what would be considered more dilute? sweet tea or unsweetened tea

Answer:

0.0011 moles

Explanation:

Recall that;

Number of moles = mass of substance/ molar mass of the substance

Mass of asprin = 0.2001 g

Molar mass of asprin = 180.158 g/mol

Number of moles =  0.2001 g/180.158 g/mol

Number of moles = 0.0011 moles

Limiting reactant in CaCO3 + HCl = CaCl2 + CO2 + H2O is HCl.

HCl is the limiting reactant because HCl has a lower molar ratio than CaCO3 in the balanced equation.

For every 1 mole of CaCO3, 2 moles of HCl are required to react completely.

However, in the given reaction providd, there is only 1 mole of HCl. This means that the HCl will be used up first, and the CaCO3 will be in excess.

The limiting reactant is the one that gets completely consumd first in the chemical reaction, thus determining the maximum amount of product that can be formed.

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Explanation:

The calculated formula masses to 133.5 amu, we find that the substance with a formula mass closest to 133.5 amu is (d) AlCl3. Therefore, the answer is option D.

To identify the substance with a formula mass of 133.5 amu, we need to calculate the formula mass of each given substance and compare it to 133.5 amu.

(a) MgCl2:

The formula mass of MgCl2 can be calculated by adding the atomic masses of magnesium (Mg) and chlorine (Cl).

Mg: atomic mass = 24.31 amu

Cl: atomic mass = 35.45 amu

Formula mass of MgCl2 = (24.31 amu) + 2(35.45 amu) = 95.21 amu

(b) SCl:

The formula mass of SCl can be calculated by adding the atomic masses of sulfur (S) and chlorine (Cl).

S: atomic mass = 32.07 amu

Cl: atomic mass = 35.45 amu

Formula mass of SCl = 32.07 amu + 35.45 amu = 67.52 amu

(c) BCl:

The formula mass of BCl can be calculated by adding the atomic mass of boron (B) and chlorine (Cl).

B: atomic mass = 10.81 amu

Cl: atomic mass = 35.45 amu

Formula mass of BCl = 10.81 amu + 35.45 amu = 46.26 amu

(d) AlCl3:

The formula mass of AlCl3 can be calculated by adding the atomic mass of aluminum (Al) and 3 times the atomic mass of chlorine (Cl).

Al: atomic mass = 26.98 amu

Cl: atomic mass = 35.45 amu

Formula mass of AlCl3 = 26.98 amu + 3(35.45 amu) = 133.78 amu. Option D

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The given question is not complete, the complete question is:

Solving applied density problems Mr. Auric Goldfinger, criminal mastermind, intends to smuggle several tons of gold across International borders by disguising it as lumps of iron ore. He commands his engineer minions to form the gold into little spheres with a diameter of exactly 6 cm and paint them black However, his chief engineer points out that customs officials will surely notice the unusual weight of the "iron ore" if the balls are made of solid gold (density 19.3 g/cm'). He suggests forming the gold into hollow balls Instead (see sketch at right), so that the fake "Iron ore" has the same density as real iron ore (5.15 g/cm'). One of the balls of fake iron ore," sliced in half Calculate the required thickness of the walls of each hollow lump of iron ore. Be sure your answer has a unit symbol, if necessary, and round it to 2 significant digits.

Answer:

The correct answer is 0.29 cm.

Explanation:

To produce fake iron balls that is, formed of gold there is a need to make sure that the mass of the iron ball should be equivalent to the mass of the fake ball.  

To calculate the volume of iron ball with the help of the given diameter, the formula to be used is 4/3πr³. The diameter of the spheres mentioned in the given question is 6 cm, so the radius will be 6/2= 3 cm.  

Now, the volume of the iron ball would be = 4/3 × 3.14 × 3³ = 113.04 cm³

To determine the mass of the iron ball, the formula to be used is volume * density. Now putting the values we get,  

113.04 × 5.15 g/cm³ = 582.156 grams (The density of the iron ore is 5.15 g/cm³)

Now, the mass of the gold ball should also be equal to 582.156 g. The density of the solid gold is 19.3 g/cm³, therefore, the volume of the gold ball by using the above formula would be,  

mass of gold ball = Volume × density

Volume = mass of gold ball / density

Volume = 582.156 g / 19.3 g/cm³

= 30.1635 cm³

Thus, the volume of the hollow sphere would be 30.1635 cm³ with the outer radius as 3 cm, now there is a need to find the inner radius.  

