Which of Maxwell's equations can be used, along with a symmetry argument, to calculate the electric field of a point charge? ds B.dA B.dA ED po I 6. B.dA I uo eo 10. E.ds
Answers
To calculate the electric field of a point charge, we can use Gauss's Law, which is one of Maxwell's equations.
Specifically, we can use the integral form of Gauss's Law, which states that the electric flux through a closed surface is proportional to the charge enclosed within the surface. By assuming symmetry of the charge distribution, we can choose a Gaussian surface that is also symmetric, such as a sphere or a cylinder. This allows us to simplify the integral and solve for the electric field at any point outside the charge distribution. So, in summary, we can use Gauss's Law, along with a symmetry argument, to calculate the electric field of a point charge.
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Related Questions
Due to our ozone layer, ultraviolet astronomy must be done from space, true or false?
Answers
True, due to the protective nature of the ozone layer and the absorption of UV radiation, conducting ultraviolet astronomy from space is necessary to gather accurate and detailed data about celestial objects and phenomena emitting UV light.
The ozone layer plays a crucial role in protecting the Earth's surface from harmful ultraviolet (UV) radiation. It absorbs a significant portion of the Sun's UV rays, preventing them from reaching the surface and potentially causing damage to living organisms.
As a result, to observe and study ultraviolet astronomy, which involves the detection and analysis of celestial objects and phenomena emitting UV radiation, observations must be conducted from space. By observing from space, astronomers can bypass the Earth's atmosphere, including the ozone layer, and directly capture the UV light from celestial sources.
UV astronomy satellites and telescopes, such as the Hubble Space Telescope and the International Ultraviolet Explorer (IUE), have been specifically designed and deployed to conduct observations in the ultraviolet spectrum. These instruments are situated above the Earth's atmosphere, enabling them to capture and analyze UV radiation without interference from atmospheric absorption.
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How many sulfur atoms are there in 25 molecules c4h4s2?.
Answers
10. Annabelle walks to school every day from her house.
The diagram below shows the distance from her house to
school measured in 1 km increments. If it takes her 30
minutes to walk to school, what was her average speed?
Answers
Answer:
A
Explanation:
A race car has a velocity of 382 km/h to the right. If the car’s mass is 705 kg and the driver’s mass is 65 kg, what force is needed to bring the car and driver to a stop in 12.0 s? What is the car’s stopping distance?
Answers
Answer:
Given: Vi = 382 km/h, Vf = 0 km/h, Mc = 705 kg, Md = 65 kg, Δt = 12
Required: Δx
F = Δp / Δt
= \(\frac{(Mc+Md)Vf-(Mc+Md)Vi}{t} \\\\= 6.81 * 10x^{3} N [left]\\\\x=\frac{1}{2} (Vi+Vf)\\ \\ = 637m[right]\)
A physics teacher is designing a ballistics event for a science competition. The ceiling is 3.00m high, and the maximum velocity of the projectile will be 20m/s.
What is the maximum that the vertical component of the projectiles initial velocity could have?
Answers
The launch proyectiles of kinematics allows to find the maximum initial vertical velocity of the body so that it just reaches the ceiling
v_{oy} = 2.56 m / s
Given parameters
The ceiling height y = 3 mTo find
Maximum vertical speed
Projectile launching is an application of kinematics where on the x axis there is no acceleration or and on the y axis the acceleration is the acceleration of gravity (g = 9.8 m / s ^ 2)
In this case, the maximum vertical velocity that the body can have occurs when the velocity on the ceiling is zero.
v_y² = v_{oy}² - 2 g y
where v and v_{oy} are the initial velocity at the ceiling e initial, respectively, g the acceleration of gravity e and the height
0 = v_{oy}² - 2 g y
v_{oy} = \(\sqrt{2gy}\)
v_{oy} = \(\sqrt{2 \ 9.8 \ 3}\)
v_{oy} = 2.56 m / s
In conclusion with the kinematic of launch projectiles we can find the maximum initial vertical velocity of the body so that it just reaches the ceiling
v_{oy} = 2.56 m / s
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When it is winter in the Northern Hemisphere, it is summer in the Southern Hemisphere. Which statement best explains the reason for this situation?
Group of answer choices
A) When the Northern Hemisphere is closer to the sun than the Southern Hemisphere is, the Southern Hemisphere is relatively far from the sun.
B) When the Northern Hemisphere is tilted toward the sun, the Southern Hemisphere is tilted away from the sun.
C) When the Northern Hemisphere is farther from the sun than then Southern Hemisphere is, the Southern Hemisphere is relatively close to the sun.
D) When the Northern Hemisphere is tilted away from the sun, the Southern Hemisphere is tilted toward the sun.
Answers
Explanation::i dont know the answer ,but pls then also mark me as brainlist
Answer:
When the N. Hemisphere is tilted away from the sun, the S. Hemisphere is tilted toward the sun
Explanation:
Unlike the idiot down there that just wanted point here you go
Tripling the tension in a guitar string will change its natural frequency by what factor?
A. 3^ 1/2
B. 1.5
C. 3^ -1/2
D. 3
Answers
Tripling the tension in a guitar string will change its natural frequency by a factor of A. \(3^1^/^2\)
The natural frequency of a vibrating string, like a guitar string, is determined by its tension, length, and mass per unit length. This relationship is given by the formula:
f = (1/2L) × √(T/μ)
where f is the natural frequency, L is the length of the string, T is the tension, and μ is the mass per unit length.
Now, let's consider the case when the tension is tripled. Let f₁ be the original frequency and f₂ be the new frequency after tripling the tension. We have:
f₁ = (1/2L) × √(T/μ)
f₂ = (1/2L) × √(3T/μ)
To find the factor by which the natural frequency changes, divide f₂ by f₁:
(f₂ / f₁) = [√(3T/μ)] / [√(T/μ)] = √(3T/μ)×√(μ/T) = √3
So, tripling the tension in a guitar string will change its natural frequency by a factor of √3, which corresponds to option A. \(3^1^/^2\) .
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An ostrich is running with a velocity of 12.3 m/s and speeds up to 15.9
m/s in 5.2 seconds. What is the ostrich's acceleration?
A 0.69 m/s2
B 1.4 m/s2
C -0.69 m/s2
D -1.4 m/s2
Answers
The acceleration of the ostrich when running from 12.3 m/s to 15.9 m/s in 5.2 seconds is 0.69 m/s².
What is acceleration?This can be defined as the rate of change of velocity.
To calculate the acceleration of the ostrich, we use the formula below.
Formula:
a = (v-u)/t............ Equation 1Where:
a = Acceleration of the ostrichv = Final velocityu = Initial velocityt = TimeFrom the question,
Given:
v = 15.9 m/su = 12.3 m/st = 5.2 secondsSubstitute these values into equation 1
a = (15.9-12.3)/5.2a = (3.6)/5.2a = 0.69 m/s²Hence, the acceleration of the ostrich is 0.69 m/s². The right option is A. 0.69 m/s².
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how much does it cost to light six 100w light bulbs for six hours if the price of electrical energy is $0.09/kwh?
Answers
It will cost 0.324 Dollars to light six 100w light bulbs for six hours if the price of electrical energy is $0.09/ kwh.
kwh is commercial unit of electric energy. 1 unit= 1 kwh.
When 100 w power device is run for 1 hour, the amount of electrical energy consumed is 1 kwh.
We will find total units of electrical energy consumed in the given question.
energy consumed by 6 bulbs = 6×100= 600 w( joules per second).
The value in kwh is = 600÷1000
= 0.6kwh
Total energy consumed in 6 hours is = 0.6×6 = 3.6 kwh
So, the cost is = 3.6×0.09 = 0.324 dollars.
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If the distance between us and a star is doubled, with everything else remaining the same, the luminosity If the distance between us and a star is doubled, with everything else remaining the same, the luminosity remains the same, but the apparent brightness is decreased by a factor of two. is decreased by a factor of four, but the apparent brightness remains the same. is decreased by a factor of two, and the apparent brightness is decreased by a factor of two. remains the same, but the apparent brightness is decreased by a factor of four. is decreased by a factor of four, and the apparent brightness is decreased by a factor of four.
Answers
Answer:
The luminosity remains the same, but the apparent brightness is decreased by a factor of four.
Explanation:
The apparent brightness, F = L/4πr² where L = luminosity and r = distance between us and the star.
Since L is independent of the distance between us and the star, it is constant, then
F ∝ 1/r²
So, F₁/F₂ = r₂²/r₁² where F₁ = apparent brightness at r₁ and F₂ = apparent brightness at r₂
If the distance is doubled, that is r₂ = 2r₁, then
F₁/F₂ = r₂²/r₁²
F₁/F₂ = (2r₁)²/r₁²
F₁/F₂ = 4r₁²/r₁²
F₁/F₂ = 4
F₂ = F₁/4
So, since the luminosity is constant, the luminosity remains the same, but the apparent brightness is decreased by a factor of four.
what is the frequency (s-1) of electromagnetic radiation that has a wavelength of 0.53 m?
Answers
The frequency of electromagnetic radiation with a wavelength of 0.53 m is 5.66 x 10^8 s-1.
The frequency (s-1) of electromagnetic radiation that has a wavelength of 0.53 m can be calculated using the equation: frequency = speed of light/wavelength.
The speed of light is a constant value of approximately 3.00 x 10^8 m/s.
Therefore, the frequency can be calculated as follows:
frequency = (3.00 x 10^8 m/s) / (0.53 m)
frequency = 5.66 x 10^8 s-1
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73. A small soap factory in Laguna supplies soap containing 30% water to a local hotel at P373 per 100 kilos FOB. During a stock out, a different batch of soap containing 5% water was offered instead.
Answers
The new cost of the soap containing 5% water would be cheaper. However, it is important to note that the new batch of soap may not have the same quality as the original batch containing 30% water. The hotel may also not be satisfied with the quality of the new batch and may choose to switch suppliers.
In the case of a small soap factory in Laguna that supplies soap containing 30% water to a local hotel at P373 per 100 kilos FOB and then experiencing a stock out, the factory may provide a different batch of soap containing 5% water. This will change the cost of the soap. The cost of the soap containing 30% water is calculated using:P373 per 100 kilos = (30% x 100 kilos) water + (70% x 100 kilos) soap= 30 kilos water + 70 kilos soap Therefore, the cost of the soap component is:P373/70 kilos soap = P5.33/kilo soapOn the other hand, if the soap contains 5% water, the cost of the soap will change. The cost of the soap component in this case would be:P373/95 kilos soap = P3.93/kilo soap. Therefore, the new cost of the soap containing 5% water would be cheaper. However, it is important to note that the new batch of soap may not have the same quality as the original batch containing 30% water. The hotel may also not be satisfied with the quality of the new batch and may choose to switch suppliers.
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i will mark brainliest if you get it right.
Answers
Answer:
Satellite D
Explanation:
It has more mass
what is the relationship between harmonics and resonance frequency in a piano
Answers
Most vibrating objects have more than one resonant frequency and those used in musical instruments typically vibrate at harmonics of the fundamental. A harmonic is defined as an integer (whole number) multiple of the fundamental frequency.
There is direct relationship between harmonics and resonance frequency.
A harmonic is a wave with a frequency that is a positive integer multiple of the frequency of the original wave whereas, resonance frequency is the frequency at which the oscillation reaches to its maximum point. The lowest resonant frequency is known as the fundamental, while on the other hand, the higher resonant frequencies are called overtones. All resonant frequencies are multiples of the fundamental, and are called harmonics. So we can conclude that there is a direct relationship between harmonics and resonance frequency.Learn more about harmonic here: https://brainly.com/question/17315536
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A car burns 3 x 10^5 J of fuel (chemical energy) per
second. It has 1.3 x 10^5 J of kinetic energy and gains
0.7 x 10^5 J of gravitational potential energy as it goes
up a slope. How much energy transfers away from
the car through thermal energy transfer? Assume that
acceleration due to gravity g = 10 m/s².
