Answer: When two objects are pressed together with more force: B. Friction increases.
Friction refers to a force that resists or prevent the relative motion of two physical objects when their surfaces comes in contact.
This ultimately implies that, friction prevent the surfaces of two (2) objects from easily sliding over each other or slipping across one another.
Generally, the friction between two (2) objects is highly dependent on the force applied on the objects. Thus, an increase in the force applied on these objects would significantly increase the friction and vice-versa.
In conclusion, friction increases when two objects are pressed together with more force.
Explanation: Hope this helps :)
A vector is defined by its direction and length; its location does not
matter.
A:True
B:False
False.
a quantity having direction as well as magnitude, especially as determining the position of one point in space relative to another.Vectors are quantities that are fully described by magnitude and direction. Not Length!
Answer:
B.) False
Explanation:
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I hope it helps you
what happens to the frequency the centripetal force on an object in circular motion is doubled while the object keeps the same radius of rotation
The new frequency also double the centripetal force on an object in circular motion is doubled while the object keeps the same radius of rotation.
The mass of the object is m .
The radius of the circle is r.
The new centripetal force F2 = 2F1 .
A force that causes a body to follow a curved path is known as a centripetal force, which derives from the Latin words centrum, "Centre," and petered, "to pursue." It always moves in a direction that is the opposite of the body's motion and in the direction of the fixed point of the path's immediate Centre of curvature. "A force by which bodies are dragged or driven, or in any other manner tend, towards a point as to a Centre," was how Isaac Newton defined it. The centripetal force that causes astronomical orbits in Newtonian physics is provided by gravity.
The scenario in which a body moves uniformly fast along a circular path is one frequent example of centripetal force. Towards the Centre of the object, the centripetal force is directed along the radius and at an angle to the velocity.
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why is a secondary rainbow dimmer than a primary bow? how are the colors arranged in the secondary bow?
Secondary rainbow is dimmer than a primary bow as : there is a second reflection with loss of light. The colors are arranged in the opposite order of the primary bow that is red on the inside instead of the outside.
Why is secondary rainbow dimmer than primary rainbow?The intensity of light is reduced further by the second reflection, therefore secondary rainbows are not as bright as primary rainbows. Fewer light rays go through four-step sequence than the three-step sequence and the color scheme of the secondary rainbow is opposite of the primary rainbow.
Double reflection in a drop produces a secondary bow and because of this extra reflection, the secondary bow is much dimmer and its colors are also reversed.
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A ball is thrown up into the air. When it falls half-way back, what kind of energy does it have?
Answer:
it's gravitational potential energy would have converted to kinetic energy half way back when it's falls
the pressure in car tires is often measured in pounds per square inch ( lb/in.2 ), with the recommended pressure being in the range of 25 to 45 lb/in.2 . suppose a tire has a pressure of 39.5 lb/in.2 . convert 39.5 lb/in.2 to its equivalent in atmospheres.
The pressure will become 2.68 atm when expressed in atmospheres.
How do we convert from unit to another ?The act of shifting a quantity's measurement between two units of measurement is known as unit conversion. Usually, multiplicative conversion factors are used, which change the value of the measured amount without altering its effects.
The metric system typically requires moving a decimal point in order to translate from one unit to another.
The given data is 39.5 \(lb/in^2\)
we have to convert it into atmospheres
The pressure is :
39.5 \(lb/in^2\) × \(\frac{1 atm}{ 14.7 lb/in^2}\)
because the conversion factor is 14.7 \(lb/in^2\)
thus the given pressure becomes ;
Pressure = 2.68 atm
The pressure will become 2.68 atm when expressed in atmospheres.
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Help!!! If you cannot type in the box, dont answer.
Answer: lollllllllllllllllllllll
Explanation:
A solution which has a solid solute is saturated at 25°C. It is then heated to 35°C. There is no change in the appearance of the solution. What term would now be associated with this solution?
