What is the distance between point N to segment LM in the figure below?

Using the .01 level of significance means that, in the long run, a Type I error occurs 1 time in 100. This means that if we perform a statistical test 100 times, and we set the level of significance at .01, then we can expect to observe one false positive result due to chance alone. So, the correct option is 1).

A Type I error occurs when we reject a true null hypothesis, or when we conclude that there is a significant difference or relationship between two variables when in fact there is not.

By setting the level of significance at .01, we are minimizing the risk of making a Type I error while increasing the risk of making a Type II error, which occurs when we fail to reject a false null hypothesis. So, the correct answer is 1).

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In question 27, the price elasticity of supply for shampoo is given as 20, and the price of shampoo increases by 0.7%. The expected change in the quantity of shampoo supplied can be determined using the concept of price elasticity of supply. However, the specific percentage change in quantity supplied is not provided, so a precise answer cannot be given based on the given information.

In question 20, an inferior good in which the income effect dominates the substitution effect is referred to as a Giffen good. It is not classified as a normal good, luxury good, mass-produced good, or favored good.

In question 30, the cross elasticity of demand measures the responsiveness of the quantity demanded of a particular good to changes in the prices of its substitutes and complements. The correct answer is that the cross elasticity of demand measures the responsiveness to changes in both substitutes and complements.

In question 27, without the specific percentage change in quantity supplied, we cannot determine the exact outcome based on the given information. The price elasticity of supply of 20 suggests that the quantity supplied is highly responsive to changes in price, but the specific percentage change in quantity supplied cannot be calculated without additional data.

In question 28, the relationship between pasta being a Giffen good and other characteristics is not specified. While pasta being a Giffen good indicates that the quantity demanded increases as the price increases, it does not imply whether pasta is a normal good, luxury good, or how price changes affect quantity demanded.

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Answer:

120

Step-by-step explanation:

One hour is 90 minutes 90/15=6 then you take 20X6=120miles

Answer:

It will travel 120 miles

Step-by-step explanation:

First, convert the hour and half to minutes: 90 minutes.

Then divide 90 with 15: 6

Then since there are 6 sections of 15 minutes, you would multiply 20 times 6 which is 120.

Answer:

y=-3x-10

Step-by-step explanation:

Hi there!

We need to find the equation of the line parallel to y=-3x+4 that has the y intercept of -10 (the point (0, -10))

Parallel lines have the same slope

The slope of y=-3x+4 is -3 (it is in the placement of where m (slope) is in y=mx+b)

So the slope of the new line parallel to y=-3x+4 is also -3

Here is the equation of that line so far:

y=-3x+b

b is a placeholder for the y intercept

However, we are given the y intercept as -10, so substitute -10 as b into the equation

y=-3x-10

There's the equation of the line parallel to y=-3x+4 with a y intercept of -10

Hope this helps!

Answer:

false

Step-by-step explanation:

pls mark brainiest

The statement is false, the graph shown is not a function.

Functions are the relationship between sets of values. e g y=f(x), for every value of x there is its exists in a set of y. x is the independent variable while Y is the dependent variable.

The graph is a demonstration of curves that gives the relationship between the x and y-axis.

Here,
A graph of figures is shown, and asked that whether it is a function or not,
So the graph shown is of the circle and the circle is not a function.

Thus, the statement is false, the graph shown is not a function.

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L(t) = (2/3)t + 3, (-1/2)t + 4, t + 2.

The curve of intersection of the cylinders x² + y² = 25 and y² + z² = 20 can be found by setting the two equations equal to each other:

x² + y² = y² + z² = 20

The intersection of the two cylinders is a circle.

To determine the radius of this circle, we use either of the two equations and solve for one variable in terms of the other two:

y² + z² = 20y²

= 20 - z²y

= ±sqrt(20 - z²)

If we substitute this expression for y into the equation x² + y² = 25, we can solve for x in terms of z:

x² + (20 - z²)

= 25x²

= 5 + z²x

= ±sqrt(5 + z²)

Thus, the curve of intersection can be expressed parametrically as follows:

r(t) = (x(t), y(t), z(t)) = (sqrt(5 + t²), sqrt(20 - t²), t)for -2sqrt(5) ≤ t ≤ 2sqrt(5)

At the point (3, 4, 2), t = 2.