Answers
The total energy of the car is the sum of its kinetic energy, potential energy, and chemical energy:
Total energy = Kinetic energy + Potential energy + Chemical energy
Total energy = 1.3 x 10^5 J + 0.7 x 10^5 J + 3 x 10^5 J
Total energy = 5 x 10^5 J
Since energy cannot be created or destroyed, the total energy of the car must remain constant. Any energy that is not accounted for in the car's kinetic, potential, or chemical energy must be transferred away from the car through thermal energy transfer. Therefore, the thermal energy transfer can be calculated as:
Thermal energy transfer = Total energy - (Kinetic energy + Potential energy + Chemical energy)
Thermal energy transfer = 5 x 10^5 J - (1.3 x 10^5 J + 0.7 x 10^5 J + 3 x 10^5 J)
Thermal energy transfer = 0.9 x 10^5 J
Therefore, 0.9 x 10^5 J of energy transfers away from the car through thermal energy transfer.
A freight train is traveling 150 km east to the nearest lumber yard. It took the train 3 hours to arrive. At what velocity is the train traveling
Answers
Answer:
2 • – 4
Explanation:
BUUUUUUUUU
how can you convert 54 grams to kilograms
Answers
Answer:
0.054 kilograms
Explanation:
divide 54 by 1000
so, 54/1000=0.054 kilograms.
Astronomers and physicists now believe they know what is happening to the missing neutrinos from the Sun (the neutrinos that our theories say should be emerging from the Sun, but our experiments in that underground mine could not find). These neutrinos are:
Answers
The missing neutrinos from the sun had merely tranformed into muon and tau neutrinos escaped detection.Hardly interacting with other matter,neutrinos comes in three different types electron,muon,and tau.
Hence option (b) turning into different type of neutrino in a neutrino oscillation is correct
Disclaimer:The question given on the portal is incomplete .Here is the complete question .
Question :Astronomers and physicists now believe they know what is happening to the missing neutrinos from the Sun (the neutrinos that our theories say should be emerging from the Sun, but our experiments in that underground mine could not find). These neutrinos are:
a)not being produced by the Sun because our star's nuclear fusion period has ended
b)turning into a different type of neutrino in a neutrino oscillation
c)being converted to antimatter in the core of the Sun and being destroyed as they hit matter
d)changing course before they reach the Earth as they hit other neutrinos in space
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Rough Surface with: Ms = 0. 8 HK = 0. 4
(a) Find the magnitude of the
force F needed to prevent the
book from sliding down the
rough wall.
F
M = 1. 5 kg
600
(b) Find the minimum force F
needed to set the book in
motion up the rough wall with
constant velocity
Answers
a) The magnitude of the force F needed to prevent the book from sliding down the rough wall is 6 N.
b) The minimum force F needed to set the book in motion up the rough wall with constant velocity is 6 N, which is equal to the force of friction acting on the book.
a) To find the magnitude of the force F needed to prevent the book from sliding down the rough wall, we need to consider the forces acting on the book. There are two forces acting on the book: the force of gravity, which pulls the book downward with a force of mg = (1.5 kg)(9.81 m/s^2) = 14.715 N, and the force of friction, which acts in the opposite direction of motion.
The force of friction can be calculated using the formula:
f = μN
where μ is the coefficient of friction (js = 0.8), and N is the normal force acting perpendicular to the surface of the wall. Since the wall is at an angle of 60 degrees to the horizontal, the normal force can be calculated as:
N = mg cos θ = (1.5 kg)(9.81 m/s^2) cos 60° = 7.5 N
Substituting the values, we get:
f = μN = (0.8)(7.5 N) = 6 N
Since the book is not moving, the force F acting on it must be equal and opposite to the force of friction, i.e., F = f = 6 N.
Therefore, the magnitude of the force F needed to prevent the book from sliding down the rough wall is 6 N.
b) To find the minimum force F needed to set the book in motion up the rough wall with constant velocity, we need to consider the forces acting on the book again. Since the book is moving with constant velocity, the net force acting on it must be zero. Therefore, the force of friction must be equal and opposite to the force F applied to the book.
