What is the momentum of a 55 kg bolder moving with a speed of 19 m/s

Answer:

0.25 kg

Explanation:

p = mv

2 = m(8)

2/8 = m(8)/8 *cancels

m = 1/4 OR 0.25 kg

Answer:

all are true so d is right

Explanation:

Electromagnets use electrlcity and magnets is true.

Magnetic fields are strongest around the poles of a magnet is true.

The south pole of a magnet will repel the south pole of another magnet is true

and since all of them is true the answer is d all of the above

The constant acceleration of the green car which passes red color car is  2.81 m/s^2.

In this problem, the initial positions of the red and green cars are xr = 0 and xg = 220 m, respectively, and their initial velocities are vr = 20 km/h and vg = 0. When the red car has a velocity of 20 km/h, the cars pass each other at x = 44.5 m, and when the red car has a velocity of 40 km/h, they pass each other at x = 76.6 m.

We can use these two equations to solve for the acceleration of the green car. First, we convert the velocities from kilometers per hour to meters per second by dividing by 3.6. This gives us vr = 5.56 m/s and vg = 0 m/s.

Then, we can substitute these values into the equation for position and solve for the acceleration. When the red car has a velocity of 20 km/h, the equation becomes:

x = 0 + 5.56t + 1/2at^2

x = 44.5

Solving for a, we find that the acceleration of the green car is a = 2.61 m/s^2.

When the red car has a velocity of 40 km/h, the equation becomes:

x = 220 + 11.11t + 1/2at^2

x = 76.6

Solving for a, we find that the acceleration of the green car is a = 2.61 m/s^2.

When the red car has a velocity of 40 km/h, the equation becomes:

x = 220 + 11.11t + 1/2at^2

x = 76.6

Solving for a, we find that the acceleration of the green car is a = 3.02 m/s^2.

Since the acceleration is the same in both cases, we can take the average of these two values to find the constant acceleration of the green car. The average of 2.61 m/s^2 and 3.02 m/s^2 is 2.81 m/s^2.

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A) To find the spring constant of the spring, we can use the conservation of energy. The spring constant of the spring is 1378.8 N/m.

B) The equilibrium point is at a height of 0 meters.

C)  The frequency of the oscillation is: f = 1/T ≈ 6.25 Hz

y(t) = 0.05 cos (2 π × 6.25 where y is in meters and t is in seconds.

The positive direction is from the equilibrium point.

a) To find the spring constant of the spring, we can use the conservation of energy. At the maximum height, the ball has no kinetic energy, so all the energy stored in the spring has been transferred to potential energy in the ball. The potential energy stored in a spring is given by:

PE = (1/2) k S^2

where k is the spring constant and S is the distance the spring is compressed. The potential energy stored in the spring must be equal to the potential energy of the ball at its maximum height. Using the given values, we can set up the equation:

(1/2) k S^2 = M g H

where M is the mass of the ball, g is the acceleration due to gravity, and H is the maximum height reached by the ball. Solving for k, we get:

k = 2 M g H / S^2

Substituting the given values, we get:

k = 2 × M × 9.81 m/s^2 × 0.35 m / (0.05 m)^2 = 1378.8 N/m

Therefore, the spring constant of the spring is 1378.8 N/m.

b) The equilibrium point of the ball when it is sitting on the spring with no forces other than gravity and the spring acting on it is the unscratched point of the spring. We can choose this point as the origin of our coordinate system, and take the upward direction as positive. Therefore, the equilibrium point is at a height of 0 meters.

c) When the ball is glued onto the spring and oscillates up and down, its motion can be described by a simple harmonic motion equation:

y(t) = A cos (ω t)

where y is the position of the ball, A is the amplitude of the oscillation, ω is the angular frequency, and t is the time. The amplitude of the oscillation is equal to the initial compression of the spring, which is 0.05 meters. The angular frequency is given by:

ω = 2 π f

where f is the frequency of the oscillation. The frequency of the oscillation is related to the period of the oscillation T by:

T = 1/f

The period of the oscillation can be found using the formula for the period of a simple harmonic motion:

T = 2 π √(m/k)

where m is the mass of the ball and k is the spring constant. Substituting the given values, we get:

T = 2 π √(0.1 kg / 1378.8 N/m) ≈ 0.16 s

Therefore, the frequency of the oscillation is:

f = 1/T ≈ 6.25 Hz

Substituting these values in the equation for the position of the ball, we get:

y(t) = 0.05 cos (2 π × 6.25 t)

where y is in meters and t is in seconds. The positive direction is upward from the equilibrium point.

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The time taken is approximately 2.08 seconds for the bag of sand to reach the ground from the moment of its release.

To determine the time it takes for the bag of sand to reach the ground, we can use the kinematic equation for vertical motion. The equation is given as:

h = ut + (1/2)gt^2

Where:

h = height (37.8 m)

u = initial velocity (0 m/s)

g = acceleration due to gravity (-9.81 m/s^2, considering downward motion)

t = time

Since the balloon is ascending with a constant upward velocity of 2.95 m/s, the initial velocity of the bag is also 2.95 m/s in the upward direction. Therefore, we need to consider the initial velocity as negative.

Substituting the known values into the equation, we have:

37.8 = (-2.95)t + (1/2)(-9.81)t^2

Simplifying the equation further, we get:

-4.905t^2 - 2.95t + 37.8 = 0

Solving this quadratic equation for time, we find two solutions: t = 2.08 s and t = -3.61 s. Since time cannot be negative, we discard the negative value.

Therefore, it takes approximately 2.08 seconds for the bag of sand to reach the ground from the moment of its release.

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1.) To protect buildings, structures and people from lightning strikes ; 2.)  Using materials that are good conductors of electricity ;3.)Provides low-resistance path for any static electricity ; 4.)Dryer sheets, damp towel or washcloth to dryer, metal dryer ball or other anti-static device; 5.)Anti-static mats, humidifiers, anti-static wrist straps and cleaning carpets.

1. Function of lightning rod is to protect buildings, structures, and people from lightning strikes. It works by providing a low-resistance path for lightning current to follow, directing it safely into ground.

2. Charge build-up on airplanes is reduced by using materials that are good conductors of electricity, such as aluminum, to help distribute any charge that builds up across the surface of the airplane.

3. Ground strap is a necessary safety feature when transferring fuel because it provides low-resistance path for any static electricity that may build up during transfer process.

4. Three methods for reducing charge build-up in clothes dryers are as :

Using dryer sheets or fabric softeners, which can help to dissipate any static charge that may build up on clothes during drying process.

Adding damp towel or washcloth to dryer, which can help to increase humidity inside the dryer and reduce the likelihood of static build-up.

Using metal dryer ball or other anti-static device, which can help to neutralize any charge that may build up on clothes.

5. The four methods for reducing charge build-up in computer room with carpet are as follows:

Using anti-static mats or flooring, which can help to dissipate any static charge that may build up on carpet.

Installing humidifiers, which can help to increase the humidity in room and reduce the likelihood of static build-up.

Using anti-static wrist straps or other grounding devices when handling sensitive electronic equipment, to help discharge any static electricity that may have built up on body.

Regularly cleaning carpet with a vacuum cleaner that is equipped with anti-static brush or hose, which can help to remove any static charge that may have built up on carpet fibers.

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Answer:

a)  v = 0.7071 v₀, b) v= v₀, c)  v = 0.577 v₀, d)   v = 1.41 v₀, e)  v = 0.447 v₀

Explanation:

The speed of a wave along an eta string given by the expression

          v = \(\sqrt{ \frac{T}{ \mu } }\)

where T is the tension of the string and μ is linear density

a) the mass of the cable is double

          m = 2m₀

let's find the new linear density

          μ = m / l

iinitial density

          μ₀ = m₀ / l

final density

          μ = 2m₀ / lo

          μ = 2 μ₀

we substitute in the equation for the velocity

initial            v₀ = \(\sqrt{ \frac{T_o}{ \mu_o} }\)

with the new dough

                    v = \(\sqrt{ \frac{T_o}{ 2 \mu_o} }\)

                    v = 1 /√2  \sqrt{ \frac{T_o}{ \mu_o} }

                    v = 1 /√2 v₀

                    v = 0.7071 v₀

b) we double the length of the cable

If the cable also increases its mass, the relationship is maintained

              μ = μ₀

   in this case the speed does not change

c) the cable l = l₀ and m = 3m₀

we look for the density

           μ = 3m₀ / l₀

           μ = 3 m₀/l₀

           μ = 3 μ₀

            v = \(\sqrt{ \frac{T_o}{ 3 \mu_o} }\)

