The table shows the proportional relationship between a hedgehog's
weight loss and the number of days of hibernation. How much weight does
the hedgehog lose during 120 days of hibernation?
Explain how you know that the relationship between the hedgehog's weight
loss and the number of days of hibernation is proportional.

The hedgehog’s total change in weight over 120 days is ____ ounces.


weight loss of hedgehog

days: change in weight:
12 -0.36
21 -0.63
71 -2.13
96 -2.88

Answer:

that's a bit too far away haha

Answer:

oof that sucks i live in cali

Step-by-step explanation:

Answer:

g(x)=0  when x= 2 or when x= 5

The graph of g intercepts the x-axis at x= 2 and x= 5

The zeros of g are 2 and 5

Step-by-step explanation:

y = -1/3x + 1

y = -2x - 3

We can compare the equations to the graphs and see which graph represents the intersection point of the two equations.

The first equation, y = -1/3x + 1, has a negative slope (-1/3) and a y-intercept of 1.

The second equation, y = -2x - 3, also has a negative slope (-2) and a y-intercept of -3.

Based on the slopes and y-intercepts, we can identify the correct graph by finding the point where the two lines intersect.

Unfortunately, since the graphs are not provided, I am unable to determine which specific graph shows the solution to the system of linear equations. I recommend referring to the graph representation of the equations and identifying the intersection point to determine the correct graph.

Largest to smallest: Crustaceans, Protozoa, Bacteria, and Viruses. The nitrification process can be understood as the biological oxidation process of ammonia to nitrate.

This process occurs in two stages. During the first stage, ammonia is converted into nitrite by Nitrosomonas bacteria. In the second stage, nitrite is oxidized to nitrate by Nitrobacter bacteria.The two-step process of nitrification can be shown by the following chemical reactions:
NH₃ + O₂ → NO₂ + H₂O
NO₂ + ½O₂ → NO₃
The Nitrosomonas bacteria and Nitrobacter bacteria are involved in the process of nitrification. c. The common sources of wastewater are domestic wastewater, industrial wastewater, and agricultural wastewater. The main objectives of wastewater treatment are:to remove harmful pollutants from wastewater to protect the environment, andto recover and recycle the valuable resources present in wastewater.
d. In a conventional wastewater treatment plant, there are three stages, which are primary treatment, secondary treatment, and tertiary treatment. The objectives of each stage are as follows:
1. Primary treatment: This stage removes large, heavy solids and floating debris from the wastewater. The objective of this stage is to reduce the amount of organic matter and suspended solids in the wastewater.
2. Secondary treatment: This stage removes dissolved and suspended organic matter from the wastewater using biological processes. The objective of this stage is to reduce the amount of organic matter, nitrogen, and phosphorus in the wastewater.
3. Tertiary treatment: This stage removes remaining suspended solids, dissolved solids, and nutrients from the wastewater. The objective of this stage is to produce effluent that can be safely discharged into the environment.
The differences (advantages/disadvantages) of each stage are as follows:
1. Primary treatment: Advantages - simple and low cost; Disadvantages - does not remove all the organic matter and nutrients.
2. Secondary treatment: Advantages - more effective than primary treatment; Disadvantages - requires more space and energy than primary treatment.
3. Tertiary treatment: Advantages - produces high-quality effluent; Disadvantages - requires advanced treatment technologies and higher cost.
e. Suspended growth wastewater treatment process refers to the use of microorganisms suspended in the wastewater to treat it. The microorganisms convert organic matter into biomass and other compounds. An example of this process is the activated sludge process.The attached growth wastewater treatment process refers to the use of microorganisms attached to a surface to treat the wastewater. The microorganisms form a biofilm on the surface, which helps in the treatment process. An example of this process is the trickling filter process.
f. The three different methods used to measure the organic content of wastewater are:
1. Chemical Oxygen Demand (COD) - It measures the amount of oxygen required to oxidize organic matter in wastewater.
2. Biological Oxygen Demand (BOD) - It measures the amount of oxygen consumed by microorganisms in the process of decomposing organic matter in wastewater.
3. Total Organic Carbon (TOC) - It measures the amount of carbon present in the organic matter in wastewater.
g. The main objectives of sludge treatment are:
to reduce the volume of sludge, andto stabilize the sludge by reducing the pathogens, organic matter, and odors present in the sludge.

