What is the change in direction of a wave that occurs when the wave changes speed when moving from one medium to another?

A.) Transmission

B.) Constructive Interference

C.) Destructive Interference

D.) Diffraction

Answers

Answer 1
Maybe A makes more sense to me I guess
Answer 2
A is the only one that basically makes sense

Related Questions

A sonar signal of frequency 1 x 10^6 Hz has a wavelength of 1.5 mm in * 30 points
water. a) What is the speed of the signal in water? b) What is its period in
water? c) What is its period in air?

Answers

a) To find the speed of the signal in water, we can use the equation:

Speed = Wavelength x Frequency

Where Wavelength is given as 1.5 mm and Frequency is given as 1 x 10^6 Hz.

Speed = 1.5 x 10^-3 m x 10^6 Hz = 1.5 x 10^3 m/s

So the speed of the signal in water is 1.5 x 10^3 m/s

b) To find the period in water, we can use the equation:

Period = 1 / Frequency

Where Frequency is given as 1 x 10^6 Hz

Period = 1 / (1 x 10^6) s = 1 x 10^-6 s = 1 microsecond

So the period of the signal in water is 1 microsecond

c) The speed of sound in air is approximately 343 m/s. Since the frequency of the signal remains constant and the speed of sound in air is different than the speed of sound in water, the wavelength of the signal will also be different. However, since the period is inversely proportional to the frequency and is independent of the medium, the period of the signal in air will be the same as in water, which is 1 microsecond.

What is the maximum speed at which a car can safely travel around a circular track of radius 142 meters if the coefficient of friction between the tires and the road is 1.07? Include units in your answer. Answer must be in 3 significant digits.

Answers

Given that the radius of the circular path is r = 142 m and the coefficient of the friction is

\(\mu=1.07\)

The condition for the car to travel safely is

Frictional force = centrifugal force

\(\mu mg=\frac{mv^2}{r}\)

Here, m is the mass of the car and the acceleration due to gravity is g = 9.8 m/s^2.

v is the maximum speed of the car.

\(\begin{gathered} v=\sqrt[]{ugr} \\ =\sqrt[]{1.07\times9.8\times142} \\ =38.58\text{ m/s} \end{gathered}\)

how many grams and calories is a 52 oz pepsi, a hot dog, and a small bad of popcorn?

Answers

Answer:

Pepsi- 660 Calories

Hot Dog- 3 Calories

Popcorn- 210 Calories

Total Calories in all 3 - 873 Calories

A uniform 6m long and 600N beam rests on two supports. What is the force exerted on the beam by the right support B

Answers

Since the beam is uniform, we can assume that its weight acts at its center of mass, which is located at the midpoint of the beam. Therefore, the weight of the beam exerts a downward force of:

F = mg = (600 N)(9.81 m/s^2) = 5886 N

Since the beam is in static equilibrium, the forces acting on it must balance out. Let's first consider the horizontal forces. Since there are no external horizontal forces acting on the beam, the horizontal component of the force exerted by each support must be equal and opposite.

Let F_B be the force exerted by the right support B. Then, the force exerted by the left support A is also F_B, but in the opposite direction. Therefore, the net horizontal force on the beam is zero:

F_B - F_B = 0

Next, let's consider the vertical forces. The upward force exerted by each support must balance out the weight of the beam. Let N_A be the upward force exerted by the left support A and N_B be the upward force exerted by the right support B. Then, we have:

N_A + N_B = F   (vertical force equilibrium)

where F is the weight of the beam.

Taking moments about support B, we can write:

N_A(3m) - F_B(6m) = 0   (rotational equilibrium)

since the weight of the beam acts at its center of mass, which is located at the midpoint of the beam. Solving for N_A, we get:

N_A = (F_B/2)

Substituting this into the equation for vertical force equilibrium, we get:

(F_B/2) + N_B = F

Solving for N_B, we get:

N_B = F - (F_B/2)

Substituting the given value for F and solving for F_B, we get:

N_B = N_A = (F/2) = (5886 N/2) = 2943 N

Therefore, the force exerted on the beam by the right support B is 2943 N.

