Two batteries, A and B are connected in parallel, an 80 ohm resistor is connected across the battery terminals. The e.m.f and the internal resistance of battery A are 100 volts and 5 ohms respectively, and the corresponding values of battery B are 95 volts and 3 ohms respectively. Find the value and direction of the current on each battery and the terminal voltage. ​

Answer:

9000 J

Explanation:

Convert minutes to seconds.

2 min = 120 s

Power = energy / time

75 W = E / 120 s

E = 9000 J

Answer:

The answer is flint glass.

Answer:

The velocity is  \(v  = 796 \  m/s \)

Explanation:

From the question we are told that

   The mass of the bullet is  \(m_b  =  5.00\  g =  0.005 \ g\)

   The mass of the hand gun is  \(m_g  =  1.00 \ kg\)

    The speed of the gun is  \(v_b  =  8.00 * 10^{2} \  m/s\)

Generally from the law of momentum conservation

     \(m_b *  u_b  +  m_g *  u_g  =  m_b*  v_b +  m_g *  - v_g\)

here \(u_g\  and \   u_b\) are zero given that before the bullet was shot the gun was at rest

\(v_g\) is negative given because from Newtons third law action and reaction is equal and opposite so if the bullet is moving forward the gun will be moving backward

So

   \( 0.005 *  0  +  1* 0=  0.005 * 8.00 * 10^{2}  -   1.00*  v_g\)      

=>  \( v_g  =  4 \  m/s \)    

Hence the velocity of the bullet with respect to the loose gun is  

     \(v  =  v_b  -  v_g\)

=>   \(v  =  8.00 * 10^{2}   - 4\)

=>   \(v  = 796 \  m/s \)

Answer:

32J

Explanation:

Heat H = MC∆T = 4 × 1.0 × 8 = 32J

Answer:

37500 N

Explanation:

F = ma

F = 7500 (5 m/s^2) = 37500 N

As the velocity of the body is uniform,

Thus, the change of displacement in equal interval time remains constant.

The graphical representation of displacement and time for the uniform motion is,

From the diagram, the velocity of the particle from origin to the point A,

The velocity is,

The velocity of the body from A to B is,

Thus, the line in the graph passing through the origin, A and B is representing the motion of the body moving with the uniform velocity.

(a) The minimum force F he must exert to get the block moving is 38.9 N.

(b) The acceleration of the block is 0.79 m/s².

The minimum force F he must exert to get the block moving is calculated as follows;

Fcosθ = μ(s)Fₙ

Fcosθ = μ(s)mg

where;

F = [0.1(36)(9.8)] / [(cos(25)]

F = 38.9 N

F(net) = 38.9 - (0.03 x 36 x 9.8) = 28.32

a = F(net)/m

a = 28.32/36

a = 0.79 m/s²

Thus, the minimum force F he must exert to get the block moving is 38.9 N.

The acceleration of the block is 0.79 m/s².

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Answer:

hydrogen, helium, lithium, beryllium, boron, carbon, nitrogen, oxygen, fluorine, neon, sodium, magnesium, aluminum, silicon, phosphorus, sulfur, chlorine, argon, potassium, calcium, scandium, titanium, vanadium, chromium, maganese, iron, cobalt, nickel, copper, zinnc, gallium, germanium, aresnic, selenium, bromine, krypton, rubidium, strongtium, yttrium, zirconium, niobium, molybdenum, technetium, ruthenium, rhodium, palladium, silver, cadmium, indium, tin, atimony, tellurium, iodine, xenon, cesium, barium, lanthanum, cerium, praseodyumium, neodymim, promethium, samarium, europium, gadolinium, terbium, dysprosium, holmium, erbium, thulium, ytterbium, luteium, hafnium, tantalum, tungsten, rhenium, osmium, irdium, platinum, gold, mercury, thallium, lead bismuth, polnium, astatine, radon, rancium, radium, actinum, thorium, protactinium

Explanation:

The net force on particle q₂, located between particles q₁ and q₃, is approximately 189000 N. The force exerted by particle q₁ on q₂ is positive and equals 252000 N, while the force exerted by particle q₃ on q₂ is negative and equals -63000 N.

To find the net force on particle q₂, we need to calculate the individual forces exerted on q₂ by particles q₁ and q₃ and then determine their sum.

The force between two charged particles can be calculated using Coulomb's law:

F = k * |q₁ * q₂| / r²

Where F is the force between the particles, k is the electrostatic constant (k ≈ 9.0 x \(10^9\) Nm²/C²), q₁ and q₂ are the charges of the particles, and r is the distance between them.

First, let's calculate the force exerted on q₂ by q₁:

F₁₂ = k * |q₁ * q₂| / r₁₂²

F₁₂ = (9.0 x \(10^9\) Nm²/C²) * |(8.0 μC) * (3.5 μC)| / (0.10 m)²

F₁₂ ≈ 252000 N

The force is positive because q₁ and q₂ have opposite charges.

Next, let's calculate the force exerted on q₂ by q₃:

F₂₃ = k * |q₂ * q₃| / r₂₃²

F₂₃ = (9.0 x \(10^9\)Nm²/C²) * |(3.5 μC) * (-2.5 μC)| / (0.15 m)²

F₂₃ ≈ -63000 N

The force is negative because q₂ and q₃ have the same charge.

Finally, we can find the net force on q₂ by summing the individual forces:

Net force = F₁₂ + F₂₃

Net force = 252000 N + (-63000 N)

Net force ≈ 189000 N

The net force on particle q₂ is approximately 189000 N.

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Answer:

The mass of the gold bar is 1,544 g

Explanation:

When mass of Mars and Phobos are given then we can calculate that Mars and Phobos are 9.098x 10⁶ meters apart.

The gravitational force is that force that pulls objects with mass towards each other.

The formula for the gravitational force between two objects is given as:

Force = G  (M1) (M2) / (distance²)

Given, Force  =  4.98 x 10¹⁵N

G  =  6.673 x 10⁻¹¹  N·m²/kg²

Given One mass =   6.79 x 10²³ kg

and Other mass = 9.1 x 10¹⁵ kg  

Force = (G) · (M1) · (M2) / (distance²)

4.98x10¹⁵N = (6.673x10⁻¹¹N-m²/kg²)·(6.79x10²³kg)·(9.1x10¹⁵kg) / (distance²)

(distance²)·(4.98x10¹⁵N) = (6.673x10⁻¹¹N-m²/kg²)·(6.79x10²³kg)·(9.1x10¹⁵kg)

(distance²)=(6.673x10⁻¹¹N-m²/kg²)·(6.79x10²³kg)·(9.1x10¹⁵kg) / (4.98x10¹⁵N)

 (distance²)  =  8.279 x 10¹³  m²

distance  =  9.098x 10⁶ meters .  

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The Sun is composed of helium and hydrogen. Option C.

The photosphere chromosphere and corona are all part of the Sun's atmosphere. Although the corona is sometimes called the solar atmosphere it is actually the sun's upper atmosphere. The sun's atmosphere includes features such as sunspots, coronal holes, and solar flares the sun is a star.

It's a huge spinning ball of hot gas. The sun is like a star in the night sky. Because we are so close it appears much larger and brighter than other stars. The sun is the center of the solar system and accounts for most of the mass of the solar system. Compared to the billions of other stars in the universe, the sun stands out. But for the Earth and the other planets orbiting around it, the Sun is a powerful focal point.

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Answer:

A. It interrupts the low of electrons when it is open.

Explanation:

The switch in an electrical circuit interrupts the flow of electrons when it is open. Therefore, option (A) is correct.

The electric circuits can be described as closed-loop or paths, forming a network of electrical components where electrons flow. The path is generally made using electrical wires. The start-off point from where the electrons start flowing is known as the source, whereas the point where electrons leave the electrical circuit is known as the return.

The switch can be described as a small gap in the circuit. There are many types of switches. A switch is used to open or close an electrical circuit. A switch can be described as an electrical component that can be used to turn on and turn off any equipment.

When the switch of an electrical circuit is off, the circuit is open, and there is no flow of current or electrons. The current flow when the circuit is closed, therefore the switch should be on.

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Explanation:

Newton’s second law is a quantitative description of the changes that a force can produce on the motion of a body. It states that the time rate of change of the momentum of a body is equal in both magnitude and direction to the force imposed on it.

The sensitization message to truck owners and the police in my community using the scene of turning effect of forces and stability is Let us work together so that the prioritization of road safety as well as the stability in our community can be secured by the promotion of responsible behavior so that all all road users can be safe.

In the non-associative learning process of sensitization, the delivery of a stimulus repeatedly causes a response's volume to gradually increase. In addition to the recurrent stimulus, sensitization is frequently accompanied by an improvement in responsiveness to a whole class of stimuli.

This is a sort of community-level intervention where we work hand-in-hand with the local population using creative means of contact and communication that enable the target audience to relate to the problems on a personal level.