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Answer:

Simple interest is calculated by multiplying the principal amount (the initial deposit) by the interest rate and the number of years.

The formula for simple interest is:

I = P * r * t

Where:

I = Interest

P = Principal (initial deposit)

r = Interest rate (expressed as a decimal)

t = Time (in years)

In this case, the principal amount is $500.00, the interest rate is 4.5% (converted to 0.045), and the time is 15 years.

We can plug in the values into the formula:

I = $500.00 * 0.045 * 15 = $337.50

So, after 15 years with the same interest rate, Arisia’s account would earn $337.50 in interest.

The total amount of wire required for all the robots and the master remote is 2090 inches.

Margarite is building 3 prototypes of a robot she designed. Each robot includes a body and a remote control.

She needs 450 inches of wire for each body and 120 inches for each remote control.

In addition, she is going to build one master remote to run all three robots at once.

The master remote will require 380 inches of wire.

The total amount of wire required for each robot:

Body = 450 inches

Remote control = 120 inches

The amount of wire required for each robot (both body and remote control) is:

             450 + 120 = 570 inches

Therefore, the total amount of wire required for the three robots is:

             3 × 570 = 1710 inches

In addition, she requires 380 inches of wire for the master remote.

Hence, the total amount of wire required to build all the robots and the master remote is:

              1710 + 380 = 2090 inches

Margarite is building 3 prototypes of a robot she designed. Each robot requires 570 inches of wire and the total amount of wire required for all three robots is 1710 inches. She is also building one master remote that requires 380 inches of wire. The total amount of wire required for all the robots and the master remote is 2090 inches.

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a. When evaluating a model, we use R2 as a parameter for performance assessment.

b. If model A has a higher MAPE but model B has a higher R2, we choose the model with the higher R2 for better overall performance.

c. For accuracy measures, we typically use MAPE (Mean Absolute Percentage Error) due to its interpretability and ability to capture relative errors.

When evaluating a model's performance, it is crucial to choose the appropriate parameters to assess its accuracy and reliability. In the case of MAPE (Mean Absolute Percentage Error) and R2 (Coefficient of Determination), the choice between them depends on the specific evaluation goals.

The R2 parameter is commonly used for evaluating models because it measures the proportion of the dependent variable's variance that can be explained by the independent variables. R2 provides insights into how well the model fits the data and captures the relationship between the input features and the target variable. Therefore, R2 is a suitable parameter to use when evaluating a model.

When comparing two models, if model A has a higher MAPE but model B has a higher R2, it is advisable to choose the model with the higher R2 value. This is because R2 indicates the proportion of variance explained, suggesting that model B performs better in capturing the underlying patterns and predicting the target variable.

Although model A may have a lower relative error (MAPE), it is crucial to prioritize the model's ability to explain and predict the target variable accurately.

Among MAPE, MAD (Mean Absolute Deviation), and MSD (Mean Squared Deviation), MAPE is commonly preferred as a parameter for accuracy measures. MAPE calculates the average percentage difference between the predicted and actual values, making it interpretable and easily understandable.

It captures relative errors and enables comparisons across different scales and datasets. MAD and MSD, on the other hand, measure absolute and squared errors, respectively, but they do not account for the relative magnitude of the errors. Hence, MAPE is a more suitable parameter for accuracy measures.

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The inverse of the conditional statement is : if two lines do not intersect, then the lines are not coplanar.

Conditionals are commands used in programming languages to handle decisions.

The contrapositive statement is :  If two lines are not coplanar, then the lines do not intersect.

The converse statement is :  If two lines are coplanar, then the lines intersect.

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Answer:

It's C. 0.223

Step-by-step explanation:

1) Since the sum of interior angles yields 180º, no matter which type of triangle it is.

2) Then we can write

3x+12 +x +6x +8 = 180

10x +20 = 180º

10x = 180-20

10x = 160

x= 16

2.2 Let's find out the measurement of each angle

m∠ A= x Plug into that the value of x

m∠ A = 16º

m∠B= 3x+12 Plug into that the value of x

m∠B = 3(16) +12

m∠B = 48+12

m∠B =60

3) Then the answers are:

x = 16

m∠ A = 16º

m∠B =60

Answer:

46.80

Step-by-step explanation:

because 45/4%=1.80 and 45+1.80=46.80

The given differential equation is −y′′−3y′ 5y=sinh(at)

y(0)=1

y′=5.