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Can someone please help me with science.

Can someone please help me with science.

Answers

C because you need to order it from fastest to slowest and the least amount of time taken is the fastest.

Two equal mass objects are moving towards each other with equal speeds. If they collide completely inelastically, which of the following situations will occur?

Answers

The two equal-mass objects will stick together and move as one object after the completely inelastic collision.

In an inelastic collision, the two objects involved stick together and move as a single object after the collision. Since the objects have equal masses and are moving towards each other at equal speeds, their momenta will be equal and opposite before the collision.

During the collision, the objects come into contact and exert forces on each other. These internal forces cause the objects to deform and redistribute their velocities. However, due to the conservation of momentum, the total momentum before the collision must be equal to the total momentum after the collision.

Since the initial momenta of the objects are equal and opposite, the final momentum of the combined object will also be zero. This means the objects will stick together and move as one object after the collision, with a common velocity. This scenario is known as a completely inelastic collision.

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if a wave has a velocity of 200 m/s and a wavelength of 4 m what is the frequency of the wave?

Answers

I will say 50 meters a second

How many crankshaft revolutions in degrees is needed to complete 4-strokes? A. 180. B. 360. C. 90.
D. 720.

Answers

The crankshaft completes one complete 360-degree rotation for each of the four equal strokes that make up the cycle. Every stroke of a camshaft involves a full rotation of 90 degrees.

What does a crankshaft accomplish?

In essence, the internal combustion engine's crankshaft serves as its support structure. The crankshaft is in charge of turning a linear motion into a rotational motion and ensuring that the engine runs properly.

How can you know if your crankshaft is broken?

If the engine is knocking or has low oil pressure, you should take note of it (from a gauge or warning light). When things become bad enough, the engine will just quit. Immediately stop your automobile and turn off the engine if you see any of these symptoms.

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the light cone, built of light paths, with 45 degree tilt, is a boundary in spacetime relative to your position at u.

Answers

The light cone, built of light paths, with 45 degree tilt, Therefore, boundary in spacetime  will berelative to your position at u.

The concept of a light cone is a fundamental aspect of spacetime geometry in relativity. It represents the region of spacetime that can be causally influenced by an event or point in spacetime. A light cone is constructed by considering all possible paths that light can take from the event, extending both into the future and the past. When we say the light cone has a 45-degree tilt, it means that the cone is symmetrical and expands equally in all directions. This tilt is relative to your position at the "u.e" (unspecified event), which serves as the origin of the cone. In other words, the light cone encompasses all events that can be reached by a light signal emitted from the event at the "u.e" and traveling at the speed of light.

The boundary of the light cone separates events that are causally connected to the "u.e" from those that are not. The inside of the cone represents events that can be influenced by the "u.e," whereas the outside represents events that are beyond the reach of any signals emitted from the "u.e."

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Question 5 of 10
What happens when a loop of wire turns between two permanent magnets in
a generator?
A. A current flows through the loop of wire.
O B. Electrical energy transforms into mechanical energy.
O C. A current flows through the permanent magnets.
D. Mechanical energy transforms into electromagnetic radiation.

Answers

Answer:

B. Electrical energy transforms into mechanical energy.

Explanation:

In the case when the wire loop transforms between the two permanent magnets in a generator so here the electrical energy turns to mechanical energy as there is a working principle behind the generator that the electrical energy would turns into mechanical energy

Therefore as per the given scenario, the option b is correct

And, the rest of the options are wrong

Moving along the elevtromagnetic spectrum from low frequency to high frequency, what , if anything, happens to the wavelength?

wavelength get longer

wavelength remains constant

the wavelengths get shorter

wavelength eventually disappear altogether

Answers

Explanation:

the wavelengths get shorter

Urgent Important!!

Many medications have a warning to avoid driving because.
A. they haven't been scientifically tested yet.
B. they have been proven to cause drowsiness.
C. they want to cover all their bases.

Answers

Answer:

B) they have been proven to cause drowsiness

Explanation:

B is the only answer that makes sense, as the other answers do not make sense.  All medications are scientifically tested before they can be used by someone.  Covering their bases would show negligence and is bad.

Hope this helps!

PS, this is biology or medical, not physics.

three resistors and two 10.0-v batteries are arranged as shown in the circuit diagram. find the current in the 12.0 ω resi

Answers

The current in the 12.0Ω resistor will be the same as the current in the entire circuit since they are in series.


In the given circuit, two 10.0V batteries are connected in series, which results in a total voltage of 20.0V.
Next, we need to determine the equivalent resistance of the three resistors. Assuming they are in series, we can simply add their resistances:
R_total = R1 + R2 + R3
If the 12.0Ω resistor is R1, you'll need the values for R2 and R3 to calculate the total resistance.
Once you have the total resistance, you can use Ohm's Law to find the current in the circuit:
I = V / R_total


Hence, The current in the 12.0Ω resistor will be the same as the current in the entire circuit since they are in series.

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If the mass of a cart is quickly loaded to have twice the mass while a propelling force remains constant, the cart's acceleration:1. quadruples.2. doubles.3. stays the same.4. halves.5. none of these

Answers

The correct option is 4. The cart's acceleration will halve. According to Newton's second law of motion, the acceleration of an object is directly proportional to the net force acting on the object and inversely proportional to the mass of the object. Mathematically, this can be expressed as:

a = F/m

where a is the acceleration, F is the net force, and m is the mass of the object.

If the mass of the cart is quickly loaded to have twice the mass while the propelling force remains constant, the net force acting on the cart will remain the same, since the propelling force is not changing. However, the mass of the cart has doubled. Substituting these values in the equation for acceleration, we get:

a = F/(2m)

Since the mass has doubled, the acceleration will be halved. Therefore, the correct option is 4. The cart's acceleration will halve.

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What is the equivalent resistance of the circuit?

What is the equivalent resistance of the circuit?

Answers

Answer:

Option D. 5.45 Ω

Explanation:

From the question given above, the following data were obtained:

Resistance 1 (R₁) = 10 Ω

Resistance 2 (R₂) = 20 Ω

Resistance 3 (R₃) = 30 Ω

Voltage (V) = 120 V

Equivalent resistance (R) =?

The equivalent resistance can be obtained as follow:

1/R = 1/R₁ + 1/R₂ + 1/R₃

1/R = 1/10 + 1/20 + 1/30

Find the least common multiple (lcm) of 10, 20 and 30. The result is 60

Divide 60 by each of the denominators and multiply by their numerators respectively. We have:

1/R = (6 + 3 + 2)/60

1/R = 11/60

Invert

R = 60/11

R = 5.45 Ω

Thus, the equivalent resistance in the circuit is 5.45 Ω

Question 17 of 25
Newton's third law deals most closely with:
O A. inertia.
.
O B. mass.
O C. action and reaction forces.
O D. acceleration.

Answers

Answer:

I think it is C

Explanation:

states that for every action (force) in nature there is an equal and opposite reaction. In other words, if object A exerts a force on object B, then object B also exerts an equal and opposite force on object A. Notice that the forces are exerted on different objects.

Someone pls help mee

Someone pls help mee

Answers

This claim isn’t true. This claim is trying to say that once force is being applied to Newton’s Cradle then it will forever stay in motion. However, from the excerpt we learn that this isn’t possible. As one of the balls are pushed, it is set into kinetic energy, and then that ball will hit another and send it into kinetic energy as well. However, not all of the kinetic energy is kept through this process, some of the energy is lost and converted into different forms such as sound energy. Therefore, it isn’t possible for Newton’s Cradle to stay in motion forever.

what are the benefits of aerobic activity and what effect does that have on endurance during exercise

help plsssssssssssssssssssssssssssss

Answers

Aerobic exercise helps you lose weight and keep it off when combined with a good diet.

When you first begin regular aerobic exercise, you could feel exhausted. But over time, you'll benefit from more endurance and less weariness.

Over time, you can also improve your bone and muscle strength as well as your heart and lung health.

Regular aerobic exercise like walking, cycling, or swimming can improve your health and length of life.

You repeatedly contract your arms, legs, and hip muscles when engaging in aerobic exercise. You'll become aware of your body's reactions immediately.

You'll deepen and speed up your breathing. The amount of oxygen in your blood is increased as a result. As a result of your heart beating more quickly, more blood will reach your muscles and return to your lungs.

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What’s the maximum height of the second hill? Use your answer from part E and the formula PE=m•g•h to determine the answer. Assume that g = 9.8m/sec2.

Whats the maximum height of the second hill? Use your answer from part E and the formula PE=mgh to determine

Answers

Answer:

111.4 m

Explanation:

PE = m x g x h

349,300 = 320 x 9.8 x h

h = 349300 : 3136

h = 111,384 m

What is the mass of a car that weighs 12kN?
Will give brainliest!!!!

Answers

Answer:

The answer is 1200 Kg

Explanation:

Given;Weight of car 12000 NTo Find;Mass of car = ?Formula;W = m × gwhere, W = weightm = mass,g = Acceleration due to gravity = 10 m/s²

Now,

W = mg

12000 = m ÷ 10

m = 12000 ÷ 10

m = 1200 kg

Thus, The mass of car is 1200 kg or 1.2k Kg.

 

-TheUnknownScientist 72

BRAINLIEST : A car starts from rest and accelerates at a rate of 40 m/s2 over a time if 2.4 s. How fast is the car going at the end of this time interval?

Please explain

Answers

Answer:

\(\boxed {\boxed {\sf 96 \ m/s}}\)

Explanation:

We are asked to find the final velocity of the car given the acceleration and time. We can use the following kinematics equation to calculate the final velocity.

\(v_f=v_i+(a \times t)\)

The car starts from rest, so the initial velocity is 0 meters per second. It accelerates a rate of 40 meters per square second over a period of time of 2.4 seconds.

\(v_i\)= 0 m/s a= 40 m/s²t= 2.4 s

Substitute the values into the formula.

\(v_f= 0 \ m/s + ( 40 \ m/s^2 \times2.4 \ s)\)

Solve inside the parentheses.

40 m/s/s * 2.4 s = 40 m/s * 2.4=96 m/s

\(v_f= 0 \ m/s + (96 \ m/s)\)

Add.

\(v_f= 96 \ m/s\)

The final velocity of the car is 96 meters per second.

How much would the displacement (in meters) of a 80 N/m spring be if the force hanging was 200 N?

Answers

The displacement of the spring with a force constant of 80 N/m is 2.5 m.

What is displacement?

Displacement can be defined as the difference between the final and initial position of a object in motion.

To calculate the displacement of the spring, we use the formula below.

Formula:

e = F/k............ Equation 1

Where:

e = displacement of the springF = Force hanging on the springk = Spring constant

From the question,

Given:

F = 200 Nk = 80 N/m

Substitute these values into equation 1

e = 200/80e = 2.5 m

Hence, the displacement of the spring is 2.5 m.

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A bicyclist of mass 75 kg (including the bicycle) can coast down a 4.0degrees hill at a steady speed of 12 km/h. Pumping hard, the cyclist can descend the hill at a speed of 32 km/h.Using the same power, at what speed can the cyclist climb the same hill? Assume the force of friction is proportional to the square of the speed v; that is, Ffr=bv2, where b is a constant.

Answers

The cyclist can climb the same hill at a speed of 16.6 km/h using the same power.

To solve this problem, we need to use the concept of conservation of energy. When coasting down the hill at a steady speed of 12 km/h, the potential energy of the cyclist and the bicycle is converted to kinetic energy. At this speed, the force of friction is equal to the force of gravity, so the net force on the cyclist is zero. When pumping hard and descending the hill at a speed of 32 km/h, the cyclist is using more power to overcome the force of friction and increase the net force in the downhill direction.

