When a piece of copper is taken to the moon , a change will be observed in it's ?​

Answer:A

Explanation

B a compound can ha e the same properties as it’s elements

C water is H2O- Hydrogen and oxygen

D water is the most common compound

Therefore A must be correct

Answer:

proteins carbohydrates and fats

Explanation:

Answer:

Carbohydrates, Proteins, and Fats.

The man is center of mass of the man-board system is 1.25m.

Solution:

xcm = (20*0 + 60*5) / (60 + 20) = 300 / 80 = 3.75.

that means the total center of mass is at x=3.75. the distance from that point to where the man is standing is...

d = | xman - xcm | = | 5 - 3.75 | = 1.25.

A centroid is a defined position relative to an object or system of objects. This is the average position of all parts of the system weighted by mass. For a simple rigid body with uniform density, the centroid is at the centroid. The centroid can be calculated by taking the masses while trying to find the centroid and multiplying them by their position. Then sum them up and divide them by the sum of all the individual masses.

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Answer:

Cd(NO3)2 + Na2S --> CdS + 2 NaNO3

Explanation:

Answer: Initial velocity is independent of the slope of the graph; that is, the acceleration. An object thrown downward still accelerates after release at the same rate as an object that is dropped.

Explanation: hope this helps

No.

A stone has the SAME acceleration whether you throw it down, throw it up, throw it sideways, or just drop it.

YOU decide the stone's initial velocity, but it always has the same acceleration after it leaves your hand.

The unknown isotopes are (a) Thorium (b) Titanium (c) Boron (d) Nickel

what is radioactive isotope?

A chemical element in an unstable form that emits radiation as it decomposes and becomes more stable.

a. 228Th→224Ra 88+α

b. 207 Ti 81→207 Pb 82+e−

c. 7Be+e−→7B

d. 60Ni 28→60Ni 25+γ

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Incomplete dominance is a type of gene inheritance pattern in which a phenotype intermediate the two parents is observed. In the F2 generation, genotypic and phenotypic ratio of 1:2:1 (red: pink: white) is observed.

Incomplete dominance is a type of gene interaction in which both the alleles of a gene at a particular locus are partially expressed in the organism, this often results in an intermediate or different phenotype from the original parental phenotypes. It is also known as partial dominance.

In the cross between the two pink-flowered (RR') F1 plants, the offspring produced are in the F2 generation shows a genotypic and phenotypic ratio of 1:2:1 (RR: RR': R'R'). The phenotypes are 1 (red): 2 (pink): 1 (white). The punnett square is attached with the answer.

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The magnitude of the resulting acceleration of the block is (8), 14.5455 m/s²

Use Newton's second law to solve this problem:

ΣF = ma

where ΣF = net force acting on the block, m = mass of the block, and a = acceleration of the block.

Resolve the force of 87 N into its horizontal and vertical components.

F_horizontal = F cosθ = 87 cos 30° = 75.366 N

F_vertical = F sinθ = 87 sin 30° = 43.5 N

The net force in the horizontal direction is:

ΣF_horizontal = 29 N

Using ΣF = ma, find the acceleration:

a = ΣF / m = 29 N / 2 kg = 14.5 m/s²

Therefore, the magnitude of the resulting acceleration of the block is:

a = 14.5 m/s²

The answer is (8) 14.5455, which rounds to 14.5 m/s².

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The electric force between two or more charged objects depends on the charge and the distance between the charged objects

Coulomb's law states that the force of attraction or repulsion between two charged bodies is directly proportional to the product of the charges and inversely proportional to the square of the distance between them. Coulomb's law shows the relationship between the force , charge and the distance between the bodies

therefore F= kq1q2/r²

where q1 is the charge of body 1 and q2 is the charge of body 2. r is the distance between them and k is called electrostatics constant which have a value of 9,×10⁹ Nm²/C²

Therefore what can affect the force between two charges are the product of the charge of the two bodies and the distance between the two charge.

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Answer:

encyclopedia most reliable I think

Answer:

the answer is 173 m/s

Explanation:

the the sound traveled from the dog to the building and back to the dog in 0.5 seconds, every second passes the sound travels 346 m/s but if half a second passes then we divide 346 by 2 and get 173 m/s.

Use the work formula:

W = Fd

Replacing we have:

W = 1 N * 1 m

Resolving operation:

W = 1 J

The work efectuated is 1 Joule.

Answer:

this is just and example of how to solve it

Explanation:

need brainliest

Given:

The applied force is,

The mass of the object is,

The constant velocity of the object is,

To find:

The coefficient of friction between the object and the surface

Explanation:

The object is moving with a constant velocity which means the object is under equilibrium. So, the applied force is equal to the frictional force on the object.

If the coefficient of friction between the object and the surface is

we can write the frictional force as,

For equilibrium condition,

Hence, the coefficient of friction between the object and the surface is 0.47.

The acceleration of the skydiver is approximately +5.4 m/s².

We can use Newton's second law of motion, which states that the net force acting on an object is equal to its mass times its acceleration:

Net force = mass x acceleration

In this case, the net force is the force due to gravity minus the force due to air resistance:

Net force = force due to gravity - force due to air resistance

So we have:

(700 N) - (322 N) = (70 kg) x acceleration

Simplifying this equation, we get:

378 N = (70 kg) x acceleration

To find the acceleration, we can divide both sides by the mass:

acceleration = 378 N / (70 kg)

acceleration = 5.4 m/s²

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Given,

The length of the pipe, L=1.8 m

Speed of the sound, v=340 m/s

To form the standing wave with the longest wavelength, the number of nodes of the thus formed standing wave should be equal to 1.

The wavelength of the standing wave created in a closed-end pipe is given by,

On substituting the known values,

Thus the longest possible wavelength is 7.2 m

The frequency of this standing wave is given by,

On substituting the known values,

Thus the frequency of this standing wave is 47.22 Hz.

According to the data given in the question the net force on the box is of 5 N.

All of the forces that are applied to an object are added up to form the net force. As a consequence of the fact that it (force) is a vector and therefore that two forces with identical magnitudes and opposing directions cancel each other out, the resultant force is the total of the forces, or put another way, the net force is just the total of all the forces.

Given data :

Force on box to the left side (F1) = 15 N

Force on box to the right side (F2) = 20 N

Because both forces are in opposite direction

Hence,

Net force = F2 - F1

Net force = 20 - 15

Net force = 5 N.

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It will take 0.82sec to reach the edge of the table if the system is free to move. If mB=1.0 kg, 99 kg mA must be used if the system's acceleration is to be kept above 1/100 g.

(a) mA = 11 kg

mB = 7 kg

T = mA mB g / (mA+mB) = 77*9.8 / 18 = 41.92 N is the formula for cord tension.

In the case of mA, we have T = mA*a

acceleration of mA, a = T / mA = 41.92 / 11 = 3.81 m/s²

For mB, we have mB*a = mB*g - T a = (mB*g - T) / mB

                                  a = (7*9.8 - 41.92) / 7 = 3.81 m/s²

(b) Initial velocity of mA, u = 0

The distance traveled by mA, s = 1.3 m

We have,

\(s = u t + (1/2) a t^2\\ s = at^2 / 2\\ t = (2s / a)^(1/2) = (2*1.3 / 3.81) (1/2) = 0.82 sec\)

(c) mB = 1 kg

The system's acceleration, a = g/100

The system's acceleration is given by the formula a = mB*g / (mA+mB).

mA = [mB*g / a] - mB = [ 1*9.8*100/9.8 ] - 1 = 99 kg

Acceleration is the rate at which velocity changes with respect to time. It is a vector quantity whose magnitude denotes the amount of change in velocity per unit of time.

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According to given statement, the velocity of the second hockey puck after the collision is approximately -23 m/s.

To find the velocity of the second hockey puck after the collision, we can use the principle of conservation of momentum. According to this principle, the total momentum before the collision is equal to the total momentum after the collision.

Before the collision, the first hockey puck has a mass of 0.17 kg and is traveling to the right at 15 m/s. The second hockey puck has a mass of 0.11 kg, and we need to find its velocity after the collision.

The momentum of an object is calculated by multiplying its mass by its velocity. So, the momentum of the first hockey puck before the collision is:

Momentum of first hockey puck before collision = mass of first hockey puck x velocity of first hockey puck
Momentum of first hockey puck before collision = 0.17 kg x 15 m/s
Momentum of first hockey puck before collision = 2.55 kg·m/s

Since the first hockey puck comes to rest after the collision, its final momentum is zero:

Momentum of first hockey puck after collision = 0 kg·m/s

According to the principle of conservation of momentum, the total momentum before the collision (2.55 kg·m/s) is equal to the total momentum after the collision (0 kg·m/s). Therefore, we can set up an equation:

Total momentum before collision = Total momentum after collision

(0.17 kg x15 m/s) + (0.11 kg x velocity of second hockey puck) = 0 kg·m/s

Now we can solve for the velocity of the second hockey puck after the collision:

0.17 kg x 15 m/s + 0.11 kg x velocity of second hockey puck = 0 kg·m/s
2.55 kg·m/s + 0.11 kg x velocity of second hockey puck = 0 kg·m/s

To isolate the velocity of the second hockey puck, we can subtract 2.55 kg·m/s from both sides of the equation:

0.11 kg x velocity of second hockey puck = -2.55 kg·m/s

Then, divide both sides of the equation by 0.11 kg to solve for the velocity:

velocity of second hockey puck = -2.55 kg·m/s / 0.11 kg
velocity of second hockey puck ≈ -23.18 m/s

The velocity of the second hockey puck after the collision is approximately -23 m/s.

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To calculate the Taguchi quality cost, we need to multiply the length of each piece by the Taguchi parameter T, and then sum up the costs.

Given:

Length of the first metal rod = 49.19 cm

Length of the second metal rod = 49.93 cm

a) Taguchi parameter T:

Since we don't have the specific value of T, we cannot calculate it.

b) Taguchi Quality Cost of the second metal rod:

Taguchi Quality Cost = Length of the second metal rod * Taguchi parameter T

c) Taguchi Quality Cost of the first metal rod:

Taguchi Quality Cost = Length of the first metal rod * Taguchi parameter T

d) Total Taguchi Quality Cost of the two units:

Total Taguchi Quality Cost = Taguchi Quality Cost of the first metal rod + Taguchi Quality Cost of the second metal rod

Since we don't have the Taguchi parameter T, we cannot calculate the specific values for parts (b), (c), and (d).

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Explanation:

Atmospheric pressure decreases with increase in altitude,as we go higher the pressure within the blood vessels exceeds the outside pressure. This causes the blood vessels to rupture. As a result, a mountaineer suffer nose bleeding, ear bleeding etc.

The distance between the 7th and the tenth second is 29.4 m.

We know that we can have to formulate the information that has been given here so as to obtain a proper progression and this would help us to get the common difference of the progression that we are looking at.

Now we know that the progression would look something like; 4.9, 14.7, 24.5 ....

We can see that this is an arithmetic progression that has a common difference of 9.8.

U7 = a + (n - 1)d

a = first term

n = Number of terms

d = common difference

U7 = 4.9 + (7 - 1) 9.8

= 63.7

U10 = 4.9 + (10 - 1) 9.8

U10 = 93.1

Between the 7th and 10th seconds, we have;

93.1 - 63.7

= 29.4 m

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Answer: velocity is the study of how fast an object changes its place, or is displaced.

Explanation: An example would be how fast a basketball reaches the other side of a gym, the acceleration and speed are measured and calculated to find velocity

Answer:

λ = 5.85 x 10⁻⁷ m = 585 nm

f = 5.13 x 10¹⁴ Hz

Explanation:

We will use Young's Double Slit Experiment's Formula here:

\(Y = \frac{\lambda L}{d}\\\\\lambda = \frac{Yd}{L}\)

where,

λ = wavelength = ?

Y = Fringe Spacing = 6.5 cm = 0.065 m

d = slit separation = 0.048 mm = 4.8 x 10⁻⁵ m

L = screen distance = 5 m

Therefore,

\(\lambda = \frac{(0.065\ m)(4.8\ x\ 10^{-5}\ m)}{5\ m}\)

λ = 5.85 x 10⁻⁷ m = 585 nm

Now, the frequency can be given as:

\(f = \frac{c}{\lambda}\)

where,

f = frequency = ?

c = speed of light = 3 x 10⁸ m/s

Therefore,

\(f = \frac{3\ x\ 10^8\ m/s}{5.85\ x\ 10^{-7}\ m}\\\\\)

f = 5.13 x 10¹⁴ Hz

The angular velocity of the skater during the finale is 2.18 rad/s.

The conservation of angular momentum is a principle in physics that states that the total angular momentum of a system remains constant if no external torques act on the system. Mathematically, this can be expressed as L1 = L2, where L1 is the initial angular momentum of a system, L2 is the final angular momentum of the system, and the total torque acting on the system is zero. This principle is analogous to the conservation of linear momentum, which states that the total linear momentum of a system remains constant if no external forces act on the system. The conservation of angular momentum is an important principle in many areas of physics, including mechanics, electromagnetism, and quantum mechanics.

We can use the conservation of angular momentum to solve this problem. The initial angular momentum of the skater and the hand-arms is given by:

L1 = I1 * w1

where I1 is the moment of inertia of the skater's body, and w1 is the initial angular velocity. Since the hand-arms are extended, their moment of inertia can be neglected.

When the skater pulls their arms inward, the moment of inertia of the system decreases. The final moment of inertia is given by:

I2 = I1 + 2md^2

where m is the mass of each hand-arm, d is the distance of the hand-arm from the axis of rotation, and we multiply by 2 since there are two hand-arms.