We have to take the Laplace transform of each side of the differential equation and then transform the given differential equation into an algebraic equation.

To take the Laplace transform of the given differential equation, we use the following formulas:

Definition of the Laplace transform

\($\mathcal{L}\left\{f(t)\right\}\)

=\(F(s)\)

=\(\int_{0}^{\infty} e^{-st} f(t) d t$Property$\mathcal{L}\left\{f^{\prime}(t)\right\}\)

=\(s F(s)-f(0)$Property$\mathcal{L}\left\{f^{\prime \prime}(t)\right\}\)

=\(s^{2} F(s)-s f(0)-f^{\prime}(0)$\)

Applying the Laplace transform to the given differential equation, we have:

\($\mathcal{L}\left\{-y^{\prime \prime}(t)-3 y^{\prime}(t)+5 y(t)\right\}\)

=\(\mathcal{L}\left\{\sinh (a t)\right\}$\)

Now, using the above Laplace transform properties,

we have

\($$s^{2} Y(s)-s y(0)-y^{\prime}(0)-3\left[s Y(s)-y(0)\right]+5 Y(s)\)

=\(\frac{a}{s^{2}-a^{2}}$$where $Y(s)\)

=\(\mathcal{L}\left\{y(t)\right\}$\)  is the Laplace transform of\($y(t)$\).

Now, substituting

\($y(0)\)

=1$ and \($y^{\prime}(0)\)

=5$,

we get

\($$s^{2} Y(s)-s-5 s-3 s Y(s)+3+5 Y(s)\)

=\(\frac{a}{s^{2}-a^{2}}$$$$\left(s^{2}-3 s+5\right) Y(s)\)

=\(\frac{a}{s^{2}-a^{2}}+s+5$$$$Y(s)\)

=\(\frac{a}{\left(s^{2}-a^{2}\right)\left(s^{2}-3 s+5\right)}+\frac{s+5}{\left(s^{2}-3 s+5\right)}$$\)

Therefore, the algebraic equation obtained by taking the Laplace transform of each side of the differential equation is

\($Y(s)\)

=\(\frac{a}{\left(s^{2}-a^{2}\right)\left(s^{2}-3 s+5\right)}+\frac{s+5}{\left(s^{2}-3 s+5\right)}$.\)

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Answer:

i think its a

Step-by-step explanation:

Answer: The cat is 4 years old, and the dog is 6 years old.

Step-by-step explanation:

We know that Buddy is 2 years old than Fluffy.

And 3 years ago, Buddy was 3 times older than Fluffy.

Let's define the variables:

B = age of Buddy

F = age of Fluffy.

The first statement can be written as:

B = F + 2

The second statement can be written as:

B - 3 = 3*(F - 3)

To solve this, we can replace the first equation into the second one, and solve that for F

B - 3 = 3*(F - 3)

(F + 2) - 3 = 3*F - 9

F - 1 = 3*F - 9

-1 + 9 = 3*F - F

8 = 2*F

8/2 = 4 = F

Fluffy is 4 years old, and with the first equation we can find the age of Buddy.

B = F + 2 = 4 + 2 = 6

Buddy is 6 years old

The required age of the dog buddy is 6 years old and the age of cat fluffy is 4 years old.

Given ,

James's dog buddy is 2 years older than Fluffy,

And the neighbor's cat Three Years ago, Buddy was three times older than fluffy.

Let ,

The age of buddy = B

The age of fluffy is = F

According to the question ,

Buddy, is 2 years older than Fluffy= Age of Buddy = Age of fluffy + 2 years older.

B = F +2

Again According to the question,

Three years ago age of Buddy = B - 3

Three years ago age of Fluffy = F - 3

Three years ago Buddy was three times older than fluffy = Three years ago age of Buddy = 3 × Three years ago Age of fluffy

B - 3 = 3 ( F - 3 )

Solving the equations,

B - 3 = 3 ( F - 3 )

Put the value of B from equation 1

F + 2 - 3 = 3 ( F -3 )

F - 1 = 3F - 9

F - 3F = - 9 +1

-2F = -8

2F = 8

\(F = \frac{8}{2}\)

F = 4

The age of fluffy is 4 years old.