A.
unsaturated
B.
saturated
C.
oversaturated
D.
supersaturated
Answer:
C. oversaturated
Explanation:
Sana nakatulong
Plzzzz help hurry plzzzzzz plzzz
Answer:
The first one is C, and the second is not clear please show another photo
Explanation:
A car with a mass of 3 Kg and velocity of 40 m/s collided with a truck of a velocity of 60 m/s, if the momentum is conserved what is the mass of the truck?
Answer:
the mass of the truck is 2 kg.
Explanation:
Given;
mass of the car, m₁ = 3 kg
initial velocity of the car, u₁ = 40 m/s
initial velocity of the truck, u₂ = 60 m/s
let the mass of the truck = m₂
Apply the principle of conservation of linear momemtum;
m₁u₁ = m₂u₂
m₂ = (m₁u₁) / u₂
m₂ = (3 x 40) / (60)
m₂ = 2 kg
Therefore, the mass of the truck is 2 kg.
The kinetic product of a reaction is the product with the _____________ the kinetic product is favored when the temperature is _________
The kinetic product of a reaction is the product with the lower activation energy and the kinetic product is favored when the temperature is high.
The kinetic product of a reaction is the product with the lower activation energy, meaning it can be formed more quickly. This product is favored when the temperature is high because it allows more molecules to overcome the activation energy barrier and proceed with the reaction.
To understand this concept better, we can look at an example reaction between two isomeric products: 2-butene and 1-butene. When the reaction is carried out at a low temperature, the thermodynamic product (1-butene) is favored because it has a lower energy state and is more stable. However, at a higher temperature, the kinetic product (2-butene) is favored because it can be formed more quickly due to its lower activation energy.
It's important to note that the favored product (kinetic vs thermodynamic) depends on the reaction conditions and may not always be the same.
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The probable question may be:
The kinetic product of a reaction is the product with the _____________ and the kinetic product is favored when the temperature is _________
A car of mass 1200Kilograms moving at 15 m/s the driver applies the brakes for 0.08 seconds and the castles down to 10 meter per second calculate the acceleration of the car
\(\\ \sf\longmapsto Acceleration=\dfrac{v-u}{t}\)
\(\\ \sf\longmapsto Acceleration=\dfrac{10-15}{0.08}\)
\(\\ \sf\longmapsto Acceleration=\dfrac{-5}{0.08}\)
\(\\ \sf\longmapsto Acceleration=-62.5m/s^2\)
Two equal, but oppositely charged particles are attracted to each other electrically. The size of the force of attraction is 87.96 N when they are separated by 24.04 cm. What is the magnitude of the charges in microCoulombs ?
The magnitude of the electric force between two charged particles is given by Coulomb's Law:
\(F=k\frac{|q_1q_2|}{r^2}\)Where q_1 and q_2 are the charges of the particles, r is the distance between the charged particles and k is the Coulomb's Constant:
\(k=8.99\times10^9N\frac{m^2}{C^2}\)Since the magnitude of both charges is the same, the equation becomes:
\(F=\frac{kq^2}{r^2}\)The force and the distance between the particles are given, the value of k is known and the charge q is unknown. Isolate q from the equation:
\(\begin{gathered} q^2=\frac{F}{k}r^2 \\ \\ \Rightarrow q=\sqrt{\frac{F}{k}r^2}=r\sqrt{\frac{F}{k}} \end{gathered}\)Replace the values of r=24.04*10^-2m, F=87.96N as well as the value of k to find the magnitude of the charges:
\(\begin{gathered} q=r\sqrt{\frac{F}{k}} \\ \\ =(24.04\times10^{-2}m)\times\sqrt{\frac{87.96N}{8.99\times10^9N\frac{m^2}{C^2}}} \\ \\ =23.779...\times10^{-6}C \\ \\ \approx23.78\mu C \end{gathered}\)Therefore, the magnitude of the charges in microCoulombs is: 23.78μC.
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Which physical quantity does not change when a piece of copper is heated?
Answer:
Resistance, resistivity and drift velocity varies with relaxation time which is dependent on temperature.
Number of free electrons in a conductor remains invariant even if its temperature changes.Hence correct option is option D.
If the time constant characteristic of this circuit is 4.00�10^?4 s, what is L, the inductance of the inductor?
The given problem involves determining the value of inductance of an inductor in an electronic circuit, given the time constant characteristic of the circuit. Specifically, we are asked to find the value of L, the inductance of the inductor, if the time constant characteristic of the circuit is 4.00×10^-4 s.
To solve the problem, we need to use the relationship between the time constant, the inductance, and the resistance of the circuit. The time constant is defined as the product of the resistance and the capacitance, or the inductance and the resistance, depending on the type of circuit. In this case, we are dealing with an inductor, so the time constant is given by L/R, where L is the inductance and R is the resistance.We are given the time constant as 4.00×10^-4 s, so we can use this value and the resistance of the circuit to solve for the inductance.
The final answer is a number, which represents the value of inductance required for the circuit.Overall, the problem involves applying the principles of electronics, including time constants and inductance, to determine the value of an inductor in a circuit. It also requires an understanding of the relationship between these quantities and how to manipulate the equations to solve for specific values.
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Which statement about the universality of gravity is untrue?
Answer: The gravitational force between two objects depends only on their masses.
Explanation:
When dealing with the force of gravity between two objects, there are only two things that are important – mass, and distance. The force of gravity depends directly upon the masses of the two objects, and inversely on the square of the distance between them.
Therefore, gravity relies on mass and distance, not just mass.
What direction can the charge move and experience no magnetic force? check all that apply. up down left right into the screen out of the screen
The correct answers are up, down, into the screen, and out of the screen.
When a charge is moving at an angle of 90 degrees to a magnetic field, it experiences no magnetic force. When a charge is moving parallel or anti-parallel to a magnetic field, it does not experience magnetic force.
Check all that apply in the following list: UpDownLeftRightInto the screenOut of the screen
A magnetic field is a field created by an electrical charge in motion, such as an electron or a current through a wire. A magnetic field's direction is determined by the direction of the current, with north and south poles corresponding to the direction of the current.
When a charged particle travels through a magnetic field, it experiences a magnetic force.The charge moves and experiences no magnetic force when it is perpendicular to the magnetic field.
Therefore, the correct answers are up, down, into the screen, and out of the screen.
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A certain quantity of a liquid has a volume of 10cm at 20°C. Calculate its volume at 50°C, if it’s cubic expansivity is 10^(-3) K^(-1)
Answer:
10.3 cm³
Explanation:
From the question given above, the following data were obtained:
Original volume (V₁) = 10 cm³
Initial temperature (θ₁) = 20 °C
Final temperature (θ₂) = 50 °C
Cubic expansivity (γ) = 10¯³ K¯¹
Final volume (V₂) =?
γ = V₂ – V₁ / V₁(θ₂ – θ₁)
10¯³ = V₂ – 10 / 10( 50 – 20)
10¯³ = V₂ – 10 / 10(30)
10¯³ = V₂ – 10 / 300
Cross multiply
10¯³ × 300 = V₂ – 10
0.3 = V₂ – 10
Collect like terms
0.3 + 10 = V₂
10.3 = V₂
V₂ = 10.3 cm³
Thus, the volume at 50 °C is 10.3 cm³
What did classical physics predict would happen to the light given off by an
object as its temperature increased?
A. The wavelength of the light would decrease from visible light into
the ultraviolet range.
B. The color of the light would fade to black as the brightness
decreased.
C. The color of the light would change to white, and the brightness
would decrease.
D. The wavelength of the light would decrease from visible light into
the infrared range.
Answer:
The Wavelength of the light would decrease from visible light into ultraviolet range A P E X
Explanation:
Classical physics predict that as the temperature is increased, the wavelength of the light would decrease from visible light into more energetic ultraviolet range.
What is classical physics?When an electric charge vibrates, an electromagnetic wave is produced. Remember that heat is simply the kinetic energy of random motion. In a hot object, electrons vibrate in random directions and produce light as a result.
A hotter object produces more energetic vibrations, and thus emits more light —- it glows brighter. So far, so good. However, classical physics was unable to explain the shape of the blackbody spectrum.
As per the classical physics concepts, as the temperature increases, the wavelength of light becomes shorter and shifts to higher energy regions. Therefore, option A is correct.
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A sailboat moves north for a distance of 10.00 km when blown by a wind from the exact southeast with a force of . The sailboat travels the distance in 1.0 h. How much work was done by the wind? What was the wind’s power? Your response should include all of your work and a free-body diagram.
Given that the direction sailboat is north and the distance traveled is d = 10 km
The direction of the wind is southeast and the force is
\(F\text{ =2}\times10^4\text{ N}\)The sailboat travels the distance in time, t = 1 h
We have to find the work done by the wind and wind's power.
The diagram is shown below
The work done by the wind will be
\(\begin{gathered} W\text{ =Fdcos}\theta \\ =2\times10^4\times10\times10^3\times\cos (135^{\circ}) \\ =-1.414\times10^8\text{ J} \end{gathered}\)The power of the wind will be
\(\begin{gathered} P=\frac{W}{t} \\ =\frac{-1.414\times10^8}{1\times60\times60} \\ =-3.93\times10^4\text{ W} \end{gathered}\)
544) monochromatic infrared waves with a wavelength of 750 nm pass through 2 narrow slits. if the slits are 25 um apart, at what angle will the fourth order bright fringe appear on a viewing screen ?
The angle at which the fourth order bright fringe appear on a viewing screen is 6.89°. If the wavelength is 750nm and distance between the two slits is 25um.
What is bright fringe?When the crest of a light wave coincides with the crest of another light wave then that interference is called as the bright fringe. The same thing happens with the dark fringe of light wave also, when the trough of one wave coincides with the trough of another wave then this results in the formation of dark fringes.
The angle of the bright fringe appear on a viewing screen can be calculated with the help of a formula:
sinθ = mλ/ d
where, θ = angle of bright fringe,
m = number of bright fringe,
λ = wavelength of the light wave,
d = distance between the two slits
sinθ = 4 × 750 × 10⁻⁹/ 25 × 10⁻⁶ = 0.12
θ = 6.89°
Therefore, the angle at which the fourth order bright fringe appear on a viewing screen is 6.89°.
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How much time would it take for the sound of thunder to travel at an average speed of 330 meters per second a distance of 8000
A girl is running in a long distance race. As she runs, her respiration rate 10 points increases. Her body cells must process energy at a faster rate to power her muscles as she runs. Is this action a response to internal stimuli or external stimuli?
A. internal stimuli
B. external stimili
Explain why tissues in multicellular organisms are supplied with nutrients using a circulatory system.
Answer:
The tissues in a multicellular organism requires a circulatory system in other to deliver oxygen and food to the tissues while also removing carbon dioxide and metabolic wastes due the complexity of these activities
Explanation:
Multicellular organisms are organisms that are made of more than one cell. the more cells an organism has the more complex certain activities might be for the organism hence the tissues in a multicellular organism requires a circulatory system in other to deliver oxygen and food to the tissues while also removing carbon dioxide and metabolic wastes
A man drives south to work every day. If his 55 mile
commute usually takes 0.75 hours, what is his average velocity?
