Underline the tens digit round to the nearest ten, a) 36,b) 162,c) 105

The value of the triple integral \(\int\int\int_EvdV\)where E is enclosed by the paraboloid z = x² + y² and plane z = 16 is 8192.

We have,

To evaluate the triple integral \(\int\int\int_EzdV\), where E is enclosed by the paraboloid z = x² + y² and the plane z = 16, we need to determine the limits of integration for each variable (x, y, and z).

The region E is the volume between the paraboloid z = x² + y² and the plane z = 16.

To find the limits of integration, we need to determine the bounds for each variable over the region E.

The paraboloid z = x² + y² intersects the plane z = 16 when x² + y² = 16. This represents a circle with a radius of 4 centered at the origin in the xy-plane.

Let's set up the limits of integration:

For z:

Since the paraboloid z = x² + y² and the plane z = 16 intersect at z = 16, the limits for z will be from 0 to 16.

For y:

The region E lies within the circle with radius 4 in the xy-plane.

So, the limits for y will be from -4 to 4.

For x:

Given y and x are symmetric, and the paraboloid is circularly symmetric, the limits for x will also be from -4 to 4.

Now, the triple integral becomes:

\(\int\int\int_E zdV = \int\int\int_E z dV\)

= ∫(from x=-4 to 4) ∫(from y=-4 to 4) ∫(from z=0 to 16) z dz dy dx

Now, integrate with respect to z:

∫(from z=0 to 16) z dz

= [z²/2] (from z=0 to 16)

= (16²/2) - (0²/2)

= 128

Now, integrate with respect to y:

∫(from y=-4 to 4) 128 dy

= 128 * [y] (from y=-4 to 4)

= 128 * (4 - (-4))

= 128 * 8

= 1024

Now, integrate with respect to x:

∫(from x = -4 to 4) 1024 dx

= 1024 [x] (from x = -4 to 4)

= 1024 * (4 - (-4))

= 1024 * 8

= 8192

Therefore,

The value of the triple integral \(\int\int\int_EvdV\)where E is enclosed by the paraboloid z = x² + y² and plane z = 16 is 8192.

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The complete question:

Evaluate \(\int\int\int_E vdV\)where E is enclosed by the paraboloid z = x² + y² and the plane z = 16

the probability of randomly selecting a jack or 4 from a standard deck of 52 cards is 2/13.

In a standard deck of 52 cards, there are four jacks and four 4s, for a total of 8 cards that are either a jack or a 4. The probability of selecting a jack or 4 can be found by dividing the number of favorable outcomes (8) by the total number of possible outcomes (52): P(jack or 4) = 8/52. This fraction can be reduced by dividing both the numerator and denominator by 4: P(jack or 4) = 2/13. Therefore, the probability of randomly selecting a jack or 4 from a standard deck of 52 cards is 2/13. Probability is a measure of the likelihood of an event occurring, expressed as a number between 0 and 1. The probability of an event is calculated by dividing the number of favorable outcomes by the total number of possible outcomes. Probability is used in a wide range of fields, from gambling and sports to scientific research and data analysis. Understanding probability is important for making informed decisions, predicting outcomes, and assessing risks.

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Answer is 2

If 8x = 16y

on rearranging question,

x/y = 16/8 = 2

Answer:

\(\frac{x}{y} = 2\)

Step-by-step explanation:

\(8x = 16y\)

\(=> \frac{8x}{8} = \frac{16y}{8}\)

\(=> x = 2y\)

\(=> \frac{x}{y} = \frac{2y}{y}\)

\(=> \frac{x}{y} = 2\)

The point of concurrency determined by the three altitudes of any triangle is called the orthocenter of the triangle.

The orthocenter is the intersection of the three altitudes of the triangle. It is a point on the plane of the triangle that is equidistant from the three sides of the triangle.

To find the orthocenter of a triangle, you can draw the altitudes of the triangle and find the point where they intersect. The orthocenter is the point of concurrency for the three altitudes.

An orthocenter of a triangle is a point where the three lines that are perpendicular to the sides of the triangle intersect. These lines are called altitudes of the triangle.