Then ,

The age of buddy

B = F + 2

B = 4 + 2

B = 6

The age of buddy is 6 years old.

The required age of the dog buddy is 6 years old and the age of cat fluffy is 4 years old.

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the probability that the diameter of a elected bearing is greater than 85 millimeter P(diameter > 85) = P(z > (85-81)/4) = P(z > 1) = 0.1587

The diameter of ball bearings is normally distributed, with a mean of 81 millimeters and a variance of 16.

To calculate the probability that a selected bearing has a diameter greater than 85 millimeters, we first calculate the z-score for 85 millimeters.

We subtract 81 from 85 to get 4, and divide by 4 to get 1 for the z-score.

We the look up the probability for a value of 1 in the z-table, which is 0.1587.

This is the probability that a selected bearing has a diameter greater than 85 millimeters, rounded to four decimal places.

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At the 2.5% level, the maximum value at risk that Michael could experience is approximately $28,187.

The value at risk (VaR) at the 2.5% level can be calculated as follows:

\(VaR = - (364,888 * 0.025 * 0.0428 - \sqrt{(364,888 * 0.025 * 0.0963)}) = - $28,187\)

Where:

Therefore, at the 2.5% level, the maximum potential loss that Michael could experience is approximately $28,187.

In simpler terms, the VaR is a statistical measure that estimates the maximum potential loss of an investment with a certain level of confidence over a given time period. In this case, we use the historical returns of American Airlines to estimate the risk of Michael's investment. The VaR tells us that there is a 2.5% chance that Michael could lose at least $28,187 from his investment in American Airlines, assuming that the future returns follow a normal distribution with the same mean and variance as the historical returns.

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Answer:

$14.04

Step-by-step explanation:

-21.46 + 35.50 is the same as

35.50 - 21.46 = $14.04

Answer: 14.04

Step-by-step explanation: -21.46 + 35.50 = 14.04

The number of minutes it will take the marshal to catch up to the robber in discuss is; 210.

Let 30minutes = 0.5 hours.

Let x represent the time for which the marshal has ran.

On this note, the robber must have galloped at; (x +0.5) hours.

Hence, it follows from the task content that if they are at the same distance from the bank; we have;

14(x+0.5) = 16(x)

14x + 7 = 16x

7 = 2x

x = 7/2 = 3.5 hours.

= 3.5 × 60minutes = 210minutes.

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Answer: To find the mean hourly wage, you need to sum up the total wages of all employees and then divide by the number of employees. The total hourly wage for 25 phone operators is 25 * $22.85 = $571.25. The total hourly wage for 5 supervisors is 5 * $27.25 = $136.25. The combined total is $571.25 + $136.25 = $707.50. The mean hourly wage for the 30 employees is $707.50 / 30 = $23.58. So, the answer is approximately $23.58.

Step-by-step explanation:

Answer:

c

Step-by-step explana i think its right

Answer:

3 OR 8  hope this helps!

Step-by-step explanation:

Answer:

The total area codes that are currently available is 692.

Step-by-step explanation:

The area code is of the form: NXX.

The variable N can take values,

N = {2, 3, 4, 5, 7, 8 and 9}

The variable X can take values,

X = {0, 1, 2, 3, 4, 5, 7, 8 and 9}

Considering that repetitions are allowed.

The total possible number of area codes is:

T = 8 × 10 × 10 = 800

So, there are 800 possible area codes.

The exception codes are:

{37X, 96X, N9X and N11}

So, the number of reserved area codes is, 10 + 10 + 80 + 8 = 108.

Then the area codes that are currently available is, 800 - 108 = 692

Thus, the total area codes that are currently available is 692.

Answer:

\(\rm x = 2 , 2 \)

Step-by-step explanation:

A quadratic equation is given to us and we need to find the solution of the equation. The given equation is ,

\(\implies x^2 -4x + 4 = 0 \)

Now for finding the roots of the equation , let's use the quadratic formula , or by factorising out the equation . Here I would be using the factorization method , as ,

\(\implies x^2 -4x + 4 = 0\\\\\implies x^2-2x-2x+4 = 0 \\\\\implies x(x-2) -2(x-2) = 0 \\\\\implies (x-2)(x-2) = 0 \\\\\implies x = 2, 2 \)

Hence the Solution of the equation is 2,2.