            v = 1 /√3  v₀

            v = 0.577 v₀

d) l = 2l₀

            μ = m₀ / 2l₀

            μ = μ₀/ 2

           v = \(\sqrt{ \frac{T_o}{ \frac{ \mu_o}{2} } }\)

           v = √2 v₀

            v = 1.41 v₀

e) m = 10m₀ and l = 2l₀

we look for the density

             μ = 10 m₀/2l₀

             μ = 5 μ₀

we look for speed

             v = \(\sqrt{ \frac{T_o}{5 \mu_o} }\)

             v = 1 /√5  v₀

             v = 0.447 v₀

(a) When the mass is doubled, the speed of the wave in the string is 0.7071 v₀.

(b) When the wire is replaced with an identical one, the speed of the wave will be the same.

(c) When the mass of the wire is tripled, the speed of the wave in the string is 0.577 v₀.

(d) When the length is doubled, the speed of the wave in the string is 1.414 v₀.

(e) When the mass increases by a factor of 10 and the length doubles, the speed of the wave in the string is 0.447 v₀.

The given parameters:

The speed of the wave at a given tension and the mass per unit length;

\(v_0 = \sqrt{\frac{T}{\mu} } \\\\v _0= \sqrt{\frac{T}{M/L} } \\\\v_0 = \sqrt{\frac{LT}{M} }\)

(a) When the mass is doubled,

\(v = \sqrt{\frac{LT}{2M} } \\\\v = \sqrt{\frac{1}{2} } \times \sqrt{\frac{LT}{M} }\\\\v = \sqrt{\frac{1}{2} } \times v_0\\\\v = 0.7071 v_0\)

(b) When the wire is replaced with an identical one,

the mass per unit length will be constant and the speed will be the same

v = v₀

(c) When the mass of the wire is tripled;

\(v = \sqrt{\frac{LT}{3M} } \\\\v = \sqrt{\frac{1}{3} } \times \sqrt{\frac{LT}{M} } \\\\v = \sqrt{\frac{1}{3} } \times v_0\\\\v = 0.577 \ v_0\)

(d) When the length is doubled;

\(v = \sqrt{\frac{2LT}{M} } \\\\v = \sqrt{2} \times \sqrt{\frac{LT}{M} } \\\\v = \sqrt{2} \times v_0\\\\v= 1.414 v_0\)

(e) When the mass increases by a factor of 10 and the length doubles;

\(v = \sqrt{\frac{2LT}{10M} } \\\\v = \sqrt{\frac{1}{5} } \times \sqrt{\frac{LT}{M} }\\\\v = \sqrt{\frac{1}{5} } \times v_0\\\\v = 0.447 \ v_0\)

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Answer: 3.13 m

Explanation:

Given

mas of the ball is m=10 kg

The ball rolls down a vertical distance of 5 m

Spring constant of spring is \(k=100\ N/m\)

Here, the potential energy of the ball converted into kinetic energy which in turn converts into elastic potential energy

\(\Rightarrow mgh=\frac{1}{2}kx^2\quad [\text{x=compression in the spring}]\\\\\Rightarrow 10\times 9.8\times 5=\frac{1}{2}\cdot 100\cdot x^2\\\Rightarrow x=\sqrt{9.8}\\\Rightarrow x=3.13\ m\)

Thus, the spring compresses by 3.13 m.

Hello!

The answer is Gravity. Lets take a look at the options:

A. Nope, this would be if the shuttle was going horizontal.

B. Again, this would be if the shuttle was going horizontal.

C. Yes! This is the only force that is being overcome by using the rocket thrusts to move up.

D. No, the shuttle is using its thrust rocks to push against gravity.

I hope this helps! :)

Answer:

26.9444m/s

pls brainliest

gear C and Z will run at the same RPM

RPM is not a unit, according to the International System of Units (SI). The word "revolution" is a semantic annotation rather than a unit, which explains this. RPM formula sign must be f for (rotational) frequency and or for angular velocity due to the measured physical quantity. s−1  or Hz is the basic SI-derived unit that corresponds. The radians per the second unit are used to express angular speed.

As a result, a disc rotating at 60 RPM  is considered to be rotating at either 2 rad/s or 1 Hz, where the former refers to angular velocity and the latter to the rate of revolutions per second.

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Answer:

605 J

Explanation:

Efficiency = work out / work in

0.78 = W / 775 J

W = 605 J

When you double the speed of your car, your braking distance quadruples. every time you double your speed, you multiply your braking distance by four.

The stopping distance of a vehicle is the sum of breaking distance and thinking distance. The stopping distance of a vehicle when we increase the velocity from 10mph to 30 mph, increases from30 feet to 90 feet.

Stopping distance is the distance covered by a vehicle when we stops. Distance is the product of time and velocity. As the velocity increases then, the time taken to cover the distance will be lower.

Stopping distance mathematically is the sum of breaking distance and thinking distance .Thinking distance is simply the speed and it is in fact means how long it takes on average to think for a break.

Breaking distance is means how long the driver takes to break or stop in actual. In general, the breaking distance is speed multiplied by 2.

Thus, for 10 mph, the thinking distance is 10 feet and breaking distance is 10 × 2 = 20 feet and therefore, the stopping distance is 10 + 20 =30 feet.

Similarly for 30 mph, breaking distance is 60 feet and thinking distance is 30 feet thus, having 60 + 30 = 90 feet of stopping distance.

Therefore, when the speed increased from 10 mph to 30 mph, stopping distance increases from 30 feet to 90 feet.

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Answer:

Density is the mass of an object divided by its volume. Density often has units of grams per cubic centimeter (g/cm3). Remember, grams is a mass and cubic centimeters is a volume (the same volume as 1 milliliter).

Explanation:

Hey, there!

Density is defined as mass per unit volume. so, when we keep is as a formula we get like,

\(density = \frac{mass}{volume} \)

So, you can state that density is calculated by dividing mass by its unit volume.

Hope it helps...

The bug will cross the sticky region once in each cycle of its motion, where a cycle is defined as one complete round trip from the top of the bowl to the bottom and back to the top.

To find the number of cycles the bug goes through, we can use conservation of mechanical energy. At the top of the bowl, the bug has only potential energy, which is converted to kinetic energy as it slides down the bowl. At the bottom of the bowl, all of the potential energy has been converted to kinetic energy, and as the bug slides up the other side of the bowl, the kinetic energy is converted back into potential energy. At the top of the bowl again, the bug has only potential energy, and the cycle repeats.

Because there is no friction (except for the sticky patch), the total mechanical energy of the system is conserved. Therefore, the potential energy at the top of the bowl is equal to the potential energy at the bottom of the bowl, and the kinetic energy at the bottom of the bowl is equal to the kinetic energy at the top of the bowl.

We can set the potential energy at the top of the bowl to zero, and use the conservation of energy to find the potential energy at the bottom of the bowl:

mgh = (1/2)mv^2

where m is the mass of the bug, g is the acceleration due to gravity, h is the depth of the bowl, and v is the speed of the bug at the bottom of the bowl.

Solving for v, we get:

v = sqrt(2gh)

Plugging in the numbers, we get:

v = sqrt(29.810.12) = 0.775 m/s

The time it takes for the bug to slide from the top of the bowl to the bottom and back up to the top is twice the time it takes to slide from the top to the bottom:

t = 2sqrt(2h/g) = 2sqrt(2*0.12/9.81) = 0.774 s

Therefore, the frequency of the bug's motion is:

f = 1/t = 1/0.774 = 1.29 Hz

Since the bug completes one cycle in each oscillation, the bug will cross the sticky region 1.29 times per second, or approximately once every 0.78 seconds.

Answer:

When buying a margarine, people should look for trans fat and saturated fat content. If it is over 2%, then it is not healthy. If it is lower that means it is healthy and fresh!

Explanation:

Answer:

Long distance transport of nitrogenous air pollution is important and people who drive are influencing the occurrence of acidic loving lichen species

Explanation:

Answer:

 y = y₀ (1 - ½ g y₀ / v²)

Explanation:

This is a free fall problem. Let's start with the ball that is released from the window, with initial velocity vo = 0 and a height of the window i

          y = y₀ + v₀ t - ½ g t²

          y = y₀ - ½ g t²

for the ball thrown from the ground with initial velocity v₀₂ = v

         y₂ = y₀₂ + v₀₂ t - ½ g t²

in this case y₀ = 0

         y₂2 = v t - ½ g t²

at the point where the two balls meet, they have the same height

         y = y₂

         y₀ - ½ g t² = vt - ½ g t²

         y₀i = v t

         t = y₀ / v

since we have the time it takes to reach the point, we can substitute in either of the two equations to find the height

         y = y₀ - ½ g t²

         y = y₀ - ½ g (y₀ / v)²

         y = y₀ - ½ g y₀² / v²

        y = y₀ (1 - ½ g y₀ / v²)

with this expression we can find the meeting point of the two balls

Considering the definition of ion, option A is correct: when an atom that has no charge loses two electrons, it becomes a positive ion or cation.

An ion is an electrically charged particle that is made up of an atom or molecule that is not electrically neutral, that is, that in its constitution has gained or lost electrons.

In other words, an ion is a molecule or atom that has a positive or negative electrical charge. That is, an ion is an atom whose electrical charge is not neutral.

If the electrical charge is positive, it is called a cation while if the electrical charge is negative, it is called a anion.

Cations are positively charged ions. They are formed as a result of the loss of electrons. This means that cations always have more protons than electrons.

Finally, option A is correct: when an atom that has no charge loses two electrons, it becomes a positive ion or cation.

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Answer:

positive ion

Explanation:

Part 1: the final angular speed is 0.64 + 0.86 = 1.50 rad/s. Substituting the values, 1.05 J.

Angular speed is the rate of change of angular displacement of a body over a period of time. It is also known as rotational speed and is usually measured in revolutions per minute (RPM) or radians per second (rad/s).

Part 1:
The angular speed is given by the formula w = Iα, where w is the angular speed, I is the moment of inertia and α is the angular acceleration. Since the moment of inertia is constant, the change in angular speed is given by Δw = ΔIα.
The change in moment of inertia is given by ΔI = mr2, where m is the mass of the objects and r is the change in radius.
So, the change in angular speed is given by Δw = mr2α.
Substituting the given values,
Δw = (3 kg)(1 m - 0.3 m)2(0.64 rad/s)
Δw = 0.86 rad/s
Therefore, the final angular speed is 0.64 + 0.86 = 1.50 rad/s.

Part 2:
The change in kinetic energy of the system is given by ΔK = ΔIw2/2.
Substituting the values,
ΔK = (3 kg)(1 m - 0.3 m)2(1.50 rad/s)2/2
ΔK = 1.05 J.

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Given data

*The given velocity of the car is v(t)= 10 + 3t + 512

The acceleration of the car is calculated as

Thus, the acceleration of the car at t = 2 s is 3 m/s^2

The statement that describes the transformation of the graph of function f onto the graph of function g is: The graph shifts 2 units right and 7 units down.

To determine the transformation of the graph of function f onto the graph of function g, we compare the two functions f(x) and g(x) and observe the changes in the equations.

The function f(x) = (1/x - 3) + 1 represents a reciprocal function that is shifted vertically 1 unit up and horizontally 3 units to the right. The reciprocal function is reflected about the line y = x.

The function g(x) = (1/(1 + 4)) + 3 simplifies to g(x) = 4 + 3 = 7, which is a constant function representing a horizontal line at y = 7.

By comparing the equations, we can see that the transformation from f(x) to g(x) involves the following changes:

The term 1/x in f(x) is replaced by the constant 1/(1 + 4) in g(x), resulting in a vertical shift of 7 units up.

The term -3 in f(x) is replaced by 3 in g(x), resulting in a vertical shift of 3 units up.

The +1 in f(x) is replaced by +3 in g(x), resulting in an additional vertical shift of 2 units up.

Therefore, the overall transformation is a shift of 2 units to the right and 7 units down.

Hence, the correct statement is: The graph shifts 2 units right and 7 units down.

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Answer:

The average density of Jupiter, 1.326 g/cm³, is the second highest of the giant planets, but lower than those of the four terrestrial planets.

Explanation:

This very low density compared with the terrestrial planets is because it is composed mostly of hydrogen and helium, in ratios similar to that found in stars (approximately 82% hydrogen and 17% helium by mass). Furthermore, Jupiter is almost entirely gas and liquid.