which molecules were nonpolar because all bonds were nonpolar

Answer:

B. Group 17

Explanation:

The element is Bromine. Its electron configuration is:

1s2 2s2p6 3s2p6d10 4s2p5  

You can see that its last orbital is 4p^5 for 5 electrons in the 4p orbital.

After one hour, the concentration of the chemical in the tank will be 4 g/L.

This is calculated by taking the initial concentration of 1500 g/L, subtracting the amount of chemical that flows into the tank (90 g/L), and subtracting the amount of chemical that flows out of the tank (60 g/L).

This results in a concentration of 1440 g/L, which is then divided by the volume of the tank (600 L) to get a final concentration of 4 g/L.

This can be calculated as follows:

1500 g/L - 90 g/L - 60 g/L = 1440 g/L

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Answer:

In Australia, it's warmer than most of the United States during winter.

Explanation:

The vapor pressure of a solution prepared by mixing 25 grams of methanol and 75 grams of ethanol at 20 degrees Celsius can be calculated using Raoult's law, which states that the vapor pressure of a component in a solution is directly proportional to its mole fraction.

To calculate the vapor pressure of the solution, we need to use Raoult's law, which is expressed as:

\(P_{total}\)= \(P_A\) ×   \(x_A\) +\(P_B\) ×   \(x_B\)

Where \(P_{total}\) is the vapor pressure of the solution, \(P_A\) and \(P_B\) are the vapor pressures of the individual components (methanol and ethanol in this case), and  \(x_A\) and  \(x_B\) are their respective mole fractions.

First, we need to calculate the mole fractions of methanol ( \(x_A\) ) and ethanol ( \(x_B\)) in the solution. To do this, we need to convert the masses of methanol and ethanol into moles using their molar masses. The molar mass of methanol \((CH_3OH)\) is 32.04 g/mol, and the molar mass of ethanol \((C_2H_5OH)\) is 46.07 g/mol.

Moles of methanol = 25 g / 32.04 g/mol

Moles of ethanol = 75 g / 46.07 g/mol

Next, we calculate the mole fractions:

\(x_A\) = Moles of methanol / (Moles of methanol + Moles of ethanol)

\(x_B\) = Moles of ethanol / (Moles of methanol + Moles of ethanol)

Now that we have the mole fractions, we can substitute them into Raoult's law to calculate the vapor pressure of the solution:

\(P_{total}\) = 92 torr × \(x_A\) + 45 torr ×  \(x_B\)

Substituting the calculated values of \(x_A\) and \(x_B\) will give us the vapor pressure of the solution at 20 degrees Celsius.

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Answer:

the spin quantum number.

The tert-butyl cation, (CH₃)₃C⁺, has a trigonal planar geometry around the central carbon atom. The carbon atom is bonded to three methyl (CH₃) groups, which are arranged in a symmetrical manner around the central carbon atom. The bond angles between the carbon atom and the three methyl groups are approximately 120 degrees.        

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Explanation:

2000 J = .870 J/(g C) * 10 g *  d        where d is the degree change

2000/ (.870 *10) = d = ~230 C

The total amount of heat : 225.704 kJ

Heat of vaporization(ΔH vap) : heat needed to vaporize 1 mole of water , units : kJ/mol

For water at boiling point (100 °C) : ΔH vap = 40.66 kj/mol

mole of 100 g water :

\(\tt \dfrac{100}{18.015}=5.551\)

so total Heat :

\(\tt 40.66\times 5.551=225.704~kJ\)

Answer:

2.43 grams are needed

Explanation:

I did the test

Hope this helps :)

Answer:

75 g/dm³

Explanation:

The following data were obtained from the question:

Mass of solute (NaCl) = 15 g

Volume of solution = 200 cm³

Concentration (in g/dm³) =?

Next, we shall convert 200 cm³ to dm³. This can be obtained as follow:

1000 cm³ = 1 dm³

Therefore,

200 cm³ = 200 cm³ × 1 dm³ / 1000 cm³

200 cm³ = 0.2 dm³

Thus, 200 cm³ is equivalent to 0.2 dm³.

Finally, we shall determine the concentration of the solution as follow:

Mass of solute (NaCl) = 15 g

Volume of solution = 0.2 dm³

Concentration (in g/dm³) =?

Concentration (in g/dm³) = mass / volume

Concentration (in g/dm³) = 15 g /0.2 dm³

Concentration (in g/dm³) = 75 g/dm³

Matter are anything that is made up of atoms. The quantity of matter can be observed only on the basis of mass and volume calculation. Therefore, by transferring electron or sharing electrons,  particles combine to form the variety of matter.

Matter is a substance that has some mass and can occupy some volume. The matter is mainly used in science. Matter can be solid, liquid or gas.

So as we saw that matter has some mass so mass can be measured in gram only. Mass can also be represented as number of molecules. We also saw that matter occupy some volume and that volume is measured only in liter. By transferring electron or sharing electrons,  particles combine to form the variety of matter.