Volume of hollow ball = 4/3π [R³ -r³]

30.1635 cm^3 = 4/3 pie [3³ = r³]

30.1635 × 3/4 × 3.14 = 27-r³

7.2046 = 27-r³

r³ = 19.7954

r = 2.7051 cm

Hence, the thickness would be outer radius - inner radius = 3-2.7051 = 0.2949 cm or 0.29 cm.  

Answer:

133.34 g/mol

Explanation:

Answer: 6.75 moles

Explanation:

This is a simple stoichiometry proboe. that I would set up like this:

(13.5 moles CuCI2) (1 mol I2 / 2 moles CuCi2)

That means you all you have to do for this problem is divide by 2 and cancel out the unit moles CuCI2, which leaves you with 6.75 moles I2.

Hope this helps :)

Answer:

a greater profit......

475 g is the correct response to the query. This is true because the combined mass of two solutions with masses of 450 g and 350 g equals 800 g. 125 g of solid crystals are created and fall to the bottom of the container as a result of a chemical reaction.

As a result, the mass of the residual solution is equal to 475 g, or 800 g less 125 g. It is significant to observe that the masses of the two solutions that were combined originally do not equal those of the solid crystals or the leftover solution.

This is because the two solutions' chemical reaction when combined results in a transition of the matter that is resulting in the production of a new substance.

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The following are categorized into polar or nonpolar molecules:

a) Beryllium chloride (BeCl₂) is a nonpolar molecule. The Be-Cl bond is polar due to the electronegativity difference between beryllium and chlorine, but the molecule is linear with the two polar bonds pointing in opposite directions, resulting in a net dipole moment of zero.

b) Hydrogen sulphide (H₂S) is a polar molecule. The H-S bond is polar due to the electronegativity difference between hydrogen and sulfur, and the molecule has a bent shape, resulting in a net dipole moment that is not zero.

c) Sulphur trioxide (SO₃) is a nonpolar molecule. The S-O bonds are polar due to the electronegativity difference between sulfur and oxygen, but the molecule is trigonal planar with the three polar bonds pointing in different directions, resulting in a net dipole moment of zero.

d) Water (H₂O) is a polar molecule. The H-O bond is polar due to the electronegativity difference between hydrogen and oxygen, and the molecule has a bent shape, resulting in a net dipole moment that is not zero.

e) Trichloromethane (CHCl₃) is a polar molecule. The C-Cl bonds are polar due to the electronegativity difference between carbon and chlorine, and the molecule has a tetrahedral shape, resulting in a net dipole moment that is not zero.

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Answer:

True if by rifting you mean continental rift. If not idk.

Answer:

D

Explanation:

The ratio of C6H12O6 (which will be referred to as "the carb") to oxygen is 1 to 6, so if we find an answer which has the same ratio, it should be chosen. A is 1:3
B is even worse with a ratio of the carb to oxygen of 1:2
C is the same as B, 1:2
D has a ratio of the carb to oxygen of 1:6, which is what we are looking for.

Answer:

The first image = double replacement

Second = single replacement

Third = Decomposition

Fourth = Combination

Explanation:

1. a color from each pair is being swapped and replacing each other so there is a double replacement

2. only the blue and the red are changing places so it is single replacement

3. the pair is being separated (decomposed)

4. the red and green are coming together (combined)

Answer:

It is a chemical reaction because it is a reaction to the oxygen

Explanation:

Answer:

a

Explanation:

Damage caused by road salt is most pronounced during the summer rather than the winter months because it increases the rate of corrosion.

This is referred to as the process in which there is a gradual deterioration of materials by chemical reaction with their environment.

Their environment consists of humans and other factors and in a situation where the salt is added to the road it leads to corrosion which makes it inaccessible and poses as a risk factor to vehicles which is why it is carefully used mostly during the winter months.

In a situation whereby salt is added during the summer months, it leads to a higher degree of corrosion because of the high temperature present during this period which is why it was chosen as the correct choice.

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Observation statements: When the mass of the sun is larger, Earth moves around the sun at a slower pace.

When the mass of the sun is smaller, Earth moves around the sun at a faster pace.

When Earth is closer to the sun, its orbit becomes faster.

When Earth is farther from the sun, its orbit becomes slower.

Hypothesis:

The gravitational force between two objects depends on their masses and the distance between them, as described by the law of universal gravitation. Therefore, if we change the mass of the sun or the distance between Earth and the sun, we should observe changes in the speed and shape of Earth's orbit around the sun.

Results:

Our observations confirm our hypothesis. When we increased the mass of the sun, we noticed that Earth's orbit around the sun became slower.

Conversely, when we decreased the mass of the sun, Earth's orbit became faster. This is consistent with the idea that larger masses exert a stronger gravitational force, which in turn affects the speed and shape of Earth's orbit.

Similarly, when we moved Earth closer to the sun, we observed that its orbit became faster, while moving it farther away from the sun resulted in a slower orbit. This is because the gravitational force between Earth and the sun is stronger when they are closer together, and weaker when they are farther apart. Therefore, the speed and shape of Earth's orbit are influenced by both the mass of the sun and the distance between Earth and the sun.

Overall, our observations suggest that the laws of universal gravitation played a crucial role in the formation and evolution of the Solar System, as they determine the dynamics of planetary motion and the stability of planetary orbits.

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For this section:

(d) To determine which acid would be completely dissociated when dissolved in water, consider the strength of the acid and its ability to ionize completely. Strong acids are those that ionize completely in water, while weak acids only partially dissociate.

Among the given options:

(H O)₂SO is sulfuric acid (H₂SO₄), which is a strong acid and completely dissociates in water.

(H O)IO₃ is iodic acid (HIO₃), which is also a strong acid and completely dissociates in water.

(H O)₂SO₂ is not a known acid and cannot be evaluated for dissociation.

HCO₂H is formic acid (HCOOH), which is a weak acid and only partially dissociates in water.

Therefore, the acids that would be completely dissociated when dissolved in water are (H O)₂SO and (H O)IO₃.

(e) To estimate the pH of the given solutions formed by titration, compare the moles of the acid and base used in the reaction.

(i) For the titration of 25.0 mL of 0.10 M aqueous NaOH with 25.0 mL of 0.10 M aqueous HCl, the reaction between a strong acid (HCl) and a strong base (NaOH) forms a neutral salt (NaCl) and water. The resulting solution would have a pH of 7, indicating neutrality.

(ii) For the titration of 25.0 mL of 0.10 M aqueous NaOH with 25.0 mL of 0.10 M aqueous acetic acid, consider the ionization of acetic acid and the formation of its conjugate base. The pKa of acetic acid is given as 4.76.

Since the volumes and concentrations of the acid and base are equal, we have a 1:1 mole ratio between them. This means that half of the acetic acid will be neutralized, and the remaining half will be in the form of the conjugate base (acetate ion, CH₃COO-). The resulting solution will be a buffer solution with a pH close to the pKa of acetic acid, which is 4.76.

(f) To predict the products formed from mixing the given reagents, we need to consider the reactions and the possible chemical reactions that occur.

(i) 3I₂ + PBr₃: This reaction involves the combination of iodine (I₂) with phosphorus tribromide (PBr₃). The balanced equation is:

3I₂ + 2PBr₃ → 6IBr + P₂

(ii) 4LiH + GaCl₃: This reaction involves the combination of lithium hydride (LiH) with gallium trichloride (GaCl₃). The balanced equation is:

4LiH + GaCl₃ → 4LiCl + GaH₃

(iii) NH₃ + BCl₃: This reaction involves the combination of ammonia (NH₃) with boron trichloride (BCl₃). The balanced equation is:

NH₃ + BCl₃ → NH₃BCl₃

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The empirical formula of the compound is C₂H₁₆S₂N₃O.

The moles of each element is as follows::

For CO₂:

Carbon (C) has a molar mass of 12.01 g/mol.

Oxygen (O) has a molar mass of 16.00 g/mol.

Moles of C in CO₂ = 2.08 g / 12.01 g/mol = 0.173 moles

Moles of O in CO₂ = 2.08 g / 16.00 g/mol = 0.130 moles

For H₂O:

Hydrogen (H) has a molar mass of 1.01 g/mol.