Answer:
73.34 mph to 2dp
Explanation:
veolcity = distance/ time
55 / 0.75 = 73.34 mph
driving home from school one day you saw a ball rolling down into the street you brake for 1.10s slowing your 950 kg 16.0m/s to 9.50 m/s
a ) v = v o + a t ( the acceleration will be negative )
9.50 = 16.0 + a * 1.2
a * 1.2 = -16.0 + 9.50
a * 1.2 = - 6.5
a = - 6.5 : 1.2
a = - 5.4167 m/s²
F = m * a = 950 kg * 5.4167 m/s²
F = 5,145.8 N ( the average force exerted on a car during braking )
b ) d = v o - a t² / 2
d = 16.0 * 1.2 - ( 5.4167 * 1.2² / 2 ) =
= 19.20 - 3.90 = 15.30 m
A 2.0 kg rock is dropped from a height of 125 m. What is the momentum of the object just before it strikes the ground (Use g=10 m/s2)?
Answer:
100Ns
Explanation:
find velocity and then plug into momentum formula momentum=(velocity)(mass)
Answer:
5,000 kg-m/s going south
Explanation:
Since you're only given mass and height, not velocity. You have to find velocity first. The equation for velocity is v=2gh. We know gravity is 10 since it's given & height is also given which is 125m. After doing the math, it's 2,500. Now that you have velocity, you can plug velocity into the formula for momentum which is p=mv. 2.0 times 2,500 = 5,000 kg-m/s going south.
A species introduced in a new habitat can cause problems by:
A. decreasing food supplies for native species
B. over reproducing because they have no predators
C. feeding on native specie
D. All of the above
The moon is roughly one-sixth the size of the earth.
Which statement is true?
a. The gravitational pull of the moon is greater than the earth because it is larger than earth.
b. The gravitational pull of the moon is less than the earth because it is smaller.
c. There is no gravitational pull on the surface of the moon.
d. The gravitation pull of the moon is the same as the earth because they are both spheres.
B.1 () The semi-empirical mass formula (SEMF) may be written in the form z m(Z, A) = 2m +(A-Z)m,-ayA+a5A?+ac (A - 2Z) ap А 28 8= + +1 0-0 0 E-O -1 E-E Avata, 41/2" [2 marks] where mp is the mass of the proton and m, the mass of the neutron. The five coefficients in the SEMF take on the following values in MeV: ay = 15.8, as = 17.8, ac = 0.71, ax = 23.7, ap = 11.2. (a) Use the SEMF to calculate the binding energy of the nucleus MSc in MeV. (b) Consider the odd A mirror nuclei 'B and 'C. Use the SEMF to predict which nuclide you would expect to beta decay to the other, and by which type(s) of beta decay. For full marks you will need to simplify your so- lution as much as possible, explain which terms cancel, and argue why the remaining term(s) make one nuclide less stable than the other. (ii) Figure 1 at the end of the paper shows a schematic diagram of the nuclear energy levels. The nuclear magnetic dipole moment is given by p = BINJ. The 81 fac- tor depends on the spin and orbital angular momentum of the contributing nucleons. For even-odd nuclei there is a special case ) = j = 1+1/2 such that [7 marks] 8J = 8) = 85: = 1+ 1/2 = (1-2)x+ (7) . = 1- 81=8 = - 0+|u+-. i = where g. -5.6, -3.8 for the proton, neutron respectively. (a) Use the shell model to show that the ground-state mirror nuclei in the previous part ('}B and "C) must have the same spin ) and parity P, and determine their )". (b) Use the shell model and your answer to part (a) to predict the nuclear magnetic moment , (in units of the nuclear magneton uw) of 'B and C in the ground state. [2 marks] [4 marks] 3 Turn over/
The energy released in the fission channel \($U_{92}^{235}\) → \(Br_{35}^{87}+La_{57}^{154}+3n$\) is 113.1 MeV.
Given:
the semi-empirical mass formula (SEMF) may be written in the form
\($m(Z,A)= Zm_p+ (A-Z)m_n-a_vA+a_SA^{2/3}+ a_c \frac{Z^2}{A^{1/3}}+ \frac{a_p}{A^{1/2}} \delta$\);
where \($m_p$\)is the mass of the proton and
\($m_n$\) is the mass of the neutron.