Therefore, by transferring electron or sharing electrons,  particles combine to form the variety of matter.

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Answer:

Moles= 11/44 = 0.25 molesof CO2. Click to see full answer Considering this, how many moles of carbon are in 1 mole of co2? A mole of CO2molecules (we usually just say “a mole of CO2”) has one moleof carbonatoms and two molesof oxygen atoms.

Exxplanation:

Answer:

1.2 mol

Explanation:

26.8L x 1mol/22.4L = 1.2 mol

Answer:

2Mg+O2=2MgO

Atomic number of Mg and O is equal in both side

Oxyfuel gas process is the most popular method used to cut metals. It involves burning oxygen and gas to melt the metal. The molten metal is then blown away by the compressed gas, resulting in a clean cut. The process is used on metals such as mild steel, cast iron, and wrought iron, to name a few.

Mild steel is the most popular type of metal cut with oxyfuel gas processes. The reason behind this is that it is the least expensive, making it perfect for low-cost jobs. The metal is also easy to weld, making it the go-to material for a wide range of construction applications. Cast iron is another type of metal that is commonly cut using oxyfuel gas processes. It is widely used in engine blocks, pipe fittings, and hydraulic equipment.

Finally, wrought iron is another type of metal that is commonly cut using oxyfuel gas processes. This metal is widely used in fences, gates, railings, and other ornamental structures. In conclusion, the oxyfuel gas process can cut a wide range of metals such as mild steel, cast iron, and wrought iron.

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The balanced chemical equation for the reaction between butane and oxygen to form carbon dioxide and water is shown below.2 C4H10(g) + 13 O2(g) → 8 CO2(g) + 10 H2O(g)We need to calculate the theoretical yield of water formed from the reaction of 2.91 g of butane and 13.5 g of oxygen gas.

To do this, we need to determine which of the two reactants is limiting and then use stoichiometry to calculate the amount of water produced. Butane reacts with oxygen in a ratio of 2:13. Therefore, to calculate the amount of oxygen needed to react with 2.91 g of butane, we use the following calculation: moles of butane = mass / molar mass = 2.91 g / 58.12 g/mol = 0.05 mol The moles of oxygen required = 0.05 mol × (13 mol of O2 / 2 mol of butane) = 0.325 mol So, the limiting reactant is oxygen because there is less of it than required. Using the stoichiometric ratio of the balanced chemical equation, we know that 10 mol of water is produced for every 13 mol of oxygen consumed.

Therefore, the number of moles of water produced can be calculated as follows: number of moles of water = 0.325 mol × (10 mol of H2O / 13 mol of O2) = 0.25 mol The mass of water produced can be calculated using its molar mass: mass of water = number of moles × molar mass = 0.25 mol × 18.02 g/mol = 4.505 g The theoretical yield of water formed from the reaction of 2.91 g of butane and 13.5 g of oxygen gas is 4.505 g of water.

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Answer:

3HCl + Cr (HCO3)3 --> CrCl3 + 3CO2 + 3H2O

Answer:1. Introduction

The main air pollutants are represented by gases forms, particles in suspension, different ionizing radiation and noise.

The gases forms are: oxidized and reduced forms of carbon (CO2, CO, CH4), of nitrogen (NO2, NO, N2O4, NH3, NH4+), SO2, O3, C6H6 vapours, Hg, volatile phenols, Cl2, etc.

The particulate forms are: PM10 and PM2.5 particulate matter, heavy metals with toxic effect (Pb, Ni, Cd, As), polycyclic aromatic hydrocarbons PAHs, etc.

Atmospheric pollutants have a negative effect on the plants; they can have direct toxic effects, or indirectly by changing soil pH followed by solubilization of toxic salts of metals like aluminum. The particulate matters have a negative mechanical effect. They cover the leaf blade reducing light penetration and blocking the opening of stomata. These impediments influence strongly the process of photosynthesis which rate declines sharply.

Explanation:

Answer:

A More air pollution because there are fewer trees to take in carbon dioxide

C Fewer birds and other wildlife because they have fewer places to live

Explanation:

I took the test on A P E X

Answer:

precipitation is when water flows into the ground

Explanation:

.................

The measured volume of hydrogen gas will be too high.

The volume of hydrogen is measured by collecting the gas over water. The volume of the gas is measured as the volume of water displaced by the gas in an inverted container.

When air leaks into the graduated cylinder, more volume of water is displaced hence a higher volume of hydrogen gas is measured.The calculated molar volume of hydrogen will be too high as a result of this error

The gas being recorded during the experiment would not only include hydrogen gas, but the air that leaked into the eudiometer tube as well. This leads to the increase in the volume of hydrogen gas which will be too high.

Since the volume of hydrogen is too high, therefore the calculated molar volume of hydrogen would also be too high.