Alternatively, you can use the following formula to find the coordinates of the orthocenter:

Let's say that the vertices of the triangle are A(x1, y1), B(x2, y2), and C(x3, y3). The coordinates of the orthocenter (H) can be found using the following formula:

Hx = ( (y1 - y3) (x1^2 + y1^2 - x3^2 - y3^2) - (y1 - y2) (x1^2 + y1^2 - x2^2 - y2^2) ) / (2 * (y1 - y3) - 2 * (y1 - y2))

Hy = ( (x1 - x3) (x1^2 + y1^2 - x3^2 - y3^2) - (x1 - x2) (x1^2 + y1^2 - x2^2 - y2^2) ) / (2 * (x1 - x3) - 2 * (x1 - x2))

Therefore, The point of concurrency determined by the three altitudes of any triangle is called the orthocenter of the triangle

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Answer:

1/3 is the same as 0.33...(The decimal continues on from here.)

(a) The conditional probability density function of X given Y=2 is f X|Y=2(x) = 4e^(-2x).

The conditional probability density function of X given Y=2, denoted as f X|Y=2(x), can be found using the formula:

f X|Y=y(x) = f XY(x, y) / f Y(y)

To find f X|Y=2(x), we need to calculate f XY(x, y) and f Y(y).

Given that f XY(x, y) = 2ye^(-xy) and Y=2, we substitute y=2 into f XY(x, y):

f XY(x, 2) = 2(2)e^(-2x) = 4e^(-2x)

Next, we need to find f Y(2), which is the marginal probability density function of Y evaluated at y=2. To calculate this, we integrate f XY(x, y) over all possible values of x:

f Y(2) = ∫f XY(x, 2)dx = ∫4e^(-2x)dx

Integrating this expression gives us f Y(2) = -2e^(-2x) evaluated from negative infinity to positive infinity. Since this is a continuous probability density function, the integral evaluates to 1:

f Y(2) = 1

Finally, substituting the calculated values into the formula for conditional probability density function, we get:

f X|Y=2(x) = (4e^(-2x)) / 1 = 4e^(-2x)

Therefore, the conditional probability density function of X given Y=2 is f X|Y=2(x) = 4e^(-2x).

(b) The conditional expectation of X given Y=2 is:

E[X|Y=2] = -2xe^(-2x) - e^(-2x) + C

The conditional expectation of X given Y=2, denoted as E[X|Y=2], can be found using the formula:

E[X|Y=y] = ∫xf X|Y=y(x)dx

In this case, we need to calculate E[X|Y=2]:

E[X|Y=2] = ∫x(4e^(-2x))dx

To solve this integral, we can use integration by parts. Let u = x and dv = 4e^(-2x)dx. Then, du = dx and v = -2e^(-2x).

Applying the integration by parts formula, we have:

∫x(4e^(-2x))dx = -2xe^(-2x) - ∫(-2e^(-2x))dx

Simplifying further:

∫x(4e^(-2x))dx = -2xe^(-2x) + 2∫e^(-2x)dx

Using the properties of integration, we can integrate e^(-2x):

∫e^(-2x)dx = -(1/2)e^(-2x)

Substituting this back into the previous equation, we have:

∫x(4e^(-2x))dx = -2xe^(-2x) + 2(-(1/2)e^(-2x)) + C

Simplifying:

∫x(4e^(-2x))dx = -2xe^(-2x) - e^(-2x) + C

Therefore, the conditional expectation of X given Y=2 is:

E[X|Y=2] = -2xe^(-2x) - e^(-2x) + C

where C is the constant of integration.

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Answer:

No solutions

Step-by-step explanation:

First, you need to divide both sides of this equation by -2, making the equation |x-16|=-3. At this point you should know there cannot be any solutions to the equation because absolute value cannot be negative.

Answer:

I- I’m sorry I can’t help

Step-by-step explanation:

Answer:

395

If xx dollar then she will earn 350+ (0.15*xx)

~~~~~~~~~~~~~~~~~~~~

Double Check :)

Kelas : VII (1 SMP)

Materi : Geometri

Kata Kunci : Garis, Sisi, Rusuk, Bidang

Pembahasan :

Titik adalah bentuk yang paling dasar dalam geometri. Titik ditulis dengan tanda titik dan diberi nama dengan huruf besar. Sebuah titik hanya untuk menunjukkan posisi dan memiliki ukuran nol (panjang nol, lebar nol, dan tinggi nol).

Garis adalah kumpulan titik-titik yang memanjang secara tak berhingga ke dua arah. Sebuah garis memiliki panjang tidak terbatas.

Ruas garis adalah potongan sebuah garis. Sebuah ruas garis memiliki dua titik ujung dan diberi nama menurut kedua titik ujungnya.

Sinar garis merupakan bagian dari sebuah garis, namun hanya memiliki satu titik ujung. Sebuah sinar garis diberi nama dengan huruf titik ujungnya dan titik lain pada sinar garis tersebut.

Sudut adalah dua sinar yang memiliki titik ujung yang sama.

Titik ujung tersebut dinamakan titik sudut dan sinar-sinar garisnya dinamakan sisi-sisi sudut. 

Bidang adalah kumpulan titik yang jumlahnya tak terhingga yang membentuk permukaan rata yang melebar ke segala arah sampai tak terhingga. Sebuah bidang memiliki panjang tak terbatas, lebar tak terbatas, dan tinggi nol. Sebuah bidang biasanya digambarkan dengan gambar segi empat dan diberi nama dengan satu huruf besar.

Rusuk adalah suatu garis yang merupakan pertemuan dari dua sisi bidang.

Dua bidang berpotongan bila terdapat garis persekutuan atau garis potong antara kedua bidang tersebut.

Dua bidang sejajar bila antara kedua bidang tersebut tidak memiliki garis persekutuan.

Dua bidang berhimpit bila setiap titik terletak pada kedua bidang tersebut.

Mari kita lihat soal tersebut.

Jika dua bidang saling berpotongan dan tidak berhimpitan, maka perpotongannya berbentuk garis.

Jadi, jawabannya adalah B.

Semangat!

Answer:

t = -3

Step-by-step explanation:

Answer:

575 if your asking for the area

Step-by-step explanation:

Answer:

No solution

Step-by-step explanation:

\(y=-2x+1\)

\(4x+2y=-1\)

The first equation is set up in slope-intercept form but the second equation isn't. So first set up the second equation in slope-intercept form.

\(4x+2y=-1\)

Divide everything by 2

\(2x+y=-\frac{1}{2}\)

Solve for y

\(y=-2x-\frac{1}{2}\)

Both equations have the same slope but different y-intercepts which means that there is no solution

Answer:

3 times - 2,times 8-13

You solve the ones in the bracket first

(the rule of BODMAS)

So 8-13 first, then

-2times 8-13,then

Then you get your answer

Answer:

The expanded form of this expression should be 7.5-10n-20.

Step-by-step explanation:

Note: I am not 100% on this answer, so if this is not the response you were looking for, do not hesitate to tell me. Hopefully this answer helps though :)

Answer:

-2.5(-3+4n+8)

7.5-10n-20

-22.5-10n

Answer:

72

Step-by-step explanation:

Answer:

first write 30% as fraction

30/100 then "of" means multiplication

30/100×240

=72

can i have brainliest if it helped

Step-by-step explanation:

Answer:

I think (if we have class. It is a blue day) but I'm not sure

Answer:

4x

Step-by-step explanation:

x hours for 4 weeks = 4x

it's 4 times x

I do not know how to solve this problem sorry see ypu later mabye

Answer: 26

Step-by-step explanation:

The spread of the data in the histogram is uneven or skewed to the right.

A histogram is a graphical representation of data used to display the distribution of values in a dataset, showing data in bins or intervals along the horizontal axis.

The data distribution in the histogram is uneven or tilted to the right. This suggests that there are fewer students who have gone water skiing less frequently (1 to 5 trips) and more students who have gone water skiing more frequently (11 to 15 trips). The frequency is greatest between 11 and 15 visits, which is reflected by the largest bar in the histogram.

In given problem, the skewed distribution of the given data shows that there are more no. of the students doing water-skiing regularly than those who are doing it less frequently.

This might imply that there is a group of students who are more experienced or enthusiastic about water skiing, and they have gone on more excursions than other students who have gone on less trips. It also implies that the majority of students fall within the 11 to 15 trip period, which might imply a common pattern or trend in the data.

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The best description of the spread of the data is that it is skewed or unevenly distributed.

A histogram is a graphical representation of data used to display the distribution of values in a dataset, showing data in bins or intervals along the horizontal axis.