The five coefficients in the SEMF take on the following values in MeV:
\($a_v\) =15.8$,
\($a_s\)=17.8$,
\($a_c\) =0.71$,
\($a_a\)=23.7$,
\($a_p\)=11.2$
The nucleus \($U_{92}^{235}$\) can undergo spontaneous fission. One of the many fission channels is
\($U_{92}^{235}\) → \(Br_{35}^{87}+La_{57}^{154}+3n$\).
(a) Estimate the energy released in this channel.
For spontaneous fission:
\($U_{92}^{235}\) → \(Br_{35}^{87}+La_{57}^{154}+3n$\).
Mass of \($U_{92}^{235}\) = \(235m_{proton} + (235-92)m_n$\)
Mass of \($Br_{35}^{87} = 87m_{proton} + (87-35)m_n$\)
Mass of \($La_{57}^{154} = 154m_{proton} + (154-57)m_n$\)
The total mass of the system before the fission,
\($235m_{proton} + (235-92)m_n$\)
The total mass of the system after the fission,
\($87m_{proton} + (87-35)m_n + 154m_{proton} + (154-57)m_n + 3m_n$\)
Total mass of the system before fission \(= 235m_{proton} + (235-92)m_n$\)
Total mass of the system after fission = \(87m_{proton} + (87-35)m_n + 154m_{proton} + (154-57)m_n + 3m_n$\)
The energy released during the fission reaction can be estimated using Einstein's equation,
E = Δmc²
where Δm is the difference in the mass of the nuclei before and after the fission reaction
.Δm = \([235m_{proton} + (235-92)m_n] - [87m_{proton} + (87-35)m_n + 154m_{proton} + (154-57)m_n + 3m_n]$$$\)
\(= 235m_{proton} + 143m_n - 87m_{proton} - 121m_n\)
\(= 148m_{proton} + 22m_n$$\)
The mass of proton, \($m_{proton}\)= 1.0073 amu
The mass of neutron, \($m_n\)= 1.0087 amu
The energy released during the fission reaction,
\($E = (148m_{proton} + 22m_n) c^2\)
\(E= (148(1.0073)+22(1.0087))(3 \times 10^8)^2\)
\(E= 181 \times 10^{12}J\)
E = 113.1 MeV
Thus, the energy released in the fission channel \($U_{92}^{235}\) → \(Br_{35}^{87}+La_{57}^{154}+3n$\) is 113.1 MeV.
(b) The Br-87 and La-154 nuclei produced after the fission reaction are highly excited and unstable. They will undergo beta decay and will eventually reach a stable configuration. The unstable Br-87 nucleus will decay to stable Kr-87 through beta decay and the unstable La-154 nucleus will decay to stable Ce-154 through beta decay.
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The pressure 30.0 meters under water is 396 kPa.
What is the pressure in atm? What is the pressure in mmHg?
The pressure 30.0 meters under water which is 396 kPa, is approximately 3.91 atm and 2970.25 mmHg.
To convert the pressure 30.0 meters under water, which is 396 kPa, to atm and mmHg:
1. To Convert kPa to atm
To convert the pressure from kPa to atm, you can use the following conversion factor:
1 atm = 101.325 kPa
So, divide the pressure in kPa (396 kPa) by the conversion factor (101.325 kPa/atm):
396 kPa / 101.325 kPa/atm = 3.91 atm (approximately)
The pressure 30.0 meters under water in atm is approximately 3.91 atm.
2. To Convert kPa to mmHg
To convert the pressure from kPa to mmHg, you can use the following conversion factor:
1 kPa = 7.50062 mmHg
Multiply the pressure in kPa (396 kPa) by the conversion factor (7.50062 mmHg/kPa):
396 kPa * 7.50062 mmHg/kPa = 2970.25 mmHg (approximately)
The pressure 30.0 meters under water in mmHg is approximately 2970.25 mmHg.
In summary, the pressure 30.0 meters under water, which is 396 kPa, is approximately 3.91 atm and 2970.25 mmHg.
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