What are the products of the combustion of a hydrocarbon?
a) carbon and oxygen
b)carbon dioxide and water
c)carbon and hydrogen
d) carbon dioxide and hydrogen

Answer: a is gamma b is alpha c is beta

Explanation:

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For the complex [Co(CO)5]x, the unknown charge (z) would be +1 based on the application of the 18 electron rule.

To find the charge (z) of the complex [Co(CO)5]x using the 18 electron rule, we can follow the steps below:

Identify the metal: In this case, the metal is cobalt (Co).

Determine the number of valence electrons of the metal: Cobalt is a transition metal with atomic number 27. In its neutral state, it has 27 electrons. However, in a complex, cobalt typically contributes all of its valence electrons to bonding, which is 9 electrons (2 from the 4s orbital and 7 from the 3d orbital).

Calculate the total number of electrons contributed by ligands: The ligand in this case is carbon monoxide (CO), which is a strong-field ligand. Each CO ligand contributes 2 electrons (one from the carbon lone pair and one from the oxygen lone pair) for a total of 5 ligands × 2 electrons/ligand = 10 electrons.

Add the valence electrons of the metal and the ligands: Cobalt contributes 9 electrons, and the CO ligands contribute 10 electrons, giving a total of 9 + 10 = 19 electrons.

Apply the 18 electron rule: According to the 18 electron rule, most stable transition metal complexes have 18 valence electrons. However, there can be variations depending on the ligands and the metal's oxidation state.

Determine the charge (z): Since the complex [Co(CO)5]x has 19 valence electrons, which is more than the expected 18 electrons, it suggests that the complex has a positive charge to balance the extra electron(s). Therefore, the charge (z) of the complex would be +1.

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Answer:

  0.0135 moles

Explanation:

You want to know the number of moles of gas in a 0.325 L container at 1.00 atm and 293 K.

The ideal gas law is ...

  PV = nRT

Solving for n, the number of moles can be found as ...

  n = PV/(RT)

  n = (101.325 kPa)(0.325 L)/(8.3145 L·kPa/(K·mol)·293 K) ≈ 0.0135 mol

The container can hold 0.0135 moles of gas.

__

Additional comment

1.00 atm = 101.325 kPa

Answerl

see explanation

Explanation:

Question

4.

How many grams would 0 .50 moles of Mg be?

Mg has  an atomic weight of 24 so 1 mole of Mg weighs 24 gms

0.50 moles weigh 0.50 X24gm = 12 gm                

5.

10 moles of Al = ? atoms

1 mole = 6.02 X10^23 atoms ...Avogadros number

10 moles is 10 X6.02X10^23 = 6.02X10^24

6.

How many atoms are in 10 moles of Zinc?

a mole is Avogadros number

same as 10 moles of Al,10 moles of Zn=  6.02 X10^24 atoms

7.

If you had 3,5 x 10 - atoms of carbon how many grams would you have?

8.

Given 100g of C = ? atoms

Carbon has an atomic of 12  100 gm of C are 100/12 = 8.33 moles of C

each mole comtains Avogadros number so there are

8.33 X 6.02 X10^23 = 5.01 X10^24 atoms of C

When a liquid such as acetic acid is stirred it causes the molecules to become far apart, due to which the forces of attraction between molecules is weakened and freezing point is lowered.

Forces of attraction  is a force by which atoms in a molecule  combine. it is basically an attractive force in nature.  It can act between an ion  and an atom as well.It varies for different  states  of matter that is solids, liquids and gases.

The forces of attraction are maximum in solids as  the molecules present in solid are tightly held while it is minimum in gases  as the molecules are far apart . The forces of attraction in liquids is intermediate of solids and gases.

The physical properties such as melting point, boiling point, density  are all dependent on forces of attraction which exists in the substances.

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Answer:

The atomic weight Ar, of M is 64

Explanation:

The formula of the given compound is M(OH)₂

Mr, is the molecular weight of a compound and for the given compound, Mr is equal to 98.