The force of friction can be calculated as before, using the formula:
f = μN = (0.8)(7.5 N) = 6 N
To find the minimum force F needed to set the book in motion up the wall, we need to overcome the force of friction. Therefore, we need to apply a force greater than or equal to the force of friction. If we apply a force slightly greater than 6 N, the book will start moving up the wall with an acceleration
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The given question is incomplete, the complete question is:
Rough Surface with: js = 0.8 HK = 0.4 (a) Find the magnitude of the force F needed to prevent the book from sliding down the rough wall m= 1.5kg , θ=60degree b)Find the minimum force F needed to set the book in motion up the rough wall with constant velocity
Two liquids A and B of relative densities 0.7 and 0.4 respectively are mixed with water, kl. How will the mixture. arrangement occur in a given container?
Answers
The liquid A is present lower in the container as compared to liquid B due to more weight.
How will the mixture. arrangement occur in a given container?If two liquids A and B of relative densities 0.7 and 0.4 respectively then the lower density liquid remain at the top and higher density solution which is liquid A remains lower in the container because higher density solution has more weight.
So we can conclude that the liquid A is present lower in the container as compared to liquid B due to more weight.
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why is there no reflection formed when light is absent?
Answers
Explanation:
Because there is no light to be reflected. Reflection is the process of bouncing back of the light but since there is no light then nothing will be reflected.
It is correct .
The light is not reflected by the mirror in a dark room due to which no image is formed.
What are shadows?A shadow is a dark area where light from a light source is blocked by an opaque object.It occupies all of the three - dimensional volume behind an object with light in front of it. The cross section of a shadow is a two - dimensional silhouette, or a reverse projection of the object blocking the lightGiven is that no reflection is formed when light is absent.
We will not see our reflection in mirror in a dark room because an image is formed only when the light gets reflected by the mirror whereas in a dark room, there is no light to cause reflection hence, no image will be formed
Therefore, the light is not reflected by the mirror in a dark room due to which no image is formed.
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The ocean's level is currently rising at about
3 mm per year.
At this rate, in how many years will sea
level be 5 m higher than now?
Answer in units of y.
Answers
Answer:
The sea level will be 5m higher in 1667 y (years)
Explanation:
From the question, the rate at which the ocean's level is currently rising is about 3mm per year.
First, we will convert mm (millimeter) to m (meter)
1 mm = 0.001 m
Then,
3 mm = 3 × 0.001 m
= 0.003m
That is, the rate at which the ocean's level is currently rising is about 0.003m per year.
Now, to determine how long it will take for the ocean's level be 5 m higher than now at the given rate,
If the ocean rises 0.003 m in 1 year, then
the ocean will rise 5 m in x years
x = (5 m × 1 year) / 0.003 m
x = 5 / 0.003
x = 1666.67 years
x ≅ 1667 years
Hence, the sea level will be 5m higher in 1667 y (years)
A roller coaster car travelling at speed N traverses a vertical circular loop. It leaves the track at the point shown in the figure and becomes a projectile. How far (measured from the point directly below the center of the loop) does the car strike the ground. Assume: r = 20 m N = 10 m/s What is the angle theta when the car leaves the track? What is the horizontal distance R' from a point directly below the center of the loop to the impact point
Answers
20.94 m is the horizontal distance R' from a point directly below the center of the loop to the impact point.
When the car leaves the track, it moves along a straight line tangent to the loop, forming a tangent. From the given information, it is observed that the radius of the loop is 20 m and the speed is 10 m/s. In the given diagram, θ represents the angle made by the line joining the center of the circle and the point where the car leaves the track. Let’s answer the given questions.
Step 1: Find the angle θ
Using the formula,v² = rg
From the given information,N² = rgN²
= 20g(g
= 9.8 m/s²)θ
= sin⁻¹(N²/rg)θ
= sin⁻¹((10)²/20(9.8))θ
= 49.03°
Step 2: Find the horizontal distance R
'The horizontal distance from a point directly below the center of the loop to the impact point can be found using the formula
,R' = (2r + h) tan(θ/2)
where h is the height of the center of the loop from the ground.
R' = (2 × 20 + 0.6) tan(49.03/2)
R' = (40 + 0.6) tan(24.51)
R' = (40.6) (0.516)
R' = 20.94 m
Therefore, the angle θ when the car leaves the track is 49.03° and the horizontal distance R' from a point directly below the center of the loop to the impact point is 20.94 m.
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A truck with 30 -in. -diameter wheels is traveling at 55mi/h. Find the angular speed of the wheels in rad/min? rad/min How many revolutions per minute do the wheels make? rpm.
Answers
The angular speed of the wheels is approximately 403.47 rad/min, and the wheels make approximately 387.68 revolutions per minute (rpm).
To find the angular speed of the wheels in rad/min, we need to convert the linear speed of the truck to angular speed. The linear speed of the truck is given as 55 mi/h. We know that the distance traveled on the circumference of a circle is equal to the product of the radius and the angle in radians subtended by the arc. In this case, the distance traveled on the circumference of the wheels is equal to the linear speed multiplied by the time taken.
We can calculate the radius of the wheels by dividing the diameter by 2, which gives us 15 inches. Converting the linear speed from miles per hour to inches per minute, we get (55 mi/h) * (5280 ft/mi) * (12 in/ft) / (60 min/h) ≈ 58080 in/min.
The angular speed is then obtained by dividing the linear speed by the radius of the wheels. So, the angular speed of the wheels in rad/min is approximately 58080 in/min / 15 in ≈ 3872 rad/min.
To find the number of revolutions per minute (rpm), we divide the angular speed by 2π, as one revolution is equal to 2π radians. Therefore, the wheels make approximately 3872 rad/min / (2π) ≈ 616.29 rpm.
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A constant force pushes a 5 kg brick at 10 N. If the mass was tripled, what would happen to the acceleration if the same force is applied?
(PLEASE SHOW WITH STEPS)
Answers
Explanation:
The original acceleration is:
∑F = ma
10 N = (5 kg) a
a = 2 m/s²
If the mass is tripled, the new acceleration is:
∑F = ma
10 N = (15 kg) a
a = 0.67 m/s²
The acceleration is reduced by a factor of 3.
Answer:
1.35 miles per second
Explanation:
1 step it depende the way and hight he is
2 step the mass of the brick it depends
3 if it was triplet the acceleration it would be 1.50
Two point charges are on the y axis. A 3.90-µC charge is located at y = 1.25 cm, and a -2.4-µC charge is located at y = −1.80 cm. (a) Find the total electric potential at the origin. V (b) Find the total electric potential at the point whose coordinates are (1.50 cm, 0). V
Answers
Answer:
a) 1.6*10^6 V
b) 13.35*10^6 V
Explanation:
The electric potential at origin is the sum of the contribution of the two charges. You use the following formula:
\(V=k\frac{q_1}{r_1}+k\frac{q_2}{r_2}\) (1)
q1 = 3.90µC = 3.90*10^-6 C
q2 = -2.4µC = -2.4*10^-6 C
r1 = 1.25 cm = 0.0125 m
r2 = -1.80 cm = -0.018 m
k: Coulomb's constant = 8.98*10^9 Nm^2/C^2
You replace all the parameters in the equation (1):
\(V=k[\frac{q_1}{r_1}+\frac{q_2}{r_2}]\\\\V=(8.98*10^9Nm^2/C^2)[\frac{3.90*10^{-6}C}{0.0125m}+\frac{-2.4*10^{-6}C}{0.018m}]=1.6*10^6V\)
hence, the total electric potential is approximately 1.6*10^6 V
b) For the coordinate (1.50 cm , 0) = (0.015 m, 0) you have:
r1 = 0.0150m - 0.0125m = 0.0025m
r2= 0.015m + 0.018m = 0.033m
Then, you replace in the equation (1):
\(V=(8.98*10^9Nm^2/C^2)[\frac{3.90*10^{-6}C}{0.0025m}+\frac{-2.4*10^{-6}C}{0.033m}]=13.35*10^6V\)
hence, for y = 1.50cm you obtain V = 13.35*10^6 V
What is one way that nuclear fission and nuclear fusion are similar? A. Nuclei are split into smaller nuclei. B. Atoms are altered in both processes. C. Small nuclei combine to form larger nuclei. D. They are both used to produce electrical power.