To find the tangent vector to the curve at this point, we take the derivative of the position vector:

r'(t) = (x'(t), y'(t), z'(t)) = (t/sqrt(5 + t²), -t/sqrt(20 - t²), 1)

at t = 2:r'(2) = (2/sqrt(9), -2/sqrt(16), 1) = (2/3, -1/2, 1)

Finally, we obtain the vector equation of the tangent line by using the point-normal form of the equation of a line:

L(t) = r(2) + t r'(2)L(t)

     = (3, 4, 2) + t (2/3, -1/2, 1)L(t)

     = (2/3)t + 3, (-1/2)t + 4, t + 2

Therefore, a vector equation for the tangent line to the curve of intersection of the cylinders x² + y² = 25 and y² + z² = 20 at the point (3, 4, 2) is:

L(t) = (2/3)t + 3, (-1/2)t + 4, t + 2.

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Brooklyn have to pay total for the 11 rides is $43 and for r rides she have to pay is $10+$3×r.

If Brooklyn goes on 11 rides, she will have to pay $10 for admission and $3 for each of the 11 rides she goes on. So her total cost would be:

$10 + (11 rides x $3/ride) = $10 + $33 = $43

If she goes on r rides, her total cost would be:

$10 + (r rides x $3/ride) = $10 + $3r

So, for example, if she goes on 15 rides, her total cost would be:

$10 + (15 rides x $3/ride) = $10 + $45 = $55

An arithmetic expression is a combination of numbers, operators (such as +, -, x, ÷), and parentheses that can be evaluated to produce a numerical result.

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Answer:

y = 10/3x - 2/3

Step-by-step explanation:

10x-3y=2​

-3y = -10x + 2

-3y/-3 = -10x/-3 + 2/-3

y = 10/3x - 2/3

Answer:

calculate the probability that the marbles are the same color, then subtract this probability from 1 to find the probability they are different colors. P(2 of the same) = P(2 green) + P(2 yellow) + P(2 red) = 1/26 + 5/26 + 2/26 = 8/26 = 4/13. P(2 different) = 1 - P(2 of the same) = 1 - 4/13 = 9/13.

Step-by-step explanation:

32(-5) + 0 + 160 = 0 is the line in the general form of the line the passing through (−5,0) with the slope 32.

A number that describes a line's direction and steepness is known as the slope or gradient of a line in mathematics. There is no obvious reason why the letter m is used to represent slope, although it first appears in English in O'Brien (1844), who wrote the equation for a straight line as "y = mx + b," and it may also be found in Todhunter (1888), who wrote it as "y = mx + c."

Let us write the given data in slope-intercept form that is

y = m(x) + b

where m = slope of the line

b = y-intercept

So substituting the values we get

0 = 32(-5) + b

-b = -160

b = 160

so we have the slope intercept form

0 = 32(-5) + 160

Converting this to General form

ax + by + c = 0

32(-5) + 0 + 160 = 0

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Translated question

Given the following conditions, determine the equation of the line in its general form Ax+By+C=0.

It passes through (−5,0) and has slope m=32.

Answer: B

Because 4x5=20

5x7=35

4x7=28

add them toghether=83

83x2=166

Given:

The area of a flower garden is 60 m².

One third of it was used for growing roses and the remaining area was divided into two equal parts.

To find:

The area of each remaining part.

Solution:

It is given that the area of a flower garden is 60 m² and one third of it was used for growing roses. So, the remaining part is:

\(\text{Remaining}=60-\dfrac{1}{3}\times 60\)

\(\text{Remaining}=60-20\)

\(\text{Remaining}=40\)

The remaining area was divided into two equal parts. So, the area of each remaining part is:

\(\text{Area of each remaining part}=\dfrac{40}{2}\)

\(\text{Area of each remaining part}=20\)

Therefore, the area of each remaining part is 20 m².

To determine if a function crosses the horizontal asymptote, analyse the behavior of the function as it approaches the asymptote and on either side of it.

1. Identify the horizontal asymptote of the function. The horizontal asymptote is a horizontal line that the function approaches as the independent variable (usually denoted as x) goes to positive or negative infinity. It is often denoted by a horizontal line y = a, where "a" is a constant.

2. Examine the behavior of the function as x approaches positive infinity. Evaluate the limit of the function as x goes to positive infinity. If the limit is equal to the value of the horizontal asymptote, then the function does not cross the asymptote. However, if the limit does not equal the asymptote, move to the next step.

3. Examine the behavior of the function as x approaches negative infinity. Evaluate the limit of the function as x goes to negative infinity. If the limit is equal to the value of the horizontal asymptote, then the function does not cross the asymptote. If the limit does not equal the asymptote, proceed to the next step.

4. Investigate the behavior of the function around critical points or points where the function changes its behavior. These points may include the x-intercepts or vertical asymptotes. Determine if the function crosses the asymptote around these points by analyzing the behavior of the function in their vicinity.

If, at any point in this process, the function crosses the horizontal asymptote, then it does not have a true horizontal asymptote. However, if the function approaches the asymptote and does not cross it at any point, then it has a horizontal asymptote.

It's important to note that some functions may have multiple horizontal asymptotes or no horizontal asymptote at all. The steps outlined above are a general guideline, but the specific behavior of the function needs to be analyzed to make a conclusive determination.

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Answer:

2. 4(x-10) = 16

The transformation T: R^3 → R^2 defined by T(x1, x2, x3) = (|x1|, 0) is not linear transformation as it violates the additivity and homogeneity properties of linearity.

To show that the transformation T: R^3 → R^2 defined by T(x1, x2, x3) = (|x1|, 0) is not linear, we need to demonstrate that it violates at least one of the two properties of linearity, namely, additivity and homogeneity.

Additivity: T(u + v) = T(u) + T(v) for all vectors u and v in R^3.

Let u = (1, 2, 3) and v = (4, 5, 6) be two vectors in R^3. Then,

T(u) = T(1, 2, 3) = (|1|, 0) = (1, 0)

T(v) = T(4, 5, 6) = (|4|, 0) = (4, 0)

T(u + v) = T(1+4, 2+5, 3+6) = T(5, 7, 9) = (|5|, 0) = (5, 0)

However,

T(u) + T(v) = (1, 0) + (4, 0) = (5, 0)

Since T(u + v) ≠ T(u) + T(v), the transformation T is not additive and hence not linear transformation.

Homogeneity: T(cu) = cT(u) for all vectors u in R^3 and all scalars c.

Let u = (1, 2, 3) be a vector in R^3, and let c = 2 be a scalar. Then,

T(u) = T(1, 2, 3) = (|1|, 0) = (1, 0)

T(cu) = T(2, 4, 6) = (|2|, 0) = (2, 0)

However,

cT(u) = 2(1, 0) = (2, 0)

Since T(cu) ≠ cT(u), the transformation T is not homogeneous and hence not linear.

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I need some help since I don't comprehend what you're asking.

1. A(x) = (f(x)-f(a)) / (x-a) This average rate of change function is called A. The function f's input is represented by x minus a, while the function f's response to the input changing from a to x is represented by f(x) minus f(a).

f(5)=-2 f(9)=14 (f(5)-f(9))/(5-9)=(-2-14)/-4=4 from the table.

Over the range of x = 5 to x = 9, the average rate of change is 4.

2. g(x)=2x2+13x+1, f(x)=4x2+6x

(f/g)(x)=(4x²+6x)/(2x²+13x+1)

Using the numbers shown in the table, x = 4,5,6,7,8,9 and f(x) = 88,85,155,116,180,151,238.190,304,233,378.280

3. f(x)=x2-6x+8, g(x)=x-2, x2-6x-x+8+2=0, x2-7x+10=0 f(x)=g(x)x2-6x+8=x-2x2-6x-x+8+2=0

x₁,₂=(7⁺₋√(7²-4*10))/2=(7⁺₋3)/2 x₁=5, x₂=2

Because 2 doesn't appear in the table of values, the answer using the table of values is x=5.

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Answer:

1/4= 25%

Step-by-step explanation:

Answer:

\(f^{-1}(x)=\pm\sqrt{x+16}\)

Step-by-step explanation:

\(f(x)=x^2-16\)

To find the inverse of this function, temporarily the f(x) with a y (or whatever else you want) and then solve for the x.

\(y=x^2-16\\y+16=x^2\\x=\pm\sqrt{y+16}\)

Now, you can swap the variables again and write the function.

\(f^{-1}(x)=\pm\sqrt{x+16}\)

Answer:

mai is faster

Step-by-step explanation:

because even though she on goes 15 meters in 6 seconds she would have 4 times the advantage because of the extra 4 seconds she has

Answer:

carry out laws and put them in action

To construct a confidence interval for the proportion of defectives, we should use the plus four method.

Since the sample size is 20, which is not very large, the large-sample interval is not appropriate. Instep, we ought to utilize a strategy that's suitable for little test sizes. 

The plus four method is one such method that is commonly used when the sample size is small. Therefore, to construct a confidence interval for the proportion of defectives, we should use the plus four method.

The plus four strategies may be a strategy for building a certainty interim for an extent when the test estimate is little.

To utilize this strategy, we to begin with include four fanciful perceptions to our test, two of which are flawed and two of which are not imperfect.

This increments the test estimate to 24, which permits us to utilize the typical guess to the binomial dispersion to build the certainty interim.

The equation for the certainty interim utilizing the also four strategies is:

p ± zα/2 √((p + 2) (1 - p + 2) / n + 4)

where:

p is the test extent (number of defectives/test estimate)

zα/2 is the basic esteem from the standard typical dissemination at the level of importance α/2

n is the test estimate (counting the included four nonexistent perceptions)

Therefore, to construct a confidence interval for the proportion of defectives, we should use the plus four method.

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Answer:

y(x)=0

Step-by-step explanation:

To solve the given differential equation using Green's function, we need to first determine the Green's function associated with the given boundary conditions.

The Green's function, G(x, ξ), satisfies the following equation:

(x^2 d^2G / dx^2) + (2x dG / dx) - 4G = δ(x - ξ)

where δ(x - ξ) is the Dirac delta function. We can solve this equation subject to the boundary conditions:

G(0, ξ) = G(∞, ξ) = 0

To solve this differential equation, we assume a solution of the form:

G(x, ξ) = A(x)B(ξ)

Substituting this form into the differential equation and simplifying, we get:

x^2 d^2A / dx^2 + 2x dA / dx - 4A = 0

This is a homogeneous second-order ordinary differential equation. We can solve it by assuming a power series solution of the form:

A(x) = ∑[n=0 to ∞] (a_n x^n)

Substituting this series into the differential equation and equating coefficients of like powers of x, we get:

a_n [(n + 2)(n + 1) - 4] = 0

Solving this equation for the coefficients, we find:

a_0 = 0

a_1 = 0

a_n = 4 / [(n + 2)(n + 1)] for n ≥ 2

Therefore, the solution for A(x) is:

A(x) = 4 * ∑[n=2 to ∞] (x^n / [(n + 2)(n + 1)])

Now, we can substitute the solution for A(x) into the form of the Green's function:

G(x, ξ) = A(x)B(ξ)

G(x, ξ) = 4 * ∑[n=2 to ∞] (x^n / [(n + 2)(n + 1)]) * B(ξ)

To determine B(ξ), we impose the boundary conditions:

G(0, ξ) = 0 => 4 * ∑[n=2 to ∞] (0 / [(n + 2)(n + 1)]) * B(ξ) = 0

G(∞, ξ) = 0 => 4 * ∑[n=2 to ∞] (ξ^n / [(n + 2)(n + 1)]) * B(ξ) = 0

From these conditions, we can conclude that B(ξ) = 0. Hence, the Green's function is:

G(x, ξ) = 0

Now, to obtain the solution to the differential equation, we can use the Green's function in the following integral form:

y(x) = ∫[0 to ∞] G(x, ξ) f(ξ) dξ

where f(ξ) is the inhomogeneous term in the original differential equation.