Oxygen (O) has a molar mass of 16.00 g/mol.

Moles of H in H₂O = 1.28 g / 1.01 g/mol = 1.27 moles

Moles of O in H₂O = 1.28 g / 16.00 g/mol = 0.080 moles

For SO₃:

Sulfur (S) has a molar mass of 32.06 g/mol.

Oxygen (O) has a molar mass of 16.00 g/mol.

Moles of S in SO₃ = 4.77 g / 32.06 g/mol = 0.149 moles

Moles of O in SO₃ = 4.77 g / 16.00 g/mol = 0.298 moles

For HNO₃:

Hydrogen (H) has a molar mass of 1.01 g/mol.

Nitrogen (N) has a molar mass of 14.01 g/mol.

Oxygen (O) has a molar mass of 16.00 g/mol.

Moles of H in HNO₃ = 3.48 g / 1.01 g/mol = 3.45 moles

Moles of N in HNO₃ = 3.48 g / 14.01 g/mol = 0.248 moles

Moles of O in HNO₃ = 3.48 g / 16.00 g/mol = 0.217 moles

The simplest whole-number ratio of the elements will be:

Carbon: 0.173 moles / 0.080 moles ≈ 2.16

Hydrogen: 1.27 moles / 0.080 moles ≈ 15.88

Sulfur: 0.149 moles / 0.080 moles ≈ 1.86

Nitrogen: 0.248 moles / 0.080 moles ≈ 3.10

Oxygen: 0.080 moles / 0.080 moles = 1

Therefore, the empirical formula is C₂H₁₆S₂N₃O.

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Answer

C.) slows down a reaction by increasing activation energy

Explanation

Inhibitors are compounds that modify the catalytic properties of the enzyme and, therefore, slow down the reaction rate, or in some cases, even stop the catalysis. Such inhibitors work by blocking or distorting the active site.

Inhibitors, on the contrary, increase the energy of activation of the reaction.

The correct option is

C.) slows down a reaction by increasing activation energy

Answer:

The answer is

Plant also use cellular respiration

Answer:

B - Plants also use cellular respiration.

Explanation:

Did the test.

The empirical formula of the compound is =NaSO2

This is the formula that analyses the different ratios of atoms in a compound in its simplest form.

To calculate the empirical formula use the least atom percentage ratio. That is,

\(na = \frac{36.5}{25.4} = 1.437\)

\(s = \frac{25.4}{25.4} = 1\)

\(o = \frac{38.1}{25.4} = 2\)

From the calculation, the ratio of the various atoms are

NaSO2

Therefore the empirical formula is NaSO2

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Answer: D) Eight

Just pretend this part doesn't exist nope nothing to see here the answer is correct on edge2020 I swear on my brainly points

Answer:

d

Explanation:

According to our reactions:

1) Li(s) + O2(g) ==> Li2O(s)

It is a Redox reaction, Li is oxidized and O is reduced. We have here loss and gain of electrons.

2) It is a precipitation reaction because when the PbI2 is formed, it precipitates.

3) This is the reaction of an acid with a base, so it is an acid/base reaction.

non-polar molecule because the chemical formula is in a tetrahedral form(O4) and the (Si) is in the centre. I hope this will help you

mole = 78.40/207.2

= 0.379 mol

1 mol = 6.02 × 10^23 atoms

0.379 mol = X

X = 0.379/1 × 6.02 × 10^23

= 6.296 × 10^-25 atoms

The molar mass is 3230.8 g/mol

First, we need to know that the formula for the general gas law  is represented as;

PV = nRT

such that the parameters are;

Substitute the values

1 × 2.33 = n × 8.314 × 433.15

Multiply the values, we get;

n = 2.33/ 8.314 × 433.15

Divide the values

n = 6.5 × 10⁻⁴ moles

But, number of moles = mass/molar mass

Molar mass = 2.10/ 6.5 × 10⁻⁴

Molar mass = 3230.8 g/mol

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Answer:

Benzoic acid is a stronger acid than phenol because the benzoate ion is stabilised by two equivalent resonance structures in which the negative charge is present at the more electronegative oxygen atom. ... Thus, the benzoate ion is more stable than phenoxide ion. Hence, benzoic acid is a stronger acid than phenol.