To find the speed at which the cyclist can climb the same hill, we need to determine the power output of the cyclist and the force of friction when going uphill. Let's start by finding the force of friction. We know that Ffr=bv^2, where b is a constant. At 12 km/h, the force of friction is equal to the force of gravity, so we can set them equal to each other:

Fg = Ffr
mg sin(theta) = bv²

where m is the mass of the cyclist and the bicycle, g is the acceleration due to gravity, theta is the angle of the hill (4.0 degrees), and v is the speed of the cyclist. Solving for v, we get:

v = √((mg sin(theta))/b)

Plugging in the values, we get:

v = √((75 kg x 9.81 m/s² x sin(4.0))/b) = 4.60 m/s

Converting to km/h, we get:

v = 16.6 km/h

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Glycerin flows through a tube that expands from a 1.00 cm2 cross-section area at point 1 to a 4.00 cm2 cross-section area farther downstream at point 2. the pressure difference between points 1 and 2 is 9.45 kpa.
Part A
What is the speed of the glycerin at point 1? Assume that the glycerin flows as an ideal fluid. Express your answer with the appropriate units.
Vi = .... units
Part B
What is the speed of the glycerin at point 2? Assume that the glycerin flows as an ideal fluid.
Express your answer with the appropriate units
V2 = .... units

Answers

To answer these questions, we can use the Bernoulli equation, which relates the pressure, velocity, and height of a fluid in a system to the pressure, velocity, and height of a reference point. For an ideal fluid flowing through a tube with a varying cross-sectional area, the Bernoulli equation is given by:

P + (1/2)ρv^2 + ρgh = constant

where P is the pressure, ρ is the density of the fluid, v is the velocity of the fluid, g is the acceleration due to gravity, and h is the height above a reference point.

In this case, we are given the pressure difference between points 1 and 2, and we are asked to find the velocity of the glycerin at each point. We can use the Bernoulli equation to solve for the velocity at each point by setting the constant equal to the pressure at one of the points and solving for the velocity at the other point.

(a) To find the velocity at point 1, we can set the constant equal to the pressure at point 1 and solve for the velocity:

P1 + (1/2)ρv1^2 + ρgh1 = P2 + (1/2)ρv2^2 + ρgh2

P1 + (1/2)ρv1^2 = P2 + (1/2)ρv2^2

(1/2)ρv1^2 = (1/2)ρv2^2

v1 = v2

Since we don't know the values of the other variables, we can't solve for the velocity directly. However, we know that the velocities at points 1 and 2 are equal, so we can use this relationship to solve for the velocity at one point in terms of the other.

(b) To find the velocity at point 2, we can set the constant equal to the pressure at point 2 and solve for the velocity:

P1 + (1/2)ρv1^2 + ρgh1 = P2 + (1/2)ρv2^2 + ρgh2

P1 - P2 = (1/2)ρv2^2 - (1/2)ρv1^2

P1 - P2 = (1/2)ρ(v2^2 - v1^2)

(P1 - P2)/(1/2)ρ = v2^2 - v1^2

(9.45 kPa)/(1/2)ρ = v2^2 - v1^2

(9.45 kPa)/(1/2)ρ = v2^2 - v1^2

(9.45 kPa)/(1/2)ρ = v2^2 - v1^2

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a 50 kg aardvark runs with a speed of 6 m/s. what is the kinetic energy of the aardvark

Answers

Answer:

900 J

Explanation:

0.5 x 50= 25 x 6^2= 900 J

a 600-w tv receiver is turned on for 4 hours with nobody watching it. if electricity costs 10 cents/kwh, how much money is wasted? the wasted money is cents.

Answers

A 600-w TV receiver is turned on for 4 hours with nobody watching it. If electricity costs 10 cents/kWh, the amount of money wasted is cents. Therefore, the amount of money wasted in this case is 24 cents.

