what is 99,765 divided by 5?

Answer:

Step-by-step explanation:

Since on each day 9 shells were found, and there are 7 days: 7 x 9 = 63

Number of shells found this summer: 63

Number of shells found fewer this year than last year: 152 - 63 = 89

Hence, Jon’s family found 63 fewer shells than last year

Jon’s family found 63 fewer shells than last year if last summer, Jon’s family found 152 shells at the beach. This summer they were at the beach for 7 days.

It is defined as the operation in which we do the addition of numbers, subtraction, multiplication, and division. It has a basic four operators that is +, -, ×, and ÷.

It is given that:

Last summer, Jon’s family found 152 shells at the beach. This summer they were at the beach for 7 days.

Let x be the number of shells they find this year than last year.

The value of x can be found as follows:

x = 152 - 7×9

x = 152 - 63

x = 89 shells

Thus, Jon’s family found 63 fewer shells than last year if last summer, Jon’s family found 152 shells at the beach. This summer they were at the beach for 7 days.

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Answer:

128 <33

Step-by-step explanation:

6 ÷ 3 + 32 • 4 - 2 = 128

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Answer:

Your answer is <, Hope it helps.

Answer:

wheres the graph

Step-by-step explanation:

Answer:

Step-by-step explanation:

Answer:

\(t=3c-8\)

Step-by-step explanation:

It seems like your question is incomplete, so I will assume it is asking for an expression that represents how many cookies Anna has left.

Let t represent the total number of cookies left. Let's build this expression. If each batch contains c cookies, and there are 3 batches, the total number of cookies baked is 3 times c. Since she ate 8 cookies, 8 must be subtracted from that total. Therefore:

\(t=3c-8\)

Hope this helps!

Solving the given equations:

cos(theta) = -1/2

theta = 2π/3 + 2πk, 4π/3 + 2πk

(Specific solutions: theta = 2π/3, 4π/3, 8π/3, 10π/3, ...)

sin(theta) = √2/2

theta = π/4 + πk, 3π/4 + πk

(Specific solutions: theta = π/4, 3π/4, 5π/4, 7π/4, ...)

cot(theta) = 0.16

theta = arccot(0.16)

theta ≈ 1.41 radians

(Specific solutions: theta ≈ 1.41)

tan(theta) = -10

theta = arctan(-10)

theta ≈ -1.47 radians

(Specific solutions: theta ≈ -1.47)

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Answer:

what is the difference in length and the shortest length

Answer:

the answer is D. y > \(-\frac{3}{2}x + 1\)

hope this helps

Answer:

x ≈ 28.3

Step-by-step explanation:

using the cosine ratio in the right triangle

cos45°= \(\frac{adjacent}{hypotenuse}\) = \(\frac{x}{40}\) ( multiply both sides by 40 )

40 × cos45° = x , then

x ≈ 28.3 ( to the nearest tenth )

Answer: F=(x-1) (3x-1/x =21

Step-by-step explanation: Fx/x=3x^2-4x+1/x

Answer:

y=8

Step-by-step explanation:

The mean (µ) and standard deviation (σ) of the binomial distribution with n=202 and p=0.44 are 88.88 and 7.8959, respectively. The probability of obtaining x=53 is approximately 0.0561, and the z-score for x=37 is -6.55.

To find the mean (µ) and standard deviation (σ) of the binomial distribution, we use the formulas µ = np and σ = sqrt(np(1-p)), where n is the number of trials and p is the probability of success.

Given n = 202 and p = 0.44, we can calculate the mean and standard deviation as follows:

µ = 202 * 0.44 = 88.88 (rounded to 2 decimal places)

σ = sqrt(202 * 0.44 * (1 - 0.44)) = 7.8959 (rounded to 4 decimal places)

Now, let's suppose we want to find the probability of obtaining a specific value of x, let's say x = 53. We can use the formula for the binomial probability:

\(P(x) = C(n, x) * p^x * (1 - p)^{n - x}\)

Substituting the values, we have:

\(P(53) = C(202, 53) * (0.44)^{53} * (1 - 0.44)^{202 - 53}\)

Using a binomial calculator or software, we can find the probability as approximately 0.0561 (rounded to 4 decimal places).

Finally, if we want to calculate the z-score for a given value of x, we can use the formula:

z = (x - µ) / σ

For x = 37, the z-score would be (37 - 88.88) / 7.8959 = -6.55 (rounded to 2 decimal places).

In conclusion, for a binomial distribution with n = 202 and p = 0.44, the mean is 88.88 and the standard deviation is 7.8959. The probability of obtaining x = 53 is approximately 0.0561. The z-score for x = 37 is -6.55.

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Answer:Joints

Step-by-step explanation:

It is likely the joining point so it is so help ful

Answer:

\(\boxed{m=7.5}\)

Step-by-step explanation:

Hey there!

Cross multiply the given info

60 = 8m

Divide both sides by 8

m = 7.5

Hope this helps :)

we know that a whole circle is found using π\(r^{2}\).

So π\(10^{2}\) = 314

so now we know that the whole circle is 314 squared units, we need to find the specific portion.

Oh wait, i learned this lol,

formula for area of sector

As (areas of sector) = π\(r^{2}\)(\(\frac{θ}{360}\))

As (areas of sector) = π\(10^{2}\)(\(\frac{θ}{360}\))

100 times 3.14

314 (43/360)

314(0.12)

As (areas of sector) = 37.68

I hope this finds you well, and have a great day.

The approximate volume of the solid created by rotating the region under the curve y = sin(x) on the interval [0, π] around the x-axis is approximately 2.094 cubic units.

To find the volume of the solid, we can use the disk method. Considering a small segment on the x-axis between x and x + Δx, the corresponding slice of the solid can be approximated as a disk with radius y = sin(x) and thickness Δx. The volume of this disk is given by V = π * (sin(x))^2 * Δx.

To find the total volume of the solid, we need to sum up the volumes of all the disks. We can do this by taking the limit as the thickness Δx approaches zero and integrating over the interval [0, π]. Thus, the volume can be calculated as V = ∫[0, π] π * (sin(x))^2 dx.

Using a calculator or integration software, we can evaluate this definite integral. The result is approximately 2.094 cubic units. Therefore, the approximate volume of the solid created by rotating the region under the curve y = sin(x) on the interval [0, π] around the x-axis is approximately 2.094 cubic units.

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Let's denote the amount invested at 8% as x and the amount invested at 10% as y.

According to the given information, Karim wants to invest a total of $100,000, and the combined annual income from both investments should be $9,000.

Set up the equations based on the information:

The first equation represents the total amount invested:

x + y = 100,000

The second equation represents the total annual income from the investments:

0.08x + 0.1y = 9,000

Solve the equations:

We can use the substitution or elimination method to solve the system of equations. Let's use the elimination method:

Multiply the first equation by 0.08 to match the coefficients of x:

0.08x + 0.08y = 8,000

Now subtract this equation from the second equation to eliminate x:

(0.08x + 0.1y) - (0.08x + 0.08y) = 9,000 - 8,000

0.02y = 1,000

Divide both sides of the equation by 0.02:

y = 1,000 / 0.02

y = 50,000

Substitute the value of y back into the first equation to solve for x:

x + 50,000 = 100,000

x = 100,000 - 50,000

x = 50,000

Calculate the amounts to invest:

Karim should invest $50,000 at 8% and $50,000 at 10% in order to obtain an annual income of $9,000 from both investments.

Karim should invest $50,000 at 8% and $50,000 at 10% in order to obtain an annual income of $9,000 from his investments.

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The equation of the tangent line is y = 2x - π/2 + 1, and the values of m and b are 2 and -π/2 + 1, respectively. To find h'(2), we need to apply the product rule and chain rule. Given that h(x) = 5 + f(x)8g(x), we have:

h'(x) = f'(x)8g(x) + f(x)(8g'(x))

Substituting the values f(2) = -4, f'(2) = 2, g(2) = -1, and g'(2) = 3, we can evaluate h'(2):

h'(2) = f'(2)8g(2) + f(2)(8g'(2))

      = (2)(8)(-1) + (-4)(8)(3)

      = -16 - 96

      = -112

Therefore, h'(2) = -112.

To find the values of a and b for the parabola y = ax^2 + bx, we need to find the slope of the tangent line at (1, -2). The slope of the tangent line is equal to the derivative of the function at that point. So:

y' = 2ax + b

At x = 1, the slope is 4:

4 = 2a + b

Since the tangent line passes through (1, -2), we can substitute these values into the equation:

-2 = a(1)^2 + b(1)

-2 = a + b

We now have a system of equations:

2a + b = 4

a + b = -2

By solving this system, we find a = -6 and b = 4.

Therefore, the values of a and b are -6 and 4, respectively.

To find the equation of the tangent line to the curve y = tan^2(x) at the point (π/4, 1), we need to find the derivative of the function and evaluate it at x = π/4. The derivative of y = tan^2(x) is:

y' = 2tan(x)sec^2(x)

At x = π/4, the slope is:

m = 2tan(π/4)sec^2(π/4)

 = 2(1)(1)

 = 2

Since the tangent line passes through (π/4, 1), we can use the point-slope form of a line to find the equation:

y - 1 = 2(x - π/4)

Simplifying, we get:

y = 2x - π/2 + 1

Therefore, the equation of the tangent line is y = 2x - π/2 + 1, and the values of m and b are 2 and -π/2 + 1, respectively.

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The probabilities are calculated assuming independence of each call and that the success probability remains constant throughout the calls.

a. The probability that, among five voters the student calls, exactly one supports candidate Smith can be calculated using the binomial probability formula. With a success probability of 64% (0.64) and exactly one success (k = 1) out of five trials (n = 5), the probability can be calculated as follows:

\[

P(X = 1) = \binom{5}{1} \times (0.64)^1 \times (1 - 0.64)^4

\]

The calculation results in approximately 0.369, or 36.9%.

b. The probability that, among five voters the student calls, at least one supports candidate Smith can be calculated as the complement of the probability that none of the voters support Smith. Using the binomial probability formula, with a success probability of 64% (0.64) and no success (k = 0) out of five trials (n = 5), the probability can be calculated as follows:

\[

P(X \geq 1) = 1 - P(X = 0) = 1 - \binom{5}{0} \times (0.64)^0 \times (1 - 0.64)^5

\]

The calculation results in approximately 0.997, or 99.7%.

c. The probability that the first voter supporting candidate Smith is reached on the fifth call can be calculated as the probability of not reaching a Smith supporter in the first four calls (0.36) multiplied by the probability of reaching a Smith supporter on the fifth call (0.64):

\[

P(\text{{First Smith Supporter on Fifth Call}}) = (1 - 0.64)^4 \times 0.64

\]

The calculation results in approximately 0.014, or 1.4%.

d. The probability that the third voter supporting candidate Smith is reached on the fifth call can be calculated as the probability of reaching two Smith supporters in the first four calls (0.64 for the first call, 0.36 for the second call, and 0.36 for the third call) multiplied by the probability of reaching a Smith supporter on the fifth call (0.64):

\[

P(\text{{Third Smith Supporter on Fifth Call}}) = (0.64)^2 \times (1 - 0.64) \times 0.64

\]

The calculation results in approximately 0.147, or 14.7%.

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The probabilities are calculated assuming independence of each call and that the success probability remains constant throughout the calls. The calculation results in approximately 0.369, or 36.9%.

a. The probability that, among five voters the student calls, exactly one supports candidate Smith can be calculated using the binomial probability formula. With a success probability of 64% (0.64) and exactly one success (k = 1) out of five trials (n = 5), the probability can be calculated as follows:

[P(X = 1) = \binom{5}{1} \times (0.64)^1 \times (1 - 0.64)^4\]

The calculation results in approximately 0.369, or 36.9%.

b. The probability that, among five voters the student calls, at least one supports candidate Smith can be calculated as the complement of the probability that none of the voters support Smith. Using the binomial probability formula, with a success probability of 64% (0.64) and no success (k = 0) out of five trials (n = 5), the probability can be calculated as follows:

[P(X \geq 1) = 1 - P(X = 0) = 1 - \binom{5}{0} \times (0.64)^0 \times (1 - 0.64)^5\]

The calculation results in approximately 0.997, or 99.7%.

c. The probability that the first voter supporting candidate Smith is reached on the fifth call can be calculated as the probability of not reaching a Smith supporter in the first four calls (0.36) multiplied by the probability of reaching a Smith supporter on the fifth call (0.64):

\[

P(\text{{First Smith Supporter on Fifth Call}}) = (1 - 0.64)^4 \times 0.64

\]

The calculation results in approximately 0.014, or 1.4%.

d. The probability that the third voter supporting candidate Smith is reached on the fifth call can be calculated as the probability of reaching two Smith supporters in the first four calls (0.64 for the first call, 0.36 for the second call, and 0.36 for the third call) multiplied by the probability of reaching a Smith supporter on the fifth call (0.64):

\[

P(\text{{Third Smith Supporter on Fifth Call}}) = (0.64)^2 \times (1 - 0.64) \times 0.64

\]

The calculation results in approximately 0.147, or 14.7%.

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The probability of getting exactly 2 heads when flipping a balanced coin 3 times is 3/8.

When flipping a coin, each flip has 2 possible outcomes: Head (H) or Tail (T). Since we are flipping the coin 3 times, the total number of possible outcomes is 2 × 2 × 2 = 8. To find the probability of a specific outcome, we divide the number of favorable outcomes by the total number of possible outcomes. In this case, the favorable outcomes are the 3 outcomes with exactly 2 heads, and thus the probability is 3/8.

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Answer:

the answer is 5

Step-by-step explanation:

a right angle has a total of 90 degrees

so you subtract 65 from 90 and get 25

that is the total degrees in the rest of the angle

then you would have to divide 25 by 5

leaving you with 5

Answer:

4y^4√3x^2y

Step-by-step explanation:

Simplify the radical by breaking the radicand up into a product of known factors, assuming positive real numbers.

Answer:

A its 10

Step-by-step explanation:

Answer:

1. 1/2

2. 1/5

Step-by-step explanation:

I used a calculator!

Answer:

1.3/6 or 1/2

2.1/5

Step-by-step explanation:

Just write that out, thats all the steps there is, 3/6 simplifies to 1/2 because they're equivalent

To prove that a differentiable function F has at most one real root when F'(x) ≠ 0 for any x ∈ R, we can use the intermediate value theorem.

Suppose, by contradiction, that F has two distinct real roots, say a and b, where a ≠ b. Without loss of generality, assume a < b. Since F is differentiable, it is continuous on the closed interval [a, b] and differentiable on the open interval (a, b).

By the mean value theorem, there exists a point c in the open interval (a, b) such that:

F'(c) = (F(b) - F(a))/(b - a)

Since F(a) = F(b) = 0 (since a and b are roots of F), we have:

F'(c) = 0/(b - a) = 0

This contradicts the assumption that F'(x) ≠ 0 for any x ∈ R. Therefore, our initial assumption that F has two distinct real roots is false, and we conclude that F can have at most one real root.

This proves that if a differentiable function F has F'(x) ≠ 0 for any x ∈ R, then F has at most one real root.

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