Ar, is the atomic weight of the elements in the compound

The molecular weight, Mrof a compound is the mass of one mole mole of that compound. It can be obtained by summing the atomic masses of all elements in that compound. For elements that has more than one atom in the compound, the atomic weight of that element is multiplied by the number of atoms of the element present in the compound and then the sum of the weight of each element gives the molecular weight of the compound.

Onnthe compound above,the atomic weight of the unknown element M, is to be obtained.

Ar of the other elements inn he compound is given : Ar of O = 16, Ar of H = 1.

Molecular weight of the compound, Mr = 98

Calculating for the Ar of M:

(M × 1) + (16 × 2) + (1 × 2) = 98

M +32 + 2 = 98

M + 34 = 98

M = 98 -34

M = 64

Therefore, the atomic weight Ar, of M is 64

Answer:

C. an entirely new substance with new properties forms as a result of the change

Answer:

. an entirely new substance with new properties forms as a result of the change

Explanation:

Answer:

5.9×10^20=158.875

Explanation:

mass of Cu = 2.501 g × 2.5% Cu/100 = 0.062525 g Cu

mass of Zn = 2.501 g × 97.5%/100 = 2.438475 g Zn

Calculate mol Cu: n = m/M; n = mole = ? mol; m = mass (g) = 0.062525 g Cu; M = molar mass (g/mol) = 63.546 g/mol Cun; Cu = 0.062525 g Cu/63.546 g/mol Cu = 0.00098393 mol Cu

Calculate the number of atoms of Cu:

1 mol atoms = 6.022×10^23 atoms

0.00098393 mol Cu × 6.022×10^23 atoms/mol = 5.9×10^20 atoms Cu to two significant figures

Calculate mol Zn:n = ? mol; m = 2.438475 g Zn; M = 65.39 g/mol Zn; n Zn = 2.438475 g Zn/65.39 g/mol Zn = 0.037291 mol Zn

Total number of atoms in a copper penny:

5.9×10^20 atoms

The number of atoms present in 2.50 grams of copper is equal to 3.93 × 10²¹  atoms.

Avogadro’s number can be described as the number of elementary entities in one mole of any chemical substance or element. Generally, these elementary units can be ions, molecules, atoms, electrons, or protons, according to the type of chemical reaction or reactant and product.

The value of Avogadro’s constant in one mole of a compound is approximately equal to 6.022 × 10²³ mol⁻¹.

Given, the mass of the copper = 2.50 g

the mass of one mole of copper = 63.5 g

The number of Cu atoms in one mole  = 6.022 × 10²³

63.5 g of copper contains Cu atoms = 6.022 × 10²³

2.50 grams of  copper contains Cu atoms = (6.022 × 10²³) × (2.50/63.5)

The number of Cu atoms = 3.93 × 10²¹ atoms

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Answer:

The order of the reaction with respect to D is 2, and the order with respect to G is 1.

Explanation:

To determine the order of a reaction with respect to each reactant, we look at how changing the concentration of a reactant changes the rate of the reaction.

Looking at the initial concentrations and rates for D in experiments 1 and 2, when the concentration of D is doubled (from 0.025 to 0.050), the rate of reaction quadruples (from 0.00480 to 0.0192). This indicates that the order of the reaction with respect to D is 2, because the rate of reaction changes by the square of the change in concentration.

Next, we look at the initial concentrations and rates for G in experiments 3 and 4. In these experiments, when the concentration of G is quadrupled (from 0.020 to 0.080), the rate of the reaction also quadruples (from 0.0986 to 0.394). This indicates that the order of the reaction with respect to G is 1, because the rate of reaction changes directly with the change in concentration.

So, the order of the reaction with respect to D is 2, and the order with respect to G is 1.

When hydrochloric acid is added to a solution containing \(Ag^{+}\) ions, silver chloride (AgCl) precipitates.

Therefore, the correct option is ( b ) AgCl precipitates.