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Answer:

Explanation:

Area of a circle = pi x r x r = 3.14 x 28.77 x 28.77 = 2600.33677 ~ 2600 (using 4 significant figures)

The reactants in the given chemical equation are methane (CH₄) and oxygen (O₂), while the products are carbon dioxide (CO₂) and water (H₂O).

During a chemical reaction, the atoms of the reactants reorganize to form new compounds in the products. A chemical change is this atomic rearrangement.

A chemical change is the transformation of one or more substances into new ones with distinct chemical and physical properties. New substances are created when the original substances' atoms are rearranged and new chemical bonds are formed during a chemical change.

Typically, a transfer of energy in the form of heat, light, or sound occurs in conjunction with this kind of change. Reactions like combustion, oxidation, decomposition, and synthesis are all examples of chemical changes. Physical changes, on the other hand, involve alterations in a substance's physical properties without altering its chemical composition.

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Answer:

-12.1

Explanation:

i’m almost sure this is it, i’m checking my old answers

if not let me know and i’ll give you some more answers

A scale which reads 0 in the vacuum of space is placed on the surface of planet Physica. On the planet's surface, the scale indicates a force of 10,000 Newtons. The surface area of the scale is 0.125 square meters.

To calculate the surface area of the scale, we can use the formula:

P = F/A

where P is the pressure, F is the force, and A is the surface area.

Given that the atmospheric pressure on the surface of Physica is 80,000 Pascals and the scale indicates a force of 10,000 Newtons, we can plug in these values into the equation:

80,000 Pa = 10,000 N / A

To solve for A, we can rearrange the equation:

A = 10,000 N / 80,000 Pa

A = 0.125 m²

In summary, based on the given information, the surface area of the scale on the surface of planet Physica is calculated to be 0.125 square meters.

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There are around 3.8179x10⁻⁹ seconds between the crests of each wave.

The number of cycles per second is the unit of frequency in Hertz. To find the time interval for a known frequency, just divide 1 by the frequency (for example, a frequency of 100 Hz has a time interval of 1/(100 Hz) = 0.01 seconds; a frequency of 500 Hz has a time interval of 1/(500Hz) = 0.002 seconds, etc.). The wavelength is the separation between a specific location and that same location in the next wave cycle.

T = 1/f

By changing the value of f, we obtain:

T = 1 / 262x10⁻⁹ Hz

T = 3.8179x10⁻⁹ seconds

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they are formed when hot

it's dependent on the rate of cooling of the melt, slow cooling allows large crystals to form, fast cooling yields small crystals. They cool too quickly to form crystals.

Hope this helps! <3 :3

The mass of the planet is  5.98 × 10^24 kg.

To calculate the mass of the planet, we can use Kepler's Third Law of Planetary Motion. This law states that the square of the period of revolution of a planet around the sun is directly proportional to the cube of the semi-major axis of its orbit.

First, we need to convert the period of the satellite's orbit to seconds. We know that there are 60 minutes in an hour, so the period can be expressed as (6 × 60 + 12) minutes, which equals 372 minutes. Multiplying this by 60 seconds, we get a period of 22,320 seconds.

Next, we need to find the semi-major axis of the orbit. In a circular orbit, the semi-major axis is equal to the radius of the orbit. Therefore, the semi-major axis is 8.8 × 10^6 m.

Now, we can apply Kepler's Third Law to calculate the mass of the planet. The formula is T^2 = (4π^2/GM) × a^3, where T is the period of revolution, G is the gravitational constant, M is the mass of the planet, and a is the semi-major axis of the orbit.

Rearranging the formula, we can solve for the mass of the planet:
M = (4π^2/G) × a^3 / T^2

Plugging in the values, we get:
M = (4 × π^2 / 6.67430 × 10^-11) × (8.8 × 10^6)^3 / (22,320)^2

Evaluating this expression, we find that the mass of the planet is approximately 5.98 × 10^24 kg.

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Answer: 13.2678 kg

Explanation: Well, 13.2678 kg is 29.25 in mass and kg.

Answer:

Measurement is the comparison of any physical quantity of an object to a standard unit which is pre-determined. The standard units such as length, time, mass etc are known as the Fundamental units of Measurement.

Explanation:

Any object that can be measured is known as a physical quantity. So, to measure the physical quantity, we require some standard units. A measurement consists of two parts - the numerical measurement and the standard unit which is pre-determined. For example, the length of a given table is 10cm, which implies that 10 is the numerical value and the standard unit of measurement is centimeter (cm).

Measurements can be both Fundamental and Derived. Examples of Fundamental quantities are Length, Time etc, while example of Derived quantity is speed which is derived from Length and Time.

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Answer: