UUC codes for ___ whereas UUA codes for ___ When synthesis of the protein reaches the altered codon, ____ would be observed. 1. phenylalanine 2. a new sequence 3. START 4. STOP 5. isoleucine 6. tyrosine 7. leucine 8. the same sequence 9. glycine

Answer:

5.46x\(10^{8}\)

Explanation:

just move the decimal however many places to the left until there is only one digit to the left of it and then square the ten by that number

Some emerging infections have increased in occurrence within the past two decades" is true.

Emerging infections are infectious diseases that are either newly discovered or previously undiscovered and are either expanding in frequency, geographic scope, or virulence .

There is evidence to show that over the past 20 years, the prevalence of several emerging infections has grown. These include ailments like SARS, Ebola, Zika, and COVID-19 as examples. The causes of this rise are complicated and multifaceted, but they may be linked to things like globalization, increased trade and travel, deforestation and alterations in the climate and land usage

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Answer:

58.44277 I hope this works best of luck for you

Answer:

fossil evidence

fit of South America and Africa

Explanation: can i have brainlist please

The volume that is occupied by the gas is obtained as  56 L.

We know that from the Avogadro's law, the volume that can be occupied by one mole of a gas is obtained as 22.4 L. This implies that we have to find the number of moles in the 70 g of the CO and then obtain the corresponding volume by simple proportion.

Number of moles of CO = 70.0 g/28 g/mol

= 2.5 moles

If 1 mole of the gas occupies 22.4 L

2.5 moles of the gas occupies 2.5 * 22.4/1 mole

= 56 L

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Answer: The water will taste sour.

Explanation:

Answer: D. The water will taste sour (Edmentum)

Explanation:

Answer:

C. He feels excited and happy

Explanation:

In determining the greater source of error in the experimentally determined density of the metal cylinder, we need to consider the mass and the volume.

The mass and volume are both measured quantities, and any errors in these measurements can contribute to the overall error in the density calculation. However, in this case, the greater source of error is likely the volume measurement.

The volume of the metal cylinder is determined by measuring its dimensions, such as length, width, and height. These measurements are subject to uncertainties due to various factors, such as parallax errors or limitations of the measuring instrument. Even small errors in the measurements of length, width, or height can result in significant differences in volume when multiplied together.

On the other hand, the mass measurement of the metal cylinder is typically more precise and less prone to errors. Using a balance with a high level of accuracy, the mass can be measured directly without much uncertainty.

To minimize the error in the experimentally determined density, it is crucial to ensure accurate measurements of the volume. This can be achieved by using precise measuring instruments, taking multiple measurements, and averaging the results. Additionally, techniques like using a water displacement method can provide a more accurate volume measurement.

In conclusion, while both the mass and volume measurements contribute to the overall error in the experimentally determined density, the volume measurement is likely the greater source of error due to the inherent uncertainties in measuring dimensions accurately.

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Rubidium sulfide( Rb2S)

please mark as brainliest

Answer:

Simple distillation is a method for separating the solvent from a solution.

Explanation:

For example, water can be separated from salt solution by simple distillation. This method works because water has a much lower boiling point than salt. When the solution is heated, the water evaporates.

Answer:

Stealing the last of your points on questions, it's been fun and I will most likely do it more in the future but for now this is the end. Thank you for the many points friend.

Explanation:

⏁⊑⏃⋏☍ ⊬⍜⎍ ⎎⍜⍀ ⏁⊑⟒ ⌿⍜⟟⋏⏁⌇ ⎅⟒⏃⍀ ⎎⍀⟟⟒⋏⎅, ⟟ ⏃⋔ ⎎⍜⍀⟒⎐⟒⍀ ⟟⋏ ⊬⍜⎍⍀ ⎅⟒⏚⏁.

The value that would be put in the numerator of this calibration would be 10° C .

The process of calibrating an instrument involves setting it up such that it can produce results for samples that are within a reasonable range. A key component of instrumentation design is eliminating or reducing conditions that lead to faulty measurements.

In order to ascertain the mistake or confirm the precision of the unknown value of the DUT, a calibration is normally carried out. As a simple illustration, you may calibrate a DUT thermometer by measuring its temperature in water at its known boiling point (212 degrees Fahrenheit) in order to determine the thermometer's inaccuracy.

To obtain accurate readings, a thermometer must be calibrated because its precision is susceptible to deterioration over time. Thermometers can change over time for a variety of reasons.

Hence, The value that would be put in the numerator would be 10° C because difference between two marked values or space between two marked value is 10.

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The growth of the balloon after being taken out of liquid nitrogen is a result of the increase in temperature, which leads to an increase in the kinetic energy and speed of the gas molecules, causing them to spread out and expand, resulting in the expansion of the balloon.

The phenomenon you are describing, where a small, partially inflated balloon grows in size after being taken out of liquid nitrogen, can be explained by the principles of gas expansion due to temperature change.

When the balloon is submerged in liquid nitrogen, it is exposed to an extremely low temperature. As a result, the air molecules inside the balloon lose thermal energy and their average kinetic energy decreases. This decrease in kinetic energy causes the molecules to slow down and move closer together, leading to a decrease in pressure and volume of the gas inside the balloon.

When the balloon is removed from the liquid nitrogen and placed on the table, it starts to warm up. As the temperature increases, the air molecules regain thermal energy and their average kinetic energy rises. This increase in kinetic energy causes the molecules to move faster and spread out, leading to an increase in pressure and volume of the gas inside the balloon.

Furthermore, gases typically exhibit a property known as Thermal expansion, which means they expand when heated and contract when cooled. As the temperature of the air inside the balloon rises, the gas expands, causing the balloon to grow in size.

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If ΔG° (standard Gibbs free energy change) is greater than 0, the correct answer is D. Reactants are more abundant at equilibrium.

The sign of ΔG° is a crucial factor in determining the direction of a chemical reaction and the relative abundances of reactants and products at equilibrium. ΔG° represents the change in free energy under standard conditions (constant temperature, pressure, and concentration).

If ΔG° is positive (>0), it indicates that the reaction is non-spontaneous in the forward direction under standard conditions. This means that the reactants have a higher free energy than the products. In such cases, the reaction tends to favor the formation of the reactants rather than the products.

At equilibrium, the forward and reverse reactions occur at the same rate, and there is no net change in the concentrations of reactants and products over time. However, the relative abundances of reactants and products at equilibrium are determined by the equilibrium constant (K).

The equilibrium constant (K) is defined as the ratio of the concentrations (or activities) of products to reactants, each raised to the power of their respective stoichiometric coefficients. If ΔG° is positive, it implies that the equilibrium constant (K) is less than 1.

According to Le Chatelier's principle, when K is less than 1, the equilibrium position shifts towards the side with a lower concentration of products. Therefore, at equilibrium, the reactants are more abundant than the products.

If ΔG° is greater than 0, the reactants are more abundant at equilibrium (option D).

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Answer:

The melting and boiling points of molecular compounds are generally quite low compared to those of ionic compounds. This is because the energy required to disrupt the intermolecular forces between molecules is far less than the energy required to break the ionic bonds in a crystalline ionic compound

Answer:

Explanation:

[2-0] NC Special Operation

[2] Supervisor

[2-1] Emergency Response

[2-2] Juggernaut

[2-3] Commander

[2-4] Division Director    

Answer:

\(\boxed {\boxed {\sf 2.62 \ mol \ N_2}}\)

Explanation:

The relationship between moles and gases is unique. Regardless of the type of gas, there will always be 22.4 liters of gas in 1 mole, as long as it's at STP (standard temperature and pressure).

We can make a ratio using this information.

\(\frac {22.4 \ L \ N_2}{ 1 \ mol \ N_2}\)

Multiply by the given number of moles.

\(58.6 \ L \ N_2 *\frac {22.4 \ L \ N_2}{ 1 \ mol \ N_2}\)

Flip the fraction so the liters of nitrogen cancel.

\(58.6 \ L \ N_2 *\frac {1 \ mol \ N_2}{ 22.4 \ L \ N_2}\)

\(58.6 *\frac {1 \ mol \ N_2}{ 22.4 }\)

\(\frac {58.6 \ mol \ N_2}{ 22.4 }= 2.61607143 \ mol \ N_2\)

The original measurement of liters has 3 significant figures, so our answer must have the same.

For the number of moles calculated, 3 sig figs is the hundredth place. The 6 in the thousandth place tells us to round the 1 to a 2.

\(2.62 \ mol \ N_2\)

58.6 liters of N₂ gas at STP is equal to about 2.62 moles.

According to the question the number of moles of CO₂(g) produced in the reaction is 1.18 mol.

Moles are small, burrowing mammals found throughout much of the world. They are classified as insectivores, meaning they are specialized in eating insects. Moles have long, cylindrical bodies, short limbs, and large, clawed feet adapted for digging. Their fur is usually black to gray, though some species may have a light brown or yellowish color. They have small eyes and ears, and their noses are long and sensitive, used to detect prey and other objects in their environment.

The ideal gas law can be used to calculate the number of moles of CO₂(g) produced in the reaction. The ideal gas law states that PV = nRT, where P is pressure, V is volume, n is the number of moles, R is the ideal gas constant, and T is temperature.
Since the volume and temperature are known, we can rearrange the equation to solve for n:
n = PV/RT
At the beginning of the reaction, the pressure is 0 and the volume is 4.3 L, so the number of moles of CO₂(g) is 0.
At the end of the reaction, the pressure is 5 atm and the volume is still 4.3 L. Plugging these values into the equation gives us:
n = (5 atm)(4.3 L)/(0.08206 L·atm/mol·K)(298K) = 1.18 mol CO₂(g)
Therefore, the number of moles of CO₂(g) produced in the reaction is 1.18 mol.

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Answer:

Water and carbon dioxide

Explanation:

The product of combustion for all hydrocarbons are carbon dioxide and water

Answer:

litmus paper

Explanation:

have a great day ahead

Answer:

methyl orange

Explanation:

hope it helps

The metal will plate a lead strip that is dipped into a solution of ions is:

c) Mercury

In this case, the metal that will plate a lead strip when dipped into a solution of its ions is mercury (Hg).

Mercury has a higher position in the electrochemical series compared to lead. When a lead strip is dipped into a solution containing mercury ions (Hg⁺²), a redox reaction occurs. The mercury ions in the solution will be reduced and gain electrons, while the lead strip will undergo oxidation and lose electrons.

As a result, the mercury ions will be reduced to metallic mercury and plate onto the surface of the lead strip. This plating process is known as electroplating and is commonly used in various applications, including coating surfaces with a layer of a different metal.

The potassium (K) and calcium (Ca) have lower positions in the electrochemical series compared to lead. Therefore, they would not plate onto a lead strip when dipped into a solution of their ions.

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The complete question is:

Which metal will plate a lead strip that is dipped into a solution of its ions?

a) potassium

b) calcium

c) mercury

Answer:

The lithosphere is the most outer solid portion of

he most outer solid portion ofthe planet Earth.

crust is the outermost layer of earth.

To calculate the standard electromotive force (emf) for the reaction: H2(g) + F2(g) → 2H+(aq) + 2F-(aq), We need to find the difference in standard reduction potentials (E°) for the half-reactions involved and sum them.

The reduction half-reactions for H2 and F2 are as follows:

H2(g) → 2H+(aq) + 2e-     (reduction half-reaction for H2)

F2(g) + 2e- → 2F-(aq)     (oxidation half-reaction for F2)

The standard reduction potentials (E°) for these half-reactions are:

E°(H2/H+) = 0.00 V

E°(F2/F-) = 2.87 V

To calculate the standard emf (ΔE°) for the overall reaction, we sum the reduction potentials of the half-reactions:

ΔE° = E°(reduction) + (-E°(oxidation))

ΔE° = 0.00 V + (-2.87 V)

ΔE° ≈ -2.87 V

The standard emf (ΔE°) for the given reaction is approximately -2.87 V.

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Molecules are the smallest chemical units of matter that retain the chemical properties of a substance. They are formed by the combination of two or more atoms held together by chemical bonds, either through sharing or transfer of electrons.

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Answer:

Explanation:

2C₂H₂ + 5O₂ = 4CO₂ +  2H₂O .

CO₂ formed in moles = 33.4 / 44 = .76 moles

4 moles of CO₂ is formed by 2 moles of C₂H₂

.76 moles of CO₂ is formed by .38 moles of C₂H₂

.38 moles of C₂H₂ were present initially

2 moles of C₂H₂  produces 2 moles of water

.38 moles of C₂H₂  produces .38  moles of water

water produced = .38 moles

= .38 x 18 = 6.84 grams of water .

Answer:

Put sand in one cup and water in the other. Put two heat lamps at equal height and under each one put the water and sand, this must be done at the same exact time. Set a timer for 5, then 10, then 15, and so forth minutes. Each time measure the temperature of each with the thermometers and write the down. Have a certain temperature you want them to get to and see which gets to it quicker. Then set a new temp 3 times to see if the answer is consistent.

Explanation:

Doing this would test whether land or water heats quicker... Hope this helps!!!...

The absolute amount of the discrepancy or simply error between the measured value and the actual value is multiplied by 100 and divided by the actual value to determine the percent error.

Follow these easy procedures to determine the error rate-

1. Don't take into consideration any minus (-) signs when calculating the inaccuracy (by deducting the predicted value from the actual value). take the error's absolute value, etc.

Approximate Value - Exact Value = Absolute Error

2. Subtract the mistake from the accurate figure (sometimes, we may get a decimal number).

3. Relative error is the difference between the precise and approximative values.

4. Add a "%" following the conversion to a percentage (by multiplying by 100).

|Approximate Value - Exact Value|/Exact Value 100% Percent Error

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Answer:

bleh

Explanation:

Neutralization reaction between magnesium hydroxide and hydrochloric acid Mg(OH)2(s) + 2HCl(aq) → 2H2O(l) + MgCl2(aq) b.

so uh pretty sure Mg(OH)2(s) + 2HCl(aq) → 2H2O(l) + MgCl2(aq) b.

correct me if im wrong <3

The process in which solid iron reacts with gaseous oxygen to form solid iron (iii) oxide is what happens when iron rusts. Iron rusts when exposed to moisture, water, and the oxygen present in the air.

when iron rustsThe process that takes place when iron rusts involves a chemical reaction between iron and oxygen in the presence of water or moisture.

The content that is loaded when iron rusts is solid iron (III) oxide (Fe2O3). It is produced from a reaction between solid iron and gaseous oxygen.

Solid iron reacts with gaseous oxygen to form solid iron(iii) oxide

The balanced chemical equation for the reaction is:

4 Fe(s) + 3 O2(g) + 6 H2O(l) → 4 Fe(OH)3(s)

Here, the solid iron reacts with the gaseous oxygen and water to produce solid iron (III) oxide and hydrogen gas. However, in the presence of excess water, the iron (III) oxide is converted to hydrated iron (III) oxide, also known as rust.

Therefore, the rusting of iron is a slow process that takes place over a period of time and can be prevented by keeping iron dry

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