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Answer: Polar bond

Explanation:

Answer:

6.94 amu

Explanation:

Step 1: Given data

Step 2: Calculate the average atomic mass (aam) of Li

We will use the following expression.

aam = m⁶Li × ab⁶Li + m⁷Li × ab⁷Li

aam = 6.0151223 amu × 0.075 + 7.0160041 amu × 0.925

aam = 6.94 amu

Answer:Transcript A liquid’s vapor pressure is directly related to the intermolecular forces present between its molecules. The stronger these forces, the lower the rate of evaporation and the lower the vapor pressure.

Explanation:

As vapors are produced more from a liquid there will be more cooling effect as vapors are inversely proportional to the boiling point that means lesser the boiling point better will be the evaporation.

Intermolecular forces are the forces present between the molecules and liquid’s vapor pressure is directly related to the intermolecular forces as well . The stronger these forces, the lower the rate of evaporation and the lower the vapor pressure.

Therefore, the relationship between the vapor pressure of a liquid and how well it cools by evaporation is having direct proportionality.

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Answer:

Explanations:

Given the following electronegativity of three elements as:

The order of strongest to weakest is as follows hydrogen bonds, dipole-dipole forces and dispersion forces. The strongest intermolecular forces are hydrogen bonds.

The high boiling point of water is a result of this connection. These bonds are crucial to the structure of both synthetic and organic polymers. Water, or H2O, is an illustration of a hydrogen bond.

Due to the persistent polarity of molecules that exists between polar molecules at the tail and head of the molecule itself, dipole-dipole forces are rather weak. Hydrochloric acid, also known as HCL, is an illustration of dipole-dipole forces.

The momentary generated dipole that causes an unequal electron density makes dispersion forces the weakest intermolecular interactions. Methane or molecules containing CH4 are an illustration of dispersion force.

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The immediate by-product of photosynthesis in plants and algae is O2 (oxygen).

In plants and algae, the immediate by-product of photosynthesis is O2, or molecular oxygen. During the process of photosynthesis, plants and algae capture light energy and use it to convert carbon dioxide (CO2) and water (H2O) into glucose (C6H12O6) and oxygen (O2). This process occurs in the chloroplasts of plant cells, specifically in the thylakoid membranes where the light-dependent reactions take place.

The overall equation for photosynthesis can be represented as:

6 CO2 + 6 H2O + light energy → C6H12O6 + 6 O2

In this equation, O2 is produced as a by-product. It is released into the atmosphere or dissolved in water, depending on the organism. The release of oxygen is essential for sustaining life on Earth as it contributes to the oxygen levels in the atmosphere and supports aerobic respiration in organisms that rely on oxygen for energy production.

Starch (a complex carbohydrate) is not an immediate by-product of photosynthesis but rather a storage form of glucose. Glucose produced during photosynthesis is converted into starch for long-term storage in plants. Starch is stored in various plant parts, such as roots, stems, and seeds, and can be broken down back into glucose when energy is needed.

H+ (hydrogen ions) are involved in the proton gradient formation during the light-dependent reactions of photosynthesis. They play a crucial role in generating ATP (adenosine triphosphate), the energy currency of cells.

CO2 (carbon dioxide) is one of the reactants in photosynthesis. It is taken up from the atmosphere and converted into glucose through a series of enzymatic reactions.

To summarize, this oxygen is released into the environment and is essential for supporting aerobic respiration and maintaining oxygen levels in the atmosphere. Starch, glucose, H+, and CO2 are all involved in photosynthesis but are not the immediate by-products.

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Answer:

I. Concrete sidewalks

Explanation:

One of the factor that affects the infiltration of water into the surface of the soil is the use of concrete sidewalks.

Concrete is impermeable and non - porous media

When concrete pavements are used, water will not be able to move into the ground. They run on the surface and collects into nearby streams and water bodies.

Answer:

The volume of the gas at 200 mmHg will be 2 L.

Explanation:

As the volume increases, the gas particles (atoms or molecules) take longer to reach the walls of the container and therefore collide with them fewer times per unit of time. This means that the pressure will be lower because it represents the frequency of collisions of the gas against the walls. In this way pressure and volume are related, determining Boyle's law which says:

"The volume occupied by a certain gaseous mass at constant temperature is inversely proportional to pressure"

Boyle's law is expressed mathematically as:

P * V = k

Now it is possible to assume that you have a certain volume of gas V1 that is at a pressure P1 at the beginning of the experiment. If you vary the volume of gas to a new value V2, then the pressure will change to P2, and it will be fulfilled:

P1 * V1 = P2 * V2

In this case:

Replacing:

800 mmHg* 500 mL= 200 mmHg* V2

Solving:

\(V2=\frac{800 mmHg* 500 mL}{200 mmHg}\)

V2= 2,000 mL= 2 L (being 1,000 mL=1 L)

The volume of the gas at 200 mmHg will be 2 L.