sum of the masses of CaO and \(CO_2\) should be equal to the mass of the \(CaCO_3\) used as a reactant, within experimental error. This will provide evidence that the mass of the reactants is conserved and equals the mass of the products, as required by the law of conservation of mass.
Additionally, the student could calculate the theoretical yield of CaO and CO2 based on the balanced equation for the reaction, and compare this to the actual yield obtained from the experiment. Any difference between the theoretical and actual yields could be due to experimental error, but the comparison can still provide additional evidence for the conservation of mass.
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Bio fuel is a mixture of petrol and 20%——————
Answer:
methane and petrol okkkkkkkkkkkkkkkkkkk
Work shown would be appreciated ❤️
20 points!!!!
Answer:
35.453 amu.
Explanation:
From the question given above, the following data were obtained:
Isotope A (Cl–35):
Abundance (A%) = 75.77%
Mass of A = 34.969 amu
Isotope B (Cl–37):
Abundance (B%) = 24.23%
Mass of B = 36.966 amu
AVERAGE atomic mass of Cl =?
The average atomic mass of Cl can be obtained as follow:
Average = [(Mass of A × A%)/100] + [(Mass of B × B%)/100]
Average = [(34.969 × 75.77)/100] + [(36.966 × 24.23)/100]
Average = 26.496 + 8.957
Average atomic mass of Cl = 35.453 amu.
Which of the following items are made from renewable resources? Select the two correct answers. (1 point)
Responses
plastic fork
plastic fork
metal can
metal can
leather jacket
leather jacket
electronics
electronics
printer paper
A leather jacket and printer paper are examples of items that can be made from renewable resources, while plastic forks, metal cans, and electronics are not considered renewable due to their reliance on non-renewable materials and processes. Option C, E
The two correct answers that are made from renewable resources are:
C) Leather jacket: Leather is derived from animal hides, which are a byproduct of the meat industry. As long as there is a sustainable and responsible approach to animal farming, the production of leather can be considered renewable. The hides are obtained from animals that are raised for meat consumption, and their use in leather production helps reduce waste.
E) Printer paper: Printer paper can be made from various sources, including trees, bamboo, and recycled paper fibers. If the paper is sourced from sustainably managed forests or from fast-growing plants like bamboo, it can be considered renewable. Additionally, the use of recycled paper fibers reduces the demand for materials and promotes a more circular economy.
The other options, A) plastic fork, B) metal can, and D) electronics, are not made from renewable resources:
A) Plastic fork: Plastics are typically derived from fossil fuels, which are non-renewable resources. The production of plastic involves the extraction and processing of petroleum or natural gas, both of which are finite resources.
B) Metal can: Metal cans are predominantly made from aluminum or steel. While these metals can be recycled, their initial production requires the extraction of raw materials from the Earth, which is not a renewable process.
D) Electronics: Electronics are made from a wide range of materials, including metals, plastics, and various chemical compounds. The production of electronics involves the extraction of raw materials, many of which are non-renewable resources.
Option C and E.
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61. Given the following information:
Ag2 CrO4(s)=2Agt (aq) + CrO4²- (aq)
Ag+ (aq) + e- Ag(s)
find the standard reduction potential at 25°C for the half-reaction
Ksp = 1 × 10-12
E = +0.799 V
Ag2 CrO4(s) + 2e¯ 2Ag(s) + CrO4²- (aq)
Q = Ksp = 1 × 10^(-12).
Substituting the values into the Nernst equation, we have:
0.799 V = E° - (RT/2F) * ln(1 × 10^(-12))
Now, solving for E°:
E° = 0.799 V + (RT/2F) * ln(1 × 10^(-12))
The value of R is the ideal gas constant, T is the temperature in Kelvin, and F is the Faraday constant.
To find the standard reduction potential at 25°C for the half-reaction Ag2CrO4(s) + 2e¯ → 2Ag(s) + CrO4²-(aq), we can use the Nernst equation, which relates the standard reduction potential (E°) to the equilibrium constant (K) and the reaction quotient (Q).
The Nernst equation is given as follows:
E = E° - (RT/nF) * ln(Q)
Given information:
Ksp = 1 × 10^(-12)
E = +0.799 V (standard reduction potential of Ag+ to Ag)
Since the reaction involves the dissolution of Ag2CrO4(s), the reaction quotient Q can be expressed as [Ag+]²/[CrO4²-].
Since the stoichiometry of the reaction is 2:1 for Ag2CrO4 to Ag+, we can say that [Ag+]² = Ksp.
Therefore, Q = Ksp = 1 × 10^(-12).
Substituting the values into the Nernst equation, we have:
0.799 V = E° - (RT/2F) * ln(1 × 10^(-12))
Now, solving for E°:
E° = 0.799 V + (RT/2F) * ln(1 × 10^(-12))
The value of R is the ideal gas constant, T is the temperature in Kelvin, and F is the Faraday constant.
Please note that without specific values for temperature (T) and the ideal gas constant (R), the exact standard reduction potential at 25°C cannot be determined.
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