Answer:

Step-by-step explanation:

x² - 4x  +4 = 0

Factorization method:

Sum = -4

Product = 4

Factor = (-2) ; (-2)    {-2 * -2 = 4  & (-2) + (-2) = -4}

x² -4x + 4 = 0

x² - 2x - 2x  + (-2)*(-2) = 0

x(x - 2) - 2 (x - 2) = 0

(x - 2) (x - 2) = 0

x - 2 = 0  or x -2 = 0

 x = 2      or x = 2

x = 2 , 2

Answer:

X=60

Step-by-step explanation:

Sum of the Quadrilateral interior angles:360

360-70-130-100=60

Answer:

44

Step-by-step explanation:

1/2bh, b=8, h=11

1/2*8*11

1/2*88

=44

The minimum hot-holding temperature for fried shrimp is d. 135 ° F 57 ° C. It is important to maintain this temperature to ensure that the food remains safe for consumption and to prevent the growth of harmful bacteria.

The minimum hot-holding temperature for fried shrimp is 135 °F (57 °C). When food is hot-held, it means it is kept at a specific temperature after cooking to maintain its quality and safety until it is served or consumed. This temperature is important because it helps prevent the growth of harmful bacteria, such as Salmonella and E. coli, that can cause food borne illnesses.

At a hot-holding temperature of 135 °F (57 °C) or higher, the heat inhibits the growth of bacteria, ensuring that the fried shrimp remains safe for consumption. This temperature range is considered a critical control point in food safety practices.

It's worth noting that the temperature of 135 °F (57 °C) is the minimum requirement for hot-holding fried shrimp. However, in practice, it's generally recommended to hold the shrimp at a slightly higher temperature to account for any temperature loss that may occur over time.

Some food establishments may set their hot-holding equipment to maintain a temperature of 140 °F (60 °C) or higher to ensure the safety and quality of the food.

By adhering to proper temperature control guidelines, including maintaining the minimum hot-holding temperature of 135 °F (57 °C), you can help prevent the risk of food borne illnesses and ensure that the fried shrimp remains safe and enjoyable to consume.

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The half-life of this substance is 828.37 days and it would take 1312.93 days for the sample to decay to one-third of its original amount.

Half-life is defined as the time it will took a substance to reduce to half of its initial amount. The half-life of a substance is determined with respect to the rate of the reaction. It can be calculated using the formula below.

N(t) = N₀(1/2)^(t/T)

where N(t) = amount of substance remaining after time t

N₀ = initial amount of substance

t = time

T = half-life

If a sample of a certain substance decayed to 77.8% of its original amount, then N(t) = 0.778N₀.

Hence,

N(t) = N₀(1/2)^(t/T)

0.778N₀ = N₀(1/2)^(300/T)

0.778 = (1/2)^(300/T)

T = 828.27 days

If the sample is to decay to one-third of its original amount, then N(t) = 1/3N₀.

Hence,

N(t) = N₀(1/2)^(t/T)

1/3N₀ = N₀(1/2)^(t/828.27)

1/3 = (1/2)^(t/828.27)

t = 1312.93 days

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The equation of the circle can be shown as, x² + y² = 9², or, x² + y² = 81.

The equation of a circle, with the center at the origin and the radius r units, is given as x² + y² = r².

In the question, we are asked to write the equation for a circle centered at the origin with x-intercepts of (-9, 0) and (9, 0).

We can find the radius of the circle using the distance formula,

D = √((x₂ - x₁)² + (y₂ - y₁)²), where (x₁, y₁) and (x₂, y₂) are the endpoints of a line segment.

Radius is the distance between the center and any point on the circle.

Thus, taking (x₁, y₁) as (0, 0), the origin, for the center, and (x₂, y₂) as (9, 0), for any point on the circle, we get the radius as:

r = √((9 - 0)² + (0 - 0)²),

or, r = √(9² + 0²),

or, r = √9² = 9.

Thus, the radius of the circle is r = 9 units.

Thus, the equation of the circle can be shown as, x² + y² = 9², or, x² + y² = 81.

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Answer:

14÷2=28

Step-by-step explanation: