Wendy has $27 to buy seed for her birdfeeders. Each bag of seed costs $5.
How many bags of seed can she buy? Do not include units in your answer.
Answer here
SUBMIT

Answer:

y-5 = 3/2(x-3)

Step-by-step explanation:

The point slope form of the equation of a line is

y-y1 = m(x-x1)  where m is the slope and (x1,y1) is a point on the line

y-5 = 3/2(x-3)

Greece is different from most other countries in southern Europe because its most popular religion is not Catholicism. Option B

Catholicism refers to the traditions, beliefs, and behaviors of the Catholic Church

Greece is predominantly an Orthodox Christian country, whereas most other countries in southern Europe, such as Italy, Spain, and Portugal, are predominantly Catholic.

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Answer:  2.4

Step-by-step explanation:

a²+b²=c²

3.9+b²=6.3

-3.9      -3.9

_________

b=2.4

check it:

3.9+2.4=6.3

there you go

mark brainly if this helps PLEASE.

Answer:

B

Step-by-step explanation:

The midpoint formula is \((\frac{x1+x2}{2} ,\frac{y1+y2}{2} )\)

Lets plug in our points:

\(\frac{(-6)+(-4)}{2}\)=-5 (the x value)

\(\frac{(-9)+(-9)}{2}\)=-9 (the y value)

Answer:

40x^20

Step-by-step explanation:

Each sequence the x value doubles.

Each sequence the x exponent goes up by 5

Answer:

A

Step-by-step explanation:

Because it is 2,413

Answer:

c

Step-by-step explanation:

Answer:

y=4x-3

Step-by-step explanation:

passes through point (6,21)

has a slope of 4

Answer:Look

Step-by-step explanation: Look and solve its not that hard

Answer:

Option B

Step-by-step explanation:

Let the point O is the origin.

Then the coordinates of the vertices A,B and C will be,

A → (-12, -8)

B → (-8, 0)

C → (-6, -4)

Rule for the dilation of a point (x, y) by scale factor 'k' about the origin is,

(x, y) → (kx, ky)

By this rule, coordinates of the vertices of the image triangle will be,

If k = \(\frac{1}{2}\),

A(-12, -8) → A'(-6, -4)  

B(-8, 0) → B'(-4, 0)

C(-6, -4) → C'(-3, -2)

From the given options,

Option B is the answer.

1. The quadratic function for the Area in terms of x: A(x) = 24x.

2. The cross-sectional area is maximized when the depth of the gutter is 0.

3. The maximum cross-sectional area is square inches 0.

To determine the depth of the gutter that maximizes its cross-sectional area and allows the greatest amount of water to flow, we need to follow a step-by-step process.

1. Write a quadratic function for the area in terms of x:

The cross-sectional area of the gutter can be represented as a rectangle with a width of 24 inches and a depth of x. Therefore, the area, A(x), is given by A(x) = 24x.

2. The cross-sectional area is maximized when the depth of the gutter is:

To find the value of x that maximizes the area, we need to find the vertex of the quadratic function. The vertex of a quadratic function in form f(x) = ax² + bx + c is given by x = -b/(2a). In our case, a = 0 (since there is no x² term), b = 24, and c = 0. Thus, the depth of the gutter that maximizes the area is x = -24/(2 * 0) = 0.

3. The maximum cross-sectional area is square inches:

Substituting the value of x = 0 into the quadratic function A(x) = 24x, we get A(0) = 24 * 0 = 0. Therefore, the maximum cross-sectional area is 0 square inches.

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The mean is approximately 9, the median is 9, the mode is 8, and the range is 7.

To find the mean, we add up all the numbers in the data set and divide by the total number of numbers:

Mean = (7 + 6 + 8 + 12 + 9 + 13 + 8) / 7 = 63 / 7 ≈ 9

So the mean is approximately 9.

To find the median, we need to arrange the numbers in order from smallest to largest:

6, 7, 8, 8, 9, 12, 13

Since there are an odd number of values in the data set, the median is the middle value, which is 9.

To find the mode, we need to look for the value that occurs most frequently in the data set. In this case, 8 occurs twice, which is more than any other value, so the mode is 8.

To find the range, we need to subtract the smallest value from the largest value:

Range = largest value - smallest value = 13 - 6 = 7

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Answer: 16.74

Step-by-step explanation:

Use long multiplication to evaluate.

Answer:

3m + 4c

Step-by-step explanation:

Whenever a word problem says the word earn that means the slope, also known as the rate of change, will be positive. Knowing this you can determine that both the caramel and milk chocolate slopes will be positive. After figuring all that out the only thing left to do is to make the equation. You know you have two slopes, and each slope needs a variable, so you will have to look back at the question. It is given that m represents the milk chocolate and c represents the caramel. Now all you have to do is make the slope the coefficient to the corresponding variable. The milk chocolates are 3 dollars, so the 3 goes in front of the m and the caramel chocolates are 4 dollars, so teh 4 goes in front of the 4. Since both slopes are positive no negatives or minus signs will be used in the equation. Knowing all this information you can now create the expression 3m + 4c.

Answer:

D

Step-by-step explanation:

3m + 4c

Answer:

the answer is 8.ITS 88888888888888888888

64% percent of students have not passed the first terminology exam.

96/150 = 16/25

16/25 = 64%

Answer:

Here is your answer

Suffered:

I drawn it

The statements that are listed above that are not propositions include the following:

A proposition statement is defined as the statement that is either a true statement or false statement but can not be both.

From the given statements,the statement that is a true proposition include the following:

The statement that is a false proposition include the following:

The statement will you be my valentine? is not a proposition but a declarative question that needs to be answered.

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Answer:

put it into slope intercept form. which is y=mx+b

Step-by-step explanation:

On solving the provided question, by the help of BODMAS we can say that - Subtract 22 from both sides is the answer to the given question.

BODMAS and PEDMAS are both names for it in various places. This stands for exponents, parenthesis, division, multiplication, addition, and subtraction. The BODMAS rule states that parentheses must be answered before powers or roots (that is, of), divisions, multiplications, additions, and lastly subtractions. The BODMAS rule states that the degree (52 = 25), parenthesis (2 + 4 = 6), any division or multiplication (3 x 6 (bracket response) = 18), and any addition or subtraction (18 + 25 = 43) come before any other operations.

\(f/3 +22 = 17\)

\(f/3 +22 -22 = 17 -22\) Subtracting the same value from both sides keeps the equation equal.  

Then simplify. The \(+22 and -22= 0\) They "cancel"   \(17-22 = -5\)

\(f/3 = -17 f/3\) is now isolated-- by itself-- in the equation.

If we have to solve  f, the next step we to take is to multiply on the both sides by  3.

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The polar coordinates of (1, -9) are (9.06, -1.47 radians).

To convert from rectangular coordinates to polar coordinates, we can use the following formulas:

r = √(x² + y²)

θ = tan⁻¹(y/x)

where r is the distance from the origin to the point, and θ is the angle between the positive x-axis and the line connecting the origin to the point.

In this case, x = 1 and y = -9. Plugging these values into the formulas, we get:

r = √(1² + (-9)²) = √82 ≈ 9.06

θ = tan⁻¹((-9)/1) ≈ -1.47 radians

Therefore, the polar coordinates of (1, -9) are (9.06, -1.47 radians). The distance from the origin to the point is approximately 9.06 units, and the angle between the positive x-axis and the line connecting the origin to the point is approximately -1.47 radians (or approximately -84.26 degrees).

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The value of the variables in the right triangle are as follows;

A right triangle is a triangle that has one of its angles as 90 degrees.

The side of a right triangle can be found by using trigonometric ratios.

Therefore, let's find the variable length of the right triangle as follows;

sin 30 = opposite / hypotenuse

sin 30 = v / 3√2

1 / 2 = v / 3√2

cross multiply

3√2 = 2v

divide both sides by 2

v = 3√2 / 2

Let's find the variable w.

cos 30 = adjacent  / hypotenuse

cos 30 = w  / 3√2

√3 / 2 = w  / 3√2

cross multiply

√3 × 3√2 = 2w

3√6 = 2w

divide both sides by 2

w = 3√6 / 2

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The rule of (x, y) → (-x, y), which is reflection over y-axis.

Given that, ΔABC maps to triangle ΔA'B'C'.

When you reflect a point across the y-axis, the y-coordinate remains the same, but the x-coordinate is taken to be the additive inverse. The reflection of point (x, y) across the y-axis is (-x, y).

The coordinate points of ΔABC are A(-4, 3), B(-3, -3) and C(1, 2) and the coordinate points of ΔA'B'C' are A'(4, 3), B'(3, -3) and C'(-1, 2).

Here, A(-4, 3) → A'(4, 3), x-coordinate is negated and y-coordinate remains same.

Similarly, B(-3, -3) → B'(3, -3) and C(1, 2) → C'(-1, 2) follows the same pattern.

From this, it is clear that the coordinates of triangle ABC is reflected on y-axis.

Therefore, the rule of (x, y) → (-x, y), which is reflection over y-axis.

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The solution is given below.

A triangle is a polygon with three edges and three vertices. It is one of the basic shapes in geometry. A triangle with vertices A, B, and C is denoted \triangle ABC. In Euclidean geometry, any three points, when non-collinear, determine a unique triangle and simultaneously, a unique plane.

here, we have,

Remember that the Angle-Side-Angle Postulate (ASA) states that if two angles and the included side of one triangle are congruent to two angles and the included side of another triangle, then the two triangles are congruent.

According to this, the correct answer is: given below.

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The price of one adult ticket is approximately $3,977.27, and the price of one child ticket is approximately $4,636.37.

Let's use the system of linear equations to solve this problem.

Let x be the price of an adult ticket and y be the price of a child ticket. We can create two equations based on the information given:

To solve this system of linear equations, we can use either substitution or elimination. In this case, we'll use elimination.

First, multiply the first equation by 17 and the second equation by 9 to make the coefficients of y the same:

Now, subtract the second equation from the first equation:

(170x + 153y) - (126x + 153y) = 1,385,500 - 1,210,500

44x = 175,000

Now, divide both sides of the equation by 44 to solve for x:

x = 175,000 / 44

x ≈ 3,977.27

Now that we have the price of an adult ticket, we can plug the value of x back into either equation to solve for y.

We'll use the first equation:

10(3,977.27) + 9y = 81,500

39,772.70 + 9y = 81,500

Now, subtract 39,772.70 from both sides of the equation:

9y = 41,727.30

Now, divide both sides of the equation by 9 to solve for y:

y = 41,727.30 / 9

y ≈ 4,636.37

So, the price of one adult ticket is approximately $3,977.27, and the price of one child ticket is approximately $4,636.37.

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The question in English is:

In a theater, 10 adult tickets and 9 children's tickets cost $81,500; 17 tickets for children and 14 for adults cost $134,500. Find the price of one adult and one child ticket.

Answer:

30

Step-by-step explanation:

Substitute your numbers in the equation

2(-3)-4((-5)-7)+3(-4)

Distribute

-6-4(-12)-12

Distribute

-6+48-12

Combine like terms

30

Hope this helped!

Answer: 30

Given  a = -3, b = -4, c = -5

2a - 4(c-7) + 3b = 2*a - 4*(c - 7) + 3*b

2 x -3 - 4 x (-5 - 7) + 3 x -4

= -6 + 48 - 12

= 48 - 18 = 30

The value of 2a - 4(c-7) + 3b is 30

2a - 4(c - 7) + 3b = 30.

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so the idea being, we have a system of equations of two variables and 4 equations, each one rendering a line, for this case these aren't equations per se, they're INEquations, so pretty much the function will be the same for an equation but we'll use > or < instead of =, but fairly the function is basically the same, the behaviour differs a bit.

we have a line passing through (-6,0) and (0,8), side one

we have a line passing through the x-axis and -6, namely (-6,0) and the y-axis and -4, namely (0,-4), side two

we have a line passing through (0,-4) and (6,4), side three

now, side four is simply the line connecting one and three.

the intersection of all four lines looks like the one in the picture below, so what are those lines with their shading producing that quadrilateral?

well, we have two points for all four, and that's all we need to get the equation of a line, once we get the equation, with its shading like that in the picture, we'll make it an inequality.