There are different steps to calculate the money wasted in this case. Here is the step-by-step solution to this problem:

First, we need to calculate the energy consumed in kWh:

Energy consumed = Power × Time Power = 600 W Time = 4 hours

Energy consumed = Power × Time Energy consumed = 600 W × 4 hours

Energy consumed = 2400 Wh.

To convert Wh into kWh, we need to divide the energy consumed by 1000:

Energy consumed = 2400 Wh = 2.4 kWh.

Now, we can calculate the amount of money wasted:

Cost of 1 kWh = 10 cents Cost of 2.4 kWh = 2.4 kWh × 10 cents/kWh

Cost of 2.4 kWh = 24 cents.  

A 600-w TV receiver is turned on for 4 hours with nobody watching it. If electricity costs 10 cents/kWh, the amount of money wasted is cents. The energy consumed by the TV receiver can be calculated by multiplying the power rating by the time it is used. In this case, the power rating is 600 W, and the time is 4 hours.

Therefore, the energy consumed is 600 W × 4 hours = 2400 Wh.

To convert the energy consumed into kWh, we need to divide it by 1000. So, 2400 Wh = 2.4 kWh. The cost of electricity is 10 cents per kWh.

Therefore, the cost of 2.4 kWh is 2.4 kWh × 10 cents/kWh = 24 cents.

This is the amount of money wasted by keeping the TV receiver turned on for 4 hours without anyone watching it. It is important to turn off electrical appliances when they are not in use to save electricity and reduce the electricity bill.

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if a body starts from rest and attains a velocity of 20 metre per second in 8 seconds find the acceleration produced in the body​

Answers

Answer:

2.5 m/s^2

Explanation:

the equation to find acceleration is \(\frac{v - v_{0} }{t}\) where \(v_{0}\) is the initial velocity, v is the current velocity, and t is the total time

so plug in your values: \(\frac{20 - 0}{8}\)

that turns into 20 ÷ 8

this equals 2.5 m/s^2

To understand the meaning and the basic applications of Newton's 1st and 2nd laws. In this problem, you are given a diagram (Figure 1)representing the motion of an object--a motion diagram. The dots represent the object's position at moments separated by equal intervals of time. The dots are connected by arrows representing the object's average velocity during the corresponding time interval. Your goal is to use this motion diagram to determine the direction of the net force acting on the object. You will then determine which force diagrams and which situations may correspond to such a motion.
Please answer Part J: Which of these situations describe the motion shown in the motion diagram at point C? The correct answer is not FG or CF.

Answers

Based on Newton's laws of motion, we can make some general observations about the motion of the object and the forces acting on it.

Newton's first law states that an object at rest will remain at rest and an object in motion will remain in motion at a constant velocity unless acted upon by an external net force.

In other words, if the net force acting on an object is zero, its motion will be uniform and unchanging.

Newton's second law states that the acceleration of an object is directly proportional to the net force acting on it and inversely proportional to its mass.

In other words, the greater the net force acting on an object, the greater its acceleration will be, and the greater its mass, the smaller its acceleration will be for the same net force.

From the motion diagram at point C, we can observe that the object is moving to the right with a constant velocity, as indicated by the equally spaced dots and arrows.

Therefore, the net force acting on the object must be zero, according to Newton's first law.

Based on this information, we can eliminate any situations that involve a non-zero net force acting on the object.

This includes situations where the object is accelerating or experiencing a net force in a different direction than its motion, such as situations involving FG or CF.

Therefore, the situation that corresponds to the motion shown in the motion diagram at point C must involve a zero net force acting on the object and motion in the same direction as the net force.

Additional information or context may be needed to identify which situation corresponds to this motion.

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A truck is pulling a trailer down a highway. The total mass of the trailer is 360kg and the
force at which the truck is pulling is 7.200N, What is the acceleration of the truck?