Answers
Answer:
B. Atoms are altered in both processes
Explanation:
Answer: B. Atoms are altered in both processes
Explanation:
The drill used by most dentists today is powered by a small air turbine that can operate at angular speeds of 3.67 x 104 rad/s (about 350,000 revolutions per minute). These drills, along with ultrasonic dental drills, are the fastest turbines in the world so far exceeding the angular speeds of jet engines. Suppose a drill starts from rest and comes up to its operating speed in 1.8 s.
a. Find the angular acceleration produced by the drill, assuming it is constant.
b. How many revolutions does the drill bit make as it comes up to speed?
Answers
The angular acceleration of the drill is 2.05 x 104 rad/s2 and the number of revolutions made by the drill bit is 1.1 x 105 radians (or about 6,300 revolutions)
What is angular acceleration?Angular acceleration is the rate of change of angular velocity over time. It is a vector quantity, meaning it has both magnitude and direction. Angular acceleration is typically represented by the symbol alpha (α). It is equal to the change in angular velocity divided by the time taken for the change, and is measured in radians per second squared (rad/s2).
a. The angular acceleration of the drill can be found using the equation for constant angular acceleration, α = (ω2 - ω1) / (t2 - t1).
In this case, ω1 = 0 rad/s (since the drill starts from rest),
ω2 = 3.67 x 104 rad/s, and t2 - t1 = 1.8 s.
Thus, the angular acceleration of the drill is:
α = (3.67 x 104 rad/s - 0 rad/s) / 1.8 s = 2.05 x 104 rad/s²
b. The number of revolutions made by the drill bit as it comes up to speed can be calculated using the equation for angular displacement,
θ = ω1 t + (1/2) α t².
In this case, ω1 = 0 rad/s and α = 2.05 x 104 rad/s², and t = 1.8 s.
Thus, the number of revolutions made by the drill bit is:
θ = 0 rad/s x 1.8 s + (1/2) x 2.05 x 104 rad/s² x (1.8 s)² = 1.1 x 105 radians (or about 6,300 revolutions)
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Which sort algorithm is this: void Sort(int array[], int tempArray[], int left, int right) { int i, j, k, middle; if(right > left) { middle
Answers
The provided code appears to implement the Merge Sort algorithm, a divide-and-conquer sorting algorithm. It recursively divides the array into smaller subarrays until each subarray contains only one element.
The given code snippet suggests the usage of two arrays, "array" and "tempArray," for sorting. The "left" and "right" parameters specify the range of indices to be sorted within the "array." The algorithm works as follows:
It checks if the range to be sorted (right > left) is valid. If not, it terminates as there is nothing to sort.
It calculates the middle index of the range as (left + right) / 2.
Recursively, the algorithm sorts the left half of the array by calling itself with the range (left, middle).
Recursively, the algorithm sorts the right half of the array by calling itself with the range (middle + 1, right).
Finally, it merges the two sorted halves into the "tempArray" using the Merge operation.
The merged result is copied back to the original "array" within the given range.
The sorting process continues recursively until the base case is reached (subarrays with only one element).
Merge Sort is an efficient sorting algorithm with a time complexity of O(n log n). It provides stability (preserves the relative order of equal elements) and is commonly used for sorting large datasets. To learn more about Merge Sort, you can refer to additional resources such as tutorials or textbooks on algorithms and data structures.
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what is the mass of a mallard duck whose speed is 8.2 m/s and whose momentum has a magnitude of 10 kg⋅m/s ?
Answers
The mass of the mallard duck whose speed is 8.2 and has a momentum of 10 kg.m/s is 1.22 kg.
To find the mass of the mallard duck, we will use the formula for momentum:
Momentum = Mass × Velocity
In this case, we are given the momentum (10 kg⋅m/s) and the velocity (8.2 m/s) and need to find the mass. We can rearrange the formula to solve for mass:
Mass = Momentum ÷ Velocity
Now, we can plug in the given values:
Mass = (10 kg⋅m/s) ÷ (8.2 m/s)
Mass = 1.22 kg
So, the mass of the mallard duck is approximately 1.22 kg.
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