The precipitation occurs due to the reaction between the chloride ions (\(Cl^{-}\)) from the hydrochloric acid and the silver ions (\(Ag^{+}\)) in solution, which results in the formation of solid silver chloride. This reaction can be represented by the following equation:

\(Ag^{+}\)(aq) + \(Cl^{-}\) (aq) → AgCl (s)

The addition of HCl to the solution provides \(Cl^{-}\) ions, which react with the \(Ag^{+}\) ions to form a sparingly soluble precipitate of AgCl. The precipitate can be filtered and weighed to determine the amount of \(Ag^{+}\) ions in the original solution.

The reaction is a classic example of a precipitation reaction, which is a type of double displacement reaction where two soluble ionic compounds react to form an insoluble product.

It is important to note that while the addition of HCl does increase the concentration of hydrogen ions (\(H^{+}\)) in the solution, \(Ag^{+}\) ions do not complex with hydrogen in this reaction. Instead, the reaction between \(Ag^{+}\)ions and \(Cl^{-}\) ions produces solid AgCl precipitate, which can be separated from the solution by filtration.

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The equilibrium conversion to hydrogen decreases when steam is added to the feed and everything else kept the same for the following reaction: C₄H₈ < == > C₄H₆ + H₂.

Conversion is defined as the transformation of a compound into another, as a result of a chemical reaction. Equilibrium conversion is the extent of conversion when a chemical reaction proceeds to equilibrium. For the given reaction:C4H8 < == > C₄H₆ +H₂

The conversion of C₄H₈ to C₄H₆ and H₂ is decreased when steam is added to the feed and everything else kept the same. The decrease in conversion is due to the Le Chatelier's principle. It states that when a system in chemical equilibrium is subjected to a change in temperature, pressure, or concentration of reactants or products, the system shifts in equilibrium position to counteract the effect of the change.

As per the principle, the system will counteract the increase in the concentration of water molecules by moving in the direction that reduces the concentration of water molecules, that is, backward.

This causes the reverse reaction to occur more and reduces the conversion of C₄H₈ to  C₄H₆ and H₂. Hence, the equilibrium conversion to hydrogen decreases when steam is added to the feed and everything else kept the same.

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Among the elements Rb (rubidium), Na (sodium), K (potassium), Cs (cesium), and Li (lithium), the one that would give the least vigorous reaction when dropped in water is lithium (Li).

Lithium is the lightest metal in the alkali metal group and is known to exhibit relatively mild reactivity when exposed to water. When a small piece of lithium is dropped into water, it reacts slowly, producing hydrogen gas (H2) and lithium hydroxide (LiOH). The reaction is exothermic, but compared to the other alkali metals, such as sodium and potassium, the reaction of lithium with water is less vigorous.

Sodium, potassium, rubidium, and cesium, on the other hand, are more reactive in water. They undergo rapid and vigorous reactions, often accompanied by the release of large amounts of heat and the formation of hydrogen gas. The reactivity of these metals increases as you move down the group, with cesium being the most reactive among them.

The reactivity of alkali metals with water can be attributed to their low ionization energy and the strong desire to lose their outermost electron to attain a stable electronic configuration. As the atomic size increases down the group, the outer electron becomes farther away from the nucleus, making it easier to remove.

In summary, among the given options, lithium (Li) would give the least vigorous reaction when dropped in water. Its relatively lower reactivity compared to the other alkali metals makes it a suitable choice for certain applications where a less violent reaction is desired.

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Explanation:

it shows covalent bonds

The type of bond the diagram shows is covalent bond. As shown the sharing of electrons in the diagram.

Bonds are defined as any of the interactions that lead to atoms joining together to form molecules, ions, crystals, and other stable species that make up the familiar materials found in everyday life. The ability to build molecules is made possible by a chemical bond, which is a strong attraction between atoms, ions, or molecules. Chemical bonds that hold molecules together also form temporary connections vital for life.