Based on the given histogram, the data is not evenly distributed across the five intervals. The majority of students have been water-skiing between 11 and 15 times, with a frequency of 5. There are fewer students who have been water-skiing between 16 and 20 times, with a frequency of 4, and even fewer students who have been water-skiing between 21 and 25 times, with a frequency of 3.

The spread of the data refers to how far apart the values in the dataset are from each other. In this case, the data is not evenly spread across the different intervals. The values in the dataset are more concentrated in the interval of 11 to 15, and less concentrated in the intervals of 1 to 5 and 21 to 25. This indicates that the majority of students have been water-skiing a similar number of times, while fewer students have been water-skiing either a lot or a little.

Therefore, the best description of the spread of the data is that it is skewed or unevenly distributed.

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The complete question is:

A group of students was asked about the number of times they had been water-skiing. The data is shown in the histogram.

A histogram titled Water Skiing Trips. The x-axis is labeled Number of Times Water Skiing and has intervals of 1 to 5, 6 to 10, 11 to 15, 16 to 20, and 21 to 25. The y-axis is labeled Frequency and starts at 0 with tick marks every 1 units up to 6. There is a shaded bar for 1 to 5 that stops at 1, for 6 to 10 that stops at 2, for 11 to 15 that stops at 5, for 16 to 20 that stops at 4, and for 21 to 25 that stops at 3.

Which of the following best describes the spread of the data? Explain its meaning in this situation?

The probability of getting at most 4 and yellow is 1/12.

In this problem, we are given two events: rolling a number that is at most 4 on a six-sided die and spinning the spinner and landing on yellow.

To find the probability of getting at most 4, we first need to determine how many outcomes on the die will satisfy this condition. There are four possible outcomes that meet this requirement: rolling a 1, 2, 3, or 4. Since there are six possible outcomes in total (rolling a 1, 2, 3, 4, 5, or 6), the probability of rolling at most 4 is 4/6, which simplifies to 2/3.

Next, we need to determine the probability of spinning the spinner and landing on yellow. There are five equally-sized sections on the spinner, so the probability of landing on yellow is 1/5.

To find the probability of both events happening, we multiply their individual probabilities. This is because the two events are independent; the outcome of the first event (rolling the die) does not affect the outcome of the second event (spinning the spinner).

Therefore, the probability of getting at most 4 and yellow is the product of the probability of getting at most 4 (2/3) and the probability of getting yellow (1/5), which equals 2/15.

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The mode of a dataset is the value that appears most frequently. In this case, we need to find the interval of rainfall that occurs most frequently.

From the given data, we can see that the interval "less than 0.01 inch" has the highest frequency with 165 days. Therefore, the mode of this dataset is "less than 0.01 inch"

Effective communication is crucial in all aspects of life, including personal relationships, business, education, and social interactions. Good communication skills allow individuals to express their thoughts and feelings clearly, listen actively, and respond appropriately. In personal relationships, effective communication fosters mutual understanding, trust, and respect.

In the business world, it is essential for building strong relationships with clients, customers, and colleagues, and for achieving goals and objectives. Good communication also plays a vital role in education, where it facilitates the transfer of knowledge and information from teachers to students.

Moreover, effective communication skills enable individuals to engage in social interactions and build meaningful connections with others. Therefore, it is essential to develop good communication skills to succeed in all aspects of life.

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Answer:

x=20

Step-by-step explanation:

2(3x−9)=5x+2

(2)(3x)+(2)(−9)=5x+2(Distribute)

6x+−18=5x+2

6x−18=5x+2

6x−18−5x=5x+2−5x

x−18=2

x−18+18=2+18

x=20

aqueell ears hanan pus

A. statistically significant difference in the mean blood hemoglobin levels between breastfed infants and formula-fed infants at α = 0.05.

B. the 95% confidence interval for the difference in population means between breast-fed infants and formula-fed infants is (−0.06, 1.18).

C. Both the hypothesis test and the confidence interval lead to the same conclusion that there is a difference in the mean blood hemoglobin levels between the two feeding regimens.

What is null hypothesis?

In statistics, the null hypothesis (H0) is a statement that assumes that there is no significant difference between two or more groups, samples, or populations.

(a) To test the hypothesis that there is a difference in the population means between breast-fed infants and formula-fed infants, we can use a two-sample t-test with equal variances. The null hypothesis is that the population means are equal, and the alternative hypothesis is that they are not equal. Using α = 0.05 as the significance level, the critical value for a two-tailed test with 40 degrees of freedom is ±2.021.

The test statistic can be calculated as:

t = (x1 - x2) / (Sp * √(1/n1 + 1/n2))

where x1 and x2 are the sample means, Sp is the pooled standard deviation, and n1 and n2 are the sample sizes. The pooled standard deviation can be calculated as:

Sp = √(((n1 - 1) * s1² + (n2 - 1) * s2²) / (n1 + n2 - 2))

where s1 and s2 are the sample standard deviations.

Plugging in the values from the table, we get:

t = (13.3 - 12.4) / (1.776 * √(1/23 + 1/19)) = 2.21

Since the absolute value of the test statistic is greater than the critical value, we reject the null hypothesis and conclude that there is a statistically significant difference in the mean blood hemoglobin levels between breastfed infants and formula-fed infants at α = 0.05.

(b) To construct a 95% confidence interval for the difference in population means between breast-fed infants and formula-fed infants, we can use the formula:

(x1 - x2) ± tα/2,Sp * √(1/n1 + 1/n2)

where tα/2,Sp is the critical value of the t-distribution with (n1 + n2 - 2) degrees of freedom and α/2 as the significance level.

Plugging in the values from the table, we get:

(x1 - x2) ± tα/2,Sp * √(1/n1 + 1/n2)

= (13.3 - 12.4) ± 2.021 * 1.776 * √(1/23 + 1/19)

= 0.56 ± 0.62

Therefore, the 95% confidence interval for the difference in population means between breast-fed infants and formula-fed infants is (−0.06, 1.18).

(c) The hypothesis test and the confidence interval both lead to the conclusion that there is a difference in the mean blood hemoglobin levels between breast-fed infants and formula-fed infants. In part (a), we rejected the null hypothesis that the population means are equal, which means we concluded that there is a difference. In part (b), the confidence interval does not contain 0, which means we can reject the null hypothesis that the difference in means is 0 at the 95% confidence level.

Therefore, both the hypothesis test and the confidence interval lead to the same conclusion that there is a difference in the mean blood hemoglobin levels between the two feeding regimens.

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Answer:

SSS

Step-by-step explanation:

Same Sides Subtract

The congruence theorem that can be used to prove that ΔBDA ≅ ΔBDC is: D. SSS

The SSS Congruence Theorem is a theorem that proves that if one triangle has three sides that are congruent to the three corresponding sides of a another triangle, both triangles are congruent.

Thus, ΔBDA and ΔBDC both have three pairs of congruent corresponding sides, namely:

Therefore, the congruence theorem that can be used to prove that ΔBDA ≅ ΔBDC is: D. SSS

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Answer:

y=1/2*(x-4)^2+13

Step-by-step explanation:

Answer:

y=1/2*(x-4)^2+13

Step-by-step explanation:

The length vector is 1. So the sketch vector field f is given below. So the option a is correct.

In the given question, the vector field F by drawing a diagram like this figure.

The given vector field F is:

F(x, y) = (yi + xj)/√(x^2 + y^2)

We can write the vector field as:

F(x, y) = yi/√(x^2 + y^2) + xj/√(x^2 + y^2)

Here

F(x, y) = [y/√(x^2 + y^2)]^2 + [x/√(x^2 + y^2)]^2

F(x, y) = y^2/(x^2 + y^2) + x^2/(x^2 + y^2)

F(x, y) = (y^2+ x^2)/(x^2 + y^2)

F(x, y) = 1

F(0, y) = y/|y| = ±1

F(x, 0) = x/|x| = ±1

So the length vector is 1.

So the sketch vector field f is given below:

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The complete question is:

Sketch the vector field F by drawing a diagram like this figure.

F(x, y) = (yi + xj)/√(x^2 + y^2)

Answer:

\(\sqrt{85}\)

Step-by-step explanation:

Calculate the distance d using the distance formula

d = \(\sqrt{(x_{2}-x_{1})^2+(y_{2-y_{1})^2 } }\)

with (x₁, y₁ ) = (- 5, 8 ) and (x₂, y₂ ) = (4, 6 )

d = \(\sqrt{4-(-5))^2+(6-8)^2}\)

  = \(\sqrt{(4+5)^2+(-2)^2}\)

  = \(\sqrt{9^2+4}\)

  = \(\sqrt{81+4}\)

  = \(\sqrt{85}\)