What experimental evidence led to the development of this atomic model from the one before it?

A few of the positive particles aimed at a gold foil seemed to bounce back off of the thin metallic foil.
Experiments with water vapor showed that elements combine in specific proportions.
Equations were used to identify regions around the nucleus where electrons would likely be.
Cathode rays were bent in the same way whenever a magnet was brought near them.

Answers

Answer 1

A few of the positive particles aimed at a gold foil seemed to bounce back off of the thin metallic foil. so, the correct answer is option A.

What is the Rutherford experiment?

Rutherford performed an experiment in which alpha particles are bombarded on the gold foil.

Some of the particles bounced back which indicates that there are heavy particles present in the center of an atom.

Most alpha particles pass through the atom which indicates that there is a lot of empty space in an atom.

A few of the positive particles aimed at a gold foil seemed to bounce back off of the thin metallic foil. so, the correct answer is option A.

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Related Questions

a large flat conducting plate has a surface charge density on one of its surfaces. what is the magnitude of the electric field this plate

Answers

The magnitude of the electric field of a large flat conducting plate with a surface charge density is determined by the equation E=σ/ε₀, where σ is the surface charge density and ε₀ is the permittivity of free space. In this equation, the electric field is a scalar quantity, and its magnitude is measured in volts per meter (V/m).

The electric field of a large flat conducting plate is an example of a uniform electric field. This means that the field is constant throughout the entire surface of the plate. This uniform electric field is generated by the charge density that is present on the plate.

The magnitude of the electric field of a large flat conducting plate is directly proportional to the surface charge density. This means that if the surface charge density of the plate is increased, the electric field will also increase. Similarly, if the surface charge density is decreased, the electric field will also decrease.

The electric field of a large flat conducting plate also depends on the permittivity of free space. The permittivity of free space is a constant value, which means that the electric field will always remain the same, regardless of the surface charge density of the plate.

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Which would have more matter: a 1 cm cube of lead or a 1 cm
cube of rubber?

Answers

Answer: 1CM CUBE OF LEAD

Explanation:

at what time of the day is the demand of electricity highest?​

Answers

Answer:

morning hours

Explanation:

Light passes from air into water at an angle of 40.0° to the normal. What is the angle of refraction? Please show all work. (ref: p.492-499)

Answers

The angle of refraction of the light is 28.88°

What is refractive index of light?

Refractive index, also called index of refraction, measure of the bending of a ray of light when passing from one medium into another. If i is the angle of incidence of a ray in vacuum (angle between the incoming ray and the perpendicular to the surface of a medium, called the normal) and r is the angle of refraction (angle between the ray in the medium and the normal), the refractive index n is defined as the ratio of the sine of the angle of incidence to the sine of the angle of refraction; i.e., n = sin i / sin r.

The refractive index of light from air to water is 1.33

Therefore n = sin i / sin r.

1.33= sin40/sinr

sinr= sin40/1.33

sinr= 0.643/1.33

sinr = 0.483

r= sin^-1(0.483)

r= 28.88°

therefore the angle of refraction is 28.88°

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The angle of refraction, given that the light passes from air into water at an angle of 40.0° to the normal, is 29°

How do I determine the angle of refraction?

Snell's law states as follow:

index of refraction (n) = Sine i / Sine r

n = Sine i / Sine r

Where

i is the angle of incidence r is the angle of refraction

With the above formula, we can obtain the angle of refraction as follow:

Angle of incidence (i) = 40.0°Index of refraction of water (n) = 1.33Angle of refraction (r) =?

n = Sine i / Sine r

1.33 = Sine 40 / Sine r

Cross multiply

1.33 × Sine r = Sine 40

Divide both sides by 1.33

Sine r = Sine 40 / 1.33

Sine r = 0.4833

Take the inverse of Sine

r = Sine⁻¹ 0.4833

r = 29°

Thus, the angle of refraction is 29 °

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Determine the Relative Humidity, Dew Point, and Lifting Condensation Level: 1. The temperature is 30∘F and it contains 3.5 g/kg of water vapor. 2. The temperature is 50∘F and it contains 5.70 g/kg of water vapor. 3. The temperature is 70∘F and it contains 3.5 g/kg of water vapor. 4. The temperature is 80∘F and it contains 5.60 g/kg of water vapor. 5. The temperature is 80∘F and it contains 11.56 g/kg of water vapor. 6. The temperature is 30∘F and the mixing ratio is 3.5. 7. The temperature is 70∘F and the mixing ratio is 8.32. 8. The temperature is 70∘F and the mixing ratio is 3.66. 9. The temperature is 80∘F and the mixing ratio is 17.59. 10. The temperature is 50∘F and the mixing ratio is 6.54.

Answers

To determine the relative humidity, dew point, and lifting condensation level (LCL) for the given conditions, we can use the provided temperature and water vapor values.

Here are the calculations for each scenario:

1. Temperature: 30°F, Water Vapor: 3.5 g/kg   - Relative Humidity (RH): N/A (Need the actual vapor pressure or saturation vapor pressure)

  - Dew Point: N/A (Need the actual vapor pressure or saturation vapor pressure)   - LCL: N/A (Need the temperature and dew point)

2. Temperature: 50°F, Water Vapor: 5.70 g/kg

  - Relative Humidity (RH): N/A (Need the actual vapor pressure or saturation vapor pressure)   - Dew Point: N/A (Need the actual vapor pressure or saturation vapor pressure)

  - LCL: N/A (Need the temperature and dew point)

3. Temperature: 70°F, Water Vapor: 3.5 g/kg   - Relative Humidity (RH): N/A (Need the actual vapor pressure or saturation vapor pressure)

  - Dew Point: N/A (Need the actual vapor pressure or saturation vapor pressure)   - LCL: N/A (Need the temperature and dew point)

4. Temperature: 80°F, Water Vapor: 5.60 g/kg

  - Relative Humidity (RH): N/A (Need the actual vapor pressure or saturation vapor pressure)   - Dew Point: N/A (Need the actual vapor pressure or saturation vapor pressure)

  - LCL: N/A (Need the temperature and dew point)

5. Temperature: 80°F, Water Vapor: 11.56 g/kg   - Relative Humidity (RH): N/A (Need the actual vapor pressure or saturation vapor pressure)

  - Dew Point: N/A (Need the actual vapor pressure or saturation vapor pressure)   - LCL: N/A (Need the temperature and dew point)

6. Temperature: 30°F, Mixing Ratio: 3.5

  - Relative Humidity (RH): N/A (Need the actual vapor pressure or saturation vapor pressure)   - Dew Point: N/A (Need the actual vapor pressure or saturation vapor pressure)

  - LCL: N/A (Need the temperature and dew point)

7. Temperature: 70°F, Mixing Ratio: 8.32   - Relative Humidity (RH): N/A (Need the actual vapor pressure or saturation vapor pressure)

  - Dew Point: N/A (Need the actual vapor pressure or saturation vapor pressure)   - LCL: N/A (Need the temperature and dew point)

8. Temperature: 70°F, Mixing Ratio: 3.66

  - Relative Humidity (RH): N/A (Need the actual vapor pressure or saturation vapor pressure)   - Dew Point: N/A (Need the actual vapor pressure or saturation vapor pressure)

  - LCL: N/A (Need the temperature and dew point)

9. Temperature: 80°F, Mixing Ratio: 17.59   - Relative Humidity (RH): N/A (Need the actual vapor pressure or saturation vapor pressure)

  - Dew Point: N/A (Need the actual vapor pressure or saturation vapor pressure)   - LCL: N/A (Need the temperature and dew point)

10. Temperature: 50°F, Mixing Ratio: 6.54

   - Relative Humidity (RH): N/A (Need the actual vapor pressure or saturation vapor pressure)    - Dew Point: N/A (Need the actual vapor pressure or saturation vapor pressure)

   - LCL: N/A (Need the temperature and dew point)

To calculate the relative humidity, dew point, and LCL, we require

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LaCie kicks a football from the ground level at a velocity of 13.9 m/s and at angle of 25 degrees to the ground. You have determined that the football would travel 15.1 m before landing. How would this value change if the football was kicked at an angle of 35 degrees? Complete all equations without rounding and then round to the nearest tenth at the end

Answers

The ball will travel more distance when projected or kicked at an angle of 35 degrees.

What is the range of projectile?

The range of the projectile or the horizontal distance traveled by the ball is calculated by applying the following kinematic equation as shown below.

R = ( u² sin (2θ ) ) / g

where;

u is the initial velocity of the ballg is the acceleration due to gravity

The horizontal distance traveled by the ball when projected at 35 degrees is calculated as;

R = ( 13.9² x sin ( 2 x 35 ) ) / ( 9.8 )

R = 18.53 m

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A football coach walks 24 meters eastward, then 12 meters westward, then 36 meters eastward, and finally 22 meters westward. What is the magnitude and direction of the displacement?

Answers

Answer:

Magnitude = 26 m

Direction = eastward

Explanation:

Given that a football coach walks 24 meters eastward, then 12 meters westward, then 36 meters eastward, and finally 22 meters westward. What is the magnitude and direction of the displacement?

Let eastward be positive and westward be negative.

Magnitude = 24 - 12 + 36 - 22

Magnitude = 60 - 34

Magnitude = 26

Since the answer is positive, the direction will be eastward.

Therefore,

Magnitude = 26 m

Direction = eastward

Sterol has four connecting rings made of which of the following elements?

Answers

Sterol has four connecting rings made primarily of carbon (C) and hydrogen (H) atoms.

Sterols are a class of lipids that include cholesterol, which is a vital component of cell membranes in animals. The structure of sterols consists of a core composed of four interconnected carbon rings, known as the steroid nucleus. Each carbon atom in the rings is bonded to hydrogen atoms, forming a stable and rigid structure. The specific arrangement and functional groups attached to the carbon rings give rise to the various sterols found in living organisms, playing essential roles in cellular function, hormone synthesis, and other biological processes.

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Explain why scientific methods are said to involve critical thinking

Answers

According to the research, scientific methods are said to involve critical thinking since it seeks to establish the explanation of a phenomenon based on what is previously known, analyzing and evaluating the information.

What is critical thinking?

It is the ability to collect that consists of analyzing and evaluating the consistency of existing information regarding a given topic or issue, trying to clarify the veracity of said information and reach a justified idea in this regard, ignoring possible external biases.

Scientific methods are based on concrete and verifiable facts, and not on beliefs or opinions, being the responsibility of the scientist or researcher to maintain their critical thinking in the research, that is, the constant questioning of information and conclusions.

Therefore, we can conclude that according to the research, scientific methods are said to involve critical thinking since it seeks to establish the explanation of a phenomenon based on what is previously known, analyzing and evaluating the information.

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describe why the bottom of a pot is painted black and the interior is painted silver​

Answers

Explanation:

The bottom part of the cooking utensil or pan is painted black. The reason is that the black surface absorbs more heat and so the contents of utensil or pan get cooked rapidly if its bottom part is painted black.

Hence, by having black bottom and shiny inner surface we can utilise the maximum heat given to the utensil.

___________ force is a supportive force that surfaces exert in order to prevent solid objects from passing through one another.

A. Contact
B. Regular
C. Normal
D. Field

Answers

the answer is normal force
The Answer is-

Normal force

A car traveling at 40 m/s runs out of gas while traveling up a 6.0 degree slope. How far will it coast before starting to roll back down?

Answers

The car will coast for approximately 2087 meters before starting to roll back down the slope.

What is the distance the car will coast up a 6.0 degree slope at 40 m/s before starting to roll back down?

To solve this problem, we need to find the distance the car will travel up the slope before coming to rest. This distance is equal to the distance the car will coast down the slope before starting to roll back.

We can use the conservation of energy principle to find the initial potential energy of the car, which will be converted to kinetic energy as the car coasts up the slope. At the point where the car comes to rest, all of the initial potential energy will have been converted to gravitational potential energy.

The initial potential energy of the car can be found using the formula:

PE = mgh

where m is the mass of the car, g is the acceleration due to gravity, and h is the height the car has traveled up the slope.

Since the car comes to rest at the top of the slope, all of the initial potential energy is converted to gravitational potential energy at this point. The gravitational potential energy can be found using the formula:

PE = mgh

where m is the mass of the car, g is the acceleration due to gravity, and h is the height the car has traveled up the slope.

Since the gravitational potential energy is equal to the initial potential energy, we can set the two formulas equal to each other:

\(mgh = 1/2 mv^2\)

where v is the final velocity of the car at the point where it comes to rest.

We can solve for h, the height the car has traveled up the slope:

\(h = 1/2 v^2/g\)

We can then use the formula for the distance traveled up the slope to find the distance the car will coast down the slope before starting to roll back:

d = h/sin(theta)

where theta is the angle of the slope.

Plugging in the values given in the problem, we get:

\(h = 1/2 (40 sin(6))^2 / 9.81 = 215.5 m\)

\(d = 215.5 / sin(6) = 2087 m\)

Therefore, the car will coast for approximately 2087 meters before starting to roll back down the slope.

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The distance it will coast before starting to roll back down is approximately 776.55 meters up the slope.

To solve this problem, we will use the concepts of kinetic energy, potential energy, and the conservation of mechanical energy. Initially, the car has kinetic energy (KE) due to its velocity (40 m/s) and no potential energy (PE) since we assume it starts at the bottom of the slope. When the car comes to a stop, all its kinetic energy is converted to potential energy.

First, we need to find the kinetic energy:
KE = (1/2) * m * v²
where m is the mass of the car and v is its velocity (40 m/s).

Next, we'll find the potential energy when the car comes to a stop:
PE = m * g * h
where g is the acceleration due to gravity (9.81 m/s²) and h is the height the car reaches on the slope.

Since the mechanical energy is conserved, KE = PE. We can set up the equation:
(1/2) * m * v² = m * g * h

The mass (m) can be canceled from both sides, leaving:
(1/2) * v² = g * h

Now we can find the height (h):
h = (1/2) * v² / g = (1/2) * (40 m/s)² / 9.81 m/s² ≈ 81.46 m

To find the distance the car traveled along the slope (d), we'll use the sine of the angle (6.0 degrees):
sin(6.0) = h / d

Solving for d:
d = h / sin(6.0) ≈ 81.46 m / sin(6.0) ≈ 776.55 m

The car will coast approximately 776.55 meters up the slope before starting to roll back down.

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(a) What is the average kinetic energy in joules of hydrogen atoms on the 5500ºC surface of the Sun? (b) What is the average kinetic energy of helium atoms in a region of the solar corona where the temperature is 6.00×105 K ?

Answers

(a) Average kinetic energy of hydrogen atoms on the 5500ºC surface of the Sun is: 1.57 × 10^−21 J.

(b) Average kinetic energy of helium atoms in a region of the solar corona where the temperature is 6.00×10^5 K is: 1.05 × 10^−19 J.

Explanation to the above given short answers are written below,

(a) To calculate the average kinetic energy of hydrogen atoms, we can use the formula,
KE = (3/2) kT,
where k is the Boltzmann constant and
T is the temperature in Kelvin. First,

we convert the temperature of the Sun's surface from Celsius to Kelvin by adding 273.15.
So the temperature is 5773 K.

Plugging in the values, we get
KE = (3/2) × 1.38 × 10^-23 J/K × 5773 K = 1.57 × 10^−21 J.

(b) The formula KE = (3/2) kT can also be used to calculate the average kinetic energy of helium atoms.
We convert the temperature in Kelvin to match the units of the Boltzmann constant.
So, T = 6.00×10^5 K = 6.00×10^8 K.

Plugging in the values, we get KE = (3/2) × 1.38 × 10^-23 J/K × 6.00×10^8 K = 1.05 × 10^−19 J.

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A wave has a wavelength of 4. 9 m and a velocity of 9. 8 m/s. The medium through which this wave is traveling is then heated so that the velocity is doubled. If the frequency remains constant, what is the wavelength of the heated wave? 2. 5 m 9. 8 m 14. 7 m 19. 6 m.

Answers

The wavelength of a wave is obtained by taking the ratio of wave speed and frequency.

The wavelength of the heated wave is 9.8 m. Hence, option (b) is correct.

What is frequency of a wave?

The number of oscillations completed by a wave in one second is known as the frequency of a wave. It is expressed as the ratio of the velocity of the wave to its wavelength.

Given data-

The wavelength of the wave is, \(\lambda = 4.9 \;\rm m\).

The velocity of the wave is, v = 9.8 m/s.

The mathematical expression for the frequency of the wave is,

\(f = \dfrac{v}{\lambda}\)

Solving as,

\(f = \dfrac{9.9}{4.9}\\\\f =2 \;\rm Hz\)

Now, with constant frequency and the double magnitude of velocity (v' = 2 × 9.8 = 19.6 m/s). The wavelength of the heated wave is calculated as,

\(f = \dfrac{v'}{\lambda'}\)

here,

\(\lambda'\) is the wavelength of the heated wave.

Solving as,

\(2 = \dfrac{19.6}{\lambda'}\\\\\lambda' = \dfrac{19.6}{2}\\\\\lambda' = 9.8 \;\rm m\)

Thus, we can conclude that the wavelength of the heated wave is 9.8 m. Hence, option (b) is correct.

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Water is heated by hot air in a double-pipe heat exchanger L = 10 m, with water flowing in the inner tube (Di = 3 cm), and air flowing in the tube annulus (Do = 5.5 cm). The flow rate of the water is 1.2 kg/s and that of the air is 0.5 kg/s. The water enters at 40°C while the air enters at 280°C. If the air-side convection coefficient hair = 1000 W/m2·K, determine the following:
(a) The outlet temperatures of both the air and the water if the heat exchanger is operating in a parallel-flow arrangement.
(b) The outlet temperatures of both the air and the water if the heat exchanger is operating in a counter-flow arrangement.
Assume fully-developed flow conditions. Evaluate the fluid properties at the inlet temperatures.

Answers

(a) In a parallel-flow arrangement, the outlet temperature of the water and the air can be determined using the energy balance equation. The heat transfer rate between the water and the air is equal to the product of the water mass flow rate, specific heat capacity of water, and the change in temperature of the water:

Similarly, the heat transfer rate between the air and the water is equal to the product of the air mass flow rate, specific heat capacity of air, and the change in temperature of the air:

Since the heat exchanger is operating under fully-developed flow conditions, the outlet temperature of the water and the air can be found by equating the heat transfer rates:

By substituting the given values, including the specific heat capacities of water and air, and solving the equations, the outlet temperatures of the air and water can be calculated.

(b) In a counter-flow arrangement, the outlet temperatures of the air and water can be determined using a similar energy balance equation. However, in this case, the change in temperature of the air is taken as the difference between the outlet and inlet temperatures of the air:

Again, by equating the heat transfer rates, substituting the given values, and solving the equations, the outlet temperatures of the air and water in a counter-flow arrangement can be calculated.

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The acceleration due to gravity on Pluto is less than that on the Earth. The mass of a person on Pluto will be

Answers

The exact same.  gravity has no effect on mass.

Answer:

The acceleration due to gravity on Pluto is less than that on the Earth. The mass of a person on Pluto will be Less

Explanation:

If € ₁ 4. 0 V. & 2 = 12. 0 V, R₁ = 40, R₂ = 1202, C-3 μF, Q = 18 μC, and I = 2. 5 A, what is the potential difference V, - V? b- 5. 0 V O-5. 0 V 30 V O-30 V & - 1. ³ 30

Answers

According to the given statement , the potential difference V across the resistor R is 3105 V.

To find the potential difference V, we can use Ohm's Law and the formula for the potential difference across a capacitor.

First, let's calculate the current flowing through the circuit. We are given that I = 2.5 A.

Next, we can calculate the total resistance in the circuit using the formula R = R₁ + R₂. Given that R₁ = 40 Ω and R₂ = 1202 Ω, we can calculate the total resistance:

R = 40 Ω + 1202 Ω = 1242 Ω

Now, we can calculate the charge stored in the capacitor using the formula Q = C * V, where Q is the charge, C is the capacitance, and V is the potential difference across the capacitor. We are given that Q = 18 μC and C = 3 μF. Plugging these values into the formula, we can solve for V:

18 μC = 3 μF * V
V = 18 μC / 3 μF
V = 6 V

Finally, we can calculate the potential difference V across the resistor R. Using Ohm's Law, we can use the formula V = I * R:

V = 2.5 A * 1242 Ω
V = 3105 V

So, the potential difference V across the resistor R is 3105 V.

In conclusion, the potential difference V across the resistor R is 3105 V.

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Recall the word ""speed"". what is speed? what equation(s) do we have for calculating speed? how can we measure the speed of a moving object?

Answers

Answer:

Speed = distance traveled / time

Speed is a "scalar" quantity

Velocity = Vector Distance Traveled / time

Velocity is a vector quantity.

Example:

One can travel one lap around a track at some particular speed and his average speed will be (lap distance / time)

However, his vector velocity would be zero because he ended up where he started with zero displacement.

If you travel 100km west and then 500km west, what is the total displacement

Answers

Answer: 600 km west

Explanation:

When looking at total distance/displacement, simply add the two given quantities together. Note- in the future, make sure to pay attention to units and directions of components. For example, if it was 100 km east and then 500 km west, your total would be -100 km west + 500 km west, giving you 400 km west.

What is the Net Force of the applied forces? *

Answers

All of anove
Bc it make sense

YO
An engineer in a locomotive sees a car stuck
on the track at a railroad crossing in front of
the train. When the engineer first sees the
car, the locomotive is 150 m from the crossing
and its speed is 16 m/s.
If the engineer's reaction time is 0.79 s,
what should be the magnitude of the mini-
mum deceleration to avoid an accident?
Answer in units of m/s2.

Answers

Hi there!

We can begin by calculating the distance remaining after the reaction time.

Δd = vt

Calculate the distance traveled within this time:

Δd = (16)(.79) = 12.64 m

Subtract from the total distance:

150 - 12.64 = 137.66 m remaining

We can use the following equation to solve for the acceleration necessary:

vf² = vi² + 2ad, where vf = 0 since the train will have slowed down to rest.

Rearrange in terms of "a":

0 = vi² + 2ad

(-vi²) = 2ad

(-vi²)/2d = a

Plug in the given values:

(-(16²))/2(137.66) = a

-256/275.32 = -.9298 m/s²

Two weights are connected by a massless wire and pulled upward with a constantspeed of 1.50 m/s by a vertical pull P. The tension in the wire is T(see figure). Whichone of the following relationships between Tand Pmust be true?A)TB)T=PC)P+T=125ND)P=T+25N

Answers

Two weights are connected by a massless wire and pulled upward with a constant speed of 1.50 m/s by a vertical pull P. The tension in the wire is T The relationship between T and P is that T = P + 125N, which is equivalent to answer choice D. The correct answer is D) P=T+25N.

This can be determined by analyzing the forces acting on the system. Since the weights are being pulled upward at a constant speed, the net force acting on them must be zero.
The forces acting on the weights are their respective weights (mg), where m is the mass of the weight and g is the acceleration due to gravity, and the tension in the wire (T). The vertical pull P also acts on the system.
Using Newton's second law (F=ma) and setting the net force equal to zero, we can write:
T - m1g - m2g - P = 0
Solving for T, we get:
T = m1g + m2g + P
Substituting in the given values of m1, m2, and g, we get:
T = 50N + 75N + P
Simplifying, we get:
T = P + 125N

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Can someone pls help me
50 points

Can someone pls help me 50 points

Answers

Answer:

0.00111111

Explanation:

I'm not sure completely, but if velocity over time (0.2/180) should equal to 0.00111111. Since the solution is velocity final minus initial velocity, it should equal to 10-9.8=0.2 which then you should divide it by the seconds. I hope this gives you some sort of help!