Since G(x, ξ) = 0, the integral evaluates to zero as well. Therefore, the solution to the given differential equation is:

y(x) = 0

In conclusion, the solution to the differential equation with the given boundary conditions is y(x) = 0.

Check the picture below.

Answer: When we have a function in formula form, it is usually a simple matter to evaluate the function. For example, the function f(x)=5−3x2 f ( x ) = 5 − 3 x 2 can be evaluated by squaring the input value, multiplying by 3, and then subtracting the product from 5.

Step-by-step explanation:

Functions is an important branch of math, which connects the variable x with the variable y. Functions are generally represented as y = f(x) and it states the dependence of y on x, or we say that y is a function of x.

Answer:

\(\frac{27y^6}{8x^{12}}\)

Step-by-step explanation:

1) Use Product Rule: \(x^ax^b=x^{a+b}\).

\((\frac{3x^{-5+2}{y^3}}{2z^0yx}) ^3\)

2) Use Negative Power Rule: \(x^{-a}=\frac{1}{x^a}\).

\((\frac{3\times\frac{1}{x^3} y^3}{2x^0yx} )^3\)

3) Use Rule of Zero: \(x^0=1\).

\((\frac{\frac{3y^3}{x^3} }{2\times1\times yx} )^3\)

4) use Product Rule: \(x^ax^b=x^{a+b}\).

\((\frac{3y^3}{2x^{3+1}y} )^3\)

5) Use Quotient Rule: \(\frac{x^a}{x^b} =x^{a-b}\).

\((\frac{3y^{3-1}x^{-4}}{2} )^3\)

6) Use Negative Power Rule: \(x^{-a}=\frac{1}{x^a}\).

\((\frac{3y^2\times\frac{1}{x^4} }{2} )^3\)

7) Use Division Distributive Property: \((\frac{x}{y} )^a=\frac{x^a}{y^a}\).

\(\frac{(3y^2)^3}{2x^4}\)

8) Use Multiplication Distributive Property:  \((xy)^a=x^ay^a\).

\(\frac{(3^3(y^2)^3}{(2x^4)^3}\)

9) Use Power Rule: \((x^a)^b=x^{ab}\).

\(\frac{27y^6}{(2x^4)^3}\)

10)  Use Multiplication Distributive Property:  \((xy)^a=x^ay^a\).

\(\frac{26y^6}{(2^3)(x^4)^3}\)

11) Use Power Rule: \((x^a)^b=x^{ab}\).

\(\frac{27y^6}{8x^12}\)

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Answer:

\(\displaystyle \frac{27y^{6}}{8x^{12}}\)

Step-by-step explanation:

\(\displaystyle \biggr(\frac{3x^{-5}y^3x^2}{2z^0yx}\biggr)^3\\\\=\biggr(\frac{3x^{-5}y^2x}{2}\biggr)^3\\\\=\frac{(3x^{-5}y^2x)^3}{2^3}\\\\=\frac{3^3x^{-5*3}y^{2*3}x^3}{8}\\\\=\frac{27x^{-15}y^{6}x^3}{8}\\\\=\frac{27y^{6}x^3}{8x^{15}}\\\\=\frac{27y^{6}}{8x^{12}}\)

Notes:

1) Make sure when raising a variable with an exponent to an exponent that the exponents get multiplied

2) Variables with negative exponents in the numerator become positive and go in the denominator (like with \(x^{-15}\))

3) When raising a fraction to an exponent, it applies to BOTH the numerator and denominator

Hope this helped!