Covalent bond are defined as a type of chemical link where atoms share electrons to create electron pairs. Low melting and boiling temperatures, low vaporization heat, low water solubility, and poor conductivity are four characteristics of covalent compounds.

Thus, the type of bond the diagram shows is covalent bond. As shown the sharing of electrons in the diagram.

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Answer:

Chemical reactions occur when chemical bonds between atoms are formed or broken. The substances that go into a chemical reaction are called the reactants, and the substances produced at the end of the reaction are known as the products.

Explanation:

hope it helps

Answer:

1.85 × 10⁻⁶

Explanation:

0.0003 ÷ 162 = 1.851851852 × 10⁻⁶ ⇒ 1.85 × 10⁻⁶

Hope that helps.

The significant figure in the answer should be one here, since the number 0.0003 contains only one significant figure. Hence, the answer is 2 × 10⁻⁶.

Significant figures are digits in a quantity with certain values along with some uncertain digits. The counting of significant figures of a number should follow some rules.

The zeros after the decimal point which is not following a nonzero number are not significant. Therefore, there is only one significant figure in the number 0.0003.

For any arithmetic operation, the number of significant figures in the result should be equal to the one in operation that is with least significant figures.

Here.  162 have 3 significant figures. Therefore, the result should contain only one significant figure.

0.0003 /162 = 1.85  × 10⁻⁶.

Then the result with correct significant figures is rounded to 2 × 10⁻⁶.

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A statement that stores the uppercase equivalent of the string referenced by the city variable is as follows:

uppercity = city.toUpperCase();

```

To store the uppercase equivalent of the string referenced by the variable "city" in the variable "uppercity," you can use the "toUpperCase()" method in Java. In the given code snippet, the "toUpperCase()" method is applied to the "city" variable and the resulting uppercase string is assigned to the "uppercity" variable.

The "toUpperCase()" method is a built-in function in Java that converts all the characters in a string to uppercase. It returns a new string with all uppercase characters, while leaving the original string unchanged. By invoking this method on the "city" variable, we ensure that the resulting uppercase string is assigned to the "uppercity" variable.

Using the "toUpperCase()" method is a convenient and straightforward way to convert a string to its uppercase form. It eliminates the need for manual conversion and provides a more concise and readable code.

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Answer:

704 meters

Explanation:

1 Kilometer = 1000 meters

0.704 km * 100m/ 1 km = 704 m

1) The reaction is exothermic and heat is a product

2) The color would turn to pink.

Let us recall that an endothermic reaction is one in which the increase in the temperature of the system would drive the forward reaction. This implies that the equilibrium would shift to the right when the set up is heated. Since the color of the solution changes to blue when heated hence the reaction is exothermic.

If you removed heat by placing the solution in the ice bath, we can see that we have removed the heat thus we expect that the reverse reaction would take place and the color would change to pink.

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The molecular formula of the given compound is \($\mathrm{H}_{2} \mathrm{CO}_{3}$\) also known as  Carbonic acid.

The simplest whole-number ratio of the various atoms in a compound is represented by an empirical formula.

The precise number of various atom types present in a compound's molecule is indicated by the molecular formula.

Given that,

H = 3.3%

C = 19.3%

O = 77.4%

No. of moles of H = 3.3/1

No. of moles of H = 3.3

No. of moles of C = 19.3 / 12

No. of moles of C = 1.60

No. of moles of O = 77.4/16

No. of moles of O = 4.83

Therefore, the ratio of the atoms of C, H and O = 3.3 : 1.60 : 4.83

Divide by smallest value which you get =3.3 / 1.60 : 1.60 / 1.60 : 4.83 / 1.60

The ratio of the atoms of C, H and O = 2 : 1 : 3

So, the empirical formula is \($\mathrm{H}_{2} \mathrm{CO}_{2}$\)

Let the molecular formula is \($\left(\mathrm{H}_{2} \mathrm{CO}_{3}\right) \mathrm{n}$\)

Then, molar mass \($=(2 \times 1+1 \times 12+3 \times 16) n\\\)

Molar mass = 62n

As the question, 62 n = 60

n = 0.96 or n = 1 (rounded off to nearest ones)

So, the molecular formula is \($\left(\mathrm{H}_{2} \mathrm{CO}_{3}\right) 1=\mathrm{H}_{2} \mathrm{CO}_{3}$\) i.e., the compound is Carbonic acid.

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The iso paraffins have the same hydrogen to carbon ratios as the normal paraffins because to prevent cooking.

What is paraffin?

A complex mixture of hydrocarbons that is derived specifically from the distillates of wood, coal, petroleum, or shale oil and utilized mostly in coating and sealing, candles, rubber compounding, pharmaceuticals, and cosmetics. It is a waxy, crystalline, combustible substance.

What is hydrogen?

The most fundamental member of the chemical element family is hydrogen (H), a colorless, odorless, tasteless, combustible gaseous material.

Therefore, the iso paraffins have the same hydrogen to carbon ratios as the normal paraffins because to prevent cooking.

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Answer:

24000 J = 24 kJ

Explanation:

Using the formula q = mcΔT (energy required to heat an object)

q = energy required

m = mass (70.0 g)

c = specific heat capacity (4.179 J *°C⁻¹*g⁻¹)

ΔT = change in temperature (100-18 = 82°C)

∴q = 70.0g * 4.179 J *°C⁻¹*g⁻¹ * 82°C ( symbols g, °C⁻¹,g⁻¹ and °C cancel out everything is multiplied together)

∴q = 24000 J = 24kJ

Answer:

d:slate

Explanation:

Answer:

Divergent

20 words

Answer:

divergent...........................

Answer:

B- why or how because any scientist deals with matter it's relationships ,properties and its composition which can be inferred from the questions why and how

Answer:

14660.75 kJ.

Explanation:

We are given from the question above that the pressure inside is represented by this equation:

P = Po + C(1-(D1/D))(D1/D).

Thus, P = 100 + C (1 - 1/4) (1/4). Therefore, P  which is = 400 is;

400 = 100 + C (1 - 1/4) (1/4).

Hence, C = 1600. And the equation can be written as P = 100 + 1600 (1 - (D1/D))(D1/D).

The work done during the entire process, w = (work done during the process 1 to 2) + (work done duringbthe process 2 to 3 ).

Therefore, work done during the process 1 to 2 = P(V2 + V1) = 100( π/6 - 0).

{NB: V2 is gotten from π/6 × D^3. Where D^3 = 1. }

Hence, work done during the process 1 to 2 = 52.36 kJ.

So, the work done duringbthe process 2 to 3 ) is going to be the integration of PdV. Where P = 100 + 1600 (1 - (D1/D))(D1/D) and dV = π/2 D^2 dD. Taking the upper and the lower limit as 4 and 1 respectively.

After the integration (kindly check attached picture for the process) the work done duringbthe process 2 to 3  = 14.61 × 10^3 kJ.  

Therefore, The work done during the entire process, w = (work done during the process 1 to 2) + (work done duringbthe process 2 to 3 ).

The work done during the entire process, w = 52.36 kJ + 14.61 × 10^3 kJ.   = 14660.75 kJ.