\((\stackrel{x_1}{-6}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{8}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{8}-\stackrel{y1}{0}}}{\underset{\textit{\large run}} {\underset{x_2}{0}-\underset{x_1}{(-6)}}} \implies \cfrac{8 -0}{0 +6} \implies \cfrac{ 8 }{ 6 } \implies \cfrac{4}{3}\)

\(\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{ \cfrac{4}{3}}(x-\stackrel{x_1}{(-6)}) \implies y -0 = \cfrac{4}{3} ( x +6) \\\\\\ y=\cfrac{4}{3}x+8\hspace{5em}\stackrel{\textit{side one} }{\boxed{y < \cfrac{4}{3}x+8}}\)

\(\rule{34em}{0.25pt}\\\\ (\stackrel{x_1}{-6}~,~\stackrel{y_1}{0})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{-4}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{-4}-\stackrel{y1}{0}}}{\underset{\textit{\large run}} {\underset{x_2}{0}-\underset{x_1}{(-6)}}} \implies \cfrac{-4 -0}{0 +6} \implies \cfrac{ -4 }{ 6 } \implies - \cfrac{2}{3}\)

\(\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{0}=\stackrel{m}{- \cfrac{2}{3}}(x-\stackrel{x_1}{(-6)}) \implies y -0 = - \cfrac{2}{3} ( x +6) \\\\\\ y=-\cfrac{2}{3}x-4\hspace{5em}\stackrel{\textit{side two} }{\boxed{y > -\cfrac{2}{3}x-4}} \\\\[-0.35em] \rule{34em}{0.25pt}\)

\(\stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{4}-\stackrel{y1}{(-4)}}}{\underset{\textit{\large run}} {\underset{x_2}{6}-\underset{x_1}{0}}} \implies \cfrac{4 +4}{6 -0} \implies \cfrac{ 8 }{ 6 } \implies \cfrac{4}{3}\)

\(\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{(-4)}=\stackrel{m}{ \cfrac{4}{3}}(x-\stackrel{x_1}{0}) \implies y +4 = \cfrac{4}{3} ( x -0) \\\\\\ y=\cfrac{4}{3}x-4\hspace{5em}\stackrel{ \textit{side three} }{\boxed{y > \cfrac{4}{3}x-4}} \\\\[-0.35em] \rule{34em}{0.25pt}\)

\((\stackrel{x_1}{6}~,~\stackrel{y_1}{4})\qquad (\stackrel{x_2}{0}~,~\stackrel{y_2}{8}) ~\hfill~ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{8}-\stackrel{y1}{4}}}{\underset{\textit{\large run}} {\underset{x_2}{0}-\underset{x_1}{6}}} \implies \cfrac{ 4 }{ -6 } \implies - \cfrac{2}{3}\)

\(\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{4}=\stackrel{m}{- \cfrac{2}{3}}(x-\stackrel{x_1}{6}) \\\\\\ y=-\cfrac{2}{3}x+8\hspace{5em}\stackrel{ \textit{side four} }{\boxed{y < -\cfrac{2}{3}x+8}}\)

now, we can make that quadrilateral a trapezoid by simply moving one point for "side four", say we change the point (0 , 8) and in essence slide it down over the line to  (-3 , 4).  Notice, all we did was slide it down the line of side one, that means the equation for side one never changed and thus its inequality is the same function.

now, with the new points for side for of (-3,4) and (6,4), let's rewrite its inequality

\((\stackrel{x_1}{-3}~,~\stackrel{y_1}{4})\qquad (\stackrel{x_2}{6}~,~\stackrel{y_2}{4}) \\\\\\ \stackrel{slope}{m}\implies \cfrac{\stackrel{\textit{\large rise}} {\stackrel{y_2}{4}-\stackrel{y1}{4}}}{\underset{\textit{\large run}} {\underset{x_2}{6}-\underset{x_1}{(-3)}}} \implies \cfrac{4 -4}{6 +3} \implies \cfrac{ 0 }{ 9 } \implies 0\)

\(\begin{array}{|c|ll} \cline{1-1} \textit{point-slope form}\\ \cline{1-1} \\ y-y_1=m(x-x_1) \\\\ \cline{1-1} \end{array}\implies y-\stackrel{y_1}{4}=\stackrel{m}{ 0}(x-\stackrel{x_1}{(-3)}) \implies y -4 = 0 ( x +3) \\\\\\ y=4\hspace{5em}\stackrel{ \textit{side four changed} }{\boxed{y < 4}}\)