I cant figure this out for so long. thank you in advance whoever helps me​

I cant figure this out for so long. thank you in advance whoever helps me

Answers

Answer:

a magnet is a material with a North and South pole

Bronco the skydiver, whose mass is 80 kg experiences 200 N of air resistance and gravity pulls on him with 800 N What is the acceleration of his fall?

Answers

H E R E I S T H E A N S W E R
Bronco the skydiver, whose mass is 80 kg experiences 200 N of air resistance and gravity pulls on him

Bronco the skydiver, whose mass is 80 kg experiences 200 N of air resistance and gravity pulls on him with 800 N. The acceleration of his fall  7.5 m/sec².

What is force?

A force is an effect that can alter an object's motion according to physics. An object with mass can change its velocity, or accelerate, as a result of a force. An obvious way to describe force is as a push or a pull. A force is a vector quantity since it has both magnitude and direction.

To find the acceleration,

   F = mg

   F = 80.(10)

   F = 800 N

   air resistance = 200 N

   Net force = F - air resistance

                = 800 - 200

                =  600 N

   600 = mass . acceleration

   600 = 80 . acceleration

   acceleration = 7.5 m/sec²

Bronco the skydiver, whose mass is 80 kg experiences 200 N of air resistance and gravity pulls on him with 800 N. The acceleration of his fall  7.5 m/sec².

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Two friends A and B started at different times and covered 30km as shown in the graph.
Identify the correct statement from the following.


option 1 - A and B move with the same speed
option 2 - B moves with non-uniform speed
option 3 - A completes his journey early
option 4 - B overtakes A at 11:10 a.m.

Two friends A and B started at different times and covered 30km as shown in the graph. Identify the correct

Answers

Answer:

Explanation:

option 1 - A and B move with the same speed INCORRECT because the lines have different slopes

option 2 - B moves with non-uniform speed  INCORRECT because the line for B is straight

option 3 - A completes his journey early INCORRECT because A ends his journey at about 11:45 after going about 42 km. B finishes his journey at about 11:35.

option 4 - B overtakes A at 11:10 a.m.  CORRECT.  They meet at the 30 km mark at 11:10, which is where the lines intersect.

1. The thin top layer of the crust is called the Crust. What are the two types of
crust?
O Magma and Nickel
O Inner Core and Outer Core
O Oceanic and Continental
O Lithosphere and Mantle

Answers

oceanic and continental

a 77 kg man is riding on a 32 kg cart traveling at a speed of 3.8 m/s. he jumps off with zero horizontal speed relative to the ground. what is the resulting change in the cart's speed, including sign?

Answers

Answer:

See below

Explanation:

Using conservation of momentum:

Initial momentum = (77+32 kg)* 3.8  m/s = 414.2   kg m/s

Jumping off with zero speed relative to ground (I think this is what zero horizontal speed MEANS) means all of his momentum is given to the cart  ( think about jumping off of a skateboard)

  final momentum of the cart

      mv = 414.2

       v = 414.2/32 = 12.94 m/s    for a + 9.13 m/s change

Why are some fibers spun together to form yarns?

Answers

Answer:

Spun yarns are produced by placing a series of individual fibres or filaments together to form a continuous assembly of overlapping fibres, usually bound together by twist. This operation is required in wool spinning because different parts of the fleece contain fibres of different length and thickness.

A train starts at rest and ends up with 1500 J of kinetic energy. How much work was done on the train?

Answers

Answer:

  1500 J

Explanation:

Apparently, we're to assume that no energy is lost to friction or other effects. Then all of the energy the train has is due to work being done on it.

  1500 J of work was done on the train

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