The question requires us to calculate the molecular mass of a gas, given its density (1.2 g/L) and conditions of pressure (745 torr) and temperature (20°C).

Density is defined as the mass of a compound over its volume. From this definition, we can calculate the molecular mass of the gas knowing the density, as given by the question, and the volume of 1 mol of the gas.

We can calculate the volume of a gas considering the equation of Ideal Gases:

where P is the pressure of the gas, V is its volume, n is the number of moles, R is the constant of gases and T is the temperature.

Note that the constant of gases R was given in units of L.atm/K.mol, while the pressure and temperature were given in Torr and °C, respectively. Thus we need to convert these values to the appropriate units.

Knowing that 1 Torr corresponds to 0.00131579 atm:

1 Torr --------------------- 0.00131579 atm

745 Torr ---------------- x

Solving for x, we have that 745 Torr corresponds to 0.980 atm.

To convert the temperature from Celsius degrees to Kelvin, we must add 273.15:

T = 20 + 273.15 K = 293.15 K

Therefore, the pressure and temperature we'll use in our calculation are 0.980 atm and 293.15 K. Also, since we are calculating the molecular mass, we'll consider 1 mol of gas.

Rearranging the equation of ideal gases to calculate the volume and applying the values to the equation, we'll have:

Therefore, the volume of 1 mol of the gas under the conditions given is 24.6L.

Next, we'll use this value to calculate the molecular mass using the density given by the question:

Therefore, the gas given by the question presents 29.5g per mol.

A mixture of two miscible liquids, such as ethanol and water, has the number of phases equal to one (option b). This is because the two liquids are fully soluble in each other, forming a homogenous mixture.

When miscible liquids are mixed, the resulting solution becomes a single phase, as the molecules of each liquid are uniformly distributed throughout the solution. In the context of your question, pressure plays a role in influencing the vapor pressure of the mixture. When the pressure is decreased, it affects the boiling points of the components in the mixture, such as ethanol and water. Ethanol and water each have different boiling points, and by reducing the pressure, the boiling point of each component is lowered. This can cause the components to evaporate at different rates, but it does not change the fact that the mixture remains a single-phase system.Regarding the water system having three phases - ice, water, and vapor - the number of components in the system is one (option a). Water is the single component that exists in all three phases, making it the only component in the system. Whether it is in the solid form (ice), liquid form (water), or gaseous form (vapor), it remains as H2O, the same molecular substance.

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When pressure decreased, liquid solubility decreases and divides into two phases. A water system is a three-component system having different properties and compositions.

Decreasing pressure can affect the number of phases in a mixture of two miscible liquids such as ethanol and water. The number of phases in this mixture depends on the temperature and composition of the solution. At room temperature and normal pressure, ethanol and water form a homogeneous solution with one phase. However, if the pressure is decreased, the solubility of the liquids decreases and the mixture can separate into two phases. For the second question, Ice and liquid water have the same chemical composition, but they are in different states of matter and have different densities. Vapor is a separate phase because it consists of water molecules in the gas phase and has different properties than liquid or solid water. Therefore, the answer is (c) three.

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The pH of the solution at the equivalence point is 7. (after titration).

Equivalence point in a titration: When titrating an acid and a base, the equivalence point is the point where the stoichiometric amounts of the acid and base have reacted. This means that all the acid present in the solution has been neutralized by the base. Likewise, all the base present in the solution has been neutralized by the acid.The pH at the equivalence point: The pH at the equivalence point depends on the nature of the acid and the base. For example, if a strong acid and a strong base are titrated, the pH at the equivalence point is 7.00. On the other hand, if a strong acid and a weak base are titrated, the pH at the equivalence point is less than 7.00. Similarly, if a weak acid and a strong base are titrated, the pH at the equivalence point is greater than 7.00. The pH at the equivalence point can be determined using a few formulas. To determine the pH of the solution at the equivalence point when a 100.0 mL sample of 0.18 M HClO4 is titrated with 0.27 M LiOH,

Steps: 1. Calculate the moles of HClO4 and LiOH at the equivalence point: Moles of HClO4 = volume (L) x concentration (M) = 0.1 L x 0.18 mol/L = 0.018 mol.  Moles of LiOH = volume (L) x concentration (M) = 0.06667 L x 0.27 mol/L = 0.018 mol

Step: 2. Since the moles of HClO4 and LiOH are equal at the equivalence point, the reaction between them is complete. The product of the reaction is water and a salt (LiClO4). The salt will not affect the pH, as Li+ and ClO4- ions do not hydrolyze in water.

Step: 3. At the equivalence point, the pH is determined by the concentration of H2O. Since water's pH is 7 at 25°C, the pH of the solution at the equivalence point is 7. (after titration).

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