The final angular velocity w2 can be found by equating the initial and final angular momentum:

L1 = I1 * w1 = I2 * w2

Substituting the expressions for I1, I2, and simplifying, we get:

w2 = w1 * I1 / (I1 + 2m(d2^2 - d1^2))

where d1 is the initial distance of the hand-arm from the axis of rotation (0.60 m), and d2 is the final distance of the hand-arm from the axis of rotation (0.20 m).

Substituting the given values, we get:

w2 = 0.50 m/s * 1.719 kgm^2 / (1.719 kgm^2 + 2 * 5.0 kg * (0.20 m^2 - 0.60 m^2))

w2 = 2.18 rad/s

Therefore, The skater's angular velocity during the grand finale is 2.18 rad/s.

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The values of all sub-parts have been obtained.

(1).  The maximum factored load the beam can withstand is 45.2 kN/m.

(2).  The moment resistance of the cross-section is 291735.65 Nm.

(3).  The factored moment demand is 27939.6 Nm

1) To draw the governing shear and bending moment diagram for the factored load, we need to first calculate the maximum factored load that the beam can withstand.

The maximum factored load on the beam is given by:

Dead Load = 20 kN/m + 15 kN

                   = 35 kN/m.

Live Load = 2 kN/m + 1 kN

                = 3 kN/m.

Total Factored Load = 1.2 x Dead Load + 1.6 x Live Load

                                  = 1.2 x 35 kN/m + 1.6 x 3 kN/m

                                  = 45.2 kN/m.

The maximum factored load the beam can withstand is 45.2 kN/m.

The shear force and bending moment diagrams for the given factored load can be obtained as shown below:

Shear Force Diagram:

Bending Moment Diagram:

2) To calculate the moment resistance of the cross-section, we can use the formula:

MR = σst A'(d - a/2) + 0.85f'c A''(d - a/2)

Where, σst = yield stress of tension steel [σst = fy / γst],

γst = safety factor for tension steel [γst = 1.15A']

A' = area of tension steel, [A'' = b(d - a)].

Where,

b = width of the beam [b = 600 mm],  

d = total height of the beam [d= 1000 mm],

a = effective depth of tension steel [a = 920 mm]

f'c = compressive strength of concrete [f'c = 25 MPa],

MR = σst A'(d - a/2) + 0.85f'c A''(d - a/2)

MR = (400 / 1.15) x 10 x (1000 - 920/2) + 0.85 x 25 x 590 x (1000 - 920/2)

MR = 291735.65 Nm

The moment resistance of the cross-section is 291735.65 Nm.

3) To check if this cross-section is adequately designed to resist the factored bending moment (LRFD), we need to calculate the factored moment demand and compare it with the moment resistance.

The factored moment demand is given by:

MF = ϕ x Mu

Where,ϕ = resistance factor = 0.9, Mu = factored bending moment

Mu = 1.2 x Dead Load x L2 / 8 + 1.6 x Live Load x L2 / 8 + 1.2 x (Dead Load + Live Load) x L2 / 2

   = 1.2 x 35 x 152 / 8 + 1.6 x 3 x 152 / 8 + 1.2 x 38 x 152 / 2

   = 31044 Nm

MF = ϕ x Mu

     = 0.9 x 31044

    = 27939.6 Nm

The factored moment demand is 27939.6 Nm, which is less than the moment resistance of the cross-section, i.e., 291735.65 Nm.

Therefore, this cross-section is adequately designed to resist the factored bending moment.

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The release height of the basketball is 0.05 m.

Projectile motion is a form of movement skilled by way of an item or particle that is projected in a gravitational area, which includes from Earth's floor, and actions alongside a curved route below the movement of gravity most effective.

Projectile motion is the motion of an item thrown (projected) into the air. After the initial force that launches the object, it best experiences the pressure of gravity. The item is known as a projectile, and its course is known as its trajectory.

The course of a projectile is parabolic. for the duration of the movement, the acceleration of the projectile is regular and acts vertically downwards being equal to g. The angular momentum of projectile = mu cos Θ × h wherein the price of h denotes the height.

calculation:-

angle with vertical  = 30°

So, the angle with the vertical = 60°

horizontal velocity = 3 cos 30° m/s

vertical velocity = 3 sin 30°  m/s  = 2 × 1/2

                          = 1 m/s

For height V² = U² -2aS

                0 = 1² - 2 ×9.8 × S

S = 1/19.6

   = 0.05 m

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Answer:

d

Explanation:

because it also depends upon accleration acting upon it