Answers

Question :-

A Truck is Pulling a Trailer down a Highway . The Total Mass of the Trailer is 360kg and the Force at which the Truck is pulling is 7200 Newton . What is the Acceleration of the Truck ?

Answer :-

Acceleration of the Truck is 20 m/s² .

Explanation :-

As per the provided information in the given question, we have been given that the Mass of the trailer is 360 kg . Force is given as 7200 Newton . And, we have beena asked to calculate the Acceleration of the Truck .

For calculating the Acceleration , we will use the Formula :-

\( \bigstar \: \: \: \boxed {\sf{ \: Acceleration \: = \: \dfrac {Force}{Mass} \: }} \)

Therefore , by Substituting the given values in the above Formula :-

\( \dag \: \: \: \sf {Acceleration \: = \: \dfrac {Force}{Mass}} \)

\( \longmapsto \: \: \: \sf {Acceleration \: = \: \dfrac {7200}{360}} \)

\( \longmapsto \: \: \: \textbf {\textsf {Acceleration \: = \: 20 }} \)

Hence :-

Acceleration = 20 m/s² .

\( \underline {\rule {180pt} {4pt} } \)

Answer:

A Truck is Pulling a Trailer down a Highway . The Total Mass of the Trailer is 360kg and the Force at which the Truck is pulling is 7200 Newton . What is the Acceleration of the Truck ?

Answer :-

Acceleration of the Truck is 20 m/s² .

Explanation :-

As per the provided information in the given question, we have been given that the Mass of the trailer is 360 kg . Force is given as 7200 Newton . And, we have beena asked to calculate the Acceleration of the Truck .

For calculating the Acceleration , we will use the Formula :-

\bigstar \: \: \: \boxed {\sf{ \: Acceleration \: = \: \dfrac {Force}{Mass} \: }}★

Acceleration=

Mass

Force

Therefore , by Substituting the given values in the above Formula :-

\dag \: \: \: \sf {Acceleration \: = \: \dfrac {Force}{Mass}}†Acceleration=

Mass

Force

\longmapsto \: \: \: \sf {Acceleration \: = \: \dfrac {7200}{360}}⟼Acceleration=

360

7200

\longmapsto \: \: \: \textbf {\textsf {Acceleration \: = \: 20 }}⟼Acceleration = 20

Hence :-

Acceleration = 20 m/s² .

Using the PhET Balancing Act, discuss the possibilities of balancing two forces acting on one side of a pivot point with a single force of the other. Select the best answer: i. This is possible with a single force at the same distance from the pivot point but on the opposite side of the pivot point as one of the forces. Ii. This is possible with a single force at the same distance as the point half way between the two forces from the pivot point but on the opposite side of the pivot point. Iii. This requires two forces. A

Answers

Balancing two forces acting on one side of a pivot point with a single force on the other side is a common concept in physics. The PhET Balancing Act simulation can help us understand this concept better.

When we have two forces acting on one side of a pivot point, it creates an imbalance. To balance the system, we need to add a single force on the other side of the pivot point. The question is, what should be the distance of this single force from the pivot point to balance the two forces?

According to the simulation, the best answer is (i) This is possible with a single force at the same distance from the pivot point but on the opposite side of the pivot point as one of the forces. This means that we can balance the two forces by placing a single force on the opposite side of the pivot point, at the same distance as one of the forces. This works because the force and distance on both sides of the pivot point are equal, creating a balanced system.

Answer (ii) states that it is possible with a single force at the same distance as the point halfway between the two forces from the pivot point but on the opposite side of the pivot point. This is incorrect because the distance is not equal on both sides of the pivot point, and the system will not be balanced.

Answer (iii) states that it requires two forces. This is also incorrect because we can balance the system with a single force, as explained in answer (i).

In conclusion, balancing two forces acting on one side of a pivot point with a single force on the other side is possible by placing the single force at the same distance from the pivot point but on the opposite side of the pivot point as one of the forces. This creates a balanced system where the force and distance on both sides of the pivot point are equal.

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